32


{(-0. 25, 2. 5), (1. 75, -5. 5), (3. 25, -11. 5)}


Write an equation in the form of y = mx + b that represents this linear function?

Answer:

18 eggs

Step-by-step explanation:

Answer:

The distance is 14 units

Step-by-step explanation:

Four scoops for $4.28 is the best rate. Therefore, option C is the correct answer.

Given that, 2 scoops for $2.98

We know that, unit rate = Total cost/Number of things

Here, 1 scoop = 2.98/2

= $1.49

3 scoops for $3.69

Here, 1 scoop = 3.69/3

= $1.23

4 scoops for $4.28

Here, 1 scoop = 4.28/4

= $1.07

Comparison 2 scoops for $2.98 is more costlier and 4 scoops for $4.28 is cheaper.

Therefore, option C is the correct answer.

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Answer:

1 / 663

Step-by-step explanation:

First, let's find the total number of ways you can pick 2 cards from the deck. This is 52 * 51 = 2652 because there are 52 cards available for your first pick, and after you pick one, you'll have 51 left for your second pick.

There are 4 5's  (one for every suite) and only 1 Queen of Hearts in a deck of cards. Therefore, the total number of successful outcomes will be 4 * 1 = 4.

The probability of picking a 5 and then a Queen of Hearts is 4 / 2652 =

1 / 663. Hope this helps!

-1

- 3/5

- 0.5

-0.4

The least is always the one furthest away from 0

Sampling from a finite population is analogous to sampling from an infinite population when the sample size is small relative to the size of the finite population, and the sampling is done without replacement

In case the sample size is less than 5% of the population, then sampling from a finite population is analogous to sampling from an infinite population.

When the sample size exceeds 5% of the population, the sample size is large enough that the sample distribution of the sample means becomes approximately normal, allowing us to use the t-distribution to test hypotheses about the population mean or to construct confidence intervals for the population mean, regardless of whether the population is finite or infinite.

The percentage of the population covered by the sample size is calculated using the following equation:

Sample percentage = Sample size/Population size x 100 %

When the sample percentage is less than 5%, it is known as a small sample size. When the sample percentage is greater than 5%, it is referred to as a large sample size.

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Given:

The length of the top diagram is 60 units.

Required:

The length of the bottom diagram.

Explanation:

Now the first diagram has two parts 80% and 20%, and the 20% further gives us the second diagram.

So to know the length of second diagram we need to find the 20% of first diagram.

so we need to calculate 20% of 60, that is

So the length of second diagram is 12 units.

Now the second diagram has two parts 60% and 40%, and the 60% further gives us the third diagram.

So to know the length of third diagram we need to find the 60% of second diagram.

so we need to calculate 60% of 12, that is

So the length of third diagram is 7.2 units.

Now the third diagram has two parts 30% and 70%, and the 70% further gives us the fourth diagram.

So to know the length of the fourth diagram we need to find the 70% of the third diagram.

So we need to calculate 70% of 7.2, that is

So the length of fourth diagram is 5.04 units

Final Answer:

The length of the bottom diagram, that is the fourth diagram, is 5.04 units.

Answer:

0.001

Step-by-step explanation:

So... errr... brainly doesn't allow cheating but i want to help so... here:

10^(-n)= 1/(10^n) following this, 10^-3=1/10^3 = 1/1000 = the second option (0.001)

In the given figure of circle, if RT = 90, SU = 25, and SO is perpendicular to RT, the length of the radius RO is 53.

In the given figure,

RT = 90

SU = 25

SO is perpendicular to RT.

Here, SO and RO are the radii of the circle and RT is a chord.

The length of the chord, RT is given as,

RT = 2 √(r² - d²)

Here, r is the radius and d is the distance of the chord RT from the center O.

Radius, r = RO and distance, d = OU

∴ RT = 2 √(RO² - OU²)

Substituting RT = 90 in the above equation, we get,

90 = 2 √[(RO)² - (OU)²]

√[RO)² - (OU)²]  = 45

(RO)² - (OU)² = 45²

(RO)² - (OU)² = 2025 ........... (1)

Now, OU = SO - SU   [From the figure]

⇒ OU = SO - 25

Substituting OU = SO - 25 in equation (1), we obtain,

(RO)² - (SO - 25)² = 2025

(RO)²- [(SO)² + (25)² - 2(SO)(25)] = 2025    [ ∵ (a-b)² = a²+b²-2ab ]

(RO)²- (SO)² - (25)² + 50(SO) = 2025 ........... (2)

Since, RO and SO both are the radii of the same circle, we have,

SO = RO

Thus, we can write equation (2), as follows,

⇒ (RO)² - (RO)² - (25)² + 50(RO) = 2025

⇒ -625 + 50RO = 2025

⇒ 50RO = 2025 + 625

⇒ RO = 2650/50

⇒ RO = 53

Hence, the length of the radius RO of the given circle is 53.

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Answer:

a) 3, 6, 9, 12, 15,...,\(3\cdot n\), b) 4, 7, 10, 13, 16,...,\(3\cdot n +1\), c) Both sequences are arithmetic.

Step-by-step explanation:

a) The sequence of natural numbers which are multiplied by 3 are represented by the function \(f(n) = 3\cdot n\), \(n\in \mathbb{N}\). Let see the first five elements of the sequence: 3, 6, 9, 12, 15,...

b) The sequence of natural numbers which are multiplied by 3 and added to 1 is represented by the function \(f(n) = 3\cdot n + 1\), \(n\in \mathbb{N}\). Let see the first five elements of the sequence: 4, 7, 10, 13, 16,...

c) Both sequences since differences between consecutive elements is constant. Let prove this statement:

(i) \(f(n) = 3\cdot n\)

\(\Delta f = f(n+1) -f(n)\)

\(\Delta f = 3\cdot (n+1) -3\cdot n\)

\(\Delta f = 3\)

(ii) \(f(n) = 3\cdot n +1\)

\(\Delta f = f(n+1)-f(n)\)

\(\Delta f = [3\cdot (n+1)+1]-(3\cdot n+1)\)

\(\Delta f = 3\)

Both sequences are arithmetic.

Answer:

466 + 68

Step-by-step explanation:

We can easily check a subtraction problem with an addition problem.

Calculate the sum of the subtracted and the difference. If the sum is equal to the minuend in the original subtraction problem, the answer is correct.

Minuend - Subtrahend = Difference

466 + 68 = 534

The statement '534 – 68 = 466' is correct.

Hope this helps.

Answer:

68+566

Step-by-step explanation:

to tell if you have the right number or answer make sure if it's addition just subtract it and see what you get

Answer:

-6

Step-by-step explanation:

Phase 5: The system of implementation is conversion.

Option B is the correct answer.

We have,

Phase 5 of the system development life cycle is commonly referred to as "Conversion" or "Systems Implementation."

During this phase,

The focus shifts from planning and designing the system to actually implementing it.

This phase involves the conversion of the old system to the new system, which includes activities such as data conversion, software installation, hardware setup, user training, and system testing.

The term "Conversion" is used because it signifies the transition from the old system to the new system.

It involves migrating data, processes, and operations from the existing system to the new system.

This phase ensures that the newly developed system is successfully integrated into the organization and becomes fully operational.

Thus,

Phase 5: The system of implementation is conversion.

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The amount of element left after the decay is found as 43 grams.

Decay rate is given as:

N = N₀(1 - r)ˣ

x - is the time in minutes

N₀ - initial mass (570 grams)

r - rate of decay (18%)

Put the values:

N = 570(1 - 0.18)¹³

N = 570*0.0757

N = 43

Thus, the amount of element left after the decay is found as 43 grams.

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The answer is b

In this image is the explanation, just click on it

At a standard deviation of $15,000, the probability that the condominium will sell at a price below $200,000 is 0.2525 and above $240,000 is 0.02. At a standard deviation of $20,000, the probability that the condominium will sell at a price below $200,000 is 0.3085 and above $240,000 is 0.0668.

From the given question;

Let the average sale price(μ)=210,000

Standard Deviation(σ)=$15,000

(a) We have to find the probability that the condominium will sell at a price.

(i) below $200,000, i.e. P(x<200,000)

Z=(x−μ)/σ

Z=(200,000−210,000)/15,000

Z= −10,000/15000

Z= −0.67

Now finding P(x<200,000) is same as finding P(Z<−0.67) using the standard table of z.

P(Z<−0.67) = 0.2525

(ii) above $240,000, i.e. P(x>240,000)

Z=(x−μ)/σ

Z=(240,000−210,000)/15,000

Z= 30,000/15000

Z= 2

Now finding P(x>240,000) is same as finding P(Z>2) using the standard table of z.

P(Z>240,000)=P(Z>2)

P(Z>240,000)=1−P(Z<2)

P(z>240,000)=1−0.98

P(z>240,000)=0.02

(b) Now the average sale price(μ)=210,000

Standard Deviation(σ)=$20,000

We have to find the probability that the condominium will sell at a price.

(i) below $200,000, i.e. P(x<200,000)

Z=(x−μ)/σ

Z=(200,000−210,000)/20,000

Z= −10,000/20000

Z= −0.5

Now finding P(x<200,000) is same as finding P(Z<−0.5) using the standard table of z.

P(Z<−0.5) = 0.2085

(ii) above $240,000, i.e. P(x>240,000)

Z=(x−μ)/σ

Z=(240,000−210,000)/20,000

Z= 30,000/20000

Z= 1.5

Now finding P(x>240,000) is same as finding P(Z>1.5) using the standard table of z.

P(Z>240,000)=P(Z>1.5)

P(Z>240,000)=1−P(Z<1.5)

P(z>240,000)=1−0.93319

P(z>240,000)=0.0668

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Cassandra will earn $65 in simple interest at the cease of the 4 years.

The formulation for simple interest is:

I = P * r * t

Wherein

In this case Cassandra's preliminary deposit is $500 so that' why the interest rate is some about 3.25% & the time period is four years.

Plugging these values into the formulation, we get:

I = $500 * 0.0325 * 4

I = $65

Therefore, Cassandra will earn $65 in simple interest at the cease of the 4 years.

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Answer:

Material one (2:25)

Step-by-step explanation:

Given that:

Lycra:Other material

2:25

3:40

Now, change it to the form of 1:n:

2:25 = 1:12.5

3:40 = 1:13.33

Now write proportions for each of them:

1:12.5 = 1/13.5

1:13.33 = 1/14.33

Now compare:

1/13.5 > 1/14.33

Hope this helps good luck

It is possible for there to be a real number t such that tan(t) is equal to 5/4.

The tangent function (tan) is a periodic function that repeats its values every π radians or 180 degrees. It has both positive and negative values across its periodicity. Therefore, for any given value of tan(t), there are multiple solutions.

To find a specific angle where tan(t) is equal to 5/4, we can use inverse trigonometric functions. The inverse tangent function (arctan or \(tan^{-1}\)) can be used to find the angle associated with a given tangent value.

In this case, we can find an angle t such that tan(t) = 5/4 by taking the inverse tangent of 5/4. Using a calculator or mathematical software, we find that arctan(5/4) is approximately 51.34 degrees or approximately 0.896 radians.

Therefore, there exists a real number t such that tan(t) is equal to 5/4, specifically at approximately t = 51.34 degrees or t = 0.896 radians.

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If 100 students participate in the fundraiser, each student needs to raise $137.50.If 25 students participate in the fundraiser, each student needs to raise amount $550.

Amount = (Total Amount Needed) ÷ (Number of Students)

For 60 students:

Amount = $275 ÷ 60 = $4.58

For 75 students:

Amount = $275 ÷ 75 = $3.67

For 40 students:

Amount = $275 ÷ 40 = $6.88

To solve this problem, we need to use a simple equation: Amount = (Total Amount Needed) ÷ (Number of Students). We can then plug in the given information to calculate the amount each student needs to raise. For example, if 50 students participate in the fundraiser, we can calculate that each student needs to raise $275 ÷ 50 = $5.50. We can then use this equation to calculate the amount that each student needs to raise if there are different numbers of students participating in the fundraiser. For example, if there are 100 students participating in the fundraiser, each student needs to raise $275 ÷ 100 = $2.75. Similarly, if there are 25 students participating in the fundraiser, each student needs to raise $275 ÷ 25 = $11.00.

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Answer:

The vertices of the image after rotating triangle uvw 90 degrees counterclockwise are u′(0, −2), v′(1, −3), w′(3, −3).

Step-by-step explanation:

Within the relevant range, a curvilinear cost function can be graphed as a curved line. A curvilinear cost function is a cost function where the total cost changes as a function of the level of activity, but not at a constant rate.

This means that as the level of activity increases, the cost per unit may increase or decrease, resulting in a curved relationship between the level of activity and the total cost. In order to determine the optimal level of activity, a manager can use calculus to find the point where the marginal cost equals the marginal revenue.

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Answer:

The domain is \({(-2,1),(-1,2),(-3,\dfrac{5}{3})}\)

Step-by-step explanation:

Given that,

The function is

\(f(x,y)=(-2x,-3y+1)\)

The coordinates of range are,

\(range=(4,-2), (2,-5), (-6,4)}\)

The domain is,

\(Domain={(x_{1},y_{1}),(x_{2},y_{2}),(x_{3},y_{3})}\)

We need to find the value of x₁ and y₁

Using given function

\(f(x.y)=(-2x,-3y+1)\)

\(f(x_{1},y_{1})=(4,-2,)\)

\((-2x_{1},-3y_{1}+1)=(4,-2)\)

On equating value of x

\(-2x_{1}=4\)

\(x_{1}=-2\)

On equating value of y

\(-3y_{1}+1=-2\)

\(-3y_{1}=-2-1\)

\(y_{1}=\dfrac{-2-1}{-3}\)

\(y_{1}=1\)

We need to find the value of x₂ and y₂

Using given function

\(f(x_{2},y_{2})=(2,-5,)\)

\((-2x_{2},-3y_{2}+1)=(2,-5)\)

On equating value of x

\(-2x_{2}=2\)

\(x_{2}=-1\)

On equating value of y

\(-3y_{2}+1=-5\)

\(-3y_{2}=-5-1\)

\(y_{2}=\dfrac{-5-1}{-3}\)

\(y_{2}=2\)

We need to find the value of x₃ and y₃

Using given function

\(f(x_{3},y_{3})=(-6,4,)\)

\((-2x_{3},-3y_{3}+1)=(-6,4)\)

On equating value of x

\(-2x_{3}=-6\)

\(x_{3}=-3\)

On equating value of y

\(-3y_{3}+1=-4\)

\(-3y_{3}=-4-1\)

\(y_{3}=\dfrac{-4-1}{-3}\)

\(y_{3}=\dfrac{5}{3}\)

We need to find the domain

Using domain

\(Domain={(-2,1),(-1,2),(-3,\dfrac{5}{3})}\)

Hence, The domain is \({(-2,1),(-1,2),(-3,\dfrac{5}{3})}\)

Answer:

ITS B, 5k

hint: it says (times) so it has to be mutilication

Step-by-step explanation:

a)  P(X=330) is approximately 0.0002. b)P(X>340) is approximately 0.0294. c) P(335≤X≤345) is approximately 0.6415. d) P(X=300) is approximately 0.0004 of given probabilities

To find the probabilities using Excel's function options, we can use the binomial distribution function, which is provided as BINOM.DIST in Excel.

a) P(X=330):

=BINOM.DIST(330, 400, 0.8, FALSE)

The first argument is the specific value (330), the second argument is the total number of trials (400), the third argument is the probability of success (0.8), and the fourth argument FALSE indicates that we want the probability for a specific value.

The result is approximately 0.0002.

Therefore, P(X=330) is approximately 0.0002.

b) P(X>340):

=1 - BINOM.DIST(340, 400, 0.8, TRUE)

Since we want the probability of X being greater than 340, we can subtract the cumulative probability of X up to 340 from 1. We use the TRUE argument to indicate that we want the cumulative probability.

The result is approximately 0.0294.

Therefore, P(X>340) is approximately 0.0294.

c) P(335≤X≤345):

=BINOM.DIST(345, 400, 0.8, TRUE) - BINOM.DIST(334, 400, 0.8, TRUE)

To find the probability of X being between 335 and 345 (inclusive), we subtract the cumulative probability of X up to 334 from the cumulative probability of X up to 345.

The result is approximately 0.6415.

Therefore, P(335≤X≤345) is approximately 0.6415.

d) P(X=300):

=BINOM.DIST(300, 400, 0.8, FALSE)

The first argument is the specific value (300), the second argument is the total number of trials (400), the third argument is the probability of success (0.8), and the fourth argument FALSE indicates that we want the probability for a specific value.

The result is approximately 0.0004.

Therefore, P(X=300) is approximately 0.0004.

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Step-by-step explanation:

circumcentre:

In geometry, the circumscribed circle or circumcircle of a polygon is a circle that passes through all the vertices of the polygon. The center of this circle is called the circumcenter and its radius is called the circumradius. Not every polygon has a circumscribed circle.

othocentre:

The orthocenter is the intersection point of three altitudes drawn from the vertices of a triangle to the opposite sides. A centroid is the intersection point of the lines drawn from the midpoints of each side of the triangle to the opposite vertex.