4bags of cement do 18m2, how many m2 can be done with 7bags?

Answer:

Yes

Step-by-step explanation:

-53 is a rational no.

Pls mark as brainliest

To prove this identity, we start with Fermat's Little Theorem, which states that if p is a prime number and a is any integer coprime to p, then a^(p-1) ≡ 1 (mod p).

Using this theorem, we can rewrite the given identity as a^(p-1) * a(p-2) ≡ 1 (mod p^2).

Next, we can multiply both sides by a to get a^(p-1) * a(p-1) ≡ a (mod p^2).

Since a and p are coprime, we can use Euler's Totient Theorem, which states that a^φ(p) ≡ 1 (mod p) where φ(p) is the Euler totient function. Since p is prime, φ(p) = p-1, so a^(p-1) ≡ 1 (mod p).

Using this result, we can rewrite our identity as a^(p-1) * a(p-1) * a^-1 ≡ a^(p-1) ≡ 1 (mod p), which implies that a^(p-1) ≡ 1 (mod p^2).

Therefore, we have proven the identity a p(p−1) ≡ 1 (mod p 2 ), where a is coprime to p, and p is prime.

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a) To conduct a hypothesis test for the mean GPA, we can use the t-test function under STAT -> TEST in a calculator.

b) We are 95% confident that the true mean GPA of all college students at CSUEB is between 3.01 and 3.29.

a) Yes, the level of confidence used in constructing a confidence interval affects the width of the interval. A higher level of confidence results in a wider interval.

b) A 90% confidence interval is narrower than a 99% confidence interval for the same data because a higher level of confidence requires a wider interval to capture the true population mean with a higher probability.

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For the given data, we will use the t-test calculator function to determine the confidence interval for the mean grade point average at the university. Based on the sample data, we can be [Select] confident that the true mean grade point average at the university is between [Select] and [Select].

For the second part, the level of confidence chosen for creating a confidence interval will determine the width of the interval. However, the choice of the confidence level does not affect the construction of the interval. A 90% confidence interval will be narrower than a 99% confidence interval. A 90% confidence interval for the same data will be [Select] than a 99% confidence interval.

a) To calculate the confidence interval for the mean grade point average, we need to use the t-test calculator function since the population standard deviation is unknown, and the sample size is less than 30. We input the sample mean, sample standard deviation, sample size, and the desired level of confidence (e.g., 95%) into the calculator. The output will provide us with the lower and upper bounds of the confidence interval.

b) The level of confidence chosen for creating a confidence interval determines the probability that the true population mean falls within the interval. A higher confidence level will result in a wider interval since we need to be more certain that the true mean falls within the interval. However, the choice of the confidence level does not affect the construction of the interval.

To illustrate this, suppose we have a sample of exam times, and we calculate a 90% confidence interval and a 99% confidence interval for the mean exam time. The 90% confidence interval will be narrower than the 99% confidence interval since we are less certain that the true mean falls within the interval at the 99% confidence level.

Therefore, a 90% confidence interval for the same data will be [narrower] than a 99% confidence interval.

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The given statement is False. A test statistic based on point estimation is not used to construct the decision rule which defines the rejection region.

In hypothesis testing, a test statistic is calculated using sample data and a specific hypothesis to assess the strength of evidence against the null hypothesis. The decision rule, which determines whether to reject or fail to reject the null hypothesis, is based on the test statistic's distribution under the null hypothesis, rather than the point estimate itself.

The construction of the decision rule involves selecting a significance level (alpha), which represents the probability of rejecting the null hypothesis when it is actually true. The rejection region is determined based on the chosen significance level and the distribution of the test statistic. If the calculated test statistic falls within the rejection region, the null hypothesis is rejected; otherwise, it is not rejected.

Point estimation, on the other hand, is used to estimate an unknown parameter of interest, such as the population mean or proportion, based on sample data. It involves calculating a single value (point estimate) that represents the best guess for the parameter value. The point estimate is not directly involved in constructing the decision rule or defining the rejection region in hypothesis testing.

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False. A test statistic based on point estimation is not used to construct the decision rule that defines the rejection region.

The process of hypothesis testing involves constructing a decision rule to determine whether to accept or reject a null hypothesis based on sample data. The decision rule is typically defined using a critical region or rejection region, which is a range of values for the test statistic.

Point estimation, on the other hand, is a method used to estimate an unknown population parameter based on sample data. It involves calculating a single value (point estimate) that serves as an estimate of the population parameter.

While point estimation and hypothesis testing are both important concepts in statistics, they serve different purposes. Point estimation is used to estimate population parameters, whereas hypothesis testing involves making decisions based on sample data.

The decision rule for hypothesis testing is typically constructed based on the significance level (alpha) and the distribution of the test statistic, such as the t-distribution or the standard normal distribution. The test statistic is calculated using sample data and compared to critical values or calculated p-values to determine whether to reject the null hypothesis.

Therefore, the statement that a test statistic based on point estimation is used to construct the decision rule defining the rejection region is false.

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A relation R on Z is an equivalence relation if and only if it is reflexive, symmetric, and transitive. Specifically, in this case, xRy if and only if x^2+y^2 is even.

Reflexive: for any x in Z, x^2+x^2 is even, thus xRx. So, R is reflexive.

Symmetric: for any x,y in Z, if xRy, then x^2+y^2 is even, which implies y^2+x^2 is even, thus yRx. So, R is symmetric.

Transitive: for any x,y,z in Z, if xRy and yRz, then x^2+y^2 and y^2+z^2 are both even, thus x^2+z^2 is even, thus xRz. So, R is transitive.

Therefore, R is an equivalence relation.

To describe the equivalence classes, we need to find all the integers that are related to a given integer x under the relation R.

Let [x] denote the equivalence class of x.

For any integer x, we can observe that xR0 if and only if x^2 is even, which occurs when x is even.

Therefore, every even integer is related to 0 under R, and we have:[x] = {y in Z: xRy} = {x + 2k: k in Z}, for any even integer x.

Similarly, for any odd integer x, we can observe that xR1 if and only if x^2 is odd, which occurs when x is odd. Therefore, every odd integer is related to 1 under R, and we have:[x] = {y in Z: xRy} = {x + 2k: k in Z}, for any odd integer x.

In summary, the equivalence classes of R are of the form {x + 2k: k in Z}, where x is an integer and the parity of x determines whether the class contains all even or odd integers.

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Answer:

A:80 B:30

Step-by-step explanation:

A complete subset of X is one in which every Cauchy sequence in A converges to a limit A. A subset of R is complete if it contains all of its limits. The answer is the first and third subsets are complete.

Let's check each subset one by one: Subset 1.1: [3, ∞) Subset 1.1 is a closed set.

A sequence in [3, ∞) is bounded below by 3.

Thus, every Cauchy sequence in [3, ∞) has a limit in [3, ∞).

Hence, subset 1.1 is complete.

Subset 1.2: \({(-1)n + 1/n :nEN}\)

In a general metric space, this set is not complete.

Consider the sequence \({(-1)n + 1/n}\)

whose limit is 0.

It is easy to verify that it is Cauchy but its limit 0 is not in the set.

Subset 1.3: The set of irrational numbers

The irrational numbers in R are dense.

A dense set is one in which every non-empty open interval contains some elements of the set.

Since the rational numbers are dense, the irrational numbers are complete by Baire's Category Theorem.

Hence, subset 1.3 is complete.

So, the answer is the first and third subsets are complete.

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Answer:

88

Step-by-step explanation:

Step-by-step explanation:

The plant Cuscuta derives its nutrition from the host plant by sending its root-like structures into the stem or roots of the host plant to absorb water, mineral salts and food from it. This type of nutrition is known as Parasitic Nutrition.

Answer:

The plant Cuscuta derives its nutrition from the host plant by sending its root-like structures into the stem or roots of the host plant to absorb water, mineral salts and food from it. This type of nutrition is known as Parasitic Nutrition.

Answer:

240 N

Step-by-step explanation:

Resistance force (A) varies directly with the square of the speed (S).

A = k S²

At a certain speed (S = s), the resistance is A = 60.

60 = k s²

k = 60 / s²

At double the speed, (S = 2s), the resistance is:

A = k (2s)²

A = (60 / s²) (2s)²

A = (60 / s²) (4s²)

A = 240

So the system of linear equations representing this situation is A + S = 900 ,4A + 2.50S = 2820.

Let A represent the number of adult tickets sold.

Let S represent the number of student tickets sold.

From the given information the following equations:

Equation 1: The total number of tickets sold is 900.

A + S = 900

Equation 2: The total revenue from adult tickets (at $4 each) plus the total revenue from student tickets (at $2.50 each) is $2820.

4A + 2.50S = 2820

These equations represent the system of linear equations for this situation.

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Answer:

4 2/5 tons

Step-by-step explanation:

2/5 = 4/10 = .40

4.40 tons > 4.3 tons

Answer: 7%

(Hope this is right.)

Step-by-step explanation:

Let's solve this using the information we have and an equation.

Shane: $32,000 - (Given)

Theresa: 18,000+14x, if x=1,160 - (Given)

---------------------------------------------------------------

Step two: (Theresa) 14(1,160) =16,240 (Algebra)

Step three: (Theresa) 18,000+16,240=34,240 (Algebra, given.) - cost of Theresa's car.

---------------------------------------------------------------

Finally,

They're asking for how much more she paid for her car as a percentage of what Shane paid.

34,240-32,000=2,240 and

2,240/32,000=0.07

0.07x100=7

Answer 7% more than what Shane paid.

Answer:

120.25

Step-by-step explanation:

4 to the third power is 64. so 64 + 9 = 83. 20-8 = 18. 6 + 2 = 8.

so 83 + 18 + 8 = 109. so 8 divided by 18 = 2.25. 109 + 9 + 2.25 = 120.25.

Answer:

7 quarts and 1 pint

Step-by-step explanation:

2 pints is equal to a quart

15 pints divided by 2 is 7r1

7 is equal to 7 quarts and r1 is equal to 1 pint.

Answer:

Step-by-step explanation:

I assume that the last question should read "cosE"

Answer:cos

Step-by-step explanation:

The answer will be as follows after answering the supplied question As a coordinates result, Anew "'s ordered pair is (-1/2 * x, 1/2 * y).

In geometry, a coordinate system is a method that uses one or more numbers or coordinates to determine the precise arrangement of points or other geometrical objects on a manifold, such as Euclidean space. Coordinates are pairs of numbers that are used to locate a point or object on a two-dimensional plane. A point's location on a 2D plane is represented by two numbers known as the x and y coordinates. a set of digits that represent precise locations. Typically, the figure has two numbers. The first number represents the front-to-back distance, while the second number represents the top-to-bottom distance. As in (12.5), when there are 12 units below and 5 above.  

To conduct a dilation with a scale factor of 1/2 around the origin, multiply each point's coordinates by 1/2. If the initial coordinates of point A are (x,y), then the dilated point A' coordinates are:

A' = (1/2 * x, 1/2 * y)

We negate the x-coordinate while keeping the y-coordinate constant to represent the dilated point A' over the y-axis. As a result, the final coordinates of A" are:

A'' = (-1/2 * x, 1/2 * y)

As a result, Anew "'s ordered pair is (-1/2 * x, 1/2 * y).

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Given:

The expression is:

\(8x^4-2x\)

To find:

The coefficient and the exponent for each term of the given expression.

Solution:

Coefficients: In the product of s number and a variable, the number is coefficient of the variable.

Exponent: The number in the power is called exponent.

We have,

\(8x^4-2x\)

Here, the terms are \(8x^4,-2x\).

For the term \(8x^4\), the coefficient is 8 and the exponent is 4.

For the term \(-2x\), the coefficient is -2 and the exponent is 1.

Therefore, the coefficients are 8 and -2, and the exponent are 4 and 1.

The probability that a rises and b does not rise in price is: 24%

We can use conditional probability to solve this problem.

Let A = "fund a rises in price" and B = "fund b rises in price".

From the information provided, we know that:

Using the formula for conditional probability, we can find the probability that a occurs and b does not occur:

We don't know the probability of a, but we can find it using the formula for conditional probability and Bayes' theorem:

Substituting in the known probabilities:

Solving for P(A), we get:

Now we can use this value to find P(A and B'):

So, the probability that fund a rises in price and fund b does not rise in price is 0.24 or 24%.

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Answer:

144km^3

Step-by-step explanation:

\(V = (6)(6)(4)\\= 144 km^3\)

Answer:

3/20

Step-by-step explanation:

15 / 100

divide both the numerator and denominator by 5: 3 / 20

Answer:

3/20 is it's simplest form.

Step-by-step explanation:

How can we solve this?

15% is equal to 15/100.

Therefore, 15/100 can be simplified to 3/20.

The significance of the slope can be tested with a t-test, which is used to determine if there is a significant relationship between the independent variable and the dependent variable.

A bivariate hypothesis focused on a numeric independent variable and a numeric dependent variable could be tested with regression analysis, which is a statistical method used to model the relationship between variables.

The dependent variable is also known as the response variable, which is the variable that is being predicted or modeled, whereas the independent variable is the predictor variable, which is the variable that is used to make predictions about the dependent variable.

Regression analysis involves fitting a line or curve to the data points to find the relationship between the independent variable and the dependent variable.

The regression analysis provides a regression equation, which can be used to predict the value of the dependent variable for any given value of the independent variable.

The regression equation can also be used to test hypotheses about the relationship between the variables, such as whether the slope of the regression line is significantly different from zero.

The significance of the slope can be tested with a t-test, which is used to determine if there is a significant relationship between the independent variable and the dependent variable.

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Answer:

3.5

Step-by-step explanation:

-11-3, then that divided by -4.

Answer

1.1056 2.15 min

Step-by-step explanation:

I'm not too certain if the first one is asking for the speed but the second is 15 mins

where is the question i can't see

The correct option is B: V = π ∫[0,2] ((y + 2)/2 - 1)^2 dy

This integral will give us the Volume of the solid generated when region R is revolved about the vertical line x = 1.

The volume of the solid generated when region R is revolved about the vertical line x = 1, we can use the method of cylindrical shells.

The formula for the volume of a solid generated by revolving a region R about a vertical line is given by:

V = 2π ∫[a,b] x * f(x) dx

In this case, since we are revolving the region R about the vertical line x = 1, the limits of integration will be from y = 2 (where the horizontal line y = 2 intersects the graph y = 2x - 2) to y = 0 (where the graph y = 2x - 2 intersects the x-axis).

Let's analyze the options provided:

A. π ∫[1,2] ((y + 2)/2 - 1)^2 dy

B. π ∫[0,2] ((y + 2)/2 - 1)^2 dy

C. π ∫[1,2] (2 - (2x - 2))^2 dy

D. π ∫[0,2] ((y + 2)/2)^2 - 1^2 dy

Option A: The limits of integration are incorrect. We need to integrate with respect to y, not x.

Option B: This appears to be the correct integral setup, integrating with respect to y and using the correct limits of integration.

Option C: This option incorrectly uses the expression (2 - (2x - 2))^2, which doesn't match the function y = 2x - 2.

Option D: The limits of integration are incorrect. We need to integrate from y = 2 to y = 0.

Therefore, the correct option is B:

V = π ∫[0,2] ((y + 2)/2 - 1)^2 dy

This integral will give us the volume of the solid generated when region R is revolved about the vertical line x = 1.

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Answer:

1 inch

Step-by-step explanation:

hshuehevdjdbevejdj

Answer:

18

Step-by-step explanation24/0.75 is 18

Answer:

18

Explanation:

Not sure what you mean by AGONSA but the method to get 18 is;

\(\frac{24}{1} *\frac{3}{4} = \frac{72}{4} = 18\)

Answer: 9/15, 16/25, 3/4 and 5/6.

Step-by-step explanation:

From the question, we have been given four fractions which are 3/4, 5/6, 16/25 and 9/15. We are told to write them in order starting from the smallest. For this to be done, we will have to change the fractions to percentages. This will be:

3/4 = 3/4 × 100 = 75%

5/6 = 5/6 × 100 = 83.3%

16/25 = 16/25 × 100 = 64%

9/15 = 9/15 × 100 = 60%

From the above percentages, arranging the fractions from the smallest will be:

9/15, 16/25, 3/4 and 5/6.