2(NaHCO3) how many atoms of hydrogen

Therefore, 9.49 grams of water is expected in the given 3.21 g sample of CuSO4 • 10H2O.

To determine the number of water molecules in the given hydrate, CuSO4 • 10H2O, we'll need to find out the molar mass of the compound and the molar mass of water to make a comparison.

The molar mass of CuSO4 • 10H2O is calculated as:

CuSO4 → 159.6 g/mol10H2O → 180.16 g/mol (18.016 g/mol × 10)CuSO4 • 10H2O → 159.6 g/mol + 180.16 g/mol

= 339.76 g/mol (rounded to three significant figures)

Thus, we can see that the molar mass of CuSO4 • 10H2O is 339.76 g/mol.

We know that this hydrate consists of ten molecules of water, each having a molar mass of 18.016 g/mol (which is the same as the molar mass of water), and one molecule of CuSO4 with a molar mass of 159.6 g/mol.

Therefore, the number of moles of water in the sample is:

(10 × 18.016 g/mol) ÷ 339.76 g/mol = 0.527 moles

So, the mass of water is equal to its molar mass multiplied by the number of moles.

The mass of water is:

0.527 mol × 18.016 g/mol = 9.49 g

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A problem that can be tested using the scientific method is the association between greenhouse gases and global warming, in this case, the dependent variable is the temperature, the independent variable is the amount of gas and the controlled variables may be the presence of non-greenhouse gases.

A controlled variable in an experiment is any conditions manipulated by the researcher that allow us to make comparisons regarding the change in the dependent variable.

Therefore, with this data, we can see that controlled variables in an experiment are useful to determine the extension of the change in the dependent variable.

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a.  the  balanced chemical equation for the reaction is :

\(C_2H_4 + 3O_2\)-> 2\(CO_2\) + 2\(H_2O\)

b.  the pressure in the container isfound to be  44.94 atm.

a. The balanced chemical equation for the combustion of ethylene

\(C_2H_4 + 3O_2\)-> 2\(CO_2\) + 2\(H_2O\)

b.

PV = nRT

P is the pressure

V is the volume (10.0 liters)

n is the number of moles of CO2

R is the ideal gas constant = 0.0821 L·atm/(mol·K))

T is the temperature in Kelvin =- 20°C = 293.15 K)

the number of moles of \(C_2H_4\):

27.0 g of\(C_2H_4\)* (1 mol / 28.05 g )

= 0.963 mol  of \(C_2H_4\)

We have that 2 moles of  carbon dioxide  are produced for every mole of Ethylene gas, the number of moles of carbon dioxide   produced is twice the number of moles of Ethylene gas :

0.963 mol of Ethylene gas  * (2 mol CO2 / 1 mol of Ethylene gas)

= 1.926 mol

P * 10.0 L = 1.926 mol  * 0.0821 L·atm/(mol·K) * 293.15 K

P = (1.926 mol * 0.0821 L·atm/(mol·K) * 293.15 K) / 10.0 L

P = 44.94 atm

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4-iodobenzoic acid can be separated into cis and trans isomers. This statement is false.

Cis isomer refers to isomers in which two particular atoms or groups of atoms are on the same side of a bond. When two groups are present on opposite sides of the bond, the isomer is referred to as a trans isomer. Cis and trans are referred to as geometric isomers, and they only exist in compounds with specific bonds or functional groups.

The compound 4-iodobenzoic acid is an aromatic acid, and because it lacks a functional group with a double bond, it cannot have cis and trans isomers.  

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Four solutions are made by dissolving a certain amount of each of the four substances in 450. g water. The substance that is added to water in the greatest amount is the one with the lowest molar mass.

The freezing point is the temperature at which the vapor pressure of a liquid equals the atmospheric pressure exerted on the liquid. This temperature represents the point at which the liquid turns into a solid.

Ionic compounds dissolve in water and dissociate into cations and anions. Therefore, they are able to change the freezing point of the solvent. The freezing point depression can be calculated using the following equation:

ΔT = Kf·m

where ΔT is the freezing point depression, Kf is the freezing point depression constant for the solvent (water in this case), and m is the molality of the solution.

The molality of a solution is defined as the number of moles of solute per kilogram of solvent. The amount of solute that is added to the solution can be calculated using the following formula:

m = n / (m solvent · w solvent)

where m is the molality of the solution, n is the number of moles of solute, m solvent is the molar mass of the solvent, and w solvent is the mass of the solvent in kilograms.

The four solutions have the same freezing point, which means that they have the same molality.

Therefore, the amount of solute that is added to the solution can be calculated using the following formula:

m = n / (m solvent · w solvent)

where m is the molality of the solution, n is the number of moles of solute, m solvent is the molar mass of the solvent, and w solvent is the mass of the solvent in kilograms.

The molality of the solution is the same for all four solutions, so the amount of solute added to the solution is inversely proportional to the molar mass of the solute.

Therefore, the substance that is added to water in the greatest amount is the one with the lowest molar mass.

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1. Acetylocholine binds sodium channels that are activated by ligands.

2. When sodium ions get inside the cell, an action potential starts.

3. The sarcolemma and T tubules carry an action potential.

From the sarcoplasmic reticulum, calcium ions are released in step 4.

5. Because calcium and troponin are bound together, tropomyosin moves.

6. Actin is bound by myosin.

7. Using ATP energy, myosin cross-bridges swing and detach in alternating fashion.

Actin is still being moved towards the M-line by myosin filaments in position 8.

Muscle contractions are regulated by calcium ions, troponin and tropomyosin proteins, AND the act of skeletal muscles contracting.

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The molecular weight (W) of the polyatomic ideal gas is equal to the temperature (T) divided by the volume (V) calculated as 0.123 kJ/(K).

The molecular weight (W) of the polyatomic ideal gas can be determined using the ideal gas equation:

PV = mRT

where:

P = pressure of the gas (in this case, it is not given)

V = volume of the gas (in this case, it is not given)

m = mass of the gas (in kilograms)

R = ideal gas constant (0.123 kJ/(kg.K))

T = temperature of the gas (in Kelvin)

To calculate the molecular weight (W), we need to find the value of m. Since the pressure and volume are not provided, we can rearrange the ideal gas equation as follows:

m = PV / (RT)

Now, let's assume a hypothetical situation where we have 1 kg of the polyatomic ideal gas. In this case, the mass (m) would be equal to 1 kg.

Substituting the values into the equation:

m = (1 kg) * V / (0.123 kJ/(kg.K) * T)

Here, we can see that the units of kilograms (kg) cancel out, leaving us with:

1 = V / (0.123 kJ/(K))

To isolate V, we multiply both sides of the equation by 0.123 kJ/(K):

0.123 kJ/(K) = V

Now, we have the volume (V) in cubic meters. The molecular weight (W) can be calculated using Avogadro's law, which states that equal volumes of gases, at the same temperature and pressure, contain an equal number of molecules.

To calculate the molecular weight (W), we need to determine the number of moles (n) of the gas. The number of moles can be found using the equation:

n = PV / (RT)

However, since the pressure and volume are not provided, we cannot calculate the number of moles directly. Instead, we can make use of the molar mass (M) of the gas, which is the mass of 1 mole of the gas.

The molar mass (M) is related to the molecular weight (W) as follows:

M = W / 1000

Since we assumed a mass of 1 kg earlier, the molar mass (M) can be calculated as:

M = (1 kg) / n

Substituting the value of n from the equation above:

M = (1 kg) / (PV / (RT))

M = RT / PV

Now, substituting the value of R (0.123 kJ/(kg.K)) and rearranging the equation:

M = (0.123 kJ/(kg.K)) * T / (0.123 kJ/(K) * V)

The units of kJ cancel out, leaving us with:

M = T / V

Using the value of V we calculated earlier (0.123 kJ/(K)), we can determine the molecular weight (W) of the polyatomic ideal gas.

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Answer:

96 Zr

Explanation:

just took the quiz and that was the right answer

The equilibrium composition of CO₂ is determined to be 0.59 kmol.

To solve this problem, we can use the ideal gas law and the equilibrium constant expression for the reaction:

CO + 1/2O₂ ⇌ CO₂

Given the initial number of moles of CO and O₂, we can set up an ICE (Initial, Change, Equilibrium) table. Let's assume that x kmol of CO is consumed and converted to CO₂. Then, the change in the number of moles for each species is:

CO: -x kmol

O₂: -0.5x kmol

CO₂: +x kmol

At equilibrium, the number of moles of CO is (2 - x) kmol, O₂ is (3 - 0.5x) kmol, and CO₂ is x kmol. The equilibrium constant expression can be written as:

Kp = (P_CO₂) / (P_CO * P_O₂(1/2))

Given Kp = 16.461 and the pressure conditions, we can substitute the equilibrium partial pressures into the expression:

16.461 = x / ((2 - x) * (3 - 0.5x)(1/2))

Solving this equation yields x ≈ 0.59 kmol.

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Answer:

1 grams Hydrogen is equal to 0.992122546977 mole.

Explanation:

Hydrogen is equal to 0.992122546977 mole.

Answer:

Explanation:

Here, we want to get the new volume of the gas without changing the pressure

From Charles' law, we know that temperature and volume are directly proportional

We have that as:

From the question, we have the given values (we have to convert the given temperature values to Kelvin by adding 273.15 K) as:

V1 is 7.6 L

V2 = ?

T1 is 8 + 273.15 = 281.15 K

T2 is 22 + 273.15 = 295.15 K

Substituting the values, we have that as follows:

The research titled "Stratospheric Ozone in the 21st Century: The Chlorofluorocarbon Problem" by F.S. Rowland was published in the journal Science in 1991. The study's significance is evident in the way it paved the way for global action on the depletion of the ozone layer.

The study outlined the link between chlorofluorocarbons (CFCs) and the depletion of the ozone layer in the stratosphere. These chemicals have long been utilized in refrigerants, air conditioning systems, foam insulation, and various industrial applications. They have been shown to destroy ozone molecules when they rise to the stratosphere, allowing ultraviolet radiation to penetrate the Earth's atmosphere. Rowland's research proved beyond a doubt that human activity is significantly affecting the ozone layer, resulting in an increased risk of skin cancer, blindness, and other problems associated with exposure to UV radiation.

The research is vital in the sense that it helped to initiate international agreements, such as the Montreal Protocol, aimed at phasing out the use of CFCs. These agreements have been instrumental in lowering the production and use of CFCs, resulting in a reduction in the depletion of the ozone layer. As a result, the world has benefited from a decrease in the risks associated with exposure to UV radiation. In conclusion, Rowland's research was groundbreaking in the sense that it confirmed the link between CFCs and ozone depletion, providing a basis for a global reaction to this critical problem.

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Explanation:

a) 0.4998 mol

b) 0.249 mol

Fungal digestive enzymes are most likely to appear within the food source soon thereafter. Mycelium has a porous structure made up of tubular filaments known as hypha.

Every single mycelium fiber is made up of an array of slender cells that are separated by cross walls, known as septum, and are all enclosed within the same cell wall. Tiny holes in the septum allow nutrients, water, and other small molecules, as well as mycelium fiber, to move quickly from cell to cell. Mycorrhizae are symbiotic relationships that fungi and plants form. Fungi colonize the root system of a host plant, increasing water and nutrient absorption, while the plant provides carbohydrates formed by photosynthesis to the fungus.

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Answer:

Explanation:

Fungal haustoria are most likely to appear in the food source shortly after a mycelium invades an untapped source of dead organic matter.

What do fungal haustoria do?

A specialized fungal hypha that breaks through the wall of a plant cell and expands inside of it creates a haustorium.

The haustorium is encircled by an extrahaustorial membrane, a thickened version of the plant cell plasma membrane, rather than being situated inside the cytoplasm of the plant cell.

Are haustoria produced by fungi?

All significant divisions of fungi create haustoria.

There are various types of haustoria.

Generally, the fungus increases the surface area in contact with the host plasma membrane upon penetration and releases enzymes that disintegrate the cell walls, allowing for a greater potential transfer of organic carbon from the host to the fungus.

What kind of structure is a haustoria?

Haustoria are incredibly diverse plant parasite structures.

Haustoria are visible on exposed roots in root parasites.

At the location of contact between the parasite and the host, they manifest as swollen tissue.

In dodders, haustoria are structures that connect the host and parasite and have the appearance of pegs or suction cups.

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The density of the gas is 1.534 g/L.

Equation 1 can be derived from the ideal gas equation, (pressure)(volume)=(mol)(gas constant)(temperature).

Let: P= pressure, V=volume, n=mol of gas, R=gas constant, T=temperature, m=mass of gas, MW= molecular weight of the gas, and ρ=density

Substitute n= m / MW, and ρ= m/V to the ideal gas equation

PV = (mRT) / MW

P = (ρRT) / MW (Equation 1)

The MW of gas can be determined from the given density, pressure, and temperature of 1.96 g/L, 1.00 atm, and 0 deg C, respectively.

MW = [(1.96 g/L)*(0.08205746 L atm/ mol K)(273 K)] / 1 atm

MW = 43.907 g/mol

Then, the density of the gas can be calculated for the given pressure, and temperature of 0.855 atm, and 25 deg C, respectively.

ρ = [ (0.855 atm)*( 43.907 g/mol)] / [(0.08205746 L atm/ mol K)*(25+273 K)]

ρ = 1.534g/L

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The type of information given by IR spectroscopy is the functional groups in a molecule. Option (b).

IR spectroscopy is commonly used to identify the presence of specific functional groups in a molecule based on the characteristic absorption patterns of infrared radiation.

It provides valuable information about the types of bonds and functional groups present in a compound, such as hydroxyl groups (OH), carbonyl groups (C=O), amino groups (NH2), and many others. It does not provide information about the number of isotopes, mass, or the number of hydrogen atoms in a molecule.

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The partial pressure of CH4 in the mixture is 239 torr.

To find the partial pressure of CH4 in the mixture, we need to use the mole fraction of CH4.

First, we need to find the moles of each component in the mixture. The molar mass of CH4 is 16.04 g/mol, so:

moles of CH4 = 90.0 g / 16.04 g/mol = 5.61 mol

The molar mass of Ar is 39.95 g/mol, so:

moles of Ar = 10.0 g / 39.95 g/mol = 0.250 mol

The total number of moles in the mixture is:

total moles = moles of CH4 + moles of Ar = 5.61 mol + 0.250 mol = 5.86 mol

Now we can find the mole fraction of CH4:

mole fraction of CH4 = moles of CH4 / total moles = 5.61 mol / 5.86 mol = 0.957

Finally, we can use the mole fraction to find the partial pressure of CH4 using Dalton's Law of Partial Pressures:

partial pressure of CH4 = mole fraction of CH4 x total pressure

partial pressure of CH4 = 0.957 x 250 torr = 239 torr

Therefore, the partial pressure of CH4 in the mixture is 239 torr.

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The combinations in which a precipitate will form are: 25.0 mL of 1.00 x 10⁻⁵ M Co(NO₃)₂ and 75.0 mL of 5.00 x 10⁻¹ M Na₂S; and 150 L of 0.0250 M BaCl₂ and 1.25 L of 0.0140 M Pb(NO₃)₂

Precipitation is a chemical reaction that occurs when two soluble salts are mixed to form an insoluble compound. The compound that forms a solid is known as the precipitate. Therefore, to determine if a precipitate is going to form when two soluble salts are combined, we need to look at the solubility of each salt. If one salt is soluble and the other is insoluble, a precipitate will form. If both salts are soluble, no precipitate will form.

Take a look at the following combinations:

1. 25.0 mL of 1.00 x 10⁻⁵ M Co(NO₃)₂ and 75.0 mL of 5.00 x 10⁻¹ M Na₂S: CoS will form as a precipitate.

2. 500 mL of 7.50 x 10⁻⁴ M AlCl₃ and 100.0 mL of 1.70 x 10⁻⁵ M Hg₂(NO₃)₂: No precipitate will form in this combination.

3. 150 L of 0.0250 M BaCl₂ and 1.25 L of 0.0140 M Pb(NO₃)₂: Ba(NO₃)₂ and PbCl₂ will form. PbCl₂ will precipitate as it is insoluble in water.

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Both aluminium and iodine form chlorides, Al₂Cl₆ and I₂Cl₆, Cl atoms is attached as "bridging". I₂Cl₆ has a shape of square planar shape.

What is mean by square planar shape?

In chemistry, the stereochemistry (spatial arrangement of atoms) that certain chemical compounds is made is described as square planar molecular geometry. The atoms in molecules with this shape are located at the corners, as the name implies.

One of the geometries that characterizes a particular atom hybridization is square planar. One core atom is surrounded by bonds to four additional atoms in a planar configuration. This shape produces dsp2 hybridization, which is hybridization. An atom's 3d-orbital energy is either comparable to 3s and 3p energy or to 4s and 4p energy.

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Answer:

Action force and Reaction force

Explanation:

The action force which is the balanced rock pushing down due to gravity and the reaction force pushing the equal amount of force. These two things are stated in Newtons third law, where he states that "Whenever one object exerts a force on a second object, the second object exerts an equal and opposite force on the first." Also, he states that "all forces acts in pairs," meaning that every force exerted, there is an opposite force on the first

Gravity, as a fundamental force of nature, is influenced by several factors. The following are some of the key factors affecting gravity:

Answer:

If you want the first option you need 2.5M.

If you want the second, you will end up with 120ml so your starting solution is:

0.5x (120/20) = 3.0M

This assumes that there’s no loss of volume on mixing. To remove that uncertainty, start with the 20ml of acid and add water, mixing, till you get the right volume.

The mass of nickel deposited at the electrode can be calculated using the following formula:
Mass of nickel = (Current x Time x Atomic weight of Ni) / (Number of electrons x Faraday's constant x Current efficiency)


In this problem, Ni²⁺ is reduced to Ni(s) at the electrode. A current of 1.25 amperes is passed for 72 hours, and we need to calculate the mass of nickel deposited at the electrode. The atomic weight of nickel is 58.69 g/mol.

We can use the formula mentioned above to calculate the mass of nickel deposited at the electrode. Number of electrons involved in the reduction of Ni²⁺ to Ni(s) is 2, and Faraday's constant is 96,485 C/mol. As per the question, we assume 100% current efficiency.

Substituting the values in the formula:

Mass of nickel = (1.25 A x 72 hours x 58.69 g/mol) / (2 x 96,485 C/mol x 1)

Mass of nickel = 122.34 g

Therefore, the mass of nickel deposited at the electrode is 122.34 g.
To summarize, we can use the formula, (Current x Time x Atomic weight of Ni) / (Number of electrons x Faraday's constant x Current efficiency), to calculate the mass of nickel deposited at the electrode. In this problem, the mass of nickel deposited at the electrode is 122.34 g, assuming 100% current efficiency.

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Answer:

i think it's will difference from compund to compund

This relationship between pressure and volume is known as Boyle’s law. A law that states that at constant temperature, the volume of a fixed amount of a gas is inversely proportional to its pressure., after its discoverer, and can be stated as follows: At constant temperature, the volume of a fixed amount of a gas is inversely proportional to its pressure.