3. All the deer in Horry County represent which of the following?

species
biome
population
community

Which statement about exothermic reactions is TRUE?

A.In an exothermic reaction, energy is absorbed, bonds are broken, and the temperature decreases.

Answer:

A) 24g soluto y 376g solvente.

B) 16.8g soluto y 39.2g solvente

C) 45g soluto y 405g solvente

D) 10g soluto y 190g solvente

E) 90mL soluto y 360mL solvente

F) 245mL soluto y 735mL solvente

G) 15mL soluto y 35mL solvente

Explanation:

El porcentaje masa/masa (% m/m) se define como la masa de soluto presente en 100g de solución (Soluto + solvente).

De la misma manera, el porcentaje volumen/volumen se define como el volumen de soluto en 100mL de solución:

A) 400 gramos de disolución al 6 % m/m.

400g solución * (6g soluto / 100g solución) = 24g soluto

400g solución - 24g soluto = 376g solvente

b) 56 gramos de disolución al 30 % m/m.

56 gramos de disolución al 30% m/m.

56g solución * (30g soluto / 100g solución) = 16.8g soluto

56g solución - 16.8g soluto = 39.2g solvente

c) 450 gramos de disolución al 10 % m/m

450 gramos de disolución al 10% m/m.

450g solución * (10g soluto / 100g solución) = 45g soluto

450g solución - 45g soluto = 405g solvente

d) 200 gramos de disolución al 5 % m/m

200 gramos de disolución al 5% m/m.

200g solución * (5g soluto / 100g solución) = 10g soluto

200g solución - 10g soluto = 190g solvente

e) 450 mL de disolución al 20 % v/v

450 mL de disolución al 20% m/m.

450 mL * (20mL soluto / 100mL solución) = 90mL soluto

450mL solución - 90mL soluto = 360mL solvente

f) 980 mL de disolución al 25 % v/v

980 mL de disolución al 25% m/m.

980 mL * (25mL soluto / 100mL solución) = 245mL soluto

980mL solución - 245mL soluto = 735mL solvente

g) 50 mL de disolución al 30 % v/v

50 mL de disolución al 30% m/m.

50 mL * (30mL soluto / 100mL solución) = 15mL soluto

50mL solución - 15mL soluto = 35mL solvente

Answer: 150 km

Explanation:

75 × 2 = 150 km

Answer:

74km per hour can be put in fraction form, 75 (km)/ 1 hour

We need to know how man miles in 2 hours so our fraction will be x (km)/ 2 hours

75/1 = x/2

x= 150 km

Explanation:

The mole-mole factors for the chemical equation is 2 moles SO₂/ 1 mole O₂ and 1 mole O₂/ 2 moles SO₂. The correct option is a.

The chemical equation is :

2SO₂(g)  +  O₂(g) --->  2SO₃(g)

The number of moles = mass / molar mass

1 mol of  O₂ reaction with the 2 moles of the SO₂ and it produces the 2 moles of the SO₃.

The mole can be define as the amount of the substance for which contains the more elementary entities for the atoms in the 0.012 kilogram of the carbon 12. The symbol of the mole is mol. The correct option is a.

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This question is incomplete, the complete question is :

Choose the mole-mole factors for the following equation: 2SO2(g) + O2(g) --> 2SO3(g)

SO2 and O2

a. 2 moles So2/1 mole O2 and 1 mole O2/2 moles SO2

b. 1 mole SO2/2 moles O2 and 2 moles O2/1 mole SO2

c. 1 moles SO2/1 mole O2 and 2 mole O2/2 moles SO2

Answer: 59.41

Explanation:

The final temperature of the system has been 130\(\rm ^\circ C\).

Specific heat can be defined as the amount of heat required to raise the temperature of 1 g of substance by 1-degree celsius.

The amount of heat lost and the heat gained have been equal.

Heat = mass × specific heat × change in temperature

Thus,

mc\(\Delta\)T = mc\(\Delta\)T

50 g × (10 - x) = 120 × (x - 80)

500 - 50x = 120x - 9600

70x = 9100

x = 130

Thus, the final temperature of the system has been 130\(\rm ^\circ C\).

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Answer:

food doesn't spoil as fast when it is refrigerated because  it would be at  room temperature. Because of the lowered temperature, there are less collisions, which slows down the reaction! Due to decomposition reactions with oxygen or carbon dioxide in the air, meat begins to feel slimy and smell spoiled.  and member mark me as brainliest

Answer:

A lower temperature slows down the reactions in the food because there are less collisions. The chemical breakdowns and microorganism activity can't work as fast as it used to because of the cold.

After 8 hours, approximately 15,729 foodborne bacteria will be present in the culture.

To find the growth rate, k, we can use the given information. Using the uninhibited growth formula:

A = A₀ · \(e^(kt)\),

where A is the final amount, A₀ is the initial amount, t is the time, and e is the base of the natural logarithm.

Given that the initial amount is 100 bacteria (A₀ = 100) and the amount after 1 hour is 350 bacteria (A = 350), we can plug these values into the equation:

350 = 100 · \(e^(kt)\).

Simplifying the equation, we have:

\(e^(kt)\) = 3.5.   [Equation 1]

Now, we need to solve for k. Taking the natural logarithm (ln) of both sides of Equation 1:

ln(\(e^k\)) = ln(3.5),

k = ln(3.5).

Using a calculator, we find that k ≈ 1.2528.

Now, we can use the growth rate k to answer the question. Plugging the values into the uninhibited growth formula with t = 8 hours:

A = 100 · \(e^(1.2528 · 8)\).

Evaluating the equation, we find:

A ≈ 15,729.

Therefore, after 8 hours, approximately 15,729 foodborne bacteria will be present in the culture.

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Yes, canola oil and olive oil are good choices for replacing saturated fats in your diet, as they are rich in monounsaturated fats.

Both canola oil and olive oil contain high amounts of monounsaturated fats, which have been shown to have health benefits, such as reducing the risk of heart disease and improving cholesterol levels. Monounsaturated fats are also more stable than polyunsaturated fats, which makes them a better choice for cooking and baking.

In contrast, saturated fats have been linked to an increased risk of heart disease, as they raise LDL (bad) cholesterol levels. For this reason, it is recommended to limit the amount of saturated fats in your diet and replace them with healthier fats, such as monounsaturated and polyunsaturated fats.

In conclusion, using canola oil and olive oil in place of saturated fats can help you achieve a healthier balance of fats in your diet.

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Weather forecasting has substantially improved thanks to technical and data analytic advancements, but there are still a lot of intricate and dynamic aspects that can influence weather patterns, such as changes in air pressure, temperature, and humidity.

It is challenging to forecast a storm's precise trajectory and strength due to the possibility of unforeseen events and anomalies. The effects of catastrophic weather occurrences can be mitigated and forecasting accuracy can be increased with the help of ongoing technical and scientific developments.

In addition to forecasting technologies, infrastructure should be resilient to the effects of powerful storms and early warning systems that can alert people to approaching danger from severe weather should be available.

Not all countries have the financial means to support the development and application of these technologies. It is morally right for developed countries to help less developed ones obtain this technology.

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Among the following, option c represent the reaction that powers a lead-acid battery where, lead metal, lead oxide and sulphuric acid reacts to form lead sulphate.

Lead acid battery uses the mixture of lead oxide and sulphuric acid as electrolyte. It  is a secondary battery . Reversible chemical processes take place in secondary cells.

By running a current through the battery, the reactants that produce an electric current through chemical processes in these batteries can be recharged (recharging).

Discharging is the chemical process of drawing current from a secondary battery (forward reaction). Charging is a process used to regenerate active material. The reaction taking place in lead-acid batteries is option c.

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Oxygen can only generate two bonds because it needs two additional electrons to complete its octet, after which it will run out of empty orbitals in which to receive additional electrons and create additional bonds.

These compounds have four, three, two, and one bonds between the carbon, nitrogen, oxygen, and chlorine atoms, respectively.

Oxygen typically contains two bonds, but it can also have three. If it has three bonds, it will be positively charged. An oxygen atom frequently has just one link, although the atom is negatively charged. Halogens typically only have one bond; polyatomic ions are significant exceptions.

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Answer:

5 cm and 50 mm

Explanation:

1 cm = 10 mm

So 5cm = 50 mm

The half-life of this unknown radioactive element is one day.

The half-life of a radioactive element is the time taken for half of the original sample to decay. To calculate the half-life of this unknown radioactive element, we need to use the formula:

Nt = N0 (1/2)^(t/T)

Where Nt is the final amount of the sample, N0 is the initial amount of the sample, t is the time passed, and T is the half-life.

From the question, we know that the radioactivity of the sample decreases by a certain percentage in days. Let's assume that the percentage decrease is 50%, which means that after one day, the sample will have only 50% of its original radioactivity. Plugging this value into the formula, we get:

1/2 = (1/2)^(1/T)

Taking the natural logarithm of both sides, we get:

ln(1/2) = ln[(1/2)^(1/T)]

-ln(2) = -(1/T)ln(2)

T = ln(2) / ln(2) = 1 day

Therefore, the half-life of this unknown radioactive element is one day.

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The physical state of a substance is determined by the balance between intermolecular attractions and the kinetic energy of its molecules. Stronger intermolecular.

attractions lead to a more condensed state (solid or liquid), while higher kinetic energy promotes a more dispersed state (gas).

The physical state of a substance, whether it is a solid, liquid, or gas, is determined by the interplay between intermolecular attractions and the kinetic energy of its molecules. Intermolecular attractions are the forces of attraction between molecules, such as hydrogen bonding, dipole-dipole interactions, and London dispersion forces. These attractions arise from the interactions between the electrons of neighboring molecules.

In a solid, the intermolecular attractions are strong, holding the molecules closely together in a fixed arrangement. The kinetic energy of the molecules is relatively low, causing them to vibrate in fixed positions. This results in a rigid structure and a definite shape and volume.

In a liquid, the intermolecular attractions are weaker compared to solids. The molecules have enough kinetic energy to partially overcome these attractions, allowing them to move past one another. This leads to a fluid state with no fixed shape but a definite volume.

In a gas, the intermolecular attractions are very weak, and the kinetic energy of the molecules is high. The molecules move rapidly and freely, colliding with each other and with the walls of the container. As a result, gases have no fixed shape or volume and can expand to fill the available space.

In summary, the balance between intermolecular attractions and the kinetic energy of molecules determines the physical state of a substance. Stronger intermolecular attractions lead to a more condensed state (solid or liquid), while higher kinetic energy promotes a more dispersed state (gas).

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C.heat the solution

Prolactin is a peptide hormone that plays a crucial role in various physiological functions in the human body, including milk production. On the diagram of prolactin, the partial or full charges present in the molecule should be labeled.

Prolactin is likely to be dissolved in water. Peptide hormones, such as prolactin, are composed of amino acids that contain functional groups, including amine (-NH2) and carboxyl (-COOH) groups. These functional groups can form hydrogen bonds with water molecules, allowing the hormone to dissolve in water. Additionally, prolactin is a polar molecule due to the presence of various charged and polar amino acids in its structure. Polar molecules are soluble in water because they can interact with the polar water molecules through hydrogen bonding.

C. On the diagram of prolactin, the areas where water molecules could interact via hydrogen bonds can be identified. These include regions with polar or charged amino acid residues. If prolactin is water-soluble, a hydration shell can be demonstrated around the molecule, indicating the formation of hydrogen bonds between water molecules and the polar regions of prolactin. The specific locations of these interactions and the hydration shell can be indicated on the diagram.

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Answer:

gasoline

Explanation:

The amount of dry NH₄HCl needed to prepare a buffer solution that has a pH of 8.56 is 188.29 grams.

To prepare the buffer solution with a pH of 8.56, first, we need to calculate the concentration of NH₄⁺ ions using the Henderson-Hasselbalch equation:

pH = pKa + log([NH₄⁺]/[NH₃])

Since we have pH and [NH₃], we need to find pKa using Kb for ammonia:

Kb = 1.8 × 10⁻⁵
Kw = 1 × 10⁻¹⁴ (ion product of water)

Ka = Kw / Kb = 1 × 10⁻¹⁴ / 1.8 × 10⁻⁵ = 5.56 × 10⁻¹⁰
pKa = -log(Ka) = 9.26

Now, we can use the Henderson-Hasselbalch equation:

8.56 = 9.26 + log([NH₄⁺]/(0.800))

Rearranging to find [NH₄⁺]:

[NH₄⁺] = 0.800 * 10^(9.26 - 8.56) = 0.800 * 10^(0.70) = 1.6 M

Now, we can calculate the grams of NH₄Cl needed to achieve this concentration:

1.6 mol/L * 2.20 L = 3.52 mol of NH₄Cl

Finally, convert moles to grams using the molar mass of NH₄Cl (53.49 g/mol):

3.52 mol * 53.49 g/mol = 188.29 g

So, you need to add 188.29 grams of dry NH₄Cl to the 2.20 L of 0.800 M NH₃ solution to prepare the buffer with a pH of 8.56.

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The function of a power source in an electric circuit is to  provide a steady flow of electrons.

An electric circuit comprises of individual electronic components like resistors, diodes,transistors , capacitors,etc. which are connected to each other by means of wires through which electric current flows.It can also be referred to as an electronic circuit.

It usually comprises of at least one active component . The combination of wires and simple and complex components allows operations to be performed, amplification of signals, displacement of data and performing of computations.

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Answer:  a steady flow of electrons

Explanation:

To prepare the pH 4.00 buffer solution, you should mix approximately 61.35 mL of the 0.100 M benzoic acid solution with 38.65 mL of the 0.240 M sodium benzoate solution.The ratio of benzoic acid to sodium benzoate in the buffer solution using the Henderson-Hasselbalch equation.

To prepare a pH 4.00 buffer solution using benzoic acid and sodium benzoate, we need to calculate the appropriate volumes of the 0.100 M benzoic acid and 0.240 M sodium benzoate solutions.

First, we need to determine the ratio of benzoic acid to sodium benzoate in the buffer solution. The Henderson-Hasselbalch equation can help us with this calculation:

pH = pKa + log([A-]/[HA])

Given that the pH is 4.00 and pKa is 4.20, we can rearrange the equation:

log([A-]/[HA]) = pH - pKa

log([A-]/[HA]) = 4.00 - 4.20

log([A-]/[HA]) = -0.20

Next, we take the antilog of -0.20 to find the ratio of [A-] to [HA]:

[A-]/[HA] = antilog(-0.20)

[A-]/[HA] = 0.63

The ratio of [A-] to [HA] is 0.63.

Now, let's calculate the volumes of each solution needed. Let's assume x represents the volume (in mL) of the 0.100 M benzoic acid solution and y represents the volume (in mL) of the 0.240 M sodium benzoate solution.

Since the total volume is 100.0 mL, we have the equation: x + y = 100

Considering the ratio of [A-] to [HA] as 0.63, we can write the equation: y/x = 0.63

Solving these two equations simultaneously will give us the volumes of each solution:

x + y = 100

y/x = 0.63

By substituting y = 0.63x from the second equation into the first equation, we get:

x + 0.63x = 100

1.63x = 100

x = 61.35 mL (rounded to two decimal places)

Substituting this value back into the equation x + y = 100, we find:

61.35 + y = 100

y = 38.65 mL (rounded to two decimal places)

Therefore, to prepare the pH 4.00 buffer solution, you should mix approximately 61.35 mL of the 0.100 M benzoic acid solution with 38.65 mL of the 0.240 M sodium benzoate solution.

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Explanation:

1) There are three sub atomic particles; protons, neutrons and electrons. Protons and Neutrons are found in the nucleus while electrons are found in orbitals outside the Nucleus.

2)  No. This is not always the case. An example is sodium which has atomic mass of 23.

Atomic Mass = Neutrons + Protons

23 = Neutrons + 11

Neutrons = 23 - 11 = 12

In sodium there are 11 protons and 12 neutrons

The value of R from the ideal gas equation is 0.082 atm.L/K/mol.

The ideal gas equation is the equation that shows the relationship between pressure, and volume. moles of a gas and the temperature of a gas under ideal conditions.

The ideal gas equation is given below as follows:

PV = nRT

At standard temperature and pressure, the values of the variables are given below;

Pressure, P = 1 atm

Volume, V = 22.4 Liters

Number of moles, n = 1 mole

Temperature, T = 273.15 K

R = PV/nT

R = 1 * 22.4 / (273.15 * 1)

R = 0.082 atm.L/K/mol

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Answer: solo necesito puntos lo siento

Explanation:

Answer:

Cadmium has larger atomic radius than sulfur.

Explanation:

Down a period, atomic radii decrease from left to right due to the increase in the number of protons and electrons across a period: when a proton is added the pull of the electrons towards the nucleus is larger, so the size of the atom decreases.

Hence, you can compare the elements that belong to a same period and predict that the atom with lower atomic number (number of protons) will haver larger atomic radius. With that:

Oxygen and fluorine are in the period 3, being oxygen to the left of fluorine, so oxygen is larger than fluorine.

Sulfur and chlorine are in the period 4, being sulfur to the left of chlorine, so sulfur is larger than chlorine.

Now see whan happens down a group. Atomic radius increases from top to bottom within a group due to electron shielding. That permits you to compare the size of the elements in a group:

Fluorine and chlorine are in the same group (17), with chlorine directly below fluorine, so the atomic radius of chlorine is larger than the atomic radius of fluorine.

Sulfur and oxygen are in the same group (16), with sulfur directlly below oxygen, so sulfur the atomic radius of sulfur is larger than the atocmi radius of oxygen.

So far, you can rank the atomic radius of sulfur, chlorine, fluorine, and oxygen, in increasing order as:

O < F < Cl < S, concluding that O, F, and Cl have smaller atomic radius than S.

Cadmiun, Cd, is to the left and below sulfur, so both electron shielding (down a group) and increase of the number of protons (down a period) lead to predict the cadmium has a larger atomic radius than sulfur.

Answer:

B. All of these

Explanation: They are all correct and beneficial

Answer:

B) all of these

all the given options are correct

Answer:

Loam is soil composed mostly of sand, silt, and a smaller amount of clay. By weight, its mineral composition is about 40–40–20% concentration of sand–silt–clay, respectively.

Explanation:

Answer:

vigorous

Explanation:

As you go down group one of the periodic table, the reactions become and more vigorous.

Answer:

Option 3, The attraction between the can and the magnet is a pull.

Explanation:

The complete question is

Mr. Wang works in a recycling center. Recyclable materials arrive at the

center mixed together. Workers use magnets to separate steel cans from

other items. Which two statements are true about the force between a steel can and a magnet?

1 Gravity pushes the can toward the magnet.

2 The force between the can and the magnet is a noncontact force.

3 The attraction between the can and the magnet is a pull.

4 The attraction between the can and the magnet is a push

Solution

The force exerted by magnet on steel is the pull force. In magnets unlike poles attract each other (pull force) while the like poles repel (push force). Now, the steel or any ferrous object in the garbage when experience magnetic field develop magnetic field of their own in such a way that their north always faces the south of the external magnet or vice versa.

Hence, the force between a steel can and a magnet is pull force