3 Cu + 8HNO3 → 3 Cu(NO3)2
+ 2 NO + 4 H2O
In the above equation, how many grams of water can be made when 10.3 moles of HNO3 are consumed?

Answer:

128.4 m

Explanation:

3.604m + 104.29m + 3.1m + 17.41m

Add all the values

= 128.404 m

The significant figure rule for addition is for the sum to have the same number of decimal places as the value with the least number of decimal places. In the addition sentence 3.604m + 104.29m + 3.1m + 17.41m, the value with the least number of decimal places is 3.1, which has 1 decimal place. Therefore, we round our sum so that it also has 1 decimal place.

128.404 m

= 128.4 m

I hope this helps!

The question is incomplete, the complete question is;

Predict the concentration if a 0.5 M solution, with a volume of 500 mL, is diluted to a volume of 1 liter. Show the calculation of this concentration, include units in all your work.

Answer:

0.25 M

Explanation:

From;

C1V1 =C2V2

C1= initial concentration = 0.5 M

C2 = final concentration = the unknown

V1 = initial volume = 500 ml

V2 = final volume = 1 litre = 1000 ml

substituting values;

0.5 * 500 = C2 * 1000

C2 = 0.5 * 500/1000

C2 = 0.25 M

Answer:

hope it is correct and helps you

good luck

The ability to build molecules is made possible by a chemical bond, which is a strong attraction between atoms, ions, or molecules. The bond may be created by the sharing of electrons in covalent bonds or by the electrostatic interaction between ions that have opposing charges.

Chemical bonds keep the atoms in molecules together. Electrostatic forces between negatively charged electrons and positively charged atomic nuclei produce bonds (the positions of which in space are determined by quantum mechanics).

The three basic types of bonds are metallic, ionic, and covalent.

Definition: Valence electrons are moved from one atom to the next to finish the outer electron shell, creating an ionic bond. Example: NaCl is a typical ionically bonded substance (Salt)

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Answer:

don't know really and don't know at alll

Explanation:

Hund's first and second rules describe how electrons are arranged in an atom's orbitals. Hund's first rule states that when electrons occupy orbitals of equal energy (such as the three p orbitals in a given shell), they will each first occupy separate orbitals before any orbital receives a second electron. This means that electrons will always try to maximize their spin, with one electron in each orbital having the same spin before any pairing occurs.

Hund's second rule states that if two or more orbitals of the same energy level are available, electrons will occupy empty orbitals before they pair up in an orbital that already has an electron.

Now, let's look at the orbital notation for sulfur. The atomic number of sulfur is 16, which means it has 16 electrons.

The orbital notation for sulfur would be:

1s² 2s² 2p⁶ 3s² 3p⁴

This indicates that sulfur has two electrons in the 1s orbital, two electrons in the 2s orbital, and six electrons in the 2p orbital, fully occupying all three 2p orbitals with two electrons in each and spinning in the same direction. Sulfur also has two electrons in the 3s orbital and four electrons in the 3p orbital, with a single electron in each of the three 3p orbitals and the fourth 3p orbital being half-filled. The half-filled 3p orbital is a consequence of Hund's rule, which predicts that electrons will fill each of the three 3p orbitals with one electron before any two orbitals receive a second electron.

Approximately 8.24 mL of the standard EDTA solution is needed to reach the endpoint of the titration when using 20 mL of 0.07 M calcium solution.

EDTA (ethylenediaminetetraacetic acid) is a chelating agent that can bind to metal ions, including calcium, magnesium, iron, and zinc. It is a colorless, water-soluble solid that is commonly used in chemistry, biochemistry, and medicine for various purposes. EDTA forms strong complexes with metal ions, making it useful for a variety of applications, such as:

Chelation therapy: EDTA can be used to treat heavy metal poisoning by binding to and removing excess metals from the body.

Titration: EDTA can be used to measure the concentration of metal ions in a solution by adding a known amount of EDTA and using an indicator to detect when all the metal ions have been bound.

To calculate the volume of the standard EDTA solution needed to reach the endpoint of the titration, we need to use the following equation:

M1V1 = M2V2

where M1 is the molarity of the calcium solution, V1 is the volume of the calcium solution used (in this case, 20 mL), M2 is the molarity of the EDTA solution, and V2 is the volume of the EDTA solution needed to reach the endpoint of the titration.

We know that the molarity of the calcium solution is 0.07 M, and we can assume that the concentration of the EDTA solution is around 0.17 M. We don't have a specific endpoint volume, so we'll leave V2 as a variable.

0.07 M x 20 mL = 0.17 M x V2

V2 = (0.07 M x 20 mL) / 0.17 M

V2 ≈ 8.24 mL

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The theoretical yield of the titanium tetra fluoride is  2.3 g.

We know that we can be able to obtain the theoretical yield from the stoichiometry of the reaction. We already have the balanced chemical reaction equation as shown in the question.

Number of moles of Titanium = 2.6 g/49 g/mol = 0.053 moles

Number of moles of fluorine = 1.4 g/38 g/mol = 0.037 moles

Given that 1 mole of Titanium reacts with 2 moles of fluorine

0.053 moles reacts with  0.053 moles * 2 moles/ 1 mole

= 0.106 moles

Thus fluorine is the limiting reactant

Now;

2 moles of fluorine produces 1 mole of titanium fluoride

0.037 moles of fluorine produces 0.037 moles * 1 mole/ 2 moles

= 0.0185 moles

Theoretical yield  of the product = 0.0185 moles * 124 g/mol

=  2.3 g

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It would require approximately 600 kilojoules of energy to vaporize 2 kg of copper.

To calculate the energy required to vaporize a substance, we need to consider the heat of vaporization, which is the amount of energy required to convert a given amount of substance from its liquid state to its gaseous state at a constant temperature.

The heat of vaporization for copper is approximately 300 kJ/kg (kilojoules per kilogram) at its boiling point, which is around 2567 degrees Celsius (4649 degrees Fahrenheit). This means that for every kilogram of copper, 300 kJ of energy is needed to vaporize it.

Given that you have 2 kg of copper, we can calculate the total energy required as follows:

Energy = Heat of Vaporization × Mass

Energy = 300 kJ/kg × 2 kg

Energy = 600 kJ

Therefore, it would require approximately 600 kilojoules of energy to vaporize 2 kg of copper.

It's worth noting that the heat of vaporization can vary slightly depending on the purity of the copper and the specific conditions, such as temperature and pressure. The value provided here is an approximation. Additionally, it's important to handle copper and any high-temperature processes with caution, as they can pose safety hazards.

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The wavelength of the light will be 9.63 × 10²³ m .The wavelength of the wave is calculated using the frequency formula.

The quantity of cycles finished in a certain amount of time is known as frequency. It also indicates the number of crests that pass past a specific position in a unit of time. It is often referred to as the reciprocal of time. Hertz are used to express frequency (Hz). The frequency of the wave is calculated using the frequency formula.

The total number of times a repeated event occurs in a unit of time is known as its frequency. Depending on the quantities known, various frequency formulas exist to calculate frequency. The terms frequency (f), time period (T), wave speed (V), and wavelength () are all found using the formula for the frequency of a wave.

We know that ,

Frequency= Speed of light/ wavelength

Wavelength= Frequency × Speed of light

=  3.215 ×10¹⁵ × 2.997× 10⁸

= 9.639 × 10²³ m

The wavelength will be obtained by frequency -wavelength formula a and it will come as 9.63 × 10²³ m .

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Taking into account the definition of sensible heat, the energy required to raise the temperature of 4.2 mol of graphite by 25.0°C is 895.3455 J.

Sensible heat is defined as the amount of heat that a body absorbs or releases without changes in its physical state (phase change). In other words, when a system absorbs (or gives up) a certain amount of heat, it can happen that it experiences a change in its temperature without a phase change occurring, which implies sensible heat.

The expression that allows to calculate heat exchanges is:

Q = c× m× ΔT

where:

In this case, you know:

Replacing in the definition of sensible heat:

Q = 0.71 J/gC× 50.442 g× 25 C

Solving:

Q= 895.3455 J

In summary, the energy required is 895.3455 J.

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The standard Gibbs free energy change of the reaction at 25°C is -18,262 J/mol.

Energy is the ability to do work. It exists in many forms, such as kinetic energy (energy of motion), potential energy (stored energy), thermal energy (heat), chemical energy (energy stored in the bonds of molecules), electrical energy (energy carried by electrons), and nuclear energy (energy produced in the nucleus of an atom).

The reaction given is a reversible reaction and the given Kp value is at 25°C. Therefore, we can use the equation ΔG°rxn = -RT ln Kp to calculate the standard Gibbs free energy change of the reaction.
We know that R = 8.314 J/mol K and T = 298 K (25°C)
Therefore, ΔG°rxn = - 8.314 J/mol K x 298 K x ln (2.26 x 10⁴)
ΔG°rxn = -18,262 J/mol
Therefore, the standard Gibbs free energy change of the reaction at 25°C is -18,262 J/mol.

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A chemical reaction is known by;

2. Heat is released

3. A gas is given off

A change in color may indicate that a chemical reaction has occurred. For example, when iron is exposed to air and moisture, it rusts and turns from silver to reddish-brown.

If a gas is produced during a reaction, it can indicate that a chemical reaction has occurred. For example, when baking soda is mixed with vinegar, carbon dioxide gas is produced, which causes bubbles to form.

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Answer:

(a )people separate mixtures in order to ger a specific substance that they need.

A. The hydronium ion concentration, [H₃O⁺] of the solution is 4.57×10⁻⁸ M

B. The hydroxide ion concentration, [OH⁻] of the solution is 1.28×10⁻⁶ M

C. The hydroxide ion concentration, [OH⁻] of the solution is 1.80×10⁻¹¹ M

We can determine the [H₃O⁺] of the solution as shown below:

[H₃O⁺] × [OH⁻] = 10¯¹⁴

[H₃O⁺] × 2.19×10⁻⁷ = 10¯¹⁴

Divide both side by 2.19×10⁻⁷

[H₃O⁺] = 10¯¹⁴ / 2.19×10⁻⁷

[H₃O⁺] = 4.57×10⁻⁸ M

We can determine the [OH⁻] of the solution as shown below:

[H₃O⁺] × [OH⁻] = 10¯¹⁴

7.81×10⁻⁹ × [OH⁻] = 10¯¹⁴

Divide both side by 7.81×10⁻⁹

[OH⁻] = 10¯¹⁴ / 7.81×10⁻⁹

[OH⁻] = 1.28×10⁻⁶ M

We can determine the [OH⁻] of the solution as shown below:

[H₃O⁺] × [OH⁻] = 10¯¹⁴

5.57×10⁻⁴ × [OH⁻] = 10¯¹⁴

Divide both side by 5.57×10⁻⁴

[OH⁻] = 10¯¹⁴ / 5.57×10⁻⁴

[OH⁻] = 1.80×10⁻¹¹ M

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The number of molecules of aspirin is \(4.01\times 10^{20} molecules\)

Given:

120. mg of the aspirin

To find:

The molecules of aspirin in 120. mg of aspirin.

Solution

Mass of aspirin = 120. mg

\(1mg = 0.001 g\\\\120. mg=120.\times 0.001 g=0.120 g\)

Molar mass of aspirin = 180.158 g/mol

Moles of aspirin =\(= \frac{0.120 g}{180.158 g/mol}=0.000666 mol\)

According to the mole concept:

\(1 mole = N_A=6.022\times 10^{23} atoms/molecule/ions\)

The molecules of aspirin in 0.000666 moles of aspirin:

\(=0.000666\times 6.022\times 10^{23} molecules\\\\=4.01\times 10^{20} molecules\)

The number of molecules of aspirin is \(4.01\times 10^{20} molecules\).

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Passive prostheses are self-regulating, as shown in the first answer option.

We can arrive at this answer because:

This limitation allows passive prostheses not to need external regulation and to be self-regulated by fitting the body parts.

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Answer:

self-powered.

Chemists prefer ribbon diagrams because they make the tertiary structure of the protein molecule easier to trace.

A protein molecule can be represented using several kinds of models. The ball and stick models which are common representations for other molecules can also be applied in the case of protein molecules.

However, the ribbon diagrams are preferred by chemists because they make the  tertiary structure of the protein molecule easier to trace. Also, the ribbon diagram shows the overall path and organization of the protein backbone in the protein molecule.

This kind of structure was first introduced by  Jane S. Richardson  around 1981.

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Answer:

Ribbon diagrams look like the name they hold- ribbons. Therefore, they would be a good option if one were to trace or copy the diagram onto another document, etc. Also, they depict protein very well so if a chemist were studying different types of protein he/she would utilize a ribbon diagram.

Explanation:

Answer:

A. C

Because in the given formulae there is no additional subscript, thus meaning only 1 atom is present.

Answer:

Answr - A. Carbon

1. Combination between two elements :

2H2(g) + O2(g)⸻➤2H2O(l)

N2(g) + 3H2⸻➤2NH3(g)

C(s) + O2(g) ⸻➤CO2(g)

The combination reactions as shown in which a new compound is formed from its constituent elements are also called synthesis reactions.

2. Combination between two compounds-

CaO(s)+ H2O(l)⸻➤Ca(OH)2(aq)+ heat

quicklime⠀⠀⠀⠀⠀slakedlime

3. Combination between an element and a compound :

2CO(g)+O2(g) ⸻➤2CO2(g)

2NO(g) + O2(g) ⸻➤2NO2(g)

Answer:

Explanation:

Here, we want to get the mass of the copper metal produced

From what we have in the balanced equation of reaction, the mole ratio for all is 1 to 1

This is the theoretical mole ratio

To get the actual, we need to look through all

Firstly, let us get the mass produced considering zinc

We need to get the number of moles produced

That would be the mass of zinc divided by the atomic mass of zinc

The atomic mass of zinc is 65 amu

The number of moles is thus: 139/65 = 2.1385 moles

The mass of copper would be the this number of moles multiplied by the atomic mass of copper

The atomic mass of copper is 64 amu

The mass is thus:

Now, let us do the same considering copper ii nitrate

We divide the mass by the molar mass

The molar mass of copper ii nitrate is 188 g/mol

The number of moles will be:

The mass of copper produced will be the product of the number of moles and the atomic mass of copper. The atomic mass of copper is 64 amu

The mass is thus:

Copper nitrate produces less amount of copper and thus it is the limiting reagent and its value should be considered

Answer:

Oxygen

Explanation:

Answer:

Oxygen is the second most abundant gas in Earth's atomsphere with nitrogen leading in first.

Answer:

Explanation:

0.25 moles KCl = 19g KCl (molar mass KCl = 74.6g)

Answer:

A. Chemical potential to Kinetic energy

Explanation:

The car engine burns gas to produce motion. Burning is a form of chemical reaction and the motion produced is the kinetic energy.

Answer:

approximately 251.55 grams of AuCl3 would contain 5.0 x 10^23 molecules.

Answer:

I dont understand what the question means

Explanation:

Answer:

3.77 x 10^-11

Explanation:

So the equilibrium would be (0.725 - 0.00000523) ≈ 0.7249

Ka = [H+] x [CH3COO^-] / [CH3COOH]

Ka = [5.23 x 10^-11] x [5.23 x 10^-11] / 0.7249

Ka = 3.77 x 10^-11

Hope this helped : )

Answer:

4- ethyl- 6-methylocta- 1,2,5- triene

Explanation:

See attached. Please give me brainliest I worked hard. ;(

Therefore if a patient receives a dose with an activity of 53. 8 mCi of technetium-99m for cardiac imaging, radioactivity will be left in the patient’s body 72 hours after injection is 0.00024

The equation that describes the radioactive decay is:

Ln [A] = -kt + Ln [A]₀

Where [A] could be taken as activity of the source after time t, [A]₀ is initial activity and k is decay constant.

Decay constant could be written as:

k = ln2 / Half-life

k = ln 2 / 6h

k = 0.115h⁻¹

Replacing in decay equation:

ln a = -0.115 x 72  + Ln [53.8]

ln a = - 8.28 + 3. 98

ln a = - 8.28

log a = -4/ 2.303

log a = 1.867

Therefore if a patient receives a dose with an activity of 53. 8 mCi of technetium-99m for cardiac imaging. radioactivity will be left in the patient’s body 72 hours after injection is 1.867

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Answer:

c - Record !!

Answer:

EZ ANSWER IS C

Explanation: