5 of 10
Before scientists publish their data and conclusions in scientific journa s, they
ask other experts in the same field to review the work and ensure that the
results and conclusions are valid. What is this process called?

The energy associated with the annihilation of a positron and an electron is approximately 2.7416 × 10⁻⁸ kilojoules per mole.

When a positron and an electron annihilate each other, their combined mass is completely converted into energy according to Einstein's mass-energy equivalence principle (E=mc²). To calculate the energy associated with this process in kilojoules per mole (kJ/mol), we need to determine the mass of the positron-electron pair and then apply the appropriate conversion factors.

The mass of an electron is approximately 9.10938356 × 10⁻³¹ kilograms, and since the positron has the same mass, the combined mass of the pair is twice that value. To convert this mass to moles, we need to divide it by Avogadro's number, which is 6.022 × 10²³ particles/mol.

Now, to calculate the energy associated with the annihilation process, we can use the equation E=mc². The mass of the positron-electron pair is multiplied by the square of the speed of light, c, which is approximately 2.998 × 10⁸ meters per second.

Therefore, the energy associated with the annihilation of a positron and an electron can be calculated as follows:

Energy (E) = (2 * mass of electron) * (speed of light)²

Substituting the known values and performing the calculation, we find:

E = (2 * 9.10938356 × 10⁻³¹ kg) * (2.998 × 10⁸ m/s)²

Finally, convert the energy to kilojoules per mole by dividing by Avogadro's number:

Energy (E) = [(2 * 9.10938356 × 10⁻³¹ kg) * (2.998 × 10⁸ m/s)²] / (6.022 × 10²³ particles/mol)

= 2.7416 × 10⁻³⁶ kg m²/s²/particles * mol

To convert this energy to kilojoules per mole, we need to multiply by the conversion factor. The conversion factor is given by 1 J/mol = 1 kg m²/s²/mol. Additionally, 1 kJ = 1000 J.

Energy (E) = (2.7416 × 10⁻³⁶ kg m²/s²/particles * mol) * (1 J/mol / 1 kg m²/s²) * (1 kJ / 1000 J)

= 2.7416 × 10⁻³⁶ * 10⁻³ * 10⁻³ kJ/mol

= 2.7416 × 10⁻⁸ kJ/mol

Therefore, the energy associated with the annihilation of a positron and an electron is approximately 2.7416 × 10⁻⁸ kilojoules per mole.

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This series of the hydrogen emission spectrum is known as the Balmer series.

This is the only series of lines in the electromagnetic spectrum that lies in the visible region.

What is the Balmer series?

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15.80 oz of gold contains approximately 3.29 x 10²³ atoms.

The ounce/oz is any of the several different units of mass, weight or volume and is derived almost unchanged from the uncia.

In order to convert 15.80 oz to atoms, we need to know the identity of substance we are dealing with. The number of atoms in a given mass of a substance depends on atomic mass and Avogadro's number.

To convert ounces to grams, we can use the following conversion factor:

1 oz = 28.35 g

15.80 oz * (28.35 g/oz) * (1 mol/196.97 g) * (6.022 x 10²³ atoms/mol) = 3.29 x 10²³ atoms

Therefore, 15.80 oz of gold contains approximately 3.29 x 10²³ atoms.

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Includes and excludes notes are important components of the ICD-10-CM coding guidelines and can be found throughout the coding manual, including both the tabular and alphabetic index sections. These notes provide additional information and guidance for code selection and help ensure accurate and specific coding.

Includes notes provide a list of terms or conditions that are considered part of the code's definition. They indicate that if the condition or term mentioned in the includes note is present, it should be coded along with the main code.

Excludes notes, on the other hand, provide guidance on conditions or terms that are not included in the code's definition. They indicate that if the excluded condition or term is present, it should not be coded together with the main code.

Both includes and excludes notes help to clarify the appropriate use of codes and promote accurate coding practices.

It's important for coders to carefully review and understand the includes and excludes notes in both the tabular and alphabetic index sections of the ICD-10-CM to ensure accurate code assignment.

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Answer:

Two young school mates talk you vivo en miami the answer is Dónde vives tú

Explanation:

Hg⁺ with I⁻ forms HgI

Hg⁺ with S²⁻ forms Hg₂S

Hg⁺ with CO₃²⁻ forms Hg₂CO₃

K⁺ with I⁻ forms KI

K⁺ with S²⁻ forms K₂S

K⁺ with CO₃²⁻ forms K₂CO₃

Answer:d

Explanation:

d

Answer: Neutron has no charge, electron has a charge and mass. Neutron occurs inside the nucleus where electron is seen outside the nucleus.

Explanation:

Answer:

V = 127.57 mL

Explanation:

In this case, we are having an acid base titration, and this, according to the overall reaction:

2H₃PO₄ + 3Ca(OH)₂ -----> Ca₃(PO₄)₂ + 6H₂O

This reaction was neutralized, so, it's a neutralization reaction, therefore, we can use the following expression for neutralization reactions:

n₁ = n₂  (1)

This is because, in the equivalence point, both moles of the reagents are the same. Now we need to do a relation between this and the actual moles that we have according to the overall reaction.

In this case, we have 2 moles of acid reacting with 3 moles of base, so, the equation (1) is re-written like this:

2n₁ = 3n₂   (2)

Knowing this, and that we have values of concentrations and volume, we can write the expression of moles in terms of molarity and volume:

n = M * V    replacing in (2):

2M₁V₁ = 3M₂V₂   From here, we can solve for V₂ which is the volume of the base:

V₂ = 2M₁V₁ / 3M₂   (3)

Now, all we have to do is replace the given values to obtain the volume of the base:

V₂ = 2 * 1.6 * 59.8 / 3 * 0.5

Answer:

\(V_{Ca(OH)_2}=0.287L=287mL\)

Explanation:

Hello,

In this case, given the reaction:

\(2 H_3PO_4 + 3 Ca(OH)_2 \rightarrow Ca_3(PO_4)_2 + 6 H_2O\)

We first compute the moles of phosphoric acid that are actually reacting given the volume (must be in litres) and the molarity:

\(n_{H_3PO_4 }=1.60\frac{mol}{L}*59.8mL*\frac{1L}{1000mL} =0.0957molH_3PO_4\)

Next, we compute the moles of calcium hydroxide that are reacting by using the 3:2 molar ratio with phosphoric acid:

\(n_{Ca(OH)_2}=0.0957molH_3PO_4*\frac{3molCa(OH)_2}{2molH_3PO_4} =0.144molCa(OH)_2\)

Finally, by knowing the 0.500 M of the calcium hydroxide solution we compute the required volume:

\(V_{Ca(OH)_2}=\frac{n_{Ca(OH)_2}}{M_{Ca(OH)_2}}=\frac{0.144mol}{0.500\frac{mol}{L} } \\ \\V_{Ca(OH)_2}=0.287L=287mL\)

Best regards.

Answer:

0.111 moldm⁻³

First work out the moles of NaOH dispensed from the burette:

1. (25.0/1000)x0.100 = 0.00250 moles of HCl

Next use the balanced equation to reason how many moles of HCl are present in the flask:

2. 1:1 therefore 0.00250 moles NaOH

Lastly, now that you have both the volume and the number of moles of HCl, work out its concentration.

3. 0.0025/(22.5/1000) = 0.111 moldm⁻³

Explanation:

Answer:

The concentration of the hydrochloric acid is 0.00047 mol/dm³.

Explanation:

The balanced equation for the reaction is:

2 HCl(aq) + Ba(OH)2(aq) → BaCl₂(aq) + 2H₂O

We know that 25.00 cm³ of the hydrochloric acid reacted with 23.50 cm³ of the 0.100 mol/dm³ barium hydroxide solution.

Given the balanced equation, it is clear that 2 moles of hydrochloric acid react with 1 mole of barium hydroxide. As we know the volume and concentration of the barium hydroxide, we can calculate the number of moles of barium hydroxide present in the 23.50 cm³ of solution.

23.50 cm³ of 0.100 mol/dm³ barium hydroxide = (23.50 x 0.100) / 1000 = 0.00235 moles

As 2 moles of hydrochloric acid react with 1 mole of barium hydroxide, and we know the number of moles of barium hydroxide, we can calculate the number of moles of hydrochloric acid.

0.00235 moles of barium hydroxide / 2 = 0.001175 moles hydrochloric acid

We have the number of moles of hydrochloric acid, we can calculate the concentration in mol/dm³.

0.001175 moles hydrochloric acid / 25.00 cm³ = 0.00047 mol/dm³

The concentration of the hydrochloric acid is 0.00047 mol/dm³.

Answer:

Evaporation is great for separating a mixture (solution) of a soluble solid and a solvent. The process involves heating the solution until the solvent evaporates (turns into gas) leaving behind the solid residue. ... This method is best for separating a liquid from a solution.

Filtration is a method for separating an insoluble solid from a liquid. When a mixture of sand and water is filtered: the sand stays behind in the filter paper (it becomes the residue ) the water passes through the filter paper (it becomes the filtrate )

Magnetic separation is the process of separating components of mixtures by using magnets to attract magnetic materials. ... Due to the magnets, magnetic particles are being drifted by the movement of the drums. This can create a magnetic concentrate (e.g. an ore concentrate).

Explanation:

That's your answer.

Answer:

b

Explanation:

glucose

During cellular respiration, a glucose molecule is gradually broken down into carbon dioxide and water. Along the way, some ATP is produced directly in the reactions that transform glucose. Much more ATP, however, is produced later in a process called oxidative phosphorylation. Oxidative phosphorylation is powered by the movement of electrons through the electron transport chain, a series of proteins embedded in the inner membrane of the mitochondrion.

Answer:

During cellular respiration, your cells release energy in the form of ATP (adenosine triphosphate), which is used as an energy source by the body. The energy released during cellular respiration comes from the breakdown of glucose, which is a type of sugar that is used by the body as a source of fuel. In addition to ATP, some heat is also released during cellular respiration, but this is not the primary product of the process. So the correct answer is a. Energy.

The order of increasing bond length is B22 > B2 > B2-.In summary, the order of increasing bond order is B22 < B2 < B2-, the order of increasing bond energy is B22 < B2 < B2-, and the order of increasing bond length is B22 > B2 > B2-.

Molecular orbital (MO) diagrams are used to assess the bonding in a molecule and provide information about bond order, bond energy, and bond length. In this question, we have to rank B22, B2, and B2- in order of increasing bond order, bond energy, and bond length using MO diagrams.

Bond order: Bond order refers to the number of chemical bonds between two atoms. It is determined by the number of bonding electrons minus the number of antibonding electrons divided by two. A higher bond order indicates stronger bonding between two atoms. B22 has a bond order of 1, B2 has a bond order of 1, and B2- has a bond order of 2. Therefore, the order of increasing bond order is B22 < B2 < B2-.

Bond energy: Bond energy refers to the energy required to break a chemical bond. A higher bond energy indicates a stronger bond. B22 has the weakest bond and the smallest bond energy because it is composed of two atoms in the ground state, which do not bond. B2 has a slightly stronger bond than B22, but the bond energy is still low. B2- has the strongest bond because it has the highest bond order. Therefore, the order of increasing bond energy is B22 < B2 < B2-.

Bond length: Bond length refers to the distance between the nuclei of two bonded atoms. A shorter bond length indicates a stronger bond. B22 has the largest bond length since it has no bond. B2 has a slightly shorter bond length than B22. B2- has the shortest bond length since it has the highest bond order.

Therefore, the order of increasing bond length is B22 > B2 > B2-.In summary, the order of increasing bond order is B22 < B2 < B2-, the order of increasing bond energy is B22 < B2 < B2-, and the order of increasing bond length is B22 > B2 > B2-.

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Constructed languages are artificial languages created for a particular purpose like for art, entertainment, religion, secret communication, international communication, or for any other reason.

They are also known as invented languages or fictional languages. Here are the constructed languages from the given list:

a. Mandarin: It is not a constructed language. It is the most widely spoken language in the world.

b. Loglan: It is a constructed language created in 1955 for scientific research by James Cooke Brown.

c. Esperanto: It is a constructed language created by a Polish doctor Ludwik Lazarus Zamenhof in 1887, to promote international understanding.

d. Na'vi: It is a constructed language created by linguist Paul Frommer for the movie Avatar directed by James Cameron.

e. English: It is a natural language that developed over thousands of years.

f. lojban: It is a constructed language developed in the 20th century for use in linguistic studies and as a philosophical language.

g. Klingon: It is a constructed language invented for the science fiction franchise Star Trek by Marc Okrand.

h. Latin: It is a natural language that was the language of the Roman Empire in ancient times.

Constructed languages from the given list are Loglan, Esperanto, Na'vi, lojban, and Klingon.

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From the samples on the slide made up of tiny cells, Terry can conclude that the cells were produced by other cells.

Cell production occurs often in a human protein, such as yeast, bacteria, or mammalian cells in culture, which then start producing the protein in large quantities. A new organism is created during the process of splicing a gene into a production cell.

Cells are often produced from other cells by the process of replication. All living things, from microorganisms to humans, rely on cells for structure and function. Scientists regard them as the tiniest form of life. Cells contain the biological machinery that produces the proteins, chemicals, and signals that are responsible for everything that occurs within our bodies.

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The volume of the balloon in the freezer is approximately 1.77 L.The ideal gas law is PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature.

Since pressure is constant, we can use the combined gas law to solve the problem.The combined gas law is

P1V1/T1 = P2V2/T2,

where P1 and T1 are the initial pressure and temperature, and P2 and T2 are the final pressure and temperature. Let's start with the initial state of the balloon:

V1 = 2.00 L T1

= 32.0 °C + 273.15 K

= 305.15 K

Now let's find the final volume of the balloon when it's in the freezer:

V2 = P1V1T2/T1P1

= constant

T2 = -3.6 °C + 273.15 K

= 269.55 K

Now we can plug in the values and solve for V2:

V2 = P1V1T2/T1

= (1 atm)(2.00 L)(269.55 K)/(305.15 K)

≈ 1.77 L

Therefore, the volume of the balloon in the freezer is approximately 1.77 L.

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The molar concentration of a 12% sodium chloride solution is approximately 2.05 M.

To determine the molar concentration of a 12% sodium chloride solution, we need to convert the given percentage concentration into molarity.

First, we need to understand that the percentage concentration refers to the mass of the solute (sodium chloride) relative to the total mass of the solution.

In this case, a 12% sodium chloride solution means that there are 12 grams of sodium chloride in 100 grams of the solution.

To convert this into molar concentration, we need to consider the molar mass of sodium chloride, which is 58.5 g/mol.

We can start by calculating the number of moles of sodium chloride in 12 grams:

Moles of sodium chloride = mass of sodium chloride / molar mass of sodium chloride

Moles of sodium chloride = 12 g / 58.5 g/mol = 0.205 moles

Next, we calculate the volume of the solution in liters using the density of the solution. Since the density is not provided, we assume a density of 1 g/mL for simplicity:

Volume of solution = mass of solution / density

Volume of solution = 100 g / 1 g/mL = 100 mL = 0.1 L

Finally, we calculate the molar concentration (Molarity) by dividing the number of moles by the volume in liters:

Molar concentration = moles of solute / volume of solution

Molar concentration = 0.205 moles / 0.1 L = 2.05 M

Therefore, the molar concentration of a 12% sodium chloride solution is approximately 2.05 M.


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Answer:

FALSE

Explanation:

The temperature of the air has a significant impact on the speed of sound in that medium. The square root of the absolute temperature of the air determines the speed of sound in that medium. The speed of sound rises along with temperature.

The speed of sound is also influenced by pressure, however this influence is minimal. The speed of sound will rise with increasing pressure and decrease with decreasing pressure, however the effect is quite tiny in comparison to the influence of temperature.

In conclusion, air temperature has a significant impact on the speed of sound in air, with pressure having a marginally smaller impact.

Answer:

.75

Explanation:

Answer:

0.75 cents

Explanation:

Answer:

answer is 2 I think I'm correct sorry if I'm not

Answer:

Some of the heavier elements in the periodic table are created when pairs of neutron stars collide cataclysmically and explode, researchers have shown for the first time. Light elements like hydrogen and helium formed during the big bang, and those up to iron are made by fusion in the cores of stars.

Explanation:

Answer: Some of the heavier elements in the periodic table are created when pairs of neutron stars collide cataclysmically and explode, researchers have shown for the first time. Light elements like hydrogen and helium formed during the big bang, and those up to iron are made by fusion in the cores of stars.

Explanation:

Answer:

Smooth endoplasmic reticulum (SER) is a type of endoplasmic reticulum consisting of tubular vesicles that lack ribosomes on the outer surface and is involved in the synthesis and storage of lipids. Rough ER has ribosomes on the outer surface. Smooth ER does have riboszomes on the outer surface.

Explanation:

Answer:

I'm assuming this is from a lab that you did - in which case, I can't really help you out here.

Explanation:

Answer:

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

\(volume = \frac{mass}{density} \\\)

From the question we have

\(volume = \frac{250}{0.001331} \\ = 187828.70025...\)

We have the final answer as

Hope this helps you

Answer:

100

Explanation:

nsvcscjkvschssvds

Answer:

anion

Explanation:

anion undergoes reduction.

cation undergoes oxidation.

The ions are categorized according to the process of oxidation and reduction. The ion usually undergoes reduction is an anion.

A process involving the partial or complete gain of electrons and loss of oxygen. The ions acquire a net negative charge on them.

Thus, anions usually undergo a reduction.

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The atomic ratio of carbon to oxygen in carbon monoxide (CO) is 1:1, and the atomic ratio of carbon to oxygen in carbon dioxide (CO₂) is 2:1.

Firstly, we can analyze the decomposition of carbon monoxide (CO) and carbon dioxide (CO₂) to determine the atomic ratios involved.

Let's denote the atomic ratio of carbon to oxygen in carbon monoxide as x, and the atomic ratio of carbon to oxygen in carbon dioxide as y.

According to the given data;

Decomposition of carbon monoxide (CO);

Oxygen produced = 3.36 g

Carbon produced = 2.52 g

We know that the atomic mass of carbon is 12 g/mol, and the atomic mass of oxygen is 16 g/mol. Using these values, we can calculate the number of moles for each element;

Number of moles of oxygen = mass / atomic mass = 3.36 g / 16 g/mol = 0.21 mol

Number of moles of carbon = mass / atomic mass = 2.52 g / 12 g/mol = 0.21 mol

Since the atomic ratio of carbon to oxygen in carbon monoxide is x, we can write the following equation;

0.21 mol C / (0.21 mol O) = x

Simplifying the equation, we have;

x = 1

Therefore, the atomic ratio of carbon to oxygen in carbon monoxide is 1:1.

Decomposition of carbon dioxide (CO₂);

Oxygen produced = 9.92 g

Carbon produced = 3.72 g

Following the same calculations as before;

Number of moles of oxygen = mass / atomic mass = 9.92 g / 16 g/mol = 0.62 mol

Number of moles of carbon = mass / atomic mass = 3.72 g / 12 g/mol = 0.31 mol

Since the atomic ratio of carbon to oxygen in carbon dioxide is y, we can write the following equation;

0.31 mol C / (0.62 mol O) = y

Simplifying the equation, we have;

y = 0.5

Therefore, the atomic ratio of carbon to oxygen in carbon dioxide is 1:0.5, which can be simplified to 2:1.

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--The given question is incomplete, the complete question is

"Missed this? watch kcv: atomic theory; read section 2.3. you can click on the review link to access the section in your text. carbon and oxygen form both carbon monoxide and carbon dioxide. when samples of these are decomposed, the carbon monoxide produces 3.36 g of oxygen and 2.52 g of carbon, while the carbon dioxide produces 9.92 g of oxygen and 3.72 g of carbon. Calculate the atomic ratio of carbon to oxygen in carbon monoxide, and carbon dioxide."--

If one part of a system fails, this affects the rest of the system.