34. Two students, Tom and Jerry devise a plan to determine the coefficient of friction between socks and freshly waxed floors at the school. Tom (60kg) pulls Jerry (75kg) with a force of 185N to get him to start sliding across the floor.a) What is the magnitude of the force that Jerry exerts on Tom? b) What is the normal force of Jerry from the surface? c) What is the coefficient of static friction between the socks and the waxed floor?

According to 1st equation of motion :

\(\boxed{ \boxed{v = u + at}}\)

where,

let's solve for t

\( \hookrightarrow \: 17.63 = 0 + 2.13t\)

\( \hookrightarrow \: t = \dfrac{17.63}{2.13} \)

\( \hookrightarrow \: t = 8.276 \approx 8.28\: \: sec\)

Answer:

Temperate marine climates are humid and have mild winters. There are three kinds of temperate marine climates: marine west coast, humid subtropical, and mediterranean. Marine west coast climates are the coolest temperate marine climates. Humid ocean air brings cool, rainy summers and mild, rainy winters.

Answer:

B) The rod is subject to tensile stress

Explanation:

Tensile stress is the force induced in the body per unit area in response to externally applied force, which stretches the body.

Tensile stress is attached with tensile forces. It is makes material elongate along the axis of the applied load.

It is given as magnitude (F) of the force that is applied along an elastic rod divided by the cross sectional area (A) of the rod in a direction that is perpendicular to the applied force.

materials such as Doctile have the ability to withstand the load while brittle materials who not have the ability they fail before reaching the ultimate material strength.

Answer:

B. Atomic number minus mass number

Explanation:

The current that flows through the 75 ohm resistor in the circuit shown below is 0.12A.

The current flowing through a circuit can be calculated using the Ohm's law equation as follows;

V = IR

Where;

According to this question, a circuit is shown in the above image. A 75 ohm resistor is given alongside a voltage of 9V. The current can be calculated as follows;

9 = I × 75

I = 0.12A

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The thermal expansion of the materials allows to find the deflection of the bimetallist strip is Δy = 3.48 cm

given paramers

    * Bimetallic brass / steel tape

    * Initial temperature, room temperature T = 20ºC

    * Final temperature, boiling water  = 100ºC

    * initial length L₀ = 222mm (1cm / 10mm) = 22.2cm

    * thickness of bimetallic tape e = 0.036 inch (2.54 cm/1 inch) = 0.0914 cm

to find

    * perpendicular deviation or deflection (Δy)

Thermal expansion is the phenomenon of change in the length of a body due to the change in temperature, due to the increase in the length of the atomic and molecular bonds, macroscopically it is described by

        ΔL = α L₀ ΔT

ΔL and ΔT are the variation of the length and temperature respectively, L₀ is the initial length and α the coefficient of expansion ends.

In this case we have a strip formed by two materials with different coefficient of thermal expansion,

Brass       α_{brass}   = 19 10⁻⁶ ºC⁻¹

Steel       α_{steel}    = 11 10⁻⁶ ºC⁻¹

In the attached we can see a diagram of the process, as the temperature increases, the material with greater thermal expansion lengthens more, so the system must curve towards the center of the material with less

thermal expansion. Let's find the length of the strip for each material

brass          L_{f brass} - L₀ = α_{brass} L₀ ΔT

Steel           L_{f steel} - L₀ = \alpha_{steel} L₀ ΔT

Note that the initial length is the same for the two materials and that the strip is in thermal equilibrium at room temperature.

If we assume that we have an arc of circumference, we can write the length of the arc

        θ = L / r

where θ is the angle in radines, L the length of the arc and r the radius of curvature, let's write this equation for each material

brass     L_{f \ brass} =θ r₁

steel      L_{f \ steel} = θ r₂

we substitute in our equations

           θ r₁ - L₀ = α_{brass} L₀ ΔT

           θ r₂ - L₀ = α_{steel} L₀ ΔT

let's subtract the two equations

           θ (r₁- r₂) = L₀ ΔT (α_{brass} - α_{steel})

the thickness of the strip is

           e = r₁ -r₂

           θ = \(Lo \ \Delta T \ \frac{\alpha_{brass} - \alpha_{steel}}{e}\)

we calculate

           θ = \(22.2 \ (100-20) \ \frac{(19-11) \ 10^{-6}}{0.0914}\)

           θ = 0.155 rad

Let's use trigonometry to find the perpendicular deflection

          tan θ = Δy / L₀

          Δy = L₀ tan θ

          Δy = 22.2 tan 0.155

          Δy = 3.48 cm

Using the thematic expansion of the two materials we find the deflection of the bimetallist strip is 3.38 cm

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Answer:

Therefore, the velocity of the mass when the displacement is -1.5 cm is 0.121 m/s.

Explanation:

To calculate the velocity of the mass attached to a spring with the given parameters, we can use the principle of conservation of energy. At the maximum displacement (2 cm), all the potential energy stored in the spring is converted into kinetic energy of the mass. Therefore, we can write:

1/2 * m * v^2 = 1/2 * k * x^2

where m is the mass of the object, v is the velocity of the object, k is the spring constant, and x is the displacement of the mass from the equilibrium position.

Substituting the given values, we get:

1/2 * 8 kg * v^2 = 1/2 * 200 N/m * (0.02 m)^2

Solving for v, we get:

v = sqrt((0.02 m)^2 * 200 N/m / 8 kg) = 0.2 m/s

Therefore, the velocity of the mass when the displacement is 2 cm is 0.2 m/s.

Similarly, at a displacement of -1.5 cm, we can use the same equation to calculate the velocity:

1/2 * 8 kg * v^2 = 1/2 * 200 N/m * (-0.015 m)^2

Solving for v, we get:

v = sqrt((-0.015 m)^2 * 200 N/m / 8 kg) = 0.121 m/s (rounded to three decimal places)

The net charge enclosed by the outer surface before Q was introduced is 1530 \text{ nC}$$. The charge Q is 847 \text{ nC}$$. After Q is introduced, the charge on the inner surface of the conductor is -847 \text{ nC}$$.The charge on the outer surface of the conductor is  2377 \text{ nC}$$.

(a) The net charge enclosed by the outer surface before Q was introduced can be found using Gauss's Law:

$$\oint \vec{E} \cdot d\vec{A} = \frac{Q_{enc}}{\epsilon_0}$$

Since the electric field is uniform and directed outward, we can simplify this to:
$$E \cdot 4\pi r² = \frac{Q_{enc}}{\epsilon_0}$$

Plugging in the given values for E and r:
$$475 \cdot 4\pi (0.32)² = \frac{Q_{enc}}{8.85 \times 1\(0^{-12}\)}$$

Solving for Qenc:
$$Q_{enc} = 475 \cdot 4\pi (0.32)² \cdot 8.85 \times 1\(0^{-12}\)

= 1.53 \times 1\(0^{-9}\)\text{ C}

= 1530 \text{ nC}$$

(b) The charge Q can be found by comparing the electric field before and after it was introduced:
$$E_{before} - E_{after} = \frac{Q}{4\pi \epsilon_0 r²}$$

Plugging in the given values:
$$475 - 212 = \frac{Q}{4\pi (8.85 \times 1\(0^{-12}\)) (0.32)²}$$

Solving for Q:
$$Q = (475 - 212) \cdot 4\pi (8.85 \times 1\(0^{-12}\)) (0.32)²

= 8.47 \times 1\(0^{-10}\) \text{ C}

= 847 \text{ nC}$$

(c)After Q is introduced, the charge on the inner surface of the conductor will be equal and opposite to Q, so:

$$Q_{inner} = -Q = -847 \text{ nC}$$

(d) The charge on the outer surface of the conductor will be equal to the net charge enclosed by the outer surface, which is the sum of the original charge and Q:

$$Q_{outer} = Q_{enc} + Q =

1530 + 847

= 2377 \text{ nC}$$

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Let, frictional force is f and normal force is N.

Balancing horizontal forces :

\(50cos \ 30^o - f = 12 \times 4.13\\\\f = 50cos \ 30^o - 49.56\\\\f = -6.26\ N\)

Also, balancing vertical forces, we get :

\(N = mg + 50sin \ 30^o\\\\N =( 12\times 9.8 ) + (50\times sin \ 30^o)\\\\N = 142.6\ N\)

Therefore, the frictional force and normal force is -6.26 N and 142.6 N.

(a) The location of a point where the electric field is zero is at the center of the triangle which is equal to ¹/₆√3a.

(b) The magnitude and direction of the electric field at the top corner due to the two charges at the base is  1.732 kq/a².

The electric field is zero at the center of the equilateral triangle whose magnitude is equal to √3a/6.

E = E₁ + E₂

where;

E = kq/a²[(cos 60i + sin 60j) + (-cos 60i + sin 60j)]

E = kq/a²[2(sin 60j)] = 1.732 kq/a²

Thus, the location of a point where the electric field is zero is at the center of the triangle which is equal to ¹/₆√3a.

The magnitude and direction of the electric field at the top corner due to the two charges at the base is  1.732 kq/a².

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Density calculations are 1.2L = 1200mL m = 2.9 x 10^4 g

Density is the mass of a material substance per unit volume. d = M/V, where d is density, M is mass, and V is volume, is the formula for density. Grams per cubic centimetre are a typical unit of measurement for density. Another way to state density is in kilogrammes per cubic metre (in metre-kilogram-second or SI units).

For instance, air weighs 1.2 pounds per cubic metre. In textbooks and manuals, the densities of typical solids, liquids, and gases are stated. The relationship between mass and volume can be easily determined using density; for example, the mass of a body is equal to its volume multiplied by the density (M = Vd), whereas the volume is equal to the mass divided by the density (V = M/d).

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Answer:

Electrons orbit the nucleus. They have a very small mass and do not contribute to atomic mass

We know that

• The average is 0.45 calories per hour.

• The energy stored is 3500 calories per pound of body fat.

• The mass is 150 pounds.

• The hours of sleep are 8.

First, we have to multiply the mass 150 lb by the average rate

This means that this person burns 67.5 calories per hour. Now, we have to multiply this rate by 8 hours.

Now, we know that 1 pound of body fat is equivalent to 3500 calories. So, let's use a rule of three to find the period of time would take this person to lose one pound of body fat (3500 cal).

Let's solve for x

To calculate acceleration, you use the equation a =Δv/Δt, where Δv is the change in velocity, and Δt is the time it takes for the change to occur.

In physics, acceleration is the change in velocity in a given unit of time. The acceleration of an object is caused by a force acting on the object, as explained in Newton's second law. The SI unit for acceleration is meters per second squared (m/s). Acceleration is the product of the velocity (m/s) divided by the time (s). So, the resulting formula is a = v/t.

Acceleration and the most basic velocity in acceleration are how fast a car can increase its speed, while velocity looks at how fast a car travels a certain distance.

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Answer:

D. how close the magnets are together and which direction the poles point.

Explanation:

The potential energy of a magnet in the presence of another magnet is related to how close the magnets are together and which direction the poles point.

When opposite poles of a magnet are aligned, there is an attractive force between them. The farther apart magnets are the more the potential energy.

The two magnets will attract each other so as to minimize the potential energy between them.

For opposite poles, the closer the magnets are, the higher the potential energy

Answer:

please mark me as brainliest I'm begging u

Explanation:

The behavior of an object that has been charged is dependent upon whether the object is made of a conductive or a nonconductive material. Conductors are materials that permit electrons to flow freely from particle to particle. An object made of a conducting material will permit charge to be transferred across the entire surface of the object. If charge is transferred to the object at a given location, that charge is quickly distributed across the entire surface of the object. The distribution of charge is the result of electron movement. Since conductors allow for electrons to be transported from particle to particle, a charged object will always distribute its charge until the overall repulsive forces between excess electrons is minimized. If a charged conductor is touched to another object, the conductor can even transfer its charge to that object. The transfer of charge between objects occurs more readily if the second object is made of a conducting material. Conductors allow for charge transfer through the free movement of electrons

Answer:

high frequent sound

Explanation:

because if its low than its slower.

Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration.

1. Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration. The valence electrons are the outermost electrons in an atom's electron shell, and they are crucial in determining the chemical properties and reactivity of elements.

2. Evidence from data tables can be shown by examining the electron configuration and the group and period numbers of various elements on the periodic table. Here is a simplified example:

Element   | Electron Configuration | Group | Period |

--------------------------------------------

Hydrogen  | 1s^1                              | 1     | 1      |

Lithium       | [He] 2s^1                     | 1     | 2      |

Carbon       | [He] 2s^2 2p^2          | 14    | 2      |

Oxygen      | [He] 2s^2 2p^4          | 16    | 2      |

Neon          | [He] 2s^2 2p^6          | 18    | 2      |

--------------------------------------------

3. The evidence from the data table supports the claim that the arrangement of elements on the periodic table is based on valence electrons.

- Group Trend: Elements within the same group (vertical columns) share the same number of valence electrons. In the example table, Hydrogen, Lithium, and Neon are all in Group 1, indicating they have 1 valence electron.

- Period Trend: Elements within the same period (horizontal rows) have the same number of electron shells. In the example table, Hydrogen and Lithium are in Period 1, indicating they have their valence electron in the first energy level. Carbon, Oxygen, and Neon are in Period 2, indicating they have their valence electrons in the second energy level.

By examining the electron configurations, group numbers, and period numbers, we can clearly see the trends and patterns in the number of valence electrons for both groups and periods on the periodic table. This evidence supports the claim that the arrangement of elements on the periodic table is based on their valence electrons, which play a crucial role in determining their chemical behavior and properties.

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Answer:

Mass and velocity are both directly proportional to the momentum. If you increase either mass or velocity, the momentum of the object increases proportionally. If you double the mass or velocity you double the momentum.

Explanation:

Answer:

below

Explanation:

Force is needed to cause a change in the motion or shape of an object. In physics, force is defined as any influence that causes an object to undergo a certain change. This can include pushing, pulling, twisting, stretching, compressing, or any other type of action that alters the state of an object. Forces are typically measured in units of Newtons (N) and are represented by vectors, which indicate both the direction and magnitude of the force. Some common examples of situations where force is needed include lifting an object, accelerating a vehicle, compressing a spring, or bending a beam.

Answer:

Force can be used in many different ways to small stuff like flicking a bug away or picking up your pencil you use force all the time even when typing just to press down on those little keys.

Force can also be used to move heavy objects such as boulders, tables, cinder blocks, and brick stones. So force can be used in many different ways the strongest man “ Ben Weider “ known as the strongest man lifting 500 pounds in 1995 - 2000. He uses force to lift up the things that he carries.

Force can be used in many ways like I said typing something out or bench pressing. But force can be limited due to your strength.

Thus the answer to your problem is, ↑↑↑↑

Answer: I = \(\frac{11}{6}MR^{2}\)

Explanation: Moment of Inertia (I) is the opposition on a rotating body. Generally, is calculated by  \(I=2mr^{2}\)

A bycicle wheel is composed of numerous parts and each part has its own moment of inertia.

Moment of inertia for this 5-spoke bike wheel will be:

Inertia of ring: \(I_{r}=m_{r}r^{2}\)

For the 5-spoke wheel:

\(I_{r}=MR^{2}\)

Inertia of spokes: \(I_{s}=\frac{1}{3}n.m_{s}r^{2}\)

where

n is the number of spokes

For the 5-spoke wheel, half of the total mass is the spokes, then:

\(I_{s}=\frac{1}{3}.5. \frac{M}{2}R^{2}\)

\(I_{s}=\frac{5}{6}MR^{2}\)

Inertia of the wheel is the sum of both inertia:

\(I=I_{r}+I_{s}\)

\(I=MR^{2}+\frac{5}{6}MR^{2}\)

\(I=\frac{11}{6}MR^{2}\)

The moment of inertia of the 5-spoke bike wheel is \(I=\frac{11}{6}MR^{2}\)

Answer:

the first one is oil and water and the second one I am between homogeneous mixture and compound

Answer:

The SI unit for intensity is watts per square meter (W/m2)

Answer:

the particle is at coordinates (18,15/2)

Explanation:

To find the acceleration of the particle, we can use the formula for velocity: v = v0 + at, where v0 is the initial velocity, a is the acceleration, and t is the time. Since we know the initial and final velocities, as well as the time interval, we can solve for the acceleration:

a = (v - v0)/t = [(9i + 7j) - (3i - 2j)]/3 = (6i + 9j)/3 = 2i + 3j

So the acceleration of the particle is a = 2i + 3j m/s².

To find the coordinates of the particle at t=3s, we can use the formula for position: r = r0 + v0t + 1/2at², where r0 is the initial position. Since the particle starts at the origin, r0 = 0. Plugging in the values we have:

r = 0 + (3i - 2j)(3) + 1/2(2i + 3j)(3)² = 9i - 6j + 9i + 27/2 j = 18i + 15/2 j

We can use the kinematic equations of motion to solve this problem.

Let the acceleration of the particle be a = axî + ayj.

(a) Using the equation of motion v = u + at, where u is the initial velocity:

f = v = u + at

Substituting the given values, we get:

(91+7j) = (3î-2j) + a(3î + 3j)

Equating the real and imaginary parts, we get:

91 = 3a + 3a (coefficients of î are equated)

7 = -2a + 3a (coefficients of j are equated)

Solving these equations simultaneously, we get:

a = î(23/6) + j(1/2)

So the acceleration of the particle is a = (23/6)î + (1/2)j.

(b) Using the equation of motion s = ut + (1/2)at^2, where s is the displacement and u is the initial velocity:

At t = 3s, the displacement of the particle is:

s = ut + (1/2)at^2

Substituting the given values, we get:

s = (3î-2j)(3) + (1/2)(23/6)î(3)^2 + (1/2)(1/2)j(3)^2

Simplifying, we get:

s = 9î + (17/2)j

So the coordinates of the particle at t=3s are (9, 17/2).

Answer:

electric charges are quantised

Explanation:

which means they exist as integral multiples q=ne . this was practically proved by the Millikan's oil drop experiment in which he let charged oil droplets as fine as mist fall under the effect of gravity, after measuring the charge on many drops the results showed that charges were multiples of a minimum value 1.6 x 10\({-19}\) which we now know as the charge on an electron or elementary charge.

We can  be more intentional on viewing parenting roles differently in order to most benefit our children/students through-

1. Being relational

2. Being consistent

3. Being Instructive

What is intentional Parenting?

Having a strategy and setting priorities for your time and energy is all that constitutes intentional parenting. Our daily decisions and the commitments you make are then influenced by these priorities.Being an intentional parent entails understanding that the time we spend with our children is valuable and finite, and that the choices we make about how to spend that time will have an impact for a lifetime.

Thankfully, successful parenting doesn't demand perfection in these areas of instruction and punishment, but it does call for us to be thoughtful. Therefore, we must keep the following in mind to be intentional parents:

1. Parenting with intention involves relationships.

As children grow older and their lives full with milestones and events, life becomes increasingly busy. Throughout the hectic times of school and extracurricular activities, look for methods to interact frequently. Look for chances to spend time with each of your kids alone. Find moments throughout the day to have fun, play, and converse, even if it is only for a little while.

2. Consistent (even relentless) attention is a hallmark of intentional parenting.

It calls for us to be persistent in our efforts to connect with our children, refusing to give up on potential future connections just because the current one falls short of our expectations. Parenting is not a chore for parents who do it intentionally. Every chance they have to affect their children is seen by them as a wonderful gift.

3. Parenting with intention is instructive.

Kids that grow up in intentional, relational families are frequently eager and willing to learn. Every day, search for opportunities to reinforce prior teachings or find instructive situations. Next, schedule specific, devoted times to concentrate on some larger goals.

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