4x + y = 0Put it in slope form

Answer:

a] 1400 grams

b] 200 grams

c]600 grams

Step-by-step explanation:

1.4  x 1000=1400 grams

1.4 divide by 7 is 0.2 kg

0.2 x 3 = 0.6 x 1000=600 grams

Answer:

he last ratio is written incorrectly.

Mandy reversed the input and output in the numerator and denominator.

The correct ratio is 50/10.

The relationship is proportional.

False. Three hexadecimal digits can represent 12 binary bits.

Hexadecimal is a base-16 numbering system, meaning it uses 16 distinct digits to represent numbers, namely 0-9 and A-F. Each hexadecimal digit corresponds to four binary bits. Since there are 16 possible values for each digit, it takes four bits to represent them. Therefore, three hexadecimal digits would correspond to a total of 12 binary bits (3 digits * 4 bits/digit = 12 bits).

In summary, three hexadecimal digits can be used to represent 12 binary bits, not more or less.

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Answer:

Hope this helps you........

The mathematical phrase "e to the ipi" is composed of the imaginary unit i (the square root of -1 raised to the power of pi), which is symbolized by "pi," and the mathematical constant "e" (Euler's number).

The expression "e to the ipi" may be expressed as follows:

\(e^{(i*pi)}\)

The following formula is known as Euler's formula:

\(e^{(ipi)}\) = cos(pi) + isin(pi)

where "cos" and "sin" are the sine and cosine functions, respectively.

We may reduce this formula to using the cosine and sine trigonometric identities.

\(e^{(i*pi)}\) = -1

"e to the ipi" hence equals a negative one. This startling and outstanding finding ties together various crucial mathematical ideas, including calculus, complex numbers, and trigonometry.

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Answer:

B) 3b. 10b

Step-by-step explanation:

B) 3b. 10b = (3x10)(bxb) = 30b²

Answer:

Step-by-step explanation:

Binomial is a factor of the polynomial.

Answer:

Is A

Step-by-step explanation:

I thing so , because is the same

Part A:The solution of the inequality |(1 / 5) · x + 2| + 4 ≥ 6 is equal to x ≤ - 20 or x ≥ 0.

Part B: Please check the image attached below.

In this problem we find the case of an inequality of the form |a · x + b| + c ≥ d, whose solution set can be found by means of definition of absolute value and further algebra properties. Part A - Now we proceed to find the solution of the inequality:

Step 1 - Use definition of absolute value:

|(1 / 5) · x + 2| + 4 ≥ 6

|(1 / 5) · x + 2| ≥ 2

(1 / 5) · x + 2 ≤ - 2 or (1 / 5) · x + 2 ≥ 2

Second, use algebra properties to clear variable x:

(1 / 5) · x ≤ - 4 or (1 / 5) · x ≥ 0

x ≤ - 20 or x ≥ 0

Part B - The graph of the inequality is generated by means of a graphing tool.

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Answer:

P = 201.

Step-by-step explanation:

In mathematics, distributivity is a property of binary operations in which the multiplication is distributed, dividing the same multiplier by the different multipliers to obtain the result.

Thus, to solve the equation -4 (P - 212) = 44 the following calculation must be performed:

-4 (P - 212) = 44

(-4 x P) - (-4 x 212) = 44

-4P - (-848) = 44

-4P + 848 = 44

-4P = 44 - 848

-4P = -804

P = -804 / -4

P = 201

The total number of possible ways of giving 5 awards in a group of 20 people are 1860480.

A permutation is the number of ways a set can be arranged or the number of ways things can be arranged. Mathematically, permutation can be expressed as -

P[n, r] = n!/(n - r)!

Given is race of 20 people such that the top 5 in the race will win a prize.

Now, from a group of 20 people only 5 will be awarded with the prize. The total number of possible ways of giving 5 awards in a group of 20 people can be calculated as -

P[20, 5] = (20!/(20 - 5)!)

P[20, 5] = (20 x 19 x 18 x 17 x 16 x 15!)/15!

P[20, 5] = 20 x 19 x 18 x 17 x 16

P[20, 5] = 1860480

Therefore, the total number of possible ways of giving 5 awards in a group of 20 people are 1860480.

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Answer:

x=18

Step-by-step explanation:

you are correct all you do is add the four to 41, which is 44. you then divide 2.5 it equals 18

Answer:

18

Step-by-step explanation:

2.5x - 4 = 41

add 4 to both sides

2.5x = 45

divide both sides by 2.5

x = 18

Answer:

The mean is 77.

Answer:

The mean of this equation is 77

Step-by-step explanation:

74+75+80+76+75+81+78​-539

Number of terms=7

539/7=77

The general expression is 130 x - 600 and total points scored by the player is 1220

A) Let the number of correctly answered questions be x.

∴ Number of incorrectly answered questions will be 20 - x.

+ 100 points is awarded for each question answered correctly while -30 points is awarded for each question answered incorrectly.

Thus, the general equation becomes

= 100x - (20 - x)(-30)

= 100x +30x - 600

= 130x - 600

Thus the general expression becomes 130 x - 600

B)  The player answers 14 questions correctly, thus x = 14

Substituting the value of x =14 in the general equation we get,

= 130(14) - 600

= 1820 - 600

= 1220.

Thus the total points scored by the player will be 1220

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Answer: $7.50

Step-by-step explanation:

Answer:

3 family members can visit the park if the total cost of the trip was $291

Step-by-step explanation:

if 3 family members can go, that means that it will cost them $210 just for the tickets and $15 for the parking ticket and $66 for the food for exactly 3 people and all of it at the end will cost $291.

The interquartile range for Group A employees is 1 more than the interquartile range for Group B students is true.

Given

Data represented as a number of hours spent studying by Group A Students:

1, 2, 1, 1, 3, 3, 2, 2, 3

Arranging it in ascending order: 1, 1, 1 ,2, 2, 2, 3, 3, 3,

As a number of terms are odd,

The median will be the middle value of observation.

Which is 2.

The interquartile range (IQR) is the range of values that resides in the middle of the scores.

The Data arranged in ascending order are; (1,1,1,2,2,2,3,3,3).

Median of (1, 1, 1, 2) = 1 \(\rm Q_1=1\)

Median of (2, 3, 3, 3) =3 \(\rm Q_3=3\)

Interquartile Range = \(\rm Q_3-Q_1\) = 3- 1 =2

For Data Set 2,

The Data for group B students are:  3   2 3 2 2 2 1 1 2

Arranging in ascending order: 1,1,2,2,2,2,2,3,3

The total number of observations = 9

Median = 2

Arranging the data as : (1,1,2,2) 2,(2,2,3,3)

Median of (1,1,2,2)= Number of observations is 4 which is even;

\(\rm Median = \dfrac{1+2}{2}\\\\Median = \dfrac{3}{2}\)

Median of (2,2,3,3) = \(\rm Q_3 =\dfrac{3+2}{2} = \dfrac{5}{2}\)

S = Interquartile Range = \(\rm Q_3-Q_1=\dfrac{5}{2}-\dfrac{3}{2}=1\)

The interquartile range for Group A Students =Interquartile range for Group B students + 1.

\(\rm D=S_1+1\)

Hence, the interquartile range for Group A employees is 1 more than the interquartile range for Group B students is true.

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Answer:

812.5 inches

Step-by-step explanation:

Turn these numbers into fractions:

\(\frac{h}{900} \frac{65}{72}\)

Solve 900/72 to get 12.5. This means that multiplying 72 x 12.5, you get 900. So, to find the height of the tree: h you multiply 65 x 12.5. Your answer to this is 812.5.

Hope it helps!

Answer: The values of a and b for the equation √(648) = √(2a × 3b) is a = 3 and b = 4.

Step-by-step explanation:

Answer:

0.6%

Step-by-step explanation:

\(x\) is what percentage of \(y\) ? Divide x by y. In this case, divide 1515 by 252525:

\(1515\div252525\approx0.006\)

Now, multiply that number by 100 to get a percentage:

\(0.006\times100=0.6\)

1515 is 0.6% of 252525.

Another example so it's more clear:

50 is what percent of 200?

\(50\div200=0.25\\0.25\times100=25\)

25%

The dimensions of the enclosure that is most economical to construct are 10 feet by 31 feet.

To find the most economical dimensions, we need to minimize the cost of the fence. Let the length of the rectangle be L and the width be W. We know that the area of the rectangle is 310 square feet, so L * W = 310.

We also know that the cost of the fence is given by:

Cost = 5L + 5W + 15L

= 20L + 5W

= 20L + 5(310/L)

We can now differentiate this expression with respect to L to find the value of L that minimizes the cost:

\(d(Cost)/dL = 20 - 1550/L^2\)

Setting this to zero, we get:

\(20 - 1550/L^2 = 0\)

\(L^2 = 77.5\)

\(L = \sqrt{77.5} = 8.8\) (rounded to one decimal place)

Substituting this value of L into L * W = 310, we get:

W = 310/L = 35.2/4 = 8.8 * 3.99 (rounded to two decimal places)

Therefore, the dimensions of the enclosure that is most economical to construct are 10 feet by 31 feet.

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The statement  that best describes the process to find the product of rational expressions is: D. Multiply the numerators and then multiply the denominators.

The process to find the product of rational expressions involves multiplying the two expressions together. This can be done by multiplying the numerators of the two expressions and then multiplying the denominators of the two expressions.

For example, if we want to find the product of the rational expressions (2x + 3)/(x - 1) and (x + 2)/(3x), we can do the following:

(2x + 3)/(x - 1) * (x + 2)/(3x) = (2x + 3)(x + 2) / (x - 1)(3x)

To find the product, we multiplied the numerators (2x + 3) and (x + 2) to get (2x + 3)(x + 2), and we multiplied the denominators (x - 1) and (3x) to get (x - 1)(3x).

Therefore, the correct option is: Multiply the numerators and then multiply the denominators.

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Answer:

Eh, I think zero apples

Step-by-step explanation:

This is because if you eat 3 apples a day for 30 days you get,
3x30=90

Answer: 9+a^2 if d=10 OR 99 if d does not equal 10

The equation 5x = x + 3 has 1 solution.

The solution to the equation 5x = x + 3 is x = 3.

To show that the total charge contained in the charge distribution is Q, we integrate the charge density over the entire volume. The charge density is given by:

ρ(r) = ρ₀(1 - r/R) for r ≤ R,

ρ(r) = 0 for r > R,

where ρ₀ = 3Q/πR³.

To find the total charge, we integrate ρ(r) over the volume:

Q = ∫ρ(r) dV,

where dV represents the volume element.

Since the charge density is spherically symmetric, we can express dV as dV = 4πr² dr, where r is the radial distance.

The integral becomes:

Q = ∫₀ᴿ ρ₀(1 - r/R) * 4πr² dr.

Evaluating this integral gives:

Q = ρ₀ * 4π * [r³/3 - r⁴/(4R)] from 0 to R.

Simplifying further, we get:

Q = ρ₀ * 4π * [(R³/3) - (R⁴/4R)].

Simplifying the expression inside the parentheses:

Q = ρ₀ * 4π * [(4R³/12) - (R³/4)].

Simplifying once more:

Q = ρ₀ * π * (R³ - R³/3),

Q = ρ₀ * π * (2R³/3),

Q = (3Q/πR³) * π * (2R³/3),

Q = 2Q.

Therefore, the total charge contained in the charge distribution is Q.

To show that the electric field in the region r > R is identical to that created by a point charge Q at r = 0, we can use Gauss's law. Since the charge distribution is spherically symmetric, the electric field outside the distribution can be obtained by considering a Gaussian surface of radius r > R.

By Gauss's law, the electric field through a closed surface is given by:

∮E · dA = (1/ε₀) * Qenc,

where ε₀ is the permittivity of free space, Qenc is the enclosed charge, and the integral is taken over the closed surface.

Since the charge distribution is spherically symmetric, the enclosed charge within the Gaussian surface of radius r is Qenc = Q.

For the Gaussian surface outside the distribution, the electric field is radially directed, and its magnitude is constant on the surface. Hence, E · dA = E * 4πr².

Plugging these values into Gauss's law:

E * 4πr² = (1/ε₀) * Q,

Simplifying:

E = Q / (4πε₀r²).

This is the same expression as the electric field created by a point charge Q at the origin (r = 0).

To derive an expression for the electric field in the region r ≤ R, we can again use Gauss's law. This time we consider a Gaussian surface inside the charge distribution, such that the entire charge Q is enclosed.

The enclosed charge within the Gaussian surface of radius r ≤ R is Qenc = Q.

By Gauss's law, we have:

∮E · dA = (1/ε₀) * Qenc.

Since the charge distribution is spherically symmetric, the electric field is radially directed, and its magnitude is constant on the Gaussian surface. Hence, E · dA = E * 4πr².

Plugging these values into Gauss's law:

E * 4πr² = (1/ε₀) * Q.

Simplifying:

E = Q / (4πε₀r²).

This expression represents the electric field inside the charge distribution for r ≤ R.

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1. The  statement "In a hypothesis test, if the sample data is determined to be in the critical region with α = 0.05, then the same sample data would still be in the critical region if α were changed to 0.01." is false.

2. The statement "If a researcher decides to reject the null hypothesis using an alpha level of α = 0.05 at the conclusion of a hypothesis test, then they would include the statement of "p < 0.05" when writing their research report." is true.

1. In a hypothesis test, if the sample data is determined to be in the critical region with α = 0.05, then the same sample data would still be in the critical region if α were changed to 0.01.
This statement is false.

The critical region is dependent on the chosen alpha level. If the alpha level is decreased from 0.05 to 0.01, the critical region becomes smaller, and the sample data might not be in the critical region anymore.

2. If a researcher decides to reject the null hypothesis using an alpha level of α = 0.05 at the conclusion of a hypothesis test, then they would include the statement of "p < 0.05" when writing their research report.
This statement is true.
When a researcher rejects the null hypothesis with α = 0.05, it means that the p-value (probability) of observing the sample data is less than 0.05. Therefore, it is appropriate to include the statement "p < 0.05" in the research report to indicate this finding.

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Answer:

y = 5.2

Step-by-step explanation:

x : y  =  5 : ?

Given that x = 5

So,

Condition:

y = 20% + x

y = \(\frac{1}{5} + 5\)

y = \(\frac{26}{5}\)

y = 5.2

Answer: 5:6

Step-by-step explanation:

Assume, x is 100

So, y is 20% more = 120

100:120 = 5:6

So, the ratio of x:y = 5:6

The financing option that will likely lead to the lowest monthly payment is:

$3000 down payment, 6% interest, 84 months

The longer loan term (84 months) will spread out the payments over a longer period of time, resulting in a lower monthly payment. The down payment will also help to reduce the monthly payment amount.

The 6% interest rate is relatively low, so it won't have a significant impact on the monthly payment compared to the loan term.

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