34 out of the 68 students at a school assembly were first-grade students. What percentage of the students at the assembly were first-graders?

Answer:

z = 36

Step-by-step explanation:

Isolate the variable, z. Note the equal sign, what you do to one side, you do to the other. Multiply 3 to both sides of the equation:

(z/3) * 3 = (12) * 3

z = 12 * 3

z = 36

z = 36 is your answer.

~

Answer:

z = 36

Step-by-step explanation:

In order to find z, solve with the opposite operation.

Since z and 3 are dividing to equal 12, multiply 12 and 3 to find z.

Multiply 12 and 3:

\(z=12(3)\)

\(z=36\)

Answer:

0.46

Step-by-step explanation:

13.80/0.46

just divide

Answer:

Sample Response: To find the image after a reflection over the x-axis, I would negate the y-coordinate. To find the image after a reflection over the y-axis, I would negate the x-coordinate. So, reflecting the point (5, 2) over the x- and y-axis, I would get (–5, –2).

Step-by-step explanation:

\(\text{Given that,}\\\\f(x) =x^3~~~ \text{and}~~ g(x) = \sqrt[3]x\\\\\\(f \circ g)(x) = f(g(x))= f\left(\sqrt[3]x \right) = \left(\sqrt[3] x \right)^3 =x \\\\(g\circ f)(x) =g(f(x)) = g(x^3) = \sqrt[3]{x^3} = x\\\\\text{Since} (f \circ g)(x) = (g \circ f) (x) ,~~ \text{f(x) and g(x) are inverses of each other.}\)

Answer:

f^-1 (x)=sqrt(x/3), -sqrt(x/3).

Step-by-step explanation:

f(x)=3x^2

y=3x^2

x=3y^2

y^2=x/3

y=sqrt(x/3), -sqrt(x/3).

Answer:

\(y=3x^2\)

\(y=3x^2\)

Step-by-step explanation:

There is no step-by-step explanation because it's a graph. Well, it's how I did it. Therefore, the graph in the picture that I'm about to post will be your answer.

Answer:

hi

Step-by-step explanation:

The algebraic expression for the given terms, "Three – fourths of v subtracted from 6 times two – ninths y" is as follows:6(2/9y) - (3/4)v.

We have to simplify this algebraic expression to obtain the final result. To do so, we must first simplify the terms within the parentheses.Step 1: Simplify the parentheses first.6(2/9y) = 4/3yStep 2: After simplifying the parentheses, subtract 3/4v from 4/3y4/3y - (3/4)v = 16/12y - 9/12v.

Step 3: Simplify 16/12y - 9/12v. 16/12 can be simplified to 4/3.4/3y - 3/4v is the final simplified form of the given algebraic expression.Thus, the answer is 4/3y - 3/4v.

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The amount of copper that is contained in 120 pounds of brass is equal to 78 pounds.

Let the amount of copper be C.

Given the following data:

Quantity of brass = 120 pounds

Percentage of copper = 65%

To calculate the amount of cooper that is contained in 120 pounds of the brass:

In this exercise, you're required to determine how many pounds of copper can be found in 120 pounds of brass. Thus, we would solve for the percentage of copper contained in this type of brass.

\(Copper=\frac{65}{100}*120\\\\Copper, c=78 ponds.\)

This is correct because 65% of 120 pounds is equal to 78 pounds. 65% can be expressed as a decimal (0.65) and multiplied by 120 pounds to find the number of pounds of copper contained in 120 pounds of the brass.

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Answer:

Option B ; C ; D

Option B i.e YX

Option C i.e YW

Option D i.e <XYZ

The parts that appear in diagram are

<XYZ

Ray YZ, YX and YW.

An angle is a figure in plane geometry that is created by two rays or lines that have a shared endpoint. The Latin word "angulus," which meaning "corner," is the source of the English term "angle." The shared terminus of two rays is known as the vertex, and the two rays are referred to as sides of an angle.

Given:

We know that when two rays meet at the point is said to be angle.

As, ray YX and YZ meet at point Y then angle is <XYZ.

Also, a ray has one end with arrow headed.

so, the rays are YZ, YX and YW.

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A rational function that has vertical asymptotes at x = -2 and x = 4 and a zero at x = 1 is:

f(x) = (x - 1) / ((x + 2)(x - 4))

A rational function is defined as the quotient of two polynomials. In this case, we want a rational function that has vertical asymptotes at x = -2 and x = 4, which means the denominator of the function should have factors of (x + 2) and (x - 4), respectively. Additionally, we want a zero at x = 1, which means the numerator should have a factor of (x - 1).

By combining these requirements, we can write the rational function as f(x) = (x - 1) / ((x + 2)(x - 4)). The numerator (x - 1) ensures that the function has a zero at x = 1. The denominator (x + 2)(x - 4) introduces the vertical asymptotes at x = -2 and x = 4, as when x approaches these values, the denominator becomes arbitrarily close to zero, causing the function to tend towards infinity or negative infinity.

Therefore, the rational function f(x) = (x - 1) / ((x + 2)(x - 4)) satisfies the given conditions of having vertical asymptotes at x = -2 and x = 4 and a zero at x = 1.

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The uncertainties ⟨Δx^2⟩ and ⟨Δp^2⟩ are given by the expressions ⟨Δx^2⟩ = a^2/2 and ⟨Δp^2⟩ = (ℏ^2)/(8a^2).

To calculate the uncertainties ⟨Δx^2⟩ and ⟨Δp^2⟩ for the given wave packet, we need to find the expectation values of the observables (x^ - ⟨x⟩)^2 and (p^ - ⟨p⟩)^2, respectively.

The wave packet is represented by the function ψ(x) = [2πa^2]^(1/2) exp[-4a^2(x - ⟨x⟩)^2 + iℏpx]. Here, a is a constant, ⟨x⟩ represents the expectation value of x, and p is the momentum operator.

To find ⟨Δx^2⟩, we calculate the expectation value of (x^ - ⟨x⟩)^2 with respect to ψ(x). By integrating (x - ⟨x⟩)^2 multiplied by the squared magnitude of the wave packet over all x values, we obtain the result ⟨Δx^2⟩ = a^2/2.

Similarly, to find ⟨Δp^2⟩, we calculate the expectation value of (p^ - ⟨p⟩)^2 with respect to ψ(x). Since p is the momentum operator, its expectation value is ⟨p⟩ = 0 for the given wave packet. By integrating (p^ - 0)^2 multiplied by the squared magnitude of the wave packet over all x values, we obtain the result ⟨Δp^2⟩ = (ℏ^2)/(8a^2).

Therefore, the uncertainties ⟨Δx^2⟩ and ⟨Δp^2⟩ are given by the expressions ⟨Δx^2⟩ = a^2/2 and ⟨Δp^2⟩ = (ℏ^2)/(8a^2).

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Answer:

A.15

Step-by-step explanation:

These two triangles are congruent triangles. This means that the side measurements can be found through a single multiplicative number.

All you have to do is divide 49 by 23 and get 2.130434783. You need that number to be specific

Next you want to multiply that number by the side length that corresponds to the length you are trying to find. In this case that is 7.  

7 x 2.130434783=14.9

14.9 rounds to 15

Answer:

D

Step-by-step explanation:

1/25 is the same thing as \(5^{-2}\). So, u wantn to find whcih answer choice does not equal that. You can use the exponent multiplication rule, where x^a times x^b equals x^a+b.

for example, answer choice A would be 5^(3+-5) which is 5^-2.

the only choice that does not equal 5^-2 is D because it equals 5^2

Answer: D

Brainliest pls

Watching the scene performed was a completely different experience from reading it. The performance emphasizes the body language and facial expressions of the actors as a means of conveying meaning. These elements are missing from the text of the scene and must be imagined by the reader.

Watching a scene performed provides a sensory and immersive experience that engages multiple senses simultaneously allowing for a more vivid and dynamic understanding of the story.  The visual and auditory elements along with the actors' expressions and movements bring the scene to life and evoke emotions in a way that reading alone cannot replicate.

On other hand, reading allows for a more introspective and personal interpretation of the scene as it allows the reader to envision the details based on their imagination and connect with the characters on a deeper level through their own mental images.

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The present age of Kevin is 6 years.

Using the provided data, we can create two equations that specify the ages of Kevin and Daniel.

Let Kevin's present age be k and Daniel's present age be d.

As per the data given:

Kevin is 3 years older than Daniel. This can be written as:

k = d + 3

Two years ago, Kevin was 4 times as old as Daniel

Two years ago, Kevin was k - 2 years old, and Daniel was d - 2 years old.

k - 2 = 4(d - 2)

Now we have two independent equations, and we can solve for our two unknowns.

Solving our first equation for d.
We get:

d = k - 3

Substituting this into our second equation, we get the equation:

k - 2 = 4((k - 3) -2)

k - 2 = 4k - 12 - 8

k - 2 = 4k - 20

4k - k = 20 - 2

3k = 18

k = 6

Therefore the answer is 6 years.

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The side lengths x and y of the right triangle are (5√2)/2 and (5√2)/2.

The figure in the image is a right triangle.

To solve for the values of x and y, we use trigonometric ratio.

Sine = Opposite / Hypotenuse

Cosine = Adjacent / Hypotenuse

Plug in the values

sin( 45 ) = x / 5

x = sin( 45 ) × 5

x = (√2)/2 × 5

x =  (5√2)/2

Next, we solve for y.

Cosine = Adjacent / Hypotenuse

cos( 45 ) = y / 5

y = cos( 45 ) × 5

y = (√2)/2 × 5

y =  (5√2)/2

Therefore, the value of x is (5√2)/2 and y is (5√2)/2.

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The total standard time required to processed for one hundred units as per given setup and run time is equal to 1120minutes.

As given in the question,

Number of units to be processed = One hundred units

Conversion used:

1 hour = 60 minutes

Time required for setup = 2 hours

                                        = 2 ( 60) minutes)

                                        = 120 minutes

Run time per piece = 10 minutes

⇒ Run time required for 100 units = 100 × 10

                                                        = 1000 minutes

Total standard time for 100 units is equal to

= Run time for 100 units + set time

= 1000 + 120

= 1120 minutes

Therefore, the total standard time required to processed 100 units is equal to 1120 minutes.

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Answer:

Given that a circle of radius 5 miles has an arc of length 3 miles.

The central angle of the arc can be found using the formula:\(\[\text{Central angle} = \frac{\text{Arc length}}{\text{Radius}}\]\)

Substitute the given values into the formula to get:\(\[\text{Central angle} = \frac{3}{5}\]\)

To get the answer in degrees, multiply by 180/π:\(\[\text{Central angle} = \frac{3}{5} \cdot \frac{180}{\pi}\]\)

Simplify the expression:\(\[\text{Central angle} \approx 34.38^{\circ}\]\)

Therefore, the measure of the central angle that subtends the arc of length 3 miles in a circle of radius 5 miles is approximately 34.38 degrees.

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a. The control limits for the 3-sigma x-bar chart are: UCL x-bar = 61.744 lb. and LCL x-bar = 59.756 lb.

b. The control limit for the 3-sigma R-chart is UCL R = 4.051 lb., rounded to three decimal places.

(a) To determine the control limits for the 3-sigma x-bar chart, we need to use the given information of the sample size, overall mean, and average range.

For the x-bar chart, the control limits are calculated using the formula:

Upper Control Limit (UCL x-bar) = overall mean + (A2 * average range)

Lower Control Limit (LCL x-bar) = overall mean - (A2 * average range)

Where A2 is a constant depending on the sample size. For a sample size of 7, the value of A2 is 0.577.

Substituting the values into the formula, we get:

Upper Control Limit (UCL x-bar) = 60.75 + (0.577 * 1.78) = 61.744

Lower Control Limit (LCL x-bar) = 60.75 - (0.577 * 1.78) = 59.756

Therefore, the control limits for the 3-sigma x-bar chart are: UCL x-bar = 61.744 lb. and LCL x-bar = 59.756 lb.

(b) To calculate the control limits for the 3-sigma R-chart, we only need the value of the average range.

The control limits for the R-chart are calculated as follows:

Upper Control Limit (UCL R) = D4 * average range

Lower Control Limit (LCL R) = D3 * average range

For a sample size of 7, the values of D3 and D4 are 0 and 2.282, respectively.

Substituting the values into the formula, we get:

Upper Control Limit (UCL R) = 2.282 * 1.78 = 4.051 lb.

Therefore, the control limit for the 3-sigma R-chart is UCL R = 4.051 lb., rounded to three decimal places.

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(1) The relative humidity is 60%.

(2) The temperature of the air parcel is Tdp ≈ 51.0 °F.

(3) LCL ≈ 1.82 km or 1820 meters

(4) The temperature at 6000 meters is 52.63 °F.

(5) SH at 6000 meters is 3.58 g/kg.

(6) Parcel temperature at 1000 meters is 35.13 °F.

Given data at sea level (ground):

(1) Calculate the Relative Humidity (RH) on the ground.

To calculate RH, we need to know the saturation-specific humidity at the given temperature.

The saturation-specific humidity (5Hs) at 59.0 °F can be found using a particular table of humidity or formula. However, since I don't have access to the internet for real-time calculations, let's assume the specific humidity at saturation is 9 g/kg at 59.0 °F.

Now we can calculate the RH on the ground:

RH = (SH / SHs) x 100

RH = (5.4 g/kg / 9 g/kg) x 100

RH ≈ 60%

(2) Calculate the Dew Point Temperature (Tdp) on the ground.

To calculate the dew point temperature, we can use the following approximation formula:

\(Tdp = T - (\dfrac{(100 - RH)} { 5}\)

Where Tdp is in °F, T is the temperature in °F, and RH is the relative humidity in percentage.

\(Tdp = 59.0 - \dfrac{(100 - 60) }{5}\\Tdp = 59.0 - \dfrac{40} { 5}\\Tdp = 59.0 - 8\\Tdp = 51.0 ^oF\)

(3) Calculate the Lifted Condensation Level (LCL) on the ground.

The LCL is where the air parcel would start to condense if lifted.

\(LCL = \dfrac{(T - Tdp)} { 4.4}\\LCL = \dfrac{(59.0 - 51.0)} { 4.4}\\LCL = \dfrac{8.0} { 4.4}\\LCL = 1.82 km or 1820 meters\)

(4) Lift the air parcel to 6000 meters (approximately 19685 feet).

The temperature decreases with height at a rate of around 3.5 °F per 1000 feet (or 6.4 °C per 1000 meters) in the troposphere. Let's calculate the temperature at 6000 meters.

Temperature at 6000 meters ≈ T on the ground - (LCL height / 1000) x temperature lapse rate

\(T= 59.0 - \dfrac{1820} { 1000} \times 3.5\\T= 59.0 - 6.37\\T= 52.63 ^oF\)

(5) Calculate the specific humidity (5H) at 6000 meters.

Assuming specific humidity decreases linearly with height, we can calculate it using the formula:

SH at 6000 meters ≈ SH on the ground - (LCL height / 1000) * specific humidity lapse rate

Let's assume a specific humidity lapse rate of 1 g/kg per 1000 meters.

\(SH = 5.4 - \dfrac{1820} { 1000} \times 1\\SH = 5.4 - 1.82\\SH = 3.58 \dfrac{g}{kg}\)

(6) The parcel descends from 6000 meters to 1000 meters.

We will assume the dry adiabatic lapse rate, which is 3.5 °F per 1000 feet (or 6.4 °C per 1000 meters).

Temperature change during descent ≈ (6000 - 1000) * temperature lapse rate

\(\Delta T= 5000 \times \dfrac{3.5} { 1000}\\\Delta T= 17.5 ^oF\)

Parcel temperature at 1000 meters ≈ Temperature at 6000 meters - Temperature change during descent

Parcel temperature at 1000 meters ≈ 52.63 - 17.5

Parcel temperature at 1000 meters ≈ 35.13 °F

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Answer:

7183 cars

Step-by-step explanation:

On Friday, 2364 cars parked in the garage.

On Sunday, 2,455 more cars parked In the garage than on Friday.

This means that the number of cars parked on Sunday is 2455 plus the number of cars parked on Friday, that is:

2455 + 2364 = 4819 cars

Therefore, the number of cars parked in the garage in the two days is:

4819 + 2364 = 7183 cars

7183 cars were parked during the two days.

For an increase of one hour in time worked, the predicted increase in the amount of money spent on entertainment is 1.86 units.

To find the predicted increase in the amount of money spent on entertainment for an increase of one hour in time worked, we need to find the slope of the line, which is the coefficient of x in the equation.

which means that for every one unit increase in x (which in this case is one hour worked), y (which in this case is the amount of money spent on entertainment) is predicted to increase by 1.86 units.

This is the change in the dependent variable (y) for a unit increase in the independent variable (x), based on the linear relationship described by the equation of the line fit.

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Answer:

parallel as if we place the ond the coordinate grkd they will form lines paral.el to each other(;

Answer:

37

Step-by-step explanation:

Answer: moderate, C, B

Step-by-step explanation:

A)  A shows a moderate negative correlation.  It is moderate because the scattered points are sort of close to the line so it has moderate/medium correlation.  It is also negative because it has a negative slope

B) C shows the strongest correlation because the points around the line are tight and close.

C)  B should not have been drawn.  The  correlation is very weak.  You do know where the line should be because the points are all over the place.

Ms. Wilson is paid $1728.97 every 2 weeks.

To find her annual salary, first, you have to calculate her monthly salary.

Each month has two payments, so you have to multiply her bi-weekly salary by 2:

Her monthly income is $3451.82

To determine her annual income you have to multiply her monthly income by 12

Her annual salary is $41493.84

The percent of attendance figures that differs from the mean by 1500 persons or more is 6.68%.

From the question above, Mean μ = 10,000

Standard Deviation σ = 1,000

The formula for z-score is :

z = (x-μ) / σ

Where, x = observation

z = z-score

Mean μ = 10,000

Standard Deviation σ = 1,000

From the above formula, let's calculate z-score for x = 11,500

z = (x-μ) / σ

z = (11,500 - 10,000) / 1000

z = 1.5

Now, find the probability of attendance figures that differs from the mean by 1500 persons or more.

P(z ≥ 1.5) = 0.0668

To find the percentage, we need to multiply the above value by 100.

P(z ≥ 1.5) × 100 = 0.0668 × 100 = 6.68%

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