34. (Double points) You help your friend construct a soap box derby car for the All-American Soap Box derby's Stock Division. Her car has a mass of
34.01 kg (75 lbs). The race lasts just 30 seconds. You think if her car attains an acceleration of 0.55 m/s² to attain a final velocity of 16.54 m/s
(37mph), she will win the race. What force would be needed to accomplish this goal.

Answer:

electric field must not exceed 5000 V / m  ( 5 kV/m)

Explanation:

All electrical equipment produces electric and magnetic fields that must be within the range recommended by WHO, the upper limit for the sum of all fields is

  The electric field must not exceed 5000 V / m

to get an idea of ​​the intensity produced by one of the devices that has the largest electric field in the radio with 180 V / m

Answer

Therefore, the angular velocity of the disk after all the sand is in place is 0.0265 rad/s.

When sand is dropped straight down onto the rotating disk, a thin uniform ring of sand is formed at a distance of 0.40 m from the axis.

The sand in the ring has a mass of 0.50 kg and the disk rotates at an angular velocity of 0.039 rad/s. The moment of intertia of the disk is 0.17kg·m².

The angular velocity of the disk after all the sand is in place is needed to be determined

The angular velocity of the disk after all the sand is in place can be determined using the principle of conservation of angular momentum.

Since there are no external torques acting on the system of the disk and sand, the angular momentum before the sand is dropped onto the disk is equal to the angular momentum after the sand is in place.

Therefore, we can write:

Iinitial = Ifinalwhere I is the moment of inertia and ω is the angular velocity.

We can find the initial angular momentum of the disk before the sand is dropped using the formula:

Linitial = Iinitial ωinitialwhere L is the angular momentum.

We know that the disk has a moment of inertia of 0.17 kg·m² and is rotating at an angular velocity of 0.039 rad/s. Therefore, Linitial = 0.17 kg·m² × 0.039 rad/s

= 0.00663 kg·m²/s

When the sand is dropped onto the disk, it will start rotating along with the disk due to frictional forces. Since the sand is dropped at a distance of 0.40 m from the axis, it will increase the moment of inertia of the system by an amount equal to the moment of inertia of the sand ring.

We can find the moment of inertia of the sand ring using the formula:

I ring = mr²where m is the mass of the sand and r is the radius of the ring. We know that the mass of the sand is 0.50 kg and the radius of the ring is 0.40 m.

Therefore, I ring = 0.50 kg × (0.40 m)²

= 0.08 kg·m²

The moment of inertia of the system after the sand is in place is equal to the sum of the moment of inertia of the disk and the moment of inertia of the sand ring.

Therefore, I final = 0.17 kg·m² + 0.08 kg·m²

= 0.25 kg·m²

We can now find the final angular velocity of the disk using the formula:

L final = I final ω final

We know that the angular momentum of the system is conserved.

Therefore, L initial = L finalor

0.00663 kg·m²/s = 0.25 kg·m² × ωfinalωfinal

= 0.00663 kg·m²/s ÷ 0.25 kg·m²ωfinal

= 0.0265 rad/s

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Answer:

The biological material used to determine a DNA profile include blood, semen, saliva, urine, feces, hair, teeth, bone, tissue and cells.

Explanation:

Answer:

bone

Explanation:

Answer:

\(\displaystyle 2\, \pi\, \sqrt{\frac{R^{3}}{G\m M}}\), where \(R\) is the orbital radius, \(M\) is the mass of the Moon, and \(G\) is the gravitational constant.

Explanation:

Let \(m\) denote the mass of the satellite. Let \(R\) denote the orbital radius, let \(M\) denote the mass of the Moon, and let \(G\) denote the gravitational constant.

The Moon would exert the following gravitational attraction on the satellite:

\(\displaystyle \frac{G\, M\, m}{R^{2}}\).

Let \(\omega\) denote the angular velocity of the satellite. For the satellite to stay in this orbit of radius \(R\), the net force on the satellite needs to be:

\(m\, \omega^{2}\, R\).

Since the gravitational force is the only force on this satellite, the net force on the satellite would be equal to the gravitational force:

\(\displaystyle m\, \omega^{2}\, R = \frac{G\, M\, m}{R^{2}}\).

Rearrange this equation to find the angular velocity:

\(\displaystyle \omega^{2} = \frac{G\, M}{R^{3}}\).

\(\displaystyle \omega = \sqrt{\frac{G\, M}{R^{3}}}\).

Note that with the Moon as the center, a full revolution around the Moon would take an angular distance of \(2\, \pi\). Divide the angular distance by the angular velocity to find the time required for this revolution:

\(\begin{aligned}T &= \frac{2\, \pi }{\omega} && \genfrac{}{}{0}{}{\text{angular displacement}}{\text{angular velocity}} \\ &= 2\, \pi \, \sqrt{\frac{R^{3}}{G\, M}}\end{aligned}\).

to find the modulus of elasticity MoE at 23% of moisture content based on the already given modulus of elasticity of 12% moisture content we need to consider a shrinkage behavior of material. the expected MoE comes out to be approximately \(6,836 N/mm².\)

given information:

Modulus of elasticity at 12% moisture content =7,920 N/mm²

resultant shrinkage or final shrinkage percentage FSP = 30%

To calculate the expected MoE at 23% moisture content we have the following equation:

MoE-23% =   \(MoE-12%\) \((1 - FSP (23 - 12) / (100 - 12))\)

MoE-23% = \(7,920 N/mm² × (1 - 0.30 × (23 - 12) / (100 - 12))\)

MoE-23% =\(7,920 N/mm² × (1 - 0.30 × 11 / 88)\)

MoE-23% = \(7,920 N/mm² × (1 - 0.1364)\)

MoE-23% = \(7,920 N/mm² × 0.8636\)

MoE-23% =  \(6,836 N/mm²\)

therefore the expected modulus of elasticity at 23% moisture content comes out to be approx \(6,836 N/mm²\).

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Answer:

I feel that people hurt the land and are destroying. I think they aren't using the land for the right reasons.

The magnetic force is perpendicular to both the direction of the current and the magnetic field.

Magnetic force is the force exerted on a charged particle moving in a magnetic field. When the charged particle moves in the direction perpendicular to the magnetic field, it experiences the magnetic force acting on it. A magnetic field is produced by a moving charged particle, such as an electron. The electric field, the force exerted on the charged particle, and the magnetic field, the force exerted on the charged particle's magnetic moment, are two forms of electromagnetic interaction.

A charged particle moving through a magnetic field experiences a magnetic force. The magnetic force (F) exerted on a charged particle moving through a magnetic field is given by: F = qvB sin θWhere:F is magnetic force q is the charge on the particle v is the speed of the particle B is the magnetic fieldθ is the angle between the magnetic field and the particle's velocity vector.

The current-carrying wire creates a magnetic field in its vicinity. A magnetic field is generated around a wire carrying a current. A magnetic field is produced by the moving charge in the wire. When a current-carrying wire is placed in a magnetic field, the magnetic force acts on it. The direction of the magnetic force can be found using the right-hand thumb rule. The magnetic force is perpendicular to both the direction of the current and the magnetic field.

Complete Question:

If A Current Carrying Wire Is Pointed Into The Sky (+Z), What Direction Is The Force On It If The Wire Is In An External Magnetic Field Which Is Pointed North? A. North B. South C. East D. West

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Answer:

Option C is the correct answer

Explanation:

Distance travelled by car during reaction time

\(=15\times0.4\\\\=6m\)

The car stopped before hitting the animal by \(1 m\)

Distance travelled during deceleration is \(21-6-1=14m\)

Hence by \(v^2=u^2+2as\)

We have

\(0^2=15^2+2 \cdot a \cdot 14\\\\a=\frac{-225}{28} \\\\=-8.03m/s^2\)

Option C is the correct answer

Distance traveled during reaction time

Total distance

\(\\ \sf\longmapsto v^2-u^2=2as\)

\(\\ \sf\longmapsto -(15)^2=2(14)a\)

\(\\ \sf\longmapsto -225=28a\)

\(\\ \sf\longmapsto a=-8.0m/s^2\)

Answer:

hope this helps

Explanation:

Of the three phases of matter (gas, liquid, and solid), sound waves travel the slowest through gases, faster through liquids, and fastest through solids

so your answer would be B.

Surface-level diversity refers to the easily observable characteristics of individuals while deep-level diversity refers to the less visible characteristics. The link between attitude and behavior is that our attitudes often influence our behaviors.

Race, age, gender, and physical appearance are some of the characteristics under surface-level diversity. On the other hand, characteristics such as personality, values, beliefs, and attitudes, are some of deep-level diversity.

The link between attitude and behavior is that our attitudes often influence our behaviors. For example, if someone has a positive attitude towards exercise, they are more likely to engage in physical activity. However, it is important to note that attitudes do not always predict behavior, as there can be other factors that influence our actions, such as social norms and external pressures.

In the context of diversity, understanding both surface-level and deep-level diversity can help organizations create a more inclusive and respectful workplace. By acknowledging and valuing the differences among employees, organizations can create a positive work environment and foster better teamwork and collaboration.

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Answer:

3.

Force(f) =2000N

Distance (d) =10m

Time(t)=50 sec

We know,

P=W/t

=f×d/t

=2000×10/50

=400 watt

4.

Force(f) =30N

Distance (d) =10 m

Time(t) =5 sec

We know,

P=w/t

=f×d/t

=30×10/5

=60 watt

Formula of

Line segment

is AB =

\(\sqrt{(x_{2} -x_{1} )^{2} } +\sqrt{(y_{2} -y_{1} )^{2} }\)

Line segment

is a part of line with definite length. It has two ending points whereas a line has no end points and extended infinitely in both the direction. Line which joins both ending points with possible shortest way is known as

Line segment

.

            A ______________________ B    

        (x₁,y₁)                                             (x₂,y₂)      

This line segment can be represented as \(\frac{}{AB} /\frac{}{BA}\). In other word we can say line segment is

subset

of line, so it contains all the points of line lying between both end point of segment. For shorter length it can simply measure by

ruler

. A bar (-) is always on top of its notation {\(\frac{}{AB}\)}.

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Formula of Line segment is AB =  \(\sqrt{(x_{2}-x_{1})^{2} } +\sqrt{(y_{2}-y_{1})^{2} }\)

Line segment

is a part of line with a definite length. It has two ending points whereas a line has no end points and extended infinitely in both the direction. Line which joins both ending points with possible shortest way is known as

Line segment

        A ______________________ B    

       (x₁,y₁)                                             (x₂,y₂)      

This line segment can be represented as\(\overline{AB}/\overline{BA}\) . In other word we can say line segment is subset of line, so it contains all the points of line lying between both end point of segment. For shorter length it can simply measure by ruler A bar (-) is always on top of its notation {\(\overline{AB}/\overline{BA}\)}.

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The minimum thickness of the electrolyte must be at least 1/108 m, or 0.009 m.

Electrolytes are minerals found naturally in the body, including sodium, potassium, chloride, calcium, phosphorus, and magnesium. They play a key role in maintaining healthy bodily functions, as they help regulate fluid balance, blood pressure, and the pH level of the body’s fluids. When these electrolytes become imbalanced, it can lead to a variety of health issues, including dehydration, muscle cramps, headaches, and fatigue. To maintain electrolyte balance, one needs to consume the right amount of electrolytes through both diet and supplementation.

The absolute minimum thickness of the electrolyte would be determined by the dielectric breakdown strength of the electrolyte, which is 108 V/m. The voltage across the electrolyte will be 1 V, so the minimum thickness of the electrolyte must be at least 1/108 m, or 0.009 m.

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Complete Question:
4.8 Given that fuel cell voltages are typically around 1 V or less, what would be the absolute minimum possible functional electrolyte thickness for a SOFC if the dielectric breakdown strength of the electrolyte is 108 V/m?

Answer:

A generator is a device that converts mechanical energy into electrical energy by rotating a coil of wire in a magnetic field.

A linear spring has to stretch 0.1m to have a potential energy of 0.10j.

0.5kx^2 = 0.1

0.5*20*x^2 = 0.1

x = sqrt(1/100)

x = 0.1 m

Potential energy is the stored power in an item because of its role, its residences, and the forces performing on it.

The two main kinds of potential strength are gravitational potential energy and elastic potential power. The unit for energy inside the global gadget of devices (SI) is the joule, which has the symbol J.

Potential energy is the latent strength in an object at rest and is certainly one of two kinds of power. Capability power is power this is saved – or conserved - in an item or substance. This stored power is based totally on function.

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When the figure skater goes into a spin and extends her arms horizontally, her angular speed changes due to the conservation of angular momentum.

Angular momentum is the product of an object's moment of inertia and its angular velocity. In this case, the figure skater's moment of inertia changes as she extends her arms, since the distribution of her mass shifts farther away from her axis of rotation.

When her arms are close to her body, her moment of inertia is relatively small. As she extends her arms, her moment of inertia increases because her mass is now distributed over a larger area. To conserve angular momentum, her angular speed must decrease. This is because when the moment of inertia increases, angular velocity must decrease in order to maintain a constant angular momentum.

This principle is the same reason why an ice skater can speed up their spin by pulling their arms and legs in, or slow down by extending them outwards. In summary, when a figure skater extends her arms horizontally during a spin, her angular speed changes by decreasing in order to conserve angular momentum.

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Answer:

MY friend has already described the purpose of projectile motion so I will quickly go through the uses of each equation ...

Explanation:

TIME OF FLIGHT = it is given as 2Usin tita/g...it is the total time taken to and fro...it is 2x of the time taken ....

TIME taken ..t= Usin tita / g.....is the time taken to reach the maximum height which is 1/2 the TOTALTIME OF FLIGHT GIVEN ABOVE ..

MAXIMUM HEIGHT: the maximum height is the height attained by the projectile when projected ...it is calculate using the formula = U^2 sin^2 tita / 2g

Range =Search Results

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An object launched into projectile motion will have an initial launch angle anywhere from 0 to 90 degrees. The range of an object, given the initial launch angle and initial velocity is found with: R=v2isin2θig R = v i 2 sin ⁡ 2 θ i g .

Answer:

(a) h = 5.1 m

(b) v = 14.13 m/s

Explanation:

(a)

We will use the law of conservation of energy. For this situation it states that:

Loss in Potential Energy of Sphere = Gain in Kinetic Energy of the Sphere

mgh = (1/2)mv²

h = v²/2g   --------------- equation (1)

where,

h = height = ?

v = speed at lowest point = 10 m/s

g = 9.8 m/s²

Therefore,

h = (10 m/s)²/(2)(9.8 m/s²)

h = 5.1 m

(b)

using the equation (1)

h = v²/2g

v = √2gh

where,

v = velocity = ?

g = 9.8 m/s²

h = height = 2(5.1 m) = 10.2 m

Therefore,

v = √[2(9.8 m/s²)(10.2 m)]

v = 14.13 m/s

The height from which the sphere was released is 5.1 m

When the height is doubled, the speed of the sphere becomes 14.14 m/s.

The given parameters:

The height from which the sphere was released is calculated as follows;

\(P.E = K.E\\\\mgh = \frac{1}{2}mv^2\\\\gh = \frac{1}{2}v^2\\\\h = \frac{v^2}{2g}\\\\h = \frac{(10)^2}{2(9.8)} \\\\h = 5.1 \ m\)

When the height is doubled, the speed of the sphere becomes;

\(h = \frac{v^2}{2g} \\\\v^2 = 2gh\\\\v = \sqrt{2gh} \\\\v = \sqrt{2 \times 9.8 \times (2 \times 5.1)} \\\\v = 14.14 \ m/s\)

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Answer:

A. The angle with which the light passes from glass into water is approximately 31.97°

B. The image formed is, real, inverted, and smaller than the object

C. The image distance is 53.2\(\overline 6\) cm

The image is real

D. The magnification is approximately 0.182

E. The type of lens required is a concave lens which corrects the focus of a powerful eye lens or a long eyeball

Explanation:

The given parameters for the light wave are;

The refractive index of the glass medium, n₁ = 1.5

The angle of incidence of the light, θ₁ = 28°

The refractive index of water, n₂ = 1.33

A. Let θ₂ represent the angle with which the light passes from glass into water

Snell's law is mathematically stated as follows;

n₁·sin(θ₁) = n₂·sin(θ₂)

According to Snell's law, we have;

1.5 × sin(28°) = 1.33 × sin(θ₂)

sin(θ) = (1.5 × sin(28°))/1.33 = 0.52947920615

∴ θ₂ = arcsin(0.52947920615) ≈ 31.97°

The angle with which the light passes from glass into water, θ₂ ≈ 31.97°

B. Please find attached the drawing of the image created with Microsoft Visio

From the drawing, we have that the image formed is real inverted smaller than the object and between the focus and radius of curvature

C. The location of the object from the mirror, u = 94.0 cm

The focal length of the mirror, f = +34.0 cm

The mirror formula for a concave mirror is given as follows;

\(\dfrac{1}{f} = \dfrac{1}{u} + \dfrac{1}{v}\)

Therefore, we have;

\(\dfrac{1}{34.0} = \dfrac{1}{94.0} + \dfrac{1}{v}\)

\(\dfrac{1}{v} = \dfrac{1}{34.0} - \dfrac{1}{94.0} = \dfrac{15}{799}\)

\(\therefore \dfrac{v}{1} = v =\dfrac{799}{15} = 56.2\overline 6\)

The image distance, v = 799/15 = 53.2\(\overline 6\) cm

Therefore the image is in front of the mirror, which is a real image

The image is real

D. The given parameters of the object and lens are;

The distance of the object from the lens, u = 65.0 cm

The distance of the image formed from the lens, i = -18 cm

The magnification, M, is given as follows;

\(M = \dfrac{-v}{u}\)

Therefore;

\(M = \dfrac{-(-11.8)}{65.0} = \dfrac{59}{325} \approx 0.18153846153\)

The magnification, M ≈ 0.182

E. For a person who is near sighted, the light from objects from distant location are almost parallel and are brought to a focus in front of the retina and therefore, they appear blurred

The use of a concave lens is required to correct nearsightedness as it causes the light to appear come from a point before the focus such that the divergent rays of the object refracted through the concave lens comes to a focus at the.

Answer:

Explanation:

okk

weather is everyday things

weather could be a hurricane

weather could be a tornado

climate is more long term over time

example the climate in Antarctica is cold because it happens over long periods overtime

Answer:

Distancia, S = 2.84 metros

Explanation:

Dados los siguientes datos;

Velocidad inicial = 55 m/s

Velocidad final = 115 m/s

Deceleración = 14500 m/s²

Para encontrar qué tan lejos viajaría el automóvil, usaríamos la tercera ecuación de movimiento;

V² = U² + 2aS

115² = 55² + 2*14500*S

13225 = 3025 + 29000S

29000S = 13225 - 3025

29000S = 10200

S = 29000/10200

Distancia, S = 2.84 metros

Answer: 1102.5 meters

Explanation:

Answer:

What's the question?

Explanation:

Answer:

the sciences concerned with the study of inanimate natural objects, including physics, chemistry, astronomy, and related subjects. Often contrasted with life sciences. I don't know why but i like physics and all this stuff.

Explanation:

The  value of the external resistor required is approximately 173 ohms.

To calculate the value of the external resistor required when a silicon diode is connected to an 18 volt source with 100 mA of current flowing through it, we need to use the following formula:

V = Vd + I*R

where V is the voltage of the power supply, Vd is the forward voltage drop across the diode, I is the current flowing through the circuit, and R is the resistance of the external resistor.

For a silicon diode, the typical forward voltage drop is around 0.7 volts. Therefore, we can rewrite the formula as:

R = (V - Vd) / I

Substituting the given values, we get:

R = (18 V - 0.7 V) / 0.1 A ≈ 173 Ω

Therefore, the value of the external resistor required is approximately 173 ohms.

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The total angle the tires rotate through during the 2.28 km trip is approximately 8602 radians.

To find the total angle (in radians) the tires rotate through during a 2.28 km trip with wheels having a radius of 26.5 cm, follow these steps:

1. Convert the distance to meters:

2.28 km = 2280 meters.

2. Convert the wheel radius to meters:

26.5 cm = 0.265 meters.

3. Calculate the circumference of the wheel using the formula C = 2πr, where C is the circumference and r is the radius:

C = 2π(0.265 m) ≈ 1.665 meters.

4. Determine the number of wheel rotations by dividing the total distance by the circumference:

2280 meters / 1.665 meters ≈ 1369 rotations.

5. Calculate the total angle in radians by multiplying the number of rotations by 2π radians (1 full rotation):

1369 rotations × 2π radians ≈ 8602 radians.

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The centre of mass of the 20 shape bounded by the lines: a) The massis 8.775 kg. The moment is 3.947 kg·m. The x-coordinate is 0.993 m. b) The mass is 59.217 kg. The moment is 31.749 kg·m. The x-coordinate is 0.993 m.

a) To find the mass of the 2D plate, we need to calculate its area first. The shape bounded by the lines y = 1.3x and x = 0 to 1.9 forms a right triangle.

The base of the triangle is 1.9 units, and the height is given by y = 1.3x. Integrating y with respect to x over the given range, we find the area of the triangle to be 2.775 units².

Multiplying the area by the uniform density of 2.7 kg/m², we obtain the mass of the 2D plate as 8.775 kg.

To calculate the moment of the 2D plate about the y-axis, we need to integrate x times the density over the area of the plate.

Integrating x * (1.3x) with respect to x over the given range, we find the moment to be 3.947 kg·m.

The x-coordinate of the centre of mass of the 2D plate can be determined using the formula for the centre of mass of a two-dimensional system: x = moment / mass. Substituting the values, we find the x-coordinate to be 0.993 m.

b) To find the mass of the 3D body, we need to calculate its volume first. By rotating the lines y = 1.3x and x = 0 to 1.9 about the x-axis, we obtain a solid with a known volume. Using the formula for the volume of a solid of revolution,

we can calculate the volume of this solid as 18.869 m³. Multiplying the volume by the uniform density of 3.1 kg/m³, we obtain the mass of the 3D body as 59.217 kg.

To calculate the moment of the 3D body about the y-axis, we need to integrate x² times the density over the volume of the body.

Integrating x² * (1.3x)² with respect to x over the given range,

we find the moment to be 31.749 kg·m.

The x-coordinate of the centre of mass of the 3D body can be determined using the formula for the centre of mass of a three-dimensional system: x = moment / mass. Substituting the values, we find the x-coordinate to be 0.993 m.

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