3. WHAT IS THE DIFFERENCE BETWEEN LAYOUT AND MEASUREMENT?
Answers
Related Questions
People tend to self-disclose to others that are in age, social status, religion, and personality.
Answers
Answer:people tend to do this when they are in a different environment they lose something or just have something going on in their life
Explanation:
rank the following gases in order of decreasing rate of effusion. rank from the highest to lowest effusion rate. to rank items as equivalent, overlap them.
Answers
It means that the gas with the lowest molecular weight will have the highest effusion rate.
What has the highest rate of effusion?The given gases' effusion rates are listed in order from highest to lowest. The effusion rate of a hydrogen molecule is the highest, whereas that of a hydrocarbon is the lowest.
A gas will effuse faster when it is lighter and more slowly when it is heavier. Helium (He) will have the highest rate of effusion since it has the lowest molecular weight (atomic weight, in this example).
The following equation can be used to compare the rate of effusion for two gases: The effusion rates in this case are inversely related to the square root of the gas molecules' masses. A container contains an amalgam of neon and argon gas.
To learn more about rate of effusion is refer to:
https://brainly.com/question/28747259
#SPJ4
Select the four areas in which environmental engineers assist manufacturers with making decisions.
energy
pollution
money
time
development
creativity
Personally, I did the first 4, since pollution is a big factor, money and time can be helped with by making decision matrixes (usually done by the engineers to help the client) and energy, since that could also be decided using a decision matrix. Thank you for your help!
Answers
Answer:
In my opinion, Energy, Time, Money and Development
Answer:
Pollution, time, money, and energy.
Explanation:
I need a word problem for y=2x
Answers
The word problem for y = 2x is as follows.
"If y is the number of cakes produced by using 2 amounts of backing ingredients (x), find the number of cakes produced if x is 25."
What is a word problem?A word problem is a mathematical exercise in scientific education in which substantial background information about the subject is conveyed in regular English rather than mathematical notation.
A word problem in mathematics is a math question expressed as one or more sentences that demand students to apply their arithmetic skills to a real-life setting.
This implies that in order to understand the word problem, students must be conversant with the terminology linked with the mathematical symbols to which they are used.
Learn more about word problems:
https://brainly.com/question/2610134
#SPJ1
Why do they use 316 stainless steel for cryogenic applications, and not 430?Mo, for example has a great high-temperature performance (e.g., potential use as a turbine blade material for aircraft engines). WHat is the problem with using it (Hint: What is its crystal structure?)?What do you think would happen on the brittle-to-ductile temperature of your steel sample if its grain size was reduced. (Why?)
Answers
The reason 316 stainless steel is used for cryogenic applications instead of 430 stainless steel is due to its higher resistance to corrosion and better mechanical properties at low temperatures.
The problem with using molybdenum for high-temperature applications like turbine blades in aircraft engines is its crystal structure. Molybdenum has a body-centered cubic (BCC) crystal structure, which tends to be more brittle at low temperatures and prone to embrittlement at high temperatures, reducing its effectiveness as a material for such applications.
If the grain size of a steel sample was reduced, the brittle-to-ductile temperature would likely decrease. This is because reducing the grain size increases the number of grain boundaries, which impedes the movement of dislocations within the material. This, in turn, can enhance the material's ductility and make it less prone to brittle failure at lower temperatures.
Learn more about Crystal structure: https://brainly.com/question/29398453
#SPJ11
Problem 3. The uniform beam is supported by two rods AB and CD that have cross-sectional areas of 10 mm2 and 15mm2, respectively. Determine the intensity w of the distributed load so that the average normal stress in each rod does not exceed 300 kPa.
Answers
Answer:
hello the diagram related to your question is missing attached below is the required diagram.
The value of AC = 6m
answer 2.25 N
Explanation:
From the diagram attached below
average intensity of loading = w/2
Total load due to linearly varying load = \(\frac{wL}{2}\)
w = maximum intensity of load , L = span of varying load
since AC = 6m( L ) then
Total load due to linearly varying load = 3w ------ ( 1 )
attached below is the detailed solution of the given problem
Due to crashes at a railroad crossing in Salem, Oregon, an overpass (with a roadway surface 26 ft above the existing road) is to be constructed on an existing level highway. The existing highway has a design speed of 50 mi/h. The overpass structure is to be level, centered above the railroad, and 180 ft long. What length of the existing level highway must be reconstructed to provide an appropriate vertical alignment
Answers
Answer:
Oregon had 19 railroad crossing accidents in 2018, up from 10 in 2013. Marion County has more than most counties, logging 28 since 2008.
Explanation:
It provides explicit guidance to improve railroad crossing safety to support ODOT’s mission of a safe and efficient transporta-tion network, but is not a policy plan. Rather, it is an action plan to help ODOT achieve greater railroad crossing safety.
To establish a suitable vertical alignment, the present level highway's 2115-foot length needs to be rebuilt.
What is Vertical alignment?The ground's gradient and vertical curves are both included in vertical alignment.
For above given example,
Calculating the maximum permitted gradient is possible.
\(G = (V^2) / (29.83R)\)
where, G is the gradient,
V is the design speed in mph.
R is the curvature's radius in feet.
\(G = (55^2) / (29.83 * 26)\)= 0.72%
Calculating the minimum viewing distance as:
\(S = 1.47Vt + 2.3(t^2) / (3.5K) (3.5K)\)
where t is the perception-reaction time in seconds, K is the coefficient of friction, and S is the minimum sight distance in feet.
The minimum sight distance can be estimated as follows using an assumption of a perception-reaction time of 2.5 seconds and a coefficient of friction of 0.3:
524.3 feet are equal to S = 1.47 x 55 x 2.5 + 2.3(2.52)/(3.5 x 0.3)
Now that we know how long the current level highway is,
The overpass's length and the sag curve's length are equal.
The following equation can be used to determine the length of the crest curve:
\(L = (S^2) / (8G)\)
where L is the length of the crest curve, S is the shortest sight distance, and G is the highest permitted gradient.
\(L = (524.3^2) / (8 * 0.0072) = 188,607.8 ft\)
The length of the sag curve, the length of the crest curve, and the length of the transition curves all make up the entire length of the level highway that needs to be rebuilt.
Assuming a 50-foot-long transition curve, we obtain:
Overall length is equal to 180 + 188,607.8 + (2 x 50) ft.= 2115 feet
Thus, the existing level highway measures 188,887.8 feet in length, which is equal to 2,265,853.6 inches or 2115 feet.
Learn more about the vertical curve, here:
brainly.com/question/28812778
#SPJ2
Your question is incomplete, most probably the complete question is:
Due to crashes at railroad crossing, an overpass (with a roadway surface 26 ft above the existing road) is be constructed on an existing level highway. see illustration below. the existing highway has a design speed of 55 mi/hr. the overpass structure is to be level, centered above the railroad, and 180 ft long.
What is the length of the existing level highway must be reconstructed to provide an appropriate vertical alignment? assume that the sag and crest vertical curves are directly connected (i.e., there is no constant grade section).
If substance A has molecules moving at a high rate and substance B has molecules moving at a low rate, which substance has the lower temperature?
Answers
Answer:
substance B
Explanation:
A cylindrical bar of metal having a diameter of 20.5 mm and a length of 201 mm is deformed elastically in tension with a force of 46300 N. Given that the elastic modulus and Poisson's ratio of the metal are 60.5 GPa and 0.33, respectively, determine the following: (a) The amount by which this specimen will elongate in the direction of the applied stress. (b) The change in diameter of the specimen. Indicate an increase in diameter with a positive number and a decrease with a negative number.
Answers
Answer:
a) The amount by which this specimen will elongate in the direction of the applied stress is 0.466 mm
b) The change in diameter of the specimen is - 0.015 mm
Explanation:
Given the data in the question;
(a) The amount by which this specimen will elongate in the direction of the applied stress.
First we find the area of the cross section of the specimen
A = \(\frac{\pi }{4}\) d²
our given diameter is 20.5 mm so we substitute
A = \(\frac{\pi }{4}\) ( 20.5 mm )²
A = 330.06 mm²
Next, we find the change in length of the specimen using young's modulus formula
E = σ/∈
E = P/A × L/ΔL
ΔL = PL/AE
P is force ( 46300 N), L is length ( 201 mm ), A is area ( 330.06 mm² ) and E is elastic modulus (60.5 GPa) = 60.5 × 10⁹ N/m² = 60500 N/mm²
so we substitute
ΔL = (46300 N × 201 mm) / ( 330.06 mm² × 60500 N/mm² )
ΔL = 0.466 mm
Therefore, The amount by which this specimen will elongate in the direction of the applied stress is 0.466 mm
(b) The change in diameter of the specimen. Indicate an increase in diameter with a positive number and a decrease with a negative number.
Using the following relation for Poisson ratio
μ = - Δd/d / ΔL/L
given that Poisson's ratio of the metal is 0.33
so we substitute
0.33 = - Δd/20.5 / 0.466/201
0.33 = - Δd201 / 20.5 × 0.466
0.33 = - Δd201 / 9.143
0.33 × 9.143 = - Δd201
3.01719 = -Δd201
Δd = 3.01719 / - 201
Δd = - 0.015 mm
Therefore, The change in diameter of the specimen is - 0.015 mm
For proper function hydraulics systems need a reservoir of which of the following?
A.) Compressible fluid
B.) Non-compressible fluid C.) Non-compressible air
Answers
Think of brake fluid on a vehicle, compressed as one applies the break= pressure to expand brake cylinders in the wheels which compress the pads on the wheel brake rotors.
Release brake and fluid relaxes back into the reservoir/accumulator.
Eugene runs a company that manufactures bricks. The manufacturing process consumes a lot of energy and causes pollution, which type of
bricks is his company manufacturing?
Answers
Answer:
D. Fire clay bricks
Explanation:
Just like in the steel mills with the big furnaces that's what causes all the smoke to come out of the stacks
Answer:
d is correct
Explanation:
Question 1
(a) A conductor has a constant current of 2 A, how many electrons pass a fixed point on
the conductor in one 30 seconds?
(b) What is the total current of energy source supplying 40 C charge over 10 s? Given the
total energy of 1000 J as heat, compute the voltage drop across the terminal of the
energy source
(c) Calculate the equivalent resistance between points a and b of Figure 3. If the input
current at port ‘a’ is 2 A, what are the voltage supply and the total average power?
Answers
The genetic engineering of our food supply has produced varied results. Which foods available in American supermarkets are most likely to have genetically engineered ingredients?
A) Soybean oil, cottonseed oil, and corn syrup
B) Fortified wheat and oats
C) Tomatoes and corn oil
D) Milk and dairy products
Answers
The most probable items to include genetically modified ingredients in US stores are those made with soy oil, cottonseed oil, and corn syrup.
Which supermarket items in America are most likely to contain genetically modified ingredients?Ingredients that Americans consume, such cornstarch, corn syrup, corn oil, soybean oil, canola oil, or granulated sugar, are made from a variety of GMO crops. Certain fresh produce, such as potatoes, summer squash, apples, papayas, and pink pineapples, are offered in GMO variants.
Where do the majority of Americans go to learn about nutrition?71% of respondents who were asked to choose their top two or three sources of nutrition-related information named the news media as their primary resource. A community diet and nutrition class was reviewing the Nutrition Information label when The nurse discusses the daily percentage value.
To know more about supermarkets visit:-
https://brainly.com/question/29360551
#SPJ4
Resistance depends on which three properties of a wire?
Color and texture are not directly related to a wire’s resistance.
1. color, thickness, texture
2. thickness, length, temperature
3. length, texture, temperature
4. temperature, color, texture
Answers
Answer:
2
Explanation:
From the formula R=(ro)A/l resistance depends on the length of the wire, the area of the wire(thickness) and the resistivity(ro) which depends on the material and temperature.
Estimate properties and pipe diameter Determine the diameter of a steel pipe that is to carry 2000 gal/min of gasoline with a pressure drop of 5 psi per 100 ft of horizontal pipe. Pressure drop is a function of flow rate, length, diameter, and roughness. Either iterative methods OR equation solvers are necessary to solve implicit problems. Total head is the sum of the pressure, velocity, and elevation. What is the density of gasoline
Answers
Answer:
Diameter of pipe is 0.535 ft
Explanation:
see attachment, its works out 1st half
A copper wire of diameter 1 cm and a resistance 0.15 ohms.Itv was drawn under pressure so that it's diameter was reduced to 50%. what is the new resistance of the wire?
Answers
The new resistance of the wire is 2.4.
How to calculate the resistanceIt should be noted that to solve for the new resistance of the wire after it has been drawn under pressure, we need to find the new cross-sectional area of the wire. We are told that the diameter of the wire has been reduced to 50% of its original value.
The cross-sectional area of a circle is proportional to the square of its diameter, so if the diameter is reduced by a factor of 2, the area is reduced by a factor of 4. Therefore, the new cross-sectional area of the wire is 1/4 of its original value.
It should be noted that R' = 16R
New resistance will be:
= 16 × 0.15
= 2.4
Learn more about resistance on:
https://brainly.com/question/17563681
#SPJ1
Explain what software is. Your answer must include the difference between hardware and the role of software. Computer science
Answers
Software is a term used to describe computer programs and related data that provides the instructions to the computer about how to perform various tasks. It refers to all the intangible components of the computer that cannot be physically touched, such as the programs, data, and instructions that run on the hardware.
Difference between Hardware and Software: Hardware is the physical components of the computer that can be touched or seen, while software is the intangible components of the computer that are installed on the hardware. Hardware consists of components such as the motherboard, memory, hard drive, CPU, and peripherals like the keyboard, monitor, and printer. Software, on the other hand, refers to programs, data, and instructions that run on the hardware.
Role of Software: Software plays a critical role in the operation of a computer. It is responsible for managing all the tasks that the computer performs. The software programs enable the computer to perform various functions, such as running an application, browsing the internet, creating documents, or editing photos. The software provides the instructions to the computer's hardware to perform these tasks. Without software, the computer would be a useless collection of hardware components that have no functionality.
Know more about Software here:
https://brainly.com/question/32393976
#SPJ11
5. According to the presentation, which of the following is NOT a food safety concern?
A. Antibiotics
B. Genetically modified organisms
C. Processed food products
D. Foodborne illnesses
Answers
According to the presentation, the answer choice that is NOT a food safety concern is A. Antibiotics
Some common food safety concerns:Foodborne illnesses: This refers to illnesses that are caused by consuming contaminated food. Foodborne illnesses can be caused by bacteria, viruses, parasites, and toxins.
Antibiotics: The use of antibiotics in livestock and poultry production can lead to the development of antibiotic-resistant bacteria, which can pose a threat to human health.
Genetically modified organisms (GMOs): Some people are concerned about the safety of GMOs and their potential long-term effects on human health and the environment.
Processed food products: Processed foods can contain additives, preservatives, and other chemicals that may be harmful to human health.
Overall, food safety concerns are important because they can have serious implications for public health. It is important for individuals, food producers, and regulators to take steps to ensure that the food supply is safe and free from contamination.
Read more about food safety here:
https://brainly.com/question/12279202
#SPJ1
Which of the following best describes the devices that will help prevent moisture from collecting in raceway systems?
a. Elbows
b. Integral drains
c. Strainers
d. Seal-off fittings
Answers
The best device to help prevent moisture from collecting in raceway systems is integral drains.
Integral drains are specifically designed to allow water to drain away from the system without the need for additional components. Elbows and strainers are not effective for this purpose, and seal-off fittings are primarily used for dust and debris protection.
Raceway systems are a type of electrical wiring system used to protect electrical wires and cables. They are typically used in industrial applications and are designed to be durable, reliable, and safe. Raceway systems typically consist of raceways, which are channels made of metal or plastic, and fittings, which provide a secure connection between the raceways and other components, such as switches and outlets.
Learn more about raceway systems :
https://brainly.com/question/28052297
#SPJ4
1. You use
switches when you
have two switches controlling one or more
lights.
single pole
4-way
2-way
3-way
Answers
If you measure 0.7 V across a diode, the diode is probably made of
Answers
Answer:
Made of Silicon.
Explanation:
A diode is a semiconductor device use in mostly electronic appliances. It is two terminals device consisting of a P-N junction formed either in Germanium or silicon crystal.
Diode can be forward biased or reverse biased.
When a diode is forward biased and the applied voltage is increased from zero, hardly any current flows through the device in the beginning.
It is so because the external voltage is being opposed by the internal barrier voltage whose value is 0.7v for silicon and 0.3v for germanium.
If you measure 0.7 V across a diode, the diode is probably therefore made of Silicon.
calculate force and moment reactions at bolted base O of overhead traffic signal assembly. each traffic signal has a mass 36kg, while the masses of member OC and AC are 50Kg and 55kg, respectively. The mass center of mmber AC at G.
Answers
Answer:
The free body diagram of the system is, 558 368 368 508 O ?? O, Consider the equilibrium of horizontal forces. F
Explanation:
I hope this helps you but I think and hope this is the right answer sorry if it’s wrong.
22. Why bicycles are imperfect substitutes to the plane a. Given the choice between bicycle and plane for a long-distance majority of people choose bicycle low for a plane b. Given the choice between bicycle and plane that makes the threat of bicycle low for a plane c. The plane rides are expensive, therefore people will choose bicycle over plane d. None of the above
Answers
None of the above options accurately explain why bicycles are imperfect substitutes for planes.
Bicycles and planes are considered imperfect substitutes for various reasons. The choice between a bicycle and a plane for long distances is influenced by factors such as speed, convenience, comfort, and the availability of infrastructure. While some individuals may choose bicycles due to personal preferences or environmental concerns, the majority of people would not choose a bicycle over a plane for long-distance travel. Bicycles have limited speed and endurance, are impractical for crossing large bodies of water or international distances, and may not be suitable for individuals with physical limitations. Additionally, planes offer significant time savings and can cover vast distances efficiently. The decision between a bicycle and a plane depends on individual circumstances and the specific requirements of the journey.
Learn more about bicycles and planes here: brainly.com/question/15983665
#SPJ11
Helium is used as the working fluid in a Brayton cycle with regeneration. The pressure ratio of the cycle is 8, the compressor inlet temperature is 300 K, and the turbine inlet temperature is 1800 K. The effectiveness of the regenerator is 75 percent. Determine the thermal efficiency and the required mass flow rate of helium for a net power output of 60 MW, assuming both the compressor and the turbine have an isentropic efficiency of (a) 100 percent and (b) 80 percent. The properties of Helium are cp = 5.1926 kJ/kg.K and k = 1.667.
Answers
Answer:
Explanation:
Find the temperature at exit of compressor
\(T_2=300 \times 8^{\frac{1.667-1}{1.667} }\\=689.3k\)
Find the work done by the compressor
\(\frac{W}{m} =c_p(T_2-T_1)\\\\=5.19(689.3-300)\\=2020.4kJ/kg\)
Find the actual workdone by the compressor
\(\frac{W}{m} =n_c(\frac{W}{m} )\\\\=1 \times 2020.4kJ/kg\)
Find the temperature at exit of the turbine
\(T_4=\frac{1800}{8^{\frac{1.667-1}{1.667} }} \\\\=787.3k\)
Find the actual workdone by the turbine
\(1 \times 5.19 (1800-783.3)\\=5276.6kJ/kg\)
Find the temperature of the regeneration
\(\epsilon = \frac{T_5-T_2}{T_4-T_2} \\\\0.75=\frac{T_5-689.3}{783.3-689.3} \\\\T_5=759.8k\)
Find the heat supplied
\(Q_i_n=c_p(T_3-T_5)\\\\=5.19(1800-759.8)\\\\=5388.2kJ/kg\)
Find the thermal efficiency
\(n_t_h=\frac{W_t-W_c}{Q_i_n} \\\\=\frac{5276.6-2020.4}{5388.2} \\\\n_t_h=60.4\)
60.4%
Find the mass flow rate
\(m=\frac{W_net}{P} \\\\\frac{60 \times 10^3}{5276.6-2020.4} \\\\=18.42\)
Find the actual workdone by the compressor
\(\frac{W_c}{m} =\frac{(\frac{W}{m} )}{n_c} \\\\=\frac{2020.4}{0.8} \\\\=2525.5kg\)
Find the actual workdone by the turbine
\(\frac{W_t}{m} =n_t(\frac{W}{m} )\\\\=0.8 \times5.19(1800-783.3)\\\\=4221.2kJ/kg\)
Find the temperature of the compressor exit
\(\frac{W_t}{m} =c_p(T_2_a-T_1)\\2525.5=5.18(T_2_a-300)\\T_2_a=787.5k\)
Find the temperature at the turbine exit
\(4221.2=5.18(1800-T_4_a)\\\\T_4_a=985k\)
Find the temperature of regeneration
\(\epsilon =\frac{T_5-T_2}{T_4-T_2}\\\\0.75=\frac{T_5-787.5}{985-787.5}\\\\T_5=935.5k\)
Answer:
a) 60.4%; 18.42 kg/s
b) 37.8% ; 35.4 kg/s
Explanation:
a) at an isentropic efficiency of 100%.
Let's first find the exit temperature of the compressor T2, using the formula:
\((r_p) ^k^-^1^/^k = \frac{T_2}{T_1}\)
Solving for T2, we have:
\( T_2 = 300 * (8)^1^.^6^6^7^-^1^/^1^.^6^6^7 = 689.3 K \)
Let's now find the work dine by the compressor.
\( \frac{W_c}{m} = c_p(T_2 - T_1) \)
\( \frac{W_c}{m} = 5.19(689.3 - 300) = 2020.4 KJ/kg\)
The actual work done by the compressor =
\( W_c = 1 * 2020.4 = 2020.4 KJ/kg \)
Let's find the temperature at the exit of the turbine, T4
\((r_p) ^k^-^1^/^k = \frac{T_3}{T_4}\)
Solving for T4, we have:
\(T_4 = \frac{1800}{(8)^1^.^6^6^7^-^1^/^1^.^6^6^7} = 783.3 K\)
Let's find the work done by the turbine.
\(\frac{W_t}{m} = c_p(T_3 - T_4)\)
\(\frac{W_t}{m} = 5.19(1800 - 783.3) = 5276.6 KJ/kg\)
The actual work done by the turbine:
= 1 * 5276.6 = 5276.6 KJ/kg
Let's find the regeneration temperature, using the formula:
\( e = \frac{T_r - T_2}{T_4 - T_2}\)
Substituting figures, we have:
\( 0.75 = \frac{T_r - 689.3}{783.3 - 689.3} \)
\( T_r = [0.75(783.3 - 689.3)] + 689.3 = 759.8 \)
Let's calculate the heat supplied.
\(Q = c_p(T_3 - T_r)\)
\( Q = 5.19(1800 - 759.8) \)
Q = 5388.2 kJ/kg
For thermal efficiency, we have:
\( n = \frac{W_t - W_c}{Q} \)
Substituting figures, we have:
\( n = \frac{5276.6 - 2020.4}{5388.2} = 0.604 \)
0.604 * 100 = 60.4%
For mass flow rate:
Let's use the formula:
\( m = \frac{W_n_e_t}{P} \)
Wnet = 60MW = 60*1000
\( m = \frac{60*10^3}{5276.6 - 2020.4} = 18.42 \)
b) at an isentropic efficiency of 80%.
Let's now find the work done by the compressor.
\( \frac{W_c}{m} = c_p(T_2 - T_1) \)
\( \frac{W_c}{m} = 5.19(689.3 - 300) = 2020.4 KJ/kg\)
The actual work done by the compressor =
\( W_c = \frac{2020.4}{0.8}= 2525.5 KJ/kg \)
Let's find the work done by the turbine.
\( \frac{W_t}{m} = c_p(T_3 - T_4) \)
\( \frac{W_t}{m} = 5.19(1800 - 787.5) = 5276.6 KJ/kg\)
The actual work done by the turbine:
= 0.8 * 5276.6 = 4221.2 KJ/kg
Let's find the exit temperature of the compressor T2, using the formula:
\(\frac{W_c}{m} = c_p(T_2 - T_1) \)
\( 2525.5 = 5.19(T_2 - 300) \)
Solving for T2, we have:
\( T_2 = \frac{2525.5 + 300}{5.19} = 787.5 \)
Let's find the temperature at the exit of the turbine, T4
\( \frac{W_t}{m} = c_p(T_3 - T_4) \)
\( 4221.2 = 5.19(1800 - T_4) \)
Solving for T4 we have:
\( T_4 = 958 K\)
Let's find the regeneration temperature, using the formula:
\( e = \frac{T_r - T_2}{T_4 - T_2}\)
Substituting figures, we have:
\( 0.75 = \frac{T_r - 787.5}{985 - 787.5} \)
\( T_r = [0.75(958 - 787.5)] + 787.5 = 935.5 K \)
Let's calculate the heat supplied.
\(Q = c_p(T_3 - T_r)\)
\( Q = 5.19(1800 - 935.5) \)
Q = 4486.2 kJ/kg
For thermal efficiency, we have:
\( n = \frac{W_t - W_c}{Q} \)
Substituting figures, we have:
\( n = \frac{4221.2 - 2525.2}{4486.2} = 0.378 \)
0.378 * 100 = 37.8%
For mass flow rate:
Let's use the formula:
\( m = \frac{W_n_e_t}{P} \)
Wnet = 60MW = 60*1000
\( m = \frac{60*10^3}{4221.2 - 2525.2} = 35.4 kg/s \)
A milling circuit consists of a primary SAG mill that is in open circuit. This is then followed by 2 secondary ball mills in parallel. The product from the SAG mill is fed to the ball mills, with the product from the ball mills being combined and classified in cyclones. The underflow from the cyclones is recycled, with the overflow forming the feed to the flotation circuit.
a) Draw the circuit, labelling items.
The milling circuit has a feed rate of 1 500 t/hr. Consider 2 size classes, above and below 75 microns. The feed has 25% passing 75 microns and each of the mills breaks 50% of the material in the feed above 75 microns to below 75 microns. The partition number for the particles above 75 microns is 0.75, while that below 75 microns is 0.25.
b) Carry out a mass balance to calculate the mass rate of both size fraction in each stream. What is the feed rate to each of the ball mills? What is the percentage passing 75 microns in the circuit product/flotation feed? This milling circuit’s feed has 80% passing 1 cm and the final feed to the flotation circuit has 80% passing 60 microns.
Answers
The correct answer is a) Here is a diagram of the milling circuit with labels: The product from the SAG mill is fed to the two ball mills in parallel, with the product from the ball mills being combined and classified in cyclones. The underflow from the cyclones is recycled, and the overflow goes to the flotation circuit.
To calculate the mass rate of each size fraction in each stream, we can start with the total feed rate of 1,500 t/hr. Since 25% of the feed is below 75 microns, that means 75% of the feed is above 75 microns. Of that 75%, 50% will be broken down in the SAG mill to below 75 microns, while the remaining 50% will be broken down in the two ball mills in parallel. Therefore: Mass rate of particles above 75 microns in feed = 1,500 x 0.75 = 1,125 t/hr Mass rate of particles below 75 microns in feed = 1,500 x 0.25 = 375 t/hr Mass rate of particles above 75 microns in SAG mill product = 1,125 x 0.5 = 562.5 t/hr Mass rate of particles below 75 microns in SAG mill product = 1,125 x 0.5 + 375 = 937.5 t/hr Mass rate of particles above 75 microns in each ball mill product = 562.5 / 2 = 281.25 t/hr Mass rate of particles below 75 microns in each ball mill product = 375 / 2 = 187.5 t/hr Mass rate of particles above 75 microns in combined ball mill product = 562.5 t/hr Mass rate of particles below 75 microns in combined ball mill product = 375 t/hr + 187.5 t/hr = 562.5 t/hr Mass rate of particles above 75 microns in cyclone overflow = 562.5 t/hr x 0.95 = 534.38 t/hr (assuming a 5% bypass) Mass rate of particles below 75 microns in cyclone overflow = 562.5 t/hr x 0.05 + 375 t/hr x 0.95 = 393.75 t/hr (assuming a 5% bypass) Mass rate of particles above 75 microns in cyclone underflow/recycle = 562.5 t/hr x 0.05 = 28.13 t/hr Mass rate of particles below 75 microns in cyclone underflow/recycle = 375 t/hr x 0.05 + 187.5 t/hr = 205.63 t/hr To calculate the feed rate to each ball mill, we can use the mass rate of particles below 75 microns in the combined ball mill product, which is 562.5 t/hr. Since there are two ball mills in parallel, the feed rate to each ball mill will be: Feed rate to each ball mill = 562.5 t/hr / 2 = 281.25 t/hr Finally, to calculate the percentage passing 75 microns in the circuit product.
To learn more about SAG mill click on the link below:
brainly.com/question/22282127
#SPJ1
Things to be done before isolation
Answers
Two stepped bar is supported at both ends.At the join point of two segments,the force F is applied(downwards).Calculate reactive forces R1 and R3 at the supports.What is value of absolute maximal stress?
Choose one answer nearest your result.
given= d1=10mm d2=20mm L1=20mm L2=10mm E=200GPa F=20kN
Answers
Answer:
F=200kN
Explanation:
using Electronic Work Bench (EWB) design the following
EWB integrated sequential logic circuit
below:
Design the prototype of a synchronous electronic voting system
that controls arguably fifty two (5
Answers
The electronic voting system is an essential system in the modern democratic electoral system.
This system ensures that the voting process is transparent, accountable, and trustworthy.
Electronic Workbench (EWB) is a powerful software tool that can be used to design and simulate complex electronic circuits, including sequential logic circuits.
The following is the design of the prototype of a synchronous electronic voting system that controls arguably fifty-two (52) voters using EWB integrated sequential logic circuit:
Step 1: Open the EWB software and select the Logic Design option from the toolbar.
Step 2: Click on the Component Toolbar button and select the required logic gates (AND, OR, NOT, etc.) from the list.
Step 3: Connect the logic gates using wires by clicking on the Wire Tool button.
Step 4: Add a clock signal generator to the circuit to ensure that all the flip-flops are synchronized with each other.
Step 5: Add a counter to the circuit that will keep track of the number of votes.
Step 6: Add a decoder to the circuit that will decode the input signals from the voters.
Step 7: Add a flip-flop to the circuit that will store the state of the voting system.
Step 8: Connect the flip-flop to the counter and decoder using wires.
Step 9: Add an output display to the circuit that will display the final voting result.
Step 10: Run the simulation and test the circuit to ensure that it works correctly.
In summary, the above steps are how you can design the prototype of a synchronous electronic voting system that controls arguably fifty-two (52) voters using EWB integrated sequential logic circuit.
To know more about electoral visit;
https://brainly.com/question/1042279
#SPJ11
TRUE/FALSE. when providing transcutaneous pacing, the appearance of wide qrs complexes and tall, broad t waves after each pacing spike confirms that mechanical capture has been achieved.
Answers
The statement is false. When providing transcutaneous pacing, the appearance of wide QRS complexes and tall, broad t waves after each pacing spike confirms that mechanical capture has been achieved.
A combination of the Q surge, R surge and S surge, the “ QRS complex ” represents ventricular depolarization. This term can be confusing, as not all ECG leads contain all three of these swells; yet a “ QRS complex ” is said to be present anyhow.
For illustration, the normal QRS complex in lead V1 doesn't contain a Q surge — only a R surge and S surge but the combination of the R surge and S surge is still appertained to as the QRS complex for this lead.
The normal duration( interval) of the QRS complex is between 0.08 and 0.10 seconds — that is, 80 and 100 milliseconds. When the duration is between 0.10 and0.12 seconds, it's intermediate or slightly dragged . A QRS duration of lesser than 0.12 seconds is considered abnormal. The QRS duration will outstretch when electrical exertion takes a long time to travel throughout the ventricular myocardium. The normal conduction system in the ventricles is called the His- Purkinje system and consists of cells that can conduct electricity relatively fleetly.
Learn more about QRS complex:
https://brainly.com/question/14057199
#SPJ4
When an appliance is not marked with its maximum overcurrent protection, the branch circuit protection device is ________.
Answers
When an appliance is not marked with its maximum overcurrent protection, the branch circuit protection device is sized according to the ampacity of the branch circuit conductors.
What is overcurrent?An overcurrent occurs in an electrical circuit when the normal load current is exceeded. Overloads and short circuits are the two most common types of overcurrent.
When dangerous overcurrents occur, the primary role of fuses and circuit breakers in a circuit is to protect personnel and equipment.
If the appliance is not marked with it, the branch circuit protection device should be used to determine the maximum overcurrent protection.
Thus, when a piece of equipment is not marked with its highest overcurrent protection, the department circuit protection device is sized according to the ampacity of the branch circuit conductors.
For more details regarding overcurrent, visit:
https://brainly.com/question/28314982
#SPJ1