3 1/5 - 1 4/5 what is the answer i dont get this at all!!!

The number of 6-word sentences is 559902673349120609600000.

There are a total of 26! (26 factorial) possible 6-word sentences that can be made using each of the 26 letters of the alphabet exactly once.

This is because there are 26 options for the first letter, 25 options for the second letter, 24 options for the third letter, and so on until there is only one option left for the last letter.

Therefore, the total number of possible 6-word sentences is 26! = 26 * 25 * 24 * 23 * 22 * 21 * 20 * 19 * 18 * 17 * 16 * 15 * 14 * 13 * 12 * 11 * 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 403291461126605635584000000.

To calculate the number of 6-word sentences, we need to divide the total number of possible sentences by the number of possible arrangements of 6 words.

This is because each 6-word sentence can be arranged in 6! (6 factorial) different ways. Therefore, the number of 6-word sentences is 26! / 6! = 403291461126605635584000000 / 720 = 559902673349120609600000.

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Answer:

-15

Step-by-step explanation:

if its just asking for what number would represent a loss of 15 it would be negative 15

i dont know if there's more to the problem or not

Answer:

-15

Step-by-step explanation:

This is because whatever much water was in the tank is now decreasing by 15, therefore, you can write it as -15,

hope this helps!

Answer:

$7 ; $4 ; $3

Step-by-step explanation:

Given that:

1 player loses and 2 wins

Loser pays each winner amount each winner already has

3 rounds was played

At the end, each player has lost 1 round each and has $8.00

Since each player lost 1 round each, then each player won twice.

Given that the players are A, B and C

Starting from the last round :

Recall; they all have $8 after the last round.

If A lost the last round and pays B and C the amount they already have.

B and C finally have $8, Hence amount A paid B and C = 8/2 = $4 each

Hence, at the end of 2nd round / before last round :

A has ($8 paid + $8 final) = $16

B and C each have $4

End of first round before 2nd round of game:

If B lost, and pays A and C the amount they already have ;

A finally has 16 hence, amount B pays A = 16/2 = $8

Amount B pays C = 4/2 = $2

A = $8

B = $4 + $(8 + 2) = $14

C = $2

Ist round

C will lose :

Amount C pays B = $14 / 2 = $7

Amount C pays A = $8 /2 = $4

Hence, amount C has before round 1:

$7 + $4 + $2 = $13

Hence; Before the game ;

Either of the three players have ;

$7 ; $4 and $13

Answer:

y = ∛(x+3) + 3

Step-by-step explanation:

I plugged each equation into a graphing calculator.

Answer:

t= 33

Step-by-step explanation:

4(8) +t = 65

32+t=65

t=33

Hope this helps!

Step-by-step explanation:

T = hourly pay (8$)

Y = hours worked

T • Y = 32

65-32 = 33$ in tips

Answer:

yes you can simplify it because both the denominators have common denominator of 15.

Answer:

Yes

Step-by-step explanation:

If the denominators are not the same, then you have to use equivalent fractions which do have a common denominator . To do this, you need to find the least common multiple (LCM) of the two denominators. To add fractions with unlike denominators, rename the fractions with a common denominator. Then add and simplify.

Answer

Explanation

Given:

To determine whether the relation defines y as a function of x, we get the domain first.

Based on the given relation, when we plug in x=0, the value would be undefined. So the function domain is x<0 or x>0.

Hence, the interval notation is:

We can use vertical line test to determine if it is a function as shown in the graph below:

As we can see, there's only one point of intersection so the relation defines y as a function of x. Therefore, the answer is:

Function; domain

There are 99 students who speak all three languages: Mandarin, Japanese, and Korean. The minimum number of students who speak all three languages is 99.

The method used to solve this problem is based on set theory, which is a branch of mathematics that deals with the study of sets, their properties, and their relationships with one another. Specifically, the principle of inclusion-exclusion, which is used in this problem, is a counting technique that is often used in combinatorics and probability theory, which are also branches of mathematics.

Let X be the number of students who speak all three languages.

Then we have:

Number of students who speak only Mandarin = 174 - 102 - 81 - X = -9 - X (since there cannot be a negative number of students)

Number of students who speak only Japanese = 139 - 102 - 71 - X = -34 - X (since there cannot be a negative number of students)

Number of students who speak only Korean = 112 - 81 - 71 - X = -40 - X (since there cannot be a negative number of students)

Number of students who speak only one language = -9 - X + (-34 - X) + (-40 - X) = -83 - 3X (since there cannot be a negative number of students)

Total number of students who speak at least one language = 268 - 37 = 231

Therefore, the number of students who speak all three languages is:

Total number of students who speak at least one language - Number of students who speak only one language - Number of students who do not speak any of the three languages

= 231 - (-83 - 3X) - 37

= 297 + 3X

Since the number of students who speak all three languages cannot be negative, we have:

297 + 3X ≥ 0

3X ≥ -297

X ≥ -99

Therefore, the minimum number of students who speak all three languages is 99.

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Answer:

The amount of deposit required is R37,999  for both

The percentage of purchase price for the required deposit is 20%

Therefore, deposit required=20%*R189,995

                                              =R37,999

The balance owed is the outstanding balance after payment of deposit plus the interest, bearing in mind that interest is computed using the simple interest approach

I=PRT

balance after payment of deposit=R189,995-R37,999

                                                       =R151,996

R=13.5% per year

T=48 months and 54 months

Interest on 48 month option=151,996*13.5%*48/12

                                              = R82,077.84

Interest on 54 month option=151,996*13.5%*54/12

                                              = R 92,337.57

The total payment without the initial deposit is the outstanding balance after payment of deposit plus the interest

Total payment for 48 month option=R151,996+R 92,337.57

                                                          =R  244,333.57

Total payment for 54 month option=R151,996+R82,077.84

                                                          =R 234,073.84

                                              Hope it helped!

Answer:

12

Step-by-step explanation:

\(24=2^{3} \times 3 \\ \\ 36=2^{2} \times 3^{2} \\ \\ 96=2^{5} \times 3\)

Hey there!

What is GCF (Greatest Common Factor)?

Basically, the GCF is the biggest number in a data set that all of your numbers share.

What are the factors of the numbers?

24:1, 2, 3, 4, 6, 8, 12, and 24

36: 1, 2, 3, 4, 6, 9, 12, 18, and 36

96: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, and 96

What are the like terms that the numbers share?

1, 2, 3, 4, 6, 8, and 12

What is the biggest number out of the like terms?

12

What is your number?

12

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

Answer:

14.8 minutes

Step-by-step explanation:

4.8 min/12mi= 0.4 min/1 mile driven

multiply the time by the distance:

37mi*(.4min/1mi), mi cancels and you're left with min

37*0.4=14.8 min

Answer: 6

Step-by-step explanation: 10/5=2 2*3=6 which means Mr. Kelly received 4 and Mr. Smith received 6 dollars.

Answer: the mean of City 1 is 68 degrees

Step-by-step explanation:

To find the mean of City 1 first add all of the values then divide by how many there are

in this case---   all numbers listed / 12

= 68.25 degrees

after rounding--- = 68 degrees

The mean of City 1 to the nearest whole degree is 68 degrees.

In mathematics and statistics, the mean refers to the average of a set of values. The mean can be computed in a number of ways, including the simple arithmetic mean (add up the numbers and divide the total by the number of observations), the geometric mean, and the harmonic mean.

Given the question above, we need to find the mean of City 1 to the nearest whole degree.

So,

\(\sf M=\dfrac{65+68+63+55+59+78+70+75+72+75+71+68}{12}\)

\(\sf M =\dfrac{819}{12}\)

\(\sf M=68.3\thickapprox\bold{68}\)

Hence the mean of City 1 to the nearest whole degree is 68 degrees.

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The graph of the solution of the system of equations is in the attachment which is the first graph

A system of equations is a pair of linear equations

Since we have the system of equations

y = -1/3x + 1

y = -2x - 3

We desire to find the graph of the solution of the system of equations. We proceed as follows.

To find the solution of the system of equations, we equate both expressions.

So, y = y

-1/3x + 1 = - 2x - 3

-1/3x + 2x = -3 - 1

5x/3 = -4

x = -4 × 3/5

x = -12/5

x = -2.4

So, substituting x into the first equation, we have that

y = -1/3x + 1

y = -1/3(-12/5) + 1

y = 4/5 + 1

y = 9/5

y = 1.8

So, the solution of the system of equations is the point (-2.4, 1.8)

Next, we plot the graph of both equations

y = -1/3x + 1

When y = 0

0 = -1/3x + 1

-1 = -1/3x

x = 3

When x = 0

y = -1/3(0) + 1

y = 0 + 1

y = 1

So, the intercepts are (3, 0) and (0, 1)

For y = -2x - 3

When y = 0

0 = -2x - 3

3 = -2x

x = -3/2

When x = 0

y = -2(0) - 3

y = 0 - 3

y = - 3

So, the intercepts are (-3/2, 0) and (0, - 3)

So, using the intercepts, we plot the graphs.

The graphs intercept at (-2.4, 1.8) which is the solution

The graph of the solution is in the attachment

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Answer:

15 Inches

Step-by-step explanation:

The Pythagorean Theorem states that: A^2 + B^2 = C^2

By using this, we get 9^2 + 12^2 = 225

Take the square root of 225 = 15

a. The two triangles PQU and PUT are congruent, and hence they have the same area.

b. Area of parallelogram PQRS = 70 cm square.

c. Area of parallelogram PQRS = area of triangle PQT. We know that U is the midpoint of QT.

Therefore, the length of the line segment PU and SQ are equal.

Thus, we can see that triangle PQS and PQU are on the same base PQ and between parallel lines PQ and SR. Area of triangle PQS = Area of triangle PQU + Area of triangle PQT Area of parallelogram PQRS = Area of triangle PQU + Area of triangle PQT { Area of parallelogram is equal to the sum of the areas of two triangles having the same base and between the same parallel lines}Area of parallelogram PQRS = area of triangle PQT.

d. d. To show that:

area of parallelogram PQRS = 4 x area of triangle VUT.

We know that PU and QT are the diagonals of the parallelogram PQRS. As we know that the diagonals of a parallelogram bisect each other.

Therefore, the line segment UV = TV.Now, triangles UTV and VUT are congruent.Area of triangle PQU = 2 × Area of triangle UTV.

Now, area of parallelogram PQRS = 2 × Area of triangle PQU Area of parallelogram PQRS = 2 × 2 × Area of triangle VUT Area of parallelogram PQRS = 4 × Area of triangle VUT.

Therefore, the area of parallelogram PQRS is 4 times the area of triangle VUT.

In the adjoining figure PQRS is a parallelogram and U is the midpoint of QT. Let us consider each question one by one:

a. Relation between the area of triangle PQU and PUT. The area of triangle PQU and PUT is equal. As U is the midpoint of QT, thus, the line segment PQ will also be divided into two equal parts.

Therefore, the two triangles PQU and PUT are congruent, and hence they have the same area.

b. If the area of triangle PUT is 35 cm square, then the area of parallelogram PQRS is 70 cm square Area of triangle PUT = 35 cm square

(Given)Now, both the triangles PQU and PUT have the same area. Thus, area of triangle PQU = 35 cm square Area of parallelogram PQRS = 2 × Area of triangle PQU { As PQU and PUT are congruent triangles, hence they have the same area}

Area of parallelogram PQRS = 2 × 35 cm square

Area of parallelogram PQRS = 70 cm square.

c. To prove that:

Area of parallelogram PQRS = area of triangle PQT. We know that U is the midpoint of QT.

Therefore, the length of the line segment PU and SQ are equal.

Thus, we can see that triangle PQS and PQU are on the same base PQ and between parallel lines PQ and SR. Area of triangle PQS = Area of triangle PQU + Area of triangle PQT Area of parallelogram PQRS = Area of triangle PQU + Area of triangle PQT { Area of parallelogram is equal to the sum of the areas of two triangles having the same base and between the same parallel lines}

Area of parallelogram PQRS = area of triangle PQT.

d. To show that:

area of parallelogram PQRS = 4 x area of triangle VUT.

We know that PU and QT are the diagonals of the parallelogram PQRS. As we know that the diagonals of a parallelogram bisect each other.

Therefore, the line segment UV = TV. Now, triangles UTV and VUT are congruent.Area of triangle PQU = 2 × Area of triangle UTV.

Now, area of parallelogram PQRS = 2 × Area of triangle PQU Area of parallelogram PQRS = 2 × 2 × Area of triangle VUT Area of parallelogram PQRS = 4 × Area of triangle VUT.

Therefore, the area of parallelogram PQRS is 4 times the area of triangle VUT.

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Answer:

Step-by-step explanation:

Answer:

Show image

Step-by-step explanation:

When reflecting on x-axis, the x-values stay the same and y-values change their signs.

When reflecting on y-axis, the x-values change signs and y-values stay the same.

Answer:

A B and C is there

Step-by-step explanation:

Id appreciate if youd give brainliest :)

If you provide the desired standard error value, I can help you calculate the corresponding population standard deviation.

The standard error is a measure of the variability or uncertainty of a sample mean. It is calculated by dividing the population standard deviation by the square root of the sample size. Therefore, if we want the standard error to be smaller, the population standard deviation should be larger.

To determine how large the population standard deviation needs to be, we need to specify a desired standard error value. Without that information, it is not possible to provide a specific answer. The relationship between the population standard deviation and the standard error is inversely proportional, so as the population standard deviation increases, the standard error decreases.

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Answer:

How to solve your problem-  

9 + 3 2 = − 1 2

Step-by-step explanation:

− 9 +  3  2  =  − 1 2

9+3p2=-12

3 2  − 9 =  − 1 2

We have shown that for any given ε > 0, there exists a natural number N such that for all m, n > N, the absolute difference |((2m+1)/m) - ((2n+1)/n)| is less than ε. Therefore, the sequence (2n+1)/n is Cauchy.

Let's define what it means for a sequence to be Cauchy. A sequence is considered Cauchy if, for any arbitrarily small positive number, there exists a natural number N such that for any two terms of the sequence with indices greater than N, the difference between them is less than the chosen positive number. In other words, the terms of a Cauchy sequence get closer and closer together as the sequence progresses. To prove that the sequence (2n+1)/n is Cauchy, we must show that it satisfies the above definition. Let ε be any positive number. Then, for any two terms (2n+1)/n and (2m+1)/m with indices greater than N, we have: |(2n+1)/n - (2m+1)/m| = |(2nm + n - 2mn - m)/(mn)| = |(n-m)/(mn)|.

Since n and m are both greater than N, we can say that |n-m| is less than εN. Also, we know that n and m are both greater than or equal to N, so |mn| is greater than or equal to N^2. Therefore, we have:|(2n+1)/n - (2m+1)/m| < εN/N^2 = ε/N. Since ε is arbitrary, we can choose N to be any natural number greater than 1/ε. Therefore, we have shown that the sequence (2n+1)/n is Cauchy. In conclusion, we have proven that the sequence (2n+1)/n is Cauchy by showing that, for any arbitrarily small positive number, there exists a natural number N such that for any two terms of the sequence with indices greater than N, the difference between them is less than the chosen positive number.

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The required answer is the series ∑ln(6k)4k diverges.

determine whether the series ∑ln(6k)4k converges or diverges.

To analyze the convergence or divergence of the given series, we can use the Ratio Test:

1. Find the ratio of consecutive terms: a_(k+1)/ask
  In this case, a_k = ln(6k)4k.

2. Compute the limit as k approaches infinity: lim(k->∞) (a_(k+1)/a_k)
  a_(k+1) = ln(6(k+1))4(k+1) and a_k = ln(6k)4k

3. Compute the ratio: (ln(6(k+1))4(k+1))/(ln(6k)4k)

4. Find the limit as k approaches infinity: lim(k->∞) [(ln(6(k+1))4(k+1))/(ln(6k)4k)]

5. Apply L'Hopital's rule for indeterminate forms (0/0 or ∞/∞) if needed.

If limit exist and partial sum converges or individual term approaches zero then series is convergent otherwise divergent and further checked by methods explained below.
In this case, however, we notice that the terms in the series do not go to zero, since ln(6k)4k will always grow larger as k increases. This implies that the series does not converge.

Thus, the series ∑ln(6k)4k diverges.

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The general solution to the differential equation y'' + 16y = 0 is y(x) = (c₁ + c₂) * cos(4x)

To solve the differential equation y'' + 16y = 0 using reduction of order, we'll assume a second solution of the form y₂(x) = u(x) * y₁(x), where y₁(x) is a known solution and u(x) is an unknown function.

Given y₁(x) = cos(4x), we'll differentiate it to find y₁'(x) and y₁''(x):

y₁'(x) = -4sin(4x)

y₁''(x) = -16cos(4x)

Now we substitute y₂(x) = u(x) * y₁(x) into the original differential equation:

y'' + 16y = 0

(-16cos(4x)) + 16(u(x) * cos(4x)) = 0

Simplifying the equation:

-16cos(4x) + 16u(x) * cos(4x) = 0

cos(4x)(-16 + 16u(x)) = 0

For this equation to hold for all values of x, we must have (-16 + 16u(x)) = 0.

Solving for u(x):

-16 + 16u(x) = 0

16u(x) = 16

u(x) = 1

Now we have the second solution:

y₂(x) = u(x) * y₁(x)

y₂(x) = 1 * cos(4x)

y₂(x) = cos(4x)

Therefore, the general solution to the differential equation y'' + 16y = 0 is:

y(x) = c₁ * y₁(x) + c₂ * y₂(x)

y(x) = c₁ * cos(4x) + c₂ * cos(4x)

y(x) = (c₁ + c₂) * cos(4x)

Where c₁ and c₂ are arbitrary constants.

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Answer:

Option (4). Rhombus

Step-by-step explanation:

From the figure attached,

Distance AB = \(\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}\)

                     = \(\sqrt{(1-4)^2+(-5+3)^2}\)

                     = \(\sqrt{(-3)^2+(-2)^2}\)

                     = \(\sqrt{13}\)

Distance BC = \(\sqrt{(4-1)^2+(-3+1)^2}\)

                     = \(\sqrt{9+4}\)

                     = \(\sqrt{13}\)

Distance CD = \(\sqrt{(-2-1)^2+(-3+1)^2}\)

                     = \(\sqrt{9+4}\)

                     = \(\sqrt{13}\)

Distance AD = \(\sqrt{(1+2)^2+(-5+3)^2}\)

                     = \(\sqrt{9+4}\)

                     = \(\sqrt{13}\)

Slope of AB (\(m_{1}\)) = \(\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\)

                           = \(\frac{4-1}{-3+5}\)

                           = \(\frac{3}{2}\)

Slope of BC (\(m_{2}\)) = \(\frac{4-1}{-3+1}\)

                            = \(-\frac{3}{2}\)

If AB and BC are perpendicular then,

\(m_{1}\times m_{2}=-1\)

But it's not true.

[\(m_{1}\times m_{2}=(\frac{3}{2})(-\frac{3}{2})\) = -\(\frac{9}{4}\)]

It shows that the consecutive sides of the quadrilateral are not perpendicular.

Therefore, ABCD is neither square nor a rectangle.

Slope of diagonal BD = \(\frac{4+2}{-3+3}\)

                                    = Not defined (parallel to y-axis)

Slope of diagonal AC = \(\frac{1-1}{-1+5}\)

                                    = 0 [parallel to x-axis]

Therefore, both the diagonals AC and BD will be perpendicular.

And the quadrilateral formed by the given points will be a rhombus.

The problem statement describes a surface, given by the equation

x^2/9 + y^2/16 = z, which is a paraboloid opening upward. This surface is then restricted to the region above the rectangle r = [-1, 1] x [-2, 2] in the xy-plane.

We need to find the surface area of this region.

To find the surface area, we will use a double integral over the rectangle r to sum up the surface area of small rectangular patches on the surface. Specifically, we will use the formula for surface area of a graph z = f(x,y) on a rectangle R:

A = ∫∫(1 + (∂z/∂x)^2 + (∂z/∂y)^2)^(1/2) dA

where the integral is taken over the region R and dA = dxdy. We can evaluate this integral using the given equation for the surface and its partial derivatives with respect to x and y. The resulting integral will give us the surface area of the paraboloid above the rectangle r.

The problem statement describes a surface, given by the equation x^2/9 + y^2/16 = z, which is a paraboloid opening upward. This surface is then restricted to the region above the rectangle r = [-1, 1] x [-2, 2] in the xy-plane. We need to find the surface area of this region.

To evaluate the given triple integral, we will use the method of cylindrical coordinates. The region of integration is a rectangle in the xy-plane, and since the surface z=1 is symmetric with respect to the z-axis, it will also be symmetric with respect to the cylindrical axis.

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The value of the test statistic is approximately 2.54.

To find the value of the test statistic, we can use the formula for calculating the test statistic for a single-sample hypothesis test for the population mean. The formula is:

t = (\(\bar x\) - μ) / (s / √n)

Where:

\(\bar x\) is the sample mean,

μ is the population mean,

s is the sample standard deviation,

n is the sample size.

Given information:

Sample mean (\(\bar x\)) = 5.8 ppm

Population mean (μ) = 5.5 ppm

Sample variance (σ^2) = 0.36 ppm^2

Sample size (n) = 26

To calculate the sample standard deviation (s), we take the square root of the sample variance:

s = √(σ^2)

s = √(0.36)

s = 0.6

Now we can calculate the test statistic (t):

t = (5.8 - 5.5) / (0.6 / √26)

t = 0.3 / (0.6 / √26)

t = 0.3 / (0.6 / 5.099)

t = 0.3 / 0.118

t ≈ 2.54 (rounded to two decimal places)

Therefore, the value of the test statistic is approximately 2.54.

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Answer:

wanna hear a dirty joke?

Step-by-step explanation:

Answer:

lol

Step-by-step explanation:

look below

hqhhahahahahahahahhaha

Answer:

y = 13x + 86

Step-by-step explanation:

y−8 =13(x+6); distribute the 13

y - 8 = 13x + 78; now add 8 to both sides

y = 13x + 86; this is the slope intercept form

The rate of return (RoR) needed for an population to increase from its starting balance to its ending balance, providing growth were repopulated at the conclusion of each period of the population life span

To determine an population CAGR:

Divide the population worth at the end of the time by the value it had at the start of the period.

The result should be multiplied by one and divided by the number of years.

The outcome is then reduced by one.

To convert the response into a percentage, multiply by 100.

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