2018 made $240,000.00. pay 10% for under $150,000.00 and %15 over $150,000.00, How much did you pay in taxes?

6. The probability that Flight A will have a full flight is 0.4163.

7. The probability that all passengers who show up will have a seat on the flight is 0.5731.

8. The probability that Flight B will have exactly 68 customers show up is 0.0904.

9. The probability that all passengers that show up will have a seat on the flight is 0.9707.

6. If the airline chooses not to oversell flight A and sells exactly 96 tickets, the probability that it will have a full flight can be calculated using the binomial distribution. Let X be the number of passengers who show up for the flight.

Then, X follows a binomial distribution with n = 96 and p = 0.97 (since the probability that a passenger shows up is 1 - 0.03 = 0.97). Thus, the probability that all 96 passengers show up is:

P(X = 96) = (96 choose 96) × \(0.97^{96}\) × \(0.03^0\) = 0.4163

So, the probability that Flight A will have a full flight is 0.4163.

7. If the airline oversells Flight A with 99 tickets sold, the probability that all passengers who show up will have a seat on the flight (i.e. 3 or more no-shows) can be calculated using the binomial distribution again. Let Y be the number of no-shows for the flight. Then, Y follows a binomial distribution with n = 99 and p = 0.03. We want to find the probability that Y is greater than or equal to 3 (i.e. there are 3 or more no-shows), which can be calculated as:

P(Y >= 3) = 1 - P(Y <= 2) = 1 - ((99 choose 0) × \(0.03^0\) × \(0.97^{99}\) + (99 choose 1) × \(0.03^1\) × \(0.97^{98}\) + (99 choose 2) × \(0.03^2\) × \(0.97^{97}\)) = 0.5731

So, the probability that all passengers who show up will have a seat on the flight is 0.5731.

8. If the airline oversells Flight B with 70 tickets sold, the probability that the flight will have exactly 68 customers show up can be calculated using the binomial distribution with n = 70 and p = 0.98 (since the probability that a customer shows up is 1 - 0.02 = 0.98). Let Z be the number of customers who show up for the flight. Then, the probability that exactly 68 customers show up is:

P(Z = 68) = (70 choose 68) × \(0.98^{68}\) × 0.02² = 0.0904

So, the probability that Flight B will have exactly 68 customers show up is 0.0904.

9. If the airline oversells Flight B with 72 tickets sold, the probability that all passengers who show up will have a seat on the flight can be calculated using the binomial distribution again. Let W be the number of no-shows for the flight. Then, W follows a binomial distribution with n = 72 and p = 0.02. We want to find the probability that W is less than or equal to 3, which can be calculated as:

P(W <= 3) = (72 choose 0) × \(0.02^0\) × \(0.98^{72}\) + (72 choose 1) × \(0.02^1\) × \(0.98^{71}\) + (72 choose 2) × \(0.02^2\) × \(0.98^{70}\) + (72 choose 3) × \(0.02^3\) × \(0.98^{69}\) = 0.9707.

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The reasonable domain for the function is (b) x > 0

From the question, we have the following parameters that can be used in our computation:

The function f(x) = 75x + 100

Where x is the number of hours

f(x) is the total cost.

In this case, the number of hours cannot be negative or 0

This means that the values of x in the function would be x > 0

These values of x are the domain

So, the reasonable domain for the function os (b) x > 0

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The area of the Shaded region, when the frame is 1 unit wide, is 20 square units.

The area of the shaded region when one rectangle is framed within another and the frame has a width of 1 unit, we need to calculate the difference between the areas of the outer rectangle and the inner rectangle.

the dimensions of the outer rectangle as length and width, and the dimensions of the inner rectangle as length' and width'. Based on the information provided, the length and width of the outer rectangle are 5 and 7 units, respectively.

The dimensions of the inner rectangle can be found by subtracting twice the width of the frame (1 unit) from the dimensions of the outer rectangle:

Length' = length - 2 * frame width = 5 - 2 * 1 = 3 units

Width' = width - 2 * frame width = 7 - 2 * 1 = 5 units

Now we can calculate the areas of the outer and inner rectangles:

Area of the outer rectangle = length * width = 5 * 7 = 35 square units

Area of the inner rectangle = length' * width' = 3 * 5 = 15 square units

Finally, to find the area of the shaded region, we subtract the area of the inner rectangle from the area of the outer rectangle:

Area of shaded region = Area of outer rectangle - Area of inner rectangle = 35 - 15 = 20 square units

Therefore, the area of the shaded region, when the frame is 1 unit wide, is 20 square units.

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Answer:

The cost of the mug is of $6.50.

Step-by-step explanation:

The cost of the mug and r refills is given by the following equation:

\(C(r) = 2.3r + 6.5\)

Cost of the mug:

The cost of the mug is found when no refills are bought, that is, C when \(r = 0\), which is \(C(0)\)

\(C(0) = 2.3*0 + 6.5 = 6.5\)

The cost of the mug is of $6.50.

Answer:

C and E

Step-by-step explanation:

23 > 16 and \(23\geq 16\) are both true statements since the quantity of 23 is greater than that of 16.

The completion of the inventory table is as follows:

A = $48

B = $264

C = $420

D = $304.

What methods are used for inventory?

Utilizing some of the inventory procedures, the aforementioned inventory table is finished.

The First-in, First-out (FIFO) principle presupposes that the physical flow of products sold corresponds to the order in which they were acquired.

The Last-in, First-out method (LIFO) bases the cost of products sold on the most recent inventory acquisitions.

The weighted-average technique calculates the ending inventory and cost of goods sold using the average cost of goods.

Allocating the expenses of products sold and ending inventory are not based on any presumptions in Specification Identification. It substitutes specified expenses instead.

Inventory Table:

                                    Units    Unit Cost    Total Cost

Jan. 1      Beg. Inventory   8        $6.00            $48 ($6 x 8)

April 11    Purchases        24       $11.00          $264 ($11 x 24)

May 17    Purchases        30      $14.00          $420 ($14 x 30)

Dec. 5    Purchases         19      $16.00          $304 ($16 x 19)

Total                                 81                         $1,036

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The velocities of the boat and the person relative to the shore are 1.337 m/s and 2.896 m/s, respectively.

We can use the conservation of momentum equation:

(mboat + mperson) * vboat = mperson * vperson

(160 kg + 70 kg) * vboat = 70 kg * (0.80 m/s + vperson)

230 kg * vboat = 56 kg * (0.80 m/s + vperson)

vboat = (56/230) * (0.80 m/s + vperson)

vperson = 0.80 m/s + vboat

vperson = 0.80 m/s + (56/230) * (0.80 m/s + vperson)

(174/115) * vperson = (504/115) * m/s

Dividing both sides by (174/115), we get:

vperson = 2.896 m/s

vboat = (56/230) * (0.80 m/s + vperson)

Substituting the value of vperson, we get:

vboat = 1.337 m/s

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On a 160-kg boat that is at rest with its bow pointed to the shore, a 70-kg person begins to walk from the bow to the stern at 0.80 m/s relative to the boat. What are the velocities of the boat and the person relative to the shore? Neglect the resistance of water to motion.

The rigid motion of the solid line figure is translated to the dotted line figure.

Translation describe a function that moves an object a certain distance.

In a translation, every point of the object must be moved in the same direction and for the same distance.

In translation, the object is not resized, rotated or reflected. The object usually remains the same but it moves a certain distance.

Therefore, the rigid motion maps the solid-line figure onto the dotted-line figure by translation

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Answer:

E: None of the above.

Step-by-step explanation:

14/40 is 35%, which is 0.35.

Answer:6 bookcases, 12 TV stands.

Step-by-step explanation:

We can model this using a system of equations. Let b represent how many bookcases he makes, and t how many TV stands he makes. He can make at most 18 pieces, so let's say that b+t <=18. The cost of the bookcases are 20, and the TV stands are 40, so 20b+40t gives us our total cost. We have 600 to spend, so 20b+40t <=600. We want to maximize the equation for profit, which is 60b+100t=P. We have three values we care about, where our inequalities intersect, if we have only TVs, and if we only have bookcases.  But, if b=0 and t=18, then our cost is 720, which is too big. So if we only have tv stands, then we can have at most 15 (40*15=600). So our three cases are: (b=0, t=15), (t=0, b=18), and the intersection, which is where the inequalities are equal. To solve that, b=18-t, 20(18-t)+40t=600, 360-20t+40t=600, 360+20t=600, 20t=240, t=12. b=18-t, b=18-12, b=6. So our final case is (b=6, t=12). Now simply plug those three cases into our equation to maximize, 60*0+15*100=1500. 18*60+0*100=1080. 6*60+12*100=1560. So, our third case yields us the highest profit, and Andrew should make 6 bookcases and 12 TV stands.

Answer:

Step-by-step explanation: 21

The probability that it is raining if the flight has been delayed is 0.07, or 7%.

We can use the following formula to calculate the probability that it is raining if the flight has been delayed:

P(Rain|Delayed) = P(Rain and Delayed) / P(Delayed)

We are given that P(Rain) = 0.07 and P(Delayed) = 0.18. We can also use the fact that P(Rain and Delayed) = P(Rain) * P(Delayed):

= 0.07 * 0.18

= 0.0126.

Substituting these values into the formula, we get:

P(Rain|Delayed) = 0.0126 / 0.18 = 0.07

Therefore, the probability that it is raining if the flight has been delayed is 0.07, or 7%.

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Answer:

Its new price is 176.88

Step-by-step explanation:

change the 33% to a decimal (.33) then multiply the decimal with the 536

looks something like this:

  536(.33)

then solve.

Hopes this helps.

True: Solving a system of equations using the graphing, substitution, or elimination method will find the exact same solution.

False: Elimination can never be used to solve a nonlinear system of equations (a system where one equation is not linear).

A system of equations can be defined an algebraic equation that only has two (2) variables and can be solved simultaneously.

In Mathematics, there are three (3) main methods that are commonly used for solving a system of equations simultaneously and these include the following:

Generally speaking, the same solution would be obtained when any of the three (3) methods for solving a system of equations are used. However, it is completely false to state that the elimination method cannot be used to solve a nonlinear system of equations.

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Answer:

\(y=-\frac{3}{2}\)

Step-by-step explanation:

\(\text{y = kx where k is a constant.}\)

\(6 = -4k\\k = \frac{6}{-4} =-\frac{3}{2}\)

9514 1404 393

Answer:

  D

Step-by-step explanation:

The inequality symbol is < (not ≤), which means the end point of the graph will be an open circle.

After dividing by the coefficient of x, you have an inequality of the form ...

  x +( ) < ( )

which means the solution will be left of the (open circle) end point of the graph. Only one graph has that form.

__

If you actually work through the numbers, you get ...

  x +8 < 9 . . . . . . divide both sides by 2.9

  x < 1 . . . . . . . . . subtract 8 from both sides

Answer:

  18 cubic inches

Step-by-step explanation:

The formulas for the volumes of a cone and a cylinder can be used to answer this question.

The volume of a cone is given by ...

  V = 1/3πr²h . . . . . volume of cone with radius r and height h

The volume of a cylinder is given by ...

  V = πr²h . . . . . volume of a cylinder with radius r and height h

Comparing the formulas, we see that the volume of a cone is 1/3 the volume of a cylinder with the same radius and height.

  (cone volume) = 1/3(cylinder volume)

Multiplying this equation by 3 gives ...

  3×(cone volume) = (cylinder volume)

Using the given value for cone volume, we have ...

  cylinder volume = 3×(6 in³) = 18 in³

The volume of the cylinder is 18 cubic inches.

Answer:

x=6 bc Diagonals are equal in a parallelogram.

Answer: x = 6

Explanation:

An existing rule states that the diagonals of a parallelogram bisect each other. Therefore, the length of the halved diagonal is equal.

Answer:

3072

i hope this helps :)

Answer:

3072

Step-by-step explanation:

First, find the common ratio and the first term. The common ratio is 6/3 or 2. The first term is 3.

Use the direct formula, xi=a*r^i-1, to find the 11th term. A is the first term, and i is the index or the number of the term.

Substitute: x11=3*2^(11-1)

Or x11=3*2^10

So x11 is 3072

Answer:

2 forms

Step-by-step explanation:

hope this helps <3

\( \sf \longrightarrow \: \frac{8}{5} \div 6 \\ \)

\( \sf \longrightarrow \: \frac{5}{8} \times 6 \\ \)

\( \sf \longrightarrow \: \frac{5 \times 6}{8} \\ \)

\( \sf \longrightarrow \: \frac{30}{8} \\ \)

\( \sf \longrightarrow \: \frac{8}{30} \\ \)

\( \sf \longrightarrow \: 0.26 \\ \)

_____________________________

By using the graph of g, the solution to g(3) is equal to 8.

In Mathematics and Geometry, a function can be defined as a mathematical expression which is typically used for defining and representing the relationship that exists between two or more variables such as an ordered pair in tables or relations.

In Mathematics and Geometry, a domain is sometimes referred to as input value and it can be defined as the set of all real numbers for which a particular function is defined.

When the domain (input value) of the given function g(x) shown in the graph is 3, the output value (range) is given by;

g(3) = 8.

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

A geometric series is one in which there is a constant between two successive numbers in the series.

When there is a constant between the two successive numbers in the series then it is called a geometric series. In other words, every next term is multiplied by that constant term to form a geometric progression.

The sequence in which every next number is the addition of the constant quantity in the series is termed the arithmetic progression

Suppose the series is given as

2,4,8,16,32,64.........

The common difference is defined as the ratio of the next term to the previous term.

From the above series, the common ratio is calculated as,

Common ratio = 4 / 2

Common ratio = 2

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The numbers as an integer or not are:

From the question, we have the following parameters that can be used in our computation:

7/10 - yes or no

-6/1 - yes or no

-30.18 - yes or no

7 - yes or no

-76 - yes or no

integers are numbers without decimal point (including 0)

Using the above as a guide, we have the following:

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Answer:

The test statistic for this test is: z = -2.60, option b.

Step-by-step explanation:

The test statistic is:

\(z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}\)

In which X is the sample mean, \(\mu\) is the value tested at the null hypothesis, \(\sigma\) is the standard deviation and n is the size of the sample.

H0: p = 0.50 vs HA : p≠0.50

This means that \(\mu = 0.5, \sigma = \sqrt{0.5*0.5} = 0.5\)

A random sample of 900 13- to 17-year-olds found that 411 had a computer in their room with Internet access.

This means that \(n = 900, X = \frac{411}{900} = 0.4567\)

Value of the test-statistic:

\(z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}\)

\(z = \frac{0.4567 - 0.5}{\frac{0.5}{\sqrt{900}}}\)

\(z = -2.598\)

The test statistic for this test is: z = -2.60, option b(should be).