2. A rock occupies a volume of 20 cm and has a mass of 54 grams. Find the density of
this rock.

Answer:

isotope

isotope

isotope

isotope

isotope

isotope

isotope

isotope

isotope

Answer:

false

Explanation:

jk true

Answer: 13.1

Explanation: just round the .06 to 1 creating three sig figs.

When determining the weak link that limits overall precision in methods that employ multiple measurements, the measurements of dimensions contribute more to the CV of the calculated density than the measurements of mass.

In this question, we are asked to determine what contributes the most to the coefficient of variation (CV) of the calculated density - the measurements of mass or of dimensions. The CV is a measure of the relative variability of a set of data, and a higher CV indicates greater variability.

To answer this question, we need to compare the standard deviations of the measurements of mass and dimensions. The standard deviation tells us how spread out the measurements are around the mean. In this case, the standard deviation for measurements of length (dimension) is 0.01 cm, while the standard deviation for measurements of mass is 0.002 g.

The CV is calculated by dividing the standard deviation by the mean and multiplying by 100. So, to determine what contributes the most to the CV of the calculated density, we need to compare the ratios of the standard deviation to the mean for mass and dimensions.

Let's consider an example: Suppose the mean mass of the lightest object is 10 g, and the mean length is 5 cm. The ratio of the standard deviation to the mean for mass is 0.002 g / 10 g = 0.0002, while the ratio for dimensions is 0.01 cm / 5 cm = 0.002.

From this example, we can see that the ratio for dimensions is higher than the ratio for mass. Therefore, the measurements of dimensions contribute more to the CV of the calculated density than the measurements of mass.

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The question is about identifying the 'weak link' in density measurements by comparing the coefficient of variation (CV) of mass and dimension measurements. Given the standard deviations, it is likely that dimensions are the 'weak link'. By identifying this, one can improve the precision of measurements.

This question is about determining the primary cause of variation, or the 'weak link', in density measurements made. This is done by analyzing the relative contribution of different measurements to the coefficient of variation (CV) of the density. In this case, the student has to compare the contribution to the CV from measurements of mass and dimensions.

Given the standard deviations for the measurements of dimensions and mass with the lab equipment, the student will need to calculate the CV of both sets of measurements. It is expected that the CV for the dimensions (Standard deviation/mean) will be larger given the higher standard deviation compared to mass. Therefore, dimensions may be the 'weak link' that is causing a higher overall CV for your density measurements.

In conclusion, by comparing the CVs for the measurements of mass and dimensions, you can identify which contributes most to the variation in your calculated density and thus improve your measurement precision.

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Au\(_2\)O\(_3\)  is empirical formula of a compound which consists of 89.14% Au and 10,80% of oxygen.

A compound's empirical equation is defined as both the formula that displays the ratio of substances contained in the compound rather than the actual number of atoms contained in the molecule. Subscripts adjacent towards the element symbols indicate the ratios.

So because subscripts are really the fewest whole integers that reflect the ratio of components, the empirical formula also was called as the simplest formula.

moles of Au = 0.8914 g/ (196.97 g/mol) = 4.5255 x 10⁻³ mols

moles of oxygen= (0.1080 g)/ (16 g/mol) = 6.75 x 10⁻³mols

Simplest whole number ratio

Au = 4.5255 x 10⁻³  /  4.5255 x 10⁻³  moles = 1

O = 6.75 x 10⁻³ mols/  4.5255 x 10⁻³  moles = 1.5

empirical formula= Au\(_2\)O\(_3\)

Therefore, empirical formula is Au\(_2\)O\(_3\).

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1- ΔH2 = -ΔH1 (The enthalpy change for the reverse reaction is the negative of the enthalpy change for the forward reaction.)

2- ΔH3 = 3ΔH1 (The enthalpy change for the reaction involving the formation of 6 moles of Al2O3 is three times the enthalpy change for the formation of 2 moles of Al2O3.)

3- ΔH4 = 0.5ΔH1 (The enthalpy change for the reaction involving the formation of one mole of Al2O3 is half the enthalpy change for the formation of 2 moles of Al2O3.)

To express the enthalpy of a reaction in terms of another reaction, we can use the concept of Hess's law. Hess's law states that the overall enthalpy change of a reaction is independent of the pathway taken and depends only on the initial and final states of the reaction.

Expressing ΔH2 in terms of ΔH1:

The reaction (ΔH2) is the reverse of the formation of aluminium oxide from aluminium and oxygen (ΔH1), so the enthalpy change for the reverse reaction will have the opposite sign. Therefore, we have:

ΔH2 = -ΔH1

Expressing ΔH3 in terms of ΔH1:

The reaction (ΔH3) involves the formation of 6 moles of Al2O3, whereas the formation of Al2O3 in ΔH1 involves the formation of 2 moles of Al2O3. Therefore, the enthalpy change for ΔH3 will be three times that of ΔH1. Hence:

ΔH3 = 3ΔH1

Expressing ΔH4 in terms of ΔH1:

The reaction (ΔH4) involves the formation of one mole of Al2O3, whereas the formation of Al2O3 in ΔH1 involves the formation of 2 moles of Al2O3. Therefore, the enthalpy change for ΔH4 will be half that of ΔH1. Hence:

ΔH4 = 0.5ΔH1

In summary:

ΔH2 = -ΔH1

ΔH3 = 3ΔH1

ΔH4 = 0.5ΔH1

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When a current is applied to an aqueous solution of sodium sulfide, the following reactions take place:

At the cathode: Na+(aq) + e- → Na(s)
Sodium ions in the solution gain an electron and form solid sodium metal at the cathode.

At the anode: 2H2O(l) → O2(g) + 4H+(aq) + 4e-
Water molecules are oxidized to produce oxygen gas, hydrogen ions, and electrons at the anode.

Therefore, the product produced at the cathode is solid sodium metal (Na(s)), and the product produced at the anode is oxygen gas (O2(g)), hydrogen ions (H+(aq)), and electrons.

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Answer:

Why do you need good toothpaste?

Explanation:

Answer:

Do this yourself smh this isnt what the wesite is for

Explanation:

Answer: In a vacuum, the objects fall at the same rate independent of their respective masses. That means coin and feather both reach ground at same time in a vacuum. Larger objects experience more air resistance than smaller objects. Also, the faster an object falls, the more air resistance it encounters.

Explanation:

Answer:

As electrons are added to the valence shell, an extra proton (i.e fundamental, positively charged nuclear particle) is added to the element's nucleus. As electrons add and Z the atomic number increases 1 by 1, nuclear charge WINS, and electronic radii contract.

Explanation:

Hope this helps you

Crown me as brainliest:)

Answer:

1M

Explanation:

The molarity of a substance is defined as the number of moles of the substance divided by how many liters the solution is. NaOH has a molar mass of about 40 grams, meaning that 10 grams of it would be 0.25 moles. 0.25/0.25= a molarity of 1.

Hope this helps!

Solution of a:

The three primary classes of materials are metals, ceramics, and polymers. They can be distinguished based on their chemical composition, atomic structure, and physical properties.

Metals: Metals are typically solid, opaque, and good conductors of heat and electricity. They have a crystalline atomic structure with closely packed atoms arranged in a regular pattern. They exhibit metallic bonding, where valence electrons are delocalized and form a "sea" of electrons, resulting in malleability, ductility, and high tensile strength.

Ceramics: Ceramics are typically hard, brittle, and insulators of heat and electricity. They have an atomic structure with a combination of metallic and non-metallic elements. They are composed of non-metallic compounds, such as oxides, nitrides, and carbides. Ceramics have strong ionic or covalent bonds, resulting in high melting points and chemical stability.

Polymers: Polymers are typically lightweight, flexible, and insulators of heat and electricity. They have large molecular structures composed of repeating units called monomers. Polymers have covalent bonds between atoms in the monomer units and weak intermolecular forces between polymer chains. This gives them low melting points, low density, and the ability to be molded into different shapes.

Solution of b:

Transition elements occur in the Periodic Table due to their unique atomic structure.

Transition elements, also known as transition metals, are located in the central block of the periodic table between the s-block and p-block elements. They are characterized by partially filled d orbitals in their atomic structure. The d orbitals can hold a maximum of 10 electrons.

The occurrence of transition elements in the periodic table is a result of the filling of electron shells according to the Aufbau principle and the Pauli exclusion principle. As electrons are added to an atom, they occupy the lowest available energy levels first. In the case of transition elements, after the filling of the s orbitals in the previous period, the d orbitals start to fill. The filling of the d orbitals leads to the transition from one period to another.

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Answer:

c. no reaction happens

Explanation:

Let me take your mind back to the idea of electrode potentials of metals. Remember that the more negative the electrode potential of a metal, the more reducing the metal is. Metals with more negative electrode potentials displace metals with less negative electrode potentials from their aqueous solutions.

The electrode potential of nickel is -0.25 V while that of copper is +0.34 V. Hence, copper is lower than nickel in the activity series and can not displace it from aqueous solution.

This implies that, if a piece of copper metal is placed in a solution that contains nickel(II) ions, no reaction happens .

Answer:

its a

Explanation:

Answer:

c

Explanation:

The most probable mechanism is SN1 (substitution nucleophilic unimolecular) mechanism.

If the rate of substitution for a specific substitution reaction is independent of both the nature and concentration of the nucleophile, it is not possible for both SN1 and SN2 mechanisms to account for the observations. Substitution reaction is a chemical reaction that entails the exchange of one substituent (or atom) for another in a molecule.

The substituents are exchanged with no change in the molecular framework. The nucleophile attacks the substrate (electrophile) in a substitution reaction.

Mechanism:The substitution nucleophilic unimolecular (SN1) mechanism is the most plausible mechanism. The SN1 reaction is a two-step process in which the initial step is rate-determining, while the second step is rapid. In this process, the leaving group (substituent) is first dissociated, generating a carbocation intermediate.

The nucleophile (new substituent) then attaches to the carbocation.Intermediate formation in the rate-determining step distinguishes the SN1 reaction from the SN2 reaction. The SN2 reaction is a one-step process, in which the substrate is attacked by the nucleophile while the leaving group departs.

Thus, if the rate of substitution for a specific substitution reaction is independent of the concentration and nature of the nucleophile, the SN1 mechanism is the most plausible.

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1. The number of mole in 0.293 Kg of Pb is 1.42 mole

2. The number of atom in 0.293 Kg of Pb is 8.55×10²³ atoms

1. How to determine the number of mole

The numbe of mole in the 0.293 Kg of Pb can be obtained as follow:

Mole = mass / molar mass

Number of mole of = 293 / 207

Number of mole = 1.42 mole

Thus, the number of mole is 1.42 mole

2. How to determine the number of atoms

The number of atoms can be obtained as follow:

From Avogadro's hypothesis,

1 mole of Pb = 6.02×10²³ atoms

Therefore,

1.42 mole of Pb = (1.42 mole × 6.02×10²³ atoms) / 1 mole

1.42 mole of Pb = 8.55×10²³ atoms

Thus, the number of atoms is 8.55×10²³ atoms

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In an ionization counter, radioactive emissions collide with gas particles, producing ion pairs, which can be detected as an electric current.

The radiation ionizes the gas atoms or molecules, creating charged particles that are then collected as a current, allowing for the detection and measurement of radioactivity.

On the other hand, a scintillation counter detects radioactive emissions by its ability to excite atoms and cause them to emit photons (light). The radiation interacts with certain materials, such as scintillators, which absorb the energy and re-emit it as visible light. The emitted light is then converted into an electric current through the photoelectric effect or the use of photomultiplier tubes, enabling the detection and measurement of radioactivity based on the emitted light intensity.

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3H₂(g)+N₂(g)——> 2NH₃ (g) , here the volume of NH₃(g) measured at STP is produced when 2.15 L of H₂(g) reacts is approximately 1.58 L of NH₃ gas will be produced when 2.15 L of H₂ reacts at STP.

3H₂(g) + N₂(g) → 2NH₃ (g)

3 moles of H₂ reacts to produce 2 moles of NH3. Therefore, one need to first calculate the number of moles of H₂ in 2.15 L.

PV = nRT

P= is the pressure (STP has a pressure of 1 atm), V =is the volume in liters, n is the number of moles, R= is the ideal gas constant (0.0821 L·atm/mol·K), T =is the temperature in Kelvin (STP has a temperature of 273 K).

Here, 

n(H₂) = (P(H₂) × V(H₂)) / (R × T)

Assuming the pressure of H₂ is also 1 atm at STP, and substituting the values:

n(H₂) = (1 atm × 2.15 L) / (0.0821 L·atm/mol·K × 273 K) n(H₂) ≈ 0.0954 mol

According to the balanced equation, 3 moles of H₂ react to produce 2 moles of NH3. Therefore, one can determine the number of moles of NH₃ produced:

n(NH₃ ) = (2/3) × n(H₂) n(NH₃ )

≈ (2/3) × 0.0954 mol n(NH₃ )

≈ 0.0636 mol

V(NH₃ ) = (n(NH₃  × R × T) / P(STP)

Substituting the values:

V(NH₃ ) = (0.0636 mol × 0.0821 L·atm/mol·K × 273 K) / (1 atm) V(NH₃ )

≈ 1.58 L

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Answer:

friction

Explanation:

jwjwkkskskaksksk

Isopropyl is a secondary alcohol because it has two alkyl groups attached to the carbon atom that is bonded to the hydroxyl group (-OH).

In the case of isopropyl alcohol, the carbon atom that carries the hydroxyl group is bonded to two other carbon atoms, which means it is a secondary carbon.

This makes isopropyl alcohol a secondary alcohol, which means it is structurally different from primary alcohols that have a hydroxyl group attached to a carbon atom that is bonded to only one other carbon atom. The classification of alcohols as primary, secondary, or tertiary is important because it affects their physical and chemical properties, as well as their reactivity in various chemical reactions.

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Answer:

temperature

Explanation:

Answer:

nucleus as electrons are being added to the same principal energy level. These electrons are gradually pulled closer to the nucleus because of its increased positive charge. Since the force of attraction between nuclei and electrons increases, the size of the atoms decreases.

Explanation:

Nuclear attractive pull to the electrons results in smaller atomic radius. Two reasons that leads the size of an atom smaller by electron loss are nuclear pulling and emptying outermost orbital.

The nucleus have a net positive charge and electrons are negative in charge, thus, each electron experience a nuclear attractive pull. However, each electrons are shielded slightly from this attraction by the surrounding electrons.

The reasons which make the atomic radius smaller are the following.

Therefore, due the two reasons mentioned above, the atomic radius reduces by electron loss.

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The N - H and the C- O  and the C- N bonds in indigo dye are polar on nature.

Indigo is a blue dye that is derived from the leaves of certain plants. The chemical structure of indigo consists of two benzene rings connected by a nitrogen atom. The molecule has several polar bonds due to the electronegativity differences between the atoms.

The polar bonds in indigo include:

The nitrogen-carbon bonds: The nitrogen atom in the middle of the molecule is connected to two carbon atoms, one in each benzene ring. Nitrogen is more electronegative than carbon, so the nitrogen-carbon bonds are polar.

The carbon-oxygen bonds: Indigo has two oxygen atoms that are double bonded to carbon atoms in the benzene rings. Oxygen is more electronegative than carbon, so the carbon-oxygen bonds are also polar.

The carbon-nitrogen bond: The nitrogen atom in the middle of the molecule is also connected to a carbon atom in one of the benzene rings. This bond is polar due to the electronegativity difference between carbon and nitrogen.

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Factor by which the force on the atom by the point charge changes when the distance is doubled:

The force between a neutral atom and a point charge is described by Coulomb's law, which states that the force is inversely proportional to the square of the distance between them. Therefore, if the distance between the neutral atom and the point charge is doubled, the force on the atom changes by a factor of 1/4.

When the distance is doubled, the force decreases because of the inverse square relationship. Mathematically, this can be expressed as:

Force₂ = (1/Distance₂^2) * Charge

where Force₂ is the new force, Distance₂ is the doubled distance, and Charge represents the magnitude of the point charge.

Comparing this to the original force (Force₁) at the original distance (Distance₁), we can calculate the ratio of the two forces:

Force₂ / Force₁ = (1/Distance₂^2) * Charge / (1/Distance₁^2) * Charge

Simplifying the expression:

Force₂ / Force₁ = Distance₁^2 / Distance₂^2

Since the distance is doubled (Distance₂ = 2 * Distance₁), we can substitute the values:

Force₂ / Force₁ = Distance₁^2 / (2 * Distance₁)^2

Force₂ / Force₁ = Distance₁^2 / (4 * Distance₁^2)

Force₂ / Force₁ = 1/4

Therefore, when the distance between a neutral atom and a point charge is doubled, the force on the atom by the point charge changes by a factor of 1/4.

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Answer:

The volume of the liquid remaining in the beaker is 0.24615 l

Explanation:

The initial volume of liquid in the beaker = 0.250 l

The volume of liquid the student pours out of the beaker = 0.00385 l

The volume of liquid remaining in the beaker, V, is given as follows;

V = The initial volume of liquid in the beaker - The volume of liquid the student pours out of the beaker

Therefore, we have;

V = 0.250 l - 0.00385 l = 0.24615 l

The volume of the liquid remaining in the beaker is 0.24615 l.

The pH at 25 °C of a 0.19 M solution of potassium cyanide . note that hydrocyanic acid is a weak acid with pka of 9.21 is 11.2.

The reaction is given as :

KCN  --->  K⁺   +   CN⁻

CN⁻  +  H₂O ⇄ HCN  +  OH⁻

KCN = HCN = 0.19 M

pka(HCN) = 9.21

ka HCN = 6.16 × 10⁻¹⁰

kb CN⁻ = 10⁻¹⁴ - 6.16 × 10⁻¹⁰

           = 1.62 × 10⁻⁵

[HCN] [OH⁻] = X

[CN⁻] = 0.19 M - x

kb = x² / (0.19 M - x )

1.62 × 10⁻⁵ =  x² / (0.19 M - x )

x = [OH⁻] = 0.00174 M

the pOH = - log (0.00174)

     pOH = 2.76

pH + pOH = 14

pH = 14 - pOH

pH = 14 - 2.76

pH = 11.2

Thus, The pH at 25 °C of a 0.19 M solution of potassium cyanide . note that hydrocyanic acid is a weak acid with pka of 9.21 is 11.2.

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37.5 moles of iron will produce 2990.31 grams of Fe₂O₃.

To determine the number of grams of Fe₂O₃ produced from 37.5 moles of iron (Fe), we need to use the balanced chemical equation for the reaction in which iron reacts to form Fe₂O₃.

The balanced equation for the reaction is:

4Fe + 3O₂ -> 2Fe₂O₃

From the balanced equation, we can see that 4 moles of iron react to produce 2 moles of Fe₂O₃. This means that the molar ratio between Fe and Fe₂O₃ is 4:2 or 2:1.

Now, we can set up a simple proportion to calculate the number of moles of Fe₂O₃ produced:

(37.5 moles Fe) * (2 moles Fe₂O₃ / 4 moles Fe) = 18.75 moles Fe2O3

So, 37.5 moles of iron will produce 18.75 moles of Fe₂O₃.

To convert moles to grams, we need to use the molar mass of Fe₂O₃. The molar mass of Fe₂O₃ can be calculated by adding the atomic masses of iron (Fe) and oxygen (O) in the compound:

(2 x atomic mass of Fe) + (3 x atomic mass of O) = (2 x 55.845 g/mol) + (3 x 16.00 g/mol) = 159.69 g/mol

Now, we can calculate the mass of Fe₂O₃ produced:

Mass = moles x molar mass

Mass = 18.75 moles x 159.69 g/mol = 2990.31 grams

Therefore, 37.5 moles of iron will produce 2990.31 grams of Fe₂O₃.

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