3. A car has a mass of 1000kg. What is its weight?

A) 9.81x10 ^ 3N
B) 1.89x10 ^ 3N

The final velocity of the 25.8 g marble after the collision is 16.15 cm/s.

The velocity of the 25.8 g marble after the collision is calculated as follows;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

where;

The final velocity of the 25.8 g marble after the collision is calculated as;

( 25.8 x 21 ) + ( 12.4 x 13.8 ) = ( 12.4 x 23.9 ) + ( 25.8v )

712.92 = 296.36 + 25.8v

25.8v = 416.56

v = 416.56 / 25.8

v = 16.15 cm/s

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A elephant kicks a 5.0 kg stone with 150 J of kinetic energy.

What is the stone’s speed?

Answer: 7.75 m/s

The period of the pendulum allows to find the result for how much it advances when the length is reduced is:

           Δt = 1550 s

Simple harmonic motion is an oscillatory motion where the restoring force is proportional to the displacement.

In the case of the simple pendulum, this is fulfilled for small angles minus 15º, the angular velocity of the pendulum is

           w = \(\frac{g}{L}\)  

Angular velocity and period are related

           w = \(\frac{2pi}{T}\)

We substitute

            T = \(2\pi \ \frac{L}{g}\)  

They indicate that for the initial length L₀ and the pendulum marks the exact time, how much time changes if the length is  3.97 feet, therefore the initial length is L₀ = 3.90 feet.

            \(T_o^2 = 4 \pi ^2 \ \frac{L_o}{g}\)  

The period for the reduced length is:

           \(T'^2 = 4\pi ^2 \ \frac{L}{g}\)  

The relationship between the periods is:

            \(( \frac{T}{T'}^2 = \frac{L_o}{L} \\T' = \sqrt{\frac{L_o}{L} } \ T\)

Let's calculate

             T ’=  \(T \ \sqrt{\frac{3.97}{3.9} }\)  

             T ’= T 1.01795

In the total time of a day.

             T = 24 hours (3600 s / 2h) = 86 400 s

We calculate

             T ’= 86400 1.01795

              T ’= 87,950 s

Therefore the pendulum moves forward in a time of:

           ΔT = T'- T

           ΔT = 87950 - 86400

           ΔT = 1550 s

In conclusion, using the period of the pendulum we can find the result for how much it advances when the length is change is:

           ΔT = 1550 s

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Answer:

C

Explanation:

The answer is C because if you look at the 1 hour mark it shows 10km

Answer:It will be 10km/hour

Explanation:

The power of man performing 500 J of work in 8 seconds is 62.5 J/s.

Power can be defined as the pace at which work is completed in a given amount of time.

Horsepower is sometimes used to describe the power of motor vehicles and other machinery.

The pace at which work is done on an item is defined as its power. Power is a temporal quantity.

Which is connected to how quickly a project is completed.

The power formula is shown below.

Power = Energy / Time

Power = E / T

Because the standard metric unit for labour is the Joule and the standard metric unit for time is the second, the standard metric unit for power is a Joule / second, defined as a Watt and abbreviated W.

Here we have given Energy as 500 J and Time as 8 second.

Power = Energy / Time

Power = 500 / 8  Joule / sec

Power = 250 / 4  Joule / sec

Power = 125 / 2 Joule / sec

Power = 62.5 Joule / sec  or  62.5 watt

Power came out to be 62.5 J/s when the man performed 500 Joule of work in 8 seconds.

So we can conclude that the power in the Energy transmitted per unit of time, and can be find out by dividing Energy by time. In our case the Power came out to be 62.5 Joule / Second.

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The change in the displacement is 70 m

Recall that the displacement is obtained as the product of the velocity and time. We have the velocity at two intervals.

At v1, the displacement can be obtained from;

x1 = 0.5 * 20 = 10 m

At v2, the displacement can be obtained as;

x2 = 2 * 40 = 80 m

Now

Δx = 80 m - 10 m = 70m

Thus the change in the displacement is 70 m

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Answer:b) 4.5×10^9km

Explanation:use s= vt/1000 here, v= speed of light which is 3×10^8m/s

t= time in second

Given:

The mass of the satellite is m = 200 kg

The initial radius of the circular orbit is

The final radius of the circular orbit is

The mass of the earth is

Also, the gravitational constant is

To find the approximate change in gravitational force.

Explanation:

In order to calculate the approximate change in the gravitational force, we have to find the difference between the initial and final gravitational forces.

The initial gravitational force can be calculated as

The final gravitational force can be calculated as

The approximate change can be calculated as

Final Answer: The approximate change in the gravitational force is -73 N

Answer:

The answer is D. In the direction of the wave

Explanation:

I took the test, hope this helps! :)

Given:

The initial velocity of the car is: u = 0 m/s

The final velocity of the car is: v = 23.4 m/s

The velocity of the car changes over the time t = 2.90 s

To find:

a) The magnitude of the car's acceleration

b) The time taken by a car to change its speed from 11.7 m/s to 23.4 m/s

Explanation:

The acceleration of the object is defined as the rate of change of its velocity.

a)

Mathematically the acceleration of the car is given as:

Here, a is the acceleration of the car.

Substituting the values in the above equation, we get:

b)

The car accelerates uniformly, thus, the acceleration of the car when its velocity changes from zero to 23.4 m/s will remain the same.

Let w be the initial velocity. Thus,

w = 11.7 m/s

The time taken by the car to change its speed from 11.7 m/s to 23.4 m/s can be determined as:

Answer:

b

Explanation:

Answer:

The correct answer is D, diatoms have glass-like cell walls.

Answer:

D

Explanation:

If the water represents the oceans water then you'd would need to calculate how much of earth is water (96.5)

Answer:

I think it's a chemical change.

Answer:

i would describe an ocean current like a pull of the water

Explanation:

water

a. The minimum time for the rocket to reach the sound barrier is 33.67 seconds.

b. The maximum vertical thrust of the rocket engines under these conditions is 250,893.6 N.

c. The rocket is 5548.1 meters above the Earth's surface when it breaks the sound barrier.

To solve this problem, we'll use Newton's second law of motion (F = ma) and consider the forces acting on the rocket and the instrument inside.

Calculating the minimum time for the rocket to reach the sound barrier without breaking the inside wire.

a) Minimum time to reach the sound barrier:

Given:

Mass of the rocket (m) = 2.56 × \(10^4\) kg

Acceleration due to gravity (g) = 9.8 m/\(s^2\)

Maximum tension the wire can support (T_max) = 27.5 N

Weight of the instrument (W) = mass of the instrument × acceleration due to gravity = 13.6 N

The forces acting on the instrument inside the rocket are its weight (W) and the tension in the wire (T). At maximum tension, the net force on the instrument is zero.

T - W = 0

T = W

Therefore, the maximum tension in the wire is equal to the weight of the instrument, which is 13.6 N.

Now, let's determine the acceleration of the rocket. The total force acting on the rocket is the sum of the rocket's weight (mg) and the tension in the wire (T).

F_total = mg + T

F_total = (2.56 × \(10^4\) kg)(9.8 m/\(s^2\)) + 13.6 N

F_total = 250,880 N + 13.6 N

F_total = 250,893.6 N

Since we're assuming the rocket's acceleration is constant.

we can use Newton's second law:

F_total = ma

250,893.6 N = (2.56 × \(10^4\) kg)a

Solving for acceleration:

a = 250,893.6 N / (2.56 × \(10^4\) kg)

a ≈ 9.8 m/\(s^2\)

The acceleration of the rocket is approximately 9.8 m/\(s^2\), which is the same as the acceleration due to gravity.

To find the minimum time to reach the sound barrier, we can use the following equation of motion:

v = u + at

where,

v = final velocity (sound barrier velocity = 330 m/s)

u = initial velocity (which is zero since the rocket starts from rest)

a = acceleration

t = time

330 m/s = 0 + (9.8 m/\(s^2\))t

Solving for t:

t = 330 m/s / 9.8 m/\(s^2\)

t ≈ 33.67 s

Therefore, the minimum time for the rocket to reach the sound barrier without breaking the inside wire is approximately 33.67 seconds.

b) Maximum vertical thrust of the rocket engines:

The maximum vertical thrust of the rocket engines is equal to the total force acting on the rocket, which we calculated earlier:

Maximum vertical thrust = F_total

Maximum vertical thrust ≈ 250,893.6 N

Therefore, the maximum vertical thrust of the rocket engines under these conditions is approximately 250,893.6 N.

c) Distance above the Earth's surface when breaking the sound barrier:

To determine the distance above the Earth's surface when breaking the sound barrier, we can use the following equation of motion:

s = ut + (1/2)at^2

where,

s = distance

u = initial velocity (which is zero)

a = acceleration

t = time it takes to reach the sound barrier (33.67 s).

s = 0 + (1/2)( 9.8 m/\(s^2\))\((33.67 s)^2\)

s = (\(4.9 m/s^2\))(1132.8289 \(s^2\))

s ≈ 5548.1 m

Therefore, the rocket is approximately 5548.1 meters (or 5.55 kilometers) above the Earth's surface when it breaks the sound barrier.

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Answer:

The right approach will be "1.3". A further explanation is given below.

Explanation:

As we know,

In Decibels, the change in sound volume will be:

= \(10log\frac{I_1}{I_2}\)

Now,

According to the question,

⇒ \(1=10 log \frac{I_1}{I_2}\)

By applying cross multiplication and putting the value of log, we get

⇒ \(10^{\frac{1}{10} }=\frac{I_1}{I_2}\)

⇒ \(1.26=\frac{I_1}{I_2}\)

⇒ \(\frac{I_1}{I_2}=1.3\)

Answer:

Non- polar molecules does not have the charges present at the end due to the reason that electrons are finely distributed and those which symmetrically cancel out each other are the non- polar molecules.

In a solution, a polar molecule cannot be mixed with the non-polar molecule.For example, consider water and oil. In this solution, water is a polar molecule whereas oil behaves as a non-polar molecule. These two molecules do not form a solution as they cannot be mixed up.

Answer: 1.02 N/m

Explanation:

To find the spring constant k, we can use Hooke's Law, which states that the force exerted by a spring (F) is proportional to the displacement from its equilibrium position (x). The equation for Hooke's Law is:

F = kx

In this case, the force exerted by the spring (F) is equal to the weight of the mass (mg). The problem provides the weight (63 N) and the displacement (61 m). We can rearrange the equation to solve for k:

k = F/x

Now, we can plug in the given values:

k = (63 N) / (61 m)

k ≈ 1.032 N/m

Rounded to two decimal places, the spring constant k is approximately 1.02 N/m.

Answer:

the resultant wave is the algebraic sum of all the waves reaching that particular point at a given time.

Explanation:

imagine two or three waves reaching a particular particle x at the same time. The particle will vibrate those waves and give out or transmit a resultant wave which is the algebraic sum of the incoming two waves. If both the waves have the same amplitude and phase, the resultant wave will be amplified. However if the waves have the same amplitude and equal but opposite phase then the resultant wave will be a straight line

"A balloon can be charged by rubbing it with your sleeve while holding it in your hand. You can conclude from this that the balloon is an insulator." The correct option is B.

Any substance or material that can keep extra charges from moving around in a space is an insulator.

The insulator maintains its position forever by immobilising any excess charge added to the insulating substance and material.

As any excess charge on the balloon has a tendency to remain where it is placed rather than spreading out as an insulator would, we can say that the balloon is an insulator.

So, option B is the best choice.

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The troposphere part of our atmosphere contains most of tthe weather activity like clouds, rain and snow.

The troposphere is the lowest part of our atmosphere. It is the part where we live on earth.

The altitude of the troposphere is ranges from 8 km to 15 km.

This part also contain most the water vapour.

Thus, the layer A contains the most water vapour and weather activity.

Hence, the option A is the correct answer.

Answer: The scenario violates the second law of thermodynamics.

Explanation: The second law states that heat cannot be converted into work without some loss of usable energy, and that the amount of usable energy in a closed system will always decrease over time. Therefore, the machine described in the scenario cannot exist because it would violate the second law by converting all of the heat into electricity without any loss of usable energy.

Answer:

Explanation:

What is percent error?

The percent error can be defined as the shift or diversion of the expected value from the actual value

let us use the following notations for our calculations

E=percent error

vA=actual value observed

vE=expected value

\(%E= \frac{VA-VE}{VE}*100\\\\%E= \frac{94.3-100}{100}*100\\\\%E= \frac{5.7}{100}*100%\\\\%E= 5.7%\)\(E= \frac{VA-VE}{VE}*100\\\\E= \frac{94.3-100}{100}*100\\\\E= \frac{5.7}{100}*100%\\\\E= 5.7%\)

Therefore the percent error is 5.7%

Answer:

P.E = 1234.8Joules

Explanation:

Given the following data;

Mass = 42kg

Distance = 3m

We know that acceleration due to gravity is equal to 9.8

To find the gravitational potential energy

P.E = mgh

P.E = 42*9.8*3

P.E = 1234.8Joules

A particular small car, with a mass of 920 kg , can accelerate on a level road from rest to 21 m/s (75 km/h ) in 12.0 s. The maximum steepness of a hill is  9.87 degrees.

The term acceleration is defined as any process where the velocity changes. Therefore,velocity is a speed and a direction, there are only two ways for you to accelerate are change your speed or change your direction or change both.

First, find the force pushing the car up a hill as follows:

Force = mass × acceleration

F = ma

Where,

a = change of velocity / change of time

F = mΔv / Δt

F = (920)(21 - 0)/(12.5 - 0)

F = 1545.6 N

By equating this value to the car's y-component:

mg sin (x) = 1545.6

Where,

x = angle of inclination

g = gravity = 9.8 m/s^2

m = mass = 920 kg

(920)(9.8)sin(x) = 1545.6

x = 9.87 degrees.

Thus, the maximum steepness of a hill is 9.87 degrees.

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Your question is incomplete, most probably your question was

a city planner is working on the redesign of a hilly portion of a city. an important consideration is how steep the roads can be so that even low-powered cars can get up the hills without slowing down. a particular small car, with a mass of 920 kg, can accelerate on a level road from rest to 21 m/s (75 km/h) in 12.5 s. using these data, calculate the maximum steepness of a hill.

The relationship is , the square of the period of an orbit is proportional to the cube of its Orbital Radius.

The relationship between orbital radius and period is described by Kepler's Third Law of Planetary Motion, which states that the square of the period of an orbit is proportional to the cube of its semi-major axis.

In other words, if we denote the orbital radius (semi-major axis) by "a" in units of astronomical units (AU) and the period by "T" in years, then:

a³ = (T²)k

where;

For objects orbiting the sun, k is approximately equal to 1.

So, if you know the orbital radius of an object around the sun, you can use Kepler's Third Law to calculate its period, or vice versa.

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Answer:

D

Explanation:

Answer:

A

Explanation:

A 0.842g sample of Hydrogen-3 decays to 0.0526g. Approximately 4.206 half-lives have occurred.

To determine the number of half-lives that have occurred, we can use the decay equation and the concept of exponential decay. The decay equation for radioactive decay is given by:

N(t) = N₀ * (1/2)^(t/T),\((1/2)^(^t^/^T^),\)

where N(t) is the remaining amount of the substance at time t, N₀ is the initial amount, t is the time elapsed, and T is the half-life of the substance.

In this case, we have an initial mass of 0.842g (N₀) and a remaining mass of 0.0526g (N(t)). We can set up the equation as follows:

0.0526g = 0.842g \(* (1/2)^(^t^/^1^2^.^3^2)\),

where t represents the number of half-lives that have occurred.

To solve for t, we can take the logarithm of both sides of the equation:

log(0.0526g/0.842g) = log\([(1/2)^(^t^/^1^2^.^3^2^)\)].

Using the logarithmic property log(\(a^b\)) = b*log(a), we can rewrite the equation as:

log(0.0526g/0.842g) = (t/12.32) * log(1/2).

Simplifying further:

log(0.0526g/0.842g) = (t/12.32) * (-log2),

where log2 is the logarithm base 2.

Now, we can solve for t:

t = (12.32 * log(0.0526g/0.842g)) / (-log2).

Using the given values and performing the calculation, we find:

t ≈ 4.206.

Therefore, approximately 4.206 half-lives have occurred.

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Answer: Foresters. Manage public and private forested lands for economic, recreational, and conservation purposes. May inventory the type, amount, and location of standing timber, appraise the timber's worth, negotiate the purchase, and draw up contracts for procurement.

Explanation: