The true probability of observing a Head based on this simulation is 0.2. What do we expect to happen to the relative frequency of the occurrence of a Head as the number of flips increases from 10 to 10000
As the number of flips increases from 10 to 10000, we can expect the relative frequency of the occurrence of a Head to become more stable and closer to the true probability of 0.2.
The true probability of observing a Head based on this simulation is 0.2, which means that out of 10 flips, we would expect to see 2 Heads on average. However, as the number of flips increases from 10 to 10000, we would expect the relative frequency of the occurrence of a Head to approach the true probability of 0.2.
This is because of the Law of Large Numbers, which states that as the sample size increases, the sample mean will approach the true mean. In the case of coin flipping, the more flips we make, the closer we will get to the expected proportion of Heads.
For example, if we flip the coin 100 times, we might get 30 Heads and 70 Tails, which is a relative frequency of 0.3. However, if we flip the coin 1000 times, we might get 200 Heads and 800 Tails, which is a relative frequency of 0.2. As we continue to increase the number of flips, the relative frequency will approach the true probability of 0.2.
Therefore, as the number of flips increases from 10 to 10000, we can expect the relative frequency of the occurrence of a Head to become more stable and closer to the true probability of 0.2. This is important to keep in mind when conducting any type of statistical analysis based on coin flipping or other random events.
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helpp how do i solve this
The correct solution is shows in below.
What is mean by Fraction?A fraction is a part of whole number, and a way to split up a number into equal parts. Or, A number which is expressed as a quotient is called fraction. It can be written as the form of p : q, which is equivalent to p / q.
Given that;
1) 3/4 - 1/5 = 11/20
2) 3 1/3 - 4/7 = 2 16/21
3) 3 3/7 - 2 2/3 = 16/21
Now,
Simplify the fraction as;
1) 3/4 - 1/5 = 11/20
LHS;
⇒ 3/4 - 1/5
⇒ (15 - 4) / 20
⇒ 11/20
⇒ RHS
2) 3 1/3 - 4/7 = 2 16/21
⇒ 10/3 - 4/7
⇒ (70 - 12) / 21
⇒ 58 / 21
⇒ 2 16/21
⇒ RHS
3) 3 3/7 - 2 2/3 = 16/21
LHS;
⇒ 3 3/7 - 2 2/3
⇒ 24/7 - 8/3
⇒ (72 - 56)/21
⇒ 16/21
⇒ RHS
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Which expression is equivalent to 20c-8d? Show all work and circle letter of correct answer.
2(10c+4d)
4(5c-8d)
4(5c-2d)
c(20-8d)
Answer correctly and get brainiest
Answer: This one is equal to what we were looking for.
4 × 5c = 20 - 8d = 12
Step-by-step explanation:
(20c - 8d = 12) so we are look for an expression that is equal to 20c 8d and 12
2 × 10c = 20 + 4d = 24
4 × 5c = 20 - 8d = 12
4 × 5c = 20 - 2d = 18
c20 - 8d = 12
9.52 Times 6.7=?Show explanation too
Answer:
63.784
Step-by-step explanation:
(9.52)(6.7)
=63.784
wym explain just use your calculator and multiply
mrk brainliest plz
Answer:
348.4 (if that is the number of the question then 52 times 6.7)
63.78 (if 9.52 times 6.7)
the claim that the variance of a normal population in σ2 = 25
is to be rejected if the variance of a random sample size 16 exceeds 54.668 or is less than 12.102. What is the probability that this claim will be rejected even though σ2 =25?
The probability of rejecting the claim that the variance of a normal population is σ2 = 25, when the variance of a random sample size 16 exceeds 54.668 or is less than 12.102, will be determined.
To find the probability of rejecting the claim, we need to determine the probability that the sample variance falls outside the given range when the population variance is known to be σ2 = 25.Since the sample variance follows a chi-squared distribution with degrees of freedom equal to the sample size minus one (df = 16 - 1 = 15), we can use the chi-squared distribution to calculate the probability. The probability of observing a sample variance greater than 54.668 or less than 12.102 can be calculated by finding the cumulative probability from the chi-squared distribution with df = 15 for these two values. This will give us the probability of observing a sample variance outside the given range. Using statistical software or chi-squared tables, we can find the corresponding cumulative probabilities. Subtracting this cumulative probability from 1 will give us the probability of rejecting the claim. Therefore, the probability that the claim will be rejected, even though σ2 = 25, can be calculated using the chi-squared distribution and the given values for the sample variance thresholds.
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express \( \cos ^{4} \theta \) and \( \sin ^{3} \theta \) in terms of multiple angles.
We can equate the real and imaginary parts: `cos^4 θ - 6 cos^2 θ sin^2 θ + sin^4 θ = cos 4θ``4 cos^3 θ sin θ - 4 cos θ sin^3 θ = sin 4θ`.
In order to express cos^4 θ and sin^3 θ in terms of multiple angles, let us first consider the following trigonometric identity:`(cos A + i sin A)^n = cos nA + i sin nA` This is called De Moivre's theorem. It gives a way to compute the nth power of a complex number written in polar form. Let us substitute A = θ and n = 4 for cos^4 θ:`(cos θ + i sin θ)^4 = cos 4θ + i sin 4θ` Expanding the left-hand side using the binomial theorem, we have:`(cos θ + i sin θ)^4 = cos^4 θ + 4i cos^3 θ sin θ - 6 cos^2 θ sin^2 θ - 4i cos θ sin^3 θ + sin^4 θ`Since this is true for all values of θ, we can equate the real and imaginary parts:`cos^4 θ - 6 cos^2 θ sin^2 θ + sin^4 θ = cos 4θ``4 cos^3 θ sin θ - 4 cos θ sin^3 θ = sin 4θ`. Therefore, we have expressed cos^4 θ and sin^3 θ in terms of multiple angles.
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according to statistics reported on cnbc, a surprising number of motor vehicles are not covered by insurance. sample results, consistent with the cnbc report, showed 46 out of 200 vehicles were not covered by insurance. Develop a 95% confidence interval for the population proportion
The 95% confidence interval for the given population proportion is between 0.1716 to 0.2884.
How to find the confidence interval for a population proportion?The confidence interval for a population proportion is calculated by the formula,
\(C.I = \bar{p}\pm z_{\alpha/2}\sqrt{\frac{\bar{p}(1-\bar{p})}{n} }\)
Where \(\bar{p}\) is the sample proportion and α is the level of significance.
Calculation:It is given that,
The statistics reported on CNBC projects, a surprising number of motor vehicles are not covered by insurance. The sample results are
The sample size n = 200;
The number of successes = 46
So, the sample proportion \(\bar{p}\) = 46/200 = 0.23
For a 95% confidence interval, the level of significance is
α = 1 - 95/100 = 1 - 0.95 = 0.05
α/2 = 0.05/2 = 0.025
Then, the z-score for the value 0.025 is
\(z_{\alpha/2}\) = 1.96 (from the table)
Thus, the confidence interval is
\(C.I = \bar{p}\pm z_{\alpha/2}\sqrt{\frac{\bar{p}(1-\bar{p})}{n} }\)
⇒ C.I = 0.23 ± (1.96) × \(\sqrt{\frac{0.23(1-0.23)}{200} }\)
⇒ C.I = 0.23 ± 1.96 × 0.0298
⇒ C.I = 0.23 ± 0.0584
So, the upper limit is 0.23 + 0.0584 = 0.2884 and the lower limit is 0.23 - 0.0584 = 0.1716.
Therefore, the 95% confidence interval for the given population proportion lies between 0.1716 to 0.2884.
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If f (x) = 3(x+5) +-, what is f(a+ 2)?
A. 3(a + 2) + 4/a + 2
B. 3(a+ 7) + 4/a+2
c. 3(f(a)+5 + 4/f(a)+2
Answer:
b
Step-by-step explanation:
What is the value of the function when x=5 f(x) = x-5
Answer:
When x=5, f(x)=0
Step-by-step explanation:
\(f(x)=x-5\\\\f(5)=5-5\\\\f(5)=0\)
Therefore, when x=5, f(x)=0
Answer:
f(x) = 0
Step-by-step explanation:
given that x = 5f(x) = x - 5 .......replace x with 5
→ 5 - 5
→ 0
Zeke had 12 friends coming for his birthday party. He wanted each friend to get 1 1/3 pounds of candy. How many pounds of candy did he need to buy?
Prove each of the following statements using a direct proof. (a) If n is an odd integer, then n^2 is an odd integer. (Note: the definition of an odd integer is an integer that can be expressed as 2k + 1, where k is an integer) (b) For any positive real numbers, x and y ty2vy (c) If x is a real number and x ≤ 3, then 12-7x +x^2 ≥ 0. (d) The product of two odd integers is an odd integer. (e) If r and s are rational numbers, then the product of r and s is a rational number.
Answer:
(a) To prove that if n is an odd integer, then n^2 is an odd integer, we assume that n is an odd integer and prove that n^2 is also an odd integer.
Since n is an odd integer, we can express it as n = 2k + 1, where k is an integer.
Now, let's square both sides of the equation:
n^2 = (2k + 1)^2
Expanding the equation:
n^2 = 4k^2 + 4k + 1
We can rewrite the equation as:
n^2 = 2(2k^2 + 2k) + 1
Let's define a new integer m = 2k^2 + 2k. Since m is an integer, we can rewrite the equation as:
n^2 = 2m + 1
The equation shows that n^2 can be expressed in the form 2m + 1, where m is an integer. Therefore, n^2 is an odd integer.
(b) To prove that for any positive real numbers x and y, xy^2 is positive, we assume that x and y are positive real numbers and prove that xy^2 is also positive.
Since x and y are positive real numbers, they are greater than zero: x > 0 and y > 0.
Multiplying x and y^2, we have:
xy^2 > 0 * y^2
xy^2 > 0
Therefore, xy^2 is positive.
(c) To prove that if x is a real number and x ≤ 3, then 12 - 7x + x^2 ≥ 0, we assume that x is a real number and x ≤ 3, and prove that 12 - 7x + x^2 is greater than or equal to zero.
We start with the quadratic expression 12 - 7x + x^2 and simplify it:
12 - 7x + x^2 = x^2 - 7x + 12
To determine the sign of the expression, we factor it:
x^2 - 7x + 12 = (x - 3)(x - 4)
Since x ≤ 3, both factors (x - 3) and (x - 4) are less than or equal to zero.
Multiplying two negative or non-positive numbers yields a non-negative or positive result:
(x - 3)(x - 4) ≥ 0
Therefore, 12 - 7x + x^2 ≥ 0 when x is a real number and x ≤ 3.
(d) To prove that the product of two odd integers is an odd integer, we assume that m and n are odd integers and prove that their product mn is also an odd integer.
Since m and n are odd integers, we can express them as m = 2k + 1 and n = 2j + 1, where k and j are integers.
Now, let's multiply m and n:
mn = (2k + 1)(2j + 1)
Expanding the equation:
mn = 4kj + 2k + 2j + 1
We can rewrite the equation as:
mn = 2(2kj + k + j) + 1
Let's define a new integer p = 2kj + k + j. Since p is an integer, we can rewrite the equation as:
mn = 2p + 1
The equation shows that mn can be expressed in the form 2p + 1, where p is an integer. Therefore, mn is an odd integer.
(e) To prove that if r and s are rational numbers, then the product of r and s is a rational number, we assume that r and s are rational numbers and prove that their product rs is also a rational number.
Since r and s are rational numbers, we can express them as r = a/b and s = c/d, where a, b, c, and d are integers and b ≠ 0, d ≠ 0.
Now, let's multiply r and s:
rs = (a/b)(c/d)
Multiplying the numerators and denominators:
rs = (ac)/(bd)
Since ac and bd are both integers and bd ≠ 0, rs can be expressed as a fraction with integers in the numerator and denominator. Therefore, rs is a rational number.
a) The n² is an odd integer. b) We have proved that for any positive real numbers x and y, their product xy is also positive.
(a) If n is an odd integer, then n² is an odd integer.
To prove this statement, we will assume that n is an odd integer and show that n² is also an odd integer.
Assumption: n is an odd integer, so n = 2k + 1, where k is an integer.
Proof:
n² = (2k + 1)² [Substituting the value of n from the assumption]
= 4k² + 4k + 1 [Expanding the square]
Now, let's express 4k² + 4k as 2m, where m is an integer:
4k² + 4k = 2(2k² + 2k) = 2m
Substituting this back into the expression for n²:
n² = 2m + 1
We have expressed n² in the form 2m + 1, where m = 2k² + 2k. Since m is an integer, n² can be expressed as 2 times an integer plus 1. Therefore, n² is an odd integer.
Hence, we have proved that if n is an odd integer, then n² is an odd integer.
(b) For any positive real numbers x and y, xy > 0.
To prove this statement, we will assume x and y are positive real numbers and show that their product is also positive.
Assumption: x and y are positive real numbers.
Proof:
Since x and y are positive real numbers, we know that both x and y are greater than zero: x > 0 and y > 0.
Multiplying two positive numbers results in a positive number. Therefore, we have:
x * y > 0
Hence, we have proved that for any positive real numbers x and y, their product xy is also positive.
(c) If x is a real number and x ≤ 3, then 12 - 7x + x^2 ≥ 0.
To prove this statement, we will assume that x is a real number and x ≤ 3, and show that the expression 12 - 7x + x^2 is greater than or equal to zero.
Assumption: x is a real number and x ≤ 3.
Proof:
We can rewrite the expression 12 - 7x + x^2 as (x - 3)(x - 4).
We know that x ≤ 3, so (x - 3) ≤ 0. Similarly, (x - 4) ≤ 0.
Multiplying two non-positive numbers or two non-negative numbers results in a non-negative number. Therefore, we have:
(x - 3)(x - 4) ≥ 0
Hence, we have proved that if x is a real number and x ≤ 3, then 12 - 7x + x^2 ≥ 0.
(d) The product of two odd integers is an odd integer.
To prove this statement, we will assume that m and n are odd integers and show that their product is also an odd integer.
Assumption: m and n are odd integers.
Proof:
Since m and n are odd integers, we can express them as m = 2k + 1 and n = 2l + 1, where k and l are integers.
The product of m and n is:
m * n = (2k + 1)(2l + 1)
= 4kl + 2k + 2l + 1
= 2(2kl + k + l) + 1
Let p = 2kl + k + l. Since k, l, and p are integers, we can rewrite the expression as:
m * n = 2p + 1
We have expressed the product m * n as 2p + 1, where p is an integer. Therefore, the product of two odd integers is an odd integer.
Hence, we have proved that the product of two odd integers is an odd integer.
(e) If r and s are rational numbers, then the product of r and s is a rational number.
To prove this statement, we will assume that r and s are rational numbers and show that their product is also a rational number.
Assumption: r and s are rational numbers.
Proof:
Since r and s are rational numbers, we can express them as fractions: r = a/b and s = c/d, where a, b, c, and d are integers and b, d ≠ 0.
The product of r and s is:
r * s = (a/b)(c/d)
= ac / bd
The product ac and bd is the product of two integers, which is also an integer. Furthermore, since b and d are nonzero integers, their product bd is also nonzero.
Therefore, ac / bd is a fraction where the numerator and denominator are both integers. Hence, the product of r and s is a rational number.
Hence, we have proved that if r and s are rational numbers, then the product of r and s is a rational number.
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Supposep(t) represents population of speciesxat time t years. whatwould be the population when the rate of change of population isfastest?
To determine when the rate of change of population is fastest, we need to analyze the behavior of the derivative dP/dt. Since the population is at its carrying capacity when P = 75, the rate of change of population is fastest when P is farthest from its carrying capacity. In this case, it would be at the lowest population value, which is P = 0.
The differential equation given is:
dP/dt = 2(1 - P/150)P
To find the carrying capacity, we need to determine the equilibrium point of the population, where the rate of change is zero (i.e., dP/dt = 0).
Setting dP/dt = 0 in the differential equation:
0 = 2(1 - P/150)P
Simplifying:
0 = 2P - \(2P^2\)/150
0 = P - \(P^2\)/75
Rearranging:
\(P^2\)/75 - P = 0
Factoring out P:
P(P/75 - 1) = 0
This equation is satisfied when either P = 0 or P/75 - 1 = 0.
For P = 0, the population is at its lowest and there is no growth.
For P/75 - 1 = 0, solving for P:
P/75 = 1
P = 75
So, the carrying capacity of the population, in this case, is 75.
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find the carrying capacity of differential equation: dP/dt= 2(1-P/150)P Suppose p(t) represents population of species x at time t years. what would be the population when the rate of change of population is fastest?
Find the equation of the parabola in completed square form with focus (-2,0) and directrix y=3. Use the definition of a parabola to find the equation. Then check the equation with the short cut
To solve the problem, it is best that we plot the given so we get an idea how the parabola looks.
The vertex of a parabola is between the directrix and the focus. Also, because we have a horizontal directrix, we know that the parabola opens downward.
Again, the vertex is right in between the directrix and the focus. So we know that the value of p is 1.5.
Using the values that we have so far, we can complete the equation. We have:
h = -2, k = 1.5, p = 1.5 direction of the parabola: opens downward
So the equation should be:
\(\begin{gathered} (x-h)^2=-4p(y-k) \\ \\ (x+2)^2=-4(1.5)(y-1.5) \\ \\ (x+2)^2=-6(y-1.5) \end{gathered}\)We rewrite this in the completing the square format using properties of equations.
\(\begin{gathered} (x+2)^{2}=-6(y-1.5) \\ \\ (x+2)^2=-6y+9 \\ \\ 6y=-(x+2)^2+9 \\ \\ y=-\frac{1}{6}(x+2)^2+\frac{3}{2} \end{gathered}\)46=3(r+6)+5(r+4) plz hurry
how many points does a team get when a player makes a shot from more than 25 feet away?
Answer:
e
Step-by-step explanation:
How much faster is parallel computing?
The amount of a program that can be parallelized limits the amount of time it takes to run. For example, if 90% of the program can be parallelized, the theoretical maximum speedup utilizing parallel computing would be 10 times regardless of the number of processors employed.
What is parallel computing?The amount of a program that can be parallelized limits the amount of time it takes to run. For example, if 90% of the program can be parallelized, the theoretical maximum speedup utilizing parallel computing would be 10 times regardless of the number of processors employed. Parallel computing is a sort of computation in which several computations or processes are performed at the same time. Large issues are frequently broken into smaller ones, which may then be tackled concurrently.
Here,
Parallelization can only speed up a program so much. For example, if 90% of the program can be parallelized, the theoretical maximum speedup utilizing parallel computing would be ten times regardless of the number of processors employed.
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Point A'(2,3)A
′
(2,3)A, prime, left parenthesis, 2, comma, 3, right parenthesis is the image of A(3,-4)A(3,−4)A, left parenthesis, 3, comma, minus, 4, right parenthesis under a translation.
Determine the translation.
Use non-negative numbers.
A translation by
units to the
and
units
Answer:
Step-by-step explanation:
1 unit left and seven units up. I got the answer right on Kahn
what are numerical or verbal descriptions that usually result from measurements of some sort?
The numerical or verbal descriptions that usually result from measurements are called data or observations.
When measurements are conducted, whether in scientific experiments, surveys, or other data collection processes, the outcome is typically a set of data or observations.
These measurements can be represented numerically, such as numerical values or quantities, or verbally, using descriptive terms or categories.
Numerical descriptions provide precise quantitative information, such as measurements of length, weight, temperature, time, or any other measurable attribute. These measurements are often expressed using numbers or units of measurement.
Verbal descriptions, on the other hand, use words or qualitative descriptions to convey information about the observations.
For example, when conducting a survey, respondents might provide verbal responses that describe their opinions, preferences, or experiences.
Both numerical and verbal descriptions play important roles in data analysis and interpretation.
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Find f(x) if f(2) = 1 and the tangent line at x has slope (x − 1)ex2 − 2x.
f(x)= _____________
If f(2) = 1 and the tangent line at x has slope (x − 1)ex2 − 2x. f(x) = ((x^2 - 2x + 1)/2)e^(x^2 - 2x).
To find f(x), we'll first integrate the given slope function to obtain the original function. The slope of the tangent line is given as (x - 1)e^(x^2 - 2x).
Let F'(x) = (x - 1)e^(x^2 - 2x). To find f(x), we need to integrate F'(x) with respect to x:
∫(x - 1)e^(x^2 - 2x) dx
Now, we can use substitution. Let u = x^2 - 2x, then du = (2x - 2) dx. Therefore, the integral becomes:
∫((u + 1)/2)e^u du
Now, we can integrate by parts. Let v = e^u, then dv = e^u du. Let w = (u + 1)/2, then dw = 1/2 du. Using integration by parts formula:
∫w dv = wv - ∫v dw
∫(u + 1)/2 * e^u du = ((u + 1)/2)e^u - ∫(1/2)e^u du
Now integrate the remaining part:
∫(1/2)e^u du = (1/2)e^u + C
Substituting back:
f(x) = ((x^2 - 2x + 1)/2)e^(x^2 - 2x) + C
Now, use the given condition f(2) = 1:
1 = ((2^2 - 2*2 + 1)/2)e^(2^2 - 2*2) + C
1 = (1)e^0 + C
C = 0
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What is the quotient of 3/4 divided by 1/5?
The quotient is
3 and ___________
Answer:
The quotient is 3 and \(\frac{3}{4}\).
Step-by-step explanation:
To find the quotient of the division (which is just the solution, really), we have to solve the division itself:
\(\frac{\frac{3}{4}}{\frac{1}{5}}\)
\(= \frac{3 \cdot 5}{1 \cdot 4}\)
\(= \frac{15}{4}\)
Now that we know the quotient, we can look at the question itself to find it requires from us an answer with a whole number in it.
Therefore, we transform the fraction as thus:
\(\frac{15}{4}\)
\(= 3 \frac{3}{4}\)
Therefore, the final answer is 3 and \(\frac{3}{4}\).
Hope this helped!
The actual distance between two towns is 90 miles. If the scale on a map is 1 inch = 30 miles, what is the distance between the two towns on the map ?
Answer: 3
Step-by-step explanation: 90 miles apart and if 1 inch equals 30 miles divide 90/30 and you'll take 3
For the functions ()=f(t)=et and ()=−4g(t)=e−4t, defined on 0≤<[infinity]0≤t<[infinity], compute ∗f∗g in two different ways: By directly evaluating the integral in the definition of ∗f∗g.
To calculate ∗f∗g by directly evaluating the integral in the definition of ∗f∗g, we need to find the convolution of the functions f(t) = et and g(t) = −4e−4t over the interval 0 ≤ t < ∞.
The convolution of two functions f(t) and g(t) is defined as:
(f * g)(t) = ∫₀ᴛ f(τ) g(t - τ) dτ
To calculate the convolution of f(t) and g(t), we need to substitute the given functions into the definition:
(f * g)(t) = ∫₀\(ᴛ e^τ (-4e^(−4(t-τ))) dτ\)
= \(-4e^(-4t)\)∫₀ᴛ\(e^(5τ)\) dτ
Using integration by substitution, we can simplify this integral to:
(f * g)(t) = -4e^(-4t) [(e^(5t) - 1) / 5]
Therefore, ∗f∗g = (f * g)(t) = \(-4/5 + (4/5)e^(t-4t) = -4/5 + (4/5)e^(-3t)\))
Thus, we have calculated the convolution of f(t) = et and g(t) = −4e−4t by directly evaluating the integral in the definition of ∗f∗g.
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what is the 8th number in the sequence 0, 1, 1, 2, 3, 5
Answer:
13
Step-by-step explanation:
the next number is the sum of the two predictions.
0+1 = 1+1 = 2+1 = 3+2 = 5
Then the sequence will continue in the same way:
3+5 = 8
5+8 = 13
WILL MARK BRAINLEST 40 POINTS Simplify three fifths times the quantity 1 plus the square root of 16 end quantity squared minus the quantity five minus two end quantity cubed.
−18
−12
36
42
The value of the expression is -5.84
How to find the value?The question is mathematically expressed as follows
The question reads: three fifths times the quantity 1 plus the square root of 16 end quantity squared minus the quantity five minus two end quantity cubed
[(3/5*1 + √16)]² - (5-2)³
Simplify the brackets first
This implies that
(3/5 + 4)² - (3)³
Simplify further to have
[(3+20)/5]² - 27
⇒(23/5) -27
Simplify to get
529/25 - 27
= 21.16 - 27
=-5.84
Therefore the expression gives -5.84
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Isabella rents an apartment for $1,500 a month and has a year's lease. She owns a car that is worth $16,700. She has a savings account of $4,950 and a credit card balance of $925. What is her net worth? Responses $18,895 $18,895 $-19,225 $-19,225 $19. 225 $19. 225 $1500
Isabella's net worth is $2,725. So, the correct answer is not $18,895 or $-19,225 or $19.225 or $1500.
It's important to understand that net worth is a measure of an individual's financial health and is a reflection of their financial standing at a given point in time. In Isabella's case, her net worth is positive, which indicates that she has more assets than liabilities. However, it's worth noting that her net worth does not take into account her income, expenses, or any other financial obligations or assets that she may have. Therefore, it's important to regularly review one's net worth and take steps to improve it over time.
To calculate Isabella's net worth, we need to add up all of her assets and subtract all of her liabilities:
Assets:
Car worth: $16,700
Savings account: $4,950
Total assets: $16,700 + $4,950 = $21,650
Liabilities:
Credit card balance: $925
Rent for the remainder of the lease: $1,500/month x 12 months = $18,000
Total liabilities: $925 + $18,000 = $18,925
Net worth:
$21,650 - $18,925 = $2,725
Therefore, Isabella's net worth is $2,725.
The correct answer is not $18,895 or $-19,225 or $19.225 or $1500.
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Answer: Hello sorry about the verified answer I got it wrong too but this is the answer. Have a great day!
3) Jane organized this stem and leaf plot to display recent temperatures. How many days of temperatures are displayed? A) 8 B) 9 C) 10 D) 12
The stem and leaf plot is an illustration of graphs and charts.
The number of days of temperatures displayed on the stem and leaf plot is 10
How to determine the number of days displayed?The stem and leaf plot is given as:
Stem Leaf
4 9
5 2 4 4 6 8
6 0 1
7 2 3
To determine the number of days, we simply count the number of leaves on the plot.
The leaves on the plot are:
Leaves: 9, 2, 4, 4, 6, 8, 0, 1, 2 and 3
The number of leaves is:
Count = 10
Hence, the number of days of temperatures displayed on the stem and leaf plot is 10
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What is x if 6x-7=13x+8
Answer:
\(-\frac{15}{7}\)
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
Answer:
it should be -\(\frac{15}{7}\)
Step-by-step explanation:
please help me answer this question asap
Answer:
It's quite easy
Step-by-step explanation:
people less than 30 years = frequency of people 0 to 15 + 15 to 30 = 8+15 =23
Therefore there are 23 people less than 30 years old.
pls mark me as brainliest pls.
For a standardized exam, it is known that the population mean score is 80 and the population standard deviation is 10. If the test is administered to 64 randomly selected individuals from this population, what is the probability that the sample mean will lie between 78 and 81
To find the probability that the sample mean will lie between 78 and 81, we need to calculate the z-scores corresponding to these values and then use the standard normal distribution to determine the probability.
The Central Limit Theorem states that when the sample size is large enough, the distribution of sample means will be approximately normally distributed, regardless of the shape of the population distribution. In this case, since the sample size is 64 (which is considered large), we can assume that the sample mean follows a normal distribution.
To calculate the probability, we first convert the sample mean values of 78 and 81 into z-scores using the formula:
z = (x - μ) / (σ / √n)
where x is the sample mean, μ is the population mean, σ is the population standard deviation, and n is the sample size.
For 78:
z = (78 - 80) / (10 / √64) = -2 / 1.25 = -1.6
For 81:
z = (81 - 80) / (10 / √64) = 1 / 1.25 = 0.8
We can then use a standard normal distribution table or a calculator to find the probability associated with these z-scores. The probability that the sample mean will lie between 78 and 81 is the difference between the cumulative probabilities corresponding to these z-scores.
P(78 ≤ x ≤ 81) = P(-1.6 ≤ z ≤ 0.8)
Using a standard normal distribution table or calculator, we can find the cumulative probabilities associated with these z-scores and calculate the probability.
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3(10)+5x=26
Answer this please!!
Answer:
=
4
-
5
Step-by-step explanation: