2. A reaction vessel is charged with hydrogen iodide, which partially decomposes to molecular hydrogen and iodine:2HI (g) H2(g) + I2(g)When the system comes to equilibrium at 425 °C, PHI = 0.794 atm, and PH2 = PI2 = 0.0685 atm. The value of Kp at this temperature is ________.

Answer:

Explanation:

A Bronsted-Lowry acid is a chemical species that donates one or more hydrogen ions in a reaction.

In contrast, a Bronsted-Lowry base accepts hydrogen ions.

The half reaction with a more positive standard reduction potential will proceed spontaneously in a redox reaction

The half reaction with a more positive standard reduction potential will undergo reduction when compared to the half reaction with a more negative standard reduction potential.

Oxidation-reduction reactions, often known as redox reactions, are a set of chemical reactions that involve electron transfer between reactants. In a redox reaction, one reactant is oxidized, losing electrons, while the other reactant is reduced, gaining electrons.

The oxidation half-reaction is the process of losing electrons and increasing the oxidation number, whereas the reduction half-reaction is the process of gaining electrons and decreasing the oxidation number. The total reaction is referred to as the redox reaction.

Half-reaction:Half-reaction refers to the two parts of an oxidation-reduction reaction that happen separately. A half-reaction must always be either an oxidation reaction or a reduction reaction. It also describes the movement of electrons and hydrogen ions in an equation.

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Answer:

The amount of CO₂ produced can be calculated using the mole ratio of CO₂ to C₂H6:

2 mol CO₂ / 1 mol C₂H6 = x mol CO₂ / 1.01 mol C₂H6

x = 2 mol CO₂ / 1 mol C₂H6 × 1.01 mol C₂H6 = 2.02 mol CO₂

Therefore, 2.02 moles of CO₂ were produced.

Answer:

Many areas of the United States experience explosive population growth. The more people that reside someplace, the more demand there is for water there. Often these urban-growth expansions are unplanned and place extraordinary stress on the water supply system, mainly on the groundwater. The stress often depletes groundwater supply, thereby causing wells to dry up. Then water must be brought from somewhere else to support the local population.

Such situations have occurred all over the United States. For example, increased population growth in the southwestern United States has significantly lowered the water table 50 to 200 feet (depending on the area) since the 1940s. Managing urban growth, efforts to reduce water demand, conservation of the resource, and attempts to increase the water supply all address the problem of exceeding water resource limits.

Human activities affect groundwater quality.

Here are some sources and possible solutions to groundwater pollution:

Agriculture—Reduce usage of pesticides and fertilizers.

Landfills—Monitor for leakage and repair linings.

Underground storage tanks—Remove damaged and unused tanks.

Household wastes—Properly dispose of household hazardous waste.

Septic tank leaks—Properly maintain and repair tanks.

Explanation:

This came from the K12 learning course read this and the answer will be there. I underlined the important parts for the answer.

Answer:

metal cann't pass non metal can  pass through electicity

Explanation:

Rough ER is connected to the nuclear membrane and is responsible for the synthesis and processing of proteins.

The rough endoplasmic reticulum (ER) is a network of membrane-bound sacs and tubules that is studded with ribosomes on its surface. These ribosomes are responsible for protein synthesis. The rough ER is connected to the nuclear membrane because it receives instructions for protein synthesis from the DNA in the nucleus. This connection allows for the efficient transfer of genetic information from the nucleus to the rough ER.

Once the ribosomes on the rough ER synthesize proteins, the rough ER is also involved in the processing and modification of these proteins. It helps in folding the newly synthesized proteins into their functional three-dimensional shapes and also adds various modifications such as glycosylation (the addition of sugar molecules) or signal sequences that target the proteins to specific locations within or outside the cell.

After processing, the proteins may be transported to other parts of the cell or exported to the cell membrane or extracellular space. The connection between the rough ER and the nuclear membrane ensures a coordinated flow of genetic information and protein synthesis, allowing the cell to efficiently carry out its functions.

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Answer:

Succinic acid

Explanation:

The most common possibility is succinic acid

As it has decimals after whole no till hundredth it contains OH and C in most of the cases .

Let's check for succinic acid

Yes approximately equal

Molecular formula is.

(CH_2)_2(CO_2H)_2

Answer:

B. Water will freeze

because the latent heat of vapourization decreases.

A colored substance that is entirely or almost entirely insoluble in water is called a pigment and organic molecule.

Thus, Contrarily, dyes are usually soluble, at least initially, during their use. In general, pigments are frequently inorganic substances while dyes are frequently organic molecules.

The global market for inorganic, organic, and specialty pigments reached around 7.4 million tons in 2006.

In a report published in April 2018 by Bloomberg Businessweek, the pigment sector was predicted to be worth $30 billion globally.

Titanium dioxide, which is used to increase the white brightness of numerous items, is valued at $13.2 billion annually, while Ferrari red is worth $300 million.

Thus, A colored substance that is entirely or almost entirely insoluble in water is called a pigment.

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Answer:

0.5g/cm^3

Explanation:

Density = Mass / Volume

Density = 20g / 42cm^3

Density = 0.476g/cm^3

note*: round to the nearest sigfig

Answer is: 0.5g/cm^3

The box's volume is 42cm³ and the mass is 20g then the density is 0.5g/cm³.

The mass of a substance per unit of volume is its density. Density is most frequently represented by the symbol, however the Latin letter D may also be used. Density is calculated mathematically by dividing mass by volume.

How much "stuff" is contained in a specific quantity of space is determined by its density. For instance, a block of the harder, lighter element gold (Au) will be denser than a block of the heavier element lead (Pb) (Au).

Because it enables us to predict which compounds will float and which will sink in a liquid, density is a crucial notion. As long as an object's density is lower than the liquid's density, it will often float.

Density = Mass ÷ Volume

Density = 20g ÷ 42cm³

Density = 0.476g/cm³

= 0.5g/cm³

Thus, the density is  0.5g/cm³.

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1. For the pair of half-reactions:

Pt2+(aq) + 2e- → Pt(s)    ... (1)

Sn2+(aq) + 2e- → Sn(s)    ... (2)

To obtain the balanced equation for the overall cell reaction, we need to multiply the half-reactions by appropriate coefficients to ensure that the number of electrons transferred is equal. In this case, we can multiply equation (1) by 2 and equation (2) by 1:

2(Pt2+(aq) + 2e-) → 2(Pt(s))

Sn2+(aq) + 2e- → Sn(s)

Combining the equations, we have:

2Pt2+(aq) + Sn2+(aq) → 2Pt(s) + Sn(s)

The cell notation for this reaction is:

Pt2+(aq) | Pt(s) || Sn2+(aq) | Sn(s)

To calculate the standard cell potential (E°), we need to know the standard reduction potentials for Pt2+/Pt(s) and Sn2+/Sn(s) half-reactions. Referring to standard reduction potential tables, we find:

E°(Pt2+/Pt(s)) = +1.20 V

E°(Sn2+/Sn(s)) = -0.14 V

The overall cell potential (E°cell) is the difference between the reduction potentials:

E°cell = E°(cathode) - E°(anode) = 0.00 V - (-0.14 V) = +0.14 V

Therefore, the standard cell potential for this reaction is +0.14 V.

2. For the pair of half-reactions:

Co2+(aq) + 2e- → Co(s)    ... (3)

Cr3+(aq) + 3e- → Cr(s)    ... (4)

To balance the number of electrons transferred, equation (4) can be multiplied by 2:

2(Co2+(aq) + 2e-) → 2(Co(s))

Cr3+(aq) + 3e- → Cr(s)

Combining the equations, we have:

2Co2+(aq) + Cr3+(aq) → 2Co(s) + Cr(s)

The cell notation for this reaction is:

Co2+(aq) | Co(s) || Cr3+(aq) | Cr(s)

To calculate the standard cell potential (E°), we refer to the standard reduction potentials:

E°(Co2+/Co(s)) = -0.28 V

E°(Cr3+/Cr(s)) = -0.74 V

The overall cell potential (E°cell) is the difference between the reduction potentials:

E°cell = E°(cathode) - E°(anode) = -0.74 V - (-0.28 V) = -0.46 V

Therefore, the standard cell potential for this reaction is -0.46 V.

3. For the pair of half-reactions:

Hg2+(aq) + 2e- → Hg (l)    ... (5)

Cr2+(aq) + 2e- → Cr(s)    ... (6)

The equation for the overall cell reaction can be obtained by multiplying equation (6) by 2:

2(Hg2+(aq) + 2e-) → 2(Hg (l))

Cr2+(aq) + 2e- → Cr(s)

Combining the equations, we have:

2Hg2+(aq) + Cr2+(aq) → 2Hg (l) + Cr(s)

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Answer:

0.05909882564 mol

Explanation:

PV=nRT

n = 1.00atm*1.50L /(0.0821L.atm/mol.k * 309.15 k)

= 0.05909882564 mol

The branched alkanes in boxes two and three all have molecular formula C6H14 and are isomers of the compound shown.

Isomers are compounds that has the same molecular formula but different structural formulas. Hence, isomers of compounds can be represented by the same molecular formula since they contain the same number of each atom.

The molecule shown has molecular formula C6H14. The branched alkanes in boxes two and three all have molecular formula C6H14 and are isomers of the compound shown.

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The volume of \(N_2O_5\) needed to produce 9.64 L of \(NO_2\) is 4.97 L, calculated using stoichiometry and the ideal gas equation.

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Answer:Ok den...

Explanation:

Nope

The actual result of the calculation is 101.920. Therefore, none of the options provided in the question matches the correct answer.

To calculate the given expression: (43 × 2.310) + (7 × 0.370), we perform the multiplication first and then add the results.

Multiplying the counted numbers:

43 × 2.310 = 99.330

Multiplying the measured numbers:

7 × 0.370 = 2.590

Now, we add the results:

99.330 + 2.590 = 101.920

The correct answer is not provided in the given options: a) 38.35, b) 38.4, c) 38, or d) 40.

The actual result of the calculation is 101.920. Therefore, none of the options provided in the question matches the correct answer.

It's important to note that when performing calculations, it is crucial to accurately follow the order of operations (multiplication before addition) and ensure precision when dealing with decimal numbers.

In this case, the correct answer is not among the options provided, and the accurate result is 101.920.

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The mass of the asteroid is C. 1.2 x \(10^{12}\) Kg

To find the mass of the other asteroid, we can rearrange the equation for the gravitational force between two objects:

F = (G * m1 * m2) / \(r^{2}\)

where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two asteroids, and r is the distance between them.

Given that the distance between the asteroids is 75000 m, the force of gravity between them is 1.14 N, and one asteroid has a mass of 8 x \(10^{7}\) kg, we can substitute these values into the equation and solve for the mass of the other asteroid (m2):

1.14 N = (6.67430 × \(10^{-11}\) N \(m^{2}\)/\(Kg^{2}\) * 8 x \(10^{7}\) kg * \(m2\)) / \((75000 m)^{2}\)

Simplifying and solving the equation, we find that the mass of the other asteroid (m2) is approximately 1.2 x \(10^{12}\) kg. Therefore, Option C is correct.

The question was incomplete. find the full content below:

Two asteroids are 75000 m apart one has a mass of 8 x \(10^{7}\) kg if the force of gravity between them is 1.14 what is the mass of the asteroid

A. 3.4 x \(10^{11}\) kg

B. 8.3 x \(10^{12}\) kg

C. 1.2 x \(10^{12}\) kg

D. 1.2 x \(10^{10}\) kg

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ANSWER : Metallic bonding is a type of chemical bonding that occurs between metal atoms. It involves the sharing of valence electrons between metal atoms, resulting in a sea of electrons that surrounds a lattice of positively charged metal ions.

Two common properties of metals are malleability and conductivity. Malleability refers to the ability of a metal to be shaped into thin sheets without breaking, while conductivity refers to the ability of a metal to conduct electricity and heat.

Metallic bonding produces these properties because the sea of delocalized electrons is free to move throughout the lattice of metal ions. When a force is applied to a metal, the ions in the lattice can slide past each other, facilitated by the movement of these electrons. This ability to move and slide past each other is what gives metals their malleability.

Similarly, the delocalized electrons are able to carry an electric current through the metal lattice. As electrons move through the metal lattice, they collide with the metal ions, transferring energy and producing heat. This transfer of energy is what gives metals their high thermal conductivity. In addition, the delocalized electrons are also able to transfer electrical charge through the metal lattice, resulting in the high electrical conductivity observed in metals.

In summary, metallic bonding produces the properties of malleability and conductivity in metals by creating a sea of delocalized electrons that can move freely throughout the lattice of metal ions, allowing for the movement of ions and the transfer of energy and electrical charge.

Explanation :

there you go home this helps :)

Answer:

Lead (IV) Iodide

Explanation:

Answer:

Answer:

125.4 kilopascals

Explanation:

wkdje

Answer:

125,400 pa = 125.4 kPa

Explanation:

1 pa = 0.001 kPa

&

1 kPa = 1,000 pa

The alternative b is not a good description because you can form bubles without the water being boiling yet.

Also, alternative c is also not a good option because it is just a description of what is being seen, it could be replicated in other ways.

Alternative d only gives a termperature, and the boiling temperature can change depending on other conditions.

The alternative the best describes is alternative A.

Due to the trend of boiling points, the optimal order for elements within a group going from top to bottom is \(A, X_o, Z_w\).

From the given information we can see that the boiling points of the elements decrease from A to Xo to Zw. The highest boiling point (350°C) is of element A, followed by Xo (215°C) and Zw (285°C). We arrange the components in decreasing order of boiling points to get A, Xo and Zw.

It is important to remember that in this situation, the alphabetical order of the elements and their atomic weights are irrelevant considerations. A reasonable basis for arranging the components within the system is provided by the trend in boiling points.

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The total gaseous mixture is 4.48 g.

The total gaseous mixture can be calculated using the ideal gas law: PV = nRT.

First, we need to convert the temperature to Kelvin: 27.0°C + 273.15 = 300.15 K.

Next, we can use the ideal gas law to calculate the number of moles of each gas:

For He: n = (1.12 atm) (2.00 L) / (0.08206 L·atm/mol·K) (300.15 K) = 0.0906 mol

For Ar: n = (4.53 g) / (39.95 g/mol) = 0.113 mol

The total number of moles of gas in the mixture is then:

n(total) = n(He) + n(Ar) = 0.0906 mol + 0.113 mol = 0.204 mol

Finally, we can calculate the total mass of the mixture:

m(total) = n(total) × M(avg)

where M(avg) is the average molar mass of the mixture, which can be calculated as:

M(avg) = (M(He) + M(Ar)) / 2 = (4.003 g/mol + 39.95 g/mol) / 2 = 21.98 g/mol

Thus,

m(total) = 0.204 mol × 21.98 g/mol = 4.48 g

Therefore, The total weight of the gaseous mixture is 4.48 g.

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Answer: The burning of fossil fuels releases carbon dioxide, methane and other greenhouse gases into the atmosphere. These gases trap heat in the atmosphere, leading to a gradual increase in global average temperatures, known as global warming. This phenomenon has serious impacts on our environment and ecosystems, including extreme weather events and rising sea levels.

Answer:

Depending on the actual amount of water, it's going to overfill.

Explanation:

If your watershed is already one that has a lot of water and is always filled, it's likely that your wetlands and rivers will start to overfill, causing a form of flooding.

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I hope this helps!

-No one

There is no reason to run these solutes at the 20 MWCO because they are both much smaller than the MWCO of the membrane.

The MWCO (molecular weight cut off) is the molecular weight of a solute at which it will be retained by a membrane during a process such as ultrafiltration or dialysis. If a solute has a molecular weight higher than the MWCO of a membrane, it will be retained and not pass through the membrane. If the molecular weight of a solute is lower than the MWCO, it will pass through the membrane.

In this case, glucose has a molecular weight of 180 g/mol (6 carbons x 12 g/mol per carbon + 6 oxygens x 16 g/mol per oxygen) and albumin has a molecular weight of approximately 81,942 g/mol (607 amino acids x 135 g/mol per amino acid). Both of these solutes have molecular weights that are much lower than 20,000 g/mol, which is a typical MWCO for ultrafiltration or dialysis membranes.

They would both easily pass through the membrane and be lost during the process. Instead, a membrane with a much lower MWCO would be needed if we wanted to retain these solutes during a process such as ultrafiltration or dialysis.

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