Answer:
.9
Explanation:
3-2.1=.9
please help PLEASE NOW
Journal prompt to be answered in 2 fully developed paragraphs
Prompt: What are some products (or programs) that you could purchase to help your performance in your current physical activity? How would the product (or program help)? Do you really think it is effective? Use specific examples from your experience.
You could purchase a fitness tracker to help your performance in your current physical activity.
Fitness tracker would help you in the area of goal setting.
Fitness trackers are effective because they have helped my friends to improve workout routine.
What are some products and programs that do help to physical activity?Wearable fitness trackers can monitor data like heart rate, number of steps taken, distance traveled, and number of calories burned.
Supplements including protein powders, creatine, and beta-alanine can enhance recovery, muscular growth, and endurance.
Working with a coach or personal trainer can help you attain your fitness objectives by offering personalized training regimens, comments on form and technique, and accountability.
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The diagram shows our solar system. name planet 4
Answer:
mars
Explanation:
it is the fourth planet of the solar system
I need help with this answer I believe it's a democracy
Answer:
a. democracy
Explanation:
beacouse the government control of their members
During the experiment it is determined that, as the cart rolls between two points on the track, the work done on the cart by the hanging masses and other forces present is 0.91 J. At the initial time of observation the cart moves with speed 0.61 m/s. Determine the speed at the second point of observation. The mass of the cart is 0.80 Kg.
Answer:
Explanation:
If the work done on the cart is NET work
Then the work will result in an increase in kinetic energy
KE₀ + W = KE₁
½mv₀² + W = ½mv₁²
½(0.80)(0.61²) + 0.91 = ½(0.80)v₁²
v₁ = 1.626991...
v₁ = 1.6 m/s
The speed of the cart at the second point of observation is equal to 1.62 m/s.
What is the work done?Work can be demonstrated as the energy utilized when a force is exerted to make an object move through a particular displacement. Work done by this force is calculated from the product of the magnitude of the exerted force (F) and the distance (d) covered by the body
W= F.d
Where 'F' is the exerted force and 'd' is the displacement and W is work done.
Work and energy have a direct relationship with each other. Work done by an object can be expressed as a change in kinetic energy:
\(W =\frac{1}{2}mv_2^2- \frac{1}{2}mv_1^2\)
Where m is the mass of the object, v₂ is the final velocity (m/s), and v₁ is the initial velocity (m/s).
Given, the work done by the cart, W = 0.91 J
The mass of the cart, m = 0.80 Kg
The speed of the cart at the first point, v₁ = 0.61 m/s
\(0.91 =\frac{1}{2}\times 0.80 \times v_2^2- \frac{1}{2}0.80 \times (0.61)^2\)
0.40 v₂² = 1.06
v₂² = 2.65
v₂ = 1.62 m/s
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The physical property that determines that how easily heat and electricity pass through a material is?
A. conductivity
B. density
C. weight
D. hardness
Answer: Hello! I'm Jungkook. Here is your answer.....
A. conductivity
Explanation:
Hope this helps! Anneyong/Bye!
xoxoKookie
3. Calculate the radii of the first five Fresnel zones if the distance from the light source to the wave surface is 1m, the distance from the wave surface to the observation point is also 1m and the light wavelength is 0.0000005m. (0.50mm; 0.71mm; 0.86mm; 1.0mm; 1.12mm).
The radii of the first five Fresnel zones is 3.6 mm.
Distance from the light source to the wave surface, d₁ = 1 m
Distance from the wave surface to the observation point, d₂ = 1 m.
Wavelength of the light used, λ = 5 x 10⁻⁶m = 5 μm
The expression for the radius of the Fresnel zones is given by,
rₙ = √[nλd₁d₂/(d₁ + d₂)]
Therefore, the radii of the first five Fresnel zones is,
r₅ = √[5 x 5 x 10⁻⁶x 1 x 1/(1 + 1)]
r₅ = √(25 x 10⁻⁶/2)
r₅ = 3.6 x 10⁻³m
r₅ = 3.6 mm
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Please don't round any possible answers
Note the rate at which oil is flowing is: 7.19 m³/s . See the computation below.
What is the rationale for the above response?We can use the principle of continuity of flow to solve this problem. According to this principle, the mass flow rate of the oil is:
m_dot = rho * A * v: where:
rho is the density of the oil,
A is the cross-sectional area of the pipe, and
v is the velocity of the oil.
The cross-sectional area of the pipe before the constriction is:
A1 = (pi/4) * d1² = (pi/4) * (0.978 m)² = 0.7526 m²
The cross-sectional area of the pipe after the constriction is:
A2 = (pi/4) * d2² = (pi/4) * (0.5868 m)² = 0.2701 m²
The velocity of the oil can be calculated using the principle of continuity of flow:
A1 * v1 = A2 * v2
where v1 is the velocity before the constriction and v2 is the velocity after the constriction.
Solving for v1, we get:
v1 = (A2/A1) * v2 = (0.2701 m^2 / 0.7526 m^2) * v2 = 0.3590 * v2
The pressure difference across the constriction is:
deltaP = P1 - P2 = 7600 N/m² - 5700 N/m² = 1900 N/m²
Using Bernoulli's equation, we can relate the pressure difference to the velocity difference:
deltaP = (1/2) * rho * (v2² - v1²)
Substituting the expression for v1, we get:
deltaP = (1/2) * rho * (v2² - 0.1290 * v2²)
Solving for v2, we get:
v2 = sqrt(2 * deltaP / rho * (1 - 0.1290)) = 20.16 m/s
Finally, the mass flow rate of the oil is:
m_dot = rho * A1 * v1 = 821 kg/m³ * 0.7526 m² * 0.3590 * 20.16 m/s
= 5904.4 kg/s
Converting to cubic meters per second, we get:
Q = m_dot / rho = 5904.4 kg/s / 821 kg/m³ = 7.19 m³/s
Therefore, the rate at which oil is flowing is 7.19 m³/s
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4.2 Determine the reactions of the loads L and R. ↓ 5m
↓ 7 kN 6m 3 kN 4m R (8)
The reaction of load L is 0 (no horizontal force), and the reaction of load R is 10 kN (vertical upward force).
How to find reaction?To determine the reactions of the loads L and R, consider the equilibrium of the forces acting on the structure.
First, analyze the vertical equilibrium. The sum of the vertical forces must be zero:
ΣFy = R − 7 kN − 3 kN
ΣFy = 0
This gives:
R = 10kN
Next, analyze the horizontal equilibrium. The sum of the horizontal forces must be zero:
ΣFx = L
ΣFx = 0
This indicates that there is no horizontal force acting on the structure.
Therefore, the reaction of load L is zero (no horizontal force), and the reaction of load R is 10 kN (vertical upward force).
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B. Exercises
Exercise 1
Direction: identfy the plumbing symbols in each item Write your answer on the space
provided before each number
Answer:
please I do not understand that question
When you jump, you push down on the earth and it pushes back up against you. The earth pushing up against you is what causes you to go into the air. Why doesn’t your push cause the earth to go down if your push on the earth is equal and opposite of the earth's push on you?
That's a great question !
The answer is: It does !
A push on an object causes the object to accelerate in the direction of the force.
The less mass the object has, the more the force accelerates it.
Now, when you jump, the forces on you and on the Earth are equal forces.
The up force on you causes you to accelerate up by some amount.
The down force on the Earth causes the Earth to accelerate down by some amount.
The Earth's mass is something like 5,972,000,000,000,000,000,000,000 kg, while your mass is something like 50 kg.
The Earth has something like 119,400,000,000,000,000,000,000 times as much mass as you have.
So your acceleration is something like 119,400,000,000,000,000,000,000 times as great as the Earth's acceleration.
==> The Earth's downward acceleration, caused by your jump, is there. It's just too small to notice.
BUT . . . That's the reason why seismometers (instruments to detect and measure the vibrations from distant earthquakes) have to be located as far as possible from cities and busy roads.
In places that are too close to cities and roads, the Earth's surface is always vibrating, wiggling, jiggling, heaving and weaving, in reaction to the forces of people walking around, cars and trucks driving around, even rain falling down. And kids jumping up and down !
In such places, these people-motions are louder and stronger than the vibrations coming from distant earthquakes. Seismometers wouldn't work there.
a 1kg ball is bening pushed by the rod to move in horizontal groved smooth slot if it startes from angle teta = zero degree . determaine the force the rod exertes on the ball at teta is =15 dgree if ai this instant the rod moves at angular speed of teta = 1 rad per sec end with angular acceleration theta = 2 rad persec and square the ball is only in contact with the outer side of the slot
The force the rod exerts on the ball at the given angle is determined as 3.94 N.
Force exerted on the rod by the ball
The force exerted is calculated as follows;
F = ma
F = mv²/r
F = mω²r
where;
m is mass of the ballω is angular speed of the ballr is radius of the pathr = 2cosθ
Angular speed when the ball moves 15 degreesωf² = ωi² + 2αθ
where;
θ is angular displacement in radians, 15⁰ = 15 x π/180 radωf² = (1)² + 2(2)(15 x π/180)
ωf² = 2.04
ωf = √2.04
ωf = 1.428 rad/s
F = mω²(2cosθ)
F = (1)(1.428)²(2 x cos15)
F = 3.94 N
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What is the net force?
60N left
4ON, right
60N, right
0N
Answer:
60n left
Explanation:
Do
A non-uniform bar of weight W = 30.0 N is suspended at rest in a horizontal position by two massless cords. The angle phi between cord 2 and the vertical is equal to 40.0o. The bar has a length L = 3.0 m and the distance of its center of gravity from the left-hand end of the bar is 2.2 m.
Answer:
12.75N
Explanation:
Let's consider the forces acting on the bar:
Weight of the bar (W = 30.0 N): It acts vertically downward, passing through the center of gravity of the bar.
Tension in cord 1 (T1): It acts horizontally and to the left, making an angle of 90° with the bar. Since cord 1 is massless, it does not contribute to the torque.
Tension in cord 2 (T2): It acts at an angle φ = 40.0° with the vertical.
To find the tension in cord 1 and cord 2, we need to set up torque equilibrium equations. The torque of the weight about the point of suspension must be balanced by the torques of the tensions in cords 1 and 2.
Taking the left end of the bar as the reference point (pivot), the torque equilibrium equation can be written as:
Torque due to weight = Torque due to T1 + Torque due to T2
The torque due to the weight is calculated as follows:
Torque due to weight = Weight of the bar * Perpendicular distance between the weight and the pivot point
The torque due to T1 is zero since it acts along the line of action passing through the pivot point.
The torque due to T2 can be calculated as follows:
Torque due to T2 = T2 * Perpendicular distance between the cord and the pivot point
Using the given values:
Weight of the bar (W) = 30.0 N
Length of the bar (L) = 3.0 m
Distance of the center of gravity from the left-hand end of the bar (d) = 2.2 m
Angle between cord 2 and the vertical (φ) = 40.0°
We can calculate the perpendicular distance between the weight and the pivot point as:
Perpendicular distance = L/2 - d
Using these values, we can solve for T2:
30.0 N * (L/2 - d) = T2 * L * sin(φ)
Let's substitute the given values and solve for T2:
30.0 N * (3.0/2 - 2.2) = T2 * 3.0 * sin(40.0°)
T2 ≈ 12.75 N
Therefore, the tension in cord 2 (T2) is approximately 12.75 N.
A car traveling at 3500 m/s is to stop on a 35-meter long shoulder of the road. What minimum deceleration is required?
The minimum deceleration required to stop the car in 35 meters is 40000 m/s^2.
What is deceleration?Deceleration is defined as the decrease in speed as the body moves away from the starting point.
The minimum deceleration required can be calculated using the equation of motion:
d = v^2 / (2 * a)
where d is the distance, v is the initial velocity, and a is the acceleration.
Rearranging the equation to solve for a:
a = v^2 / (2 * d) = (3500 m/s)^2 / (2 * 35 m) = 40000 m/s^2
In conclusion, , the minimum deceleration required to stop the car in 35 meters is 40000 m/s^2.
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Explain why force, acceleration, and velocity are vectors.
Answer:
simply because they all have direction
Explanation:
vector quantities are quantities which have both magnitude and direction.Force,acceleration and velocity have both magnitude and direction.
True of false
The graduated cylinder is empty before using the overflow container to fined volume
Answer:
True
Explanation:
what is a shargaff rule
According to Chargaff's rule, the amounts of adenine (A), thymine (T), and guanine (G) in the DNA molecule are equal to each other. The amounts of cytosine (C) and guanine (G) are also equal.
Who is Chargaff ?Erwin Chargaff was a biochemist, author, Bucovinian Jew who immigrated to America during the Nazi era, and professor of biochemistry at Columbia University's medical school.
Chargaff found patterns among the four bases, or chemical building blocks, of DNA, which are directly related to DNA's function as the genetic material of living things.
He was born in Austria-Hungary. Heraclitean Fire: Sketches from a Life Before Nature, an autobiography he penned, received positive reviews.
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Car A rounds a curve of 150-m radius at a constant speed of 54 km/h. At the instant represented, car B is moving at 81 km/h but is slowing down at the rate of 3m / (s ^ 2) Determine the velocity and accelera- tion of car A as observed from car B.
The velocity of the car A as observed from car B is (15i - 22.5j) m/s
The acceleration of car A as observed from car B is 4.5j m/s²
The velocity of car A and car B in m/s is equal:
VA = 54 km/h * 5/18 = 15 im/s
VB = 81 km/h * 5/18 = 22.5 jm/s
The relative velocity is:
\(v_{AB} = v_{A} - v_{B} =\) (15 i -22.5 j ) m/s
The acceleration of the cars are:
\(a_{A} = v^{2}_{A} = 15^{2} /150 =1.5 jm /s^{2}\)
The relative acceleration is:
\(a_{AB} = a_{A} - a_{B} =\) 1.5- (-3), negative - because - the - car - is- slowly - down
\(a_{AB\) = 4.5 jm/ \(s^{2}\)
The relative velocity is defined as the velocity of an object with respect to another observer. It is the time pace of change of relative position of one object with respect to another object.
The relative acceleration (also or ) is the acceleration of an object or observer B in the rest casing of another object or observer A. Acceleration of B relative to An is =ab−aa.
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Monochromatic light is incident on a metal surface and electrons are ejected. If the intensity of the light is increased, what will happen to the ejection rate and maximum energy of the electrons
Answer:
Increase the rate and the same maximum energy of the electrons
Explanation:
According to the photoelectric effect we can say:
The number of electrons, or the electric current, has a linear behaviour with the intensity of the light and a constant behaviour whit the frequency. Therefore, the rate of electrons increases.The kinetic energy of the ejected electrons has a linear dependence on the frequency of the light and has a constant behaviour with the intensity. So, we can say there is the same maximum energy.I hope it helps you!
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The weight of a box is found to be 30 N. What is the approximate mass of the box?
3 kg
300 kg
120 kg
30 kg
Answer:
3kg
Explanation:
3kg is the appropriate mass
Answer:
3kg
Explanation:
just took the test
What is not a type of electromagnetic wave?
Explanation:Beta Rays are not Electromagnetic Waves
Beta rays also known as beta radiation is obtained through the emission of an electron. Beta rays are not electromagnetic waves because they are charged particles and are capable of getting deflected by the magnetic field.
Microwaves are a form of "electromagnetic" radiation; that is, they are waves of electrical and magnetic energy moving together through space. Electromagnetic radiation spans a broad spectrum from very long radio waves to very short gamma rays. ... But the most common consumer use of microwave energy is in microwave ovens.
Visible light is carried by photons, and so are all the other kinds of electromagnetic radiation like X-rays, microwaves and radio waves. In other words, light is a particle.
So the answer is sound.
The sound wave is not an electromagnetic wave
What are electromagnetic waves?In terms of science, electromagnetic radiation is made up of electromagnetic field waves that travel over space while carrying electromagnetic radiant energy and velocity. It consists of X-rays, gamma rays, microwaves, infrared, light, and radio waves.
In order from highest to lowest energy, the sections of the EM spectrum are named: gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves.
Given data ,
Let the electromagnetic wave be represented as A
Now , when A = microwaves
Microwaves are waves of electrical and magnetic energy traveling across radio waves and infrared radiation on the electromagnetic spectrum combined. There is a wide range of electromagnetic radiation, from very lengthy radio waves to very brief gamma rays.
And , when A = x-rays
X-rays are high-frequency, and thus high-energy, electromagnetic radiation
They are found to reside between ultraviolet radiation and gamma rays on the electromagnetic spectrum.
X-rays are more energetic because they have shorter wavelengths. When discussing X-rays, we frequently refer to their energy rather than its wavelength.
Now , the sound waves are not electromagnetic waves as sound waves are examples of mechanical waves
Hence , sound waves are not electromagnetic waves
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how do you mountaineers reduce the effects of changes in atmospheric pressure?
What step occurs first in a scientific investigation and in the development of a new technology?
-Findings are communicated to others.
-A problem or need is identified
-A series of tests are analyzed.
-Information is researched
Answer:
B. A problem or need is identified
Explanation:
hoep this helps
Answer:
B
Explanation:
edge
A satellite is orbiting the earth at 15000.km above the center of the earth, What speed is it going?
from the drop down menu arrange the electromagnetic radiation which starts with the highest energy and decreases to the lowest energy.
"The energy of the electromagnetic radiation from the highest to lowest energy is given as gamma rays, x-rays, ultra-violet radiation, visible light, infrared radiation and the radio waves."
The range of all forms of electromagnetic radiation is known as the electromagnetic spectrum. Electromagnetic waves typically move at velocities close to the speed of light in a vacuum.
Depending on how they are created, how they interact with matter, and how they are used practically, electromagnetic waves in these various bands have distinct properties.
The lowest energies are allegedly found in radio waves and micro waves.
With over 10,000 times more energy than the photons of visible light, gamma rays are the most powerful type of electromagnetic radiation. Their wavelength is the shortest. Nuclear blasts and radioactive atoms both produce these waves.
In the given question. The drop menu is missing. The order of electromagnetic radiation is given generally.
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When you jump over something is it a balanced force?
Answer:
no..
Explanation:
in balanced force it will or in this case u would stay still or u would move at the same speed.. but when u jumps the speed changes..so this is an unbalanced force
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The system is released from rest at θ = 0° when a constant couple moment M = 100 N.m is applied. If the mass of the cable and links AB and BC can be neglected, and each pulley can be treated as a disk having a mass of 6 kg, determine the speed of the 10-kg block at the instant link AB has rotated θ = 90°. Note that point C moves along the vertical guide. Also, the cable does not slip on the pulleys.
For a system released from rest at θ = 0° when a constant couple moment M = 100 N.m is applied, the speed of the 10-kg block is mathematically given as
V=4.33m/s
What is the speed of the 10-kg block?Generally, the equation for the workdone is mathematically given as
W=T tehta<dtheta
W=100(90*\pi/180)
W=1.5707*100
W=1.57Nm
The change in potential energy across the pulley
dP=mgh
dp=10*9.81*111.8
dp=10.97J
For the thrid position, potential energy is
dP=mg(0.3)
dP=17.658J
dP'=17.658J-13.125
dP'=-4.532J
For 2nd position dP=0
The change in Kinectic energy across the pulley\
dK.E=0.5mv^2
For 1st
dk.E=0.5m(10)^2
2nd
dK.E=0.5Iw^2
dK.E=0.5(7.5*10^-3)(v^2/0.05)^2
3rd
2nd=3rd
In conclusion,
157.07=dKE+dP.E
157.07=5v^2+ (7.5*10^-3)(v^2/0.05)^2+10.97-4.53
V=4.33m/s
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An astronaut measure the period of a mass spring system on Earth. How would the period be affected if the astronaut measured the period of the same mass spring system on the moon? (Moon's gravity = 1/6 Earth's gravity.)
An astronaut measure the period of a mass spring system on Earth.
The period of a mass spring system on the moon would be longer than the period on Earth. This is because the period of a mass spring system is dependent on the square root of the ratio of the mass to the spring constant, and the acceleration due to gravity. Since the acceleration due to gravity on the moon is only 1/6th of that on Earth, the restoring force on the mass will be weaker, resulting in a longer period. Therefore, the astronaut would measure a longer period for the same mass spring system on the moon than on Earth.
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The spacecraft was moved closer to the launcher by the same amount Wednesday as it was on Tuesday, and yet its speed went up much more. Claim 3 suggests that the magnetic force was much stronger on Wednesday than on Tuesday.
Consider the two subclaims for Claim 3 and answer the question below.
Claim 3.A: The magnetic force was much stronger on Wednesday because the magnet was stronger.
Claim 3.B: The magnetic force was much stronger on Wednesday because the magnetic force is stronger closer to the magnets.
Which claim do you think is more convincing, and why?
Answer:
The magnetic force was much stronger on Wednesday because the magnetic force is stronger closer to the magnets.
Explanation:
The magnetic force was much stronger on Wednesday than on Tuesday because the magnetic force is stronger closer to the magnets. Therefore claim 3B is more convincing.
What is magnetic force?Magnetic force can be described as a consequence of electromagnetic force which is caused due to the motion of charges. A moving charge surrounds itself with a magnetic field and the force that arises due to interacting magnetic fields.
The magnetic force between two moving charges is the effect exerted upon either charge by a magnetic field generated by the other. The magnetic force depends on the charge, the motion of each of the objects, and the separation between them.
The magnitude of the force is determined by the cross product of velocity and the magnetic field is equal to q.[v × B]. The resultant force can be described as perpendicular to the direction of the velocity and the magnetic field.
Therefore, the magnetic force was much stronger closer to the magnets.
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