2.5x−20 when X = 15?

Answer:

481.92

Step-by-step explanation:

3.2÷100×466,98=

14,94

then add

466.98 +14.94

481.92

Answer:

Amount of fencing required = 75 yards

Step-by-step explanation:

Distance between the two points \((x_1,y_1)\) and \((x_2,y_2)\) is given by the formula,

d = \(\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)

Distance between A(3, 6) and B(3, -2) = \(\sqrt{(3-3)^2+(6+2)^2}\)

                                                               = 8 yards

Distance between B(3, -2) and C(-7, 4) = \(\sqrt{(3+7)^2+(-2-4)^2}\)

                                                                = \(\sqrt{136}\)

                                                                = 11.66 ≈ 12 yards

Distance between C(-7, 4) and D(-7, -2) = \(\sqrt{(-7+7)^2+(4+2)^2}\)

                                                                 = 6 yards

Distance between D(-7, -2) and E(-3, -2) = \(\sqrt{(-7+3)^2+(-2+2)^2}\)

                                                                   = 4 yards

Distance between E(-3, -2) and F(-3, -8) = \(\sqrt{(-3+3)^2+(-2+8)^2}\)

                                                                = 6 yards

Distance between F(-3, -8) and G(3, -8) = \(\sqrt{(-3-3)^2+(-8+8)^2}\)

                                                                 = 6 yards

Distance between G(3, -8) and H(10, -12) = \(\sqrt{(3-10)^2+(-8+12)^2}\)

                                                                   = \(\sqrt{49+16}\)

                                                                   = \(\sqrt{65}\)

                                                                   = 8.06 ≈ 8 yards

Distance between H(10, -12) and J(10, 6) = \(\sqrt{(10-10)^2+(-12-6)^2}\)

                                                                   = 18 yards

Distance between A(3, 6) and J(10, 6) = \(\sqrt{(10-3)^2+(6-6)^2}\)

                                                               = 7 yards

Since length of fence required = perimeter of the flat area

Perimeter of the given area = 8 + 12 + 6 + 4 + 6 + 6 + 8 + 18 + 7

                                              = 75 yards

Therefore, amount of fencing required = 75 yards

Answer:

75 yards

Step-by-step explanation:

The ratio of boy to girl who play kickball at race is 6 to 2. There are 18 girl on the team. the number of boys who play kickball at race is 12 boys.

The ratio of boy to girl who play kickball at race is 6 to 2

6 boys: 2 girls

Multiply the number of girls by the ratio:

18 girls x (6 boys / 2 girls) = 18 x 3 = 54

Subtract the number of girls from the total to get the number of boys:

54 - 18 = 36

Therefore, there are 12 boys who play kickball at race.

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Answer:

145°

Step-by-step explanation:

180 - 35 = 145

145°

Answer:

x=1   y=4

Step-by-step explanation:

8(1) =8

2(4) =8

8+8=16

Answer:

∠1 = 90°

∠2 = 66°

∠3 = 24°

∠4 = 24°

Step-by-step explanation:

Usually the diagonals of a rhombus bisect each other at right angles.

Thus; ∠1 = 90°

Since they bisect at right angles, then;

∠R1S = 90°

Now, sum of angles in a triangle is 180°

Thus;

66° + 90° + ∠4 = 180°

156 + ∠4 = 180

∠4 = 180 - 156

∠4 = 24°

Now, also in rhombus, diagonals bisect opposite angles.

Thus; ∠4 = ∠3

Thus, ∠3 = 24°

Similarly, the diagonal from R to T bisects both angles into 2 equal parts.

Thus; ∠2 = 66°

Problem

Concept

The x is the input value and f(x) is the output value.

To find f(34) you substitute x = 34 in the function.

Next,

Substituting x = 34 into the function we get:

Final answer

f(34) = -3

The value of x in sequence of number is 10.

Here, first term of sequence is x and each term there after is twice the previous term. Also Fifth term is 160.

What is geometric series?

Geometric series is an infinite series of the form:

\(a+ar+a r^{2} +ar^{3} +..........\)

where r is known as common ratio.

Now, first term is x and each term there after is twice the previous term.

So the series will be;

x , 2x , 4x , 8x, ..........

Clearly this series is geometric series with common ratio 2.

And the nth term of geometric series is \(ar^{n-1}\)

⇒ fifth term is 160

\(ar^{5-1} = 160\\ar^{4} = 160\\a 2^{4} =160\\a=\frac{160}{16} \\a=10\)

Here, first term is x.

The value of x in sequence of number is 10.

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Answer:

\(\boxed{\sf{13}}\)

Step-by-step explanation:

The only way to solve this problem is to use the distance formula from left to right.

Distance formula:

\(\sf{(X_1,Y_1)(X_2,Y_1)}\)

\(\sf{\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}}\)

y2=5

y1=(-7)

x2=2

x1=7

Solve the problem by rewriting it down.

\(\sf{\sqrt{\left(2-7\right)^2+\left(5-\left(-7\right)\right)^2}}\)

\(\boxed{\sf{=13}}\)

Therefore, the final answer is 13.

I hope this helps! Let me know if my answer is wrong or not.

Answer:

Step-by-step explanation: To find out what grade Sally needs to earn on her fifth and last math test to achieve a 90 average, we  use the following steps:

Step 1: Add the total points Sally has received: 80 + 82 + 92 + 98 = 352.

Sally has taken 4 tests so far.

Step 2: Find the total marks required for a 90 average on 5 tests: 90 x 5 = 450.

Step 3: Find the score Sally needs to achieve on her fifth test by subtracting the points earned  from the total required points: 450 - 352 = 98.

Therefore, Sally needs to earn a grade of 98 on her 5th and last test to achieve a 90 average on all five tests this semester.

Answer:

keep in coming it is easy it is 14

A factor of a number that, when multiplied by itself, gives the original number is called a square root.

The square root of 3 is 9.

The integer that has the nearest to the integer that has a square root of 3 is √10.

A factor of a number that, when multiplied by itself, gives the original number.

We have,

9 is a square root of 3.

The nearest square root of 3 can be 8 or 10.

The value of the square root of 8.

= √8

= 2.83

The value of the square root of 10:

= √10

= 3.16

The nearest can be determined by finding out the difference between each of its values with 3.

For √8,

= 3 - 2.83

= 0.17

For √10,

= 3.16 - 3

= 0.16

We see that √10 is nearest to the integer that has a square root of 3.

Thus the integer that has the nearest to the integer that has a square root of 3 is √10.

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Answer:

2/5 or 40% chance

Step-by-step explanation:

The matrix A is not diagonalizable.

To determine if a matrix is diagonalizable, we need to check if the sum of the dimensions of its eigenspaces is equal to the size of the matrix. In this case, the combined dimensions of the eigenspaces of A equal four.

Given that A has eigenvalues A₁ = 2 with an algebraic multiplicity of two and A₂ = -7 with an algebraic multiplicity of three, we can find the dimensions of the corresponding eigenspaces.

For the eigenvalue A₁ = 2, the geometric multiplicity (dimension of the eigenspace) must be less than or equal to the algebraic multiplicity. Since the algebraic multiplicity is two, the maximum possible dimension of the eigenspace is two.

For the eigenvalue A₂ = -7, the geometric multiplicity (dimension of the eigenspace) must also be less than or equal to the algebraic multiplicity. In this case, the maximum possible dimension of the eigenspace is three.

When we add the dimensions of the eigenspaces for both eigenvalues, we get a combined total of (2 + 3) = 5, which is greater than the size of the matrix (2 x 2).

Since the combined dimensions of the eigenspaces exceed the size of the matrix, A is not diagonalizable.

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Answer:

i didnt get u what do u want that i should explain u

If it is impossible for events A and B to occur simultaneously, the events are said to be mutually exclusive. For such events, P(A or B) is equal to the sum of the individual probabilities of events A and B.

In other words, if A and B are mutually exclusive events, the probability of A or B occurring is equal to the sum of the probabilities of A and B individually.

Mathematically, P(A or B) = P(A) + P(B).

This holds true because when two events are mutually exclusive, the occurrence of one event excludes the possibility of the other event happening at the same time. Therefore, there is no overlap in the outcomes, and we can simply add their probabilities to calculate the probability of either event occurring.

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Answer:

try c hope this helps

Step-by-step explanation:

In pent-2-en, the trans isomer would have one hydrogen atom and one methyl group on each side of the double bond.

For pent-2-ene, there are two geometric isomers: cis-pent-2-ene and trans-pent-2-ene. In cis-pent-2-ene, the two alkyl groups (CH3 and CH2CH2CH3) are on the same side of the double bond. In trans-pent-2-ene, these two alkyl groups are on opposite sides of the double bond. These isomers have different physical and chemical properties due to the spatial arrangement of their atoms.

Pent-2-en is a five-carbon molecule with a double bond between the second and third carbon atoms. Therefore, it has two possible geometric or cis/trans isomers. The first isomer is the cis isomer, also known as Z-isomer, where the two substituents on the double bond are on the same side of the molecule. In pent-2-en, the cis isomer would have the two hydrogen atoms on one side of the double bond, and the two methyl groups on the other side.  The second isomer is the trans isomer, also known as the E-isomer, where the two substituents on the double bond are on opposite sides of the molecule. In pent-2-en, the trans isomer would have one hydrogen atom and one methyl group on each side of the double bond.

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Therefore, the probability that in any given minute there will be 2 or fewer arrivals is approximately 0.4231 or 42.31%.

To find the probability of 2 or fewer arrivals in a given minute, we can use the Poisson distribution formula.

The formula for the Poisson distribution is:

P(X = k) = (e*(-λ) * λ\(^k\)) / k!

Where:

P(X = k) is the probability of k arrivals,

e is the base of the natural logarithm (approximately 2.71828),

λ is the average rate of arrivals,

k is the number of arrivals.

In this case, the average rate of arrivals is given as 3 per minute.

Let's calculate the probabilities for k = 0, 1, and 2.

For k = 0:

P(X = 0) = (e⁻³ * 3⁰) / 0! = e⁻³ ≈ 0.0498

For k = 1:

P(X = 1) = (e⁻³ * 3¹) / 1! = 3e⁻³ ≈ 0.1493

For k = 2:

P(X = 2) = (e⁻³ * 3²) / 2! = 9e⁻³ / 2 ≈ 0.224

To find the probability of 2 or fewer arrivals, we sum up the probabilities for k = 0, 1, and 2:

P(X ≤ 2) = P(X = 0) + P(X = 1) + P(X = 2)

= 0.0498 + 0.1493 + 0.224

≈ 0.4231

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Answer:

set A presents {a,c,e}

Answer:

The dolphin's final depth was -25 feet.

Step-by-step explanation:

Answer:

25 feet

Step-by-step explanation:

110 - 85=25

The slope of the tangent line at (4, 54) is 45. So the equation of the tangent line to the curve y = x^3 - 3x + 2 at the point (4, 54) is y = 45x - 126.

To find the equation of the tangent line to the curve y = x^3 - 3x + 2 at the point (4, 54), we need to use calculus. First, we find the derivative of the function:

y' = 3x^2 - 3

Next, we plug in x = 4 to find the slope of the tangent line at that point:

y'(4) = 3(4)^2 - 3 = 45

So the slope of the tangent line at (4, 54) is 45. To find the equation of the line, we use the point-slope form of the equation:

y - y1 = m(x - x1)

where m is the slope and (x1, y1) is the point on the line. Plugging in our values, we get:

y - 54 = 45(x - 4)

Simplifying, we get:

y - 54 = 45x - 180

y = 45x - 126

So the equation of the tangent line to the curve y = x^3 - 3x + 2 at the point (4, 54) is y = 45x - 126.

To find the equation of the tangent line to the curve y = x^3 - 3x + 2 at the point (4, 54), we need to first find the derivative of the function and then use the point-slope form of a line.

1. Find the derivative of the function with respect to x:
y'(x) = d/dx (x^3 - 3x + 2) = 3x^2 - 3

2. Evaluate the derivative at the given point (4, 54) to find the slope of the tangent line:
m = y'(4) = 3(4)^2 - 3 = 3(16) - 3 = 48

3. Use the point-slope form of a line (y - y1 = m(x - x1)):
y - 54 = 48(x - 4)

4. Simplify the equation:
y - 54 = 48x - 192
y = 48x - 138

So, the equation of the tangent line to the curve y = x^3 - 3x + 2 at the point (4, 54) is y = 48x - 138.

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A LOD score is the ratio of probabilities that two genes are linked to the probability that they are not linked, expressed as a log10. This measure is commonly used in linkage analysis, a statistical method used to determine whether genes are located on the same chromosome and thus tend to be inherited together.

In linkage analysis, the LOD score is used to determine the likelihood that two genes are linked, based on the observation of familial inheritance patterns. A LOD score of 3 or higher is generally considered to be strong evidence for linkage, indicating that the likelihood of observing the observed inheritance pattern by chance is less than 1 in 1000.

The LOD score is also used to estimate the distance between two linked genes, with higher LOD scores indicating that the two genes are closer together on the chromosome. In general, the LOD score is a useful tool for identifying genetic loci that contribute to complex diseases or traits.

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The estimated value of the machine after 4 years when the rate of depreciation dV/dt is inversely proportional to the square of t + 1 is $234,375.

Since the rate of depreciation is inversely proportional to the square of t + 1, we can write:

dV/dt = k / (t + 1)²

where k is the constant of proportionality. We can find k by using the initial value of the machine:

dV/dt = k / (t + 1)² = -100,000 / year when t = 0 (the first year)

Therefore, k = -100,000 * (1²) = -100,000.

To find the value of the machine after 4 years, we need to solve the differential equation:

dV/dt = -100,000 / (t + 1)

We can do this by separating variables and integrating:

∫dV / (V - 500,000) = ∫-100,000 dt / (t + 1)²

ln|V - 500,000| = 100,000 / (t + 1) + C

where C is the constant of integration.

We can find C by using the initial value of the machine:

ln|500,000 - 500,000| = 0 = 100,000 / (0 + 1) + C

Therefore, C = -100,000.

Substituting this value of C, we get:

ln|V - 500,000| = 100,000 / (t + 1) - 100,000

ln|V - 500,000| = -100,000 / (t + 1) + ln|e¹⁰|

ln|V - 500,000| = ln|e¹⁰ / (t + 1)²|

V - 500,000 = \(e^{10/(t + 1)²)}\)

V = \(e^{10/(t + 1)²)}\) + 500,000

Finally, we can estimate the value of the machine after 4 years by substituting t = 3:

V = \(e^{10/(3 + 1)²}\) + 500,000

V ≈ $234,375

Therefore, the correct answer is $234,375.

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Answer:

11_100

0.11

iam not sure

best of luck