4. Evaluate the piecewise function at the indicated values from the domain: ƒ(−8) = −2 ƒ(−8) = 8ƒ(−8) = 0ƒ(−8) = 64

Answer: -2 is the slope

(0,0) (1,4) (rise over run) *Y2 - Y1/X2 - X1*

X1= 0

Y1= 4

X2= 1

Y2= 2

2-4= -2

1-0= 1

-2/1= -2

the slope is -2

Answer:

The baker makes 60 cupcakes.

As a result, the set of all [u, w] Rn Rn satisfying the previous equation is the tangent space to F at [v1, v2]  by using preimage theorem.

Let F be the Stiefel manifold of orthonormal 2-frames in Rn to apply the preimage theorem. The collection of all tangent vectors to curves passing through [v1, v2] in F is what is known as the tangent space T[F] at a location [v1, v2]. Let (t) be a straight line in F such that (v1, v2) is a smooth curve. The tangent vector to t at time t = 0 is then given by

γ′(0) = [u, w] ∈ T[F].

We must now determine the requirements that [u, w] must meet in order to be in T[F]. Assume that V is a matrix with columns named v1 and v2. If Q is an orthogonal matrix, then any orthonormal 2-frame [v1′, v2′] in Rn can be represented as VQ. The category to which [v1′, v2′] belong Q is a 2 by 2 matrix with determinant 1, and F is equivalent to Q. Given that Q(0) = I, let Q(t) be a smooth curve in SO(2). Then, there is

γ(t) = VQ(t) (t),

and

γ′(0) = VQ′(0) (0).

We have Q since Q(t) is orthogonal (t)

TQ(t) = I, indicating

Q′(0)T + Q′(0) = 0.

Let [u, w] T[F] now. Once this is the case, a smooth curve Q(t) in SO(2) exists with Q(0) = I and

[u, w] = VQ′(0) (0).

Applying the equation above, we obtain

v1uv2w plus v1wv2u equals 0.

As a result, the set of all [u, w] Rn Rn satisfying the previous equation is the tangent space to F at [v1, v2].

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Step-by-step explanation:

godhoddohohdxgoixglsut0uts0utsp

Given jack is 3 times as old as lacy.

Let the age of the lacy be x.

Then, the age of the jack is 3x.

After 8 years from now, the sum of their ages will be 64.

Thus, the value of x will be

Therefore, the age of the lacy is 12 and the age of the jack is

Thus, Jack is 36 years old while lacy is 12 years old.

The calculated areas are the same for regular polygon and equal to 43.5 units squared.

The area of polygon is given by the formula:

A = (1/2)ap,

where A is the area, an is the apothem (the distance from the centre of the polygon to the midpoint of any side), and p is the polygon's perimeter, is the formula for calculating the area of a regular polygon.

The apothem of the equilateral triangle can be found using the formula:

a = s / (2 tan(π/n))

Substituting the value of s = 10 we have, and n = 3 side.

a = 10/ / (2 tan(π/3))

a ≈ 2.9 units

The perimeter of the triangle is given as:

p = 3 x 10 = 30 units

Now, the area of the triangle is given as:

A = (1/2)ap

A = (1/2)(2.9)(30) = 43.5 sq. units.

Hence, the calculated areas are the same and equal to 43.5 units squared.

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Answer:

Step-by-step explanation:

Bianca’s answer.

The apothem, rounded to the nearest tenth, is

✔ 2.9 units.

The perimeter of the equilateral triangle is

✔ 30 units.

Therefore, the area of the equilateral triangle is

✔ 1/2(2.9)(30) , or approximately 43.5 units2.

The calculated areas are

✔ the same, despite using different formulas

.

The cash from financing activities for Majka Company, can be found to be

The net amount of financing a business generates during a specific time period is called cash flow from financing activities. The issuing and repayment of equities, the payment of dividends, the issuance and repayment of debt, and capital lease obligations are all examples of financial activity.

The cash from Financing activities for Majka Company is therefore:

= Common stock issued - Cash dividends

= 52, 500 - 3, 100

= $ 49, 400

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The full question is:

Majka Company was started on January 1, Year 1. During Year 1, the company experienced the following accounting events: (1) Issued 52,500 worth of common stock (2) earned cash revenues of $33,400, (3) paid cash expenses of $14,800, and (4) paid a $3,100 cash dividend to its stockholders. These were the only events that affected the company during Year 1.

What were the cash flows from financing for the year?

To solve this problem one must be aware of the concepts of standard deviation and variance of raw data.

There is a direct formulae to calculate the variance of the data,

Variance = \(σ^{2} =\frac{Sigma(xi-m)^{2}}{n}\)

Now here we need to verify ∑x and ∑\(x^{2}\).

∑x = 21+19+15+32+27

     = 114

and ∑\(x^{2}\) = \(21^{2} +19^{2} +15^{2} +32^{2} +27^{2}\)

             = 441+361+225+1024+729

             = 2780

So, the given relation is true.

Now the variance of the given data by putting the values in the formulae is  equal to 45.2.

And Standard deviation=\(\sqrt{Variance}\)

                                     = \(\sqrt{45.2}\)

                                      = 6.72

And for population α²=36.16 and deviation=6.01.

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Answer:

b

tep-by-step explanation:

The correct option is C) m = 0; b = 9. The slope and y-intercept of the linear equation y = 9 are m = 0; b = 9.

To explain step by step:

In summary, the slope of the linear equation y = 9 is 0, indicating a horizontal line, and the y-intercept is 9, representing the point where the line intersects the y-axis.

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Answer:

there is no picture

Step-by-step explanation:

Answer:

it depends on what triangle it is. if it an equilateral then the answer is 6.7 (20 divided by 3)

Step-by-step explanation:

Please follow me :)

Have a wonderful day!!!! Hope this helps. Ask me anytime if you need any help :)

Answer:

\(\sf (2x-4z+3)(2x+5z+3)\)

Step-by-step explanation:

Given

\(\sf \left(2x+3\right)^2+(2xz+3z)-20z^2\)

Remove the parenthesis in the second term and write the first term as a product.

\(\sf \left(2x+3\right) \left(2x+3\right)+2xz+3z-20z^2\)

Expand the first 2 terms using the FOIL method.

\(\sf \left(4x^2+12x+9\right)+2xz+3z-20z^2\)

Collect in terms of \(\sf x\).

\(\sf 4x^2+x(2z+12)+(-20z^2+3z+9)\)

Factor out the minus sign.

\(\sf 4x^2+x(2z+12)+(-(20z^2+3z+9))\)

Factor \(\sf 20z^2+3z+9\) by finding factors of 20(-9) whose sum is \(\sf -3\).

\(\sf 4x^2+x(2z+12)-(4z(5z+3)-3(5z+3))\)

Factor common terms.

\(\sf 4x^2+x(2z+12)-((4z-3)(5z+3))\)

Factor the expression by splitting the product \(-((4z-3)(5z+3))\)          into two parts whose sum is \(\sf 2z+12\).

\(\sf 4x^2-2x(5z+3)+2x(-4z+3)+(-4z+3)(5z+3)\)

Factor by grouping.

\(\sf 2x(-4z+2x+3)+(5z+3)(-4+2x+3)\)

Pull a common factor out and rearrange the terms.

\(\sf (-4z+2x+3)(5z+2x+3)\)

\(\sf (2x-4z+3)(2x+5z+3)\)

Answer:

0

Step-by-step explanation:

Answer:

3 to -3? = 0

Step-by-step explanation:

Hope this helped you!

the answer is (D) 11

Answer:

839

Step-by-step explanation:

689+150=839

Hope this helped!

The cost of the molding is given as follows:

$119.30.

The circumference of a circle of radius r is given by the equation presented as follows:

C = 2πr.

The parameters for this problem are given as follows:

d = 9 -> r = 4.5.

(as the radius is half the diameter)

Hence the circumference is given as follows:

C = 2 x π x 4.5

C = 28.27 ft.

The cost is of $4.22 per ft, hence the total cost is given as follows:

4.22 x 28.27 = $119.30.

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Answer:

I think it is step 2

Step-by-step explanation:

Because if 2x comes left of the =, then +2x becomes minus, so it shouldn't be 5x but x

Step-by-step explanation:

Option D is correct,

the correct solution is

3(x + 5) = 2x + 35

→ 3x + 15 = 2x + 35

→ 3x - 2x = 35 - 15

→ x = 20

verifying

3 ( 20 + 5 ) = 2(20) + 35

60 + 15 = 40 + 35

75 = 75

hence first step that is incorrect is step 2

hope this answer helps you dear!

\(f'(2) = -\frac{3}{16}\\\)

Given:

\(f(x) = \frac{3}{x +2}\\\)

Recall:

\(\frac{\text{d}}{\text{d}x}f(x) = f'(x)\\\)

\(\frac{\text{d}}{\text{d}x}(\frac{f(x)}{g(x)}) = \frac{f'(x)g(x) -f(x)g'(x)}{g(x)^2}\\\)

If we want to solve for \(f'(2)\), we must first find how \(f'(x)\) will be defined.

\(f'(x) = \frac{\text{d}}{\text{d}x}f(x) \\ f'(x) = \frac{\text{d}}{\text{d}x}(\frac{3}{x +2}) \\ f'(x) = \frac{3' \cdot (x +2) -3 \cdot (x +2)'}{(x +2)^2} \\ f'(x) = \frac{0(x +2) -3(1)}{(x +2)^2} \\ f'(x) = \frac{-3}{(x +2)^2} \\ f'(x) = -\frac{3}{(x +2)^2}\)

Now we can evaluate \(f'(2)\).

\(f'(2) = -\frac{3}{(2 +2)^2} \\ f'(2) = -\frac{3}{(4)^2} \\ f'(2) = -\frac{3}{16}\)

3 1/2 cups can be expressed as the multiplication expression: 3 + 1/2.

To express 3 1/2 cups as a multiplication expression using the unit "1 cup" as a factor, you can write it as:

3 1/2 cups = (3 + 1/2) cups = 3 cups + 1/2 cup

Since there are 1 cup in each term, we can rewrite it as:

3 cups + (1/2) cup

Now, we can express each term as a multiplication expression:

3 cups = 3 * 1 cup = 3

(1/2) cup = (1/2) * 1 cup = 1/2

Putting it all together, the multiplication expression is:

3 * 1 cup + (1/2) * 1 cup = 3 + 1/2

Therefore, 3 1/2 cups can be expressed as the multiplication expression: 3 + 1/2.

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The solution is: Piece-wise function

f(x)=x+6 , x≤1

f(x) = x^2 + 3 , x>1, the following functions is graphed below.

Option C is correct.

Explanation:

We are given a graph of piece-wise function which break at x=1

We need to choose correct option for graph.

Function is break at x=1.

We will get two function

For x≤1 and x>1

As we can see x≤1, graph is linear and x>1 graph is parabolic.

Equation of linear graph, x≤1

Take two point of graph (0,6) and (-6,0)

Equation of line:

y-y1/y2-y1 = x-x1/x2-x1

y = x+1

f(x)=x+6 , x≤1

Equation of parabolic graph, x>1

f(x) = x^2 + 3

Piece-wise function

f(x)=x+6 , x≤1

f(x) = x^2 + 3 , x>1

Please see the attached figure.

Hence, The option C is correct.

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Answer:

Step-by-step explanation:

81 texts in 9 hours

So you do 81 divided by 9

Which givrs you 9 text an hour

The difference between the average daily temperature is 53°

Given,

The average daily temperature in May = 52°

The average daily temperature in December = -1°

We have to find the difference between the average daily temperature;

Average daily temperature;

By adding up the highest and lowest instantaneous temperatures over the course of a 24-hour period and dividing by two, the weather and climate community has traditionally determined the observed daily mean temperature.

Here,

Difference between the average daily temperature in May and December

= Average daily temperature in May -  Average daily temperature in December = 52° - (-1°) = 53°

That is,

The difference between the average daily temperature is 53°

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Answer:

d

Step-by-step explanation:

Answer: b + p ≤ 7

Step-by-step explanation:

Let's use b to represent the number of bags of popcorn purchased and p to represent the number of bags of pretzels purchased.

Since Cai can buy a maximum of 7 bags of popcorn and pretzels altogether, we know that:

b + p ≤ 7

This is the inequality that represents the possible values for the number of bags of popcorn purchased (b) and the number of bags of pretzels purchased (p).

Answer:

Step-by-step explanation:

Answer:

x = 9  or  x = -9

Step-by-step explanation:

x² - 4 = 77

then

x² - 4 + 4 = 77 + 4

then

x²  = 81

then

x² - 81 = 0

then

x² - 9² = 0

then

(x - 9)(x + 9) = 0

then

x - 9 = 0  or  x + 9 = 0

then

x = 9  or  x = -9

__________________________

:)

Answer:

Last option, a translation of 1.5 units left, 0.5 unit up, then a reflection across the x-axis

Step-by-step explanation:

Let's pick any random point. So let's just chose point L. Comparing point L to point L', we can already see that the options given are incorrect. For example,  the first option with just translations is incorrect because when we do translate point L 1.5 units left and then 1.5 units down, it does not line up with point L'. For the second and third options, we know that L(-2.5, 1.5) and L'(-4,-2). Therefore, there must be some sort of shift left, right, up, or down, to go from coordinates with decimals to coordinates with whole numbers, leaving the last option, D, as the correct one.

Step-by-step explanation:

When x=-3

7-2(-3)=7-(-6)

=7+6

=13

Answer:

$280

Step-by-step explanation:

7•40=$280