24 cans cost 6 pounds how much does 1 can cost​

Answer:

252000

Step-by-step explanation:

we take 2.52 and move the decimal back 5 places. when we run out of numbers we add zeros. so if we moved 3 places back it would be 2520 but since we move 5 it is 252000. 10 by any power you just move the decimal place if it is negtive move it forward if positive move backward.

Answer:

2 : 19

Step-by-step explanation:

We know 2 of the bushes are blooming (this is the left number in my answer) but the other 17 are not. Neither of these is the total number of bushes. To find that, we need to add these together to get 2 + 17 = 19.

This means 2 out of 19 rose bushes are blooming.

Hope this helps! Have a great day!

The probabilities for the hypergeometric distribution with the given parameters are:

a. P(X = 1) ≈ 0.000407

b. P(X = 6) = 0

c. P(X = 4) ≈ 0.098117

d. P(X = 0) ≈ 1.97e-05

Probability is a measure of the likelihood of an event to occur. Many events cannot be predicted with total certainty.

To determine the probabilities for the hypergeometric distribution with the given parameters, we can use the following formula:

P(X = k) = (choose(K, k) * choose(N-K, n-k)) / choose(N, n)

where "choose(a, b)" represents the binomial coefficient, calculated as a! / (b! * (a - b)!)

Let's calculate the probabilities:

a. P(X = 1):

P(X = 1) = (choose(20, 1) * choose(100-20, 4-1)) / choose(100, 4)

        = (20 * 80) / 3921225

        ≈ 0.000407

b. P(X = 6):

P(X = 6) = (choose(20, 6) * choose(100-20, 4-6)) / choose(100, 4)

        = (38760 * 0) / 3921225

        = 0

c. P(X = 4):

P(X = 4) = (choose(20, 4) * choose(100-20, 4-4)) / choose(100, 4)

        = (4845 * 80) / 3921225

        ≈ 0.098117

d. P(X = 0):

P(X = 0) = (choose(20, 0) * choose(100-20, 4-0)) / choose(100, 4)

        = (1 * 77) / 3921225

        ≈ 1.97e-05

Therefore:

a. P(X = 1) ≈ 0.000407

b. P(X = 6) = 0

c. P(X = 4) ≈ 0.098117

d. P(X = 0) ≈ 1.97e-05

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The complete question is:

Suppose that X has a hypergeometric distribution with N = 100, n = 4, and K = 20. Determine the following: a. P(X = 1) b. P(X = 6) c. P(X = 4) d. P(X = 0).

Answer:

458210 in binary

10001111001102

To convert decimal number 4582 to binary, follow these steps:

Divide 4582 by 2 keeping notice of the quotient and the remainder.

Continue dividing the quotient by 2 until you get a quotient of zero.

Then just write out the remainders in the reverse order to get binary equivalent of decimal number 4582.

Using the above steps, here is the work involved in the solution for converting 4582 to binary number:

4582 / 2 = 2291 with remainder 0

2291 / 2 = 1145 with remainder 1

1145 / 2 = 572 with remainder 1

572 / 2 = 286 with remainder 0

286 / 2 = 143 with remainder 0

143 / 2 = 71 with remainder 1

71 / 2 = 35 with remainder 1

35 / 2 = 17 with remainder 1

17 / 2 = 8 with remainder 1

8 / 2 = 4 with remainder 0

4 / 2 = 2 with remainder 0

2 / 2 = 1 with remainder 0

1 / 2 = 0 with remainder 1

Then just write down the remainders in the reverse order to get the answer, The decimal number 4582 converted to binary is therefore equal to : 

1000111100110

By using the concept of Permutation and Combination, Counting Principle  Phyllis can make 168 ways to select students.

Permutation and Combination are about making arrangements and making selections on the basis of certain formulas

The re-arranging of any given sorted/ordered set is called a permutation. The “permutation” word actually tells us that change the linear order of the ordered set.

Selecting items from a large collection without taking any care about their order is called combinations.

We need to select one freshman out of 12 freshmen. So selecting r things from n things we can do selection in nr ways, so we can do a selection of freshmen in 12c1 ways

Similarly, we need to select one sophomore out of 14 sophomores, so we can do a selection of sophomores in 14c1 ways

We know that ncr is equivalent to \(\frac{n!}{r!(n-r)!}\)

So, using this concept total number of ways to select a student

= ((12c1)×(14c1))

=12×14

=168 ways

Hence Phyllis can select students in 168 ways

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Answer:

Bruno = 15 years

Mother = 8 + 2(15) = 38 years

Father = 38 + 3 = 41 years

Step-by-step explanation:

Given that :

Let

Bruno's age = x

Mothers age = 8 + 2x

Father's age = 8 + 2x + 3 = 2x + 11

x + 8 + 2x + 2x + 11 = 94

5x + 19 = 94

5x = 75

x = 75 /5

x = 15

Bruno = 15 years

Mother = 8 + 2(15) = 38 years

Father = 38 + 3 = 41 years

The required value of x is 22 degrees for the given figure.

Adjacent angles are a sort of additional angle. Adjacent angles share a common side and vertex, such as a corner point. Their points do not overlap in any manner.

As we know that supplementary angles are defined as when pairing of angles addition to 180° then they are called supplementary angles.:

According to the given figure, it can be written as follows:

2x + 24 + 6x - 20 = 180

8x + 4 = 180

8x = 180 - 4

8x = 176

x = 176/8

x = 22

Therefore, the required value of x is 22 degrees for the given figure.

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The complete question is as follows:

Find the value of x for the below figure.

The cost per second to power such a circuit during the peak usage period is approximately \(2.376 x 10^-6\)$/s. The cost per second to power the circuit during the peak usage period can be calculated using the following steps:

Calculate the power consumption of the device-The power consumption of the device can be calculated using the formula: Power = Voltage x Current. P = V x I, Substituting the given values:

P = 110V x 0.12A

= 13.2 W

Calculate the cost per second-The cost per second can be calculated using the formula:

Cost per second = Power x Cost per Joule

C = P x CC

= 13.2 W x 1.8 x \(10^-7\) $/J

≈ 2.376 x 10^-6 $/s

Therefore, the cost per second to power such a circuit during the peak usage period is approximately 2.376 x\(10^-6\) $/s.

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A = P ( 1 + r )^t

Given A = $2000 , r = 3% = 0.03

so, after 2 years t = 2

A = 2000 * ( 1 + 0.03)^2 = $2,121.8

so, the total after 2 years = $2,121.8

==============================================================

How much money should be invested today to accumulate to $10,000 in 10 years at 4.5% compounded monthly? (Simplify your answer. Round to the nearest cent as needed)

so, A = $10,000

r = 4.5% = 0.045

t = 10 years = 10 * 12 = 120 months

So, A = P (1 + r/n)^t ,,, n = 12

10,000 = P ( 1 + 0.045/12)^120

10,000 = P * 1.567

P = 10,000/1.567 = 6,381.65 ( to the nearest cent )

so, the money should be invested = $6,381.65

The type of triangle that Kevin drew based on the information is a scalene triangle.

A scalene triangle is a triangle with different lengths for each of its three sides and different measures for each of its three angles. A scalene triangle's angles adhere to the angle sum property and always add up to 180 degrees.

A scalene triangle has three sides, each of which is measured differently. Each of a triangle's three interior angles has a different measurement. Scalene triangles don't have a symmetry line.

In this case, the sides are all different as illustrated in Kevin's case.

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Addition And Subtraction

1.) -27+68-56+61= 46

2 ) 4.17-9.42+0.2= -5. 05

3 ) 3.1+(-4.72)+(-8.12)-(-0.96)=-8.78

4 ) -18.31-6.27+(-8.44)-(-31.67)=-1. 35

5 ) 6 5/12 - (-4 2/3)8 + (-2 3/4)= 5/12

6 ) 4 1/8 - 6 2/9+ (-3 1/6) - (-5 3/4)= -49/72

1.) -27+68-56+61=

Because in this arithmetic operation there is only addition and subtraction, it can be calculated starting from anywhere.

2 ) 4.17-9.42+0.2= -5. 05

Because in this arithmetic operation there is only addition and subtraction, it can be calculated starting from anywhere.

3 ) 3.1+(-4.72)+(-8.12)-(-0.96)=-8.78

Because in this arithmetic operation there is only addition and subtraction, it can be calculated starting from anywhere.

But it should be noted that before the number (-0.96) there is a negative sign (-) so you need to multiply the sign with the number in brackets. In this case the result is . positive.

4 ) -18.31-6.27+(-8.44)-(-31.67)=-1. 35

Because in this arithmetic operation there is only addition and subtraction, it can be calculated starting from anywhere.

But it should be noted that before the numbers (-8.44) and (-31.67) there is a negative sign (-) so you need to multiply the sign with the number in brackets. In this case the result is positive.

5 ) 6 5/12 - (-4 2/3) + (-2 3/4)= 5/12

In question number 5, it involves mixed fractions. To do this, you can change mixed fractions to improper fractions.

6 ) 4 1/8 - 6 2/9+ (-3 1/6) - (-5 3/4)= -49/72

In question number 6, it involves mixed fractions. To do this, you can change mixed fractions to improper fractions.

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Answer:

- 7\(x^{6}\)\(y^{9}\)

Step-by-step explanation:

using the rule of exponents

\(a^{m}\) × \(a^{n}\) = \(a^{(m+n)}\)

given

- 7x³\(y^{5}\) (x³\(y^{4}\))

= - 7 × x³ ×x³ ×\(y^{5}\) × \(y^{4}\)

= - 7 × \(x^{(3+3)}\) × \(y^{(5+4)}\)

= - 7\(x^{6}\)\(y^{9}\)

Answer:

Answer: The average speed is 54 miles per hour.

Answer:

56 mph

Step-by-step explanation:

You need to find the average of the speed for the five hour span of time.

If you're traveling at 50 mph for 2 hours, and 60 mph for 3 hours, then you can express each hour as 50, 50, 60, 60, 60. These are the speeds for each hour for your five hour trip. To find the average, add them all up and divide by the number of hours.

50+50+60+60+60 = 280

Then divide by five (the number of total hours).

280/5 = 56.

And there you go, there's the average speed of your trip (in bold).

Answer:

13

Step-by-step explanation:

In order to find u, we have to get u by itself. So first step is to divide both sides by 7, which you end up with:

\(u=\frac{91}{7}\)

and this simplifies to

u=13

Answer: on edge c. X + 8=5

Step-by-step explanation:

Answer: put the parallelograms in the box that says 2 pairs of parallel sides next put the squares in the box that says 4 right angles the put rectangles in the box that says 4 congruent sides and last put rhombuses in the middle box that says 4 right angles and 4 congruent sides

Step-by-step explanation:

Answer:

The answer is 6.07 x 10^5

Step-by-step explanation:

Answer:

6.07 x 10^5

Step-by-step explanation:

khan

Answer:

its b

Step-by-step explanation:

got it right on edge

The volume of the metal in the cylinderical pipe given the dimensions of the larger and smaller cylinders is 271.30 mm³.

A cylinder is a three-dimensional object. It is a prism with a circular base.

Volume of a cylinder = nr^2h

Where:

The volume of the metal in the cylinderical pipe = 3.14 x 10 x [(8.4/2)² - 6/2)²] = 271.30 mm³

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False. The percentage of children enrolled in public schools that are of non-Caucasian ancestry varies by location and can change over time. According to the National Center for Education Statistics (NCES), as of the 2018-2019 school year, the percentage of public school students who were non-Caucasian was around 50%.

According to the National Center for Education Statistics (NCES), as of the 2018-2019 school year, the percentage of public school students who were non-Caucasian was around 50%. So it is not true that over 62% of children enrolled in public schools are of non-Caucasian ancestry.

It's hard to say why the percentage of non-Caucasian students in public schools is less than 62%. It could be because of a variety of factors, such as demographic changes in the population, socioeconomic factors, or even educational policies. However, it's important to note that the percentage of non-Caucasian students in public schools can vary depending on location and can change over time.

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The solution to the initial value problem is:

y(t) = (-3/4) * e^(-4t+4) + (3/8) * e^(2t+8)

To solve a second-order linear homogeneous differential equation the equation is y′′ 2y′-8y = 0.

Given initial conditions: y(102) = 3 and y′(102) = -12.

To solve this differential equation, we can use the characteristic equation: r^2 + 2r - 8 = 0

Factoring this equation, we get: (r + 4)(r - 2) = 0

So the roots of the characteristic equation are r = -4 and r = 2.

The general solution to the differential equation is:

y(t) = c1 * e^-4t + c2 * e^2t

To find the values of c1 and c2, we can use the initial conditions.

We know that y(102) = 3, so we can substitute t = 2 into the general solution:

3 = c1 * e^-8 + c2 * e^4

We also know that y′(102) = -12, so we can take the derivative of the general solution and substitute t = 2:

y′(t) = -4c1 * e^-4t + 2c2 * e^2t

y′(102) = -4c1 * e^-8 + 2c2 * e^4 = -12

Solving for c1, we get:

c1 = (-3/4) * e^4 + (3/4) * e^-8

Solving for c2, we get:

c2 = (3/8) * e^8 - (3/8) * e^-4

Therefore, the solution to the initial value problem is:

y(t) = (-3/4) * e^(-4t+4) + (3/8) * e^(2t+8)

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the error bound for the estimate of 10√3 using the third Taylor polynomial for x√3 at x = 9 is 1/384

To find the error bound for the estimate of 10√3 using the third Taylor polynomial for x√3 at x = 9, we need to calculate the fourth derivative of x√3 and evaluate it at a suitable point.

The fourth derivative of x√3 is given by \(f^(4)(x)\) = \(3/8(x^(-7/2)).\) Evaluating this derivative at x = 9, we get \(f^(4)(9)\) = \(3/8(9^(-7/2))\)= 3/8(1/3) = 1/8.

According to Taylor's theorem, the remainder Rn(x) in the third degree Taylor polynomial is given by R3(x) = \(f^(4)(c)(x-a)^4/4!\), where c is some value between x and a.

Substituting the known values, we have R3(x) = (1/8)(x-9)^4/4!.

To bound the error, we need to find the maximum value of R3(x) in the interval between 9 and our desired approximation value of 10.

By substituting x = 10 into R3(x), we get R3(10) =\((1/8)(10-9)^4/4!\) = 1/384.

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The angle between the lines with slopes -1 and 0 is 45 degrees (or π/4 radians).

To find the angle between two lines given their slopes, we can use the formula:

θ = atan(|(m1 - m2) / (1 + m1 * m2)|)

where m1 and m2 are the slopes of the two lines.

In this case, we have two lines with slopes -1 and 0.

Let's calculate the angle:

θ = atan(|(-1 - 0) / (1 + (-1) * 0)|)

= atan(|-1 / 1|)

= atan(1)

The arctangent of 1 is 45 degrees (or π/4 radians).

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The simplified form of the expression \((x^4 - 4x^3 - 8x^2 + 9x + 2) / (x + 2)\) is \(x^3 - 6x^2 + 4x - 5 - 62/(x+2).\) This is achieved by polynomial division.

The solution using polynomial division can be shown as:

\(x+2 | x^4 - 4x^3 - 8x^2 + 9x + 2\)

\(- (x^4 + 2x^3)\)

----------------

\(-6x^3 - 8x^2\)

\(+ (6x^3 + 12x^2)\)

-------------------

\(-20x^2 + 9x\)

\(+ (20x^2 + 40x)\)

Therefore, the result of the division is \(x^3 - 6x^2 + 4x - 5\) with a remainder of 62.

So, the simplified form of the given expression is \(x^3 - 6x^2 + 4x - 5 - 62/(x+2).\)

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What is the simplified form of the expression (x^4 - 4x^3 - 8x^2 + 9x + 2) / (x + 2)

a) The null hypothesis H sub 0 is that the mean time for the mice to complete the maze with the loud noise is equal to 18 seconds, or H sub 0: µ = 18. The alternative hypothesis H sub a is that the mean time for the mice to complete the maze with the loud noise is less than 18 seconds, or H sub a: µ < 18. A Type I error would occur if the researcher rejects the null hypothesis and concludes that the loud noise causes the mice to complete the maze faster when in fact it does not. A Type II error would occur if the researcher fails to reject the null hypothesis and concludes that the loud noise does not cause the mice to complete the maze faster when in fact it does.

b) The null hypothesis H sub 0 is that the mean score for the teaching assistant's students is equal to 50, or H sub 0: µ = 50. The alternative hypothesis H sub a is that the mean score for the teaching assistant's students is greater than 50, or H sub a: µ > 50. A Type I error would occur if the teaching assistant rejects the null hypothesis and concludes that his students have a higher mean score than the class as a whole when in fact they do not. A Type II error would occur if the teaching assistant fails to reject the null hypothesis and concludes that his students do not have a higher mean score than the class as a whole when in fact they do.

c) The null hypothesis H sub 0 is that the mean percent of total spending on housing for households in the Cleveland metropolitan area is equal to 31%, or H sub 0: µ = 31%. The alternative hypothesis H sub a is that the mean percent of total spending on housing for households in the Cleveland metropolitan area is not equal to 31%, or H sub a: µ ≠ 31%. A Type I error would occur if the homebuilders association rejects the null hypothesis and concludes that the national finding does not apply in their area when in fact it does. A Type II error would occur if the homebuilders association fails to reject the null hypothesis and concludes that the national finding does apply in their area when in fact it does not.

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To find the correct equations for the missing boxes, we need more information about the relationships between the different activities in Jake's Gems. However, based on the given context, we can make some assumptions and suggest potential equations:

Mining and Cutting activities produce diamonds, rubies, and other gems. Let's assume that the production of each gem type is represented by a variable: D (diamonds), R (rubies), and G (other gems).

Maintenance supports the Mining and Cutting activities. We can assume that the maintenance effort required for each activity is represented by the variable M (maintenance).Since the question mentions five missing boxes, we can suggest additional equations to represent relationships between these variables, such as:

Mining + Cutting = D + R + G (the sum of all gem types produced equals the total production from Mining and Cutting activities).

Maintenance = M (maintenance effort required).

The relationships between these variables might include equations like D = f(M), R = g(M), G = h(M), where f, g, and h represent some functions or formulas that relate gem production to maintenance effort.

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Answer:

300 new employees

Step-by-step explanation:

1:3

x + 3x = 1,200

4x = 1200

x = 300

Answer:

V=3456

Step-by-step explanation:

V=\(a^{2}\)\(\frac{h}{3\\}\)

Answer:

no she will be 3 min late

Step-by-step explanation:

Therefore, According to the given information: W = 30 J (x=4.0m to x=7.0m), W = 40 J (x=0 to x=7.0m and x=7.0m to x=2.0m)

To calculate work, we use the formula W = F * d * cos(theta), where F is the force applied, d is the distance moved, and theta is the angle between the force and displacement vectors. Since the force is parallel to the x-axis, theta = 0 and cos(theta) = 1.
For the first question, the force is constant between x=4.0m and x=7.0m, so we can use W = F * d = (10 N)(3.0 m) = 30 J.
For the second question, we need to split the distance into segments where the force is constant. From x=0 to x=2.0m, the force is 0 N, so no work is done. From x=2.0m to x=4.0m, the force is 5 N, so W = (5 N)(2.0 m) = 10 J. From x=4.0m to x=7.0m, the force is 10 N, so W = (10 N)(3.0 m) = 30 J. Adding these up gives W = 40 J.
For the third question, we use the same approach as the second question but in reverse. From x=7.0m to x=4.0m, the force is 10 N, so W = (10 N)(3.0 m) = 30 J. From x=4.0m to x=2.0m, the force is 5 N, so W = (5 N)(2.0 m) = 10 J. From x=2.0m to x=0, the force is 0 N, so no work is done. Adding these up gives W = 40 J.

Therefore, According to the given information: W = 30 J (x=4.0m to x=7.0m), W = 40 J (x=0 to x=7.0m and x=7.0m to x=2.0m)

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