350. mL of a sodium chloride solution with a concentration of .225 mol/L is diluted with 550 ml Potassium chloride solution with a concentration of .125 mol/k What is the concentration of chloride in the mixed solution

If we label the reactions 1 - 3 in order as they appear in the image attached.

Reaction 1 - The yield is increased by decreasing the volume

Reaction 2 - The yield is increased by decreasing the volume

Reaction 3 - The yield is increased by increasing the volume

We know that when a constraint is imposed on a reaction system that is in equilibrium, it is usual that the equilibrium position of the system would shift. The reason why the equilibrium position would shift is so that the constraint that is on the system can be annulled and then a new position of equilibrium would become established.

We would now look at the reactions. We know that when we increase the volume of the reaction, the equilibrium position would shift to the direction in which the volume is lesser. Similarly, if the volume is decreased, the direction to which the equilibrium position would shift would be that of a higher volume.

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A trial refers to a plan to test an idea. A trial is a test, a plan to test an idea, or one of a series of tests that are designed to determine whether a hypothesis or a theory can be verified or disapproved in the field of science.

Trials are conducted to assess the effectiveness of new medications or to identify the underlying cause of a disease, among other things. A hypothesis is developed in which the scientist predicts the outcome of the trial before it is conducted. The null hypothesis, which assumes that there is no significant difference between the control and test groups, is another hypothesis. After the trial has been conducted, the outcomes are evaluated, and the hypothesis is either confirmed or refuted based on the findings. Trials are critical in determining the effectiveness of new treatments and interventions for human illnesses and ailments. They are the primary technique used to determine if new medicines or therapies are effective, and they can assist in establishing the scientific basis for a specific medicine or therapy.

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The element that can be found in both plays and stories is "characters."

Characters are an essential element of both plays and stories. They are the individuals or entities that drive the narrative, interact with each other, and contribute to the development of the plot. In plays, characters are typically portrayed by actors who perform their roles on stage, while in stories, characters are described and depicted through written words.

Characters can be central or supporting figures in a play or story, and they play a vital role in engaging the audience or readers. They have distinct personalities, motivations, and relationships that influence the events and conflicts within the narrative. Through their actions, dialogue, and character development, they contribute to the overall themes and messages conveyed by the play or story.

Whether it is a theatrical production or a written narrative, the presence and portrayal of characters are fundamental to creating engaging and compelling plays and stories.

Thus, the element that can be found in both plays and stories is "characters."

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Answer:

its volume will increase

Answer:

398 mL

Explanation:

Using the equation for molarity,

C₁V₁ = C₂V₂ where C₁ = concentration before adding water = 8.61 mol/L and V₁ = volume before adding water, C₂ = concentration after adding water = 1.75 mol/L and V₂ = volume after adding water = 500 mL = 0.5 L

V₂ = V₁ + V' where V' = volume of water added.

So, From C₁V₁ = C₂V₂

V₁ =  C₂V₂/C₁

= 1.75 mol/L × 0.5 L ÷ 8.61 mol/L

= 0.875 mol/8.61 mol/L

= 0.102 L

So, V₂ = V₁ + V'

0.5 L = 0.102 L + V'

V' = 0.5 L - 0.102 L

= 0.398 L

= 398 mL

So, we need to add 398 mL of water to the nitric solution.

Answer:

Explanation:

c

The root-mean-square speed of Ne atoms at the temperature where their average kinetic energy is 5.90 kJ/mol is about 461 m/s.

The following equation describes the root-mean-square (rms) speed of gas molecules: v = sqrt((3kT)/m).

where m is the molar mass of the gas in kilogrammes per mole, v is the rms speed, k is the Boltzmann constant (1.38 x 10-23 J/K), T is the temperature in Kelvin, and k is the Boltzmann constant.

We must first change the supplied kinetic energy from joules per mole to joules per atom in order to compute the rms speed of Ne atoms:

6.02 x 1023 atoms/mol / 5.90 kJ/mol = 9.80 x 10-21 J/atom

The equation for rms speed is now: v = sqrt((3kT)/m).

The molar mass of Ne is 20.18 g/mol, which is equivalent to 20.18/1000 = 0.02018 kg/mol. To get the mass of one Ne atom, we divide by Avogadro's number:

0.02018 kg/mol / 6.02 x 10^23 atoms/mol = 3.35 x 10^-26 kg/atom

Now we can substitute the given temperature and Ne atom mass into the formula for rms speed:

v = sqrt((3kT)/m) = sqrt((3 x 1.38 x 10^-23 J/K x 298 K) / 3.35 x 10^-26 kg)

v ≈ 461 m/s

Therefore, the root-mean-square speed of Ne atoms at the temperature at which their average kinetic energy is 5.90 kJ/mol is approximately 461 m/s.

Ne has a molecular mass of 20.18 g/mol, or 20.18/1000 = 0.02018 kg/mol.

One Ne atom's mass is obtained by dividing by Avogadro's number:

3.35 x 10-26 kg/atom = 0.02018 kg/mol / 6.02 x 1023 atoms/mol

The formula for rms speed can now be modified to include the specified temperature and mass of the Ne atom:

The formula for v is sqrt((3kT)/m) = sqrt((3 x 1.38 x 1023 J/K x 298 K) / 3.35 x 1026 kg).

v ≈ 461 m/s

The average kinetic energy of Ne atoms is 5.90 kJ/mol, hence their root-mean-square speed at that temperature is roughly 461 m/s.

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The value of ΔG at 298 K for a reaction mixture containing 1.9 atm N2, 1.6 atm H2, and 0.65 atm, the answer is (a) -3.86 × 10^3.

NH3 can be calculated using the equation:

ΔG = ΔG° + RT ln(Q)

where ΔG is the standard Gibbs free energy change, ΔG° is the standard Gibbs free energy change at standard conditions, R is the gas constant, T is the temperature in Kelvin, and Q is the reaction quotient.

In this case, we are given ΔG° as -33.3 kJ/mol. To calculate Q, we need to use the partial pressures of the gases in the reaction mixture. The reaction stoichiometry tells us that the ratio of the partial pressures of N2, H2, and NH3 is 1:3:2. Therefore, we can write:

Q = (P(NH3))^2 / (P(N2) * P(H2)^3)

Plugging in the given values of P(N2) = 1.9 atm, P(H2) = 1.6 atm, and P(NH3) = 0.65 atm, we can calculate Q. Then, using the value of R = 8.314 J/(mol·K) and the temperature T = 298 K, we can substitute these values into the equation and solve for ΔG.

The calculated value of ΔG at 298 K for the given reaction mixture is approximately -3.86 × 10^3 J/mol. This value is equivalent to -3.86 kJ/mol. Therefore, the answer is (a) -3.86 × 10^3.

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Answer:

it is created by movement of molecules with higher energy upwards and the movement of molecules with lower energy downwards

Explanation:

please rate brainliest if I deserve

Answer:

Zn + K2CrO4 -----> 2K + ZnCrO4

Explanation:

Answer:

No

Explanation:

No. The demonstration does not violate the conservation of mass.

The law of conservation of mass states that mass can neither be created nor destroyed in a reaction. However, mass can be converted from one form to another during the reaction.

In this case, even though the remaining bits of paper weigh 0.5 g while the original paper weighed 2.5 g, the ashes and smoke/gas from the burning will all add up to the lost weight of the paper.

The burned part has been converted into other forms. If the smoke/gas and the ashes are properly captured, they will mark up with the weight of the remaining paper to give the weight of the original paper.

The answer to the question on whether the burning violates the law of conservation of mass, we say that;

No, the demonstration does not violate the conservation of mass because the mass formed still adds up to the original mass.

The law of conservation of mass states that mass in an isolated system, matter can neither be created nor destroyed by chemical reactions or physical transformations. However, it could involve change in mass from one form to another.  

Now, we are told that the remaining bits of paper has a mass of 0.5 g while the original paper has a mass 2.5 g. The reason why the mass left is 0.5 kg is because the ashes and smoke from the burning will add up to give the original weight of the paper.

Thus, since when the ashes, and smoke add up to still give the original mass of 3.5 g, it means that the mass is neither created nor destroyed

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The empirical formula : C₆H₂Cl₂O

The molecular formula : C₁₂H₄Cl₄O₂

Given

The percentage composition

Required

The empirical formula and the molecular formula

Solution

The mol ratio of the components :

C : H : Cl : O

=44.76/12 : 1.25/1 : 44.05/35.5 : 9.94/16

=3.73 : 1.25 : 1.241 : 0.621 divide by 1.241

= 3 : 1 : : 1 : 0.5 x 2

= 6 : 2 : 2 : 1

The empirical formula : C₆H₂Cl₂O

(Empirical formula)n=molecular formula

(C₆H₂Cl₂O)n=321.97

(160.986)n=321.97

n=2

(C₆H₂Cl₂O)₂=C₁₂H₄Cl₄O₂

The molecular formula : C₁₂H₄Cl₄O₂

Answer:

0.56kg=?mg

0.56kg x (1000 g/1kg) X (1000mg/1g) = 560,000mg

Explanation:

You got it right. Great Job!

Jill combines two different sorts of HCl (hydrochloric acid) concentrations: 0. 375 liters of 25% and 0. 625 liters of 65%. The mixed solution will have an HCl concentration of 1L of 50% HCl.

In this case, we're interested in learning the concentration of HCl as a proportion of the total amount.

First off, the combined volume is 0.375 + 0.625 = 1 L.

The percentage can be calculated as follows:

37.5% of the required 25% is present.

while 62.5% of the 75% are in presence

When we talk about the percentage present, we're talking about the 1 total liter that is there.

Consequently, the final mixture's concentration will be;

(37.5% of 25) + (62.5% of 65)

= 9.375% + 40.625%

50% is obtained by adding both.

Therefore, the concentration is 1L of 50% HCl.

Your question is incomplete but most probably your full question was

Jill mixes two types of concentrations od hci (hydrochloric acid) 0.375 liters of 25% hydrochloric acid and 0.625 liters of 65% hydrochloric acid. what is the hcl concentration in the mixed solution?

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\(\begin{gathered}\boxed{\begin{array}{c}\\ {\pmb{\sf{Three \: equation \: of \: motion}}} \\ \\ \sf \star \: v \: = u \: + at \\ \\ \sf \star \: s \: = ut + \: \dfrac{1}{2} \: at^2 \\ \\ \sf \star \: v^2 - u^2 \: = 2as\end{array}}\end{gathered}\)

\(\pink{\qquad \pmb{ \sf\longrightarrow v \: = u \: + at}}\)

\( \qquad \pmb{\sf \longrightarrow v = 0 + 2.5 \times 2}\)

\(\qquad \pmb{ \sf\longrightarrow v = 0 + 5}\)

\( \qquad \pmb{\sf \longrightarrow v = 5 \: ms^{-1}}\)

\(\qquad \longrightarrow {\pink{\underline{\underline{\pmb{\sf{ Final \: velocity= 5 \: ms^{-1} }}}}}}\)

Henceforth –

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Answer:

A. the right side

Explanation:

Taking into account the definition of covalent bond, the correct answer is option A.) right side of the periodic table contain atoms that form covalent bonds.

The covalent bond is the chemical bond between atoms where electrons are shared, forming a molecule. Covalent bonds are established between non-metallic elements. These elements have many electrons in their outermost level (valence electrons) and have a tendency to gain electrons to acquire the stability of the electronic structure of noble gas. The shared electron pair is common to the two atoms and holds them together.

In other words, a covalent bond is a force that joins two atoms of non-metallic elements to form a molecule. Atoms share pairs of electrons from their valence shell to achieve the stability of the molecule formed. The tendency of the elements to reach a stable configuration is known as the octet rule.

Finally, since the nonmetallic elements are found on the right side of the periodic table, the correct answer is option A.) right side of the periodic table contain atoms that form covalent bonds.

Learn more:

Answer:

1.099 gmL¯¹ ≈ 1.1 gmL¯¹

Explanation:

From the question given above, the following were obtained:

Mass of empty cylinder = 9.5 g

Mass Cylinder + NaOH = 31.92 g

Volume of solution = 20.4 mL

Concentration of solution =?

Next, we shall determine the mass of sodium hydroxide, NaOH. This can be obtained as as illustrated below:

Mass of empty cylinder = 9.5 g

Mass Cylinder + NaOH = 31.92 g

Mass of NaOH =?

Mass of NaOH = (Mass Cylinder + NaOH) – (Mass of empty cylinder)

Mass of NaOH = 31.92 – 9.5

Mass of NaOH = 22.42 g

Finally, we shall determine concentration of the solution as follow:

Mass of NaOH = 22.42 g

Volume of solution = 20.4 mL

Concentration of solution =?

Concentration = mass /volume

Concentration of solution = 22.42 / 20.4

Concentration of solution = 1.099 gmL¯¹ ≈ 1.1 gmL¯¹

Therefore, the concentration of the solution is 1.1 gmL¯¹

If Half- life of an isotope is 30 days and it was assumed that the person ate 100 Bq of isotope, there are 50 transformations in the stomach.

The radioactive decay of a sample of an isotope can be characterized by the half-life of that isotope. When a radioisotope undergoes decay, its nucleus becomes unstable, and it emits particles or energy to become more stable. The half-life of an isotope is the time it takes for half of the original sample to decay. The question states that the half-life of an isotope is 30 days, and the person ingested 100 Bq of isotope. It also says to calculate the number of transformations in the stomach using GI track model information .

Since the isotope has a half-life of 30 days, we can use the following formula to find the number of transformations in the stomach:` N = N₀ (1/2)^(t/T₁/₂)`where: N₀ = initial number of nuclei N = final number of nuclei (after time t)T₁/₂ = half-life of the isotope The isotope has a half-life of 30 days, so T₁/₂ = 30 days. The question doesn't specify how long the person has had the isotope in their stomach, so we'll assume it's been there for one half-life, or 30 days. Therefore, t = 30 days.

Substituting into the formula:` N = 100 (1/2)^(30/30)`Simplifying:` N = 100 (1/2)^1`Evaluating:`N = 50`So after 30 days in the stomach, the person would have 50 Bq of the isotope left. Therefore, the number of transformations in the stomach is the difference between the initial number of transformations (100 Bq) and the final number of transformations (50 Bq):`Number of transformations in stomach = 100 - 50 = 50 transformations. Therefore, there are 50 transformations in the stomach.

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Answer:

Heat is released when they are both mixed together.

Explanation:

The formula of De Broglie is the following:

Remember that the mass of an electron is 9.11 x 10 ^(-31) kg, so replacing in the formula, we're going to obtain:

The answer is that the wavelength of an electron traveling at 1.48 x 10^(5) m/s is 4.91 x 10^(-9) m.

Answer:

wind is just high and low pressure of air, when a high pressure comes and crashes into a low pressure air pocket than it can form a wind storm.

Explanation:

The Uneven heating of the Earth's surface. Earth's rotation and unequal heating of the Earth's surface. air pressure towards regions of lower air pressure. ... air moving from areas of high pressure to areas of low pressure.

This is what will most likely cause a sudden wind to start blowing.

The  number of moles of CaCO3 and number of moles of CO2 produced by one tablet is 0.00974 mol.

Based on the given information, we can use stoichiometry to calculate the number of moles of CaCO3 in one tablet and the number of moles of CO2 produced.

To calculate the number of moles of CaCO3 in one tablet, we need to know the balanced chemical equation for the reaction between hydrochloric acid (HCl) and calcium carbonate (CaCO3):

CaCO3 + 2HCl → CaCl2 + CO2 + H2O

From the equation, we can see that 1 mole of CaCO3 produces 1 mole of CO2.

Therefore, the number of moles of CaCO3 in one tablet is equal to the number of moles of CO2 produced by the tablet.

The given information states that one tablet reacted with excess hydrochloric acid to produce 0.24 dm3 of carbon dioxide at r.t.p. We can convert the volume of CO2 to moles using the ideal gas law:

PV = nRT

where;

P is the pressure (which is 1 atm at r.t.p.),

V is the volume (0.24 dm3),

n is the number of moles of gas,

R is the gas constant, and

T is the temperature (which is 273 K at r.t.p.).

Rearranging the equation and solving for n, we get:

n = PV/RT = (1 atm)(0.24 dm3)/(0.08206 L·atm/mol·K)(273 K)

n = 0.00974 mol

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Hydrogen outer shell full with only two electrons, to have completely filled electronic configuration.

Hydrogen has atomic number of 2 i.e., it has total of 2 electrons. As per the rule maximum of 2 electrons can be filled in first energy shell.

In case of Hydrogen both the electrons are present in n = 1 shell, here n is principle quantum number. It has completely filled electronic configuration and also the most stable electronic configuration.

Valence electrons can be defined as the number of electrons present in the outermost shell of the atom of a chemical element.

Therefore, hydrogen would require just a single valence electron to have full outer shell and it has only one proton and one electron in its nucleus.

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The work done by the gas for question A will be 4.2 * 10^5 J.

The change in internal energy of the gas for question B is 6.43 * 10^5 J.

For a gas, it is the product of the pressure P and the volume V during a change of volume. The formula for work done in gas is W (work) = P (pressure) * V (volume)

Now, let's calculate the work done by gas to answer question A.

Work = Pressure * (Volume 2 - Volume 1)

= 1 atm * (16.2 - 12)

= 10^5 Pa * 4.2

= 4.2 * 10^5 J

So the work done by the gas is 4.2 * 10^5 J.

Now, let's find the change in internal energy of the gas.

The heat energy added to the system is

Q = 254kcal

= 254kcal * (4184J / 1 kcal)

= 1.063 * 10^6 J

The change in internal energy of gas is

ΔU = Q (the heat energy added) - W (work done by gas)

= 1.063 * 10^6 J - 4.2*10^5 J

= 6.43 * 10^5 J

Therefore, the change in internal energy of the gas is 6.43 * 10^5 J

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