47=3-6y I can't do it some one helpppppp

Answer:

1. D

2. C

3. C, A F

Step-by-step explanation:

The number of megafilns-per-strord should be smaller than the number of filns-per-strord since a mega is a conversion factor of 10³ and is greater than 1, hence 1 megafiln is greater than 1 filn.

(a) The given units can be converted as follows: 6 glints = 1 filn...

(1)12 grees = 1 zool...

(2)2 grees = 10 twibbs...

(3)5 grees = 1 bic...

(4)Note that the grees are in both the numerator and denominator of the second unit conversion factor (3). Hence we can cancel out the grees by using it twice in the numerator and denominator. Now using the given conversion factors in equation (1), we get:

7 glint/twibb=7 glint/ (10 grees/2 grees)=14 glint/10 grees=14 glint/ (5 grees/12 grees)=16.8 filn/strord

(b) We need to convert the result of part (a) from filn/strord to megafiln/strord.

1 mega = 106

Thus 1 megafiln = 106 filn

16.8 filn/strord = (16.8 filn/strord) x (1 megafiln/106 filn) = 1.68 x 10-5 megafiln/strord

The number of megafilns-per-strord should be smaller than the number of filns-per-strord since a mega is a factor of 10³ and is greater than 1, hence 1 megafiln is greater than 1 filn. Similarly, going 1 foot-per-hour would mean going a smaller number of feet-per-hour than going 1 mile-per-hour since there are 5280 feet in a mile.

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Answer:

im learning the same thing

The equation of a line that is perpendicular to y=-(3)/(4)x+9 and goes through the point (6,4) is y = 4x/3 - 14/3.

Given line is y = -(3)/(4)x+9

We know that if two lines are perpendicular to each other, the product of their slopes is equal to -1.Let the required equation of the line be y = mx+c.

Therefore, the slope of the line is m.To find the slope of the given line:y = -(3)/(4)x+9

Comparing it with the general equation of a line:y = mx+c

We can say that slope of the given line is -(3/4).

Therefore, slope of the line perpendicular to the given line is: -(1/(-(3/4))) = 4/3

Let the equation of the perpendicular line be y = 4/3x+c.

Therefore, we have:4 = 4/3 * 6 + c4

= 8 + cC

= 4 - 8

= -4

Therefore, the equation of the required line is:y = 4x/3 - 14/3.

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Answer:

Transversal

Step-by-step explanation:

By finding the side length of the square, we will see that the area is 20 square units.

For a square of side length S, the area is:

A = S^2

In this case, the side length of the square will be the distance between two consecutive vertices, so we can say that S is the distance between points G and O.

Remember that the distance between two points (x₁, y₁) and (x₂. y₂) is:

\(d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\)

So the distance between the points G(1, 0) and O(5, 2) is:

\(S = \sqrt{(5 - 1)^2 + (2 - 0)^2} = \sqrt{20}\)

Then the area of this square is:

\(A = S^2 = (\sqrt{20})^2 = 20\)

The area is 20 square units.

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Answer:

B

Step-by-step explanation:

To make it easy

In 612 different ways can the three lions and three tigers walk if no two lions are the same and no two tigers are the same.

An arrangement of objects where the order in which the objects are selected does not matter.

When no two lions are the same and no two tigers are the same, there are a total of 6! = 720 possible ways to arrange the lions and tigers in a row.

Subtract the number of arrangements where the three lions are walking next to each other.

Three ways to arrange the lions together, and then there are 3! = 6 ways to arrange the three lions within that group.

The remaining three animals (the tigers) can be arranged in 3! = 6 ways. Therefore, there are 3 x 6 x 6 = 108 arrangements where the lions are walking next to each other.

Total number of arrangements where no two lions are the same and no two tigers are the same, and where the lions are not walking next to each other.

720 - 108 = 612

Hence, In 612 different ways can the three lions and three tigers walk if no two lions are the same and no two tigers are the same.

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Answer:

It's B, because thats where the two points cross

Step-by-step explanation:

Thus, there are over 2 trillion ways for Mavis to move each counter to an adjacent square without having any of them end up in the same square.

There are several ways Mavis can move each counter to an adjacent square, but the question is how many ways can she do this without having two counters end up in the same square.

First, let's consider the top row of the board. There are 7 counters, and each counter has two adjacent squares that it can move to.

However, the counter on each end only has one adjacent square to move to. So, the total number of ways to move the counters in the top row without any of them ending up in the same square is:

2 x 2 x 2 x 2 x 2 x 2 x 1 = 64

Now, let's consider the second row. There are also 7 counters in this row, but the two end counters now have two adjacent squares to move to.

However, there is a new constraint: each counter in the second row must move to a square that is not occupied by a counter in the top row.

This means that the first and last counters in the second row each have three possible squares to move to, while the other five counters each have two possible squares to move to.

So, the total number of ways to move the counters in the second row without any of them ending up in the same square is:

3 x 2 x 2 x 2 x 2 x 2 x 3 = 288

We can continue this process for each row, taking into account the constraints of not having any counters end up in the same square and not moving to squares already occupied in the previous row.

In the end, the total number of ways Mavis can move the counters to adjacent squares is the product of the number of ways for each row:

64 x 288 x 288 x 288 x 288 x 288 x 64 = 2,051,717,760,000

So, there are over 2 trillion ways for Mavis to move each counter to an adjacent square without having any of them end up in the same square.

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Answer:

$-105.00

Step-by-step explanation:

375.00 - 160.00 = 215.00

215.00 - 160.00 = 55.00

55.00 - 160.00 = -105.00

Answer:

160×3=480 and

375-480= -105

Answer:

36 dollars per person and they all will pay 2 dollars each the large group will hit a wall

Answer:

Kym is wrong because instead of 25% it would be 50 percent

Step-by-step explanation:

Answer:

Sample Response: The ratio of boys to total students was 25:50. Written as a fraction, this is 25/50. Rewrite the fraction with a denominator of 100 to 50/100. So 50% of the students were boys.

You might wanna change up some words so the teacher doesn't know your cheating lol

Answer:

100 cars

Step-by-step explanation:

Alex: Pete

7:        3

Multiply by x to get the number of cars

Alex  has 7x cars

Pete has 3x cars

Now Alex gives pete 20

Alex has 7x-20

Pete has 3x+20

They have the same number of cars so set the expressions equal

7x-20 = 3x+20

Subtract 3x from each side

7x-20-3x = 3x+20-3x

4x-20 = 20

Add 20 to each side

4x-20+20 = 20+20

4x= 40

Divide by 4

4x/4 = 40/4

x = 10

Alex had 7x = 7*10 = 70 to start

Pete had 3x = 3*10 = 30 to start

Together 70+30 = 100 cars

Answer:

100 cars

Step-by-step explanation:

Alex: Pete

7:        3

Multiply by x to get the number of cars

Alex  has 7x cars

Pete has 3x cars

Now Alex gives pete 20

Alex has 7x-20

Pete has 3x+20

They have the same number of cars so set the expressions equal

7x-20 = 3x+20

Subtract 3x from each side

7x-20-3x = 3x+20-3x

4x-20 = 20

Add 20 to each side

4x-20+20 = 20+20

4x= 40

Divide by 4

4x/4 = 40/4

x = 10

Alex had 7x = 7*10 = 70 to start

Pete had 3x = 3*10 = 30 to start

Together 70+30 = 100 cars

On solving the provided question we can say that the equation gives us  101.77 mi S; 63.59 mi W and S 39.4° W; 131.7 nautical miles

An equation is a mathematical formula that connects two assertions using the equal sign (=) to denote equivalence.

The ship will have traveled 120 nautical miles in the six hours between noon and six o'clock using the formula distance = speed time distance (20 nm/h) (6 h).

The location of the ship will be in (S, W) coordinates.

\(120(cos(32), sin(32)) ≈ 120(0.848048, 0.529919) ≈ (101.77, 63.59)\)

The ship will have traveled 101.77 miles south and 63.59 miles west.

83.59). The distance from port will be ...

\(d = √(101.77^2 +83.59^2) = 131.7\\ arctan(83.59/101.77) ≈ 39.4\)

The bearing and distance are ...

S 39.4° W

131.7 nautical miles

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Answer:

280 students

111 non students

Step-by-step explanation:

number of students (S)

number of non students (N)

S+N=391     S=391-N

4S+6N=1786

substitute S

4(391-N)+6N=1786

1564-4N+6N=1786

subtract 1564 from each side

2N=222

N=111

S=391-111=280

Check the picture below.

Answer:60 3/4

Step-by-step explanation: 4 1/2 times 2 1/4 = 10 1/8

4 1/2 times 3 = 13 1/2

3 times 2 1/4 6 3/4

Answer:

54353456452

Step-by-step explanation:

364564

Step-by-step explanation:

Answer is 1, because, your multiplying 1  12 times, so it is

1*1*1*1*1*1*1*1*1*1*1*1=1

even if it was 1 to the power of 100, it's still going to be 1, if the base number is 1, then exponent can be any number and still getting 1.

The probability of both events occurring is P(A ∩ B) = P(A)P(B) = 0.16^2 = 0.0256.

The event of getting a "2" and the event of getting a "5" on the first roll of a die are mutually exclusive events because they cannot both occur in the same trial. The probability of either of these events occurring is P(A) = 0.16, and the probability of both events occurring at the same time is P(A ∩ B) = 0.00.

The event of getting a "2" on the first roll and the event of getting a "5" on the second roll of a die are independent events. This can be confirmed using the formula P(A ∩ B) = P(A)P(B). The probability of getting a "2" on the first roll is P(A) = 0.16 and the probability of getting a "5" on the second roll is P(B) = 0.16. Thus, the probability of both events occurring is P(A ∩ B) = P(A)P(B) = 0.16^2 = 0.0256.

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The effect estimation requires more than simple regressions of "Quality of Care" on "Shift Hours" (Part 1) or with "Hospital Characteristics" (Part 2). Including "Tiredness" (Part 3) or using variable (Part 5) is necessary.

To estimate the causal effect of changing shift hours on quality of care, several factors must be considered. Regression analysis with just a constant and "Shift Hours" (Part 1) fails to account for confounding variables, leading to biased estimates. Including "Hospital Characteristics" (Part 2) still overlooks omitted variable bias and endogeneity issues.

However, by adding "Tiredness" to the regression (Part 3), the direct and indirect effects of shift hours on quality of care can be estimated. The coefficient of "Shift Hours" represents the direct causal effect, while the coefficient of "Tiredness" captures the mediating effect. Regressing "Quality of Care" solely on "Policy" (Part 4) neglects confounders.

When "Hospital Characteristics" are unobserved, instrumental variable estimation (Part 5) can address endogeneity by identifying an instrumental variable unrelated to quality of care but affecting shift hours.

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Given:

Radius of a circle = 21 m

Area of a sector of the circle = 27.72 m²

To find:

The angle at the center of the circle.​

Solution:

The area of a second is:

\(A=\pi r^2\times \dfrac{\theta}{360^\circ}\)

Where, r is the radius of the circle and \(\theta\) is the central angle.

Putting \(\pi=\dfrac{22}{7},\ r=21,\ A=27.72\) in the above formula, we get

\(27.72=\dfrac{22}{7}\times (21)^2\times \dfrac{\theta}{360^\circ}\)

\(27.72=1386\times \dfrac{\theta}{360^\circ}\)

\(27.72=3.85^\circ \times \theta\)

\(\dfrac{27.72}{3.85^\circ }=\theta\)

\(7.2^\circ=\theta\)

Therefore, the central angle of the sector is \(7.2^\circ\).

In a standard normal distribution, the mean is 0 and the standard deviation is 1.

Then, according to the normal table, the probability of gettin z < 0.18 is given by the area on the left of z = 0.18 in the graph related to the distribution. Then we have: P (z < 0.18) = 0.5714

Answer:

4(h+3) = 20

Step-by-step explanation:

Para empesar, disculpa si mi español no es perfecto, pero igual me encataria a ayudarte.

Pues, se sabe que estas temporadas de practica vienen en groupitos de horas a la ves. Dijo que cada dia, ella practica por alguans horas, las cuales suman a 20 en total. Como la problema nos dice que ella practica 4 veces a la semana, tienemos 4 de estos groupitos de horas. Por eso, la respuesa es 4(h+3) = 20, porque ella va por estas 4 temporadas de practicar 3 horas en la manana y quien sabe cuantos en la tarde. Addicionalmente, este"quien sabe" numero de horas se representa con h.

Answer:

x=17 and y=23 DONT SUE ME IF I GET THIS WRONG PLZZ ;-;

Step-by-step explanation:

Answer:

(1, - 1 )

Step-by-step explanation:

Given the 2 equations

3x - 2y = 5 → (1)

4x + 3y = 1 → (2)

Multiplying (1) by 3 and (2) by 2 and adding the result will eliminate y- term

9x - 6y = 15 → (3)

8x + 6y = 2 → (4)

Add (3) and (4) term by term to eliminate y

17x + 0 = 17

17x = 17 ( divide both sides by 17 )

x = 1

Substitute x = 1 into either of the 2 equations and solve for y

Substituting into (2)

4(1) + 3y = 1

4 + 3y = 1 ( subtract 4 from both sides )

3y = - 3 ( divide both sides by 3 )

y = - 1

solution is (1, - 1 )

Step-by-step explanation: