3. Find the measure of the sides of the triangle if the vertices of AEFG are E
(1,4), F(5, 4), and G(1,0). Then classify the triangle by its sides.

Answer:

-2x+24

Step-by-step explanation:

given,

= -3(2x-8)+4x

= -6x+24+4x

= 2x+24

therefore 2x+24 is the required equation.

hope it helps!

The domain of the function where the function is decreasing is (-∞, 1). Then the correct option is D.

The domain means all the possible values of the x and the range means all the possible values of the y.

The function is given below.

f(x) = x² - 2x + 5

The equation can be written as

f(x) = x² - 2x + 1 + 4

f(x) = (x - 1)² + 4

Then the domain of the function where the function is decreasing will be (-∞, 1).

Then the correct option is D.

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Answer:

y+1=-5(x-4)

Step-by-step explanation:

YOUR WELCOME

Answer:

hello gimme-Dem points.

Step-by-step explanation:

Answer:

For X is (x=4y−4) and for Y is (y= 1 /4 x+1)

Step-by-step explanation:

Let's solve for x.

x−4y=−4

Step 1: Add 4y to both sides.

x−4y+4y=−4+4y

x=4y−4

Answer:

x=4y−4

Let's solve for y.

x−4y=−4

Step 1: Add -x to both sides.

x−4y+−x=−4+−x

−4y=−x−4

Step 2: Divide both sides by -4.

−4y /−4  =  −x−4 /−4

y= 1 /4 x+1

Answer:

x = 6

Step-by-step explanation:

35 - 2x = 23

35 - 23 - 2x = 0

35 - 23 = 2x

12 = 2x

x = 6

35- 2x = 23

Subtract 35 from both sides.

Subtract 35 from 23 to get −12.

Divide both sides by −2.

Divide −12 by −2 to get 6.

1a)The values of l range from 0 to (n-1), so for n = 3, l can have the values 0, 1, and 2.

b) The values of m can be -2, -1, 0, +1, and +2

c) There are a total of 9 orbitals

The qualities and traits of quantum systems, like the electrons in atoms, are described by a set of numbers known as quantum numbers. They offer knowledge on the system's energy, angular momentum, orientation, and spin, among other characteristics.

Using the formula, number of electrons = \(n^2\)

Number of electrons =\(3^2 = 9\)

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Answer:

yes

Step-by-step explanation:

Answer:

no solution

Step-by-step explanation:

|-1-g|=-1

There's no value of g   that makes the equation be true since an absolute value can never be negative.

Answer:4,200

Step-by-step explanation:

Aisha's net balance after writing the check of $100 to five employees will be $260 .

Given, Aisha’s account balance $760.

Now, to get the net balance of account after deductions .

Remaining amount = Original Balance - Payment amount.

Substitute the values,

Remaining amount = $760 - 5 × $100

Remaining amount = $760 - $500

Remaining amount = $260

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Answer:

5) 2(4 - n) = -3n

2 × 4 - 2 × n = -3n

8 - 2n = -3n

-2n + 3n = -8

1n = -8

n = -8/1

n = -8

6) 5 - 3(2 + 2w) = -7

5 - 3 × 2 + -3 × 2w = -7

5 - 6 - 6w = -7

-1 - 6w = -7

-6w = -7 + 1

-6w = -6

w = -6/-6

w = 1

7) 5(2r + 3) - 5 = 0

5 × 2r + 5 × 3 - 5 = 0

10r + 15 - 5 = 0

10r + 10 = 0

10r = -10

r = -10/10

r = -1

8) 3 - 5(2d - 3) = 4

3 - 5 × 2d - 5 × -3 = 4

3 - 10d + 15 = 4

-10d + 15 + 3 = 4

-10d + 18 = 4

-10d = 4 - 18

-10d = -14

d = -14/-10

d = 7/5

hope this helps you!!

The t statistics and the confidence intervals are both invalid no matter how large sample size is in a regression model if variance of dependent variable Y, conditional on an explanatory variable x , or Var(y|x)  is not constant.

Regression is a statistical technique that relates independent variable to one or more independent variables

It shows Whether changes observed in the dependent variable are associated with the changes in one more more of the explanatory variables .

The 2 basic type of regressions are

If in a regression model, a variance of dependent variable Y ,conditional on an dependent variable x is not constant then the t statistics and the confidence intervals both are not valid regardless of sample size

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Answer:

Switch the second and third one on what you have now. U r good to go

Step-by-step explanation:

7/25=.28

8/32=.25

The critical points of function f(x,y) are (0,0) and (2,1), and (2,1) is a local maximum.

To find the critical points of f(x,y), we need to find all values of (x,y) where the gradient of f(x,y) equals zero. The gradient of f(x,y) is given by:

∇f(x,y) = <(y-2xy), (x-2y^2)>

Setting each component of the gradient equal to zero yields two equations:

y - 2xy = 0

x - 2y^2 = 0

Solving these equations simultaneously, we obtain two critical points: (0,0) and (2,1).

To determine the nature of each critical point, we compute the Hessian matrix of f(x,y):

H(f) = [ 2y -2x ]

[-2y 4y ]

At (0,0), H(f) = [0 0; 0 0], which is a degenerate matrix. Therefore, we cannot use the second derivative test to determine the nature of this critical point.

At (2,1), H(f) = [2 -4; -2 4], which has a negative determinant and a positive trace. Therefore, by the second derivative test, we conclude that (2,1) is a local maximum.

In summary, the critical points of f(x,y) are (0,0) and (2,1), and (2,1) is a local maximum.

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Answer:

160÷3=40

Step-by-step explanation:

that is the answerrrrrrrrrrrrrrrrrrrrrrrrrrr

Recall the definition of each concept to check if it fits the figure.

A) Square: A square is a quadrilateral whose sides all have the same length.

B) Polygon: A polygon is a 2D shape formed by non-intersecting straight segments.

C) Triangle: A triangle is a polygon with exactly 3 sides.

D) Polyhedron: A polyhedron is a 3D shape formed by flat polygonal shapes.

E) Pyramid: A pyramid is a polyhedron formed by a simple polygon whose lateral faces are triangles that converge in a common vertex.

F) Prism: A prism is a polyhedron formed by two parallel and equal polygonal faces, whose lateral faces are parallelograms.

The given object is a 3D shape formed by flat polygonal shapes, with a base that is a quadrilateral and whose lateral faces are triangles that converge in a common vertex.

Therefore, the only two terms that correcty describe the given object are:

D) Polyhedron

E) Pyramid

The choice of reinforcement schedule can have important implications for both learning and the persistence of behavior over time.

The reinforcement schedule can have a significant impact on how quickly a response/behavior is learned and how quickly extinction occurs.

In general, continuous reinforcement schedules (where the behavior is reinforced every time it occurs) tend to result in faster learning of the behavior than partial reinforcement schedules (where the behavior is only reinforced some of the time). This is because the individual learns more quickly that the behavior is associated with the reinforcement.

However, once the behavior is learned, partial reinforcement schedules tend to result in greater resistance to extinction than continuous reinforcement schedules. This is because the individual has learned that the behavior is not always followed by reinforcement, so they are more likely to persist in the behavior even if reinforcement is no longer provided.

Among partial reinforcement schedules, fixed ratio schedules (where reinforcement is provided after a fixed number of responses) tend to lead to the fastest responding and highest rates of responding, but also tend to result in rapid extinction once reinforcement is removed. In contrast, variable ratio schedules (where reinforcement is provided after an average number of responses, with some variation) tend to lead to more stable responding and slower extinction. Fixed interval and variable interval schedules (where reinforcement is provided after the first response following a fixed or variable amount of time) tend to lead to moderate rates of responding and moderate resistance to extinction.

Overall, the choice of reinforcement schedule can have important implications for both learning and the persistence of behavior over time.

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The values of r where the area of the shaded region be greater are values at least 8

From the question, we have the following parameters that can be used in our computation:

The area of the larger rectangle is

Area = 12 * 8

Area = 96

The area of the shaded region is

Area = r * 6

Area = 6r

When the shaded region is greater than or equal to half of the area of the larger rectangle, we have

6r ≥ 1/2 * 96

This gives

r ≥ 1/12 * 96

Evaluate

r ≥ 8

Hence, the values of r are r ≥ 8

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If we let Z = 3 - X, then Z is another exponential random variable with mean 1 that is negatively correlated with X.

Let Y = 2 - X, where X is an exponential random variable with mean 1.

To show that Y is negatively correlated with X, we need to show that Cov(X,Y) < 0.

Cov(X,Y) = E[XY] - E[X]E[Y]

Since X and Y are both exponentially distributed with mean 1, we have:

E[X] = 1, E[Y] = 2 - E[X] = 1

E[XY] = E[X(2-X)] = 2E[X] - E[X^2] = 2 - Var(X)

Var(X) = E[X^2] - (E[X])^2 = 1 - 1^2 = 0

Therefore, Var(X) = 0, which means that E[XY] = 2, and Cov(X,Y) = E[XY] - E[X]E[Y] = 2 - 1*1 = 1 > 0.

Since Cov(X,Y) > 0, we know that Y is positively correlated with X. To find a random variable that is negatively correlated with X, we can use Y = 3 - X instead.

Therefore, if we let Z = 3 - X, then Z is another exponential random variable with mean 1 that is negatively correlated with X.

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you need first see something all the numbers in the polynomial can be divided by 3 then we can rewrite the polynomial as

3(x^3+4x^2+x-6)

the polynomial x^3+4x^2+x-6 is easier to solve and find the roots

the roots are

x = -3

x = -2

x = 1

and finally

we can rewrite the polynomial as

3(x+3)(x+2)(x-1)

so we can say that the right answer is D. 3(x-1)(x+3)(x + 2)

When there is 580 feet of fencing available to complete the job, the largest possible total area of the 5 pens is 7008.33 feet.

The quantity area expresses the extent of a region on a plane or curved surface.

STEP 1: We know that,

A=x y

The perimeter equals 580feet.

The equation is,

580=6x+2y

Step 2: Solving y terns with x,

y=-3x+290

This information will assist us in obtaining our Area equation in terms of a single variable (just in terms of x).

Step 3: Using the x-y relationship discovered in Step 2, write your Area equation in terms of x only. You should obtain

A=x y

A=x(-3x+290)

A=-3x²+290x

Step 4: Derive the area equation,  A' = -6x+290

Step 5: Set A' = 0

-6x+290=0

x=290/6

x=48.33

Step 6: Find y by substituting 48.33 in x in the perimeter equation then,

y=-3(48.33)+290

y=145.01

Step 7:  A=x y

A=(48.33)(145.01)

A=7008.33 feet

The largest possible total area of the 5 pens is 7008.33 feet

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The probability of getting all 4 cards from different suits is 0.267 or approximately 26.7%.

There are 4 suits in a standard deck of cards, and there are 13 cards in each suit. There are C(52,4) ways to choose 4 cards from a deck of 52 cards.

To calculate the probability of getting 4 cards from different suits, we can break it down into steps:

Choose 1 card from any suit (there are 52 possible cards to choose from).

Choose the next card from one of the 39 remaining cards of a different suit (there are 39 cards remaining after taking out the 13 cards from the first suit).

Choose the third card from one of the 26 remaining cards of a different suit (there are 26 cards remaining after taking out the 13 cards from the first and second suits).

Choose the fourth card from one of the 13 remaining cards of a different suit (there are 13 cards remaining after taking out the 13 cards from the first, second, and third suits).

The probability of getting all 4 cards from different suits can be calculated as:

P = (52/52) x (39/51) x (26/50) x (13/49) = 0.267

Therefore, the probability of getting all 4 cards from different suits is 0.267 or approximately 26.7%.

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Answer:

for how much each kid gets

Step-by-step explanation: big brain math kid

Answer:

Step-by-step explanation:

The probability that the coin will show tails and the cube will show a three, four, or six is 1/4.

The probability of two independent events occurring, we multiply their individual probabilities.

Let's start by determining the probability of the coin showing tails.

Since it is a fair coin, there are two equally likely outcomes: heads or tails.

The probability of the coin showing tails is 1/2.

Next, we consider the number cube.

It is a standard six-sided die, and we want to find the probability of rolling a three, four, or six.

Out of the six possible outcomes (numbers 1 to 6), three of them satisfy our condition (3, 4, and 6).

The probability of rolling a three, four, or six is 3/6 or 1/2.

Now, we can find the probability of both events occurring by multiplying the probabilities together:

P(Tails and 3, 4, or 6) = P(Tails) × P(3, 4, or 6)

= 1/2 × 1/2

= 1/4

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Answer:

Static

Step-by-step explanation:

By process of elimination, static is the only one that would work.

Answer:

static.

Step-by-step explanation:

\(\\ \leq \int\limits^a_b {x} \, dx x^{2} \sqrt{x} \sqrt[n]{x} \leq \geq \neq \lim_{n \to \infty} a_n \int\limits^a_b {x} \, dx \left \{ {{y=2} \atop {x=2}} \right.\)