4 Two friction disks A and B are to be brought into contact withoutslipping when the angular velocity of disk A is 240 rpm counterclockwise. Disk A starts from rest at time t = 0 and is given a constantangular acceleration with a magnitude α. Disk B starts from rest attime t = 2 s and is given a constant clockwise angular acceleration,also with a magnitude α. Determine (a) the required angular acceleration magnitude α, (b) the time at which the contact occurs

The frequency at which the capacitive reactance is 375 ω and the Capacitance of 3.25 μF is 131 s⁻¹.

Capacitance is the ability or capacity of the substance to collect and store electrical energy and the unit of capacitance is Farad (F). Capacitive reactance is the term that measures the opposition to current flow in the AC circuits and the unit of capacitive reactance is the ohm(Ω).

From the given,

The capacitive reactance (Xc) = 375ω

capacitance (C) = 3.25μF

capacitive reactance Xc = 1/(2π×f×C)

Frequency (f) = 1/(2π×Xc×C)

                     = 1/(2×3.14×375×3.25×10⁻⁶)

                     = 131 s⁻¹.

Thus, the frequency of the capacitive reactance is 131 s⁻¹.

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Answer:

Gases obey the ideal-gas law at high temperatures and low pressures.

Explanation:

Answer:

0.82

Explanation:

constant velocity.means acceleration a = 0, so net force = 0

F - μmg = ma = 0

so μ = F/(mg) = 200/(25*9.8) = 0.82

Answer:

t=8

Explanation:

u have solution I give solution also

don't mark plzz follow y

Answer:

Oh! I just learned abt this

Explanation:

the body is said to be in equilibrium if it is resting or moving with uniform velocity.

Answer: The body is said to be in balance if it is at rest or moving at a uniform speed. In other words, if the body's linear and angular acceleration is zero, the body is said to be in balance. 1

=> A.) 6

Explanation:

=> 6 molecules of water are recycled into one molecule of glucose during photosynthesis.

6CO2 + 6H2O + light energy → C6H12O6 + 6O.

The luminosity of this star in units of the solar luminosity would be: 483.7L.

To calculate the luminosity, we would use the different values given and the formula for luminosity.

Temperature = 9305K

Star's radius = \(5.90 * 10^{9} m\\\)

Luminoisty of the star

Luminosity of the sun

= \(\frac{4π * (5.90 * 10^9)^2 * 5.67 * 10^-8 * 9305^4 W}{3.846 * 10^26 W}\)

= 483.7L

This is the unit for luminosity.

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the force the woman exerts to do a push-up at constant speed is 333 N.

the work the woman does is 152 J.

her useful power output is 76 W.

(a) To calculate the force the woman exerts to do a push-up, we need to use torque methods. The woman is doing a push-up at constant speed, which means that the net torque on her body is zero. The only torque acting on her body is due to her weight W, which acts at the center of mass of her body. The distance between her center of mass and her hands is 0.76 m, and the angle between her body and the horizontal is 45 degrees.

The torque due to her weight about her hands is given by:

τ = r x W = (0.76 m) x (cos 45°)(W)

where r is the distance between her hands and her center of mass and cos 45° is the component of the distance perpendicular to the weight vector. Since the woman is at constant speed, the torque she exerts about her hands must be equal and opposite to the torque due to her weight. Therefore:

τ = (0.76 m)(cos 45°)(W) = (1/2)(W)(0.76 m)

Solving for W, we get:

W = 2(τ/0.76 m) = 2[(0.5)(mg)(0.76 m)/(0.76 m cos 45°)] = 333 N

Therefore, the force the woman exerts to do a push-up at constant speed is 333 N.

(b) The work the woman does is equal to the change in her potential energy as her center of mass rises. The woman's mass is not given, so we will assume a value of 60 kg. The gravitational potential energy of the woman is given by:

U = mgh

where m is the mass of the woman, g is the acceleration due to gravity (9.81 m/s^2), and h is the height her center of mass rises (0.26 m). Therefore:

U = (60 kg)(9.81 m/s^2)(0.26 m) = 152 J

Therefore, the work the woman does is 152 J.

(c) The useful power output of the woman is the work she does per unit time, taking into account the work done in lowering her body. Each push-up involves two phases: lifting her body and lowering her body. When she lowers her body, the work done is negative, as the force she exerts is in the opposite direction to the displacement. The work done in lowering her body is equal to the work done in lifting her body, so the total work done in one push-up is zero.

The woman does 30 push-ups in 1 minute, which means she does one push-up every 2 seconds. Therefore, the useful power output of the woman is:

P = (152 J)/(2 s) = 76 W

Therefore, her useful power output is 76 W.

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The speed of the roller coater at the bottom of the hill is 31 m/s.

Apply the principle of conservation of mechanical energy as follows;

K.E(bottom) = P.E(top)

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

v = √(2 x 9.8 x 49)

v = 31 m/s

Thus, the speed of the roller coater at the bottom of the hill is 31 m/s.

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Answer:

light reflects when it hits the surface

Explanation:

Youngs double slit is a evidence for wave nature,

The properties refraction are attributed as properties of waves. The phenomena of interference and diffraction also fall in this category.

So,

     the answer must be B

Answer: Light does not need a medium to travel.

Explanation: I took the test and got it right :]

No, the quantity of kinetic friction on a moving item is not affected by its speed.

The consistency of the speed is more crucial than the actual speed. As was mentioned the friction force needs to be cancelled out by a constant force. The applied force would be equal to the kinetic friction force if the motion was constant in speed.

Therefore, the kinetic friction coefficient is not affected by the relative speeds of the two objects. The types of surfaces in contact are the sole factors that affect the coefficient of kinetic friction.

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The physics behind the movement of electric charges between parallel plates is based on the principles of electrostatics. Electric charges are either positive or negative, and they are affected by electric fields.

Electric fields are created by a difference in electric potential, which is measured in volts. When a voltage is applied to a set of parallel plates, the charges within the plates will be affected by the electric field, and will move in response to it.

When a voltage is applied to a set of parallel plates, the positive charges in the plate connected to the positive voltage will be attracted to the negative voltage, while the negative charges in the plate connected to the negative voltage will be attracted to the positive voltage.

The movement of charges between the plates is also affected by the presence of any obstacles or resistances in the electric field, such as resistance in the wire. This can slow down the movement of charges and result in a decrease in the current flowing through the circuit.

In all, the movement of charges between electric parallel plates is the result of the electric field created by a difference in electric potential, and the movement of charges is called drift velocity. The movement is also affected by the presence of resistance.

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The coefficient of volume expansion of the liquid, βliquid is 2.24 * 10⁻⁴ (C°)⁻¹.

The coefficient of volume expansion of the liquid is determined as follows:

Let the initial volume of the object be V₀

The change in the volume of the object will be ΔV

The expression for the change in the volume of the object when the temperature of the object changes by ΔT is:

ΔV = βV₀ΔT

where;

β is the coefficient of volume expansion

The data provided is as follows;

The initial volume of liquid and aluminum can, V₀ = 7.0 * 10⁻⁴ m³

The coefficient of volume expansion for aluminum = 69 x 10⁻⁶ (C°)⁻¹

The volume of liquid that spilled out, ΔV = 7.8 * 10⁻⁶ m³

Change in temperature, ΔT = (78 - 6)°C

ΔT = 72 °C

The difference between the change in volume of the liquid and the can is equal to the amount of liquid that spilled out.

ΔV = (βV₀ΔT)liquid - (βV₀ΔT)can

βliquid = ΔV/V₀ΔT + βcan

βliquid = (7.8 * 10⁻⁶ m³) / (7.0 * 10⁻⁴ m³ * 72 °C) + 69 x 10⁻⁶ (C°)⁻¹

βliquid = 2.24 * 10⁻⁴ (C°)⁻¹

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From a position on the ground, a ball is thrown 36 m/s vertically upward. The speed of the falling ball is given by v = -9.8 (m/s2) t j.

The ball is going upward, even if its upward motion is occurring at a lower velocity. In light of this, the ball's velocity is also positive. The gravitational force is what causes the acceleration that the body experiences. From the top of a multi-story building, a ball is hurled vertically and at a speed of 20 meters per second. The ball is thrown from a location that is 25 meters above the ground in height.

The greatest height of the ball can be calculated using the vertical motion model, h=-16t2 + vt+s, where v is the initial velocity in feet/second and s is the height in feet. From the top of a multi-story building, a ball is hurled vertically and at a speed of 20 meters per second.

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Answer:

R_total = 14.57 Ω ,  V_C = 1.176 V

Explanation:

To solve this circuit we are going to find the equivalent resistance of each branch, let's remember

* Serial resistance  

         \(R_{eq}\) = ∑ \(R_{i}\)

* For resistance in parallel

        1 / R_{eq} = ∑ 1/R_{i}

We solve the two branches of the wheatstone bridge

Series resistors

Branch B

         R_B = Rb + R4

         R_B = 2 + 18

         R_B = 20 Ω

Branch C

         R_C5 = Rc + R5

         R_C5 = 3 + 12

         R_C5 = 15 Ω

Resistance in parallel R_B and R_C5

         1 / R_BC = 1 / R_B + 1 / R_C5

          1 / R_BC = 1/20 + 1/15 = 0.116666

          R_BC = 8.57 Ω

Now we have a single branch, we solve the series resistance

          R_total = R_A + R_BC

          R_total = 6 + 8.57

          R_total = 14.57 Ω

b) they ask us for the voltage in the resistance R_C

Let's remember that the voltage in a series circuit is the sum of the voltages

           10 = V_a + V_BC

           10 = i R_a + i R_BC = i (R_a + R_BC)

           i = 10 / (R_a + R_BC)

           i = 10 / (14.57)

           i = 0.6863 A

The current in the series circuit is constant

          V_BC = i R_BC

          V_BC = 0.6863 8.57

          V_BC = 5.8819 V

This voltage is divided in the bridge, for the two branches in parallel it is the same, but the resistance is different in each branch.

     Branch C

             V_BC = i R_C5

             i = V_BC / R_C5

             i = 5.8819 / 15

             i = 0.39213 A

In this branch we have two resistors in series, let's remember that the current in a series circuit is constant

             V_C = i R_C

              V_C = 0.39213 3

              V_C = 1.176 V

With an initial horizontal velocity of 32.31 m/s and a time of 3.23 seconds to impact the earth, the projectile was launched.

When an object is hurled horizontally in projectile motion, it has zero initial vertical velocity and only a horizontal initial velocity. Through the projectile's entire motion, the original horizontal velocity is maintained.

\(y = 1/2 * a_y * t^2\)

\(t^2 = 2y / a_y\)

\(t = sqrt(2y / a_y)t = sqrt(2*75.72 m / 9.81 m/s^2)\)

t = 3.23 s (rounded to two decimal places)

\(x = vi_x * t\)

\(vi_x = x / t\)

\(vi_x = 104.42 m / 3.23 s\)

\(vi_x = 32.31 m/s\)(rounded to two decimal places)

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Answer:Total Inductive reactance XL =538.63 Ω

Explanation:

Parallel combination for Effective inductance is calculated as

L total =  \(\frac{1}{1/L1 + 1/L2 + ... 1/Ln}\)

=\(\frac{1}{1/5 + 1/2}\)

\(\frac{1}{0.2 + 0.5 \\}\)

=\(\frac{1}{0.7}\)

=1.42857H

Inductive reactance XL = 2 πFL

where f= frequency= 60Hz

L=  Effective inductance=1.42857H

Inductive reactance , XL = 2 X 3.142 X 60 X 1.42857

=538.63Ω

This bone can only tolerate 0.0405 mm of compression before it snaps.

The Young's modulus.

The ratio of tensile stress to tensile strain is a feature of the material that expresses how easily it can stretch and bend.

A modulus function is a function that provides a number or variable's absolute value. It generates the size of the number of variables.

The modulus operator, which can be used with any two accessible operands, is an addition to the C arithmetic operators. In order to obtain a result, it divides the supplied numerator by the supplied denominator. In other words, it results in a remainder for the integer division.

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Answer:

=55.21 is the answer.........

Complete Question

The image for this question is shown on the first uploaded image

Answer:

\(v = 3.4 \ m/s\)

Explanation:

From the question we are told that

   The mass of the collar is  \(m = 2 \ kg\)

    The original length is  \(L = 3.0 \ m\)

     The spring constant is  \(k = 3.0 \ N/m\)

Generally the extension of the spring  is  mathematically evaluated as

        \(e = 4 -3 = 1 \ m\)

Now with Pythagoras theorem we can obtain the length from A to B as

        \(AB = \sqrt{5 ^2 + 4^2}\)

       \(AB = 6.4 \ m\)

The  extension of the spring at B is  

     \(e_b = 6.4 - 3 = 3.4 \ m\)

According to the law of energy conservation

   The energy stored in the spring at point A +  the kinetic energy of the  spring =  The  energy stored on the spring at B

So

     \(\frac{1}{2} * k * e + \frac{1}{2} * m* v^2 = \frac{1}{2} * k * e_b\)

substituting values

    \(\frac{1}{2} * 3 * 1^2 + \frac{1}{2} * 2* v^2 = \frac{1}{2} * 3 * 3.4^2\)

=>   \(v = 3.4 \ m/s\)

If Vector G and H lie in the xy plane with magnitudes of 45 meters and 66 meters respectively. the cross product of G and H is a vector that has a magnitude of approximately 364.6 square meters and points in the negative z direction.

In this case, since G and H lie in the xy plane, their cross product will be a vector that points in the z direction (perpendicular to the xy plane). To determine the magnitude of this vector, we can use the formula:

|G × H| = |G| |H| sin(θ)

where θ is the angle between the two vectors. Since G and H make angles of 55 degrees and 70 degrees, respectively, with the positive x-axis, the angle between them is 70 - 55 = 15 degrees.

Plugging in the given magnitudes and angle, we get:

|G × H| = (45 m) (66 m) sin(15°) ≈ 364.6 m^2

Therefore, the magnitude of the cross product is approximately 364.6 square meters. To determine the direction, we use the right-hand rule as described above. Since G makes an angle of 55 degrees with the positive x-axis, we can write it as:

G = 45 cos(55°) i + 45 sin(55°) j

Similarly, H can be written as:

H = 66 cos(70°) i + 66 sin(70°) j

Using these expressions and the right-hand rule, we find that the direction of the cross product is in the negative z direction, so the resulting vector is:

G × H = -364.6 k

where k is the unit vector in the positive z direction. Therefore, the cross product of G and H is a vector that has a magnitude of approximately 364.6 square meters and points in the negative z direction.

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Answer:

thermal energy

Explanation:

Answer:

thermal energy

Explanation:

Answer:

S = Vy t + 1/2 g t^2 = 1/2 g t^2    vertical speed with zero initial speed

t = (2 S / g)^1/2      with g = 32 ft/sec^2

t = (900 / 32)^1/2 = 5.30 sec    time to reach ground

V = a t = 32 ft/s^2 * 5.30 s = 170 ft/sec

170 ft/sec / (88 ft/sec / 60 mph) = 116 mph           since 88 ft/sec = 60 mph

The package strike the ground relative to the point directly below it was released at 213.3m.

Given values,

Velocity of plane 45 m/s

Acceleration due to gravity 9.8 m/s²

horizontal component of plane velocity is

ux = 45 m/s

Vertical component is zero

In the same way

ay = - 9.8  m/s²

ax = .0 m/s^2

Motion in y direction = -110 m

From equation of motion time of flight is

d = u x t + 1/2 at²

where,

d is distance

u is velocity initial

a is acceleration

t is time

So, putting values

-110 = 0 + 1/2 (-9.8)t²

-110 = -4.9t²

t² = 110 / -4.9

t² = 22.45

t = √22.45

t = 4.74

Motion in x direction,

d = u x t + 1/2 at²

d = ( 45 x 4.74) + 1/2 (0) 4.74²

d = 213.3 + 0

d = 213.3m

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At the top the forces on the mass are the weight and the tension. Then by Newton's second law we have that the total force Fc is:

Therefore the answer is b.

Solving Gaussian integration with polar coordinates involves converting the integral into polar coordinates, finding the mean and standard deviation of the function, substituting them into the Gaussian distribution formula, and integrating it over the range of the function in polar coordinates.

Gaussian integration with polar coordinates is the process of finding the integral of a function using polar coordinates and the Gaussian distribution. The polar coordinate system is a two-dimensional coordinate system that uses the radius and angle to locate a point in a plane. The Gaussian distribution is a probability distribution that is often used to describe random variables in statistics.
To solve the Gaussian integration with polar coordinates, we need to convert the integral into polar coordinates. The conversion is done using the following equations:
x = r cos(θ)
y = r sin(θ)
r² = x² + y²
θ = tan⁻¹(y/x)
Once the integral is converted into polar coordinates, we can use the Gaussian distribution to solve it. The Gaussian distribution is given by the following formula:
f(x) = (1/σ√(2π))e^(-(x-μ)²/2σ²)
where μ is the mean of the distribution and σ is the standard deviation. To use this formula, we need to first find the mean and standard deviation of the function we are integrating.
After finding the mean and standard deviation, we can substitute them into the Gaussian distribution formula and integrate it over the range of the function in polar coordinates. The result of the integration will be the value of the integral.
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To determine the magnitude of the lift force ⃗ and the force of air resistance ⃗ acting on the jet, we need to resolve the weight ⃗ and the forward thrust ⃗ into their horizontal and vertical components.

The weight ⃗ can be resolved into two components:

- the vertical component, Wsin(30°), acting downward

- the horizontal component, Wcos(30°), acting to the left

The forward thrust ⃗ can also be resolved into two components:

- the vertical component, Tsin(30°), acting upward

- the horizontal component, Tcos(30°), acting to the right

Since the jet is flying at a constant speed, the lift force ⃗ must be equal in magnitude to the weight component acting downward, Wsin(30°). Therefore, the magnitude of ⃗ is 86,500 Nsin(30°) = 43,250 N.

The force of air resistance ⃗ is equal in magnitude to the horizontal component of the weight, Wcos(30°), minus the horizontal component of the forward thrust, Tcos(30°). Therefore, the magnitude of ⃗ is (86,500 Ncos(30°)) - (103,000 Ncos(30°)) = -8,715 N, where the negative sign indicates that the force of air resistance is acting in the opposite direction to the motion of the jet.

Therefore, the magnitude of the lift force ⃗ is 43,250 N and the magnitude of the force of air resistance ⃗ is 8,715 N.

Answer:

  4.617 s

Explanation:

The speed of 60 mi/h can be converted to m/s:

  (60 mi/h) × (1609.344 m/mi) × (1 h)/(3600 s) = 26.8244 m/s

The relationship between speed and acceleration is ...

  v = at

  t = v/a = (26.8244 m/s)/(5.81 m/s²) ≈ 4.617 s

It will take the car 4.617 seconds to reach 60 mi/h starting from rest.

Answer:

4.62 s

Explanation:

We have 3 known variables and 1 unknown variable that we want to solve for.

Convert 60 mi/h to m/s.

Use the kinematic equation that contains all four of these variables.

It takes the car 4.62 seconds to reach a velocity of 60 mi/h (26.82 m/s) if it starts from rest.

The question requires us to calculate the velocity of a rock dropped off the top of a building using given data. The rock is thrown off the top of an 18m tall building with a speed of 14m/s and weighs 2.5kg. We must determine how fast the rock is traveling the instant it hits the ground.

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