200 L of a gas at 10 atm pressure and 400 K is cooled to 100 K and reduced to 2 atm pressure. What is the new volume?

Answer:

D i belive

Explanation:

A redox reaction's hydroxide ion component involving oxidation or reduction is referred to as a half reaction. By taking into account, we get a half reaction.

The diatomic anion OH, which is made up of oxygen and hydrogen atoms, is most frequently referred to in chemistry as hydroxide. It is among the known simplest diatomic ions. The group of substances that contain the hydroxide ion is referred to as "hydroxide" as well.

Galvanic cell with Zn and Cu as an example. CuSO4(aq) Zn(s) + CuSO4(aq) (s) Oxidation occurs at the Zn anode (the metal loses electrons). This can be seen in the oxidation half-reaction shown below (see how the electrons are on the products side): Zn(s) equals Zn2+ + 2e.

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The specific heat capacity of the metal object is approximately -4.88 J g^(-1) °C^(-1).

To solve this problem, we can apply the principle of conservation of energy. The heat lost by the hot water and metal object is equal to the heat gained by the cold water and the calorimeter. The heat gained or lost can be calculated using the equation:

q = m * c * ΔT

Where:

q is the heat gained or lost

m is the mass of the substance

c is the specific heat capacity of the substance

ΔT is the change in temperature

First, let's calculate the heat gained by the cold water:

q_cold = m_cold * c_water * ΔT_cold

m_cold = mass of cold water = 50.01 g

c_water = specific heat capacity of water = 4.184 J g^(-1) °C^(-1)

ΔT_cold = final temperature - initial temperature = 35.9°C - 0.5°C = 35.4°C

q_cold = 50.01 g * 4.184 J g^(-1) °C^(-1) * 35.4°C = 7427.87 J

Next, let's calculate the heat gained by the calorimeter:

q_calorimeter = m_calorimeter * c_aluminum * ΔT_calorimeter

m_calorimeter = mass of calorimeter (aluminum cup) = 39.78 g

c_aluminum = specific heat capacity of aluminum = 0.903 J g^(-1) °C^(-1)

ΔT_calorimeter = final temperature - initial temperature = 35.9°C - 0.5°C = 35.4°C

q_calorimeter = 39.78 g * 0.903 J g^(-1) °C^(-1) * 35.4°C = 1267.65 J

Now, let's calculate the total heat gained by the hot water and metal object:

q_total = q_cold + q_calorimeter = 7427.87 J + 1267.65 J = 8695.52 J

Finally, we can calculate the specific heat capacity of the metal object:

q_total = m_metal * c_metal * ΔT_metal

m_metal = mass of metal object = 49.98 g

ΔT_metal = final temperature - initial temperature = 35.9°C - 69.5°C = -33.6°C (negative because it lost heat)

c_metal = q_total / (m_metal * ΔT_metal)

c_metal = 8695.52 J / (49.98 g * (-33.6°C)) = -4.88 J g^(-1) °C^(-1)

The specific heat capacity of the metal object is approximately -4.88 J g^(-1) °C^(-1).

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Answer:

At 4°C what is not able to decompose into hydrogen and oxygen chemical changes cannot be reverted, in this case it can. It will not change color, because water is always clear, and won't at this state turn into ice. though it can be reverted.

Explanation:

I hope that is correct that's all I've learned so far!

Answer:

A) Its temperature

Explanation:

Increasing atomic radius can have a significant impact on the crystal structure of a material, affecting parameters such as interatomic distances, coordination numbers, lattice parameters, symmetry, and mechanical properties.

As the atomic radius increases, there are several effects on the crystal structure of a material:

1. Interatomic Distance: With increasing atomic radius, the average distance between neighboring atoms in a crystal lattice also increases. This leads to a larger unit cell and a decrease in atomic packing density.

2. Coordination Number: The coordination number refers to the number of atoms surrounding an atom in a crystal lattice. As the atomic radius increases, the coordination number may change. For example, a smaller atom might have a higher coordination number, while a larger atom might have a lower coordination number. This can influence the overall structure and stability of the crystal.

3. Lattice Parameters: The lattice parameters, such as the lattice constant or unit cell dimensions, may be affected by changes in atomic radius. An increase in atomic radius can result in an expansion of the crystal lattice, leading to changes in the lattice parameters.

4. Symmetry: Changes in atomic radius can affect the symmetry of the crystal structure. Larger atoms may disrupt the symmetry and introduce distortions or vacancies in the crystal lattice.

5. Mechanical Properties: The mechanical properties of a material, such as its strength, hardness, and flexibility, can be influenced by changes in atomic radius. Alterations in atomic size can affect the bonding forces between atoms and, consequently, the material's mechanical behavior.

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Answer:

See explanation

Explanation:

The structure of ethylene is shown in the image attached. The two carbon atoms have a double covalent bond between them.

The two carbon atoms are sp2 hybridized. The bond between them is a covalent bond, there is one pi bond and one sigma bond between the carbon atoms. Between carbon and hydrogen, there are covalent bonds also. The covalent bonds are sigma bonds.

The pi bonds between carbon atoms is weaker than the sigma bonds between the carbon atoms. This is because, the side-by-side overlap the p orbitals in a pi bond is less effective than the end-to-end overlap of a sigma bond.

The group 1 element; the alkali metals which are lithium, sodium and potassium have a pattern of reactivity such that they produce alkali when they dissolve in water.

The chemical equation is given below:

Na(s) + H2O(l) --- NaOH(aq) + H2(g)

K(s) + H2O(l) --- KOH(aq) + H2(g)

These are the metals which belong to the group 1 of the periodic table. They are called alkali metals because when they react with water, they produce soluble hydroxide known as alkali. For this reason, they are referred to as alkali metals.

So therefore, the group 1 element; the alkali metals which are lithium, sodium and potassium have a pattern of reactivity such that they produce alkali when they dissolve in water.

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The mass of a substance is the product of its density and volume. Thus, the   mass of the dissolved solids with a density of 125 mg/dm³ with a volume of 250 cm³ is 31.25 mg.

Density of a substance is the measure of its mass per unit volume. Thus it describes how much denser the substance is in a given volume. Mathematically it is the ratio of mass to the volume.

Density of a substance depends on the mass, volume, bond type, temperature and pressure. The ratio of density of a substance with the density of water is called its specific gravity.

It is given that the density of the dissolved solids is 125 mg/dm³ and the volume is 250 cm³ or 0.25  dm³. Thus the mass can be calculated as follows:

density = mass/volume

 mass   = density × volume

             = 0.25  dm³  ×  125 mg/dm³

             = 31.25 mg

Hence, the mass of the dissolved solids in the river wayer is 31.25 M=mg.

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Multiply the amount in moles by the molar mass.

To obtain the mass in grams from the amount in moles, you need to multiply the number of moles by the molar mass of the substance. The molar mass is the mass of one mole of a substance and is expressed in grams per mole (g/mol).

The formula to calculate the mass (m) in grams from the number of moles (n) and the molar mass (M) is:

m = n x M

Thus the mass in grams is obtained by multiplying with the molar mass of the compound.

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Iodine is an essential element that the human body needs for proper thyroid function and the production of thyroid hormones. Thyroid hormones play a vital role in many important bodily functions, including metabolism, growth, and development. However, in areas where soil and water are deficient in iodine, people may not consume enough iodine in their diet, leading to iodine deficiency.

To address this issue, the United States government began adding iodine to table salt in the 1920s, a practice that continues to this day. This is known as iodized salt. Iodized salt is a simple and cost-effective way to ensure that the population gets enough iodine in their diet to prevent iodine deficiency, which can cause a range of health problems, including goiter (enlarged thyroid gland), hypothyroidism, and intellectual disabilities in children.

Iodine deficiency is still a significant problem in many parts of the world, particularly in developing countries. The addition of iodine to salt has been one of the most successful public health interventions in history, helping to prevent iodine deficiency and its associated health problems.

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Answer:

dd

Explanation:

dddddddddddddddddddddddddddddddddddddd

After a helium flash, which occurs in the core of a star during the later stages of its evolution, the star enters a stable phase of helium burning. During the flash, helium ignites explosively, producing a burst of energy that causes the core to expand and cool.

However, once the temperature and pressure in the core have reached the required levels again, helium burning resumes, producing energy and keeping the star stable. This process continues until the star exhausts its helium fuel, at which point it may undergo further nuclear reactions or collapse, depending on its mass. The helium flash is a crucial stage in the evolution of low- to medium-mass stars, allowing them to continue burning and shining for billions of years.

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The characteristic of science that is missing from this experiment is that "the results are not reliable because the airplanes were only tested one time".

In conclusion, the correct option is D.

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Answer:

D

Explanation:

In chemistry, hypochlorite is an anion with the chemical formula ClO−. It combines with a number of cations to form hypochlorite salts. The pKb for hypochlorous anions, ClO-, is 6.48 at 25°C

The Ka expression for hypochlorous acid, HClO, is:

Ka = [H+][ClO-] / [HClO]

At 25°C, the value of Ka for HClO is \(3.0*10^{-8}\). We can use this value to calculate the Kb expression for its conjugate base, hypochlorite ion, ClO-:

Kw = Ka x Kb

where Kw is the ion product constant for water, which is \(1.0*10^{-14}\) at 25°C.

Solving for Kb, we get:

Kb = Kw / Ka = (\(1.0*10^{-14}\)) / (\(3.0*10^{-8}\)) = \(3.33*10^{-7}\)

Now, we can use the relationship between Ka and Kb to calculate the pKb of hypochlorite ion:

pKb = -log(Kb) = -log(\(3.33*10^{-7}\)) = 6.48

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Answer:
Answer 1: The mass of magnesium contained in the compound is 0.57g, which can be determined by subtracting the mass of the crucible and lid (31.064g) from the mass of the crucible, lid, and magnesium ribbon (31.634g).

Answer 2: The mass of oxygen contained in the compound is 1.39g, which can be determined by subtracting the mass of the crucible, lid, and magnesium oxide (31.970g) from the mass of the crucible and lid (31.064g).

Answer 3: The change in mass between the two can be accounted for by the reaction of the magnesium with oxygen to form magnesium oxide.

Answer 4: The number of moles of magnesium is 0.0995 (2.39/24) and the number of moles of oxygen is 0.0868 (1.39/16). Dividing the moles of each element by the smallest amount of moles (0.0868) results in a simplest ratio of 1:1. Therefore, the empirical formula of magnesium oxide is MgO.

Answer 5: The known formula for magnesium oxide is MgO, which is the same as the empirical formula determined in question 4.

Answer:

The density of aluminum is 2.7 g/cm³. Thus given sample is aluminum.

Explanation:

Given data:

Mass of sample = 54 g

Volume of sample = 20 cm³

Density of sample = ?

Is the sample is aluminum = ?

Solution:

We will calculate the density from given mass and volume.

d = m/v

d = density

m = mass

v = volume

d = 54 g/ 20cm³

d =  2.7 g/cm³

From literature it is known that the density of aluminum is 2.7 g/cm³. Thus given sample is aluminum.

Answer:

a) 3.16 m

b) 0.39 M

Explanation:

a)

The wavelength of a radio wave with a frequency of 95 x 10^6 Hz can be calculated using the formula:

wavelength = speed of light / frequency

The speed of light is approximately 3 x 10^8 m/s. Substituting the given values:

wavelength = (3 x 10^8 m/s) / (95 x 10^6 Hz)

wavelength ≈ 3.16 m (rounded to 2 significant figures)

Therefore, the wavelength of the radio wave is approximately 3.16 meters.

b)

The molarity (M) of a solution can be calculated using the formula:

Molarity = moles of solute / liters of solution

Substituting the given values:

Molarity = 0.44 mol / 1.12 L

Molarity ≈ 0.39 M (rounded to 2 significant figures)

Therefore, the molarity of the solution is approximately 0.39 M.

2 asymmetric carbon atoms are present in the molecule shown.

Asymmetric carbon atoms, also known as chiral carbon atoms or stereogenic carbon atoms, are carbon atoms that are bonded to four different groups or atoms. They are important in organic chemistry because they give rise to molecular asymmetry and the existence of enantiomers.

The presence of an asymmetric carbon atom in a molecule leads to chirality, which is the property of having two non-superimposable mirror image forms (enantiomers). Enantiomers have identical physical and chemical properties, except for their interaction with other chiral molecules, such as in biological systems.

The existence of enantiomers is significant because they can exhibit different biological activities, pharmacological effects, and reactivities. For example, one enantiomer of a drug may be therapeutically effective, while its enantiomer could be biologically inert or even produce adverse effects.

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Answer:

Ionization Energy

Explanation:

Answer:

In general, the magnetic field is strongest close to the wire and weaker farther away. In fact, the magnetic field weakens as 1/r1/r where rr is the distance from the wire. This can change a bit depending on the length and shape of the wire. Far enough away, the magnetic field decays as 1/r21/r2 .

Answer:

Closest to the wire

Explanation:

In general, the magnetic field is strongest close to the wire and weaker farther away. In fact, the magnetic field weakens as where is the distance from the wire. This can change a bit depending on the length and shape of the wire.

The Answer For Your Question is:

A) F

There could be several reasons why a student produced less magnesium oxide than expected. Here are two possibilities: Incomplete reaction,  Loss of product

Incomplete reaction: Magnesium oxide is produced when magnesium metal is heated in the presence of oxygen. However, if the reaction is incomplete, then less magnesium oxide will be produced. One reason for incomplete reaction could be that the temperature was not high enough to provide the necessary activation energy.

Loss of product: It is possible that some of the magnesium oxide that was produced was lost during the experiment. For example, if the magnesium oxide was not handled carefully after it was produced, it may have been spilled or blown away.

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Answer:

1) KI

2) Mg3P2

3) Ag2S

4) FeBr3

5) Mg(OH)2

6) Na2SO4

7) Pb(NO3)4

8) (NH4)2CO3

A meso compound is an achiral compound that has chiral centers, but it also has a plane of symmetry that divides the molecule into two congruent halves. Option  A is correct .

The molecule can rotate the polarization plane in both directions to the same extent. Here, we have four cyclic compounds, so let's look at each one. Cyclohexane: Since there are no chiral centers, it cannot be a meso compound.

                                     Cyclopentane: Cyclopentane is also not a meso compound because it doesn't have any chiral centers.Cyclopropane: Cyclopropane, on the other hand, has chiral centers; however, there is no plane of symmetry in the molecule.

                               As a result, cyclopropane is not a meso compound. Cyclooctane: Cyclooctane, like cyclohexane, lacks chiral centers, and it is also not a meso compound. Since none of the cyclic molecules has a plane of symmetry, it can be concluded that none of them is a meso compound. Hence, the answer is that none of the cyclic molecules are meso compounds.

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Answer:

it will option B ,hope it helps

The two universal electron acceptors that take electrons from the citric acid cycle and glycolysis are: a. FADH2,  b. NAD+.

In both the citric acid cycle and glycolysis, energy-rich molecules such as glucose are broken down to produce energy in the form of ATP. During these processes, electrons are transferred from various molecules to electron carriers, which act as electron acceptors.

FADH2 (flavin adenine dinucleotide) and NAD+ (nicotinamide adenine dinucleotide) are two important electron carriers involved in these metabolic pathways.

FADH2 is the reduced form of FAD, and it accepts electrons during the citric acid cycle. It is formed when succinate is oxidized to fumarate, and it delivers electrons to the electron transport chain to generate ATP.

NAD+ is the oxidized form of NADH, and it accepts electrons during both the citric acid cycle and glycolysis. In the citric acid cycle, NAD+ accepts electrons when isocitrate is converted to alpha-ketoglutarate and when malate is converted to oxaloacetate. In glycolysis, NAD+ accepts electrons during the oxidation of glyceraldehyde-3-phosphate to 1,3-bisphosphoglycerate.

On the other hand, FAD (flavin adenine dinucleotide) is not a universal electron acceptor. It is the oxidized form of FADH2, and it acts as a carrier of electrons rather than an acceptor.

Oxygen (e) is the final electron acceptor in the electron transport chain, which occurs after the citric acid cycle and glycolysis. It accepts electrons from NADH and FADH2 to form water.

The two universal electron acceptors that take electrons from the citric acid cycle and glycolysis are FADH2 and NAD+. FADH2 accepts electrons during the citric acid cycle, while NAD+ accepts electrons in both the citric acid cycle and glycolysis.

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the answer to you question is -2

Answer:

So that we know how many electrons are thre in which shell and how many shells are present in an atom....

Explanation:

Hope it helps!!!

The half life of the sample is 14 hours and the time taken is 97 hours.

We know that radioactivity has to do with the fact that there is element decomposed within a given time frame. Let us note that the half life has to do with the time taken for only half of the radioactive material to remain.

We can see that the time that is taken for only half of the sample to remains is about 14 hours.

We now know that;

N/No = (1/2)^t/\(t_{\frac{1}{2} }\)

N = Number of atoms

No = Initial number of atoms

t = time taken

\(t_{\frac{1}{2} }\) = The half life

Then we have;

2.5/320 = (1/2)^ t/14

7.8 * 10^ -3 = (0.5)^t/14

ln(7.8 * 10^ -3 ) = t/14 ln(0.5)

t = ln(7.8 * 10^ -3 ) / ln(0.5) * 14

t = -4.8/-0.693 * 14

t = 97 hours

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