3. If you have 2.6 moles of NaI and 3.9 moles of bromine, how many grams of NaBr can be made from this reaction?
Br2 + NaI → NaBr + I2

Answer:

mm hola hablas español??????

Answer:

there are N_A, "Avogadro's number" of copper atoms in a 63.55*g mass of copper wire. And N_A, "Avogadro's number" = 6.022xx10^23 individual copper atoms. I look on the Periodic Table, and at Z=29, i.e. copper, the quoted atomic mass is 63.55*g.

Explanation:

One mole of every substance contains 6.022×10²³ atoms. The atomic mass of copper is 63.55 g. Thus it is one mole of copper which contains copper 6.022×10²³ atoms.

Copper is 29th element in periodic table. It is a transition metal classified into d-block. Transition metals are named so because they in between the metals and non-metals in periodic table.

Transition metals have varying oxidation state. Copper exists in +1, +2 and +3 oxidation states.

Any substance containing 6.022×10²³ atoms is called one mole of that substance. This number is called Avogadro number. Hence one mole of each element contains avogadro number of its atoms.

Similarly one mole of each compound contains 6.022×10²³ number of molecules. Here, the atomic mass of copper is 63.55 g. That is one mole of copper weighs 63.55 g. Hence, number of atoms in 63.55 g of copper is 6.022×10²³ atoms.

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First, we need to write out the balanced chemical equation for the reaction: 4 KO2 + 2 CO2 → 2 K2CO3 + 3 O2

From the equation, we can see that 4 moles of KO2 react with 2 moles of CO2 to produce 3 moles of O2. Therefore, we need to convert the given masses of KO2 and CO2 into moles:

moles of KO2 = 2.61 g / molar mass of KO2 = 2.61 g / 71.10 g/mol = 0.0367 mol
moles of CO2 = 4.46 g / molar mass of CO2 = 4.46 g / 44.01 g/mol = 0.1013 mol

Next, we need to determine the limiting reagent (the reactant that will be completely consumed in the reaction) by comparing the mole ratios of KO2 and CO2 in the balanced equation. The ratio of moles of KO2 to moles of CO2 is:
0.0367 mol KO2 / 4 mol KO2 per 2 mol CO2 = 0.0184 mol CO2

Since this ratio is less than the actual number of moles of CO2 we have (0.1013 mol), CO2 is in excess and KO2 is the limiting reagent.

Using the mole ratio from the balanced equation, we can calculate the number of moles of O2 produced:

moles of O2 = 3 mol O2 per 4 mol KO2 × 0.0367 mol KO2 = 0.0275 mol O2

Finally, we can convert the moles of O2 to grams:

mass of O2 = moles of O2 × molar mass of O2 = 0.0275 mol × 32.00 g/mol = 0.88 g
Therefore, 2.61 g of KO2 and 4.46 g of CO2 would produce 0.88 g of O2.

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Answer:

C6H6<C7H15OH<C6H13OH<C2H5OH​

Explanation:

Organic substances are ordinarily nonpolar. This means that they do not dissolve in water. However, certain homologous series of organic compounds actually dissolve in water because they possess certain functional groups that effectively interact with water via hydrogen bonding.

A typical example of this is alcohol family. All members of this homologous series contain the -OH functional group. This group can effectively interact with water via hydrogen bonding, leading to the dissolution of low molecular weight alcohols in water.

Low molecular weight alcohols are miscible with water in all proportions. This implies that they are highly soluble in water. However, as the size of the alkyl moiety in the alcohol increases, the solubility of the alcohol in water decreases due to less effective interaction of the -OH group with water via hydrogen bonding. This explains the fact that C2H5OH​ is the most soluble alcohol in the list.

C6H6 is insoluble in water since it is purely a hydrocarbon with no -OH group capable of interaction with water via hydrogen bonding.

The following will be true regarding the relative partial pressures of the gases remaining in the vessel after some of the gas mixtures have effused. Pressure H₂ < Pressure  N₂ < Pressure Ar

Let us first write the formula for Graham's law of diffusion/effusion to answer this question.

r ∝ 1/√M

Where;

r denotes the diffusion/effusion rate.

M denotes molar mass.

In effusion, a barrier with very small holes usually prevents the gas from rapidly expanding into a new volume. As a result, the heavier the gas, the slower the effusion rate; the lighter the gas, the faster the effusion rate.

Now, the heavier gas has a higher pressure than the lighter ones.

The molar masses of the following gases are as follows:

Molar mass of H₂ = 2.016 g/mol

Molar mass of Ar = 39.95 g/mol

Molar mass of N₂ = 28.0134 g/mol

The rate of effusion is inversely proportional to the molar mass, according to the effusion equation.

As a result, the higher the molar mass, the lower the effusion rate and, as a result, the higher the pressure because it is a heavy gas.

As a result, Ar has the greatest molar mass and will experience the greatest pressure.N₂  comes next, followed by H₂.

If a container is filled with more than one gas, each gas exerts pressure on the container. The partial pressures of any gas within the container are referred to. Partial pressure is the pressure exerted by one of the gases in the mixture if it occupies the same volume on its own.

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The complete question is:

equal numbers of moles of h2(g), ar(g), and n2(g) are placed in a glass vessel at room temperature. if the vessel has a pinhole-sized leak, which of the following will be true regarding the relative values of the partial pressures of the gases remaining in the vessel after some of the gas mixtures have effused?

a) Pressure  H₂< Pressure N₂ < Pressure Ar

b) Pressure  H₂ < Pressure Ar < Pressure N₂

c) Pressure Ar < Pressure  N₂< Pressure  H₂

d) Pressure  H₂ = Pressure Ar = Pressure N₂

Answer:

Explanation:

To determine the mass of NaCl in 1.25L of 0.1035M solution, we can use the formula:

mass = concentration x volume x molar mass

where concentration is in molarity (M), volume is in liters (L), and molar mass is in grams per mole (g/mol).

The molar mass of NaCl is 58.44 g/mol.

Plugging in the given values, we get:

mass = (0.1035 M) x (1.25 L) x (58.44 g/mol)

mass = 7.3188 g

So, there is approximately 7.3188 grams of NaCl in 1.25L of 0.1035M solution.

A. The mass of NaCl needed to react with F₂ at 280 K and 1.50 atm is 115.83 g

B. The mass of NaCl needed to react with F₂ at STP is 78.39 g

We'll begin by calculating the number of mole of F₂ by using the ideal gas equation as follow:

n = PV / RT

n = (1.5 × 15) / (0.082 × 280)

n = 0.98 mole

Next, we shall determine the number of mole NaCl that reacts. This is given below

F₂ + 2NaCl → Cl₂ + 2NaF

From the balanced equation above,

1 mole of F₂ reacted with 2 moles of NaCl.

Therefore,

0.98 mole of F₂ will react with = 0.98 × 2 = 1.96 moles of NaCl

Finally, we shall determine mass of NaCl as follow

Mass = mole × molar mass

Mass of NaCl = 1.98 × 58.5

Mass of NaCl = 115.83 g

At standard temperature and pressure (STP),

22.4 L = 1 mole of F₂

Therefore,

15 L = 15 / 22.4

15 L = 0.67 mole of F₂

Next, we shall determine the number of mole NaCl that reacts. This is given below

F₂ + 2NaCl → Cl₂ + 2NaF

From the balanced equation above,

1 mole of F₂ reacted with 2 moles of NaCl.

Therefore,

0.67 mole of F₂ will react with = 0.67 × 2 = 1.34 moles of NaCl

Finally, we shall determine mass of NaCl as follow

Mass = mole × molar mass

Mass of NaCl = 1.34 × 58.5

Mass of NaCl = 78.39 g

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Answer:

1.44 g

Explanation:

1. get number of nitrogen atoms in 9.79 grams of nitrogen

1 mole of Nitrogen is 6.022 x 10^23 atoms N which is = 14.01g N

2.

if 6.022 x 10^23 atoms of Nitrogen is 14

then x atoms  of Nitrogen is 9.79

3.

6.022 x 10^23/ x = 14/9.79 ->

x = 8.431 x 10^24 / 9.79 =

8.61799714478 x 10^23

4.

8.61799714478 x 10^23 atoms of N

6.022 x 1023 atoms of H have a mass of 1.008g, so

8.61799714478 x 10^23 atoms of H have a mass of (1.008/6.022 x 1023) x 8.61799714478 x 10^23) = 1.44250051072175g

1.44 g

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Answer:

b. Ni, Fe, Ti, K

Explanation:

The given elements are present in period 4 of periodic table. Now we will discuss the trend of atomic radius along period.

Atomic radius:

" It is the smallest distance from nucleus to the outer most valance shell of an atom"

When we move from left to right in the periodic table the number of valance electrons in an atom increase. The atomic size goes to decrease in same period because of edition of electron with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. In this way positive charge is also going to increase and this charge is greater in effect than the charge of electrons. This effect causes the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell come closer to the nucleus.

As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.

Ni ∠ Fe ∠ Ti ∠ K

The molecular mass of the gas, given that 2.63 g of the gas occupied 0.98 L at standard conditions of temperature and pressure is 60 g/mol

First, we shall obtain the mole of the gas. Details below:

PV = nRT

1 × 0.98 = n × 0.0821 × 273

0.98 = n × 22.4133

Divide both sides by 22.4133

n = 0.98 / 22.4133

n = 0.0437 mole

Finally, we shall obtain the molecular mass of the gas. This is shown below:

Molar mass = mass / mole

Molar mass of gas = 2.63 / 0.0437  

Molar mass of gas = 60 g/mol

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The highest electric force exerted by charges -4 ×10⁻⁵ C and 3 ×10⁻⁵ C  placed 0.5 m apart is equal to 43.15 N.

The lowest electric force exerted by charges 3 ×10⁻⁵ C and 3 ×10⁻⁵ C  placed 1 m apart is equal to 8.10 N.

According to Coulomb’s law, the force of attraction between two charges is equal to the product of their charges and is inversely proportional to the square of the distance. This electric force applies along the line joining the two charges.

The magnitude of the electric force can be written as follows:

\(\displaystyle F = k\frac{q_1q_2}{r^2}\)

where k is constant proportionality = 8.99 × 10⁹ N.m²/C².

Given the charge on one point charge, q₁ =  4 ×10⁻⁵ C

The charge on the other point charge, q₂ = - 3 × 10⁻⁵C

The distance between these two charges, r = 0.5 m

The magnitude of electric force between the charges  will be:

\(\displaystyle F = 8.99\times 10^{9}\times \frac{4\times 10^{-5}\times 3\times 10^{-5}}{(0.5)^2}\)

F = 43.15 N

Given the charge on one point charge, q₁ =  3 ×10⁻⁵ C

The charge on the other point charge, q₂ = 3 × 10⁻⁵C

The distance between these two charges, r = 1 m

The magnitude of force between the charges will be:

\(\displaystyle F = 8.99\times 10^{9}\times \frac{3\times 10^{-5}\times 3\times 10^{-5}}{(1)^2}\)

F = 8.1 N

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In 4.38 × 10^21 molecules of water, there are approximately 0.073 moles.

To calculate the number of moles, we can use Avogadro's number, which states that 1 mole of a substance contains 6.022 × 10^23 molecules. So, by dividing the given number of molecules (4.38 × 10^21) by Avogadro's number, we can find the number of moles.

Now, let's explain the process in detail. Avogadro's number is a constant that represents the number of particles (atoms, molecules, etc.) in one mole of a substance. It is approximately 6.022 × 10^23. Therefore, if we divide the given number of molecules by Avogadro's number, we can determine the number of moles.

In this case, we divide 4.38 × 10^21 molecules by 6.022 × 10^23 molecules/mole, resulting in approximately 0.073 moles.

Significant figures play an important role in reporting the answer. The given number of molecules has three significant figures (4, 3, and 8), so our answer should be reported with three significant figures as well. Therefore, the number of moles is approximately 0.073.

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Answer:c

Explanation:c

Answer:  84.56 L is the answer.

Explanation:

Answer:

84.6

Explanation:

I took the test

The mass of silicon, Si produced from the reaction is 329.41 g

SiCl₄ + 2Mg —> 2MgCl₂ + Si

Molar mass of SiCl₄ = 28 + (35.5×4) = 170 g/mol

Mass of SiCl₄ from the balanced equation = 1 × 170 = 170 g

Molar mass of Si = 28 g/mol

Mass of Si from the balanced equation = 1 × 28 = 28 g

From the balanced equation above,

170 g of SiCl₄ reacted to produce 28 g of Si.

From the balanced equation above,

170 g of SiCl₄ reacted to produce 28 g of Si.

Therefore,

2 Kg (i.e 2000 g) of SiCl₄ will react to produce = (2000 × 28) / 170 = 329.41 g of Si

Thus, 329.41 g of Si were obtained from the reaction

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Answer: Yo! hope this helps you dude

When ice is placed into a beaker filled with water, the water level does not drop because of the concept of displacement. When the ice is added, it displaces an amount of water equal to its own volume. This means that the ice takes up space in the beaker, pushing out an equal amount of water to make room for itself. Therefore, the total volume of water and ice in the beaker remains the same, and the water level does not drop.

This is due to the fact that the density of ice is lower than that of water and when the ice is placed into the water, it will float on the surface, pushing out an amount of water equal to its own volume.

Additionally, when the ice melts, it will release the same amount of water it displaced before and the water level will not change.

Explanation:

Answer:

The atoms in the solid would be vibrating in position.

Explanation:

i took the test

Three grams of the same substance in different phases are stored in three different containers. Each container is barely large enough to hold the substance. Therefore, the correct option is option B.

Atom, the smallest unit of matter that may be separated without releasing electrically charged particles. It is also the tiniest unit of matter with the characteristics of a chemical substance. As a result, the atomic is the fundamental building component of chemistry.

The majority of the molecule is empty space. The rest of the structure is made up of a positive-charged nucleus of neutrons and protons surrounding by a swarm of negative-charged electrons. In comparison to electrons, the lightest charge particles in nature, nuclear nucleus is small yet dense. The atoms in the liquid would be vibrating in position.

Therefore, the correct option is option B.

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Answer:

unbalanced forces can cause an object to move.

Answer:

Unbalanced Forces

Explanation:

The order of the graphs that shows the movement of the object is; B  C E A D.

We know that energy has to do with the ability to do work. In this case, we can see that the object has been dropped from a height and we must have in mind the principle of the conservation of mechanical energy. In this principle, it has been stated that energy can neither be created nor destroyed but can be converted from one form to another.

As the object is falling, there are three main kinds of energy that would come into play and these are; mechanical energy, kinetic energy and potential energy.

The kinetic energy is the energy that is in motion while the kinetic energy has to do with the energy that is at a point. Looking at the graph, we know that the amount of the thermal energy would increase the farther the object falls to the ground. Let the letters be shown as A B C D E standing for each of the graphs.

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Although sodium and phosphorus are both found in the same period of the periodic table, the nature of their oxides is different. Although P2O5 is acidic, Na2O is basic.

Metal oxides are basic, whereas non-metal oxides are acidic. The metallic character of the elements lessens as you move from left to right over time, while the non-metallic character grows.

Since the oxides in an element's higher oxidation state are more acidic than those in its lower oxidation state, dinitrogen pentoxide is the most acidic oxide compared to nitrogen dioxide and nitrogen tetraoxide.

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The conjugate acid : H₂CO₃

Given

Reaction

HCO₃− + H₂S → H₂CO₃ + HS−

Required

The conjugate acid

Solution

Bronsted-Lowry

Acid ⇒ H⁺ + conjugate base

Bases + H⁺⇒ conjugate acids

Acid and conjugate base : H₂S and HS−

Base and conjugate acid : HCO₃− and H₂CO₃

H₂S gives (H⁺), then the remaining acid is a conjugate base  HS−

HCO₃− receives (H +), then the conjugate acid H₂CO₃

Answer:

The correct answer is D.

Explanation:

Edge'21

Inter-conversion of glucose and fructose occurs with an equilibrium constant of 1.0. Glucose isomerase catalyzes this reaction. The final concentration of fructose at equilibrium from 40mM glucose is a. 40 mM.

Using this formula to find the  final concentration of fructose

Final concentration of fructose  =Equilibrium from glucose/ Equilibrium constant

Where:

Equilibrium constant = 1.0

Equilibrium from glucose = 40 mM

Let plug in the formula

Final concentration of fructose  = 40mM / 1.0

Final concentration of fructose  =  40mM

Therefore we can conclude that the correct option is A.

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The complete question is:

Inter-conversion of glucose and fructose occurs with an equilibrium constant of 1.0. Glucose isomerase catalyzes this reaction. The final concentration of fructose at equilibrium from 40mM glucose is

a. 40 mM

b. 20 mM

c. 10 mM

d. 0 mM​

Large magnetic moments can be found in iron atoms. This is due to the fact that iron is a ferromagnetic substance, meaning that its magnetic moments align with one another in the same direction to produce a potent magnetic field.

The first element in the periodic table's eighth column is iron. It is under the transition metal category. Iron atoms contain 26 protons, 26 electrons, and 30 neutrons in their most common isotope.

A silver-gray metal with lustre, ductility, and malleability is iron (group VIII of the periodic table). Four different crystalline forms are known to exist for it. In moist air, iron rusts, but not in dry air. In weak acids, it dissolves easily.

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Answer:

Kc = [B₃]²/[A₂]³  = 0.40

Explanation:

3A₂ ⇄ 2B₃  

Given at equilibrium =>  [A₂] =2.5 and [B₃] = 2.5

Kc = [B₃]²/[A₂]³ = (2.5)²/(2.5)³ = (2.5)⁻¹ = 0.40

i hope this calculation will help you  

the maximum amount of product that can be formed is 124.39 g SO₃, and there will be 36.8 g of excess O₂ left over.

To find the amount of excess reagent, you need to first determine which reactant is limiting and which is in excess.

Determine the limiting reagent:

Use stoichiometry to determine how much product can be formed from each reactant:

mol SO2:

2 SO₂ + O₂ -> 2 SO₃

2 mol SO₃/2 mol SO₂ = 1 mol SO₃/mol SO₂

1 mol SO₃ = 80.06 g SO₍₃₎

From 2.7 mol O₂

2 SO₂ + O₂ -> 2 SO₃

1 mol SO₃/1 mol O₂ = 1 mol SO₃/mol O₂

1 mol SO₃ = 80.06 g SO₃

2.7 mol O₂ x (1 mol SO₂/1 mol O₂) x (80.06 g SO₂/mol SO₂) = 216.45 g SO₂

Since the amount of SO₂ produced from 3.1 mol of SO₂ is less than the amount produced from 2.7 mol of O₂, SO₂ is the limiting reagent.

Calculate the amount of excess reagent:

To find the amount of excess O₂, use the balanced equation to determine how much O₂ is required to react with all of the SO₂:

2 SO₂ + O₂ -> 2 SO

3.1 mol SO2 x (1 mol O₂/2 mol SO2) = 1.55 mol O₂

Subtract the amount of O₂ used from the initial amount of O₂:

2.7 mol O₂ - 1.55 mol O2 = 1.15 mol O₂

Finally, convert the excess O₂ to mass:

1.15 mol O₂ x 32.00 g/mol = 36.8 g O₂

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.Answer:

2kclo3 --> 2kcl + 3o2 is a decomposition reaction because it is breaking apart (thinks decompose- to break apart/down)

H2 + I2 --> 2HI is a synthesis reaction because synthesis is like creation/ building

think DNA synthesis or the book of genesis in the bible about creation

2 Na + 2 H20 --> NaOH + H2 --- not balanced at all

other one is a balanced equation- the Zn + 2HCl one

Explanation:

Answer:

1.67

Explanation:

Mass÷mr=moles

3÷18=1.67