Answer:
Car 1
Characteristic
Car mass
Crumple zone length
1,450 kg
110 cm
Explanation:
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explain in terms of the arrangement of particles the kinetic theory of matter
Answer:
The kinetic theory of matter can be used to explain how solids, liquids and gases are interchangeable as a result of increase or decrease in heat energy. When an object is heated the motion of the particles increases as the particles become more energetic
a ball is thrown horizontally from a height of 1 m and lands 5 m away
Answer:
it's from gravity because when you throw something up it goes forward a certain distance
Masses m and 2m are joined by a light inextensible string which runs without slipping over a uniform circular pulley of mass 2m and radius a. Using the angular position of the pulley as generalized coordinate, write down the Lagrangian function and Lagrange's equation. Find the acceleration of the masses.
Answer: the acceleration of the masses is given by = 0, which means the angular acceleration of the pulley is zero. This implies that the masses m and 2m move with constant velocity, they are in equilibrium.
How is the pressure of a gas related to its concentration of particles?
Answer:
Explanation:
Pressure will expand a gas, enlarging its volume and reducing its density and concentration of particles. Pressure will magnify a gas, developing its volume and multiplying its density and concentration of particles.
Increasing the pressure of a gas is exactly the same as increasing its concentration. If you have a given mass of gas, the way you increase its pressure is to squeeze it into a smaller volume. If you have the same mass in a smaller volume, then its concentration is higher.
a model car moves round a circular path of radius 0.3m at 2 revolutions per secs what is its angular speed, the period of the car and the speed of the car
Answer:
a) T = 0.5 s
b) v = 1.2π m/s ≈ 3.77 m/s
Explanation:
It makes two revolutions in one second so makes one revolution in ½ second
circumference of the circle is
C = 2πr = 0.6π m
which it traverses in one time period
0.6π m / 0.5 s = 1.2π m/s
To solve this, we must be knowing each and every concept related to speed and its calculations. Therefore, the angular speed of a model car moves round a circular path of radius 0.3m at 2 revolutions per secs is 3.77 m/.
What is speed?Speed may be defined as the distance traveled by an item in the amount of time it requires to travel that distance. In other words, it measures how rapidly an item travels but does not provide direction.
Speed may be calculated in Science. The speed equation is a scientific formula that is used to calculate various types of speed.
Mathematically, the formula for speed can be given as
speed= distance/time
Values that are given
Time period= 0.5 s
Circumference = 2πr = 0.6π m
substituting all the given values in the above equation, we get
speed =0.6π m / 0.5 s
On calculations, we get
= 1.2π m/s
=3.77 m/s
Therefore, the angular speed of a model car moves round a circular path of radius 0.3m at 2 revolutions per secs is 3.77 m/.
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if the distance from the earth to the sun is 92.9 million miles, and the angle formed between Venus, the earth, and the sun is 47degrees, find the distance from the sun to venus
Answer:
if the mean distance 93 million miles then the range of distances has to go from 92.293.8 million miles however the earth goes
What is the period of revolution of a satellite with mass (m) that orbits the earth in a circular path of radius 7480 km (about 1100 km) above the surface of the earth)?
When a mass (m) that orbits the earth in a circular path of radius 7480 km (about 1100 km) above the surface of the earth), the period of revolution of the given satellite is approximately 8207 seconds or 2.28 hours.
The period of revolution of a satellite with mass (m) that orbits the earth in a circular path of radius 7480 km (about 1100 km) above the surface of the earth) can be determined by using Kepler's third law which relates the period of revolution of a satellite to the average radius of its orbit.
Kepler's third law states that the square of the period of revolution of a satellite is proportional to the cube of the average radius of its orbit.
Mathematically, the law can be expressed as: T² = (4π² / GM) × R³Where T is the period of revolution, G is the gravitational constant, M is the mass of the earth, and R is the average radius of the orbit of the satellite.
To find the period of revolution of the given satellite, we can substitute the given values in the equation: R = 7480 km + 6370 km = 13850 kmM = 5.97 × 10²⁴ kgG = 6.67 × 10⁻¹¹ Nm²/kg²T² = (4π² / GM) × R³T² = (4π² / (6.67 × 10⁻¹¹ × 5.97 × 10²⁴)) × (13850 × 10³)³T² = 6.7182 × 10¹⁴ seconds²
Taking the square root of both sides, we get:T = 8.2079 × 10³ seconds
Therefore, the period of revolution of the given satellite is approximately 8207 seconds or 2.28 hours.
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what could be the possible answer to the question ?
thankyou ~
The value of the force, F₀, at equilibrium is equal to the horizontal
component of the tension in string 2.
Response:
The value of F₀ so that string 1 remains vertical is approximately 0.377·M·gHow can the equilibrium of forces be used to find the value of F₀?Given:
The weight of the rod = The sum of the vertical forces in the strings
Therefore;
M·g = T₂·cos(37°) + T₁
The weight of the rod is at the middle.
Taking moment about point (2) gives;
M·g × L = T₁ × 2·L
Therefore;
\(T_1 = \mathbf{\dfrac{M \cdot g}{2}}\)
Which gives;
\(M \cdot g = \mathbf{T_2 \cdot cos(37 ^{\circ})+ \dfrac{M \cdot g}{2}}\)
\(T_2 = \dfrac{M \cdot g - \dfrac{M \cdot g}{2}}{cos(37 ^{\circ})} = \mathbf{\dfrac{M \cdot g}{2 \cdot cos(37 ^{\circ})}}}\)
F₀ = T₂·sin(37°)
Which gives;
\(F_0 = \dfrac{M \cdot g \cdot sin(37 ^{\circ})}{2 \cdot cos(37 ^{\circ})}} = \dfrac{M \cdot g \cdot tan(37 ^{\circ})}{2} \approx \mathbf{0.377 \cdot M \cdot g}\)
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where ? in kenya
a, have you been born c, were you born
b, are you born d, was you born
Answer:
C, We're you born. Sorry if I'm wrong :).
Answer:
It's C. Were you born
hope this helps! :D
Explanation:
Which statement describes a situation with a displacement of zero check all tha apply
A rigid body is rotating with constant angular speed 3 radians per second about a fixed axis through the points A. (4, 1, 1), B. (2, -1; 0), distances being measured in centimeters. The rotation is in the left-handed sense relative to the direction AB
1, Determine the unit vector pointing in the direction BA.
2, What is the angular velocity () of the of the body?
3, Write the position vector of point P: P .
Find the instantaneous velocity of particle P [hint v = w×r)
4, What is meant by left-handed rotation (left-handed coordinate system)?
5, Write the position vectors of points A and B The rotation axis AB has direction BA. Write the direction BA in terms of the components given above.
1.Unit vector in the direction BA: BA/|BA| = (2/3, 2/3, 1/3)
2.The angular velocity (ω) of the body is given as 3 radians per second.
3.Without the position of point P given, it is not possible to write the position vector of P.
4.Left-handed rotation refers to the direction of rotation where the rotation follows the left-hand rule.
5.Position vector of point A: (4, 1, 1)
Position vector of point B: (2, -1, 0)
The direction vector BA = (-2, -2, -1)
1.To determine the unit vector pointing in the direction BA, we subtract the coordinates of point B from the coordinates of point A and normalize the resulting vector.
The direction vector BA is given by:
BA = (4 - 2, 1 - (-1), 1 - 0) = (2, 2, 1)
To obtain the unit vector in the direction of BA, we divide the direction vector by its magnitude:
|BA| = √(2^2 + 2^2 + 1^2) = √(4 + 4 + 1) = √9 = 3
Unit vector in the direction BA: BA/|BA| = (2/3, 2/3, 1/3)
2.The angular velocity (ω) of the body is given as 3 radians per second.
3.Without the position of point P given, it is not possible to write the position vector of P. Please provide the position of point P to proceed with the calculation.
4.Left-handed rotation refers to the direction of rotation where the rotation follows the left-hand rule. In a left-handed coordinate system, if you curl the fingers of your left hand in the direction of rotation, your thumb will point in the direction of the rotation axis. It is the opposite direction to a right-handed rotation.
5.The position vectors of points A and B are:
Position vector of point A: (4, 1, 1)
Position vector of point B: (2, -1, 0)
The direction vector BA can be obtained by subtracting the coordinates of point A from the coordinates of point B:
BA = (2 - 4, -1 - 1, 0 - 1) = (-2, -2, -1)
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Given the two displacement
D=(6i +3j -k )
E=(4i - 5j +8k)
Find the magnitude of displacement 2D -E
The approximate value of the magnitude of the displacement vector 2D - E is roughly 16.88.
How to find the magnitude of the displacementIn order to find out the magnitude of the displacement vector 2D - E, you can use these steps:
multiplying D by 2. this would result to
12i + 6j - 2k
subtracting E from 2D. this would result to
8i + 11j - 10k
The calculation of Step three entails computing the magnitude of 2D - E where |V| = sqrt(Vi^2 + Vj^2 + Vk^2)
|2D - E| = sqrt((8^2) + (11^2) + (-10^2))
|2D - E| = sqrt(64 + 121 + 100)
|2D - E| = sqrt(285),
|2D - E| = 16.88 when rounded off to two decimal places.
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How do atomic and molecular interactions explano the properties of matter that we see and feel?
Answer:
The atomic and molecular interactions unveil the bulk properties of matter in our environment by ways of the fact that everything in the whole universe is made of either atoms, molecules or even ions
How matter is made up of atoms and molecules?
It has been proven practically everything in the whole universe is matter and everything which interact with matter is also matter. This explains to us the reasons why matter could be atoms, molecules or ions.
That being said, some substances (matter) is made up of atoms of elements, some made up of molecules or atoms and molecules and others ions or both. However, matter is anything which has mass and occupies space.
In conclusion, we can now conclude from the explanation above that the properties of matter are as a result of the interaction which exists between matter at the atomic and molecular level.
Think about how geothermal energy is captured and used. Explain how geothermal energy shows the flow of thermal energy from hot to cold or cold to hot.
Answer:
People can capture geothermal energy through: Geothermal power plants, which use heat from deep inside the Earth to generate steam to make electricity. Geothermal heat pumps, which tap into heat close to the Earth's surface to heat water or provide heat for buildings
When the weather is cold, the water or refrigerant heats up as it travels through the part of the loop that's buried underground. Once it gets back above ground, the warmed water or refrigerant transfers heat into the building. The water or refrigerant cools down after its heat is transferred.
Suppose the woman in the figure is 54kg , and the board she is standing on has a 10kg mass. What is the reading on each of the scales?
The reading on each of the scales on the right is 421.4 N.
The reading on each of the scales on the left is 156.8 N.
What is the reading on each scale?The reading on each scale is determined from the distribution of the weight of the woman.
The weight of the board is distributed uniformly and each scale with have equal reading of the weight of the board.
weight of the board = 10 kg x 9.8 m/s² = 98 N
Reading of each due to weight of the board is calculated as;
W₁ = ¹/₂ (98 N) = 24.5 N
The distribution of the weight of the woman on the right scale is calculated as;
W (R) = ( 1.5 m / 2 m) x ( 54 x 9.8 )
W (R) = 396.9 N
The distribution of the weight of the woman on the left scale is calculated as;
W (L) = ( 0.5 m / 2 m) x ( 54 x 9.8 )
W (L) = 132.3 N
Total reading on the scale on the right = 396.9 N + 24.5 N = 421.4 N
Total reading on the scale on the left = 132.3 N + 24.5 N = 156.8 N
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How long does it take for radiation from a cesuim-133 atom to complete 1.5 million cycles
A cesium-133 atom's radiation goes through 1.5 million cycles in around 0.1633 microseconds (or 163.3 nanoseconds).
What frequency does one kind of radiation that cesium-133 emits have?9,192,631,770 hertz (cycles per second) is the frequency of the microwave spectral line that the isotope cesium-133 emits. The basic unit of time is provided by this. Cesium clocks have an accuracy and stability of 1 second in 1.4 million years.
The radiation emitted by cesium-133 has a frequency of 9,192,631,770 cycles per second, or 9.192631770 109 Hz.
The following formula may be used to determine how long 1.5 million radiation cycles take to complete:
Time is equal to the frequency of cycles.
Plugging in the numbers, we get:
time = 1.5 million / 9.192631770 × 10^9 Hz
time = 1.632995101 × 10^-7 seconds
So it takes approximately 0.1633 microseconds (or 163.3 nanoseconds) for radiation from a cesium-133 atom to complete 1.5 million cycles.
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.
1. How does the arrangement of a pulley system affect its ideal mechanical advantage
Answer: In a pulley, the ideal mechanical advantage is equal to the number of rope segments pulling up on the object. The more rope segments that are supporting to do the lifting work, the less pressure that is needed for the job.
Explanation:
Put these 5 events in the correct order. Formation of Atoms, Time begins, Formation of Galaxies
Formation of subatomic particles, Formation of stars
Answer:
Time begins, Formation of subatomic particles, Formation of Atoms, Formation of stars, Formation of Galaxies
Explanation:
At the beginning right after the big bang time starts then sub-atomic particles forms i.e. protons, neutrons from this atoms form and after that stars and galaxies form.
Clear umbra can be obtained by .................................
what is the word come to this blank?
Joey drives his Skidoo 13 kilometres north. He stops for lunch and then drives 10kilometres south. What distance did he cover? What was his displacement?
Answer:
Total distance covered (scalar quantity) = 23 km
Displacement (vector quantity) = 3 km north from the original starting point
Explanation:
Since he drove 13 km north and then 10 km south, the total distance he cover in his drive was: 13 km + 10 km = 23 km
On the other hand, his displacement was 3 km north from where he started.
WHAT IS ENERGY AND HOW WE USE
ENERGY
An 82kg male and 48kg female pari figure starting team are gliding across the ice of 7.4m/s preparing for a throw jump maneuver. The male starter tosses the female starter forward with a speed of 8.6n/s. Determine the speed of the male starter immediately after the throw.
Answer:
Explanation:
(m1 + m2)*V1 = m2*V2 + m1*Vx
Vx = ((m1 + m2)*V1 - m2*V2) / m1
Vx = ((82 + 48)*7.4 - 48*8.6) /82 = 6.7 m/s
A 53 g ice cube at −30◦C is dropped into a container of water at 0◦C. How much water freezes onto the ice? The specific heat of ice is 0.5 cal/g · ◦ C and its heat of fusion of is 80 cal/g. Answer in units of g.
For A 53 g ice cube at −30◦C is dropped into a container of water at 0◦C, the amount of water that freezes onto the ice? is mathematically given as
x = 9.93 g
What is the amount of water that freezes onto the ice?Where
Energy received = energy given out
Generally, the amount of water is mathematically given as
(53)(0.5)(30) = (80)(x)
Therefore
x = (49)(0.5)(16)/(80)
x = 9.93 g
In conclusion, the mass of water
x = 9.93 g
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Do this for alot of points
1. A complete fitness and exercise program should incorporate three basic components: Endurance (Aerobic), Flexibility, and Strength. Each of these components has specific guidelines, which govern their effectiveness
Can someone explain how to do the algebra for this question? I know everything else, I just don’t know how to rearrange the question to solve for v.
Answer:
Refer to the step-by-step Explanation.
Step-by-step Explanation:
Simplify the equation with given substitutions,
Given Equation:
\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)
Given Substitutions:
\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)
Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)
Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)
\(\hrulefill\)
Simplifying the left-hand side of the equation:
\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)
Simplifying the third term.
\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)
\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)
\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)
"R²'s" cancel, we are left with:
\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)
We have like terms, combine them.
\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)
Each term has an "m" in common, factor it out.
\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)
Now we have the following equation:
\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)
\(\hrulefill\)
Simplifying the right-hand side of the equation:
\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)
\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)
Now we have the equation:
\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)
\(\hrulefill\)
Now solving the equation for the variable "v":
\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)
Dividing each side by "m," this will cancel the "m" variable on each side.
\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)
Subtract the term "gh" from either side of the equation.
\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)
Multiply each side of the equation by "10/7."
\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)
Now squaring both sides.
\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)
Thus, the simplified equation above matches the simplified equation that was given.
What makes the element named iron (Fe) different from the element named nickel (Ni)? A. Iron is a solid but nickel is a gas. B. The only difference is the name of the element. C. Atoms of iron are different from atoms of nickel. D. Iron is made of atoms but nickel is not.
Answer:C, Atoms of iron are different from atoms of nickel.
Explanation:All the atoms that make up each type of element are alike, and they are different from the atoms that make up every other type of element. So the element iron is different from the element nickel because the atoms that make up the iron are different from the atoms that make up the nickel.
Which correctly describes a different evolutionary stage of a star like the sun?
A) it’s forms from a cold, dusty molecular cloud
B) During a yellow giant stage, it burns carbon in its core and helium in the shell surrounding the core.
C) After leaving the main sequence, its core is stable due to electron degeneracy
D) It becomes a white dwarf after exploding as a supernova
E)During a red giant stage, its core contracts and cools
Answer:
Explanation:
The correct option that describes a different evolutionary stage of a star like the sun is:
D) It becomes a white dwarf after exploding as a supernova
This is because a star like the sun does not have enough mass to undergo a supernova explosion. After it has exhausted all the fuel in its core, it will evolve into a red giant and then a planetary nebula, leaving behind a small, hot, dense remnant known as a white dwarf. Supernovae occur in much more massive stars that have cores that can collapse to form a neutron star or black hole.
The NEC states the resistance of 4/0 coated
copper conductors is 0.0626 ohms per 1000
feet. What would be the total resistance of the
three 4/0 conductors installed in parallel, if the
total length for each of the three conductors is
323 feet?
Answer:
The resistance of 4/0 coated copper conductors is given as 0.0626 ohms per 1000 feet. To find the total resistance of the three 4/0 conductors installed in parallel, we can use the formula for combining resistances in parallel.
Since the total length for each of the three conductors is 323 feet, the resistance of each conductor can be calculated as follows:
Resistance of one conductor = (0.0626 ohms / 1000 feet) * 323 feet
To find the total resistance when the conductors are in parallel, we use the formula:
1/Total Resistance = 1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3
Total Resistance = 1 / (1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3)
Substituting the values, we get:
Total Resistance = 1 / (1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet))
Simplifying the expression will give us the total resistance of the three 4/0 conductors installed in parallel.
in a typical cop movie we see the hero pulling a gun firing that gun straight up into the air and shouting
It is not recommended to fire a gun straight up into the air.
When a bullet is fired into the air, it will eventually come down and can pose a danger to people and property below. The bullet can still be lethal when it reaches the ground, especially if it lands on a hard surface or hits someone directly.
Additionally, firing a gun in a residential area can be illegal and can result in legal consequences. In general, guns should only be fired in designated shooting ranges or in self-defense situations where there is an immediate threat to life. It is important to handle firearms responsibly and follow all safety guidelines to prevent accidents and injuries.
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395,000 meters in 9000
Answer:
43.88 meters per second
Explanation:
The computation of the speed is shown below:
As we know that
\(Speed = \frac{Distance}{time}\)
where,
Distance is 395,000 meters
Time is 9,000 seconds
Now placing these values to the formula
So, the speed is
\(= \frac{395,000}{9,000}\)
= 43.88 meters per second
As speed shows the relation between the distance and time and the same is to be considered i.e by applying the formula