2- for a soil deposit in the field, the dry unit weight is 14.9 kn/m3. from the laboratory, g= 2.66, emax=0.89, emin=0.48. find the relative density in the field.

Answers

Answer 1

For a soil deposit in the field, the dry unit weight is 14.9 kn/m3. from the laboratory, g= 2.66, emax=0.89, emin=0.48. There is no relative density of the soil deposit.

The dry unit weight of the soil deposit in the field is 14.9 kN/m³.

The emax is 0.89.

The emin is 0.48.g = 2.66

The relative density can be calculated as follows:

Relative density, Dr is given by the following formula,

Dr = (emax - e) / (emax - emin)

where, e is the void ratio of the soil deposit. The specific gravity, Gs, of soil is given by the following formula,

Gs = (ρs / ρw)

where ρs is the density of the soil particles, ρw is the density of water, which is 1000 kg/m³.

g = 2.66ρs = g × ρw = 2.66 × 1000 = 2660 kg/m³

The dry unit weight of the soil deposit in the field is 14.9 kN/m³.

ρd = γ

d = 14.9 kN/m³= 14.9 × 1000 / 9.81= 1518.22 kg/m³

Let,Dr = relative density of soil deposit

e = void ratio of soil deposit

Now,we know that,γd = γs / (1 + e)γs = γd (1 + e)γs = ρs × gγs = 2660 × 9.81 = 26,086.6 N/m³

Putting these values in the above formula,

γs = γd (1 + e)γs = 1518.22 (1 + e)26,086.6 = 1518.22 (1 + e)e = 17.14

Putting this value of e in the formula of Dr,

Dr = (emax - e) / (emax - emin)

Dr = (0.89 - 0.17.14) / (0.89 - 0.48)Dr = -0.0803 (which is not possible)

Hence, there is no relative density of the soil deposit.

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Answer 2

Dry unit weight of soil deposit in the field, γd = 14.9 kN/m³Gravity of the soil, G = 2.66emax = 0.89emin = 0.48Relative density can be calculated as-γd = (1 + e) G γγ = (γd / G (1 + e))where e = (emax - emin)Hence,Relative density of soil deposit in the field can be calculated as-γ = (γd / G (1 + e))= 14.9 / 2.66 (1 + 0.89 - 0.48)= 14.9 / 2.66 × 1.41= 7.7Therefore, the relative density of the soil deposit in the field is 7.7.

The importance of knowing the relative density of soil is due to its relationship with soil strength, shear resistance, compaction, and stability. By measuring the relative density of soil, the engineering properties of soil can be determined, which helps in soil classification and designing of foundations. In this case, we have used the formula to calculate the relative density of the soil deposit in the field.

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A cylindrical bar of metal having a diameter of 19.2 mm and a length of 207 mm is deformed elastically in tension with a force of 52900 N. Given that the elastic modulus and Poisson's ratio of the metal are 61.4 GPa and 0.34, respectively, determine the following:

a. The amount by which this specimen will elongate in the direction of the applied stress.
b. The change in diameter of the specimen. Indicate an increase in diameter with a positive number and a decrease with a negative number.

Answers

Answer:

1)ΔL = 0.616 mm

2)Δd = 0.00194 mm

Explanation:

We are given;

Force; F = 52900 N

Initial length; L_o = 207 mm = 0.207 m

Diameter; d_o = 19.2 mm = 0.0192 m

Elastic modulus; E = 61.4 GPa = 61.4 × 10^(9) N/m²

Now, from Hooke's law;

E = σ/ε

Where; σ is stress = force/area = F/A

A = πd²/4 = π × 0.0192²/4

A = 0.00009216π

σ = 52900/0.00009216π

ε = ΔL/L_o

ε = ΔL/0.207

Thus,from E = σ/ε, we have;

61.4 × 10^(9) = (52900/0.00009216π) ÷ (ΔL/0.207)

Making ΔL the subject, we have;

ΔL = (52900 × 0.207)/(61.4 × 10^(9) × 0.00009216π)

ΔL = 0.616 × 10^(-3) m

ΔL = 0.616 mm

B) Poisson's ratio is given as;

υ = ε_x/ε_z

ε_x = Δd/d_o

ε_z = ΔL/L_o

Thus;

υ = (Δd/d_o) ÷ (ΔL/L_o)

Making Δd the subject gives;

Δd = (υ × d_o × ΔL)/L_o

We are given Poisson's ratio to be 0.34.

Thus;

Δd = (0.34 × 19.2 × 0.616)/207

Δd = 0.00194 mm

I want to draw a monster should i do it on my free time and if you want to give me ideas.

Answers

Answer:

yes

Explanation:

an idea could be a jack o lantern monster since it Halloween tomorrow  

You should draw nice and sweet Disney princesses and make them evil for Halloween

Kieran and Kurt spend most of their day performing physical labor, aligning materials, and inspecting projects for quality and safety. However, Kieran has no fear of heights, while Kurt works with his feet on the ground. Which most likely explains the jobs of Kieran and Kurt? Kieran is a Roofer, and Kurt is a Plumber. Kieran is a Plumber, and Kurt is a Roofer. Kieran is a Carpenter, and Kurt is a Drafter. Kieran is a Drafter, and Kurt is a Carpenter.

Answers

Answer:

Kieran is a Carpenter, and Kurt is a Drafter

Explanation:

Among all the professions listed, Kurt can only possibly be a Drafter.  A Drafter is an engineering technician who makes detailed technical drawings or plans for machinery, buildings, electronics, infrastructure, sections, etc. Drafters make use of computer software and manual sketches to convert the designs, plans, and layouts of engineers and architects into a set of technical drawings. All the other professions will at some point need for the professional to stand and work at an height above the ground except for a drafter, whose feet will remain on the ground at almost all times.

Answer:

A is the right answer.

Explanation:

Hope that helps

due at 11:59pm please help

Which of the items shown in the photo were developed using engineering design processes to develop a solution to a problem?

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C. table
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An engineer proposes that a newly developed chemical could be sprayed from aircraft to slow the rate of burning in a forest fire. What is the next step the engineer is likely to take to develop a solution to fighting forest fires?

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B. spray and compare the effectiveness of each tested chemical to water.

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D. design a spray system for the chemical.

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I believe it’s c table

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Answer:

I don't even know if you're serious but... you call the fire department and tell them about the issue and they get it unstuck

where is the most accurate reading in analogue multimeter is taken

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Answer:

The most accurate reading for an analog meter is a pointer position between 2/3 of full scale and full scale. Typically, dc voltage measurements use the full count capability of the ADC, since signal conditioning is rather straight forward: it uses resistive dividers and filters.

Consider an ideal ramjet engine flying at an altitude of 10,000 m (see local atmospheric conditions in appendix III of the textbook). The jet fuel used has a heat of combustion of 43,000 kJ/kg, and a stoichiometric fuel to air ratio of 0.06. The maximum temperature of the ramjet is 2600 K. Assume the specific heat ratio up to the combustion chamber is 1.4, and that the specific heat ratio through the rest of the engine (including the combustor) is 1.33. The specific heat at constant pressure for the gases in the combustor can be calculated using the following equation: C = R. 17-1 where R is assumed to be 0.287 kJ/kgk throughout the engine. Calculate the specific thrust and TSFC as a function of flight Mach number from a range of 1 to 6. Note that the fuel to air ratio can not be above the stoichiometric value (i.e. we can't burn more fuel than that at an equivalence ratio of unity). Some operating points may require a higher value off than the stoichiometric value to reach the temperature limit. Under this condition, f should be set to the stoichiometric value, and the combustor exit temperature T04 should be calculated from the energy equation. Otherwise, the maximum temperature is used and f is calculated from the energy equation. Using a procedure and an if/then/else approach might be ideal for this. Include the following plots: 1. Specific thrust (1) vs. Mflight 2. TSFC vs. Mflight 3. T04 vs. Mflight 4. Aexit/Athroat Vs. Mflight 5. 1th, Np, and no vs. Mflight TABLE 1 Geometric altitude S.I. units H, m TK P , N/m? p, kg/m3 . 4, m/s v, m/s po 0 1000 2000 3000 4000 5000 0 1000 1999 2999 3997 4996 288.150 281.651 275.154 268.659 262.166 255.676 1.01325 +5 8.9876 +4 7.9501 +4 7.0121 +4 6.1660 +4 5.4048 +4 1.00000 +0 8.87009-1 7.84618 -1 6.92042 - 1 6.08541 - 1 5.33415 - 1 1.2250 +0 1.1117 +0 1.0066 +0 9.0925 - 1 8.1935 - 1 7.3643-1 1.0000 +0 9.0748 -1 8.2168 -1 7.4225-1 6.6885 -1 6.0117 - 1 340.294 336.435 332.532 328.583 324.589 320.545 1.4607 -5 1.5813-5 1.7147-5 1.8628 - 5 2.0275 -5 2.2110 -5 6000 7000 8000 9000 10000 5994 6992 7990 8987 9984 249.187 242.700 236.215 229.733 223.252 4.7217 +4 4.1105 +4 3.5651 +4 3.0800 +4 2.6500 +4 4.66001 - 1 4.05677 -1 3.51854 -1 3.03979 - 1 2.61533 -1 6.6011 - 1 5.9002 -1 5.2579 -1 4.6706 -1 4.1351 - 1 5.3887 - 1 4.8165 - 1 4.2921 - 1 3.8128-1 3.3756 -1 316.452 312.306 308.105 303.848 299.532 2.4162 -5 2.6461 -5 2.9044-5 3.1957 -5 3.5251 - 5

Answers

H is the enthalpy of the gas, Hf is the enthalpy of the fuel, m is the mass flow rate of air, Vexit and Vinlet are the exit and inlet velocities.

What is mass?

Mass is the measure of the amount of matter an object contains. It is measured in kilograms (kg) in the International System of Units (SI). Mass is also known as a measure of inertia, which is the resistance of an object to change its velocity or its direction. In other words, mass is the measure of an object's resistance to acceleration.

The specific thrust is the amount of thrust generated per unit mass flow rate of air through the engine. It can be calculated by the following equation:

T = m * (Vexit – Vinlet)

where m is the mass flow rate of air and Vexit and Vinlet are the exit and inlet velocities respectively.

TSFC

The TSFC is the amount of fuel consumed per unit of thrust produced. It can be calculated by the following equation:

TSFC = (mf/T) * (Vexit – Vinlet)

where mf is the fuel flow rate and T is the thrust generated.

T04

T04 is the temperature of the gases exiting the combustor. It can be calculated from the energy equation, which is given by:

H = Hf + m * (Vexit2/2 – Vinlet2/2) + mf * (Qf – Hf)

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an illustration of the term "automatic stabilizer" is provided by

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An automatic stabilizer is an economic policy instrument that automatically adjusts to counteract fluctuations in economic activity without any deliberate intervention by policymakers.

They are designed to stabilize an economy by decreasing the impact of economic shocks, such as recessions or booms, and help maintain a consistent level of economic growth.

A prime example of an automatic stabilizer is the progressive income tax system. In this system, as an individual's income increases, they are subjected to higher tax rates. Conversely, as their income decreases, they pay lower tax rates. During economic expansions, when individuals' incomes rise, the government collects more taxes, which helps reduce inflationary pressures. Conversely, during recessions, when incomes fall, the government collects fewer taxes, providing an automatic boost to disposable income and, in turn, consumer spending.

Another illustration of an automatic stabilizer is unemployment benefits. When the economy experiences a downturn and unemployment rates increase, the government automatically provides financial assistance to those who have lost their jobs. This support not only helps the unemployed meet their basic needs but also sustains consumer spending, which in turn helps stabilize the economy.

In summary, automatic stabilizers, such as the progressive income tax system and unemployment benefits, play a crucial role in mitigating economic fluctuations. They work passively without the need for active policy intervention, providing a stabilizing effect that helps maintain economic growth and reduces the severity of economic shocks.

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Technician A says that gasoline has a rating of 25,000 Btu. Technician B says that diesel fuel has a 14,000 Btu rating. Who is correct?
Select one:
O a. Technician A
O b. Technician B
O c. Both A and B
O d. Neither A nor B
Next page

Answers

I think the answer is C. Both A and B

Is it Possible to anchor a steel cable from Earth to the moon without the steel cable breaking???....

Answers

The answer to this question is quite simple....
Answer:
No, it is not possible!
Is it Possible to anchor a steel cable from Earth to the moon without the steel cable breaking???....

Many of the products that we eat and drink are advanced manufactured products. Is this statement TRUE or FALSE?

Answers

True. anything found in a jar or a box at the grocery has been manufactured.

A storage tank is purged continuously with a stream of nitrogen. The purgestream leaving the tank is saturated with the product stored in the tank. A majorpart of the product lost in the purge could be recovered by installing a scrubbingtower to absorb the product in a solvent. The solution from the tower could befed to a stage in the production process, and the product and solvent recoveredwithout significant additional cost. A preliminary design of the purge recoverysystem has been made. It would consist of:1. A small tower 0.5 m diameter, 4 m high, packed with 25 mm ceramic saddles,packed height 3 m.2. A small storage tank for the solution, 5 m3 capacity.3. The necessary pipe work, pump, and instrumentation.All materials of construction, carbon steel.Using the following data, evaluate whether it would be economical to install therecovery system:1. cost of product £5 per kg,2. cost of solvent 20 p/kg,3. additional solvent make-up 10 kg/d,4. current loss of product 0.7 kg/h,5. anticipated recovery of product 80 per cent,6. additional service(utility) costs, negligible.Other operating costs will be insignificant.

Answers

Answer:

It is economical

Explanation:

Given data for determining

cost of product = £5 per kg

cost of solvent = £20 per /kg

additional solvent makeup = 10 kg/d

current loss of product = 0.7 kg/h

anticipated recovery of product = 80%

additional service ( utility cost ) = negligible

Determine if it is economical to install the recovery system

cost of product = £5 per kg

cost of solvent = £20 per /kg

additional solvent required = 10 kg / d

cost of additional solvent in a day  = £200 / day  ( £20 per kg * 10 kg / d )

product lost = 0.7 kg/h

product recovered = 0.7 * 80% = 0.56 kg/h

therefore product recovered in a day = 0.56 * 24 = 13.44 kg / day

Next :

calculate income generated from product recovery

13.44 kg/day *  £20 /kg =  £268.88 / day

Determine if it is economical

Income - cost

= £268.88 - £200

=  £68.88  ( hence it is economical )

The company PureNSafe is designing a portable, solar-powered disinfection system for Army use only. The system is simply an inlet pipe, a pump, a mixing chamber and an outlet pipe. The water is continuously pumped into the chamber where it is irradiated with UV light before it exits through the the appropriate tube into a collection vessel. The disinfection rate constant rate of disinfection with UV light is 7.80 s.1 and the amount of bacteria has to be reduced by 99.9%. be reduced by 99.9%. Since the Army requires an object that can be carried in a backpack, it requires that the chamber of the apparatus must not hold a capacity greater than 2 L. How much water will the system be able to produce during 10 hours of sunshine?

Answers

Solution :

The treatment system will operate as the well mixed chamber.

Disinfection rate constant for the UV light, k is 7.80 /s. Number of bacteria in water need to be reduced by 99.9%

Percent reduction of bacteria should be \($(1-10^{0.99}) \times 100 =89.7\%$\)

Volume of the unit chamber is fixed at 2L

Assume the inlet concentration, \($C_0$\) as 1000

The outlet concentration of bacteria, C should be \($1000-\left(1000 \times \frac{89.7}{100}\right)$\)

                                                                                  = 103

The well mixed chamber will then follow a completely mixed flow reactor model.

Compute the time required :

\($t=\frac{1}{k}\left(\frac{C_0}{C}-1\right)$\)

\($t=\frac{1}{7.8}\left(\frac{1000}{103}-1\right)$\)

  = 1.115 s

Flow through the system is    \($\frac{2 \ L}{1.115 \ s}$\)  = 1.79 L/s

The amount of water treated during the 10 hours of sunlight is 1.79 x 10 x 60 x 60 = 64440 L

Identify the careers that match the descriptions. Operates machines that cut through rocks underground so natural resources can be harvested: Studies and manages natural resources to protect the environment: Manages forests for conservation, human enjoyment, and harvesting: Inspects, measures, and classifies logs based on quality: Operates machinery to cut down trees and move logs:

Answers

Answer:

1. Operates machines that cut through rocks underground so natural resources can be harvested: Mine-cutting and channeling operator

2. Studies and manages natural resources to protect the environment: Conservation Scientist

3. Manages forests for conservation, human enjoyment, and harvesting: Forster

4. Inspects, measures, and classifies logs based on quality: Log grader or scaler

5. Operates machinery to cut down trees and move logs: Logging equipment Operator

Explanation:

Conservation Scientist – studies and manages natural resources to protect the environment and support human uses of natural resources

Forester – manages forests for conservation, human enjoyment, and tree harvesting

Mine Cutting and Channeling Machine Operator – operates machinery in underground mines that bring natural resources up to the surface for human use

Logging Equipment Operator – operates logging machinery, such as tractors or bulldozers

Log Grader or Scaler – inspects, measures, and classifies logs based on their quality

The careers that match the given descriptions are; Conservation Scientist, Forester , Mine Cutting and Channeling Machine Operator ,and Logging Equipment Operator.

What are the careers that match the given descriptions?

Conservation Scientist deals with the studies and manages natural resources to protect the environment and support human uses of natural resources

Forester deals with forests for conservation, human enjoyment, and tree harvesting

Mine Cutting and Channeling Machine Operator are the operates machinery in underground mines that bring natural resources up to the surface for human use

Logging Equipment Operator are the operates logging machinery, such as tractors or bulldozers

Log Grader or Scaler deals with the inspects, measures, and classifies logs based on their quality.

The careers that match the given descriptions are; Conservation Scientist, Forester , Mine Cutting and Channeling Machine Operator ,and Logging Equipment Operator.

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what is the esr in the capacitor

Answers

Answer: Equivalent Series Resistance

Explanation:

Equivalent series resistance (ESR), also known as internal resistance, is a value representing the loss of useful energy in a simple electronic circuit consisting of a resistor and an ideal (perfect) capacitor.

How many additional years does it take to earn a Masters after getting a Bachelors degree?

Answers

Answer: Most master’s degree programs will take an average of two years from start to finish – about half of the time it takes to earn your bachelor’s degree. While bachelor’s degree programs involve many introductory and general education courses, a master’s degree curriculum is all about the subject area you selected to study.

Explanation: Hope this was helpful

which of the following devices are used in networking? check all that apply?
switches, hubs,TCP or routers​

Answers

Answer:

Hub , switch port , transmission media , hope I helped

Explanation:

Show three periodic tasks that do not satisfy the simple schedulable utilization (Schedulability Test 2) but can still be RM-scheduled.
(test 2 Utilization U = sum c_i / p_i Number of tasks n A task set is schedulable if U <= n(2^(1/n) – 1))
Please type it out

Answers

Irregular Task Think about the cruise control system in a car. The main purpose of cruise control is to maintain a consistent speed for the vehicle. Let's say the driver has set the target speed at 60 mph.

The inbuilt computer sends a signal to the engine controller to set the speed appropriately if the vehicle is moving slower or faster than the selected speed. Control rate, which is established by the designer of the control system, is the frequency at which the computer checks to see if the vehicle's current speed is consistent with the programmed speed.

A erratic task keeps happening at random times.

The following tuple can be used to define a sporadic task Ti:

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Find the total present worth of a series of cash flows with an annual interest rate of 2% per year. Round your answer to the nearest cent.



Initial benefit of 5,330 at year 0

Benefit of 13,075 at year 3

Salvage value of 2,308 at year 4

Answers

The total present worth is $19,783.01

The present worth of a series of cash flow is the value of the cash flows in year 0 (today)

Cash flow in year 0 = 5330

Cash flow in year 1 = 0

Cash flow in year 2 = 0

Cash flow in year 3 = 13075 / (1.02)^3 = 12,320.86

Cash flow in year 4 = 2308 / (1.02)^4 = 2,132.24

Present worth = $19,783.01

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What’s one important way engineering students can sharpen their study skills through their engineering notebooks?

A. They can put together a well-designed and nicely illustrated book.

B. They can learn to compare and their work to that of other students.

C. They can use the notebook to organize their class work for all courses.

D. They can collect information for graded presentations and summaries.

Please answer quickly and thoroughly. Thanks! :)

Answers

C. They can use the notebook to organize their class work for all courses.

C is the right answer I hope this helps you :)

Determine the brake horsepower required by a pump for a discharge of 0.2 m3/s and a total dynamic head of 20m, with an efficiency of 80%.

Answers

Answer:

The BHP would be "65.659 HP".

Explanation:

The given values are:

Discharge,

Q = 0.2 m³/s

Dynamic head,

H = 20 m

Efficiency,

% = 80%

Now,

The Power will be:

⇒ \(P=\delta QH\)

On substituting the values, we get

⇒     \(=1000\times 9.81\times 0.2\times 20\)

⇒     \(=39240 \ W\)

The brake horse power will be:

⇒ \(BHP=\frac{100 Q H}{3960n}\)

On putting values, we get

⇒           \(=\frac{100\times 0.2\times 20}{3960\times 0.80}\)

⇒           \(=65.659 \ HP\)

How would you handle a situation where another team member was critical of your work?

Answers

If the criticism is constructive I would pay attention to it.

What error results if the curvature and refraction correction is neglected in trigonometric leveling for sights: (a) 3000 ft long (b) 1200 m long (c) 4500 ft long?

Answers

The  error results if the curvature and refraction correction is neglected in trigonometric levelling for sights are

(a) 3000 ft long. = 0.1854 ft

(b) 1200 m long = 0.0972 m

(c) 4500 ft long = 0.4172 ft

What is levelling?

This refers to the term in surveying used to describe taking measurements of heights with reference to a datum. Levelling is achieved using levelling instruments.

How to find the error results if the curvature and refraction correction is neglected

given data

(a) 3000 ft long

(b) 1200 m long

(c) 4500 ft long

(a) 3000 ft long

= 0.0206 * F^2

= 0.0206 * ( 3000 / 1000 )^2

= 0.0206 * ( 3 )^2

=  0.0206 * ( 9 )

= 0.1854 ft

(b) 1200 m long

= 0.0675 * K^2

= 0.0675 * ( 1200 / 1000 )^2

= 0.0675 * ( 1.2 )^2

=  0.0675 * ( 1.44 )

= 0.0972 m

(c) 4500 ft long

= 0.0206 * F^2

= 0.0206 * ( 4500 / 1000 )^2

= 0.0206 * ( 4.5 )^2

=  0.0206 * ( 20.25 )

= 0.4172 ft

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The XYZ Company is planning a new product line and a new factory to produce the parts and assemble the final products. The product line will include 13 different models. Annual production of each model is expected to be 1,000 units. Each product will be assembled of 250 components, but 65% of these will be purchased parts (not made in the new factory). There is an average of 8 processing operations required to produce each component, and each processing step takes 30 sec (including an allowance for setup time and part handling). Each final unit of product takes 48 min to assemble. All processing operations are performed at work cells that include a production machine and a human worker. Products are assembled at single workstations consisting of one worker each plus assembly fixtures and tooling. Each work cell and each workstation require 25 m2 of floor space and an additional allowance of 45% must be added to the total production area for aisles, work-in-process storage, shipping and receiving, rest rooms, and other utility space. The factory will operate one shift (the day shift, 2,000 hr/yr). Determine:
(a) how many processing and assembly operations,
(b) how many workers (direct labor only), and
(c) how much total floor space will be required in the plant.

Answers

In summary, the XYZ Company will require:

(a) 705 processing and assembly operations,

(b) 710 workers (direct labor only), and

(c) 25,738 m2 of total floor space for the new plant.

How to solve

To calculate the required processing and assembly operations, workers, and total floor space for the new factory, we can break down the problem into smaller parts and analyze each element.

(a) Processing and assembly operations:

Number of components made in the factory: 250 components * 35% = 87.5 (round up to 88 components)

Processing operations for components: 88 components * 8 processing operations = 704 processing operations

Assembly operations for final product: 1 assembly operation (as each product is assembled in one workstation)

Total operations = 704 processing operations + 1 assembly operation = 705 operations

(b) Number of workers (direct labor only):

Processing workers: 704 processing operations / 1 (one worker per work cell) = 704 workers

Assembly workers: 13 models * 1000 units/model = 13,000 units/year

Assembly time per unit: 48 min/unit = 0.8 hr/unit

Assembly time for all products: 13,000 units * 0.8 hr/unit = 10,400 hr

Assembly workers required: 10,400 hr / 2,000 hr/shift = 5.2 (round up to 6 workers)

Total workers = 704 processing workers + 6 assembly workers = 710 workers

(c) Total floor space required:

Processing floor space: 704 work cells * 25 m2/cell = 17,600 m2

Assembly floor space: 6 workstations * 25 m2/station = 150 m2

Total production area: 17,600 m2 + 150 m2 = 17,750 m2

Additional allowance (45%): 17,750 m2 * 45% = 7,987.5 m2

Total floor space = 17,750 m2 + 7,987.5 m2 = 25,737.5 m2 (round to 25,738 m2)

In summary, the XYZ Company will require:

(a) 705 processing and assembly operations,

(b) 710 workers (direct labor only), and

(c) 25,738 m2 of total floor space for the new plant.

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Calibrations on a recent version of an operating system showed that on the client side, there is a delay of at least 0.5 ms for a packet to get from an application to the network interface and a delay of 1.4 ms for the opposite path (network interface to application buffer). The corresponding minimum delays for the server are 0.20 ms and 0.30 ms, respectively.

What would be the accuracy of a run of the Cristian's algorithm between a client and server, both running this version of Linux, if the round trip time measured at the client is 6.6 ms?

Answers

Answer:

4.2ms

Explanation:

Calibrated time= 0.3+0.2+0.5+1.4= 2.4

Measured time= 6.6ms

Accuracy is closeness of measurement to an observed or true value

Accuracy= 6.6-2.4= 4.2ms

A cylindrical buoy is 2m in diameter and 2.5m long and weight 22kN . The specific weight of sea water is 10.25kN/m^3 . (I) Show that buoy does not float with its axis vertical. (II). What minimum pull should be applied to a chain attached to the center of the base to keep the buoy vertical?

Answers

Answer:

\(GM<0\)

So the bouy does not float with its axis vertical

Explanation:

From the question we are told that:

Diameter \(d=2m\)

Length \(l=2.5m\)

Weight \(W=22kN\)

Specific weight of sea water \(\mu= 10.25kN/m^3\)

Generally the equation for weight of cylinder is mathematically given by

Weight of cylinder = buoyancy Force

\(W=(pwg)Vd\)

Where

\(V_d=\pi/4(d)^2y\)

Therefore

\(22*10^3=10.25*10^3 *\pi/4(2)^2y\\\\\22*10^3=32201.3247y\\\\\y=1.5m\)

Therefore

Center of Bouyance B

\(B=\frac{y}{2}=0.26m\\\\B=0.75\)

Center of Gravity

\(G=\frac{I.B}{2}=2.6m\)

Generally the equation for\BM is mathematically given by

\(BM=\frac{I}{vd}\\\\BM=\frac{3.142/64*2^4}{3.142/4*2^2*0.5215}\\\\BM=0.479m\\\\\)

Therefore

\(BG=2.6-0.476\\\\BG=0.64m\)

Therefore

\(GM=BM-BG\\\\GM=0.479m-0.64m\\\\GM=-0.161m\\\\\)

Therefore

\(GM<0\)

So the bouy does not float with its axis vertical

1. The term lefty loosey, righty tighty is used to prevent what?

Answers

Answer:

Used to recall the direction a standard screw

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