2C2H2(g) + 5O2.  4CO2(g) + 2H2O





What is the theoretical yield of CO2 if 24. 96 grams of C2H2 are reacted with excess oxygen?

Answer:

314mL OR 0.314L

Explanation:

this requires the dilution formula M1V1 = M2V2 where

M1 = initial concentration

V1 = initial volume

M2 = final concentration

V2 = final volume

In this case, we are solving for V1 where M1 = 5.65M, V1 = 250.0 mL, and M2 = 4.50M

Plugged into the equation we get:

(5.65M)(250.0mL) = (4.50M)V2

divide both sides by 4.50M and it becomes (M cancel)

V2 = 314mL

The mole fraction of the solvent in the solution is approximately 0.982.

To calculate the mole fraction of the solvent in a solution, we need to determine the number of moles of the solute and the solvent.

Given;

Mass of solute (KCl) = 0.3 kg

Molality of the solution = 2 mol/kg

Volume of the solvent (water) = 45 ml

Density of water = 1 g/ml

Molar mass of water = 18 g/mol

First, let's convert the mass of the solute to moles:

Moles of solute (KCl) = (Mass of solute) / (Molar mass of KCl)

Moles of solute (KCl) = (0.3 kg) / (74.55 g/mol) [Molar mass of KCl

= 74.55 g/mol]

Moles of solute (KCl) = 0.00402 mol

Next, let's convert the volume of the solvent to mass:

Mass of solvent (water) = (Volume of solvent) × (Density of water)

Mass of solvent (water) = (45 ml) × (1 g/ml)

Mass of solvent (water) = 45 g

Now, we calculate the mole fraction of the solvent;

Mole fraction of solvent = (Moles of solvent)/(Total moles)

Total moles = Moles of solute (KCl) + Moles of solvent (water)

Total moles = 0.00402 mol + (Mass of solvent / Molar mass of water)

Total moles = 0.00402 mol + (45 g / 18 g/mol)

Total moles = 0.00402 mol + 2.5 mol

Total moles = 2.50402 mol

Mole fraction of solvent = (Moles of solvent) / (Total moles)

Mole fraction of solvent = (45 g / 18 g/mol) / 2.50402 mol

Mole fraction of solvent = 0.982

Therefore, the mole fraction of solvent in the solution will be 0.982.

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Answer:

Thermal Energy

Explanation:

The thermal energy of an object increases as the temperature increases, causing atoms and molecules to move faster. When the temperature decreases, the thermal energy decreases, causing atoms and molecules to move slower. Another term for thermal energy is heat energy.

The molar mass of calcium hydroxide, Ca(OH)₂ is 74.10 g/mol. The moles of the K₂SO₄ is 0.086 mol . The grams of the glucose is 639 g.

The molar mass of the Calcium oxide , Ca(OH)₂ is :

Ca(OH)₂ = 40 + 2( 15.99 + 1 )

              = 74.10 g/mol

The moles of the  K₂SO₄ in the 15 g of the  K₂SO₄ :

Moles = mass / molar mass

Moles = 15 / 174.25

Moles = 0.086 mol

The moles of the glucose, C₆H₁₂O₆ = 3.55 mol

The mass of the glucose = moles × molar mass

                                         = 3.55 × 180

                                         = 639 g

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To make a 48% solution from 25 g of solute, you would need approximately 52.08 mL of solvent.

To calculate the volume of solvent required, we need to consider the mass percent of the solution. The mass percent is defined as the ratio of the mass of solute to the total mass of the solution, multiplied by 100. In this case, the mass percent is given as 48%.

To find the volume of solvent, we can set up a proportion using the mass percent. Let's assume the total volume of the solution is V mL. We can set up the following equation:

(25 g)/(V mL) = (48 g)/(100 mL)

Cross-multiplying and solving for V, we get:

25V = 48 * 100

V = (48 * 100)/25

V ≈ 192 mL

Therefore, you would need approximately 192 mL of the solvent to make a 48% solution from 25 g of solute.

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Answer:

As a metal, it is (was) widely used for its malleability, ductility, and its resistance to corrosion, making popular in older plumbing systems. Strangely, even as a metal, it is not a good conductor of electricity.

Answer:

CO₃²¯(aq) + 2H⁺(aq —> H₂O(l) + CO₂(g)

Explanation:

The net ionic equation for sodium carbonate (Na₂CO₃) and sulfuric acid (H₂SO₄) can be obtained as follow:

Na₂CO₃ + H₂SO₄ —>

In solution, Na₂CO₃ and H₂SO₄ will dissociate as follow:

Na₂CO₃(aq) —> 2Na⁺(aq) + CO₃²¯(aq)

H₂SO₄(aq) —> 2H⁺(aq) + SO₄²¯(aq)

Na₂CO₃(aq) + H₂SO₄(aq) —>

2Na⁺(aq) + CO₃²¯(aq) + 2H⁺(aq) + SO₄²¯(aq) —> 2Na⁺(aq) + SO₄²¯(aq) + H₂O(l) + CO₂(g)

Cancel out the spectator ions (i.e Na⁺ and SO₄²¯) to obtain the net ionic equation.

CO₃²¯(aq) + 2H⁺(aq —> H₂O(l) + CO₂(g)

The energy transferred on the object is 1000 Joules.

Given:

An object on which a constant force of 100 N was applied to displace it over a distance of 10 meters.

To find:

The energy transfer occurs on the object.

Solution

The force applied on the object = F = 100 N

The displacement of the object = d = 10 m

The energy transferred on the object or work done is given by:

\(W = F\times d\\W=100 N\times 10 m = 1,000 J\)

The energy transferred on the object is 1000 Joules.

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Answer:

lead

Explanation:

Answer:

Lead is poisonous.

Explanation:

The compounds ranked by their expected lattice energy from greatest to least are: MgF_2, MgCl_2, MgBr_2, MgI_2.

Lattice energy is a measure of the energy released when gaseous ions come together to form an ionic solid. It is influenced by factors such as ion charge and ion size. In general, as the charges of the ions increase, the lattice energy also increases. However, when comparing ions with the same charge, the size of the ions becomes the determining factor.

In the given compounds, the common ion is Mg_2+ (with a +2 charge), while the anions are F-, Cl-, Br-, and I-. Among these anions, fluoride (F-) has the smallest ionic radius, followed by chloride (Cl-), bromide (Br-), and iodide (I-). Smaller ions have a higher charge density, meaning the positive charge is concentrated in a smaller space, leading to stronger attractive forces between the ions.

Therefore, based on ion size, the compound with the greatest expected lattice energy is MgF_2, followed by MgCl_2, MgBr_2, and MgI_2, with MgF_2 having the strongest bond and MgI_2 having the weakest bond.

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The alkyl halide that reacts the fastest in an SN2 reaction is Chloromethane (d).

SN2 (substitution nucleophilic bimolecular) reactions involve the attack of a nucleophile on an alkyl halide, resulting in the displacement of the halide ion. The rate of an SN2 reaction is determined by several factors, including steric hindrance and the nature of the leaving group.

In this case, Chloromethane (d) reacts the fastest in an SN2 reaction. The primary reason for this is the absence of steric hindrance. Chloromethane has the smallest alkyl group (methyl) attached to the halide atom, making it the least bulky among the given options. Bulky alkyl groups can hinder the approach of the nucleophile, slowing down the reaction. In contrast, Chloromethane's compact structure allows the nucleophile to access the carbon atom more easily, facilitating a faster reaction rate.

Additionally, the nature of the leaving group plays a role in SN2 reactions. Chlorine is a good leaving group, as it can stabilize the negative charge on the carbon atom through resonance. This stability enhances the reaction rate.

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The solutions ranked from the highest [H₃O⁺] (1) to the lowest [H₃O⁺] (5) are as follows:

1. [OH⁻] = 4.35 × 10⁻² M

2. pH = 1.05

3. [H₃O⁺] = 3.16 × 10⁻⁴ M

4. pOH = 4.0

5. pOH = 7.0

What are hydronium ions?

Hydronium ions (H3O+) are formed when a water molecule (H2O) combines with an additional proton (H+). They are commonly found in aqueous solutions and play a crucial role in acid-base chemistry. Hydronium ions are responsible for the acidic properties of solutions with a pH less than 7.

[H₃O⁺] represents the concentration of hydronium ions (H₃O⁺) in a solution, which is a measure of acidity. A higher concentration of hydronium ions indicates a more acidic solution, while a lower concentration indicates a less acidic or more basic solution.

Comparing the given values, we can determine the rankings:

1. The highest [H₃O⁺] is represented by the concentration of hydroxide ions ([OH⁻]) at 4.35 × 10⁻² M. This solution is highly basic, resulting in a low concentration of hydronium ions.

2. pH = 1.05 represents a strongly acidic solution, so it is ranked second.

3. [H₃O⁺] = 3.16 × 10⁻⁴ M represents a moderately acidic solution, ranking third.

4. pOH = 4.0 indicates a concentration of hydroxide ions ([OH⁻]) at 10⁻⁴ M, which corresponds to a moderately basic solution, making it fourth in the ranking.

5. pOH = 7.0 represents a highly basic solution with a low concentration of hydronium ions, ranking it as the solution with the lowest [H₃O⁺].

Therefore, the solutions are ranked in the order provided: 1, 2, 3, 4, 5.

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A. The activation energy for the souring of milk is approximately 56757 J/mol.

B. The equilibrium expression shows the concentrations of the products (N₂O and H₂O) raised to their respective stoichiometric coefficients.

A. To calculate the activation energy for the souring of milk, we can use the Arrhenius equation:

ln(k2/k1) = (Ea/R) * (1/T1 - 1/T2)

Where:

k1 is the rate constant at temperature T1

k2 is the rate constant at temperature T2

Ea is the activation energy

R is the gas constant (8.314 J/(mol*K))

T1 and T2 are the temperatures in Kelvin

Given the data:

T1 = 28 degrees Celsius = 28 + 273.15 = 301.15 K

t1 = 4.0 hours = 4.0 * 3600 seconds

T2 = 5 degrees Celsius = 5 + 273.15 = 278.15 K

t2 = 48 hours = 48.0 * 3600 seconds

Using the ratio of rate constants and rearranging the equation, we have:

ln(k2/k1) = (Ea/R) * (1/T1 - 1/T2)

ln(t2/t1) = (Ea/R) * (1/T1 - 1/T2)

ln(48.0 * 3600 / 4.0 * 3600) = (Ea/8.314) * (1/301.15 - 1/278.15)

Solving for Ea, we get:

Ea ≈ (ln(12.0) * 8.314) / (1/301.15 - 1/278.15)

Ea ≈ 56757 J/mol

B. The equilibrium expression for the reaction NH₄NO₃(s) → N₂O(g) + 2H₂O(g) is:

K = [N₂O] * [H₂O]²

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Answer:

Melting point

Explanation:

it melting

Both Technician A and Technician B are correct in their statements about octane ratings and the use of regular and high octane gasoline.

Technician A is correct because most modern engines are designed to use regular grade gasoline, which has an octane rating of 87. This is the most commonly used gasoline and it is suitable for most engines.

Technician B is also correct because high octane gasoline, which has an octane rating of 91 or higher, should only be used when an engine was designed to use it. High octane gasoline is more expensive and is not necessary for most engines. However, some high-performance engines require high octane gasoline to prevent engine knocking and to achieve optimal performance.

Therefore, both Technician A and Technician B are correct in their statements about octane ratings and the use of regular and high octane gasoline.

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Reaction C would likely proceed the fastest, as H2O is a very strong nucleophile, capable of reacting quickly with the substrate. Reaction A would likely proceed the slowest, as NN=OH is a weaker nucleophile than H2O and is less likely to react quickly with the substrate.  

In nucleophilic substitution reactions, the rate of the reaction depends on the stability of the substrate, the strength of the nucleophile, and the ability of the leaving group to leave. In general, the reaction rate increases as the nucleophile strength increases and the leaving group ability decreases.

Given the three reactions:

A. CH2=CH2 + Br- → CH2=CHBr- + H+ (NN=OH is the nucleophile)

B. CH2=CH-CO2- + H2O → CH2=CHOH + CO32- (N=CH2 is the nucleophile)

C. CH2=CH2 + H2O → CH2=CHOH + H3O+ (N=H2O is the nucleophile)

Reaction C would likely proceed the fastest, as H2O is a very strong nucleophile, capable of reacting quickly with the substrate. Reaction A would likely proceed the slowest, as NN=OH is a weaker nucleophile than H2O and is less likely to react quickly with the substrate. The rate of reaction B would likely fall in between A and C, as the nucleophile N=CH2 is moderately strong. However, without more information on the reaction conditions and the specific reactants involved, it is difficult to say for certain which reaction would be the fastest or slowest.

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The statement in which La Niña affect the climate of the Pacific Ocean is "The cold water sinks deeper into the ocean."

La Niña is a climate phenomenon that depicts the cooling of surface ocean waters along the coast of South America's tropical west coast.

The average weather in a certain place over a longer length of time is referred to as climate.

The jet stream moves northward and weakens across the eastern Pacific as a result of La Niña. The South experiences warmer and drier weather than usual during La Nia winters. The North and Canada are wetter and colder than the rest of the country. The seas off the Pacific coast are cooler and contain more nutrients than typical during La Niña.

Water in the eastern Pacific is colder than typical because to La Niña. El Niño might cause the water to be warmer than usual in the same place. During La Niña years, drought-stricken areas are drenched, while El Niño years are drenched.

Hence the correct option is 2.

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Answer:

A weather station

Explanation:

A weather station measures the wind speed and humidity of a specific area. GIS gives visual data that scientists can analyze, GPS gives the exact location of a weather phenomenon, and a hammer and lens allow scientists to study Earth’s geologic features.

Answer:

Isotope 2

Explanation:

Isotope 2 is the most abundant. Its percent abundance is 78.68% which is the largest percentage, and therefore the most common of the isotopes presented.

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Of the four solutes added to a solvent, the one with the smallest surface area (2 mm2) will dissolve the fastest.

The surface area or particle size especially affects the rate of solubility.

The greater the surface area (smaller particle size) the faster it dissolves. This is evidenced by the fact that a sugar cube dissolves more slowly than granulated sugar.

The rate at which a solute dissolves depends on the size of the solute particles.

Dissolution is a surface phenomenon, since it depends on solvent molecules colliding with the external surface of the solute.

A given amount of solute dissolves faster when it is ground into small particles, rather than large chunks, because more surface area is exposed.

In addition to solute surface area, temperature and pressure influence the balance of intermolecular forces between solvent and solute, and the change in entropy that accompanies solvation, thus changing solubility.

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In the photosynthesis lab, blowing into the tubes with phenol red serves a specific purpose. Phenol red is a pH indicator that changes color based on the acidity or basicity of the solution it is in. When the solution is more acidic, it turns yellow, and when it is more basic, it turns pink.

During photosynthesis, plants release oxygen gas as a byproduct, which makes the solution in the tubes more basic. Blowing into the tubes helps to mix the solution and ensure that the phenol red is evenly distributed throughout. This makes it easier to see the color change when oxygen is being produced by the plant through photosynthesis.
Blowing into the tubes also helps to remove any excess carbon dioxide in the solution, which can interfere with the pH indicator and lead to inaccurate results. By removing the excess carbon dioxide, the phenol red can more accurately reflect the changes in pH that occur during photosynthesis.
Overall, blowing into the tubes with phenol red in the photosynthesis lab is an important step in ensuring accurate and reliable results. It helps to mix the solution and remove any interfering factors, allowing for a clear and easy-to-interpret visual representation of the plant's photosynthetic activity.

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Answer:

a proton turns into an atom that goes kabloey into fission products and other neutrons.

Explanation:

The percentage (w/v) of dextrose in the solution is approximately 1.9817%. To determine the percentage (w/v) of dextrose in a solution with a given osmolarity, we need to calculate the amount of dextrose present in 100 mL of the solution.

First, we convert the osmolarity from mosmol/L to mosmol/100 mL:

100 mosmol/L = 100 mosmol/100 mL

Next, we calculate the number of moles of dextrose present in 100 mL of the solution:

Number of moles = Osmolarity (in mosmol/100 mL) / 1000

Number of moles of dextrose = 100 mosmol/100 mL / 1000 = 1 mosmol/100 mL

Now, we can calculate the mass of dextrose present in 100 mL of the solution:

Mass of dextrose = Number of moles of dextrose * Molecular weight of dextrose

Mass of dextrose = 1 mosmol/100 mL * 198.17 g/mol = 1.9817 g/100 mL

Finally, we can calculate the percentage (w/v) of dextrose:

Percentage (w/v) = (Mass of dextrose / Volume of solution) * 100

Percentage (w/v) = (1.9817 g/100 mL / 100 mL) * 100 = 1.9817%

Therefore, the percentage (w/v) of dextrose in the solution is approximately 1.9817%.

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Answer: Each element on the periodic table is listed in a box with its atomic symbol and atomic number. The element's full name and atomic mass is also sometimes indicated. The image below shows a typical entry for the element calcium. The number above the atomic symbol represents the atomic number.

Hydrogenated compounds, particularly hydrogen gas (H2), are often considered as potential fuels for spark ignition engines.

Hydrogenated compounds are considered the most suitable fuels for spark ignition engines because hydrogen is a highly flammable gas with a low ignition energy and a wide flammability range. When compared to gasoline or diesel, hydrogen has a higher energy content by weight, which makes it an attractive fuel choice.

Due to increasing temperature, the chemical reaction rate also increases as the element moves from a solid to a liquid to a gas.Physical state transitions are dependent on temperature, and the rate of chemical reactions that occur as a result of these state transitions is also influenced by temperature.

At higher temperatures, the chemical reaction rate typically rises as molecules have more kinetic energy and collide with one another more frequently.

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Answer:

Aluminium Can not rust (Can't rust also meaning Corrode)

Because it's surface is protected by aluminium Oxide which stops the metal below from coming in contact with the air (which contains Oxygen) Unlike rust, which can flake off the surface of iron and steel objects, the layer of aluminium oxide does not flake off.

Corrode

destroy or damage (metal, stone, or other materials) slowly by chemical action.

Answer:

Modern chemistry describes the composition, structure, and physical and chemical properties of substances. ... The main aim of modern chemistry is to improve the communication and conversation among the scientists, researchers, engineers, and policymakers, who are working under the area of modern chemistry

Explanation:

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