The length of an open-open pipe with a 594 Hz fundamental frequency is roughly 0.35 metres.
The formula f = (n/2L)*v, where f is the frequency, n is the harmonic number (n=1 for the fundamental frequency), L is the length of the pipe, and v is the speed of sound in air (roughly 343 m/s at room temperature), determines the fundamental frequency of an open-open pipe (a pipe open at both ends). L = (n/2) * v/f is the result of rearrangement of the equation to solve for L. When the given values are substituted, we obtain L = (1/2) * 343/594 = 0.35 metres. The pipe is roughly 0.35 metres long as a result.
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A piece of wood, with a volume of 0.48 m³, is floating in water with half of it is submerged. What is the buoyant force acting on the wood? Density of water is 1000 kg/m³ Consider g = 10 m/s2
A cylindrical column of water has a height of 5.3 m and a crosssectional area of 2.7 m². The density of water is 1000 kg/m3 What is the pressure of the water column at the base of the column? g = 10 m/s²
The buoyant force acting on the wood is 2400 Newtons.
Pressure of water column at the base is 53,000 Pascal (53 kPa).
To calculate the buoyant force acting on the wood, we need to determine the volume of water displaced by the submerged portion of the wood.
Given:
Volume of wood (V_wood) = 0.48 m³
Density of water (ρ_water) = 1000 kg/m³
Acceleration due to gravity (g) = 10 m/s²
Since half of the wood is submerged, the volume of water displaced (V_water) is equal to half the volume of the wood.
V_water = V_wood / 2
= 0.48 m³ / 2
= 0.24 m³
The buoyant force (F_buoyant) acting on an object submerged in a fluid is equal to the weight of the displaced fluid. Therefore, we can calculate the buoyant force using the following formula:
F_buoyant = ρ_water * V_water * g
Plugging in the given values:
F_buoyant = 1000 kg/m³ * 0.24 m³ * 10 m/s²
= 2400 N
Therefore, the buoyant force acting on the wood is 2400 Newtons.
To calculate the pressure of the water column at the base, we can use the formula:
Pressure = ρ_water * g * h
Given:
Height of the water column (h) = 5.3 m
Cross-sectional area of the column (A) = 2.7 m²
Density of water (ρ_water) = 1000 kg/m³
Acceleration due to gravity (g) = 10 m/s²
Substituting the values into the formula:
Pressure = 1000 kg/m³ * 10 m/s² * 5.3 m
= 53,000 Pascal (Pa)
Therefore, the pressure of the water column at the base is 53,000 Pascal or 53 kPa.
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You may have already used the Blackbody Spectrum simulation to see how the temperature of a substance affects how light is emitted. Many of the light sources you’re familiar with are incandescent light sources. They glow because they have a nonzero temperature. The hotter the source, the more radiant energy it gives off. Now, let’s explore a few different incandescent energy sources and investigate their lighting efficiency. In this simulation, the curve represents the radiation intensity and energy emitted with respect to the wavelength at a given temperature.
To begin, launch the Blackbody Spectrum simulation.
The Blackbody Spectrum simulation allows us to explore how the temperature of incandescent light sources affects their emitted light.
First, discuss the relationship between temperature, radiant energy, and lighting efficiency.
Incandescent light sources emit light due to their nonzero temperature. As the temperature of the source increases, the amount of radiant energy it gives off also increases. The Blackbody Spectrum simulation helps us visualize how the temperature of a substance affects the way light is emitted.
In the simulation, a curve represents the radiation intensity and energy emitted with respect to the wavelength at a given temperature. As the temperature rises, the curve's peak shifts towards shorter wavelengths, and the area under the curve increases. This shift indicates that the emitted light becomes more energetic and intense.
However, not all of this emitted energy is in the visible spectrum; a significant portion can be in the form of infrared radiation (heat). Incandescent light sources are not very energy-efficient, as a large portion of their energy output is wasted as heat rather than visible light. The lighting efficiency of an incandescent source is determined by the percentage of radiant energy that falls within the visible spectrum.
To summarize, the Blackbody Spectrum simulation allows us to explore how the temperature of incandescent light sources affects their emitted light. As the temperature increases, the emitted radiant energy also increases. However, a considerable amount of energy is lost as heat, making incandescent sources less energy-efficient compared to other lighting technologies.
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Please select the word from the list that best fits the definition
Creates an image that is reflected through a focal point
A) Plane mirror
B) concave mirror
C) diffuse reflection
D) Specular reflection
Pls help :'(
Answer: the answer is B) Concave mirror
Explanation:
Does Santa Maria have a globe effect
Answer:
I don't think so
Explanation:
Answer:
yes
Explanation:
Two persons are applying forces on two opposite sides of a moving cart. The cart still moves with the same speed in the same direction. What do you infer about the magnitudes and direction of the forces applied?Explain.
Explanation:
If two persons are applying forces on two opposite sides of a moving cart and the cart still moves with the same speed in the same direction we can infer that the magnitudes of the forces applied by the two persons are equal and the direction of the forces is opposite to each other.
This is because of Newton's First Law of Motion which states that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force. In this case the cart is already in motion and is moving in a straight line. The forces applied by the two persons are external forces acting on the cart. Since the cart is moving with the same speed and in the same direction we can infer that the forces applied by the two persons are equal in magnitude and opposite in direction.
This is also known as the principle of action and reaction which is the third law of motion. According to this law for every action there is an equal and opposite reaction. In this case the action is the force applied by the two persons on the cart and the reaction is the force exerted by the cart on the two persons in the opposite direction.
A 1,168-kg car comes to a stop without skidding. The car's brakes do -23,180 J of work
to stop the car.
Which of the following was the car's velocity when the brakes were initially applied?
The initial velocity of the car when the brake was initially applied is 6.3 m/s.
option D is the correct answer.
What is the velocity of the car when the brake was initially applied?
The velocity of the car when the brake was initially applied is calculated as follows;
Mathematically, kinetic energy formula is given
K.E = ¹/₂mv²
where;
m is the mass of the speedv is the speed of the car when the brake was initially appliedmv² = 2 K.E
v² = ( 2 K.E ) / ( m)
v = √ [ ( 2 K.E ) / ( m) ]
Substitute the given parameters and solve of the initial velocity of the car when the brake was applied.
v = √ [ ( 2 x 23,180 ) / ( 1168) ]
v = 6.3 m/s
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The complete question is below:
A 1,168-kg car comes to a stop without skidding. The car's brakes do -23,180 J of work
to stop the car.
Which of the following was the car's velocity when the brakes were initially applied?
A. 3.2 m/s
B. 1.7 m/s
C. 5.1 m/s
D. 6.3 m/s
What happens in the gray zone between solid and liquid?
MORE POINTSSSSSSS TAKE 'EM SOOOONNNNNN
Please Answer the question to get them
Answer:
Hence from liquid to solid or solid to liquid the transition has to cross the grey zone. This grey zone transition is is very crucial which includes the intermolecular forces acting on the molecules and each atoms which makes the change in state from hot to cold and cold to hot.
Explanation:
A metal of length 15.01m is heated until its temperature rises by 60 degree celsius. If its new length is 15.05, calculate its linear expansivity.
The linear expansivity of the metal is 4.44 × \(10^{-6}\) /°C.
What is Temperature?
Temperature is a measure of the degree of hotness or coldness of a substance or object, expressed in terms of a numerical scale. It is a physical property that determines the direction of heat transfer between two bodies in thermal contact. The most commonly used scales for temperature measurement are Celsius, Fahrenheit, and Kelvin.
Linear expansivity is defined as the change in length per unit original length per degree Celsius change in temperature.
Let the initial length of the metal be L1 = 15.01 m and the change in temperature be ΔT = 60°C.
The final length of the metal is L2 = 15.05 m.
The change in length of the metal is:
ΔL = L2 - L1
ΔL = 15.05 m - 15.01 m
ΔL = 0.04 m
The linear expansivity α can be calculated as:
α = ΔL / (L1 ΔT)
α = 0.04 m / (15.01 m × 60°C)
α = 4.44 ×\(10^{-6}\) /°C
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What is the maximum number of grams of fat recommended on a 2000-kcalorie diet based on the daily value?
a. 34
b. 45
c. 78
d. 56
e. 67
The maximum number of grams of fat recommended on a 2000-kcalorie diet based on the daily value is around 65 grams,therefore option (e)
The term "daily value" (DV) describes how much of a nutrient you should eat daily based on a diet of 2,000 calories.On the FDA website, you may obtain the daily values for a variety of nutrients. In order to meet the average adult's energy requirements, the FDA picked 2,000 calories.Fat intake must be kept to a minimum. A 2,000 calorie diet per day should contain no more than 65 grammes of total fat, 20 grammes or less of saturated fat, and trace levels of trans fat. Trans fats are bad because they narrow our arteries, increasing our risk of coronary heart disease.Learn more about daily value from here:https://brainly.com/question/23095932
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a jet dives vertically at a speed v = 298 m/s, before pulling out of the dive along a circular arc. the pilot can survive an acceleration of a = 5.3 g. his mass is m = 93 kg.
The pilot can survive an acceleration of 5.3 times the acceleration due to gravity. With a mass of 93 kg and a diving speed of 298 m/s, the minimum radius of the circular arc during the pullout is approximately 888.19 meters.
The pilot's survival acceleration is given as 5.3 g, where g is the acceleration due to gravity (approximately 9.8 m/s²). The pilot's mass is 93 kg. To determine the minimum radius of the circular arc during the pullout, we can use the equation:
a = v² / r
Where:
a = Acceleration
v = Velocity
r = Radius
Substituting the given values:
5.3g = (298 m/s)² / r
Simplifying the equation:
r = (298 m/s)² / (5.3g)
Now we can calculate the radius:
r = (298 m/s)² / (5.3 * 9.8 m/s²)
r ≈ 888.19 meters
Therefore, the minimum radius of the circular arc during the pullout is approximately 888.19 meters.
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Verify that the intermediate value theorem applies to the indicated interval and find the value of c guaranteed by the theorem. f(x) = x2 5x 1, [0, 9], f(c) = 15
This is also numerically proved by solving f(c) = 15 ⇒ c² - 5c + 1 - 15 = 0,which can be written as c² - 5c - 14 = 0, whose solutions are c = 7 and c = -2, but -2 doesn't belong to [0, 9]. Hence, c = 7.
According to the intermediate value theorem, since f(0) = 1 and f(9) = 67, there is at least one number c in the interval [0, 9] such that f(c) = 15.
The Intermediate Value Theorem states that if a function is continuous on the closed interval [a, b], then it must have at least one value c in the open interval (a, b) such that f(c) is equal to any number M,
where f(a) ≠ M and f(b) ≠ M.
If f(x) = x² - 5x + 1 and [0, 9] is given,
we can see that: f(0) = 1,f(9) = 67.
From the theorem, we know that f(c) = 15 since 15 lies between f(0) and f(9).
therefore, here exists a number c in the interval [0, 9] such that f(c) = 15.
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in a scale model of the solar system erected in dallas at the perot museum to give a true sense of the size of the solar system, the earth is represented by a tiny poppy seed with a properly scaled orbit that is located 77 feet from the scale model sun (which is represented by a softball to keep the difference in sizes properly balanced). to keep the scale properly spaced, how far away would neptune - at 30.1 au - have to be placed (using only 3 significant figures)?
To keep the scale properly spaced, Neptune would have to be placed 2,350 feet away from the scale model sun.
In the scale model at the Perot Museum, the Earth is represented by a poppy seed and is located 77 feet from the scale model Sun. To determine the distance for Neptune, we will use the given information about Earth's distance and the astronomical unit (AU) conversion.
1 AU is the average distance from Earth to the Sun, which is 93 million miles. Neptune is 30.1 AU from the Sun.
First, find the scale of the model by dividing the scaled Earth-Sun distance (77 feet) by 1 AU in feet (93 million miles * 5280 feet/mile):
Scale = 77 ft / (93,000,000 miles * 5280 ft/mile) ≈ 1.592 × 10^-10
Next, calculate the scaled Neptune-Sun distance by multiplying Neptune's actual distance in AU (30.1 AU) by the conversion factor (1 AU in feet) and the scale factor:
Scaled distance = 30.1 AU * (93,000,000 miles * 5280 ft/mile) * 1.592 × 10^-10 ≈ 2350 feet
So, in this scale model, Neptune would have to be placed approximately 2350 feet away from the Sun.
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A rifle has a mass of 2. 5 kg. if it is loosely gripped and a 1. 5-g bullet is fired from it with a muzzle velocity of 1400 m/s. Determine the recoil velocity of the rifle just after firing.
A rifle has a mass of 2. 5 kg. if it is loosely gripped and a 1. 5-g bullet is fired from it with a muzzle velocity of 1400 m/s. The recoil velocity of the rifle just after firing is 0.840 m/s.
Rifle
A rifle is a long-barreled gun with a helical pattern of grooves (rifling) etched into the bore wall that is intended for precise shooting. Rifles are often made to be handled with both hands and stabilized on the shooter's shoulder by a buttstock, in line with their emphasis on accuracy. Armed conflict, self-defense, law enforcement, criminal activity (most notably assassinations), hunting, and shooting sports all make substantial use of rifles.
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a nozzle with a radius of 0.595 cm is attached to a garden hose with a radius of 1.878 cm. the volume flow rate through the hose and nozzle is 0.339 l/s. calculate the speed of the water in the nozzle. answer to 3 sig figs.
The volume flow rate through the hose and nozzle is 0.339 l/s, the speed of the water in the nozzle is approximately 9.058 m/s.
To calculate the speed of the water in the nozzle, we can use the principle of continuity, which states that the volume flow rate is constant at any point along a pipe or hose.
The equation for the principle of continuity is given by A₁v₁ = A₂v₂, where A₁ and A₂ are the cross-sectional areas of the hose and nozzle, and v₁ and v₂ are the velocities of the water in the hose and nozzle, respectively.
First, we need to convert the given volume flow rate from liters per second to cubic meters per second, which gives us 0.339 × 10⁻³ m³/s.
Next, we can calculate the cross-sectional areas of the hose and nozzle using the given radii. The area of a circle is given by the formula A = πr².
For the hose, A₁ = π(0.01878 m)² and for the nozzle, A₂ = π(0.00595 m)².
Using the principle of continuity, we can rearrange the equation to solve for v₂: v₂ = (A₁v₁) / A₂.
Substituting the known values, we find v₂ ≈ (π(0.01878 m)² × 0.339 × 10⁻³ m³/s) / (π(0.00595 m)²).
Simplifying the equation, we get v₂ ≈ 9.058 m/s. Therefore, the speed of the water in the nozzle is approximately 9.058 m/s.
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EARS: Two ears (E) is dominant to one ear (e). Both parents are heterozygous.
Answer:
what's the question
Explanation:
I don't understand the question
What is the difference between a counting loop and an infinite loop?
amber walks towards the back of a train at 3mph. The train is moving foward at 65mph. Find the velocity of amber relative on the ground ?
Answer: 62mph
Explanation:
How would you obtain a mean value for the specific heat
capacity of a material?
2. A quantity of gas is trapped by a piston in a cylinder with thin metal walls. The piston is free to move
without friction within the cylinder.
a) The air in the freezer is at atmospheric pressure, which is 1.0 × 105Pa. The area of the piston in
contact with the air in the freezer is 2.4 × 10–3m2
.
i. Calculate the force exerted on the piston by the air in the freezer.
ii. When the cylinder is first placed into the freezer, the temperature of the gas in the cylinder decreases
and the air pushes the piston into the cylinder. Calculate the work done on the piston by the air in the
freezer as the air pushes the piston at distance of 0.021m into the cylinder.
b) The initial temperature of the cylinder and the gas is 21°C and, in the freezer, the temperature of the
cylinder decreases to –18°C. The thermal capacity of the cylinder is 89J/ °C. Calculate the change in
the internal energy of the cylinder.
a)
i. The force exerted on the piston by the air in the freezer is 240 N.
ii. The work done on the piston by the air as it pushes the piston 0.021 m into the cylinder is 5.04 J.
b) The change in the internal energy of the cylinder is 3486 J.
a)
i. To calculate the force exerted on the piston by the air in the freezer, we can use the formula:
Force = Pressure * Area
Given:
Pressure (P) = 1.0 × \(10^5\) Pa
Area (A) = 2.4 ×\(10^(^-^3^) m^2\)
Substituting these values into the formula, we have:
Force = (1.0 × 10^5 Pa) * (2.4 ×\(10^(^-^3^) m^2)\)
= 240 N
ii. To calculate the work done on the piston by the air in the freezer as the air pushes the piston, we can use the formula:
Work = Force * Distance
Given:
Force = 240 N
Distance (d) = 0.021 m
Substituting these values into the formula, we have:
Work = (240 N) * (0.021 m)
= 5.04 J
b) To calculate the change in the internal energy of the cylinder, we can use the formula:
ΔU = mcΔT
Given:
Initial temperature (T1) = 21°C = 21 + 273 = 294 K
Final temperature (T2) = -18°C = -18 + 273 = 255 K
Thermal capacity (c) = 89 J/°C
Substituting these values into the formula, we have:
ΔU = (89 J/°C) * (294 K - 255 K)
= 3486 J
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La superficie de unas botas suman 400 cm2 y la persona que las usa tiene 45 kg de masa, calcula la presión que ejerce sobre el piso. NOTA: Se debe encontrar la fuerza, para lo cual, se debe obtener el peso utilizando la fórmula de masa por gravedad que es 9.8 m / s2
Answer:
11025 N / m²
Explanation:
Los siguientes datos se obtuvieron de la pregunta:
Área (A) = 400 cm²
Masa (m) = 45 Kg
Aceleración por gravedad (g) = 9,8 m / s²
Presión (P) =?
A continuación, determinaremos la fuerza aplicada. Esto se puede obtener de la siguiente manera:
Masa (m) = 45 Kg
Aceleración por gravedad (g) = 9,8 m / s²
Fuerza (F) =.?
F = m × g
F = 45 × 9,8
F = 441 N
A continuación, convertiremos 400 cm² a m². Esto se puede obtener de la siguiente manera:
1 cm² = 0,0001 m²
Por lo tanto,
400 cm² = 400 cm² × 0,0001 m² / 1 cm²
400 cm² = 0,04 m²
Por tanto, 400 cm² equivalen a 0,04 m².
Finalmente, determinaremos la presión ejercida de la siguiente manera:
Área (A) = 0.04 m².
Fuerza (F) = 441 N
Presión (P) =?
P = F / A
P = 441 / 0,04
P = 11025 N / m²
Por tanto, la presión ejercida es 11025 M / m²
What is the charge of an ionic compound after an ionic bond is formed?
Answer:
Ionic bonds are formed between cation and anions . A cation is formed when a metal ion loses valence electron while an anion is formed when a non-metal gains a valence electron.
The energy flow to the earth from sunlight is about 1.4kW/m^2
(a) Find the maximum values of the electric and magnetic fields for a sinusoidal wave of this intensity.
(b) The distance from the earth to the sun is about
1.5×10^11 m. Find the total power radiated by the sun
The maximum values of the electric and magnetic fields for a sinusoidal wave of this intensity E_max ≈ 1026 V/m.
Ours is given;I = 1.4kW/m2 = 1400 W/m2 is the intensity.
The following is the formula for the maximum value of the electric field in respect to intensity:
E max = (I/2(o•c))
Where;
Electric constant _o is equal to 8.85 10(-12) C2/N.m2.
c is the speed of light, which is 3 10(8) m/s.
Thus;
E max = √(2 × 1400)/(8.85 × 10^(-12) × 3 × 10^(8)))
E max 1026 mV
The maximal magnetic field formula is;
E max/c = B max
B max = 1026/(3 × 10^(8))
B max = 3.46 × 10^(-6) (-6) T
The equation for total power is;
P = IA
Where;
A = area = 4 r2.
Ours is given;
Radius: 1.5 10(11) meters
A = 4π × (1.5 × 10^(11))
² = 2.82 × 10^(23) m²
P = 1400 × 2.82 × 10^(23)
P = 3.95 × 10^(26) W
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A certain mass of oxygen has a volume of 5m^3 at 27°C.If the pressures remain constant,What will be its volume at 77°C?
I need the full answer with working
Answer:
With a pressure, for instance, of 4 atmospheres, and a volume of 5 liters yields 4 x 5 = 20. Divide the result by the number of moles of gas. If, for instance, the gas contains 2 moles of molecules: 20 / 2 = 10. Divide the result by the gas constant, which is 0.08206 L atm/mol K: 10 / 0.08206 = 121.86.
Does Sam's story give you any idea for how two taster parents might have a child who is a non-taster
Answer:
if sams answer is yes that they can have a child who is a non-taster then your answer is yes
Explanation:
if both parents are heterozygotes, 25% of their children can be nontaster.
8. How much power is created if 162 J. of work is done in 18 seconds when starting an engine?
The amount of power generated for a 162 J work done in 18 seconds is 9.0 Watts.
How much power is generated in the given time?Power is the quantity of energy transferred per unit time. It can be expressed as;
P = E/t
Where P is power, E is energy and t is time.
Given the data in the question;
Work done / Energy E = 162 J = 162kgm²/s²Elapsed time t = 18.0sPower P = ?To determine the amount of power created, plug the given values into the formula above and solve for P.
P = E/t
P = 162kgm²/s² / 18.0s
P = 9 kgm²/s³
P = 9.0 W
Therefore, the power generated is 9.0 Watts.
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helpp! A certain chemical reaction produces 0.0450grams of product. How many significant figures does this measurement have?
a.3
b.4
c.5
d.2
The measurement have 4 significant figures. Hence, option (b) is correct.
What is significant figures?The number that is given as digits is established using significant figures. A meaningful representation of numbers is carried by these digits.
Frequently, significant digits are employed in place of figures. By counting all of the values beginning with the first non-zero digit on the left, we may determine the number of significant digits.
The certain chemical reaction produces 0.0450grams of product.
In 0.0450, there have 4 significant figures.
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Answer: The answer is 3 sig figs, option A
Explanation:
If a book has a mass of 3 kg, what is the book's weight in N?
Answer:
29.4 N
Explanation:
F = ma
F = (3 kg) (9.8 m/s²)
F = 29.4 N
Una bola de ping pong de 10 g. de masa rueda a 10 m/s hacia una bola de pool de 250 g de masa, inicialmente quieta. Luego del choque la pelota rebota hacia la izquierda con una velocidad de 5 m/s. Calcular la velocidad que adquiere la bola de pool, si esta pelota se movía hacia la izquierda con una velocidad de 0.4 m/s antes del choque
if you push the first cart for 3 s and then the other one for the same length of time, exerting equal force on each, the momentum of the light cart is the momentum of the heavier cart. (caution: you are asked to compare the final momenta of the two carts, not the final speeds!)
When you push the first cart and the second cart for an equal amount of time with equal force, the momentum of the light cart will be equal to the momentum of the heavier cart.
The multiplication of an object's mass and its velocity is know as Momentum. The momentum of an object is conserved unless acted upon by external forces. In this scenario, both carts experience the same force for the same duration, which means they experience the same impulse (change in momentum).
2nd law of motion states that force is equal to the rate of change of momentum. Since the force and time are equal for both carts, the change in momentum will also be equal. However, the change in momentum depends on the mass of the object. The light cart has less mass compared to the heavier cart, so the change in velocity will be greater for the light cart to compensate for its lower mass, resulting in an equal change in momentum.
Therefore, the momentum of the light cart will be the same as the momentum of the heavier cart, even though their final speeds may differ due to their different masses.
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mass = 20Kg
velocity = 10m/s
what is the kinetic energy
Answer:
kinetic energy = 1 / 2 mv²
kinetic energy = 1 / 2 × 20 × 10 ²
kinetic energy = 1000 joules
.........