2. a 35 kg wagon is being pushed with a metal rod that makes an angle of 48o with the horizontal. the applied force is 449 n and the coefficient of kinetic friction between the wagon and the ground is 0.19.
I'm not sure what equation to use to find the normal force and then the acceleration

Answers

Answer 1

The acceleration required to push the wagon is 16.12m/s².

Acceleration is the rate of change of velocity with respect to time.

Also it defines the maximum capacity of a vehicle to attain its speed.Its SI unit is m/sec².

According to Newtons Second law of motion,

Force = Mass * acceleration

Fnet = m*a

Fnet = Fm + Ff

Fm = Force due to Mass of the wagon = mg = 449N

Ff = Force due to friction = μR

Fnet = mg + μR

μ = 0.19

m = 35kg

R = mg; g = 9.8 m/s²

Fm + Ff = ma

449 + (0.19*35*9.8) = 35*a

499 + 65.17 = 35a

564.17 = 35a

a = 16.12 m/s²

The acceleration required to push the wagon is 16.12m/s² and the normal force will be the force acting due to weight of the wagon i.e. 449N.

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Related Questions

A 1050 W carbon-dioxide laser emits light with a wavelength of 10μm into a 3.0-mm-diameter laser beam. What force does the laser beam exert on a completely absorbing target?

Answers

The force exerted by the laser beam on a completely absorbing target is \(3.5 \times 10^{-6} \ N\).

The given parameters;

power of the laser light, P = 1050 Wwavelength of the emitted light, λ = 10 μm

The speed of the emitted laser light is given as;

v = 3 x 10⁸ m/s

The force exerted by the laser beam on a completely absorbing target is calculated as follows;

P = Fv

\(F = \frac{P}{v} \\\\F = \frac{1050}{3\times 10^8} \\\\F = 3.5 \times 10^{-6} \ N\)

Thus, the force exerted by the laser beam on a completely absorbing target is \(3.5 \times 10^{-6} \ N\).

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Two blocks with masses 2.00 kg and 4.00 kg are placed side-by-side on a frictionless horizontal surface. A horizontal force with a magnitude of 5.20 N is applied to the 2.00-kg block perpendicular to its surface. What is the magnitude of the force on the 4.00-kg block?
a. 2.60
b. 3.11
c. 3.47
d. 3.89

Answers

The magnitude of the force on the 4.00-kg block is 3.47 N.

The given parameters:

Mass of first block, m1 = 2 kgMass of second block, m2 = 4 kgHorizontal force, F = 5.2 N

Acceleration of both blocks;The acceleration of both blocks is calculated by applying Newton's second law of motion.

\(a = \frac{F}{m_1 + m_2} \\\\a = \frac{5.2}{2 + 4} \\\\a = \frac{5.2}{6} \\\\a = 0.867 \ m/s^2\)

The magnitude of the force on the 4.00-kg block is calculated as follows;

F = ma

F = 4 x 0.867

F = 3.47 N

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х
Help
Close
Pre-video question: What type of cell division produces sperm and
ova?

Answers

Answer:

HI THERE

Explanation:

MEIOSIS produces sperm and ova

thank you

I am also reading this chapter

it will come in my exams

Meiosis ? I did this in class too


The NEC states the resistance of 4/0 coated
copper conductors is 0.0626 ohms per 1000
feet. What would be the total resistance of the
three 4/0 conductors installed in parallel, if the
total length for each of the three conductors is
323 feet?

Answers

Answer:

The resistance of 4/0 coated copper conductors is given as 0.0626 ohms per 1000 feet. To find the total resistance of the three 4/0 conductors installed in parallel, we can use the formula for combining resistances in parallel.

Since the total length for each of the three conductors is 323 feet, the resistance of each conductor can be calculated as follows:

Resistance of one conductor = (0.0626 ohms / 1000 feet) * 323 feet

To find the total resistance when the conductors are in parallel, we use the formula:

1/Total Resistance = 1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3

Total Resistance = 1 / (1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3)

Substituting the values, we get:

Total Resistance = 1 / (1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet))

Simplifying the expression will give us the total resistance of the three 4/0 conductors installed in parallel.

A circuit is complete when there is a ___ path for electricity to travel from one end
of the energy source to the other end.

a.) continuous path
b.) zig zag path
c.) random path
d.) broken path

Answers

The answer is continuous path because in order for electricity to conduct, there needs to be a continuous path with no breaks! Hope this helped! BRANLIEST plz!

A circuit is complete when there is a continuous path for electricity to travel from one end of the energy source to the other end.

What is electric circuit?

Electric circuit: a way for current to travel. A battery or generator, a device that provides energy to the charged particles that make up the current, a device that uses current, such as a lamp, an electric motor, or a computer, and the connecting wires or transmission lines make up an electric circuit. Ohm's law and Kirchhoff's rules are two fundamental laws that quantitatively define how electric circuits function.

Several categories are used to categorise electric circuits. One-way current only flows through a direct-current circuit. As in most residential circuits, an alternating-current circuit transports current that pulses back and forth repeatedly every second.

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6.) What is
the voltage
across a 50
ohm circuit
element that
draws a current of 2 A?

Answers

Answer:

100 V

Explanation:

Hi there!

Ohm's law states that \(V=IR\) where V is the voltage, I is the current and R is the resistance.

Plug the given information into Ohm's law (R=50, I=A)

\(V=IR\\V=(2)(50)\\V=100\)

Therefore, the voltage across this current is 100 V.

I hope this helps!

a student must conduct two experiments so that the inertial mass and gravitational mass of the same object can be determined. in the experiment to find the object's gravitational mass, the student ties one end of a string around the object with the other end tied to a spring scale so that the object can vertically hang at rest. in the experiment to find the object's inertial mass, the student uses a spring scale to pull the object, starting from rest, across a horizontal surface with a constant applied force such that frictional forces are considered to be negligible. in addition to the spring scale, the student has access to other measuring devices commonly found in a science laboratory. which of the following lists the essential measuring devices the student can use to collect the data necessary to find the object's gravitational and inertial mass?meterstick and timer
meterstick, timer, and motion director
meterstick, timer, motion director, and mass balance
meterstick, timer, motion detector, mass balance, and protractor

Answers

In order to collect data to find an object's gravitational and inertial mass, meterstick and timer are two essential measuring devices that are needed.

Using the angular frequency value (w), inertial mass (m) is determined using the equation below:

w=√k/m

The equation above is solved for mass (m).

m=k/w²

To calculate the gravitational mass, following equation is used:

force gravity =  G  ×  M  ×  m / radius²

Where: mass, m, is 1 kilogram; mass of the Earth, M, is 6.0 × 1024 kilogram; the radius of the Earth (separation of masses), r, is 6.4 × 106 m; and G is 6.67 × 10⁻¹¹ newton square metrekilogram-2}.

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How to model parallel circuit?

Answers

A parallel circuit can be modelled by connecting the components parallel.

A parallel circuit is a form of electrical circuit in which the components are linked in parallel to one another, each having a separate channel for current flow and being directly connected to the power source. The circuit must first be schematically represented, with the power supply and each component linked in parallel. Next, the total resistance the total current in the circuit by using Ohm's Law must be calculated.

Additionally, it is necessary to confirm that the total current entering the circuit equals the total current leaving the circuit. In a parallel circuit, the total current passing through all of the components equals the current entering the circuit. The voltage drop between each component must then be once more computed using Ohm's Law.

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03: Hook's law suggests that F is directly proportional to -x, how much true you have found this statement in your experiment? Explain any differences.​

Answers

Hooke's Law can be given as follows sometimes:

The restoring force of a spring is equal to the spring constant multiplied by the displacement from its normal position:

F = -kx

Where, F = Restoring force of a spring (Newtons, N)

k = Spring constant (N/m)

x = Displacement of the spring (m)

The negative sign relates to the direction of the applied force and by convention, the minus or negative sign is present in F = -kx. The restoring force F is directly proportional to the displacement (x), according to Hooke's law. When the spring is compressed, the displacement (x) is negative. It is zero when the spring is at its original length and positive when the spring is extended.

Practically, Hooke's Law is applicable only within a limited frame of reference, and through experimenting, this statement proves to be true. Because materials cannot be compressed beyond a certain size or expanded beyond a certain size without some permanent deformation or change of their original state.

The law only applies under some conditions such as a limited amount of force or deformation. Factually, many materials will noticeably deviate from Hooke's law even before those elastic limits are reached.

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A swing has a potential energy of 150 J and a kinetic energy of 75 J at a certain spot. What is the mechanical energy of the swing?

Answers

The mechanical energy of the swing is the sum of the potential energy and the kinetic energy which is equal to 225 Joules.

What is Mechanical energy?

Mechanical energy is the energy which is present either in an object which is in motion or the energy which is stored in objects by their position. Mechanical energy is the main driver of renewable energy. Many different forms of renewable energy rely directly on the mechanical energy to adequately produce enough amount of power or convert energy.

The mechanical energy of the object is the sum total of individual energies which are present in the object. The mechanical energy of an object can be represented as:

M.E. = P.E. + K.E.

M.E. = Mechanical energy,

P.E. = Potential energy,

K.E. = Kinetic energy

Therefore, the mechanical energy of the swing will be:

M.E. = 150J + 75J

M.E. = 225 Joules

Therefore, the mechanical energy of the swing is equal to 225 Joules.

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Why is it a bad idea to drink hot cocoa out of a tin cup? Explain the energy transfers on the atomic level.​

Answers

It is not a good idea to drink hot cocoa out of a tin cup since metal is a good conductor of heat and the hot cocoa's high temperature will cause the metal cup to quickly transfer heat to your hand and mouth, perhaps resulting in burns or pain.

What is the name for the energy that is transferred when hot cocoa is put into a cold mug?

When particles of warmer matter collide with particles of cooler matter, some of the thermal energy from the warmer particles is transferred to the cooler particles. Certain solids and liquids typically conduct electricity more quickly than gases do.

How does sipping a cup of hot chocolate transmit heat?

Conduction is the mechanism by which the hot chocolate transmits heat to the mug. As the molecules of the hot chocolate clash with those of the mug, energy is transferred to both of them as well as to the surrounding air.

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a. Do the waves made by the two faucets travel faster than the waves made by just one faucet?
b. How do you know this? Describe how the two-faucet wave pattern compares with the one-faucet pattern.
c. Describe what happens to the two-faucet wave pattern as the separation of the faucets is increased.

Answers

Answer:

asdasd dsa dasdasd sadas dasd asdasd asd asd dsa asdd 223 aasd ada dasd sa dasd dsaa sd adsd asasd

Explanation:

Jane (m=50kg) wants to save Tarzan (m= 80kg) who is standing in the middle of a ring of fire of 5.0 m diameter. Jane has a vine (conveniently attached to a branch right above Tarzan, at a height of 33 m above the ground. Jane holds onto the vine and climbs a tree, growing 16 m away from Tarzan, until she reaches a height of 5.3 m above the ground. She swings down and grabs Tarzan around his waist (1.0m above ground). If they let go of the vine when they reach their highest point, where will they land, relative to Tarzan's original position?

Answers

The height that will illustrate the distance will be d = 6.36m

How to calculate the height?

Based on the information given, the length of the vine will be:

L = ✓(16² + 27.7)²

L = 32m

The velocity of Jane when she reaches position B will be:

V = ✓2gh

V = ✓(2 × 9.8 × 4.3)

V = 9.18m/s

We will apply the conversation of momentum. This will be:

50 × 9.18 = (50 + 80)V1

V1 = 3.53m/s

Therefore, the height that will illustrate the distance will be:

31.36² + d² = 32²

d² = 32² - 31.36²

d = 6.36m

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Please Help!!!!!
Belinda observes that the reaction 2H2O+O2=2H2O2 appears to have stopped, because the concentrations of reactants and products are not changing. Which statement is true at this point in the reaction
A P E X

Answers

Answer: Molecules of H202, H20 and 02 are still forming. ( A P E X )

Explanation: I know this is late but for anyone looking at this later

The above question is incomplete, I think the original  question is

Belinda observes that the reaction 2H20+02 2H2O2 appears to have stopped because the concentrations of reactants and products are not changing. Which statement is true at this point in the reaction?

A. Molecules of H₂O₂ are formed only when the reaction vessel is disturbed.

B. Molecules of H2O2 have stopped forming.

C. Molecules of H20 and O₂ have stopped forming.

D. Molecules of H2O2, H2O, and O2 are still forming.

At this point in the reaction, the system has reached a state of equilibrium i.e there is no net change in the concentrations of reactants and products. So the Molecules of H2O2 have stopped forming. The correct option is B.

What is the state of equilibrium?

In chemistry, a state of equilibrium refers to a situation where the concentrations of reactants and products in a chemical reaction are no longer changing over time.

This occurs when the rates of the forward and reverse reactions are equal, and there is no net change in the concentrations of reactants and products.

At equilibrium, the system is in a dynamic state, where the forward and reverse reactions continue to occur, but at the same rate, resulting in no overall change in the concentrations of the species involved in the reaction. The equilibrium state is typically characterized by the equilibrium constant, which is a measure of the relative concentrations of reactants and products at equilibrium for a given reaction under specific conditions of temperature, pressure, and concentration.

Here in this question,

The molecules of H2O2 have stopped forming. This means that the forward reaction (2H2O + O2 → 2H2O2) and the reverse reaction (2H2O2 → 2H2O + O2) are occurring at the same rate, resulting in no net change in the concentration of H2O2. However, molecules of H2O and O2 are still being consumed and produced as they are involved in the reaction, but their concentrations are not changing because they are being replenished at the same rate that they are being consumed.

Therefore, the correct answer is B i.e Molecules of H2O2 have stopped forming.

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In the figure, block 2 of mass 2.0 kg oscillates on the end of a spring in SHM with a period of 20 ms The block' s position is given by x (1.0 cm) cos(ot + 7/2). Block 1 of mass 4.0 kg slides toward block 2 with a velocity of magnitude 6.0 m/s, directed along the spring' s length The two blocks undergo completely inelastic collision at time t = 5.0 ms. (The duration of the collision is much less than the period of motion. What is the amplitude of the SHM after the B3n collision?

Answers

A block oscillates on the end of the spring. The amplitude of SMH after the collision is 40.67 m.

According to the rule of conservation of momentum, the total amount of momentum before and after a collision is equal.

Given that, m₁ = 2 kg

m₂ = 4 kg

Time period T = 20 ms = 0.2 s

v₁ = 6 m/s

t = 5 ms = 0.005 s

x = 1.0 cm cos (ωt + π/2)

Kinetic energy in block 1 is Ek = 1/2* m₁ v₁²

Energy in spring in block 2 Es = 1/2* k x²

We know, f = 1 / T = 1 / 0.02 = 50 hz

ω = 2 π * f = 2 π * 50 = 100 π

To find k, we know the formula, k = ω² * m₂ = (100 π)² * 2 = 197317

x = (1.0 cm) cos (ωt + π/2)

ω = 100 π rad,  t = 0.005 s

x = (0.01) cos (100 π* 0.005 + π/2) = -0.01 m

Energy of block 1 = 0.5* 4* 6 = 72 J ---(1)

Energy of the spring = 0.5* 2* (100 π)² - 0.01² = 9.86 J ---(2)

Energy before collision will be (1) + (2) = e₁ + e₁ =  72 + 9.86 = 81.86 J

Energy after the collision E after = 1/2* k x²

1/2 * k x² = 1/2 * ω² * x²

m = m₁ + m₂ = 6 kg

ω = √(k/m²) = (197317/36) = 74.03 rad/s

Applying, Energy before collision = Energy after collision

81.86 = 1/2 * 6 * 74.03 * x²

x² = 0.37

x = 0.61 m

Amplitude can now be found since we have gotten all the parameters

x = A cos (ω t + π / 2)

0.61 = A cos [181.3 * (0.005) + π / 2]

A = - 0.61/0.015 = 40.67 m

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Kepler's second law states that as a planet orbits the Sun, itsweeps out equal areas in equal times. Which of the followingstatements describe a characteristic of the solar system that isexplained by Kepler's second law?
Check all that apply
a) Venus orbits the Sun faster than Earth orbits the Sun.
b) Inner planets orbit the Sun at higher speed than outerplanets
c) The Sun is located slightly off-center from the middle ofeach planet's orbit.
d) All the planets orbit the Sun in nearly the same plane
e) Earth is slightly closer to the Sun on one side of itsorbit than on the other side
f) Pluto moves faster when it is closer to the Sun thanwhen it is farther from the Sun

Answers

Kepler's second law states that as a planet orbits the Sun, it sweeps out equal areas in equal times. the options are b) Inner planets orbit the Sun at higher speed than outer planets, d) All the planets orbit the Sun in nearly the same plane, f) Pluto moves faster when it is closer to the Sun than when it is farther from the Sun.

Kepler's second law states that as a planet orbits the Sun, it sweeps out equal areas in equal times. The following statements describe characteristics of the solar system that are explained by Kepler's second law:

The correct options are option b, d and f.

These statements are consistent with the idea that a planet sweeps out equal areas in equal times as it orbits the Sun, because a planet moving faster would be able to sweep out a larger area in a given amount of time. Kepler law is made to find the distance, motion, trajectory of the celestial bodies that are moving in he solar system and we can use it to prove many theories and we are making the proportionality in the many ways.

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When a body falls freely under gravity, then the work done by the gravity is ___________​

Answers

Answer: positive

Explanation:

Gravity can be defined as the force with which the body is attracted towards the center of the earth, or towards any other body. If the force acting on the body is in the direction of displacement then the word done by the applicable force is positive. This causes the free fall of the ball under the influence of gravity is also positive.

Explain the light detection technique of photovoltaic detection​

Answers

Answer:

Photovoltaic detection is a technique that converts light into electrical energy. It is a process that involves the use of a photovoltaic cell, which is made up of semiconductor materials, to generate an electric current when exposed to light.

The photovoltaic cell absorbs the photons of light, which then knock electrons out of their orbits, creating a flow of electricity. The amount of electricity produced is proportional to the intensity of the light. The photovoltaic cell is commonly used in solar panels to generate electricity from sunlight. The efficiency of the photovoltaic cell is dependent on several factors, including the type of semiconductor material used, the purity of the material, and the thickness of the cell.

The photovoltaic cell has many applications, including in solar power generation, telecommunications, and remote sensing. The technique of photovoltaic detection is an important area of research, as it has the potential to provide a clean and renewable source of energy that can help mitigate climate change.

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calculate the percentage contraction of a rod moving with a velocity of 0.8c in a direction inclined at 60° to its own length​

Answers

Answer:

Let lo be the length of the rod in the frame in which it is at rest and s' is the frame which is moving with a speed 0.8c in a direction making an angle 60° with x-axis. The components of lo along and perpendicular to the direction of motion are lo cos 60° and lo sin 60° respectively.

Now length of the rod along the direction of motion

= lo cos 60°_/1-(0.8) 2/c2

= lo/2×0.6

= 0.3 lo.

Length of the rod perpendicular to the direction of motion.

= lo sin 60°

=_/3/2 lo

Length of moving rod

l = [(0.3lo)2+{lo_/3/2} 2] 1/2

= 0.916 lo.

Percentage contraction

= lo-0.916lo/lo×100

= 8.4%.

Explanation:

Brainliest?

Highway safety engineers want to design roadside barriers that will crumple
in the event that a car drives off the road and collides with them, slowing
down the car more gradually. The average person has a mass of 68 kg and
travels on a highway at a velocity of 27 m/s. If the engineers know that the
maximum force that a person can safely withstand is 1650 N, approximately
how much time is required to crumple the barrier to safely slow the person
with this force?
A 1.5s
B. 0.7 s
C. 1.1 s
D. 2.1 s

Answers

The time required to crumple the barrier and safely slow down the person with a force of 1650 N is approximately C, 1.1 seconds.

How to find time?

To determine the time required to crumple the barrier and safely slow down the person with a maximum force of 1650 N, use the equation of motion:

F = m × a

where:

F = force

m = mass

a = acceleration

Given:

m = 68 kg

F = 1650 N

Find the acceleration (a) first. Rearranging the equation:

a = F / m

Substituting the values:

a = 1650 N / 68 kg

a ≈ 24.26 m/s²

Now, use the equation of motion to find the time (t):

v = u + at

where:

v = final velocity (0 m/s as the person comes to a stop)

u = initial velocity (27 m/s)

a = acceleration (24.26 m/s²)

t = time

Rearranging the equation:

t = (v - u) / a

Substituting the values:

t = (0 m/s - 27 m/s) / 24.26 m/s²

t ≈ -27 m/s / 24.26 m/s²

t ≈ -1.11 s

The negative sign indicates that the time is in the opposite direction to the initial velocity. Taking the absolute value, the time required to crumple the barrier and safely slow down the person with a force of 1650 N is approximately 1.11 seconds.

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a stone on the ground has zero energy why​

Answers

Explanation:

it has no energy when considered with respect to earth ,as it has neither height (i e potential energy) nor velocity (i.e kinetic energy).

Read and choose the option that answers the question.

¡Buenas tardes, amigos! Me llamo Elena y vivo en El Salvador. Me despierto a las seis y cuarto de la mañana y hago mis quehaceres. Desayuno, me ducho y me arreglo para ir a la escuela.

Based on the reading, select the "yo-go" verb used in the paragraph.

Answers

Answer:

hago

Explanation:

hago mis quehaceresmeans means I do my homework

The steering wheel of a car has a radius of 0.19 m, and the steering wheel of a truck has a radius of 0.25 m. The same force is applied in the same direction to each steering wheel. What is the ratio of the torque produced by this force in the truck to the torque produced in the car

Answers

Answer:

\(\frac{T_t}{T_c} = 1.32\)

Explanation:

The torque applied on an object can be calculated by the following formula:

\(T = Fr\)

where,

T = Torque

F = Applied Force

r = radius of the wheel

For car wheel:

\(T_c = Fr_c\\\)

For truck wheel:

\(T_t = Fr_t\)

Dividing both:

\(\frac{T_t}{T_c} = \frac{Fr_t}{Fr_c}\)

for the same force applied on both wheels:

\(\frac{T_t}{T_c} = \frac{r_t}{r_c} \\\)

where,

rt = radius of the truck steering wheel = 0.25 m

rc = radius of the car steering wheel = 0.19 m

Therefore,

\(\frac{T_t}{T_c} = \frac{0.25\ m}{0.19\ m} \\\)

\(\frac{T_t}{T_c} = 1.32\)

A figure skater glides along a circular path of radius 3.93 m. (a) If she coasts around one half of the circle, find the magnitude of the displacement vector. (b) If she coasts around one half of the circle, find what distance she skated. (c) What is the magnitude of the displacement if she skates all the way around the circle?

Answers

The magnitude of the displacement vector refers to the length or amount of the displacement vector. Displacement is the change in position of an object. Displacement is a vector quantity, which means it has both magnitude and direction. In this question, a figure skater is gliding along a circular path of radius 3.93 m.

If she coasts around one half of the circle, we have to find the magnitude of the displacement vector. The figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, then her final and initial position is on the same point. Therefore, the magnitude of the displacement vector is zero. Distance Skated Distance refers to the length covered by an object or an individual. In this question, the figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, we have to find what distance she skated. The distance covered by an object or individual is determined by the formula:Distance = Circumference/2Given that the radius of the circle is 3.93 m, then:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 m.Therefore, the distance covered by the figure skater around half of the circle = 24.7 m/2 = 12.35 m. Therefore, she skated 12.35 m.Magnitude of DisplacementIf the figure skater skates all the way around the circle, then she covers the entire circumference of the circle. Therefore, the magnitude of the displacement vector is the same as the circumference of the circle, which is given as:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 mTherefore, the magnitude of the displacement vector when the figure skater skates all the way around the circle is 24.7 m.

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Answer it with 1 reason.1.Mirrors having a curved reflecting surface are called as:
a.Plane mirror
b.Spherical mirror
c.Simple mirror
d.None of above
2.Type of spherical mirror are:
aConcave
b.Convex
c.both A and B
d.none of the above
3.Spherical mirror with reflecting surface curved inwards is called ……………
a. convex mirror.
b. concave mirror
c. curved mirror
d. none of the above
4.Spherical mirror with reflecting surface curved ………………… is called concave mirror.
a.Outwards
b.Inwards
c.Backwards
d.none of the above
5.The center of reflecting surface of a spherical mirror is known as……………
a.Pole
b.Aperture
c.Axis
d.Curvature​

Answers

1 a. Spherical Mirror

2. Both A and B

3. Concave mirror

4.Inwards

5. Pole.

These are your answer. You can mark me Brainliest. Thanks.

hope it helps you have a good day

Explanation:

spherical mirror

both A and B

inwards

pole

An electric drag racer is much like its piston engine counterpart, but instead it is powered by an electric motor running off of onboard batteries. These vehicles are capable of covering a 1/4 mile straight-line track in 10s.

A. Determine the acceleration of the drag racer in units of m/s^2
B. Calculate the final speed of the drag racer in mi/h

Answers

Assuming it is starting from rest final velocity = 40.233m/s
Acceleration = 4.0233m/s^2

what is the voltage supplied to a wire that has a resistance of 1200 Q and a current of 0.10 amps

Answers

The voltage supplied to the wire is 120 volts.

To calculate the voltage supplied to a wire, we can use Ohm's Law, which states that voltage (V) is equal to the product of current (I) and resistance (R). Mathematically, this relationship is expressed as V = I * R.

In this case, the wire has a resistance of 1200 Ω (ohms) and a current of 0.10 amps. We can substitute these values into the formula to find the voltage:

V = I * R

V = 0.10 A * 1200 Ω

V = 120 A * Ω

Therefore, the voltage supplied to the wire is 120 volts.

It's important to note that Ohm's Law holds true for resistors and other components in a circuit that obey Ohm's Law. In real-world scenarios, there may be other factors to consider, such as the presence of non-ohmic devices or components with varying resistance.

Additionally, in an AC (alternating current) circuit, the relationship between voltage, current, and resistance may involve complex quantities and phase differences. However, for a simple DC (direct current) circuit with a linear resistor, Ohm's Law provides an accurate relationship between voltage, current, and resistance.

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Please answer correctly will give brainlist if correct
Before you kick a soccer ball you pull your leg back. For a brief moment, before you kick the ball, your leg is not moving as seen in the image below. At this point, your leg has______
Active Energy
Potential Energy
Conservation of Energy
Kinetic Energy

Answers

If your keg is not moving the only energy your leg can have is Potential energy.

Answer:

Kinetic energy

Newton's first law of motion states that an object's motion will not change unless

Answers

Answer:

unless an external unbalanced force acts on it.

Answer:

An object in motion will not change unless an external force acted upon it.

A meterstick of negligible mass is placed on a fulcrum at the 0.4 m mark, with a 1 kg mass hung at the zero mark and a 0.5 kg mass hung at the 1.0 m mark. The meterstick is held horizontal and released. Immediately after release, the magnitude of the net torque on the meterstick about the fulcrum is most nearly:________

a. 1 Nm
b. 2 Nm.
c. 2.5 Nm.
d. 7 Nm
e. 7.5 Nm

Answers

Answer:

The net torque is 0.98 Nm.

Explanation:

The torque is given by

Torque = force x perpendicular distance

The clock wise torque is taken as negative while the counter clock wise torque is taken as positive.

Take the torques about the fulcrum.

Torque =  1 x 9.8 x 0.4 - 0.5 x 9.8 x 0.6

Torque = 3.92 - 2.94 = 0.98 Nm

A meterstick of negligible mass is placed on a fulcrum at the 0.4 m mark, with a 1 kg mass hung at the
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