4. how does the intensity of a linearly polarized electromagnetic wave relate to its electric field?

Answers

Answer 1

The intensity of a linearly polarized electromagnetic wave is directly proportional to the square of its electric field amplitude.

The electric field of a linearly polarized electromagnetic wave can be represented by a sine or cosine function, where the amplitude of the wave represents the maximum value of the electric field.

The intensity of the wave is proportional to the average power per unit area that is carried by the wave.

Mathematically, the intensity (I) of an electromagnetic wave is given by the formula:

I = (1/2)εcE0^2

where ε is the electric constant (approximately equal to 8.85 x 10^-12 F/m), c is the speed of light in a vacuum (approximately equal to 3.00 x 10^8 m/s), and E0 is the amplitude of the electric field.

From this formula, it is clear that the intensity of the wave is proportional to the square of the electric field amplitude.

Therefore, if the electric field amplitude of a linearly polarized electromagnetic wave is increased by a factor of 2, the intensity of the wave will increase by a factor of 4 (i.e., 2 squared).

Similarly, if the electric field amplitude is decreased by a factor of 2, the intensity of the wave will decrease by a factor of 4.

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Related Questions

Gases, just like liquids are made of particles which can be further classified as atoms or molecules,
True
False

Answers

Answer:

True

Explanation:

Solids, Liquids, and Gases are all make up of atoms and molecules.

A common black ant discovers a piece of bread 85 cm east of the entrance of her nest. If the ant carries 10 bits of bread back to her nest on separate trips before moving on to other chores, what distance did she travel after discovering the bread? What was her displacement from the nest after dropping up the last bit of bread?

Answers

Answer:

19 x 85 = 1,615 for distance. Displacement is 0

Explanation:

The total distance traveled by the ant in 9 round trips and one 1/2 trip, or 19 one bash way trips: 19 x 85cm = 1615cm. The displacement of the ant after the tenth trip is 0 cm ( the displacement origin is the nest.)

A humpback whale dove beneath the ocean's surface, and 310 seconds later it sang to
another whale that was 1,800 meters away. The song's sound wave traveled at a constant
velocity of 1,500 meters per second toward the other whale. How much time did it take the
sound wave to travel from one whale to the other?

Answers

The sound wave took 1.2 seconds to travel from one whale to the other.

Velocity is a physical quantity that describes the rate of change of an object's position with respect to time and includes both the speed and direction of motion. It is a vector quantity, meaning it has both magnitude and direction and is typically measured in meters per second (m/s) or other appropriate units.

The time it took for the sound wave to travel from one whale to the other can be calculated using the formula:

time = distance/velocity

In this case, the distance between the whales is 1,800 meters and the velocity of sound in water is 1,500 meters per second. Therefore:

time = 1,800 meters / 1,500 meters per second

time = 1.2 seconds

Hence, The distance between the two whales was covered by the sound wave in 1.2 seconds.

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Can you think of how a ball made of iron that floats on water

Answers

A ball made of iron typically sinks in water because the density of iron is greater than that of water. However, if we want to explore a scenario where an iron ball floats on water, we can consider two possible scenarios:

Hollow Iron Ball: If the iron ball is hollow, it can be designed in a way that the overall density of the ball is less than that of water. This can be achieved by adjusting the thickness and volume of the hollow portion. By making the ball buoyant, it will float on the water's surface.

Composite Ball: Another possibility is to create a composite ball using iron and materials with lower density. By combining iron with materials like foam or lightweight metals, the overall density of the ball can be reduced, allowing it to float on water.

It's important to note that both scenarios involve altering the properties of iron or combining it with other materials to achieve buoyancy. In reality, a solid iron ball would sink in water due to its high density.

a 9.25 cm -diameter toy top has a moment of inertia of 0.000412 kg m2 about its rotation axis. a string is wrapped around the outside edge of the top. the string is long enough to wrap around the top at least five whole turns. to get the top spinning, its string is pulled with a constant tension of 0.49 n. the tension force is tangent to the circular top.

Answers

The time taken to complete its first five revolutions is 1.07 seconds.

We need to know about torque to solve this problem. Torque is the rotational equivalent of linear force. It can be determined as

τ = F x r

where τ is torque, F is perpendicular force and r is radius.

Torque is also can be calculated by the moment of inertia

τ = I . α

where I is moment of inertia and α is angular acceleration.

From the question above, the parameters given are

F = 0.49 N

I = 0.000412 kgm²

d = 9.25 cm

r = 0.04625 m

N = 5 turns

Find the angular acceleration

τ = τ

I . α = F x r

0.000412 . α = 0.49 . 0.04625

α = 55.01 rad/s²

Find the displacement of total revolution (θ)

θ = N . 2π

θ = 5 . 2π

θ = 10π rad

Find the time taken

θ = 1/2 . α . t²

10π = 1/2 . 55.01 . t²

t² = 1.14

t = 1.07 seconds

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How long was a 50 W lightbulb left on for if 500,002 J were burned?

Answers

" 50 W " means " 50 Watts "  or  " 50 Joules per second ".

(500,002 J) / (50 J/sec)  =  10,000.04 seconds

(That's 2 hours 46 minutes 40.04 seconds.)

Which of the following Resistors A, B, C or D, would use the least power? Make
your claim, give evidence and explain your reasoning. You may use math to support
your claim.
Please Help.

Which of the following Resistors A, B, C or D, would use the least power? Makeyour claim, give evidence

Answers

i think the answer is D 10.0

What is the net force if you pull a cart to the right with 5N of
force and a friend pushes the left to the left with 5 N of force

Answers

Answer:

In this case the net force is zero.

According to Newton's third law of motion: For every action, there is an equal and opposite reaction. In this case the net force is zero.

Explanation:

Hope this helps!! :)

2) a negatively charged particle is moving to the right, directly above a wire having a current flowing to the right, as shown below. in which direction is the magnetic force exerted on the particle? 2) a) out of the page b) upward c) downward d) into the page e) the magnetic force is zero since the velocity is parallel to the current.

Answers

If a negatively charged particle is moving to the right, the current in the wire also flows to the right, then the direction of the magnetic field will be upward due to maxwell's right-hand thumb rule.

Maxwell's Right-Hand Rule of Thumb:

Following this rule, imagine grasping a live wire with your right hand, with your thumb pointing in the direction of the current. The direction in which the finger grips the wire is the magnetic field lines around the wire. The right-hand rule used to find the direction of the magnetic field due to the current element is the direction of the magnetic field.

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A truck heading east has an initial velocity of 6 m/s. It accelerates at 2 m/s2 for 12 seconds. What distance does the truck travel in the given time?Paco was driving his scooter west with an initial velocity of 4 m/s. He accelerates at 0. 5 m/s2 for 30 seconds. What is his final velocity?

Answers

The distance the truck travel in given time is 216 m and the final velocity of acceleration at 0.5m/\(s^{2}\) for 30 seconds is 19 m /s

The following question has two parts

For part 1 we need to calculate the distance covered by the truck in 12 seconds

We know that

 s = ut + \(\frac{1}{2}a .t^{2}\) . . . . . . .  . . . . .(1)

where s = distance travelled

           u = initial velocity

           a = acceleration

           t  =  time in seconds

Now , As per the question

u = 6 m/s

a = 2 m/\(s^{2}\)

t  = 12 seconds

Putting the values in the equation (1)

                          s = 6 X 12 + \(\frac{1}{2}\) X 2 X 144

                          s = 72 + 144

                          s = 216 m

Therefore the distance travelled is 216 m

For part 2 we need to calculate the final velocity that Paco was driving

We know that

v = u + at . . . . . . . . . . .  .(2)

where v = final velocity

          u = initial velocity

          a = acceleration

           t = time in seconds

As per the question,

u = 4m/s

a = 0.5 m/\(s^{2}\)

t = 30 seconds

Putting in equation (2)

                                      v = 4 + 0.5 X 30

                                      v  =  4 + 15

                                      v = 19 m/s

Therefore the final velocity is 19 m/s

Therefore , the distance the truck travel in given time is 216 m and the final velocity of acceleration at 0.5m/\(s^{2}\) for 30 seconds is 19 m /s

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The final velocity of the scooter is 19 m/s.

Given:

Initial velocity of truck, u = 6 m/s

Acceleration of truck, a = 2 m/s²

Time taken by the truck, t = 12 s

Formula used:

s = ut + 1/2 at²

Where,

s = Distance travelled

u = Initial velocity

a = Acceleration

t = Time taken

Substituting the given values in the above formula, we get:

s = ut + 1/2 at²

 = 6(12) + 1/2 × 2 × (12)²

 = 72 + 1/2 × 2 × 144

 = 72 + 144

 = 216 m

Therefore, the truck travels 216 m in the given time.

Given:

Initial velocity of scooter, u = 4 m/s

Acceleration of scooter, a = 0.5 m/s²

Time taken by the scooter, t = 30 s

Formula used:

v = u + at

Where,

v = Final velocity

u = Initial velocity

a = Acceleration

t = Time taken

Substituting the given values in the above formula, we get:

v = u + at

 = 4 + 0.5 × 30

 = 4 + 15

 = 19 m/s

Therefore, the final velocity of the scooter is 19 m/s.

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A box of mass m hangs by a string from the ceiling of an elevator that is accelerating upward.1) Which of the following best describes the tension T in the string?T < mgT = mgT > mg2) A block sits at rest on a horizontal frictionless surface. Which of the follwoing sketches most closely resembles the correct free body diagram for all forces acting on the block. Each red arrow represents a force.A,B,C, or D?3) Briefly describe the forces represented by each of the arrows in your choice for the above question.

Answers

A is the correct answer. The arrow pointing up in A represents the force of gravity (mg).

What is force?

Force is an external influence that can change the motion, direction, shape, and/or energy of a physical object. It can be a push, a pull, or a twist, and it can act on an object at a distance. Force is a vector quantity, meaning that it has both magnitude and direction.

The arrow pointing to the right represents the normal force (N), which is the force that the surface exerts on the block in order to keep it from sinking into the surface due to gravity. The arrow pointing down in A represents the frictional force (f), which is the force that the surface exerts on the block in order to prevent it from sliding along the surface.

1)

T > mg

The force due to tension acts upwards on the box and the force due to gravity acts downwards on the box. As the box is accelerated upwards then the T should be greater than the weight of the box.

ma = T - mg

mg = T- ma

Therefore, T> mg

2)

The option A, best describes the free body diagram.

3) In option A, the normal force is equal to the weight of the block which is kept at rest. N = mg

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what will happen to the rigid bar acb upon the temperature increase? multiple choice it will rotate around c in the clockwise direction and come back first to the original position. it will rotate around c in the clockwise direction. it will rotate around c in the counterclockwise direction first and come back to the original position. it will rotate around c in the counterclockwise direction. it will remain at the original place.

Answers

Upon increasing the temperature, the rigid bar ACB will experience thermal expansion, which may cause it to rotate. So, the correct answer is: "It will rotate around C in the clockwise direction."


As the temperature increases, the bar ACB will expand due to thermal expansion. This expansion will cause the bar to rotate around point C.

Since the expansion occurs along the length of the bar, end A will move away from C, causing the bar to rotate in a clockwise direction. The bar will not return to its original position unless the temperature is decreased, and it contracts back to its initial length.

In summary, upon temperature increase, the rigid bar ACB will rotate around point C in the clockwise direction due to thermal expansion.

So, the correct answer is: "It will rotate around C in the clockwise direction."

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If the thumb and finger each squeeze with a force Ft = Ff = 10.0 N, what force do the forceps jaws exert on the plastic rod?
Express your answer to three significant figures and include the appropriate units.

If the thumb and finger each squeeze with a force Ft = Ff = 10.0 N, what force do the forceps jaws exert

Answers

Answer:

FJ = 31.48N

Explanation:

In this case you have that the torque exerted by each, thumb and finger, over the point P, is equal and opposite by the torque exerted by each Jaw.

You equal one of the torque produced by your hand, as for example, the torque of the finger, with the torque produced by one jaw:

\(\tau_F=\tau_J\\\\F_Fd_1=F_Jd_2\)         (1)

FF: finger force = 10.0N

FJ: jaw force = ?

d1: distance from finger to point P = 8.50cm = 0.085m

d2: distance form the border of the Jaws to the point P = 2.70cm = 0.027m

You solve the equation (1) for FJ and replace the values of the other parameters:

\(F_J=\frac{F_Fd_1}{d_2}=\frac{(10.0N)(0.0850m)}{0.027m}=31.48N\)

The force exerted by each jaw is 31.48N

The force that the forceps jaws exert on the plastic rod will be 31.48N.

From the information given, the following can be depicted:

d1 = 8.50cm = 0.085md2 = 2.70cm = 0.027mFf = 10NFj = Unknown

Therefore, the jaw force will be calculated thus:

Fj = (Ff × d1) / d2

Fj = (10 × 0.085) / 0.027

Fj = 31.48N

Therefore, the jaw force is 31.48N.

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a piece of beeswax of density 0.95g/cm3 and mass 190g is anchored by a 5cm length of cotton to a lead weight at the bottom of a vessel containing brine of density 1.05g/cm3 .If the beeswax is completely immersed, find the tension in the cotton in Newtons.​

Answers

To find the tension in the cotton, we need to consider the forces acting on the beeswax.

Given:
Density of beeswax (ρ_beeswax) = 0.95 g/cm^3 = 950 kg/m^3 (converting to kg/m^3)
Mass of beeswax (m_beeswax) = 190 g = 0.19 kg
Length of cotton (L) = 5 cm = 0.05 m
Density of brine (ρ_brine) = 1.05 g/cm^3 = 1050 kg/m^3 (converting to kg/m^3)

Let's analyze the forces acting on the beeswax when it is completely immersed in the brine.

The upward buoyant force on the beeswax is equal to the weight of the displaced brine. The weight of the beeswax is acting downwards.

Weight of the beeswax (F_weight_beeswax) = mass of beeswax * acceleration due to gravity
F_weight_beeswax = 0.19 kg * 9.8 m/s^2 = 1.862 N

The volume of the beeswax (V_beeswax) can be calculated using the formula:
V_beeswax = m_beeswax / ρ_beeswax
V_beeswax = 0.19 kg / 950 kg/m^3 = 0.0002 m^3

The volume of the displaced brine is equal to the volume of the beeswax.

The buoyant force (F_buoyant) on the beeswax is given by:
F_buoyant = ρ_brine * g * V_beeswax
F_buoyant = 1050 kg/m^3 * 9.8 m/s^2 * 0.0002 m^3 = 2.058 N

Since the cotton is anchored to the lead weight, the tension in the cotton (T_cotton) is the difference between the weight of the beeswax and the buoyant force acting on it:

T_cotton = F_weight_beeswax - F_buoyant
T_cotton = 1.862 N - 2.058 N
T_cotton ≈ -0.196 N

The negative value indicates that the tension in the cotton is acting upward (opposite to the weight of the beeswax). However, it is important to note that a negative tension value does not have a physical interpretation in this context. It implies that the cotton is not under tension and may be slack in this scenario.

Therefore, the tension in the cotton is approximately 0 N (or negligible tension).

suppose that a body on the surface of a fictional planet named freya, which has the same radius as earth, weighs 4 times more than it does on earth. what is the mass ????f of freya in terms of earth’s mass ????e?

Answers

On the fictional planet Freya, which has the same radius as Earth, a body weighs 4 times more than it does on Earth. To determine the mass of Freya in terms of Earth's mass, we can use the concept of gravitational force.

The gravitational force acting on an object is given by the formula F = (G × m1 × m2) / r², where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between the centers of the objects.
Since the radius of Freya is the same as Earth, we can assume the distance between the object and the center of Freya is the same as the distance between the object and the center of Earth. Therefore, the distance cancels out in the equation.
Let's assume the mass of the body on Earth is me and the mass of Freya is mf. According to the problem, the weight of the body on Freya is 4 times its weight on Earth.
Weight is given by the formula W = m × g, where W is the weight, m is the mass, and g is the acceleration due to gravity. On Earth, the acceleration due to gravity is approximately 9.8 m/s².
So, we have 4me × g = mf × g.
Canceling out the acceleration due to gravity, we get 4me = mf.
Therefore, the mass of Freya (mf) is 4 times the mass of Earth (me).

In other words, the mass of Freya is 4 times the mass of Earth.
In terms of mathematical notation, we can express this as mf = 4 × me.
In conclusion, the mass of Freya is 4 times the mass of Earth.
The mass of Freya (mf) is 4 × the mass of Earth (me).

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A block of mass m1 = 14.4 kg is on a frictionless table to the left of a second block of mass m2 = 20.2 kg, attached by a horizontal string (see the figure below).

(a) If a horizontal force of 1.53 ✕ 102 N is exerted on the block m2 in the positive x-direction, use the system approach to find the acceleration (in m/s2) of the two blocks.

(b) What is the tension (in N) in the string connecting the blocks?

A block of mass m1 = 14.4 kg is on a frictionless table to the left of a second block of mass m2 = 20.2

Answers

(a) The acceleration (in m/s²) of the two blocks is 4.42 m/s².

(b) The tension (in N) in the string connecting the blocks is 63.65 N.

What is the acceleration of the blocks?

The acceleration of the blocks is determined by applying Newton's second law of motion as shown below.

F(net) = ma

where;

F(net) is the net force on the blocksm is the mass of the blocksa is the acceleration of the blocks

F = m₁a + m₂a

F = a(m₁ + m₂)

a = F/(m₁ + m₂)

where;

a is the common acceleration of the blocksm₁ is the mass of the first block = 14.4 kgm₂ is the mass of the second block = 20.2 kgF is the applied force on the blocks = 153 N

a = (153) / (14.4 + 20.2)

a = 4.42 m/s²

The tension (in N) in the string connecting the blocks is calculated as follows;

T = m₁a

T = 14.4 x 4.42

T = 63.65 N

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in a closed container filled with gas, what happens to the pressure as the volume of the container increases?

Answers

According to Boyle's Law, as the volume of a closed container filled with gas increases, the pressure will decrease.

According to Boyle's Law, which describes the relationship between the pressure and volume of a gas at constant temperature, the pressure of a gas will decrease as the volume of the container increases, assuming the amount of gas and temperature remain constant.

Boyle's law can be stated mathematically as:

P1 × V1 = P2 × V2

where:

P1 and V1 = initial pressure and volume of the gas

P2 and V2 = final pressure and volume of the gas.

As the volume increases (V2 > V1), the equation shows that the pressure (P2) must decrease to maintain the equality. In other words, if the volume of the container increases, the pressure will be decreased, assuming the temperature and the amount of gas remain constant.

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Can someone please give me the (Answers) to this? ... please ...

I need help….

Can someone please give me the (Answers) to this? ... please ...I need help.

Answers

Note : Please discard your other answers as they are incorrect. I have personally solved this problem and have attached the appropriate image.

Have a blessed day, if you have any follow-up questions please reach out!

Stay safe!

- Robert

Can someone please give me the (Answers) to this? ... please ...I need help.

describe how you could measure the magnetic force due to an external uniform magnetic field using magnets and a scale

Answers

By carefully following these steps and recording the necessary measurements, you can estimate the magnetic force due to the external uniform magnetic field using magnets and a scale.

To measure the magnetic force due to an external uniform magnetic field using magnets and a scale, you can perform the following experiment:

Materials needed:

1. Two magnets (with known magnetic field strengths)

2. A scale (preferably a sensitive one)

3. Non-magnetic support or stand

4. String or thread

5. Ruler or measuring tape

Procedure:

1. Set up the experiment by attaching one of the magnets to a non-magnetic support or stand so that it is suspended freely.

2. Tie a string or thread to the magnet in such a way that it hangs vertically down.

3. Place the scale underneath the magnet, making sure it is directly below the magnet's center of gravity.

4. Record the initial position of the magnet on the scale.

5. Bring the other magnet, which has a known magnetic field strength, close to the suspended magnet.

6. Gradually increase the distance between the two magnets while observing any movement of the suspended magnet.

7. Take note of the position of the magnet on the scale when it reaches equilibrium (where the magnetic force and gravitational force balance out).

8. Measure the distance between the magnets using a ruler or measuring tape.

9. Repeat the experiment several times with different distances between the magnets, ensuring that the magnets and the scale are in the same orientation each time.

10. Calculate the magnetic force between the magnets using the equation for the magnetic force between two magnets, which is given by the product of their magnetic field strengths divided by the square of the distance between them.

11. Plot a graph of the magnetic force against the distance between the magnets.

12. Using the graph, extrapolate the magnetic force for a distance of 0 (when the magnets are in direct contact) to determine the magnetic force due to the external uniform magnetic field.

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Describe the difference between potential and kinetic energy

Answers

Answer:

Explanation:

Kinetic energy involves motion so something that is not moving has zero kinetic energy.

Potential energy does not involve motion and is based on position in a field like gravity and magnetic.

1. How much heat energy ( Q ) is required to heat 2.0 kg of copper from 30.0 oC to 80.0 oC?

Answers

Answer:

38500

Explanation:

I looked it up so it may be wrong

If u have it, u want to share it. If u share it u dont have it.
what is it?​

Answers

I think its a secret!!

Answer:

uhh, uhh i think it's a carrot?

nah a secret

Explanation:

SOMEONE ANSWER ME ASAPPP ILL GIVE U BRAINLIEST ANSWER

Options are
a)6.5km
b)9.0km
c)10.5km
d)2.5km

SOMEONE ANSWER ME ASAPPP ILL GIVE U BRAINLIEST ANSWEROptions are a)6.5kmb)9.0kmc)10.5kmd)2.5km

Answers

Answer:

2.5 km because displacement is xf -xi

xf = 2.5

xi= 0

2.5 - 0 =2.5 km

Kory was on the porch when a loud sound caught his attention. Looking up, he saw a red car spinning across the intersection and a white car stopped in the intersection. He knew the typical sequence of events for a car collision involved two vehicles moving at speed. As he tried to make sense of the scene, he filled in missing details that he had not actually observed. This will likely result in:

Answers

The information illustrates that this will likely result in schema distortion.

What is schema?

It should be noted that schema simply means a mental model of an object that includes knowledge, beliefs, and expectations.

In this case, the information illustrates that this will likely result in schema distortion. This led to the missing details.

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Un prisma rectangular con un volumen de 80 m^3 se sumerge hasta la mitad en agua, calcular la fuerza de empuje que recibe.(rho_(del agua)=1000 kg/m^3)

Answers

Answer:

400 kN

Explanation:

El principio de Arquímedes establece que, cuando un cuerpo está total o parcialmente sumergido en un fluido, experimenta un empuje hacia arriba que es igual al peso del fluido desplazado.

Dado que;

Volumen del bloque = 80m ^ 3

Densidad del agua = 1000 kg / m ^ 3

Empuje hacia arriba = 1/2 * 80 * 1000 * 10

Empuje hacia arriba = 400 kN

Two coils A and B are wound side by side. Coil A has 8120 turns and coil B has 11842 turns. 54% of flux produced by coil A links coil B. A current of 6 A in coil A produces 0.02 mWb, while the same current in coil B produces 0.078 mWb. a) Calculate the mutual inductance and the coupling coefficient. b) Calculate the emf induced in coil B when the current is reversed in 0.015 seconds.

Answers

a) Mutual inductance = 0.108 H; Coupling coefficient = 0.482. b) - 4.95 V.


a) Mutual inductance, M between coil A and coil B can be given as:

M = k√(L_AL_B) here, k is the coupling coefficient, L_A and L_B are the inductances of the coil A and coil B respectively. Since 54% of flux produced by coil A links coil B,

So, K = 0.54

L_A = N_A Φ/I_AL_A

= 8120 × 0.02/6

= 27.07 mH

L_B = N_B Φ/I_BL_B

= 11842 × 0.078/6

= 154.63 mH

M = k√(LALB) = 0.482 × √(27.07 × 0.15463) = 0.108 H

b) The emf induced in coil B can be given as:-

ε = M (dI_B/dt)/L_B

ε = 0.108 × (-6/0.015) / 0.15463 = -4.95 V

Thus, the emf induced in coil B when the current is reversed in 0.015 seconds is -4.95 V.

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Approximately how long does it take the uterus lining to build up again after menstruation

Answers

The uterus lining is rebuilt by the end of the menstrual period. The rebuilding of the uterus lining starts after menstruation and the lining is typically completely rebuilt by day 14 of the menstrual cycle, which is when ovulation occurs and the uterus is preparing to potentially receive a fertilized egg.

The endometrium is the inner lining of the uterus, and it thickens every month to prepare for pregnancy. After menstruation, the endometrium grows and thickens to prepare for the implantation of a fertilized egg. The cells in the lining multiply and enlarge, and the glands in the lining begin to secrete mucus and other substances that help support the fertilized egg and promote its growth.

The rebuilding of the endometrium usually takes about two weeks after menstruation. This process is closely regulated by hormones such as estrogen and progesterone, which are produced by the ovaries and other parts of the body. These hormones help control the growth and development of the endometrium and other reproductive tissues.

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To the proper number of significant figures, what is the solution to calculation below?
(165.43 g-78.15 g) × 4.184 Jg^(-1) K^(-1) x (297.6 K-292.8 K)=

Answers

The solution to the calculation, rounded to the proper number of significant figures, is approximately 1654 J.

To find the solution to the calculation, we need to follow the rules of significant figures and perform the arithmetic operations step by step.

Subtract the given masses: (165.43 g - 78.15 g) = 87.28 g.

Calculate the temperature difference: (297.6 K - 292.8 K) = 4.8 K.

Multiply the mass difference by the specific heat capacity and the temperature difference:

(87.28 g) × (4.184 Jg^(-1) K^(-1)) × (4.8 K) = 1653.71776 J.

Round the result to the proper number of significant figures based on the given values.

The given values have the following significant figures:

165.43 g has 5 significant figures.

78.15 g has 4 significant figures.

4.184 Jg^(-1) K^(-1) has 4 significant figures.

297.6 K has 4 significant figures.

292.8 K has 4 significant figures.

Since we are multiplying and dividing, the result should have the same number of significant figures as the value with the fewest significant figures, which is 4.

Round the result to 4 significant figures: 1653.71776 J ≈ 1654 J.

Therefore, the solution to the calculation, rounded to the proper number of significant figures, is approximately 1654 J.

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Describe how you would find absolute pressure in a car tire if you had a barometer and a tire pump with an air
pressure gauge

Answers

The absolute pressure in a car tire can found by following method:

Pressure is the force per unit area applied toward a course perpendicular to the outer layer of an item. To keep it precise, it is an amount of force following up on a unit area. The SI unit for pressure is measured in Pascals (Pa). Other non-SI units are bar and PSI. There are two types of references to quantify pressure,

                                 Gauge Pressure

                                 Absolute Pressure

The most well-known pressure reference is Gauge Pressure which is connoted by a ‘g’ after the pressure unit, for example, 33 psi g. It is the pressure relative to barometric or atmospheric pressure; it is positive for pressures above atmospheric pressure and negative for pressures that are below atmospheric pressure. An Absolute pressure estimation is one that is alluded to as a perfect or an ideal vacuum. The best illustration of an absolute referenced pressure is the calculation of Barometric pressure. To deliver an absolute pressure sensor, one strategy is for a maker to seal a high vacuum behind the detecting diaphragm.

Formula of Absolute pressure is given by:

                                       p(a) = p(g) + p(atm)

Where ,

p(a) is absolute pressure,

p(g) is gauge pressure and

P(atm) is atmospheric pressure

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When a marble is at rest what happened

Answers

The marble will stay in place until another force pushes it

Answer: the marble will remain in place at a constant velocity of zero

Explanation:

Newton's first law states that a body at rest will remain at rest, and a body in motion will remain in motion in a straight line at a constant velocityunless acted upon by an outside force

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