22. What is the difference between lodine-130 and lodine-131?

Answer:

the earth is green because the green part is the plants and tree.

Answer:

The excess carbon dioxide in the atmosphere has created a greener planet,

Explanation:

Answer:

A strong acid or a strong base should be neutralized before pouring down a drain.

Explanation:

Always make sure to add acid to water (not vice-versa) to avoid a nasty exothermic reaction :)

CsBr has a larger lattice energy than LiCl because Cs+ has a larger ionic radius and a greater charge than Li+.

The lattice energy of an ionic compound is determined by the strength of the electrostatic attraction between the ions in the solid crystal lattice. This attraction is influenced by the charges on the ions and the distance between them. The larger the charge on the ions, the greater the lattice energy, and the smaller the distance between them, the greater the lattice energy.

Br- also has a greater charge density than Cl-, making the electrostatic attraction between Cs+ and Br- stronger than that between Li+ and Cl-. Therefore, CsBr has a higher lattice energy than LiCl.

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The two main methods used to increase CO2 levels in beer after fermentation are natural carbonation and forced carbonation.

Natural carbonation involves adding a small amount of sugar to the beer before bottling or kegging. The residual yeast in the beer will consume the sugar, producing CO2 as a byproduct, which will dissolve into the beer, naturally carbonating it. This process can take anywhere from a few days to a few weeks, depending on the beer style and temperature.

Forced carbonation, on the other hand, involves using a CO2 tank to directly inject carbon dioxide into the beer. The beer is placed in a closed vessel and pressurized with CO2 until the desired level of carbonation is reached. This method is much quicker and more precise than natural carbonation, but it requires specialized equipment and can be more expensive.

Both methods have their advantages and disadvantages, and many breweries use a combination of both to achieve the desired level of carbonation for their beers. The level of carbonation can greatly affect the taste and mouthfeel of the beer, so it is an important consideration for brewers to get right.

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Answer:

epic

Explanation:

hakuna matata

Answer:

Explanation:

Absorption of digested food takes place in the small intestine.

Hope this helps

plz mark as brainliest!!!!!

Answer:

Absorption of digested food takes place in the small intestine.

Explanation:

Answer:

calcium=20

gold=79

copper=29

iron=26

Explanation:

Answer: C.) Xe

Explanation: To figure out the answer go to the Noble Gas Family and count down 5 elements.

According to the electronic configuration the symbol which would be included in the noble gas notation for an element that had valence electrons in the 5 s subshell is xenon  .

Electronic configuration is defined as the distribution of electrons which are present in an atom or molecule in atomic or molecular orbitals.It describes how each electron moves independently in an orbital.

Knowledge of electronic configuration is necessary for understanding the structure of periodic table.It helps in understanding the chemical properties of elements.

Elements undergo chemical reactions in order to achieve stability. Main group elements obey the octet rule in their electronic configuration while the transition elements follow the 18 electron rule. Noble elements have valence shell complete in ground state and hence are said to be stable.

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Answer:

the answer is 1

the  coefficient needed to balance this equation is 1

Explanation:

Answer: 5.6L

Explanation:

Just did it on an assignment

A 3.5L flexible container holds a gas at 250K. The new volume will be 5.6 L, if the temperature is increased to 400K.

Charles law is an ideal gas law which states that at a constant pressure volume of a gas is directly proportional to the absolute temperature.

It is expressed as

\(\frac{V_1}{T_1} = \frac{V_2}{T_2}\)

where,

V₁ = initial volume

T₁ = initial temperature

V₂ = final temperature

T₂ = final temperature

Now put the values in above formula, we get

\(\frac{V_1}{T_1} = \frac{V_2}{T_2}\)

\(\frac{3.5\ L}{250\ K} = \frac{V_2}{400\ K}\)

\(V_{2} = \frac{3.5\ L \times 400\ K}{250\ K}\)

\(V_{2} = \frac{1400}{250}\)

V₂ = 5.6 L

Thus, from the above conclusion we can say that A 3.5L flexible container holds a gas at 250K. The new volume will be 5.6 L, if the temperature is increased to 400K.

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The pH of the resulting solution when 250 mL of 2.1 M HBr is mixed with 200 mL of 2.5 M KOH is 12.7.

This can be calculated by first finding the moles of each of the reactants, and then using the ICE table to determine the concentration of ions in the solution. The equation for the ICE table is:

The concentration of H3O+ can then be determined by taking the square root of the KW, and the concentration of the OH- can be calculated by dividing the KW by the H3O+ concentration. The pH can then be calculated by taking the negative log of the H3O+ concentration.

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Answer:

Answer = 'A' => Sodium Hydroxide (NaOH)

Explanation:

Aqueous electrolysis of salt solutions finds the salt ions in competition with electrolysis of water at the respective electrodes. That is, water can undergo reduction at the cathode as can the cation of the salt; while at the anode water can undergo oxidation as can the anion of the salt. The competing reactions are as follows:

Cathode:
Cation + electrons => Reduced form of metal in Basic Standard State

H₂O(l) + 2e⁻ ⇄ 2OH⁻(aq) + H₂(g)

Anode:  

Anion ⇄ Basic Standard State element + electrons

2H₂O(l) ⇄ O₂(g) + 4H⁺(aq) + 4e⁻

Na⁺ + e⁻ => Na⁰(s); εo = -2.71v

2H₂O(l) + 2e⁻ ⇄ 2OH⁻(aq) + H₂(g); εo = -0.83v (Dominant Rxn at cathode – more positive value)

At the Anode:

Cl⁻(aq) => Cl₂(g) + 2e⁻; εo = 1.36v

2H₂O(l) => O₂(g) + 4H⁺ + 4e⁻; εo = 1.23v (Dominant Rxn at anode – more positive value)

Since the more dominant reaction at the cathode produces hydroxide ions, the solution would become alkaline with Na⁺ ions already present. NaOH will effect the change in color of red litmus to blue. The gases produced in the half-reactions would have evaporated and not be present for flame test.  

The distinction can be determined by comparing the 'Standard Reduction Potentials' of the half-reactions. At the cathode (site of reduction), the more positive electrode potential will dominate while at the anode (site of oxidation) the more negative electrode potential will dominate.  

For NaCl(s) => Na⁺(aq) + Cl⁻(aq) finds the ions in competition with the oxidation and reduction reactions of water.  

At the Cathode:

The balanced chemical equation between strong base and weak acid is represented as follows:

NaOH(aq)+ CH3COOH(aq)-----> CH3COONa(aq) + H2O(l)

When an acid reacts with a base, a salt is formed along with the formation of water, and this reaction is termed as neutralization reaction.

When a weak acid and a strong base are mixed, they react according to the following net-ionic equation: HA(aq) + OH⁻(aq) → A⁻(aq) + H₂O(l).

The balanced chemical equation between strong base and weak acid is represented as follows:

NaOH(aq)+ CH3COOH(aq)-----> CH3COONa(aq) + H2O(l)

Here, sodium hydroxide (NaOH) is a strong base and acetic acid (CH3COOH) is a weak acid.

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\(▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪\)

Na = 1

O = 1

H = 1

C = 1

O = 2

Ca = 3

O = 3

Mg = 2

Cl = 4

Answer:

C

Explanation:

It was the first to show that the atom had no net charge.

Answer: D

Explanation:

D - Decomposition of carbonates into oxide and carbon dioxide

A - Combustion reaction. Combustion of methane to form Carbon dioxide and water.

C - Reaction of reactive metal (Na) and water to form hydroxide.

B - No particular name of the reaction. Usually denoted as a synthesis redox reaction.

Answer:CaCO3  CaO + CO2

Explanation: just took it

Yes or No Reagent Formula of Precipitate:

   Reagent        Formula of Precipitate if YES

During laboratory work to separate \(Ca^2^+\) and \(Cu^2^+\) ions in aqueous solution, certain chemicals may be used to preferentially precipitate one of the ions. \(Ca^2^+\) ions can be precipitated into calcium sulfate \((CaSO_4)\)using \(K_2SO_4\). Similar to \(K_2S\), \(Cu^2^+\) ions can be precipitated as copper sulfide (CuS) using \(K_2S\).

Solubility mismatches between the precipitates produced and the residual ions in solution are what drive these precipitation reactions. \(Ca^2^+\) and \(Cu^2^+\) ions cannot be dissociated by KI. This knowledge is useful for formulating separation strategies that take into account the unique reactivity and solubility characteristics of the ions involved.

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Your question is incomplete, most probably the complete question is:

In The Laboratory You Are Given The Task Of Separating Ca2+ And Cu2+ Ions In Aqueous Solution. For Each Reagent Listed Below Indicate If It Can Be Used To Separate The Ions. Type "Y" For Yes Or "N" For No. If The Reagent CAN Be Used To Separate The Ions, Give The Formula Of The Precipitate. If It Cannot, Type "No" Y Or

In the laboratory you are given the task of separating Ca2+ and Cu2+ ions in aqueous solution.

For each reagent listed below indicate if it can be used to separate the ions. Type "Y" for yes or "N" for no. If the reagent CAN be used to separate the ions, give the formula of the precipitate. If it cannot, type "No"

Y or N Reagent Formula of Precipitate if YES

1. K2SO4

2. K2S

3. KI

Answer:

False,not all chemicals pollute the enviorment

Explanation:

Hope this helps!

Brainliest?

Answer:

False

Explanation:

Oxygen?

a. substituting in the expression of C(t) obtained in part a, we get,2500 = 12000/ (1 + 12000/ 5000 - 1) * e^(-2*3*t)  we get,t = 1/ (6 * log (2)) * log (5/3)≈ 0.276 h Therefore, it would take approximately 0.276 hours to reduce this concentration into C/2.

The differential equation for the indoor concentration of the given computer industry can be given as follows: dC/dt = P (0- C) - 2C²The above differential equation can be solved by the method of separating the variables as follows: dC/ (P (0- C) - 2C²) = dtIntegrating both sides, we get,-1/ [2P log (C/ (C- P0))] + (P0/ [P (C- P0)]) - (1/ (2C)) = t + c where c is the constant of integration. After simplification, the above equation can be expressed as:C(t) = P0/ (1 + (P0/ Co - 1) e^(-2Pt))The initial particle concentration Co is the value of C at t = 0. Hence, Ce = P0/ (1 + P0/ Co - 1) which can be simplified as Ce = Co/ (1 + P0/ Co - 1) = Co/P0b. Given that Co = 5000 cm³ and C/2 = 5000/2 = 2500 cm³,

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Taking into account the definition of dilution, if you needed to make 100 mL of a 0.2 M fruit drink solution from the 1.0 M fruit drink solution, you need to add more solvent until you get a final volume of 500 mL.

When it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

In this case, you know:

Replacing in the definition of dilution:

1 M× 100 mL= 0.2 M× Vf

Solving:

(1 M× 100 mL)÷ 0.2 M= Vf

500 mL= Vf

In summary, if you needed to make 100 mL of a 0.2 M fruit drink solution from the 1.0 M fruit drink solution, you need to add more solvent until you get a final volume of 500 mL.

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the law of mass action reflects the observation that an equilibrium state is reached by a chemical system regardless of the initial concentrations of reacting substances. in other words, a chemical system can reach equilibrium either from the reactants or from the products.

According to the rule of mass action, the rate of a reaction is thus inversely proportional to the product of the activity (or, to put it another way, concentration) of the reactants.

According to the rule of mass action, the chemical system can proceed from any direction, starting with a mixture of reactants or products, or even both, and eventually reaching a condition where the concentrations of reactants and products are in an equilibrium with a constant ratio.

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Since 12C’s molar mass is 12 grams, 48 grams of 12C atoms would be equal to 4 moles.

Carbon, is a chemical element having symbol C and its atomic number 6. Carbon atoms have six protons and usually have six neutrons in their nucleus, although isotopes of carbon with different numbers of neutrons exist.

Since the molar mass of 12C is 12 grams/mole, we can use the following formula to calculate the number of moles;

moles = mass / molar mass

Substituting the given values, we get;

moles = 48 g / 12 g/mol

moles = 4 mol

Therefore, 48 grams of 12C atoms is equal to 4 moles of 12C.

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Decomposition and synthesis are chemical processes that happen in opposition to one another.

A chemical substance splits or decomposes into two or more molecules during a decomposition process. The breakdown reaction is typically shown as AB A + B.

This sort of reaction is the opposite of synthesis reaction in that a final product or compound is converted into components or separate reactants. It is also known as chemical breakdown or chemical decomposition. An example of a decomposition reaction is CaCO3(s) CaO(s)+CO2(g).

Contrarily, in a synthesis process, different reactants come together to create a chemical molecule. As an illustration, the synthesis reaction CaO(s)+CO2(g) CaCO3(s) is the opposite of the decomposition process.

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Answer:

0.271J/g°C

Explanation:

mass of iron=93.3g

∆°C=65.58

mass of water=75g

C of water=4.184

∆°C=22.4-16.95=5.29°C

mc∆°C of iron = mc∆°C of water

93.3×C×5.29=75×4.184×5.29

C=75×4.185×5.29/93.3×65.58

C=0.271J/g°C

The term rate of reaction, RR, refers to the speed at which the reactants of a chemical reaction are turned into products. A) RR = 0.0047 M/s; B) RR = 0.0038 M/s; C) 0.0019 M/s.

When talking about the rate of reaction we refer to the speed at which a chemical reaction occurs, turning reactants into products.

It can be measured as

The formula to calculate the rate of reaction is the following,

RR = Δ concentration / Δ Time

Where,

In the exposed example, the chemical reaction is

                              NO₂(g) → NO(g) + 12 O₂(g)

So the rate of reaction can be measured according to

Since the collected data was the concentration of NO₂ as a function of time, then the rate of reaction was measured as the speed at which NO₂ was consumed.

A. What is the average rate of the reaction between 10 and 20 s?

Available data

RR = Δ concentration / Δ Time

RR = (0.951 - 0.904) / 20 - 10

RR = 0.074 / 10

RR = 0.0047 M/s

B. What is the average rate of the reaction between 50 and 60 s?

Available data

RR = Δ concentration / Δ Time

RR = (0.778 - 0.740) / 60 - 50

RR = 0.038 / 10

RR = 0.0038 M/s

C. What is the rate of formation of O₂ between 50 and 60 s?

Now, since NO₂ turns into NO and O₂, then

                  RR = Rate of NO₂ consumed = 2x rate of O₂ produced

If RR between 50 and 60 s is 0.0038 M/s, then the rate of formation of O₂ is,

Rate of NO₂ consumed / 2 =  rate of O₂ produced

0.0038 M/s / 2 = rate of O₂ produced

0.0019 M/s = rate of O₂ produced

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The gas sample is Cl₂. Answer A.

The ideal gas equation formula PV = nRT

Calculating the number of moles of the gas sample.

PV = nRT

1.04 × 1.365 = n × 0.0821 × 368

1.4196 = n × 30.21

n = 1.4196 ÷ 30.21

n = 0.04699 mol

The formula for mass and number of moles m = n × Mr

Calculating the molar gas from the sample

Mr = m ÷ n
Mr = 3.33 ÷ 0.04699

Mr = 70.9 g/mol

From the info given, gas Cl₂ has the same molar mass as the sample.

So, the gas sample is Cl₂, chlorine gas.

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Answer:

electron are on the outside of the nucleus and form rings

Explanation:

Answer:

Lithium and beryllium.

Explanation:

Answer: The new temperature is \(63^{o}C\).

Explanation:

Given: \(V_{1}\) = 1.90 L,    \(T_{1} = 21.0^{o}C\)

\(V_{2}\) = 5.70 L,         \(T_{2} = ?\\\)

Formula used to calculate new temperature is as follows.

\(\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\)

Substitute the values into above formula as follows.

\(\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{1.90 L}{21.0^{o}C} = \frac{5.70 L}{T_{2}}\\T_{2} = 63^{o}C\)

Thus, we can conclude that the new temperature is \(63^{o}C\).

The correct answer is (d) increases until reaching a maximum.

The substrate concentration has a significant effect on the rate of an enzyme-catalyzed reaction. Initially, as the substrate concentration increases, the reaction rate also increases proportionally.

This is because a higher substrate concentration provides more opportunities for the enzyme and substrate to collide and form an enzyme-substrate complex.

However, at some point, increasing the substrate concentration will no longer have a significant effect on the reaction rate, and the rate will reach a maximum.

This is because all of the enzyme active sites are saturated with substrate molecules, and any additional substrate molecules will not have an available active site to bind to.

Therefore, the correct answer is (d) increases until reaching a maximum.

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