2weeks convert to hours​

Answer:

Option D. 9.8 N

Explanation:

From the question given above, the following data were:

Mass of object = 1 kg

Normal force (R) =.?

The normal force experienced by the object can be obtained by using the following formula:

Normal force (R) = mass (m) × acceleration due to gravity (g)

R = mg

Mass of object = 1 kg

Acceleration due to gravity (g) = 9.8 m/s²

Normal force (R) =.?

R = mg

R = 1 × 9.8

R = 9.8 N

Thus, the normal force experienced by the object is 9.8 N

The ranges of forces required to open a wine bottle with bottle opener as per shown in the figure is 25.1 N to 45.57 N

In physics, a strain is an effect with the ability to alter the velocity of an object. A force can influence a surplus object's velocity to alter or rise. To describe force, a pushing or a pulling makes intuitive sense. Forces have both size and direction, since they are vector quantities. It is measured in newtons using the SI system (N). The symbol for force is the letter F.

Balancing moment (r x F) about left end:

Net torque = (9 mm x F(cork) - ((9 + 70) F) = 0

F = ( 9 / 79) F(cork)

F = 0.114 F(cork)

Range of F(cork) = 220 N to 400 N

F = [0.114(220) to 0.114(400)] = 25.1 N to 45.57 N

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a. The velocity must remain constant to keep the ratio of frequency and wavelength in check. The wave speed is determined by the properties of the medium through which the wave travels, and is independent of the frequency and wavelength of the wave.

c. 0.35 m. The wavelength can be calculated using the formula: wavelength = wave speed / frequency. Plugging in the given values, we get wavelength = 4.5 m/s / 25 Hz = 0.18 m/Hz = 0.35 m (rounded to two decimal places).

Answer:

question  1: force

question 2: velocity or inertia

question 3: 0

The magnitude of the force exerted on this object is 1.2 Newton.

Given the following data:

In Science, the impulse that is experienced by an object is always equal to the change in momentum of the object, due to the force acting on an object.

Mathematically, impulse is given by this formula:

\(Impulse = change\;in\;momentum\\\\Force \times time = m \Delta V\)

Substituting the given parameters into the formula, we have:

\(Force \times 10=12\\\\Force =\frac{12}{10}\)

Force = 1.2 Newton.

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- The resistance of the first resistor (R₁) is 12 Ω.

- The electromotive force (EMF) of the battery is 18 V.

- The internal resistance of the battery is 12 Ω.

To solve the given problem, we can apply Kirchhoff's laws and Ohm's law to determine the resistance of the first resistor (R₁) and the electromotive force (EMF) and internal resistance of the battery.

Let's start by calculating the resistance of the first resistor (R₁):

1. Apply Ohm's law to find the voltage drop across the external circuit:

  V = I * R

  V = 1 A * 6 Ω

  V = 6 V

2. The voltage drop across the external circuit is equal to the EMF minus the voltage drop across the internal resistance of the battery:

  V = E - Ir

  6 V = E - (1 A * r)   (where r is the internal resistance of the battery)

3. We also know that the EMF of the battery is the sum of the voltage drops across each cell in the battery:

  E = 6 cells * 3 V/cell

  E = 18 V

4. Substitute the value of E in the equation from step 2:

  6 V = 18 V - r

  r = 12 Ω

Therefore, the resistance of the first resistor (R₁) is 12 Ω.

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equal in magnitude but opposite in direction

Take intoaccount that for points A, D, and B, almost all the mechanical energy is potential gravitational energy. For the lowest point the potential energy is least and then the kinetic energy is maximum.

Then, you can conclude that for point C the kinetic energy is maximum.

If drag and friction forces are included, then, for point E (that is, after the roller coaster is traveled all the trajectory shown) part of the mechanical energy has been dissipated.

For point E the mechanical energy is minimum.

Answer:

Explanation:

To find the net electric flux through a closed surface, we need to apply Gauss's law:

Phi_E = Q_enclosed / epsilon_0

where Phi_E is the electric flux, Q_enclosed is the net charge enclosed by the closed surface, and epsilon_0 is the electric constant.

Let's consider a spherical closed surface of radius R enclosing the charges. We can divide the surface into two regions: inside and outside the sphere.

For the charges inside the sphere, the net charge enclosed is:

Q_enclosed = +1.00 nC - 3.00 nC = -2.00 nC

Therefore, the electric flux through the inner surface of the sphere is:

Phi_E_inside = Q_enclosed / epsilon_0 = (-2.00 nC) / epsilon_0

For the charge outside the sphere, the net charge enclosed is:

Q_enclosed = +2.00 nC

Therefore, the electric flux through the outer surface of the sphere is:

Phi_E_outside = Q_enclosed / epsilon_0 = (2.00 nC) / epsilon_0

The net electric flux through the closed surface is the sum of the electric flux through the inner and outer surfaces:

Phi_E_net = Phi_E_inside + Phi_E_outside = (-2.00 nC) / epsilon_0 + (2.00 nC) / epsilon_0

= 0

Therefore, the net electric flux through the closed surface is zero. This means that the total amount of electric field lines entering the surface is equal to the total amount of electric field lines leaving the surface. This result is consistent with Gauss's law, which states that the net electric flux through a closed surface is proportional to the net charge enclosed by the surface. In this case, since the net charge enclosed is zero, the net electric flux is also zero.

The normal derivative of the electric field is given by \(\frac{1}{E}\times\frac{dE}{dn}=-(\frac{1}{R_{1}}+\frac{1}{R_{2}} )\).

The Gauss law is really applied in integral form, E da = 0.

then there is no contained charge. prior to thinking about the three-dimensional issue. Think about the similar circumstance in two dimensions.

Gauss laws therefore state that if you place a curve Gaussian box adjacent to the charged conductor's surface at a position where the radius of curvature is R.

\(0=\int {E.x} \, da=E_{top}\triangle a_{top} -E_{bottom}\triangle a_{bottom}\)

\(\triangle a_{top}\) and \(\triangle a_{bottom}\) are the top and bottom portions of the box, respectively.

using \(\triangle a_{top}\) =(R+E)d∅× dz and,

\(\triangle a_{bottom}\)=Rd∅× dz gives

\(E_{bottom}=E_{top}(1+\frac{E}{R})\)

This enables us to compute.

\(\frac{dE}{dn}= \lim_{E \to 0} \frac{E_{top}-E_{bottom}}{E} =\lim_{E \to 0}(\frac{-E_{top}}{R})= \frac{-E_{top}}{R}\)

Taking into consideration that Flop is the same as E ,this may be written as

\(\frac{1}{E}\times\frac{dE}{dn}=-\frac{1}{R}\)

This is a two-dimensional expression analogue.

Returning to the 3D issue, we will use the aforementioned methods. However, this time around, the top and bottom

\(\triangle a_{top}\)=\((R_{1}+E)\times(R_{2}+E)\times\)dФ

\(\triangle a_{bottom}\)=\(R_{1}R_{2}\)dФ

Now putting these in equation

\(E_{bottom}=E_{top}(1+\frac{E}{R_{1} })(1+\frac{E}{R_{2} })\)

which gives,

\(\frac{dE}{dn}= \lim_{E \to 0} \frac{E_{top}-E_{bottom}}{E} =\lim_{E \to 0}(-E_{top}(\frac{1}{R_{1} }+\frac{1}{R_{2} }+\frac{E}{R_{1} R_{2} })=-E_{top}(\frac{1}{R_{1} }+\frac{1}{R_{2} })\)

Rearranging the equation gives,

\(\frac{1}{E}\times\frac{dE}{dn}=-(\frac{1}{R_{1}}+\frac{1}{R_{2}} )\)

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When light encounters an obstacle such as a wall, it can be either absorbed, transmitted, reflected, or refracted. The way in which light is blocked depends on the characteristics of the obstacle and the properties of the light.

For example, a solid object such as a wall absorbs light, meaning that the energy of the light is transferred to the object, causing the object to heat up. This can result in the object becoming warmer, such as a wall or floor in direct sunlight, or it can result in the object changing its chemical properties, such as with photosensitive materials like photographic film.

Reflection occurs when light bounces off an object, changing the direction of the light. This can result in a mirror image or a diffuse reflection, depending on the characteristics of the object.

Refraction occurs when light passes through an object, changing the direction of the light. This can occur when light passes through transparent materials such as water or glass.

Finally, light can also be blocked by scattering, which occurs when light is dispersed in many different directions as it encounters small particles in the atmosphere, such as dust or water droplets. This is why the sky appears blue during the day, as the shorter blue wavelengths of light are scattered more than the longer wavelengths of red and orange light.

Answer:

Acceleration is 2.55m/s²

Explanation:

Force(F)=mass of object(m) ×acceleration(a)

in the scenario above,a force of 15N is used to push the box and because the floor is not having a smooth surface,frictional force(8N) will oppose the 15N used to push the box thereby decreasing the acceleration. so the actual force moving the box is 7N.

Force =Normal Force - Frictional Force

F= 15N - 8N

F= 7N

therefore the 7N is the actual force causing the box to move.

To find the acceleration,insert the mass of the box and the actual force into the formula (F=m×a)

F=m×a

7N =2.75kg × a

make a the subject by dividing both sides of the equation by 2.75kg.

7/2.75 = (2.75×a)/2.75

a= 7/2.75

therefore a= 2.55m/s²,where a is the Acceleration.

Answer: Because temperature is a measure of the average kinetic energy of the atoms or molecules in the system. The zeroth law of thermodynamics says that no heat is transferred between two objects in thermal equilibrium; therefore, they are the same temperature.

Explanation:9 (- _ -)

Answer:

340 kg

Explanation:

F = ma

Rearranging the equation to solve for mass (m):

m = F/a

Substituting the given values:

m = 850 N / 2.5 m/s^2

m = 340 kg

Answer:

Photovoltaic detection is a technique that converts light into electrical energy. It is a process that involves the use of a photovoltaic cell, which is made up of semiconductor materials, to generate an electric current when exposed to light.

The photovoltaic cell absorbs the photons of light, which then knock electrons out of their orbits, creating a flow of electricity. The amount of electricity produced is proportional to the intensity of the light. The photovoltaic cell is commonly used in solar panels to generate electricity from sunlight. The efficiency of the photovoltaic cell is dependent on several factors, including the type of semiconductor material used, the purity of the material, and the thickness of the cell.

The photovoltaic cell has many applications, including in solar power generation, telecommunications, and remote sensing. The technique of photovoltaic detection is an important area of research, as it has the potential to provide a clean and renewable source of energy that can help mitigate climate change.

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The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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Answer:

1) 1256.02 kJ

2)76.20 lb

3)2336.30 lb

Explanation:

The kinetic energy of a 4,934 pound pickup truck going 55 mph is:

First, we need to convert the mass of the truck from pounds to kilograms:

4,934 lb = 2,236.17 kg

The kinetic energy is given by the formula: KE = 0.5 * m * v^2

where m is the mass of the object and v is the velocity.

Plugging in the values, we get:

KE = 0.5 * 2,236.17 kg * (55 mph)^2 = 1,256,024.47 J

Converting to kJ, we get:

KE = 1,256,024.47 J / 1000 = 1256.02 kJ

A 4,992 lb car has a rolling resistance coefficient of 0.015. How much force, in lb, will it take to push this car at 30 mph?

The force required to overcome rolling resistance is given by the formula:

F = Crr * W

where Crr is the rolling resistance coefficient and W is the weight of the car.

First, we need to convert the weight of the car from pounds to Newtons:

4,992 lb = 22,612.88 N

Plugging in the values, we get:

F = 0.015 * 22,612.88 N = 339.19 N

Converting to pounds, we get:

F = 339.19 N / 4.45 = 76.20 lb

The 2022 Hummer EV comes with a 212 kWh battery. How much will this battery weigh in lbs?

We cannot directly convert from kilowatt-hours to pounds, as they are two different units. However, we can use the energy density of the battery to estimate its weight.

Assuming an energy density of 200 Wh/kg for the battery, we can calculate the mass of the battery as:

212 kWh * 1000 Wh/kWh / 200 Wh/kg = 1060 kg

Converting to pounds, we get:

1060 kg * 2.205 lb/kg = 2336.30 lb

Answer:

The magnification of an image is equal to the ratio of the image height to the object height.

The magnitude of the resultant force, F = 1,190.3 acting at a direction X = 13.35°.

The resultant force on the rocket is calculated thus:

The 513N thrust is resolved into vertical and horizontal components;

Horizontal component: 513N cos(32.4°) = 433.14 N

Vertical component: 513N sin(32.4°) = 274.88 N

Total forward force on the rocket = 725 N + 433.14 N = 1,158.14 N

Total force at right angles:

0 + 274.88 N = 274.88 N

The resultant force (F) is then given as follows:

F² = a² + b²

F² = (1158.14 N)² + (274.88 N)²

F = √1,416,847.27

F = 1,190.3

To find the direction:

tan X 274.88 N / 1,158.14 N

X = tan⁻¹ 0.237346089419241

X = 13.35°

Therefore, the magnitude of the resultant force, F = 1,190.3 acting at a direction X = 13.35°.

In conclusion, the resultant force is obtained by resolving the forces into vertical and horizontal components.

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Answer:

Renewable energy minimizes carbon pollution and has a much lower impact on our environment. And it's having its moment in the sun. "Giving more New Yorkers access to renewable energy can allow them to reduce their own energy bills while reducing stress on the grid and demand for fossil fuel power.

Answer:

0.045 J

Explanation:

From the question,

The elastic potential energy stored in a spring is given as,

E = 1/2ke²...................... Equation 1

Where E = elastic potential energy, k = spring constant, e = compression.

Given: k = 100 N/m, e = 0.05-0.02 = 0.03 m

Substitute these values into equation 1

E = 1/2(100)(0.03²)

E = 50(9×10⁻⁴)

E = 0.045 J

Hence the right option is 0.045 J

Two carts connected by a 0.05 m spring hit a wall, compressing the spring to 0.02 m.The spring constant k is 100 N/m.

What is the elastic potential energy stored from the spring’s compression?

Answer: 0.045 J

Answer:

it deflects most of the solar wind, whose charged particles would otherwise strip away the ozone layer that protects the Earth from harmful ultraviolet radiation

The recoil speed of the catapult is 6.96 m/s.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given parameters:

Mass of the catapult : M = 1400 kg.

Mass of the boulder: m = 75 kg.

Velocity of the rock: v = 130 m/s.

We have to find: recoil speed of the catapult: V = ?

From the principle of conservation of linear momentum:

momentum of the boulder = - momentum of the  catapult

⇒ mv = - MV

⇒ v = -mv/M = - (75 × 130)/1400 m/s = - 6.96 m/s

Negative sign indicates recoil of the catapult is in opposite direction of motion of the boulder.

So, the recoil speed of the catapult is 6.96 m/s.

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The electric field in the direction is 4.5×10^5 N/C.

We denote the inner and outer cylinders with subscripts i and o, respectively.

(a) Since r_i<r=4.0cm<r_o,  

E(r)= λ_i / 2πϵ_0r = 5.0×10^−6C/m / 2π(8.85×10^−12C^2/N.m)(4.0×10^−2m) = 2.3×10^6 N/C

(b) The electric field E(r) points radially outward.

(c) Since r>r_o,

E(r=8.0cm)= λ_i+λ _o / 2πϵ_0r = 2π(8.85×10^−12 C/N.m 2)(8.0×10^2m)

5.0×10^−6C/m−7.0×10^−6C/m =−4.5×10^5 N/C

or ∣E(r=8.0cm)∣=4.5×10^5 N/C.

(d) The minus sign indicates that E(r) points radially inward.

An electric field is a physical phenomenon that arises from the presence of charged particles. When a charged particle, such as an electron or a proton, is placed in a region of space, it creates an electric field that permeates that space. The electric field is a vector field, meaning it has both magnitude and direction, and is represented by electric field lines. The strength of the electric field is proportional to the magnitude of the charge that created it and inversely proportional to the distance from the charge.

Electric fields play a crucial role in many aspects of physics and engineering, including electronics, electrostatics, and electromagnetism. They are responsible for many everyday phenomena, such as the attraction and repulsion of magnets, the operation of electric motors and generators, and the functioning of electronic devices like smartphones and computers.

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9.8 N is the magnitude of the force that maintains circular motion acting on the puck.

32.53 m/sec is the linear speed of the puck.

The term "force" has a specific meaning in science. At this level, it is quite acceptable to refer to a force as a push or a pull. An item does not have a force inside of it or within it. Another item applies a force to another. The concept of a force is not restricted to living or non-living entities. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

As we know, from free body diagram, when the system is in equillibrium, the force acting on the puck on the table is as follows:

When the air puck of mass is revolving round the circle, then the tension (T) in the top string and the bottom of the string is same.

F = T

F = 9.8 N

Now, calculate the velocity of the puck:

From the given data, the air puck moves in a circular path. Hence, the tension in the top string is equal to the centripetal force acting on the puck.

Thus, the expression for the tension in the top string is as follows:

T = mv² / R

The velocity of the puck is as follows:

Mg = mv² / R

v² = MgR / m

v² = (2.7 × 9.8 × 1.2 ) / 0.030

v² = 1058.4

v = \(\sqrt{1058.4}\)

v = 32.53 m/sec

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Answer:

the phenomenon of the system supports the principle of conservation of momentum.

Explanation:

The law of conservation of momentum says that:

Initial Momentum = Final Momentum

So, first we calculate initial momentum of the system:

Initial Momentum  = m₁u₁ + m₂u₂

where,

m₁ = mass of car = 600 kg

m₂ = mass of van = 400 kg

u₁ = Initial Speed of Car

For initial speed of car, we use:

Vf = Vi + at

Vf = 0 m/s + (0.2 m/s²)(60 s)

Vf = u₁ = 12 m/s

u₂ = Initial Speed of Van = 0 m/s

Therefore,

Initial Momentum  = (600 kg)(12 m/s) + (400 kg)(0 m/s)

Initial Momentum  = 7200 Ns   --------------- equation (1)

Now, for the final momentum:

Final Momentum  = m₁v₁ + m₂v₂

where,

v₁ = v₂ = Final Speed of Car and van (both are locked) = 7.2 m/s

Therefore,

Final Momentum = (600 kg)(7.2 m/s) + (400 kg)(7.2 m/s)

Final Momentum = 7200 Ns   ------------- equation (2)

Comparing equation (1) and (2):

Initial momentum = Final Momentum

Hence, the phenomenon of the system supports the principle of conservation of momentum.

Answer:

16+15+19= ??

Am just messign with u lol

Explanation:

anwser s 19 inches

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