{x, y, z} = { -16/13, -10/13, -28/13}.
Can someone help me answer these sentences?
A 16 inch pendulum swings through an angle of 40. How far does the tip of the pendulum travel in a singles swing
The tip of the pendulum travels 22.33 inches in a singles swing.
A pendulum is a weight suspended from a pivot so that it can swing back and forth under the influence of gravity. Pendulums are commonly used as timekeepers in clocks, but they also have other applications, such as in seismology, where they can be used to detect earthquakes.
Each swing does an angle of 40° in each direction, so we have a total angle of 80°.
Then, we want to get the length of an arc defined by an angle of 80° on a circle with a radius of 16 in, this is:
L = (80°/360°) * 3.14 * (2 * 16 in)
= 22.33 in.
The distance that the tip of the pendulum travels on each swing is 22.33 inches.
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The tip of the pendulum travels approximately 28.3 inches in a single swing through an angle of 40 degrees.
To calculate how far the tip of the pendulum travels in a single swing through an angle of 40 degrees, we will use the formula:
Distance = 2 * PI * Length * (angle / 360)
Where PI is approximately 3.14 and Length refers to the length of the pendulum.
In this case, the length of the pendulum is 16 inches. Therefore, we can substitute these values into the formula:
Distance = 2 * 3.14 * 16 * (40 / 360)
Distance = 2 * 3.14 * 16 * 0.111
Distance = 28.3 inches
Therefore, the tip of the pendulum travels approximately 28.3 inches in a single swing through an angle of 40 degrees.
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Write a system of equations to describe the situation below, solve using elimination, and fill in the blanks.
A boy scout troop is selling Christmas trees at a local tree lot. In the morning, they sold 6 Douglas Fir trees and 16 Noble Fir trees, earning a total of $986. In the afternoon, they sold 6 Douglas Fir trees and 24 Noble Fir trees, earning a total of $1,386. How much does each type of tree cost?
A Douglas Fir costs $_____
and a Noble Fir costs $_______
Solving the system of equations we can see that:
A Douglas Fir costs $33.50_and a Noble Fir costs $47.75__How to write and solve the system of equations?
We can define the variables:
x = price of a Douglas Fir trees
y = price of a Noble Fir trees.
By using the given information we can write:
6x + 16y = 986
6x + 24y = 1368
That is our system of equations
If we take the second equation and we subtract the first one we get.
(6x + 24y) - (6x + 16y) = 1368 - 986
8y = 382
y = 382/8 = 47.75
now that we know the value of y, we can find the value of x using the first equation.
6x + 16y = 986
6x = 965 - 16y
x = (965 - 16y)/6
x = (965 - 16*47.75)/6 = 33.5
So:
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what are the factors to 424,380
Answer:
the factors are: 1, 2, 3, 4, 5, 6, 10, 11, 12, 15, 20, 22, 30, 33, 44, 55, 60, 66, 110, 132, 165, 220, 330, 643, 660, 1286, 1929, 2572, 3215, 3858, 6430, 7073, 7716, 9645, 12860, 14146, 19290, 21219, 28292, 35365, 38580, 42438, 70730, 84876, 106095, 141460, 212190, 424380.
Step-by-step explanation:
A company produces fruity drinks that contain a percentage of real fruit juice. Drink A contains 10% real fruit juice and Drink B contains 15% real fruit juice. How many liters of real fruit juice would be needed to produce 100 liters of Drink A and 250 liters of Drink B? How many liters of real fruit juice would be needed to produce a liters of Drink A and b liters of Drink B?
What is the distance between 5 and -4?
Answer: its 9
Step-by-step explanation:
Think about what you learned about the events during the Progressive time period. Drag and drop the tiles to match the descriptions.
The tiles to match the descriptions are;
Hull house - Neighbourhood assistance.
Muckrakers - Investigative journalists.
Protestants - Temperance movement.
Women's suffrage - Nineteenth amendment.
What is Progressive time period?The Progressive Era, which encompassed the years between the 1890s and the 1920s in US history, was one of intense social and political reform with the goal of advancing the creation of a better society.
Case 1: The settlement home that welcomed newly arrived European immigrants to the United States in 1889 is known as Hull House. There were also social, educational, and artistic initiatives for immigrants in this building.
Case 2: Muckrakers A name used to describe a group of North American journalists in the early 20th century who made public criticisms of: government corruption, abuse of labor is destructive to society and is committed by influential people or institutions of the time.
Case 3: Third, the term "Protestantism" is used to describe a variety of 16th-century religious movements. Because the Catholic Church had a different understanding of the Bible's holy texts, this movement was distinguished by its break with it.
Case 4: The 19th Amendment to the United States Constitution, which was adopted in June 1919, guaranteed every American woman the right to vote.
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The complete question is-
Think about what you learned about the events during the Progressive time period. Drag and drop the tiles to match the
descriptions
Tiles;
Hull House
Muckrakers
Protestants
Women's Suffrage
Pairs;
Investigative journalists
Temperance Movement
Neighbourhood assistance
Nineteenth Amendment
Is it better to buy a used car or a new car? Why
Answer: This depends on how well the used car was taken care of if the used car has no problems wrong with it and is cheaper than the unused car you are looking to buy then the used car is best if you are wanting to save money, but if the used car has problems that cost more to fix then the car cost then you should go with the unused car.
P3: A simply supported beam has a span of 6 m. If the cross section of the beam is as shown below, f. = 35 MPa, and fy = 420 MPa, determine the allowable uniformly distributed service live load on the beam. "5 min 2-20 F om 400 mm MED 3-32 1-2 250 mm
The allowable uniformly distributed service live load on the beam is 3.11 MPa.
To determine the allowable uniformly distributed service live load on the beam, we need to use the formula for bending stress.
The bending stress in a simply supported beam is given by the formula:
σ = (M * y) / I
where σ is the bending stress, M is the bending moment, y is the distance from the neutral axis to the point of interest, and I is the moment of inertia of the cross-sectional area of the beam.
In this case, we need to find the maximum bending moment that the beam can withstand.
The maximum bending moment occurs at the center of the span of the beam, and it is given by:
\(M = (w * L^2) / 8\)
where w is the uniformly distributed load and L is the span of the beam.
To find the maximum allowable uniformly distributed service live load, we need to set the bending stress equal to the yield stress of the material:
σ = fy
where fy is the yield stress of the material.
Now, let's calculate the maximum allowable uniformly distributed service live load.
Given:
Span of the beam (L) = 6 m
Bending stress (σ) = fy = 420 MPa
First, let's calculate the maximum bending moment (M):
\(M = (w * L^2) / 8\)
\(M = (w * 6^2) / 8\)
M = 36w / 8
M = 4.5w
Next, let's set the bending stress equal to the yield stress:
σ = fy
(4.5w * y) / I = 420 MPa
Since we are assuming a rectangular cross section for the beam, the moment of inertia (I) can be calculated as:
\(I = (b * h^3) / 12\)
where b is the width of the beam and h is the height of the beam.
Given:
Width of the beam (b) = 400 mm = 0.4 m
Height of the beam (h) = 250 mm = 0.25 m
Substituting the values into the equation for moment of inertia (I):
\(I = (0.4 * 0.25^3) / 12\)
\(I = 0.004167 m^4\)
Now, let's substitute the values of M and I into the equation for bending stress:
(4.5w * y) / 0.004167 = 420 MPa
We need to solve this equation for w, the uniformly distributed service live load.
To simplify the equation, let's multiply both sides by 0.004167:
4.5w * y = 0.004167 * 420 MPa
4.5w * y = 1.75 MPa
Now, let's solve for w:
w = 1.75 MPa / (4.5 * y)
Since we are looking for the maximum allowable uniformly distributed service live load, we want to find the value of y that gives us the lowest value for w.
The distance from the neutral axis to the point of interest (y) is half the height of the beam (h/2):
y = 0.25 m / 2
y = 0.125 m
Substituting this value of y into the equation for w:
w = 1.75 MPa / (4.5 * 0.125 m)
w = 3.11 MPa
Therefore, the allowable uniformly distributed service live load on the beam is 3.11 MPa.
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Please help solve this, my last two brain cells aren't working rn
Answer:
dude my brain cells are perishing
-2/3 is your answer my guy
have fun
Step-by-step explanation:
CNJ
하
2 15find the zeros of the quadratic polynomial and verify the relationship between the zeros and coefficients T square - 15
Step-by-step explanation:
Here is your answer in the attachment.
Hope it helps :)
find the zeros (x-intercept) and the y-intercept of the function
f(x)=x^2-x-6
find (f o g) (x) and (g o f) (x)
f(x) = 1-x
g(x)= 2x^2-x+4
The expressions for (f o g)(x) and (g o f)(x) are: (f o g)(x) = -2x^2 + x - 3, (g o f)(x) = 2x^2 - 3x + 5
To find the zeros (x-intercepts) of a function, we set f(x) equal to zero and solve for x. Let's find the zeros of the function f(x) = x^2 - x - 6:
f(x) = x^2 - x - 6 = 0
To factor the quadratic equation, we need to find two numbers whose product is -6 and whose sum is -1 (the coefficient of x). The numbers that satisfy these conditions are -3 and 2:
x^2 - 3x + 2x - 6 = 0
x(x - 3) + 2(x - 3) = 0
(x + 2)(x - 3) = 0
Setting each factor equal to zero gives us:
x + 2 = 0 or x - 3 = 0
Solving these equations, we find:
x = -2 or x = 3
So the zeros (x-intercepts) of the function f(x) = x^2 - x - 6 are x = -2 and x = 3.
To find the y-intercept of the function, we set x equal to 0 and evaluate f(x):
f(0) = (0)^2 - (0) - 6 = -6
So the y-intercept of the function f(x) = x^2 - x - 6 is y = -6.
Now let's find (f o g)(x) and (g o f)(x) given the functions f(x) = 1 - x and g(x) = 2x^2 - x + 4.
(f o g)(x) represents the composition of functions f and g, which means we substitute g(x) into f(x):
(f o g)(x) = f(g(x)) = f(2x^2 - x + 4)
Substituting the expression for g(x) into f(x):
(f o g)(x) = 1 - (2x^2 - x + 4)
Simplifying:
(f o g)(x) = 1 - 2x^2 + x - 4
(f o g)(x) = -2x^2 + x - 3
(g o f)(x) represents the composition of functions g and f, which means we substitute f(x) into g(x):
(g o f)(x) = g(f(x)) = g(1 - x)
Substituting the expression for f(x) into g(x):
(g o f)(x) = 2(1 - x)^2 - (1 - x) + 4
Simplifying:
(g o f)(x) = 2(1 - 2x + x^2) - 1 + x + 4
(g o f)(x) = 2 - 4x + 2x^2 - 1 + x + 4
(g o f)(x) = 2x^2 - 3x + 5
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PLEASE HELP ME PLEAAASWEEEE
Please help me
five subtracted from the product of 6 and a number is less than or equal to 29. Write as an inequality
Answer:
6x-5 ≤ 29
Step-by-step explanation:
Let translate each part of the sentence into an equation or expression.
1. "five subtracted from the product of 6 and a number"
Lets say the "number" is x. The product of 6 and a number would be: 6x'five subtracted from" would be -5So the "five subtracted from the product of 6 and a number" would be 6x-5.2. "is less than or equal to 29"
using just math symbols, this would be ≤ 293. Assemble the two expression into an equation
Combine parts 1 and 2 into an equation.
6x-5 ≤ 29
=============
Extra
6x-5 ≤ 29 can be simplified:
6x ≤ 29+5
6x ≤ 36
x ≤ 6
Helppppppppp meeeeee
Answer:
y=-1
Step-by-step explanation:
y=-1 just shows the y value which means its just a horizontal line which is parallel to the x axis.
Enter the number that makes the equation true?
Answer:
800
Step-by-step explanation:
happy to help
Step-by-step explanation:
You'll need to add up all the numerators and the answer you'll get is 7226. Then you'll subtract 7226 from 7826 and you'll get 600. The missing value is 600.solve for y.
-38=7y+17-12y
Answer:
y=11
Step-by-step explanation:
Im so 100 percent sure but thats mostly the right answer
Answer:
y = 11
Step-by-step explanation:
-38 = 7y + 17 - 12y
-38 = -5y + 17
-17 -17
-55 = -5y
divide both sides by -5
11 = y
or y = 11
Hope this helps!!!
solve/answer the question and help me understand this question please
thank you to all user that will help me!
Answer:
5.25 m
Step-by-step explanation:
A diagram can help you understand the question, and can give you a clue as to how to find the answer. A diagram is attached. The problem can be described as finding the sum of two vectors whose magnitude and direction are known.
__
understanding the directionIn navigation problems, direction angles are specified a couple of different ways. A bearing is usually an angle in the range [0°, 360°), measured clockwise from north. In land surveying and some other applications, a bearing may be specified as an angle east or west of a north-south line. In this problem we are given the bearing of the second leg of the walk as ...
N 35° E . . . . . . . 35° east of north
Occasionally, a non-standard bearing will be given in terms of an angle north or south of an east-west line. The same bearing could be specified as E 55° N, for example.
the two vectorsA vector is a mathematical object that has both magnitude and direction. It is sometimes expressed as an ordered pair: (magnitude; direction angle). It can also be expressed using some other notations;
magnitude∠directionmagnitude cis directionIn the latter case, "cis" is an abbreviation for the sum cos(θ)+i·sin(θ), where θ is the direction angle.
Sometimes a semicolon is used in the polar coordinate ordered pair to distinguish the coordinates from (x, y) rectangular coordinates.
__
The first leg of the walk is 3 meters due north. The angle from north is 0°, and the magnitude of the distance is 3 meters. We can express this vector in any of the ways described above. One convenient way is 3∠0°.
The second leg of the walk is 2.5 meters on a bearing 35° clockwise from north. This leg can be described by the vector 2.5∠35°.
vector sumThe final position is the sum of these two changes in position:
3∠0° +2.5∠35°
Some calculators can compute this sum directly. The result from one such calculator is shown in the second attachment:
= 5.24760∠15.8582°
This tells you the magnitude of the distance from the original position is about 5.25 meters. (This value is also shown in the first attachment.)
__
You may have noticed that adding two vectors often results in a triangle. The magnitude of the vector sum can also be found using the Law of Cosines to solve the triangle. For the triangle shown in the first attachment, the Law of Cosines formula can be written as ...
a² = b² +o² -2bo·cos(A) . . . . where A is the internal angle at A, 145°
Using the values we know, this becomes ...
a² = 3² +2.5² -2(3)(2.5)cos(145°) ≈ 27.5373
a = √27.5373 = 5.24760 . . . . meters
The distance from the original position is about 5.25 meters.
_____
Additional comment
The vector sum can also be calculated in terms of rectangular coordinates. Position A has rectangular coordinates (0, 3). The change in coordinates from A to B can be represented as 2.5(sin(35°), cos(35°)) ≈ (1.434, 2.048). Then the coordinates of B are ...
(0, 3) +(1.434, 2.048) = (1.434, 5.048)
The distance can be found using the Pythagorean theorem:
OB = √(1.434² +5.048²) ≈ 5.248
Using the partial fractions technique, the function f(x) = 68x+168/ x^2+2x-24 can be written as a sum of partial fractions
We can express f(x) as a sum of partial fractions as: f(x) = (-10 / (x + 6)) + (78 / (x - 4))
To write the function f(x) = \((68x + 168) / (x^2 + 2x - 24)\) as a sum of partial fractions, we first need to factor the denominator:
\(x^2 + 2x - 24 = (x + 6)(x - 4)\)
So we can write:
f(x) = (68x + 168) / ((x + 6)(x - 4))
Now we can use the method of partial fractions to express f(x) as a sum of simpler fractions:
f(x) = A / (x + 6) + B / (x - 4)
where A and B are constants that we need to find. To do this, we can multiply both sides of the equation by the common denominator (x + 6)(x - 4):
(68x + 168) = A(x - 4) + B(x + 6)
Expanding and collecting like terms, we get:
68x + 168 = (A + B) x + (6B - 4A)
Since this equation holds for all values of x, we can equate the coefficients of x and the constant terms separately:
68 = A + B
168 = 6B - 4A
Solving these two equations simultaneously, we get:
A = -10
B = 78
Therefore, we can express f(x) as a sum of partial fractions as:
f(x) = (-10 / (x + 6)) + (78 / (x - 4))
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Death Valley National Park, in California and Nevada, is the site of the lowest elevation in the Western Hemisphere. Bad water Basin in the park is about 86 meters below sea level.
Write the equation of the line that passes through the points (−3,9) and (1,−6).
Answer:
y=-3.75x-2.25
Step-by-step explanation:
Step 1: Find the slope (m) using the Slope Formula, Y2-Y1/X2-X1
(-6)-(9)/(1)-(-3) = -15/4 = -3.75
Step 2: Find the Y-intercept (b) using the Slope Intercept Formula, y=mx+b
9=-3.75*(-3)+b
9=11.25+b
b=9-11.25
b=-2.25
Step 3: Plug in your slope (m) and Y-intercept (b) values into the Slope Intercept Formula, y=mx+b
y=-3.75x-2.25
Step 4: Plug your X values into the formula, you should get your Y values after solving
y=-3.75(-3)-2.25=11.25-2.25=9 (-3, 9)
y=-3.75(1)-2.25=-3.75-2.25=-6 (1, -6)
Helpcppdpdppd nessxbshzj
Answer:
dear hope it helps you...
what is the answer to 6a-7-5a-8
Answer:
a-15
Step-by-step explanation:
=> 6a-7-5a-8
=> 6a-5a-7-8
=> a -15
a-15
Step-by-step explanation:
6a-7-5a-8
6a-5a-8-7
a-15
what is the last digit of 3 with a power of 2011
So to find any last digit of 3^2011 divide 2011 by 4 which comes to have 3 as remainder. Hence the number in units place is same as digit in units place of number 3^3. Hence answer is 7.
If a and b must be positive integers, what is the largest integer n such that 13a + 18b = n has no solutions?
Answer:
Any integer that is not integer multiple of 234 is not a solution.
Step-by-step explanation:
We are required to find the largest integer n such that 13a + 18b = n has no solution, where a and b are integers.
13a + 18b = n
For a = 1, b = 0
n = 13
For a = 0, b = 1
n = 18
So, for the solution sets (1, 0), (0, 1), n will always have a solutions.
Consider n = 13 × 18 = 234
This means that any integer that is not integer multiple of 234 is not a solution.
144 divided by 19 using long division and explanation/prove it
i have a test and im studying but cant understand dis one
Answer:
Step-by-step explanation:
Write an equation for a line perpendicular to y=2x+2 and passing through the point (6,-2)y =
The equation of the line is given as,
\(y=2x+2\)According to the slope-intercept form, the equation of a line with slope 'm' and y-intercept 'c', is given by,
\(y=mx+c\)Comparing with the given equation, the slope of the given line is,
\(m=2\)Theorem: The product of two slopes of two perpendicular lines is -1 always.
Let the slope of the perpendicular line be (m'), and 'b' be the y-intercept. Then, it follows that,
\(\begin{gathered} m^{\prime}\cdot m=-1 \\ m^{\prime}\cdot(2)=-1 \\ m^{\prime}=\frac{-1}{2} \end{gathered}\)The equation of this perpendicular line is given by,
\(\begin{gathered} y=m^{\prime}x+b^{\prime} \\ y=(\frac{-1}{2})x+b^{\prime} \end{gathered}\)Given that the perpendicular lines pass through the point (6,-2), so it must also satisfy its equation,
\(\begin{gathered} -2=(\frac{-1}{2})(6)+b^{\prime} \\ -2=-3+b^{\prime} \\ b^{\prime}=-2+3 \\ b^{\prime}=1 \end{gathered}\)Substitute this value back in the equation of the perpendicular line,
\(y=\frac{-1}{2}x+1\)Thus, the equation of a line perpendicular to the given line and passing through the given point is obtained as,
\(y=\frac{-1}{2}x+1\)Tina's soccer practice is 60 minutes long. 20% of the time is spent warming up. How
many minutes does Tina spend warming up?
Pick the model that represents the problem.
0%
10% 20%
30%
40%
50%
60%
70%
80%
90% 100%
0
?
60
0%
10%
20%
30%
40%
50%
60%
70%
80%
90% 100%
0
20
?
How many minutes does Tina spend warming up?
Answer:
12 minutes are spent warming up.
Step-by-step explanation:
Multiply 0.2 by 60. You get 12. 20% of 60 is 12.
Anthony downloaded 8 total items onto his phone. The games he purchased were $2.00 each and songs were $1.00. How many of each did he buy after spending $11.00?
Answer:
he downloaded 9 songs and 1 game
Step-by-step explanation (3x2= 6) (5x1= 5) (3+5= 8) $6.00 + $5.00 = $11.00
so add 3 items to the games that would be $6.00 so 5 items would remain put the rest of those items into the music that would be 5x1 =$5.00. So $6.00+$5.00= $11.00 so the answer is $11.00.
assume you purchased some corporate stock 4 years ago for $7,500. You received quarterly dividends of 875 ; your dividends total $1,200 (16 dividend checks ×$75=$1,200). You sold the stock today for $8,050. 6. The PV is $8,050 because that is the amount you received today (in the present). (T or F ) 7. $1,200 represents which variable (PV, PMT, or FV)? 8. What is the FV amount? Unit 12.2 Financial calculators 9. When is it not necessary to clear the TVM registers? 10. By setting our "periods per year" register at 1 we must enter the periodic rate in the i-register. (T or F)
6. False. The present value (PV) is the initial investment or the amount invested in the stock, which is $7,500, not the amount received today ($8,050).
7. $1,200 represents the variable PMT (Payment). It represents the total dividends received over the four-year period.
8. The future value (FV) amount is $8,050, which is the amount received from selling the stock today.
9. It is not necessary to clear the TVM (Time Value of Money) registers when the calculations are completed, and you don't need to perform any further calculations.
10. True. When the "periods per year" register is set to 1, the periodic rate (interest rate) should be entered directly into the i-register as a decimal value, such as 0.05 for 5%.
Therefore, the PV is not $8,050 but $7,500, representing the initial investment. The variable $1,200 represents the PMT (payment) or the total dividends received. The FV amount is $8,050, the selling price of the stock. Clearing the TVM registers is not necessary after completing calculations, and when "periods per year" is set to 1, the periodic rate is entered directly into the i-register.
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