2. Find each product in lowest terms.
a) 3/4 x 1 7/9 b) 4 4/7 x 3 1/4
c) 1 7/8 x 2 1/4



please help me I want it right now​

Answer:

Step-by-step explanation:

In the question we are given ,

And , we have to find the height of cylinder .

We know that ,

\(

\longrightarrow \pink{ \boxed{Volume \: of \: Cylinder = \pi r {}^{2}h }} \longleftarrow\)

Our solution starts from here :

\( \longmapsto \: \pi \: r {}^{2} h = 225\pi\)

Step 1 : Cancelling π with π :

\( \longmapsto \: \cancel{\pi} \: r {}^{2} h = 225 \cancel{\pi}\)

Step 2 : Substituting value of radius which is 5 cm in the formula :

\( \longmapsto \: (5) {}^{2} \times h = 225\)

\( \longmapsto \: 25h = 225\)

Step 3 : Transposing 25 to right hand side :

\( \longmapsto \: h = \frac{225}{25} \)

Step 4 : Cancelling 225 by 25 :

\( \longmapsto \: \red{\boxed{h = 9 \: cm}}\)

Answer:

A) 20+0.6\(x\)

B) range is [0, 50] (i.e. both inclusive)

C) 8.33 litres

Step-by-step explanation:

Given that concentration of acid in 50 litre container is 40%.

Amount of acid in the container = 40% of 50 litres

Amount of acid in the container = \(\frac{40}{100} \times 50 = 20\ litre\)

\(x\) litres are removed.

Amount of acid removed = 40% of \(x\) litre.

Now, remaining acid in the container = (20 - 40% of \(x\)) litre

Now, replaced with 100% acid.

So, final acid in the container = (20 - 40% of \(x\) + 100% of \(x\) ) litre

Amount of acid in the final mixture:

\(20 - \dfrac{40}{100} \times x + \dfrac{100}{100} \times x\\\Rightarrow 20 +\dfrac{100-40}{100}x\\\Rightarrow 20 +\dfrac{60}{100}x\)

Answer A) Amount of acid in the final mixture = 20+0.6\(x\)

Answer B) \(x\) can not be greater than 50 litres (initial volume of container) and can not be lesser than 0 litres.

so, range is [0, 50] (i.e. both inclusive)

Answer C)

Given that final mixture is 50% acid.

amount of acid = 50% of 50 litres = 25 litres

Using the equation:

\(20+0.6x =25\\\Rightarrow 0.6x =5\\\Rightarrow \bold{x =8.33\ litres}\)

statement D declares the student grade variable .

What is variable ?

In computer programming, a variable is associate degree abstract storage location paired with associate degree associated symbolic name, that contains some famous or unknown amount of knowledge brought up as a value; or in easier terms, a variable may be a named instrumentation for a specific set of bits or style of information.

Main body:

As we need to assign grade to students out of A,B,C,D,F

so we need to use enum as formula and assign the name as grades .

Hence the answer is  enum grades {a, b, c, d, f} studentgrade.

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Answer:

1. Put a dot at y=4

2. Go DOWN 5 blocks, go RIGHT 4 blocks

3. Put a dot at this point

4. Connect your 1st dot to the second dot for your first line segment

5. Follow the pattern

A recursive definition of a function cwi (I0) that returns a set of companies that have at least one investor in set I0 is provided below in pseudocode. The base case is when there is only one investor in the set I0.

The base case involves finding the companies that the investor owns and returns the set of companies.The recursive case is when there are more than one investors in the set I0. The recursive case divides the set of investors into two halves and finds the set of companies owned by the first half and the second half of the investors.

The recursive case then returns the intersection of these two sets of def cwi(I0):

companies.pseudocode:

   if len(I0) == 1:

       i = I0[0]

       return [c for (j, c, n) in ICN if j == i and n > 0]

   else:

       m = len(I0) // 2

       I1 = I0[:m]

       I2 = I0[m:]

       c1 = cwi(I1)

       c2 = cwi(I2)

       return list(set(c1) & set(c2))

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The intervals of concavity for f(x) = 3 cos x, with 0 < x < 21, are (0, π/2) and (3π/2, 2π).

To find the intervals of concavity for f(x) = 3 cos x, we need to analyze the second derivative of the function.

First, let's find the second derivative of f(x):

f'(x) = -3 sin x (derivative of cos x)

f''(x) = -3 cos x (derivative of -3 sin x)

Now, we can analyze the concavity of f(x) by considering the sign of the second derivative:

When x ∈ (0, π/2): In this interval, cos x > 0, so f''(x) < 0. The second derivative is negative, indicating concavity downwards.

When x ∈ (π/2, 3π/2): In this interval, cos x < 0, so f''(x) > 0. The second derivative is positive, indicating concavity upwards.

When x ∈ (3π/2, 2π): In this interval, cos x > 0, so f''(x) < 0. The second derivative is negative, indicating concavity downwards.

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∑Hey , jillianwagler ⊃

Answer:

x = 7, y = -5

Step-by-step explanation:

Given~:

Solve the system below using elimination

{5x+9y= -10}

{7x+10y= -1}

Solve:

\(\begin{bmatrix}5x+9y=-10\\ 7x+10y=-1\end{bmatrix}\)

Isolate x ( 5x + 9y = -10 ) : \(\mathrm{x=\frac{-10-9y}{5}}\)

Substitute: \(\mathrm{x=\frac{-10-9y}{5}}\)

\(\begin{bmatrix}7\cdot \frac{-10-9y}{5}+10y=-1\end{bmatrix}\)

\(\begin{bmatrix}\frac{-70-13y}{5}=-1\end{bmatrix}\)

Isolate y : \(\frac{-70-13y}{5}=1:y=-5\)

Substitute: \(y=-5\)

\(x=\frac{-10-9\left(-5\right)}{5}=7\)

Hence, \(x=7\)

Therefore, the solution for \(\begin{bmatrix}5x+9y=-10\\ 7x+10y=-1\end{bmatrix}\) are:

\(x=7,\:y=-5\)

xcookiex12

8/19/2022

The value of the line integral is: (100 + √5)/3.

We need to evaluate the line integral:

∫c x² + y² + z² ds

where c is the path defined by r(t) = sin(t)i + cos(t)j + 2tk, 0 ≤ t ≤ 5.

We have ds = ||r'(t)|| dt, so we need to find r'(t):

r'(t) = cos(t)i - sin(t)j + 2k

||r'(t)|| = √(cos²(t) + sin²(t) + 2²) = √(1 + 4) = √5

Now we can evaluate the line integral:

∫c x² + y²+ z² ds = ∫0⁵ (sin²(t) + cos²(t) + (2t)²) √5 dt

= ∫0^5 (1 + 4t²) √5 dt

= (1/3) √5 t + (4/5) √5 t³ |0⁵

= (1/3) √5 (5) + (4/5) √5 (125)

= √5 (1/3 + 100)

= (100 + √5)/3

Therefore, the value of the line integral along the given path is (100 + √5)/3.

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The function f(x) that satisfies the initial-value problem f'(x) = 6x^2 - 8x and f(1) = 3 is f(x) = 2x^3 - 4x^2 + 5.

The given initial-value problem is f'(x) = 6x^2 - 8x with the initial condition f(1) = 3. We need to find the function f(x) by integrating f'(x) and determine the value of the constant of integration using the condition f(1) = 3.

To find f(x), we integrate the right-hand side of the differential equation f'(x) = 6x^2 - 8x with respect to x. The integration of a polynomial involves increasing the power of x by 1 and dividing by the new power. Integrating each term separately, we have:

∫(6x^2 - 8x) dx = 2x^3 - 4x^2 + C

Here, C is the constant of integration.

Now, we need to determine the value of C using the condition f(1) = 3. Substituting x = 1 into the expression for f(x), we get:

f(1) = 2(1)^3 - 4(1)^2 + C = 2 - 4 + C = -2 + C

Since f(1) is given as 3, we can equate it to -2 + C and solve for C:

-2 + C = 3

Adding 2 to both sides gives:

C = 3 + 2 = 5

Therefore, the constant of integration C is 5.

Now we can write the function f(x) by substituting the value of C into our previous expression:

f(x) = 2x^3 - 4x^2 + C = 2x^3 - 4x^2 + 5

In summary, the function f(x) that satisfies the initial-value problem f'(x) = 6x^2 - 8x and f(1) = 3 is f(x) = 2x^3 - 4x^2 + 5. We found this function by integrating f'(x) and determining the value of the constant of integration using the condition f(1) = 3.

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The average CPI of the ARM processor is 0.9 with 2 ALU pipeline stages and 30% data hazards, 1/3 of which are LDR data hazards.

The given information are as follows:

Running program through two parallel ALUs increases the overall speed by 20%.

The delay time was attributable to the ALU.

The percentage increase of delay time will be= (20/120) x 100=16.67%

Thus, the percentage of the delay time attributable to the ALU is 16.67%.

The given information are as follows: Back to single ALU 5-stage pipelined baseline design with forwarding10% of the operations involve load hazardsLoad CPI = 2; all other ops CPI = 1

The formula used for average CPI is as follows:

Average CPI = ((frequency of load operation * load CPI) + (frequency of all other operations * CPI of all other operations)) / Total number of instructions

Therefore, the frequency of load operation will be 10% of the total number of instructions.

Therefore, the average CPI will be, Average CPI= (10/100) x 2 + (90/100) x 1

= 0.2 + 0.9= 1.1

Hence, the average CPI of a standard 5-stage pipelined ARM processor with forwarding will be 1.1.5.3

2 ALU pipeline stages and 30% data hazards1/3 of which are LDR data hazards.

The formula used to calculate the average CPI is, Average CPI = ((frequency of LDR operation * LDR CPI) + (frequency of all other operations * CPI of all other operations)) / Total number of instructions

Therefore, the frequency of LDR operation will be 30% of 1/3 of the total number of instructions.

Therefore, the average CPI will be,Average CPI = (30/100 x 1/3 x 2) + (70/100 x 1)

= 0.2 + 0.7 = 0.9

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Answer:

-3 and 8

Step-by-step explanation:

I hope this helps!

Answer:

24

Step-by-step explanation:

you would have to do 12 x 1.5 to get 18 then so 16 x 1.5 to get 24

The depth of the water in the cone-shaped tank is increasing at a rate of approximately 1.385 meters per second.

To determine the rate at which the depth of the water is changing, we can use related rates. Let's denote the depth of the water as h(t), where t represents time. We are given that dh/dt (the rate of change of h with respect to time) is 12 m/sec, and we want to find dh/dt when h = 18 meters.

To solve this problem, we can use the volume formula for a cone, which is V = (1/3)πr^2h, where r is the base radius and h is the depth of the water. We can differentiate this equation with respect to time t, keeping in mind that r is a constant (since the base radius does not change).

By differentiating the volume formula with respect to t, we get dV/dt = (1/3)πr^2(dh/dt). Now we can substitute the given values: dV/dt = 12 m/sec, r = 26 meters, and h = 18 meters.

Solving for dh/dt, we have (1/3)π(26^2) (dh/dt) = 12 m/sec. Rearranging this equation and solving for dh/dt, we find that dh/dt is approximately 1.385 meters per second. Therefore, the depth of the water in the tank is increasing at a rate of about 1.385 meters per second.

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The slope for the function f(t) = 3 - 3/5t at point (3/5, 2) is 5/3.

What is slope?

A line's steepness and direction are measured by the line's slope. Without actually using a compass, determining the slope of lines in a coordinate plane can assist in forecasting whether the lines are parallel, perpendicular, or none at all.

The given function is - f(t) = 3 - 3/5t.

The data points are - (3/5, 2)

Rewrite the function -

f(t) = 3 - 3/5 t^-1

Differentiate with respect to t. Use the difference rule.

d/dt (3) - d/dt (3/5 t^-1)

Use the constant rule and the constant multiple rule.

0 - 3/5 d/dt (t^-1)

Use the power rule.

-3/5(-1)t^(-1 - 1)

3/5t^-2

Now plug in 3/5 for t on the derivative in order to find the slope at point (3/5, 2).

3/5(3/5)^-2

3/5(5/3)^2

3/5 × 25/9

5/3

Therefore, the slope value is 5/3.

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Find the slope of the graph of the function at the given point.

Function Point f(t) = 3 - 3/5t (3/5, 2)

Answer: C: 0.4

Step-by-step explanation:

1/5 is 0.2 and double that is 0.4 since there are 2 half hours in an hour :)

Step-by-step explanation:

m1:90 degrees . .... angles in a perpendicular line

m2: 180-(90+27).....angles in a triangle add to 180 degrees

m3:63 degrees ... angles in an iscolese triangle

The measure of angles 1, 2, 3 are -  \(90^{o} ,\;63^{0} ,\;63^{0}\).

Consider the figure attached.

We have a labelled kite similar to mentioned in the question. We have angle ABO = \(27^{o}\).

We have to find the measure of angle 1, 2, 3.

Here are some of the properties of kite -

According to the question -

In ΔAOB,

\(\angle2 + \angle ABO+\angle AOB = 180^{o} \\\angle2+27^{o} +90^{o}=180^{o}\\\angle2+117^{o} =180^{o}\\\angle2 = 63^{o}\)

Th, the two angles opposite to the two equal sides are also equal, since BA and BC are equal, therefore - \(\angle2=\angle3\)\(=63^{o}\).

Since the diagonals of the kite intersect each other perpendicularly, therefore -

\(\angle1=90^{o}\)

Hence the measure of angles 1, 2, 3 are -  \(90^{o} ,\;63^{0} ,\;63^{0}\).

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Answer:

3 hours 39 minutes

Step-by-step explanation:

6 to 10 = 4 hours

35 to 14 = -21

4 x 60 = 240

240 - 21 = 219

220 to hours and minutes = 3 hours and 39 minutes

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:

10,710 People claimed their water bottle

Step-by-step explanation:

The correlation for the resulting data, when each of the X values were multiplied by 2, is r=0.10.

Explanation:

Given that, a set of n=15 pairs X and Y values has a Pearson correlation of r=0.10. And, in each of the X values were multiplied by 2, then we need to calculate the correlation for the resulting data.

When each of the X values is multiplied by 2, then the resulting correlation does not change. It is because the correlation coefficient of Pearson, r, only measures the linear relationship between two variables and not the scale of the variables.

Thus, the correlation for the resulting data, when each of the X values were multiplied by 2, is r=0.10.

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Answer:

Step-by-step explanation:

to find the slope of a line that passes for two given points we can use this formula (y2-y1)/(x2-x1). x and y inidcate the coordinates of the two points.

A (-2-7)/(-4-5) = (-9)/-9 = 1 (m is positive)

B (-10-3)/(1-1)) = the denominator is equal to zero, so the division is impossibile. This mean that m is undefined and the line is parallel to y axis

The part of the figure of a circle labeled as angle APB is

The part of the circle marked by a question marked as angle APB is solved using the relationship below

given angle formed by the tangents = major arc ACB - 180 degrees

information given in the problem includes

given angle formed by the tangents = angle APB

major arc ACB = 266

substituting in these values results to

given angle formed by the tangents = 266 degrees - 180 degrees

given angle formed by the tangents = 86 degrees

hence the required side, which is angle APB is 86 degrees

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Answer:

C

Step-by-step explanation:

Use the pythagorean theorem.

32^2+b^2=48^2

1024+b^2=2304

Subtract 1024

b^2=1280

Square root

b=sqrt(1280)

Now simplify sqrt(1280)

sqrt(1280) = sqrt(256*5)

You can take the square root of 256 since it is a perfect square so take it out of the radical.

sqrt(256*5)=16sqrt(5)

So the answer is c, 16\(\sqrt{5}\)

Answer:

C. 16/5

Step-by-step explanation:

pythagorean theorem

a^2 + b^2 = c^2

divide 48 and 32 by 16

a= 2 c= 3

4 + b^2 = 9

b^2 = 5

b = √5

then multiply 16 with √5

which =

16√5

Answer:

Each pair costs $8.86

Step-by-step explanation:

Divide 35.45 by 4

You get 8.8625

Round that to the nearest hundredth.

You get $8.86

Hope this helped!

The conditional expectation of Y given that X is less than or equal to 1/2 is calculated by taking the weighted average of the possible values of Y, with the weights being the probabilities of X being less than or equal to 1/2 for each value of Y.
The formula for E(Y | X<=1/2) is:
E(Y | X<=1/2) = ∑y P(Y=y | X<=1/2) * y
To find P(Y=y | X<=1/2), we can use the formula:
P(Y=y | X<=1/2) = P(X<=1/2 | Y=y) * P(Y=y) / P(X<=1/2)
We can then plug in the values for each possible value of Y and calculate the conditional expectation.

For example, if Y can take on the values 0, 1, and 2, and the probabilities of X being less than or equal to 1/2 for each value of Y are 0.2, 0.5, and 0.3, respectively, and the probabilities of Y being 0, 1, and 2 are 0.4, 0.3, and 0.3, respectively, then:
E(Y | X<=1/2) = (0.2 * 0.4 / 0.5) * 0 + (0.5 * 0.3 / 0.5) * 1 + (0.3 * 0.3 / 0.5) * 2
E(Y | X<=1/2) = 0 + 0.3 + 0.36
E(Y | X<=1/2) = 0.66

Therefore, the conditional expectation of Y given that X is less than or equal to 1/2 is 0.66.

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Answer:

A. 3^-2

Step-by-step explanation:

the question is 3^6/3^8

according to the law of exponents

a^n/a^m = a^n-m

for this question it will be

3^6-8 which is 3^-2

you're welcome....

Answer:

B on edge

Step-by-step explanation:

The graph that represents the function g(x) = |x + 4| + 2 is graph A.

Option A is the correct answer.

A function has an input and an output.

A function can be one-to-one or onto one.

It simply indicated the relationships between the input and the output.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

The function g(x) = |x + 4| + 2 is a transformation of the absolute value function f(x) = |x|.

The absolute value function has a V-shaped graph that passes through the origin with a slope of 1 on both sides.

When a constant is added to the absolute value function, it shifts the graph vertically.

In this case, the constant 4 is added inside the absolute value, which shifts the graph horizontally to the left by 4 units.

Next, the constant 2 is added to the result of the previous operation, which shifts the graph vertically upwards by 2 units.

The graph of g(x) = |x + 4| + 2 is a V-shaped graph that has been shifted 4 units to the left and 2 units upwards, as shown below:

The vertex of the V-shape is at (-4, 2), where the absolute value function crosses the x-axis.

The slope of the graph on both sides of the vertex is 1.

Thus,

The graph that represents the function g(x) = |x + 4| + 2 is graph A.

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Step-by-step explanation:

Everytime the dice is rolled, there is a 50% chance to get an odd number.

Hence 50% * 50% = 25%.

Answer:

in total 21 miles

Step-by-step explanation:

The given information tells us that the sin a is equal to 5/13, and that 0 is less than a, which is less than π/2. Therefore, the exact function value for sin a is 5/13 and the value for a is approximately  5/12.

We are given that sin(a) = 5/13 and 0 < a < π/2. We can use the Pythagorean identity cos²(a) + sin²(a) = 1 to find cos(a):

cos²(a) + sin²(a) = 1

cos²(a) + (5/13)² = 1

cos²(a) = 1 - (5/13)²

cos²(a) = 144/169

cos(a) = ± 12/13

Since 0 < a < π/2, we know that cos(a) > 0. Therefore, cos(a) = 12/13. We can use the definition of tangent to find tan(a):

tan(a) = sin(a)/cos(a) = (5/13)/(12/13) = 5/12

Therefore, the exact function value we were asked to find is tan(a) = 5/12.

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