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1)
The sum of four consecutive integers is -18. What are the four integers?
(Use a let statement)​

Your monthly payment for the 60-month, 5.54% APR motorcycle loan to purchase your dream Harley-Davidson will be $136.88.

To calculate the monthly payment for a motorcycle loan, we can use the formula for the present value of an annuity. The formula is:

PMT = PV * r / (1 - (1 + r)^(-n))

Where:
PMT = Monthly payment
PV = Present value of the loan
r = Monthly interest rate
n = Number of months

In this case, the present value of the loan (PV) is $7,200, the monthly interest rate (r) is 5.54% divided by 12 (0.0554 / 12), and the number of months (n) is 60.

Plugging in these values into the formula, we get:

PMT = 7200 * (0.0554 / 12) / (1 - (1 + (0.0554 / 12))^(-60))

Evaluating this expression, the monthly payment comes out to be approximately $136.88.

Therefore, your monthly payment for the 60-month, 5.54% APR motorcycle loan to purchase your dream Harley-Davidson will be $136.88.

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Step-by-step explanation:

volume of cylinder πr2h

radius = 7.5in

height = 11in

 volume= 22/7 x7.5 x7.5x11

           = 1942.875

therefore volume =1942.875 in

The correlation coefficient between the grades on Midterm 1 and the grades on Midterm 2 is the square root of the proportion of variability in Midterm 2 grades that is explained by the linear relationship with Midterm 1, which is `sqrt(0.622) = 0.789`.

1. The fitted least squares regression line is `Midterm 2 = 28.02 + 0.6589 Midterm 1`.

2. The fitted intercept is `28.02`.

3. The fitted slope is `0.6589`.

4. For every one point increase in Midterm 1, the grade on Midterm 2 tends to increase by `0.6589`.

5. For every ten point increase in Midterm 1, the grade on Midterm 2 tends to increase by `6.589`. This is because the slope is the change in `Midterm 2` for a one-unit change in `Midterm 1`, and therefore multiplying by 10 gives the change for a ten-unit change.

6. The amount of variability in the Midterm 2 grades that is left unexplained when their mean is used as a single-number summary to predict (or "explain") the Midterm 2 grades is the total variability minus the variability explained by the regression. In this case, the variance of Midterm 2 is `S² = 5.78809² = 33.488`, so the variability left unexplained is `33.488 - 20.793 = 12.695`.

7. The amount of variability in the Midterm 2 grades that is left unexplained when the Midterm 1 grades are used to predict (or "explain") the Midterm 2 scores through a linear relationship is the residual variance of the regression, which is `S² = 5.78809² = 33.488`.

8. The amount of variability in the Midterm 2 grades that is explained when the Midterm 1 grades are used to predict (or "explain") the Midterm 2 grades through a linear relationship is the explained variance of the regression, which is `20.793`.

9. The proportion of variability in the Midterm 2 grades that is explained when the Midterm 1 grades are used to predict (or "explain") the Midterm 2 grades through a linear relationship is the ratio of the explained variance to the total variance, which is `20.793/33.488 = 0.622`. This is also the square of the correlation coefficient between Midterm 1 and Midterm 2.

10. The sum of the squared vertical distances between the data points and the fitted least squares linear regression line is the residual sum of squares (RSS) of the regression, which is given by `RSS = S²(n-2) = 5.78809²(52-2) = 844.721`.

11. The predicted grade on Midterm 2 of a student who received a grade of 60 on Midterm 1 is `Midterm 2 = 28.02 + 0.6589(60) = 66.528`.12. The correlation coefficient between the grades on Midterm 1 and the grades on Midterm 2 is the square root of the proportion of variability in Midterm 2 grades that is explained by the linear relationship with Midterm 1, which is `sqrt(0.622) = 0.789`.

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Answer:

A

Step-by-step explanation:

The quotient is  5x³ -5x² + 2x -2.

Synthetic division is typically used to identify the zeroes of polynomials and is described as "a simplified method of dividing a polynomial with another polynomial equation of degree 1." This division method requires less human calculation effort than the lengthy division method.

Given:

(5\(x^4\) – 3x² + 4) ÷ (x + 1)

So, the division is

                       (x+1) |  (5\(x^4\) – 3x² + 4) | 5x³ -5x² + 2x -2

                                   5\(x^4\) + 5x³

                               ___________

                                          -5x³ - 3x²

                                          -5x³ - 5x²  

                                       ____________

                                                    2x² + 4    

                                                    2x² + 2x      

                                              ____________

                                                              4 - 2x      

                                                              -2 - 2x

                                                             _______

                                                                    6

Hence, the quotient is  5x³ -5x² + 2x -2.

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SOLUTION

Since the house decreased by 15%, the value of this in dollars becomes

Which is

Hence the house value decreased by $39,150

The current value of the house becomes

Hence the current value is $221,850

Solution:

Given a table of data;

Where the total hours in 50 hours

The hours spent for jogging is 20 hours.

The sum of angles about a point or in a circle is, 360°

The portion for jogging in degrees is

Substitute into the formula above

Hence, the portion for jogging is 144°

Answer:

It's b

Step-by-step explanation:

Just answered it

The given statement  P(z < −2.1)  is equivalent to the expression 1 – P(z < 2.1). Option B is correct.

A Z-score is stated as the fractional model of data point to the mean using standard deviations.

here, z = x - μ / σ

where, μ = mean and σ = standard deviation

Here,
P(z < −2.1)
By the property of the Z score,

P(z < −2.1) = 1 – P(z < 2.1)

Thus, the given statement  P(z < −2.1)  is equivalent to the expression 1 – P(z < 2.1).

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The Pearson correlation coefficient can be used as both a descriptive statistic and an inferential statistic.

As a descriptive statistic, the Pearson correlation coefficient describes the strength and direction of the linear relationship between two variables. It provides a numerical measure between -1 and 1, where -1 indicates a perfect negative linear relationship, 1 indicates a perfect positive linear relationship, and 0 indicates no linear relationship.

As an inferential statistic, the Pearson correlation coefficient can be used to test hypotheses and make inferences about the population correlation based on a sample. Hypothesis testing allows you to determine whether the observed correlation in the sample is statistically significant or occurred by chance. By examining the p-value associated with the correlation coefficient, you can make inferences about the strength of the relationship in the population.

Therefore, the correct answer is that the Pearson correlation coefficient can be used as both a descriptive and an inferential statistic.

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The sample size that would be required for the width of 99% is 2653.

The number of subjects involved in a sample size is referred to as the sample size in market research. A set of people chosen from the general community who are thought to be a representative sample size for that particular study is referred to as the sample size.

The following details are given:

Margin of error, E = 0.025; Significance Level, = 0.01

The proportion p is estimated to be p = 0.53.

The significance level with a critical value of 0.01 is 2.58.

The smallest sample size needed to estimate the population proportion p within the necessary margin of error is determined using the formula shown below:

n >= p*(1-p)*(zc/E)2 n = 0.53 *(1 - 0.53*)2 n = 2652.97 *(1-p)*(2.58/0.025)2

As a result, we determine that n = 2653 is the minimal sample size needed to satisfy the criteria that

n >= 2652.97 and that it must be an integer value.

Sample size is 2653.

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Tan(d)=105/125 is trigonometric ratio corect

The hypothesis test is performed to determine whether the filling process for Glow toothpaste should continue operating or be stopped and corrected.

The sample of 35 toothpaste tubes has a sample mean of 6.1 oz and a standard deviation of 0.2 oz. The null hypothesis, denoted as H0, assumes that the population mean filling weight is 6 oz, while the alternative hypothesis, denoted as Ha, suggests that the population mean filling weight is different from 6 oz.

Using a 0.03 level of significance, we can conduct a t-test to evaluate the hypothesis. By comparing the sample mean to the hypothesized population mean and considering the sample size and standard deviation, we can calculate the t-statistic and compare it to the critical t-value for the given significance level and degrees of freedom (n-1)

If the calculated t-statistic falls within the rejection region, which is determined by the critical t-value, we reject the null hypothesis and conclude that the filling process should be stopped and corrected.

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The expression -20 + 18.5u, when u is 0.6, in a decimal or whole number is equal to -8.9.

To evaluate the expression -20 + 18.5u when u = 0.6, we simply substitute 0.6 in place of u and simplify using the order of operations (PEMDAS).

-20 + 18.5u = -20 + 18.5(0.6) (substitute 0.6 for u)

-20 + 11.1 = -8.9 (simplify using multiplication first and then addition/subtraction)

Therefore, the value of the expression when u = 0.6 is -8.9.

The order of operations is a set of rules that dictate the order in which mathematical operations should be performed to avoid ambiguity and ensure that calculations are carried out correctly. PEMDAS stands for Parentheses, Exponents, Multiplication and Division (performed from left to right), and Addition and Subtraction (also performed from left to right).

In this case, we first multiply 18.5 and 0.6, giving us 11.1. Then, we subtract 20 from 11.1, resulting in -8.9.

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Answer:

i believe number 1 is 18 and number 2 is 9.

Step-by-step explanation:

if one full circle represents 6 CDs then on wednesday 18 Cds were sold because 6+6+6=18 and on thursday they sold 9 more Cds than on wednesday because they sold 6+6+6+6+3 which equals 9.

The solar panels installed on the university parking garage require approximately 10,952 hours of operation per year to break even, based on the given parameters and a maximum operational capacity of 12,321 hours per year.


To calculate the number of hours per year the solar panels need to operate to break even, we need to consider the present value of operating the solar panels for 1 hour per year.
The initial investment cost for installing the solar panels is $2 million. We’ll calculate the present value of this cost over 20 years using a discount rate of 20%.
PV = Initial Cost / (1 + Discount Rate)^Years
PV = $2,000,000 / (1 + 0.20)^20
PV = $2,000,000 / (1.20)^20
PV = $2,000,000 / 6.191736
PV = $323,035.53
The present value of operating the solar panels for 1 hour per year is $323,035.53.
Now, we’ll calculate the revenue generated by operating the solar panels for 1 hour per year. The capacity of the solar panels is 300 kW, and the electricity can be purchased at $0.10 per kWh. Therefore, the revenue generated per hour is:
Revenue per hour = Capacity (kW) * Price per kWh
Revenue per hour = 300 kW * $0.10/kWh
Revenue per hour = $30
To break even, the revenue generated per hour should be equal to the present value of the installation cost:
Revenue per hour = PV
$30 = $323,035.53
Now, we can calculate the number of hours per year the solar panels need to operate to break even:
Number of hours per year = PV / Revenue per hour
Number of hours per year = $323,035.53 / $30
Number of hours per year ≈ 10,767.85
Since the solar panels can operate only for a maximum of 12,321 hours per year, the project will break even at approximately 10,768 hours per year.
Among the given options, the closest number to 10,768 is 10,952.15, so the answer is 10,952.15.

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Answer:

x=7

Step-by-step explanation:

8x – 2y = 48

Let y = 4

8x - 2(4) = 48

8x - 8 = 48

Add 8 to each side

8x-8+8 = 48+8

8x = 56

Divide each side by 8

8x/8 = 56/8

x=7

Answer:

\(x = 7\)

Step-by-step explanation:

\(8x - 2y = 48 \\ 8x = 48 + 2y \\ x = \frac{48 + 2y}{8} \)

\(y = 4\)

\(x = \frac{48 + 2y}{8} \\ x = \frac{48 + 2 \times 4}{8} \\ x = \frac{48 + 8}{8} \\ x = \frac{56}{8} \\ x = 7\)

hope this helps

brainliest appreciated

good luck! have a nice day!

Answer:

|x| = 25

Step-by-step explanation:

Original Equation:

|x - 4| = 21

Just add 4 to both sides

|x| = 25

Hope this helped :)

Answer:

the answer is 25 or -17

Therefore, the statement that while finding the distance between two clusters during agglomerative clustering, the complete-linkage clustering represents the distance between cluster centroids is true.

While finding the distance between two clusters during agglomerative clustering, the complete-linkage clustering represents the distance between cluster . This statement is true.

Let's discuss it in more detail below. When dealing with clustering techniques, one of the most essential aspects is calculating the distance between two clusters centroids . There are various ways to do it, and each of them has its pros and cons. One of the most popular approaches is complete-linkage clustering.

In complete-linkage clustering, the distance between two clusters is measured as the maximum distance between any two points, one from each cluster. The rationale behind this is that complete-linkage clustering tries to find the pair of points from two different clusters that are farthest from each other.

This leads to clusters that are relatively separated and compact. Complete linkage clustering may be used to evaluate numerous data formats. It is effective in cases where there are a large number of variables and is commonly utilized in computational biology, particularly for studying genetic data. In general, complete linkage clustering is suitable for datasets with highly distinct and separate clusters.

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There are two possible ways to answer the question "If 3 dice are thrown, in how many ways can we obtain a sum of 15? (a toss of 6, 6, 3, is different from a toss of 6, 3, 6)" .There are 25 possible ways to obtain a sum of 15 when 3 dice are thrown.

The long answer would require listing out all the possible ways to obtain a sum of 15, which would be quite tedious. The minimum possible sum when 3 dice are thrown is 3 (when each die shows 1). The maximum possible sum is 18 (when each die shows 6).

To obtain a sum of 15, we need to find all possible combinations of three dice that add up to 15. We can start by listing all possible ways to obtain a sum of 3, 4, 5, 6, and so on, up to 18:3: 1+1+14: 1+1+2, 1+2+1, 2+1+15: 1+2+3, 1+3+2, 2+1+3, 2+3+1, 3+1+2, 3+2+116: 1+2+4, 1+4+2, 2+1+4, 2+4+1, 4+1+2, 4+2+117: 1+2+5, 1+5+2, 2+1+5, 2+5+1, 5+1+2, 5+2+118: 1+2+6, 1+6+2, 2+1+6, 2+6+1, 6+1+2, 6+2+1There are 25 possible combinations of three dice that add up to 15.

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Answer:

c < 3

Step-by-step explanation:

2c + 4 < 10 ( subtract 4 from both sides )

2c < 6 ( divide both sides by 2 )

c < 3

Answer:

2c + 4 < 10

2c < 10 - 4

2c < 6

c < 6/2

c < 3

brainliest plz

After rewriting the given equation P = 2(I + b) by taking the subject 'l', the resultant equation is l = (P - 2b)/2.

An equation is a mathematical statement that contains the symbol "equal to" between two expressions with identical values.

As in 3x + 5 = 15, for example.

There are many different types of equations, including linear, quadratic, cubic, and others.

The point-slope form, standard form, and slope-intercept form are the three main types of linear equations.

So, we have the equation:

P = 2(I + b)

Now, rewrite the equation taking 'l' as the subject:

P = 2(I + b)

P = 2I + 2b

2l = P - 2b

l = (P - 2b)/2

Therefore, after rewriting the given equation P = 2(I + b) by taking the subject 'l', the resultant equation is l = (P - 2b)/2.

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Step-by-step explanation:

−3x−6+(−1)

-3x-7

Answer:

−3 −7

Step-by-step explanation:

-3x-6-1

-3x-7

The greatest possible number of intersection points for four circles of different sizes is 12.

The greatest possible number of intersection points of four circles of different sizes can be calculated by considering the maximum number of intersection points each pair of circles can have and then summing them up.

When two circles intersect, they can have a maximum of two intersection points. So, if we have four circles, we can find the maximum number of intersection points by considering each pair of circles separately.

For the first circle, it can intersect with the other three circles at most two times each, giving us a total of 2 * 3 = 6 intersection points.

For the second circle, it can intersect with the remaining two circles at most two times each, giving us a total of 2 * 2 = 4 intersection points.

The third circle can intersect with the last remaining circle at most two times, giving us a total of 2 * 1 = 2 intersection points.

Finally, the fourth circle doesn't have any other circle left to intersect with, so it doesn't contribute any additional intersection points.

Now, we can sum up the intersection points from each pair of circles: 6 + 4 + 2 + 0 = 12.

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Answer:

x = 6

Step-by-step explanation:

Here it's sayin that Q is a point in between the end-points P & R. If we join P & R , it forms a line segment & Q is in the line segment PR. Hence PQ & QR are also line segments which combine to form line segment PR. So ,

PR = PQ + QR

Putting the given values of PQ ,QR & PR

=> 4x - 12 + 2x + 7 = 31

=> 6x - 5 = 31

=> 6x = 31 + 5

         = 36

=> x = 36/6 = 6

Answer:

101.35

Step-by-step explanation:

pir^2

pi5.68^2

32.2624

pi(32.2624)

about 101.355

Answer:

7 Rows of 9

Step-by-step explanation:

Planting 7 rows of 9 would leave you with no more tomato plants, and 18 more cabbage plants left over

The property states that if J is a subgroup of G such that J = H ∩ K, then for any a ∈ G, Ja = Ha ∩ Ka. This implies that if H and K are subgroups of finite index in G, their intersection H ∩ K is also of finite index.

The property, we need to show that Ja = Ha ∩ Ka for any a ∈ G.

Let x ∈ Ja, then x = ja for some j ∈ J = H ∩ K. Since j ∈ H and j ∈ K, we have x = ja ∈ Ha and x = ja ∈ Ka, which implies that x ∈ Ha ∩ Ka. Hence, Ja ⊆ Ha ∩ Ka.

Conversely, let y ∈ Ha ∩ Ka. Then y ∈ Ha and y ∈ Ka, which means y = ha = ka for some h ∈ H and k ∈ K. Since j = h^-1k ∈ J = H ∩ K, we have y = ha = jk ∈ Ja. Therefore, Ha ∩ Ka ⊆ Ja.

Combining both inclusions, we conclude that Ja = Ha ∩ Ka for any a ∈ G.

Now, if H and K are of finite index in G, it means that both H and K have a finite number of distinct left cosets in G. Since their intersection H ∩ K is a subset of both H and K, it follows that H ∩ K also has a finite number of distinct left cosets in G. Therefore, H ∩ K is of finite index in G.

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Answer:

d

Step-by-step explanation:

We know that the surface area of a sphere is given by the formula:

Surface area of sphere = 4πr²

On differentiating the above equation with respect to r, we get: dA/dr = 8πr [∵ d(r²)/dr = 2r]

dA/dr = 8πr is the expression for the rate of change of surface area with respect to r.

Therefore, at the instant when the surface area is 5 square meters, we can calculate the rate of change of radius as follows:

5 = 4πr²⇒ r² = (5/4π)⇒ r = √(5/4π)

On differentiating the above equation with respect to time, we get:

2r(dr/dt) = 0.5/π × (dπ/dt)⇒ 2 (√(5/4π)) (dr/dt) = (0.5/π) × (0) [∵ π is constant]⇒ (dr/dt) = 0.5/4√π

Now, we know that the volume of the sphere is given by the formula:

Volume of sphere = 4/3 πr³

On differentiating the above equation with respect to r, we get:dV/dr = 4πr²dV/dr = 4πr² is the expression for the rate of change of volume with respect to r.

Therefore, at the instant when the radius is increasing at the rate of 1/3 meters per minute we can calculate the rate of change of volume as follows:

(dV/dt) = (dV/dr) × (dr/dt)⇒ (dV/dt) = 4πr² × (dr/dt)Putting r = √(5/4π) and (dr/dt) = 0.5/4√π in the above equation, we get:(dV/dt) = 4π (√(5/4π))² × (0.5/4√π)⇒ (dV/dt) = 5/6 m³/min

Hence, the approximate rate at which the volume of the sphere is changing is 5/6 m³/min.

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