3. Helium gas at 1500 kPa and 300 K is throttled through an adiabatic valve to a final pressure of 100 kPa. Compute the exit temperature of the helium gas if:

Answer:

10.203 Volts

Explanation:

For this problem, we need to understand that a series resistive circuit is simply a circuit with some type of voltage source and some resistors, in this case, R1 and R2.

First, we need to find the voltage in the circuit.  To do this, we need to find the total resistance of the circuit.  When two resistors are in series, you sum the resistance.  So we can say the following:

R_Total = R1 + R2

R_Total = 570 Ω + 560 Ω

R_Total = 1130 Ω

Now that we have R_Total for the circuit, we can find the voltage of the circuit by using Ohm's law, V = IR.

V_Total = I_Total * R_Total

V_Total = 17.9 mA * 1130 Ω

V_Total = 20.227 V

Now that we have V_Total, we can find the voltage drop across each resistor by using Ohm's law once more.  Note, that since our circuit is series, both resistors will have the same current (I.e., I_Total = I_1 = I_2).

V_Total = V_1 + V_2

V_Total = V_1 + I_2*R2

V_Total - I_2*R2 = V_1

20.227 V - (17.9 mA * 560 Ω) = V_1

20.227 V - (10.024 V) = V_1

10.203 V = V_1

Hence, the voltage drop across R1 is 10.203 Volts.

Cheers.

Answer:

Explanation:

The 7 Habits of Highly Effective People, is a book written and first published in 1989. It is a business and self-help book that was written by Stephen Covey. The seven habits include

Being proactive

Starting anything with the end in mind

First things first

Always thinking towards a win-win situation

Seeking initially to understand, then going on to want to be understood

Synergize, and lastly

Growing

Answer:

b

Explanation:

A closed section will have a bottom surface.

Order the parts needed is NOT a duty of the General Service Technician.

General service technicians are knowledgeable workers who are in charge of carrying out repair tasks on cars and other light vehicles. Customers must interact with these specialists in order to discuss pricing estimates for undertaking car maintenance services. They are required to undertake any required repairs or part replacements as well as visual vehicle inspections. They must possess the necessary skills to operate equipment that mounts and balances vehicle tyres. General service personnel should be able to install car batteries and inspect the electrical systems of vehicles.

Therefore, order the parts needed is NOT a duty of the General Service Technician.

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Without specific details or descriptions of the graphs, it is not possible to determine whether each graph has an Euler path or an Euler circuit, or to provide the degree of each vertex.

Determining the presence of an Euler path or an Euler circuit in a graph requires knowledge about the specific details and connections of the graph.

This includes information about the number of vertices, edges, and the connections between them.

Without this information, it is not possible to determine whether an Euler path or an Euler circuit exists.

Additionally, determining the degree of each vertex requires knowledge of the specific graph structure.

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Answer:

it is 70 lbs...........

.

Answer:

Explanation:

The standard conversion factor for pounds and kg is 2.20462 pounds make 1 kg

This is a proportion question. A proportion consists of 2 equal ratios. If 3 of the 4 parts are known, the 4th part can be found.

Givens

1 kg = 2.20462 pounds    (that's 2 of the 4 parts)

32kg = x                             32 kg is our 3rd part.

Solution

1/32 = 2.20462/x                Cross Multiply

x = 32*2.20462

x = 70.55 pounds rounded to the nearest hundredth

Answer:

The answer is false, I hope this helps. :3

Answer:

False

Explanation:

I took the quiz and it was correct

(a) To determine the Schmid factor for all slip systems in a single crystal of iron (bcc) pulled in tension along the [120] direction, we need to consider the valid slip systems and their corresponding Schmid factors.

In bcc crystals, slip occurs on specific slip systems characterized by a combination of crystallographic planes and directions. The valid slip systems in iron (bcc) include {110}<111>, {112}<111>, and {123}<111>.

To calculate the Schmid factor for each slip system, we need to determine the dot product between the slip direction and the applied tensile stress direction, as well as the dot product between the slip plane normal and the tensile stress direction.

For example, for the {110}<111> slip system:

Slip direction: [110]

Slip plane normal: [111]

Tensile stress direction: [120]

Schmid factor = (Dot product of slip direction and tensile stress direction) * (Dot product of slip plane normal and tensile stress direction)

By calculating the dot products for each slip system and applying the formula, we can determine the Schmid factors.

(b) The tensile stress at which the crystal will flow plastically depends on the critical resolved shear stress (CRSS) for the slip system with the highest Schmid factor. The CRSS represents the stress required to initiate slip in a particular slip system.

Once we identify the slip system with the highest Schmid factor, the corresponding CRSS value can be obtained from experimental data or material properties. The tensile stress at which plastic flow will occur is equal to or greater than the CRSS for that slip system.

It's important to note that the exact values for Schmid factors, CRSS, and the tensile stress required for plastic flow can vary depending on the specific crystallographic orientation and material properties of the iron (bcc) single crystal.

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Velocity ratio refers to the ratio of the angular velocities or rotational speeds of two interacting components in a mechanical system, typically gears or pulleys.

(a) Number of teeth on Gear B:

Given the velocity ratio (V.R.) = 1.48 and N1 = 24 (as smaller gear is A), we can calculate N2 using the equation N2 = 1.48 × N1. Substituting the values, we find N2 ≈ 36. Therefore, the number of teeth on Gear B is 36.

(b) Pitch diameters of both the gears:

Using the formula for pitch diameter D = (number of teeth × module) / π, we can calculate the pitch diameters. For gear A, D1 = (24 × 2) / π = 15.245 mm, and for gear B, D2 = (36 × 2) / π = 22.867 mm.

(c) Addendum:

The addendum (a) is equal to the module, so for both gears, a1 = a2 = 2 mm.

(d) Dedendum:

The dedendum (b) is equal to 1.25 times the module, so for both gears, b1 = b2 = 2.5 mm.

(e) Circular pitch:

The circular pitch (p) is equal to π times the module, so for both gears, p1 = p2 = 6.2832 mm.

(f) Tooth thickness:

The tooth thickness is equal to half of π times the module, so for both gears, t1 = t2 = 3.1416 mm.

(g) Speed of gear B:

Using the velocity ratio formula V.R. = N1 / N2, we can calculate the speed of gear B. For gear B, N2 = N1 / V.R. = 24 / 1.48 = 16.216 rpm.

(h) Theoretical center distance of the two gears:

The theoretical center distance is given by (module × (N1 + N2)) / 2. Therefore, the theoretical center distance for the two gears is T.C.D. = (2 × (24 + 36)) / 2 = 60 mm.

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A minimum of 3006 mm² of flexural reinforcement is required at the mid-span to satisfy the section.

For a simply supported beam of span 8m subjected to a 30kN/m live load and self-weight, with concrete grade C25, steel grade S300, width 250mm.

If we are assuming a total load of around 35kN/m (including self-weight), the maximum bending moment at mid-span is M = wl²/8 ≈ 35 * 8²/8 = 280 kNm.

For Class I work, a common d/b ratio is 0.9.

Assuming an effective depth d = 0.9 * 250 = 225mm, and using the formula 0.87fy * Ast = M / (0.9 * d), we get Ast ≈ 3006 mm².

Therefore, a minimum of 3006 mm² of flexural reinforcement is required at the mid-span to satisfy the section.

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The average number of errors in every transmitted codeword is 1 bit. the number of packets received in error from is 20,000 transmitted packets.

(a) To find the average number of errors in every transmitted codeword, we use the given Pbe (bit error probability) and n (block length):

Average number of errors = Pbe * n
Average number of errors = 0.05 * 20
Average number of errors = 1

So, the average number of errors in every transmitted codeword is 1 bit.

(b) To find the number of packets received in error from 20,000 transmitted packets, we need to calculate the probability of receiving more than 3 errors, as the block code can correct a maximum of 3 bits in every received dataword.

First, calculate the probability of receiving 4 or more errors:

P(4 or more errors) = 1 - [P(0 errors) + P(1 error) + P(2 errors) + P(3 errors)]

Using the binomial probability formula, we can calculate the probabilities for each case:

P(x errors) = C(n, x) * (Pbe)^x * (1-Pbe)^(n-x)

where C(n, x) represents the number of combinations of n items taken x at a time.

After calculating the probabilities for 0, 1, 2, and 3 errors, and finding the probability for 4 or more errors, multiply the result by the total number of transmitted packets:

Number of packets received in error = P(4 or more errors) * Total transmitted packets

This will give you the number of packets received in error from 20,000 transmitted packets.

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Answer:

14.5° ; THD % = 3.873 × 100 = 387.3%.

Explanation:

Okay, in this question we are given the following parameters or data or information which is going to assist us in solving the question efficiently and they are;

(1). "500 VAR reactive power from 230 Vrms 50 Hz 1.5 KVAR reactor".

(2). Consideration of up to 12th harmonic.

So, let us delve right into the solution to the question above;

Step one: Calculate the Irms and Irms(12th) by using the formula for the equation below;

Irms = reactive power /Vrms = 500/230 = 2.174 A.

Irms(12th) = 1.5 × 10^3/ 12 × 230 = 0.543 A.

Step two: Calculate the THD.

Before the Calculation of the THD, there is the need to determine the value for the dissociation factor, h.

h = Irms(12th)/Irms = 0.543/ 2.174 = 0.25.

Thus, THD = [1/ (h)^2 - 1 ] ^1/2. = 3.873.

THD % = 3.873 × 100 = 387.3%.

Step four: angle AC - Ac converter

theta = sin^-1 (1.5 × 10^3/ 12 × 500) = 14.5°.

Answer:

The condition does not hold for a compression test

Explanation:

For a compression test the engineering stress - strain curve is higher than the actual stress-strain curve and this is because the force needed in compression is higher than the force needed during Tension.  The higher the force in compression leads to increase in the area therefore for the same scale of stress the there is more stress on the Engineering curve making it higher than the actual curve.

Hence the condition of : on the same scale for stress, the tensile true stress-true strain curve is higher than the engineering stress-engineering strain curve. does not hold for compression test

The shape of a bridge is determined by the material it's made of. Bridges are made from different materials such as wood, steel, stone, and reinforced concrete.

Stone bridge: A stone bridge is built from stone blocks or stones that are cut and fitted together. The shape of a stone bridge is typically arched or curved. This is because stone is a very heavy and dense material that can withstand a lot of pressure. The arched shape of the stone bridge helps distribute the weight of the bridge evenly across the supporting pillars.

Steel bridge: A steel bridge is made from steel beams or trusses. The shape of a steel bridge is typically angular and geometric. This is because steel is a very strong material that can be easily molded and shaped into different shapes. The angular shape of the steel bridge helps distribute the weight of the bridge evenly across the supporting pillars. The shape also helps provide stability and prevent the bridge from swaying or moving in high winds.

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A hypothesis for an experiment forecasts the changes that will occur in the variable when the predictor variables is altered.

An assumption or notion is given as a hypothesis for the goal of debating it and testing whether it may be true. In the process of science, the hypothesis is developed before any primary active from a basic backdrop review—has been conducted.

A thesis is a rough explanation for a collection of facts that may be put to the test by specific follow-up studies. The two major categories are alternative hypothesis and null hypothesis. A issue is how most research projects begin.

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Answer:

no need for that

Explanation:

they are not the same at all

A console application called IPconfig is used to display information about TCP/IP settings as well as information about DNS and DHCP (Dynamic Host Configuration Protocol).

Both IPv4 and IPv6 networks use IPsec to authenticate and encrypt data packets. A packet's IP header contains IPsec protocol headers, which specify how a packet's contents are handled, including how it is delivered across a network and routed. Email messages are transmitted over the Internet using the Simple Mail Transfer Protocol (SMTP). Most email clients use this protocol to send messages to the server, and servers also use it to forward messages to their intended recipients.

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Using the knowledge of computational language in C++ it is possible to write a code that user-input value is the number of nodes in the linked list

#include "MileageTrackerNode.h"

#include <string>

#include <iostream>

using namespace std;

int main(int argc, char *argv[]) {

   // References for MileageTrackerNode objects

   MileageTrackerNode *headNode;

   MileageTrackerNode *currNode;

   MileageTrackerNode *lastNode;

   double miles;

   string date;

   // Front of nodes list

   headNode = new MileageTrackerNode();

   lastNode = headNode;

   // Read in the number of nodes

   int no_nodes;

   cin >> no_nodes;

   // For the read in number of nodes, read in data and insert into the linked list

   MileageTrackerNode *tail = headNode;

   for (int i = 0; i < no_nodes; ++i) {

       double milesInit;

       cin >> milesInit;

       cin >> date;

       MileageTrackerNode *newNode = new MileageTrackerNode(milesInit, date, nullptr);

       tail->InsertAfter(newNode);

       tail = newNode;

   }

   // Call the PrintNodeData() method to print the entire linked list

   MileageTrackerNode *cur = headNode->GetNext();

   while (cur != nullptr) {

       cur->PrintNodeData();

       cur = cur->GetNext();

   }

   // MileageTrackerNode Destructor deletes all following nodes

   delete headNode;

}

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Answer:

True

Explanation:

To summarise, waves carry energy. The amount of energy they carry is related to their frequency and their amplitude. The higher the frequency, the more energy, and the higher the amplitude, the more energy.

Explanation:

rational

Step-by-step explanation:

The discriminant (d) of a quadratic equation ax^2 + bx + c = 0ax

2

+bx+c=0 is:

\boxed{\mathrm{d =} \ b^2 - 4ac}

d= b

2

−4ac

.

If:

• d > 0, then there are two real solutions

• d = 0, then there is a repeated real solution

• d < 0, then there is no real solution.

In this question, we are given the quadratic equation 3x^2 + 4x - 2 = 03x

2

+4x−2=0 . Therefore, the discriminant of the equation is:

b² - 4ac = (4)² - 4(3)(-2)

= 16 - (-24)rational

Step-by-step explanation:

The discriminant (d) of a quadratic equation ax^2 + bx + c = 0ax

2

+bx+c=0 is:

\boxed{\mathrm{d =} \ b^2 - 4ac}

d= b

2

−4ac

.

If:

• d > 0, then there are two real solutions

• d = 0, then there is a repeated real solution

• d < 0, then there is no real solution.

In this question, we are given the quadratic equation 3x^2 + 4x - 2 = 03x

2

+4x−2=0 . Therefore, the discriminant of the equation is:

b² - 4ac = (4)² - 4(3)(-2)

= 16 - (-24)

= 40

Since the discriminant, 40, is greater than zero, the quadratic equation has 2 rational solutions.

= 40

Since the discriminant, 40, is greater than zero, the quadratic equation has 2 rational solutions.

Answer:

Explanation:

The only vertical force that can be applied at joint D is that of link CD. Since joint D is stationary, there must be no vertical force. Hence the force in link CD must be zero, as must the force in link DE.

At joint E, the only horizontal force is that applied by link EF, so it, too, must be zero.

Then link CE has 15 N tension.

The downward force in CE must be balanced by an upward force in CF. Of that force, only 1/√2 of it will be vertical, so the force in CF is a compression of 15√2 N.

In order for the horizontal forces at C to be balanced the 15 N horizontal compression in CF must be balanced by a 15 N tension in BC.

At joint F, the 15 N horizontal compression in CF must be balanced by a 15 N compression in FA. CF contributes a downward force of 15 N at joint F. Together with the external load of 10 N, the total downward force at F is 25 N. Then the tension in BF must be 25 N to balance that.

At joint B, the 25 N downward vertical force in BF must be balanced by the vertical component of the compressive force in AB. That component is 2/√5 of the total force in AB, which must be a compression of 25√5/2 N.

The horizontal forces at joint B include the 15 N tension in BC and the 25/2 N compression in AB. These are balanced by a (25/2+15) N = 55/2 N tension in BG.

In summary, the link forces are ...

_____

Note that the forces at the pins of G and A are in accordance with those that give a net torque about those point of 0, serving as a check on the above calculations.

The radial load in bearing b when the motor is stopped with zero tension in the chain is 300 lb. It is logical that the load in the bearing is higher when the motor is stopped than when it is running and putting tension in the chain due to the principle of statics.

Here's why:When the motor is running, the chain is stretched due to the tension force applied to it. This tension force counteracts the radial load on the bearings, which is why the load is lower in this scenario.On the other hand, when the motor is stopped with zero tension in the chain, the weight of the load is entirely supported by the bearings.

The radial load on the bearing is given by the formula:Radial load on bearing = (Weight of load / Number of bearings) + Axial load due to belt tensionTherefore, when the motor is stopped with zero tension in the chain, the radial load on bearing b can be calculated as follows:Radial load on bearing b = (300 lb / 2) + 0Radial load on bearing b = 150 lbHence, the radial load in bearing b when the motor is stopped with zero tension in the chain is 150 lb.

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Answer:

If I am not mistaken I believe it is a higher voltage.

Explanation:

Hope this helps

At time t=2 min, the concentration inside the tank is 0.042 kg/kg and the concentration outside the tank is 0.476 kg/kg.

To determine the concentration inside and outside the tank at 2 minutes, we need to use the mass balance equation:

mass in - mass out + mass generated = change in mass in the tank

At time t=0, the mass in the tank is 8 kg, and there is no mass generated. Thus, we have:

(2.2 + 0.2) kg/min - 2 kg/min + 0 kg/min = dM/dt

Simplifying, we get:

dM/dt = 0.4 kg/min

Integrating both sides, we get:

M(t) = M(0) + (dM/dt) * t

Plugging in the values, we get:

M(2) = 8 kg + (0.4 kg/min) * 2 min = 9.6 kg

Now, we can calculate the concentration inside and outside the tank:

Concentration inside the tank:

At time t=0, the concentration inside the tank is:

Cin(0) = 0 kg/kg (since there is no salt in the tank initially)

At time t=2 min, the amount of salt in the tank is:

Min(2) = 0.2 kg/min * 2 min = 0.4 kg

Thus, the concentration inside the tank is:

Cin(2) = Min(2) / M(2) = 0.4 kg / 9.6 kg = 0.042 kg/kg

Concentration outside the tank:

The rate of salt leaving the tank is 2 kg/min, and at time t=2 min, the total amount of salt leaving the tank is:

Mout(2) = 2 kg/min * 2 min = 4 kg

Thus, the amount of salt remaining in the tank is:

Mrem(2) = M(0) + Min(2) - Mout(2) = 8 kg + 0.4 kg - 4 kg = 4.4 kg

The total mass leaving the tank is 2 kg/min * 2 min = 4 kg. Thus, the concentration outside the tank is:

Cout(2) = Mout(2) / (M(0) + Min(2)) = 4 kg / 8.4 kg = 0.476 kg/kg

Therefore, at time t=2 min, the concentration inside the tank is 0.042 kg/kg and the concentration outside the tank is 0.476 kg/kg.

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Valve supervisory initiating devices are designed to detect the movement or position of a valve and initiate a supervisory signal in the event of any abnormal conditions.

The specific requirements regarding the initiation of the supervisory signal may vary depending on the applicable codes and standards. However, a common requirement is that the supervisory signal should be initiated within a certain revolution(s) of the hand wheel or a certain percentage of the travel distance of the valve.

The exact number of revolutions or percentage of travel distance can vary, but typically, it is expected that the supervisory signal should be initiated within one revolution of the hand wheel or within a range of 20% to 30% of the total travel distance of the valve.

These requirements ensure that any abnormal conditions or unauthorized adjustments to the valve are detected promptly and the supervisory system is alerted, allowing for appropriate action to be taken to address the situation and ensure the proper functioning of the valve system.

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Answer:

A. ) 591.7 v

B.) 991.7v

C.) 59.7%

D.) 47.9 Kw

E.) 247925 W

F.) 59.7 %

Explanation:

Given that a simple power system consists of a dc generator connected to a load center via a transmission line. The load power is 100 kW. The transmission line is 100 km copper wire of 3 cm diameter. If the voltage at the load side is 400 V,

Let first calculate the resistance in the wire.

The resistivity (rho) of a copper wire is 1.673×10^-8 ohm metres

Resistance R =( L× rho)/A

Where Area = πr^2 = π × 0.015^2

Area = 0.00071 m^2

R = (100000 × 1.673×10^-8) / 0.00071

Resistance in wire = 2.367 ohms

Then let calculate the resistance in the load.

Also, since Power P = V^2 /R

Make R the subject of formula

R = V^2/ P

R = 400^2/100000

Resistance in load = 1.6 Ohms

Current l = V / R

I = 400/1.6 = 250 Ampere

a.) Voltage drop across the line V line will be achieved by using Ohms law.

V = I R

V = 250 × 2.367

V = 591.7 v

B.) Voltage at the source side Vsource will be

V = V line + V load

V = 400 + 591.7

V = 991.7 v

C.) Percentage of the voltage drop Vline /Vsource

591.7/991.7 × 100 = 59.7%

D.) Line losses

P = I V

P = 250 × 591.7

P = 147925 W

Power loss = 147925 - 100000

Power loss = 47,925 W

Power loss = 47.9 Kw

E.) Power delivered by the source

P = IV

P = 250 × 991.7 = 247925 W

F.) System efficiency

Efficiency = power line / power source × 100

Efficiency = 147925 / 247925 × 100

Efficiency = 59.7 %

In this exercise we have to use the circuit knowledge of an electrical system and calculate the characteristics so we have to:

A. ) 591.7 v

B.) 991.7v

C.) 59.7%

D.) 47.9 Kw

E.) 247925 W

F.) 59.7 %

Organizing the information given in the statement we have that:

Calculating the resistivity we find that:

\(R =( L* \rho)/A\\A= \pi r^2 = 0.00071 m^2\\R = (100000 * 1.673*10^{-8}) / 0.00071\\R = 2.367 ohms\)

Then it becomes simpler to calculate the power and current, we have:

A)  With the above information, we can calculate the voltage as:

\(V = I R\\V = 250 * 2.367\\V = 591.7 v\)

B) Now calculating the source voltage, we find that:

\(V = V line + V load\\V = 400 + 591.7\\V = 991.7 v\)

C.) The percentage will be calculated as the division of the two previous values, like:

\(591.7/991.7 * 100 = 59.7\%\)

D.) Like any imperfect circuit, losses occur, so the loss will be calculated as:

\(Power loss = 147925 - 100000\\Power loss = 47,925 W\\Power loss = 47.9 Kw\)

E.) Power delivered by the source, can be:

\(P = IV\\P = 250 * 991.7 = 247925 W\)

F.) System efficiency, will be:

\(Efficiency = power line / power source *100\\Efficiency = 147925 / 247925 * 100\\Efficiency = 59.7 \%\)

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