4.
How does the United Nations Development Program use its resources?
It provides health programs for mothers and children.
O It develops natural resources.
It works to eliminate poverty through development.
O It invests funds in industrialized nations.
Economic

Answers

Answer 1

Answer:

It develops natural resources.

It works to eliminate poverty through development.


Related Questions

A body of weight 200N is dropped from a certain height and it attains a maximum velocity before it hit the ground with this velocity it moves at a constant of proportionality 5kg/s .find
A, the terminal velocity
B.the height it moved ​

Answers

We can use the equations of motion and the concept of terminal velocity to solve this problem.

Let's start by finding the terminal velocity:

A. Terminal Velocity:

The terminal velocity is the maximum velocity that a falling object can reach when the resistance of the medium through which it is falling (such as air) is equal to the force of gravity acting on the object. At terminal velocity, the net force on the object is zero, so the object moves at a constant velocity.

We can find the terminal velocity using the equation:

vT = mg/k

where vT is the terminal velocity, m is the mass of the object, g is the acceleration due to gravity, and k is the constant of proportionality.

Given that the body has a weight of 200 N, its mass is:

m = F/g = 200 N/9.81 m/s^2 ≈ 20.38 kg

We are also given that the constant of proportionality is k = 5 kg/s.

Therefore, the terminal velocity is:

vT = mg/k = (20.38 kg)(9.81 m/s^2)/5 kg/s ≈ 39.77 m/s

B. Height Traveled:

Next, we can use the equations of motion to find the height that the body traveled before reaching terminal velocity. At the maximum velocity, the net force on the body is zero, so the body moves at a constant velocity. We can use the equation:

v^2 = u^2 + 2as

where v is the final velocity (terminal velocity), u is the initial velocity (which is zero), a is the acceleration, and s is the distance traveled.

We can rearrange this equation to solve for s:

s = (v^2 - u^2)/2a = v^2/2a

At terminal velocity, the acceleration is zero, so we can use the terminal velocity we found in part (A) to find the height traveled:

s = vT^2/2a = (39.77 m/s)^2/(2 × 0) = 794.60 m

Therefore, the height that the body traveled before reaching terminal velocity is approximately 794.60 meters.

From fastest to slowest, which of the following lists describes the speed at which sound tends to travel in different materials?
A. Gases, solids, liquids
B. Gases, liquids, solids
C. Solids, liquids, gases
D. Solids, gases, liquids

Answers

Answer:

C. Solids,Liquids, Gases

if a 5kg bowling ball and a 10kg bowling ball are both going 5 m/s which bowling ball has more konetic energy

Answers

Answer:

10kg bowling ball has more kinetic energy

6. a block of ice of 4 kg is at 0 C. what is the amount of heat to change this ice to water at
50 C

Answers

Hence, 1344 10 3 J of heat are needed to melt the ice. From 0°C to 4°C, heating water causes it to continuously contract rather than expand.

From where does energy come?

In accordance with the U.S. Energy Statistics Administration, coal, nuclear power, and natural gas made up the majority of the country's electrical generation in 2020. Renewable energy sources like wind, hydropower, solar, biomass, and geothermal are also used to generate electricity.

How does energy become made?

Using coal and oil, nuclear energy, biomass, geothermal, & solar thermal energy, steam turbines are used to produce the majority of the world's power. Gas turbines, hydroelectric turbines, wind turbines, & solar photovoltaics are some additional significant electricity generation systems.

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radioactivity is characterized by order kinetics, so the rate of decay in a particular sample the number of nuclei present.

Answers

Since the decay rate is dependent upon the number of radioactive atoms, in terms of chemical kinetics, one can say that radioactive decay is a first order reaction process.

What is radioactivity ?

Radioactive decay is the loss of elementary particles from an unstable nucleus, ultimately changing the unstable element into another more stable element. There are five types of radioactive decay: alpha emission, beta emission, positron emission, electron capture, and gamma emission. Each type of decay emits a specific particle which changes the type of product produced. The number of protons and neutrons found in the daughter nuclei (the nuclei produced from the decay) are determined by the type of decay or emission that the original element goes through.

Also, radioactive decay is an exponential decay function which means the larger the quantity of atoms, the more rapidly the element will decay. Mathematically speaking, the relationship between quantity and time for radioactive decay can be expressed in following way:

dN/dt=−λN

or more specifically

dN(t)/dt=−λN

or via rearranging the separable differential equation

dN(t)/N(t)=−λdt

by Integrating the equation

ln⁡N(t)=−λt+C

with

C is the constant of integration.N(t) is the amplitude of N after lapse of time t.λ is the decay rate constant.

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Two hockey pucks with mass 0.1 kg slide across the ice and collide. Before
the collision, puck 1 is going 15 m/s to the east and puck 2 is going 12 m/s to
the west. After the collision, puck 2 is going 15 m/s to the east. What is the
velocity of puck 1?

Answers

Answer:

Puck 1 = 12 m/s

Explanation:

Conservation of energy

KE_1a + KE_2a = KE_1b + KE_2b

(1/2)(0.1kg)(15m/s)^2 + (1/2)(0.1kg)(12m/s)^2 = (1/2)(0.1kg)(V)^2 + (1/2)(0.1kg)(15m/s)^2

V = 12m/s

Answer:

12 m/s west

Explanation:

just did it

Two hockey pucks with mass 0.1 kg slide across the ice and collide. Beforethe collision, puck 1 is going

A 4kg brick is dropped from the top of a building whose hight is 30m.what is the velocity with which it reaches the ground​

Answers

Answer:

=24.25 ^−1

Explanation:

Let   and   be initial and final velocity of the body respectively,  

be acceleration due to gravity ( 9.8^−2 ),  ℎ be the height of the body.

=0 ^ −1

ℎ=30

we know that, ^2−^ 2=2ℎ

^2=2∗9.8∗30

^2=588

=24.25 ^−1

What is the torque in ( lbs-ft ) of a man pushing on a wrench with 65 lbs of force 8 unches from the nut / bolt he is trying to turn?

Answers

Explanation:

The torque \(\tau\) is given by

\(\tau=Fd = (65\:\text{lbs})(\frac{8}{12}\:\text{ft}) = 43.3\:\text{lbs-ft}\)

Which increases the rate of soil formation?

A. mixed layers
B. more precipitation
C. cooler temperatures
D. very hard parent material

Answers

Answer:

a

Explanation:

Answer: b. more precipitation

Explanation:

Which increases the rate of soil formation?A. mixed layersB. more precipitationC. cooler temperaturesD.

If a body travelled a distance 's' in 't'.
What is the distance travelled in 't'​

Answers

Answer: Distance traveled in time t is s

Explanation: Self Explanatory

In an immersion measurement of an odd-shaped metal object, the weight of the object is found to be 980 N when submerged in water. When it is submerged in a heavier Bromine liquid (density 3100 kg/m3), the object weighs 840 N. What is the volume of this object

Answers

Answer: \(0.00680\ m^3\)

Explanation:

Given

The weight of the object, when submerged in the water is \(980\ N\)

When it is submerged in the bromine liquid, it weighs \(840\ N\)

Suppose,

\(\rho=\text{Density of object}\\\rho_w=\text{Density of water}\\\rho_b=\text{Density of bromine}\\V=\text{Volume of the object}\)

for water,

\(\Rightarrow V(\rho -\rho_w)g=980\quad \ldots(i)\)

For bromine

\(\Rightarrow V(\rho-\rho_b)g=840\quad \ldots(ii)\)

Divide (i) and (ii)

\(\Rightarrow \dfrac{\rho-1000}{\rho-3100}=\dfrac{980}{840}\\\\\Rightarrow 840\rho -840\times 1000=980\rho-980\times 3100\\\\\Rightarrow 140\rho=(3038-840)\cdot 1000\\\\\Rightarrow \rho=15,700\ kg/m^3\)

Put the density value in equation (i)

\(\Rightarrow V(15,700-1000)\cdot 9.8=980\\\\\Rightarrow V=\dfrac{100}{14,700}\\\\\Rightarrow V=0.00680\ m^3\)



How much kinetic energy does a 4.50kg block with a speed of 5.00m/s have?

Answers

Answer:

56.25J

Explanation:

Kinetic energy = 1/2 x 4.50 x (5.00)^2= 1/2 x 4.50 x (5.00 x 5.00)= 1/2 x 4.50 x 25Multiply through = 112.5/2= 56.25J

A bicycle camper rides from her starting point to her first campsite one day, then continues to a second campsite the next day. If her average speed for the two days equals the average of her speeds each day, what must be true about her journey?

Answers

Answer:

is there any more to this question

Explanation:

1. The Train Itself
It is late on an exhausting school night. You wake up to find yourself sitting in the car of a sleek and modern express subway train. The train signs indicate that it is a south-bound train. Its intended destination is downtown: 14th Street. You are no longer at John Jay College's uptown address; you are somewhere between 59th Street and 14th Street.
Inside the train, everything looks symmetric (the same, in a certain way). That is, seats face north, south, east and west; windows are arranged identically on all walls; neither the floor nor the ceiling is marked by any distinguishing features. You neither feel nor hear anything: no bumps, no lurches, no turns. None of your senses experience anything to indicate instability nor change. You do recognize that the train design seems quite technologically up-to-date.
The question is: Are you moving?
Some time later, you look through an arbitrary window and see a slew of tiny white lights rushing by. All the lights appear to move as one group. That is, they all appear to move at one speed and in one direction. You are just looking out the window for the first time, so you do know when, if ever, the lights had begun to behave in this manner.
2A) Draw a neat and clear sketch of what you see through the window.
2B) At this moment, are you moving?
a. Yes.
b. No.
c. Both yes and no.
d. Neither yes nor no.
e. Not enough information to choose any of the above.

Answers

Answer:

c. Both yes and no.

Explanation:

A uniform electric field ai + bj intersects a surface of area A. What is the flux through this area if the surface lies (a) in the yz plane? (b) in the xz plane? (c) in the xy plane?

Answers

Answer:

Explanation:

The electric flux through a surface is given by the dot product of the electric field and the area vector of the surface:

Φ = E · A

where Φ is the electric flux, E is the electric field, and A is the area vector of the surface.

(a) If the surface lies in the yz plane, its area vector is in the x direction. Therefore, the area vector can be written as A = Ax i, where Ax is the magnitude of the area. The electric field is given as E = ai + bj. Therefore, the flux through the surface is:

Φ = E · A = (ai + bj) · (Ax i) = aAx

(b) If the surface lies in the xz plane, its area vector is in the y direction. Therefore, the area vector can be written as A = Ay j, where Ay is the magnitude of the area. The electric field is given as E = ai + bj. Therefore, the flux through the surface is:

Φ = E · A = (ai + bj) · (Ay j) = bAy

(c) If the surface lies in the xy plane, its area vector is in the z direction. Therefore, the area vector can be written as A = Az k, where Az is the magnitude of the area. The electric field is given as E = ai + bj. Therefore, the flux through the surface is:

Φ = E · A = (ai + bj) · (Az k) = 0

since the dot product of perpendicular vectors is zero.

An electron with a velocity of 14.4 m/s in the positive y-direction enters a region where there is a uniform electric field of 201 N/C in the positive x-direction. The mass of the electron is 9.109 × 10−31 kg.

What is the y-component of the electron’s displacement 2.40 μs after entering the electric-field region if no other forces act on it in μm?

What is the x-component of the electron’s displacement 2.40 μs after entering the electric-field region if no other forces act on it in m?

Answers

1. The electron experiences acceleration and moves independently in the y-direction.

2. The y-component of the electron's displacement after 2.40 μs in the electric field is -8.11 μm.

3.  The x-component of displacement remains zero.

To calculate the y-component and x-component of the electron's displacement, we need to consider the motion of the electron in the electric field. Let's break it down step by step:

1. Acceleration of the Electron:

The electric field causes a force on the electron given by the equation: F = qE, where F is the force, q is the charge of the electron, and E is the electric field.

Since the charge of an electron is -1.6 × \(10^-^1^9\) C, and the electric field is 201 N/C, we can calculate the force:

F = (-1.6 × \(10^-^1^9\)C) * (201 N/C)

  = -3.216 × \(10^-^1^7\) N

Using Newton's second law, F = ma, we can find the acceleration (a) of the electron:

a = F / m

  = (-3.216 × \(10^-^1^7\) N) / (9.109 ×\(10^-^3^1\) kg)

  = -3.530 × \(10^1^3 m/s^2\)

2. Displacement in the y-direction:

Since no other forces act on the electron, its motion in the y-direction is independent of the electric field. The equation for displacement (y) under constant acceleration is:

y = (1/2) * a *\(t^2\)

Substituting the values, where the time (t) is 2.40 μs (2.40 ×\(10^-^6\) s), we can calculate the y-component of displacement:

y = (1/2) * (-3.530 ×\(10^1^3 m/s^2\)) * (2.40 ×\(10^-^6 s)^2\)

  = -8.11 μm

Therefore, the y-component of the electron's displacement 2.40 μs after entering the electric-field region is -8.11 μm.

3. Displacement in the x-direction:

Since the electron's velocity is only in the y-direction initially, the x-component of the displacement remains zero. Without any forces acting in the x-direction, the electron continues to move in the y-direction without changing its x-position.

Hence, the x-component of the electron's displacement 2.40 μs after entering the electric-field region is 0 meters.

Please note that the calculations provided are based on the given values and the provided formulas for displacement and acceleration.

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what apparatus is used to measure salt and water

Answers

Answer:

Salinometer, also called salinimeter or salimeter, device used to measure the salinity of a solution. It is frequently a hydrometer that is specially calibrated to read out the percentage of salt in a solution.

Explanation:

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have a great day ahead

In general, what do you think is the best way to enter a new market: acquisition, joint venture, or Greenfield investment? What location, firm, and industry characteristics would affect this decision? +

Answers

In general, the option that I think is the best way to enter a new market is option B: joint venture and the location should be in a remote place as well as a place that is close to available market.

Why is it vital to enter a new markets?

A person can get an edge over your rivals by entering new markets, especially emerging ones. You have the first-mover advantage and an opportunity to develop a brand presence as the go-to location if they don't already operate in that country. New locations, as indicated, also bring new opportunities.

Therefore , by expanding your firm into new markets entails finding niche product markets or adjacent sectors where you can prosper. To advance your firm in one or more ways, you need enter a new market.

To enter a new market, do the following:

Turnkey projects.Licensing.Franchising.Joint Venture.

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Several masses m are determined to be equal by comparing them on an equal-arm balance, and a large mass M is found to just balance two of the small ones on a similar balance. The mass M and one of the masses m are each forced to go around a bend of 1.0 m at a constant speed of 1.0 m/s. As they move around the curve their magnitudes of the forces acting on them are
Question 1 options:

a)

equal.

b)

in the ratio of 4:1.

c)

along the direction of motion.

d)

in the ratio of 2:1.

e)

zero.

Answers

Answer:

Option (d) is correct.

Explanation:

As the large mass M is found to just balance two of the small mass, m, so

\(M=2m\cdots(i)\)

As both the masses M as well as m are forced to go around a bend of 1.0 m at a constant speed of 1.0 m/s.

So, the radius of curvature of the bend (curved path), R= 1.0 m

The speed both the masses, v= 1.0 m/s.

Naturally, without any restriction, all the masses have the tendency to move in a straight line due to its inertia, but here both the masses are moving on the curved path because of the application of the external force on them. This continuous change in the direction is due to the force by the wall of the curved path which is actually the normal reaction by the wall on both the masses.

This reaction force, \(F_R\), balance the centrifugal force, F with which the masses have a tendency to go out of the path, the magnitude of this centrifugal force is,

\(F = \frac {mv^2}{R}\)

Where m is the mass of the body, v is the speed at that instant, R is the radius of curvature of the path.

So, \(F_R=\frac {mv^2}{R}\)

Now, for the small mass, m, the reaction force on it is

\(F_R1= \frac {mv^2}{R}\)

\(\Rightarrow F_R1= \frac {m(1)^2}{1}\)

\(\Rightarrow F_R1= m \cdots(ii)\)

And for the bigger mass, M, the reaction force on it is

\(F_R2= \frac {Mv^2}{R}\)

\(\Rightarrow F_R2= \frac {M(1)^2}{1}\)

\(\Rightarrow F_R2= M\)

By using equation (i), we have

\(F_R2= 2m\)

\(\Rightarrow F_R2=2F_R1\) [by using (ii)]

\(\Rightarrow F_R2 / F_R1 = 2/1\)

So, the ratio of force acting on the bigger mass M to the magnitude of the force acting on the smaller mas m is 2:1.

Hence, option (d) is correct.

A 0.056 kg sample of an unknown substance is heated to 89.6 °C in a hot water tube. It is then quickly removed and placed into an insulated jar holding 188 ml of water initially at 132.8° F. The final equilibrium temperature of the system is 67° C. What is the specific heat of this unknown substance?

Answers

The specific heat of the unknown substance is 6.84 J/gºC

How do I determine the specific heat capacity?

First, we shall convert 132.8° F to ° C. Thisis illustrated below:

Temperature (° F) = 132.8 ° FTemperature (° C) =?

°C = (°F − 32) × 5/9

°C = (132.8 − 32) × 5/9

°C = 56 °C

Next, we shall determine the heat absorbed by the water. This is illustrated below:

Volume of water (V) = 188 mLDensity of water (d) = 1 g/mLMass of water (M) = dV = 1 × 188 = 188 gInitial temperature (T₁) = 56 °CFinal temperature (T₂) = 67 °CChange in temperature (ΔT) = 67 - 56 = 11 °CSpecific heat capacity of copper (C) = 4.184 J/gºC Heat absorbed (Q) =?

Q = MCΔT

Q = 188 × 4.184 × 11

Q = 8652.512 J

Finally, we shall determine the specific heat capacity of the unknown metal. This can be obtained as follow:

Heat absorbed (Q) = 8652.512 JHeat released (Q) = -8652.512 JMass of unknown substance (M) = 0.056 kg = 56 gInitial temperature (T₁) = 89.6 °CFinal temperature (T₂) = 67 °CChange in temperature (ΔT) = 67 - 89.6 = -22.6 °CSpecific heat capacity of unknown substance (C) = ?

Q = MCΔT

-8652.512 = 56 × C × -22.6

-8652.512 = C × -1265.6

Divide both sides by -1265.6

C = -8652.512 / -1265.6

C = 6.84 J/gºC

Thus, the specific heat capacity is 6.84 J/gºC

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Which characteristic gives the most information about what kind of element an atom is ?

Which characteristic gives the most information about what kind of element an atom is ?

Answers

Answer:

The atomic number

Explanation:

Answer :

The atomic number

as a snowball its mass m decreases at a rate proportional to its surface area .The surface area of a snowball is directly proportional to m2/3

Answers

The initial condition is mathematically given as  t=0 and m=125 in the equation.

What is the initial condition?

The given problem tells us that

\(&\frac{d m}{d t} \infty m^{2 / 3}\\\)

because  mass m decreases at a rate proportional to its surface

the area so the constant of proportionality is negative

therefore we will take as a constant proportionality

Rewrite the given proportionality equation

\(&\frac{d m}{d t} \infty m^{2 / 3} \\\)

\(\frac{d m}{d t}=-k^2 m^{2 / 3}\)

\(\frac{d m}{m^{2 / 3}}=-k^2 d t\\\)

\(\int m^{-2 / 3} d m=-k^2 \int d t \quad \text\)

\(\frac{m^{-2 / 3+1}}{1-\frac{2}{3}}=-k^2 t+C_1 \quad\left\)

\(C_1=\text { intregal constant and } \int x^n d x=\frac{x^{n+1}}{n+1}\right]\\\)

\(&\Rightarrow 3 m^{1 / 3}=-k^2 t+C_1\\\\&\Rightarrow m^{1 / 3}=-\frac{k^2 t}{3}+\frac{C_1}{3}\\\\&\Rightarrow m^{1 / 3}=-\frac{k^2 t}{3}+C \quad \ldots\)

\(C=\frac{C_1}{3}\)

Now if at

t=0

the mass  m=125

\((125)^{1 / 3}=-\frac{k^2 \times 0}{3}+C\)

\(&\Rightarrow\left(5^3\right)^{1 / 3}=C\)

C=5

Substitute }

\(C=5 \text { in eq.(1) }\)

\(&m^{1 / 3}=-\frac{k^2 t}{3}+5\\\\&\Rightarrow m=\left(5-k^2 t / 3\right)^3\)

In conclusion, the initial condition should be  t=0 and m=125

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Two blocks, M = 14.2 kg and m = 4.73 kg, are connected via a massless rope. They are being pushed up a frictionless hill, with a slope of 15.80, with a constant force in the direction of the incline, such that there is a total acceleration of 2.53 m/s2 for the system

Answers

Slope is rise over run, meaning the ratio of the change in height to the change in horizontal distance. So a slope of 15.80 corresponds to an angle of ascension θ of

tan(θ) = 15.80   →   θ ≈ 86.38°

The order of the blocks (i.e. whether the large one is pulling the smaller one up or vice versa) does not matter, since friction is not a concern. So if we take the connected blocks as a single mass, by Newton's law we have a net force acting parallel to the incline of

F = P - (M + m) g sin(θ) = (M + m) a

(see the attached free body diagram)

where

P = magnitude of the push

g = 9.80 m/s²

a = 2.53 m/s²

and M and m are the given masses.

Then the system requires a push of

P = (M + m) (a + g sin(θ))

P = (14.2 kg + 4.73 kg) (2.53 m/s² + (9.80 m/s²) sin(86.38°))

P ≈ 233 N

If you have to find the tension in the rope, consider the free body diagram for one of the blocks. By Newton's second law, the net parallel force acting on, say, the larger block (if it's being pulled by the rope) is

F = T - M g sin(θ) = M a

where

T = tension in the rope

Then

T = M (a + g sin(θ))

T = (14.2 kg) (2.53 m/s² + (9.80 m/s²) sin(86.38°))

T ≈ 175 N

Two blocks, M = 14.2 kg and m = 4.73 kg, are connected via a massless rope. They are being pushed up

Explain the advantages in having the meter officially
defined in terms of the distance light travels in a
given time rather than as the length of a specific metal bar

Answers

Answer:

Thermal expansion causes the bar to expand in length (also, thermal contraction causes the bar to shrink). Having the meter measured in this way allows for consistency and can be easily converted.

Explanation:

5. How did your calculated final temperature compare with the actual temperature of the
air-metal mixture? Why or how did you make the prediction that you did?

Answers

To calculate the final temperature of an air-metal mixture, we need to use the principle of heat transfer.

The heat transfer equation states that the heat gained by the metal is equal to the heat lost by the air. This equation can be written as:

mcΔT = mairCpΔT

How to make prediction the of the final temperature?

To make a prediction of the final temperature, we need to consider factors such as the thermal conductivity of the metal and air, the specific heat capacities of the materials, and the heat transfer coefficients at the metal-air interface. Additionally, the shape and size of the metal object and the surrounding environment can affect the final temperature.

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he nucleus of 8Be, which consists of 4 protons and 4 neutrons, is very unstable and spontaneously breaks into two alpha particles (helium nuclei, each consisting of 2 protons and 2 neutrons). (a) What is the force between the two alpha particles when they are 6.60 ✕ 10−15 m apart? N (b) What is the initial magnitude of the acceleration of the alpha particles due to this force? Note that the mass of an alpha particle is 4.0026 u. m/s2

Answers

Answer:

A) F = 21.134 N

B) a = 3180.76 × 10^(24) m/s²

Explanation:

A) We are given;

Mass of alpha particle; m = 4.0026 u

Now, 1u = 1.66 × 10^(-27) kg

Thus; m = 4.0026 × 1.66 × 10^(-27)

Distance apart; r = 6.60 × 10^(−15) m

Charge on the alpha particle is;

q = 2e = 2 × 1.6 × 10^(-19) C

Formula for the force between the two alpha particles is;

F = kq1.q2/r²

k = 8.99 × 10^(9) N.m²/C²

q1 = q2 = 2 × 1.6 × 10^(-19) C

F = 8.99 × 10^(9) × (2 × 1.6 × 10^(-19))²/(6.60 × 10^(−15))²

F = 21.134 N

B) acceleration is given by;

a = F/m

Thus; a = 21.134/(4.0026 × 1.66 × 10^(-27))

a = 3180.76 × 10^(24) m/s²


for a certain chemical reaction, the reactants contain 52 kj of potential energy and the products contain 32 kj how much energy is absorbed or released by the reaction. A.84 kj is released B.20 kj is released C. 20 kj is absorbed D.84 kj is absorbed

Answers

B, is the answer. (20 kj is released)

Answer:

B. 20 kj is released

Explanation:

A.P.E.X. CST

A boat, whose speed in still water is 1.75 m/s, must aim upstream at an angle of 26.3° (with respect to a line perpendicular to the shore) in order to travel directly across the stream.
(a) Determine the speed of the current.
(b) Determine the resultant speed of the boat with respect to the shore.

(a) should be 0.7775 m/s
(b) should be 1.57 m/s (i’m looking for the explanation)

Answers

A boat must aim upstream at an angle of 26.3° (with respect to a line perpendicular to the coast) with respect to a line should be 1.57 m/s for a boat moving at 1.75 m/s in still water.

How come a line is perpendicular?

Perpendicular lines are two different lines that cross at a right angle of 90 degrees. Here, AB and XY connect at a 90-degree angle, making AB perpendicular to XY. The two lines do not intersect and run parallel to one another. They can't possible be compared side by side.

What is a perpendicular's form?

A form is considered perpendicular if at least two of its sides are 90 degrees from one another. Shapes with perpendicular sides include the following: Square. Rectangle.

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2) An object tied to the end of a string moves in a circle. The force exerted by the string
depends on the mass of the object, its speed, and the radius of the circle. What
combination of these variables expresses the relation?​

Answers

Answer:

Centripetal force formula

Explanation:

F = mv²

----

r

(a) Name a part of the electromagnetic spectrum with:
a longer wavelength than microwaves:
(i)
(ii) greater energy than X-rays:
(iii) a higher frequency than ultraviolet:

Answers

The answer is Gamma rays
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