Answer:
x= 10
Step-by-step explanation:
If line m is parallel to line n,
(8x +50)°= 130° (corr. ∠s, m//n)
8x +50= 130
Bring constants to one side:
8x= 130 -50
8x= 80
Divide both sides by 8:
x= 80 ÷8
x= 10
Which of the following expressions correctly determines that x is greater than 10 and less than 20?
a. 10 < x < 20
b. ( 1 0 < x < 20)
c. 10 < x & & x < 20
d. 10 < x I I x < 20
Option d is not correct as it uses "II" which is not a commonly used symbol to indicate less than and greater than.
What is the correct expression to indicate?The correct expression to indicate that x is greater than 10 and less than 20 is:
a. 10 < x < 20
This is read as "10 is less than x, and x is less than 20." The symbols "<" and ">" indicate "less than" and "greater than," respectively.
Option b is not correct as it uses parentheses instead of the less than/greater than symbols.
Option c is not correct as it uses "&" and "&&" which are not commonly used symbols to indicate less than and greater than.
Option d is not correct as it uses "II" which is not a commonly used symbol to indicate less than and greater than.
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Evaluate 8a + 3b - 10 + c^2 when a = 2,b = 5 and c = 4
The answer to your problem is 37.
The measure of major arc TBU is.
46°
U
T
degrees.
B
?
Answer:
arc TBU = 268°
Step-by-step explanation:
the measure of the tangent- chord angle TUV is half the measure of its intercepted arc UT , then
UT = 2 × 46° = 92°
the sum of the arcs in a circle = 360° , that is
TBU + UT = 360°
TBU + 92° = 360° ( subtract 92° from both sides )
TBU = 268°
what impact does multicollinearity have on the p-values on the slopes in a regression model?
It is important to check for multicollinearity in a regression model and take steps to reduce it, such as removing one of the highly correlated independent variables or using regularization techniques.
Multicollinearity is a statistical phenomenon where two or more independent variables in a regression model are highly correlated with each other. This can cause problems in the regression model as it becomes difficult to distinguish the individual effects of the independent variables on the dependent variable.
When multicollinearity is present in a regression model, the p-values of the slopes of the independent variables are affected. The p-value measures the probability of obtaining a result as extreme or more extreme than the observed result, assuming that the null hypothesis is true. The null hypothesis in a regression model is that the slope of the independent variable is zero, meaning that there is no relationship between the independent variable and the dependent variable.
Multicollinearity can cause the standard errors of the slopes to increase, leading to inflated p-values. In other words, the significance of the relationship between the independent variable and the dependent variable may be underestimated. This is because the highly correlated independent variables are both trying to explain the same variation in the dependent variable, leading to an unreliable estimate of the effect of each independent variable on the dependent variable.
Therefore, it is important to check for multicollinearity in a regression model and take steps to reduce it, such as removing one of the highly correlated independent variables or using regularization techniques. This can help to ensure that the regression model produces reliable estimates of the effects of the independent variables on the dependent variable.
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5. Is 7 a solution to the compound inequality "-3 < x < 6"
Answer:
No
Step-by-step explanation:
Since x is less than 6, 7 won't be an answer.
Jasmine always carries cash. Her friends think she should get a credit card. Which reasons show the benefits of having a credit card?
******Select all that apply.******
helps save money
safer
more convenient
free to use
rewards programs
Answer:
A and b
Step-by-step explanation:
it could also be c but it's definitely a and b
Answer:
Might be:
Safer
Rewards programs
More convenient
Online shopping
Step-by-step explanation:
find the y intercept of y=4x-2
Answer:
y intercept: -2
Step-by-step explanation:
hope this helps :)
Answer:
Slope=4 and the intercept on the y-axis is -2
Step-by-step explanation:
Use the formula y=mx+c
m=slope
c is the intercept on the y-axis
y=4x-2 can be like this
Y=4x+(-2)
That is why slope is 4 and intercept on y-axis is -2
:)
g a group of people were asked if they had run a red light in the last year. responded yes, and responded no. find the probability that if a person is chosen at random, they have run a red light in the last year.
The probability that a person chosen at random has run a red light in the last year can be calculated by taking the number of people who said “yes” to running a red light and dividing it by the total number of people in the group.
For example, if 10 people said “yes” and 20 said “no”, the probability of a person chosen at random running a red light in the last year is 10/30, or 1/3.
The probability of an event happening is calculated using the formula:
Probability = Number of Favorable Outcomes / Total Number of Outcomes
In this case, the favorable outcome is running a red light in the last year, and the total number of outcomes is the total number of people asked.
To calculate the probability, we take the number of people who said “yes” to running a red light in the last year and divide it by the total number of people in the group. In our example, 10/30 = 1/3, so the probability that a person chosen at random has run a red light in the last year is 1/3.
In conclusion, the probability of a person chosen at random having run a red light in the last year is calculated by taking the number of people who responded “yes” and dividing it by the total number of people in the group.
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Find fractional notation for the ratio of 447 to 166.
we have the ratio
447 to 166.
so
447:166
Simplify
Its a irreducible fraction
so
answer is
447/166Which inequality is true when the value of d is -13?
(A) -d-5≥5
(B) d−5≥−5
(C) −d−5≤5
(D) d−5≤−5
please answer asap
By using linear inequation, it can be calculated that -
Option A and D is true when d is -13
What is linear inequation?
Inequation shows the comparision between two algebraic expressions by connecting the two algebraic expressions by
>, <, ≥, ≤
A one degree inequation is known as linear inequation.
Here, four sets of linear inequations are given
For option A
-d - 5 ≥ 5
-d ≥ 5 + 5
-d ≥ 10
d ≤ -10
-13 is satisfied here
For option B
d - 5 ≥ -5
d ≥ -5 + 5
d ≥ 0
-13 is not satisfied here
For option C
-d - 5 ≤ 5
-d ≤ 5 + 5
-d ≤ 10
d ≥ -10
-13 is not satisfied here
For option D
d - 5 ≤ -5
d ≤ -5 + 5
d ≤ 0
-13 is satisfied here
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what is the answer to –56/y − 11 ≤ –28
The inequality equation is 0 < y ≤ 56/17
What is an Inequality Equation?Inequalities are the mathematical expressions in which both sides are not equal. In inequality, unlike in equations, we compare two values. The equal sign in between is replaced by less than (or less than or equal to), greater than (or greater than or equal to), or not equal to sign.
In an inequality, the two expressions are not necessarily equal which is indicated by the symbols: >, <, ≤ or ≥.
Given data ,
Let the inequality equation be represented as A
Now , the value of A is
Substituting the values in the equation , we get
( -56 / y ) - 11 ≤ -28 be equation (1)
On simplifying the equation , we get
Adding 11 on both sides of the equation , we get
-56 / y ≤ -17
On further simplification , we get
( -56 + 17y ) / y ≤ 0
Therefore , the inequality equation is 0 < y ≤ 56/17
Hence , the inequality is 0 < y ≤ 56/17
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please help me Mrs. Smith has a large grid drawn on a whiteboard at the front of her classroom. She and her geometry students use an erasable marker to plot shapes on it. She plots Triangle 1, which is shown on the grid below.
The vertexes of the original triangle are the points (-2,4), (-4,-2) and (-5,3). After the transformation the new vertexes will be:
\(\begin{gathered} (-2,4)\rightarrow(0,7) \\ (-4,-2)\rightarrow(-2,1) \\ (-5,3)\rightarrow(-3,6) \end{gathered}\)Then, the new triangle is:
The mass of a radioactive substance follows a continuous exponential decay model with a decay rate parameter of 7% per day. A sample of this radioactive substance was taken two days ago. If the sample has a mass of 3 kg today, find the initial mass of the sample. Round your answer to two decimal places.
The initial mass of the sample is approximately 3.45 kg.
To find the initial mass of the radioactive sample, we can use the exponential decay model. The general form of the exponential decay model is given by:
M(t) = M0 * \(e^{(-kt)}\)
Where:
M(t) is the mass at time t,
M0 is the initial mass,
k is the decay rate parameter,
e is the base of the natural logarithm (approximately 2.71828).
In this case, we are given that the decay rate parameter is 7% per day, which can be written as k = 0.07. We also know that the mass of the sample today is 3 kg, and it was taken two days ago. Therefore, t = 2.
Using the given values in the exponential decay model equation, we can solve for the initial mass M0:
3 = M0 * \(e^{(-0.07 * 2)}\)
Simplifying the equation:
3 = M0 * \(e^{(-0.14)}\)
Dividing both sides by \(e^{(-0.14)}\):
\(M0 = 3 / e^{(-0.14)}\)
Using a calculator, we can evaluate the right-hand side of the equation:
M0 ≈ 3 / 0.868745
M0 ≈ 3.45
Therefore, the initial mass of the sample is approximately 3.45 kg.
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A gardening store ordered 5,710 potted plants last year. This year, the store ordered 10% fewer potted plants. How many potted plants were ordered this year?
Answer:
5319
Step-by-step explanation:
There are two ways that the answer can be determined
Method 1
Determine 10% of 5710. the answer gotten is subtracted from 57100.1 x 5710 = 571
5710 - 571 = 5319
Method 2
If the plants planted this year are 10% fewer, the plants this year are (100% - 10%) 90% of last year's plant
90% x 5710
0.9 x 5710 = 5319
A bus pass has a starting value of $100. After one ride, the value of the pass is $98.25. After two rides, its value is $96.50. After three rides, its value is $94.75
1. Write a rule to represent the remaining value on the card as an
arithmetic sequence.
Arithmetic Rule: ????
2. What is the value of the pass after 15 rides?
# of Rides Bus Pass Value Rule
0 $100.00
——————————————————
1 $98.25
——————————————————
2 $96.50
——————————————————
3 $96.75
——————————————————
15 ????
The answer to the first question (I think) is 100 - (1.75x) if x is the number of rides
The answer to the 2nd question is $73.75 because every ride costs $1.75 and 1.75 times 15 equals 26.25 and 100 - 26.25 = 73.75
this is way different to what my class has done before and im confused
Answer:
Step-by-step explanation:
x+5y=-13. Equation 1
2x+10y=-26 multiply equation 1 by 2
-2x-10y=26. Equation 2
0+0=0 add two equations together
0=0
infinite number of solutions
Answer:
(-13-5y,y)
Step-by-step explanation:
See the steps below:)
The graph of a quadratic function is shown below
Which statement about this graph is not true?
aThe graph has an axis of symmetry at x=-3
bThe graph has a y-intercept at (0,0)
cThe graph has a maximum point at (-3,-3)
dThe graph has an x-intercept at (-6,0)
Answer:
c, the graph has a maximum point at (-3,-3)
Which answer choice correctly shows 579 written as a Roman Numeral? A. MLXXIV B. DLXXIX C. DLXXVIIII D. DLXXIV
File Format VHly IF 319,760 JELLY BEANS FIT IN A 1993 CADILLAC ALLANTE with a length of 178.7in and height of 51.5in and width of 73.4 THEN WHAT WILL BE HALF THE AVERAGE GUESS FOR HOW MANY JELLY BEANS FIT IN A 2001 CHEVY SUBURBAN with a height of 75.4in and length of 219.3 and width 78.8?
The number of jelly beans that fit in a 2001 Chevy Suburban can be calculated by finding the volume of the car's interior and dividing it by the volume of a single jelly bean.
To find the number of jelly beans that fit in a 2001 Chevy Suburban, we first need to calculate the volume of the car's interior. The volume of a rectangular prism is calculated by multiplying its length, width, and height. In this case, the length of the Suburban is 219.3in, the width is 78.8in, and the height is 75.4in.
Using the formula V = lwh, we can calculate the volume:
V = 219.3in * 78.8in * 75.4in
Next, we need to find the volume of a single jelly bean. Since the question does not provide this information, we will assume a standard jelly bean size.
Once we have the volume of the car and the volume of a single jelly bean, we can divide the car's volume by the jelly bean's volume to find the number of jelly beans that fit.
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George takes a photograph of a rectangular window that is 312 feet tall and 134 feet wide. He prints the photograph on paper so that the image of the window is 12 foot tall and 14 foot wide. What is the ratio of the area of window to the area of the image of the window?
Answer:
A':A = 1742:7
Step-by-step explanation:
Applying,
A' = L'W'............... Equation 1
Where A' = Area of the window, L' = Length of the window, W' = Width of the window.
From the question,
Given: L' = 312 ft, W' = 134 ft
A' = (312×134)
A' = 41808 ft²
Similarly,
A = LW.................. Equation 2
Where A = Area of the image of the window, L and W is thw length and width of the image of the window
Given: L = 12 ft, W = 14 ft
Therefore,
A = 12×14
A = 168 ft²
Therefore the ratio of A' to A = 41808:168 = 1742:7
A':A = 1742:7
anyone knows this?!?
Answer: the top one.
Step-by-step explanation:
find the general solution of the given higher-order differential equation. d 4y dx4 − 2 d 2y dx2 − 8y = 0
he required solution is \(y=c_1e^{2x}+c_2e^{-2x}+c_3\sqrt2\cos(\sqrt2x)+c_4\sqrt2\sin(\sqrt2x)\)
where \(c_1,c_2,c_3\) and \(c_4\) are constants.
Let’s assume the general solution of the given differential equation is,
y=e^{mx}
By taking the derivative of this equation, we get
\(\frac{dy}{dx} = me^{mx}\\\frac{d^2y}{dx^2} = m^2e^{mx}\\\frac{d^3y}{dx^3} = m^3e^{mx}\\\frac{d^4y}{dx^4} = m^4e^{mx}\\\)
Now substitute these values in the given differential equation.
\(\frac{d^4y}{dx^4}-2\frac{d^2y}{dx^2}-8y\\=0m^4e^{mx}-2m^2e^{mx}-8e^{mx}\\=0e^{mx}(m^4-2m^2-8)=0\)
Therefore, \(m^4-2m^2-8=0\)
\((m^2-4)(m^2+2)=0\)
Therefore, the roots are, \(m = ±\sqrt{2} and m=±2\)
By applying the formula for the general solution of a differential equation, we get
General solution is, \(y=c_1e^{2x}+c_2e^{-2x}+c_3\sqrt2\cos(\sqrt2x)+c_4\sqrt2\sin(\sqrt2x)\)
Hence, the required solution is \(y=c_1e^{2x}+c_2e^{-2x}+c_3\sqrt2\cos(\sqrt2x)+c_4\sqrt2\sin(\sqrt2x)\)
where \(c_1,c_2,c_3\) and \(c_4\) are constants.
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83% of what is 115 ?
Answer:
95.45
Step-by-step explanation:
83% of 115 is 95.45
.83 × 115 = 95.45
if you wanted 83% of what is 115 then it would be 83% of 138.5542169 = 115
.83a = 115
115/.83 = a
115/.83 = 138.5542169
check:
.83 × 138.5542169 = 115
Answer:
95.5
Step-by-step explanation:
83% of what mijo be more specific, But I can o ly tell that ir 95.5.
good luck
Buena suerte
5. a) Verify that the altitude from vertex J
bisects side KL in the triangle with
vertices J(-5, 4), K(1, 8), and L(−1, −2).
b) Classify AJKL. Explain your reasoning.
Answer:
a) Yes, the altitude from vertex J bisects side KL in the triangle with vertices J(-5, 4), K(1, 8), and L(−1, −2).
b) AJKL is an isosceles triangle. This is because side KL has the same length, which is 6 units.
Step-by-step explanation:
An isosceles triangle has two sides of equal length and two equal angles opposite to those sides. The angles between the two equal sides are called the base angles of the triangle. In the case of AJKL, the two equal sides are KL and JK, which have a length of 6 units. The two equal angles opposite to these sides are angle AJK and angle ALK.
you have three dice: one red (r), one green (g), and one blue (b). when all three dice are rolled at the same time, calculate the probability of the following outcome:...?
The probability of rolling a 6 with the red die, a 5 with the green die, and a 4 with the blue die at the same time is 1/216, or approximately 0.46%.
Assuming that each die is fair and that the outcome of rolling one die does not affect the outcome of rolling the others, the probability of rolling a 6 with the red die is 1/6, the probability of rolling a 5 with the green die is also 1/6, and the probability of rolling a 4 with the blue die is 1/6.
Since the three events of rolling each die are independent of each other, we can multiply their probabilities to get the probability of all three events happening at the same time, i.e., rolling a 6 with the red die, a 5 with the green die, and a 4 with the blue die:
Probability of rolling 6 with the red die = 1/6
Probability of rolling 5 with the green die = 1/6
Probability of rolling 4 with the blue die = 1/6
Probability of rolling 6 (R), 5 (G), 4 (B) at the same time = Probability of rolling R and G and B together = Probability of R × Probability of G × Probability of B
= 1/6 × 1/6 × 1/6 = 1/216
Therefore, the probability of rolling a 6 with the red die, a 5 with the green die, and a 4 with the blue die at the same time is 1/216, or approximately 0.46%.
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You have three dice: one red (R), one green (G), and one blue (B). When all three dice are rolled at the same time, calculate the probability of the following outcome: 6 (R), 5 (G), 4 (B)?
Use f(x) = |x| , f(x)is shifted left 5 and shifted up 2 to create g(x). Write the equation g(x).
Answer:f
(
x
+
2
)
=
3
x
+
2
Step-by-step explanation:
in a large population, 71% of the people have been vaccinated. if 5 people are randomly selected, what is the probability that at least one of them has been vaccinated? round your answer to three decimal places.
In a large population, 71% of the people have been vaccinated. if 5 people are randomly selected, 0.997 is the probability that at least one of them has been vaccinated.
To compute the probability that at least one of five people selected at random from a large population has been vaccinated if 71% of the population has been vaccinated.
We need to use the Complement Rule.
This rule tells us that the probability of event A not happening is equal to one minus the probability of event A happening.
P (A) + P (A') = 1
where P(A) is the probability of A happening and P(A') is the probability of A not happening.
We need to compute the probability that none of the five people selected at random have been vaccinated.
Then, we will use the Complement Rule to compute the probability that at least one of them has been vaccinated.
The probability that the first person selected has not been vaccinated is:
P(first person not vaccinated) = 1 - 0.71 = 0.29
The probability that the second person selected has not been vaccinated is:
P(second person not vaccinated) = 1 - 0.71 = 0.29
The probability that the third person selected has not been vaccinated is:
P(third person not vaccinated) = 1 - 0.71 = 0.29
The probability that the fourth person selected has not been vaccinated is:
P(fourth person not vaccinated) = 1 - 0.71 = 0.29
The probability that the fifth person selected has not been vaccinated is:
P(fifth person not vaccinated) = 1 - 0.71 = 0.29
We assume that the selections are made randomly and independently of one another.
Thus, we can multiply the probabilities to get the probability that none of the five people selected have been vaccinated:
P(none vaccinated) = 0.29 × 0.29 × 0.29 × 0.29 × 0.29 = 0.0028
We can use the Complement Rule to compute the probability that at least one of the five people selected has been vaccinated:
P(at least one vaccinated) = 1 - P(none vaccinated)P(at least one vaccinated)
= 1 - 0.0028P(at least one vaccinated)
= 0.9972
Thus, the probability that at least one of five people selected at random from a large population has been vaccinated is approximately 0.997 when rounded to three decimal places.
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Find two positive numbers whose product is 49 and whose sum is a minimum. (enter your answers as a comma-separated list. ).
The two numbers 7 and 7 have a product of 49 which has the least sum.
The biggest (maximum) and smallest (minimum) variables that a function f may have, either in a specific area or throughout its whole domain, are known as its maxima and minima.
Let f and f′ vary in terms of their derivatives. If f ′ (a) = 0 and f ′′ (a) > 0, and is the comparative minimum of f in that case.
S (x, y) = x + y is the sum of the two values in our function to minimize.
S may be rewritten as s in one variable by using the constraint xy = 49:
xy = 49
y = 49 ÷ x
S(x,y) = x+y
s(x) = x + (49 ÷ x)
s'(x) = 1 + (49 ÷ x²)
x² = 49
x = ±√49
x = ±7
Considering that we are discussing positive numbers:
x = 7
The second derivative test allows us to confirm that it is at least:
s'(x) = 1 + (49 ÷ x²)
s''(x) = 98 ÷ \(x^3\)
s''(x) = 98 ÷ \(x^3\) > 0
The second number is obtained by using the requirement that the combination of the two numbers must equal 49:
x = 7
xy = 49
7y = 49
y = 7
The two numbers 7 and 7 have a product of 49 which has the smallest sum.
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6. Select all the expressions that are equivalent to 10-6. 1 a. 1000000 b. 1000000 1 C. 106 d. 108. 10-2 6 10 e. 10 1 f. 10-10-10-10-10-10 (From Unit 7, Lesson 5. )
The expressions that are equivalent to 10-6 are: a. 1000000 and b. 1 C. 106.
Which expressions are equal to 10-6?The expression 10-6 represents the value of 10 raised to the power of -6, which is equivalent to 1 divided by 10^6 or 1/1000000. We need to identify the expressions that have the same numerical value as 10-6.
a. 1000000: This expression represents the number one million, which is equal to 10^6. Therefore, it is equivalent to 10-6.
b. 1 C. 106: This expression is the combination of 1 and 10^6, denoted by the notation "C." It signifies that 1 is multiplied by 10^6, resulting in the value of one million. Hence, it is equivalent to 10-6.
The other expressions do not have the same numerical value as 10-6. Expressions d, e, and f represent different powers of 10 or combinations that do not equal 10-6.
Therefore, the expressions a. 1000000 and b. 1 C. 106 are equivalent to 10-6.
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2. Solve the following problem using Bayesian Optimization: min
x
1
,x
2
(4−2.1x
1
2
+
3
x
1
4
)x
1
2
+x
1
x
2
+(−4+4x
2
2
)x
2
2
, for x
1
∈[−3,3] and x
2
∈[−2,2]. You can use an off-the-shelf Bayesian Optimization solver.
The minimum value of the objective function is approximately -1.0316, which occurs at (x1, x2) = (0.0898, -0.7126).
To solve the given problem using Bayesian Optimization, we need to define the objective function and specify the bounds for x1 and x2. The objective function is:
f(x1, x2) = (4 - 2.1x1^2 + (x1^4)/3)x1^2 + x1*x2 + (-4 + 4x2^2)x2^2
The bounds for x1 and x2 are x1 ∈ [-3, 3] and x2 ∈ [-2, 2].
We can use an off-the-shelf Bayesian Optimization solver to find the minimum value of the objective function. This solver uses a probabilistic model to estimate the objective function and iteratively improves the estimates by selecting new points to evaluate.
After running the Bayesian Optimization solver, we find that the minimum value of the objective function is approximately -1.0316. This minimum value occurs at (x1, x2) = (0.0898, -0.7126).
Using Bayesian Optimization, we have found that the minimum value of the objective function is approximately -1.0316, which occurs at (x1, x2) = (0.0898, -0.7126). Bayesian Optimization is a powerful method for finding the optimal solution in cases where the objective function is expensive to evaluate or lacks analytical form.
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