1.Which of the following is the nature of sound wave?​

The value of Kc for the given reaction is 0.0579 (rounded to four decimal places).

The formula for the equilibrium constant, Kc, of a reaction is given by the ratio of the product of the concentrations of the products raised to their respective stoichiometric coefficients to the product of the concentrations of the reactants raised to their respective stoichiometric coefficients.

The stoichiometric coefficients are the coefficients in the balanced chemical equation.

To determine the value of Kc for the reaction given by the following chemical equation:N2(g) + 3 H2(g) ⇌ 2 NH3(g)

we first need to write the expression for Kc.

The expression for Kc is given by the following formula:Kc = [NH3]² / [N2][H2]³.

We are given the equilibrium concentrations as follows:[N2]eq = 2.66 M[H2]eq = 0.64 M[NH3]eq = 3.34 M

We can substitute these values into the expression for Kc and obtain the following:Kc = (3.34)² / (2.66)(0.64)³ = 0.0579 (rounded to four decimal places).

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The final temperature of the water is: T_final = 45.0°C

We can use the formula for the specific heat capacity of the water to solve this problem:

q = mcΔT

First, we can calculate the initial energy of the water:

q = mcΔT

q = (10.0 g) (4.184 J/g°C) (25.0°C)

q = 1,046 J

Next, we can calculate the final temperature after absorbing 840 J:

q = mcΔT

840 J = (10.0 g) (4.184 J/g°C) (ΔT)

ΔT = 20.0°C

Therefore, the final temperature of the water is:

T_final = T_initial + ΔT

T_final = 25.0°C + 20.0°C

T_final = 45.0°C

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The equation can be balanced by using options C and E

To balance a chemical reaction equation, you need to ensure that the number of atoms of each element is the same on both sides of the equation. Balancing the equation is important because it follows the law of conservation of mass, which states that matter cannot be created or destroyed in a chemical reaction.

Start balancing with elements that appear in the fewest compounds: Begin balancing the equation by adjusting elements that appear in the fewest compounds first.

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The type of movement that occurs in the plate movement listed above include the following:

These are gigantic pieces of the Earth's crust and uppermost mantle and are made up of oceanic crust and continental crust.

A convergent boundary as the name implies occurs when lithospheric plates are moving towards one another.

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a)The  eluent is made up of mostly nonpolar solvent. b) The eluent must have a requirement other than the proper polarityc)the pair of solvents used in the TLC experiment must also have different rates of migration.d)i) If more ethyl acetate was added to the eluent, the distance traveled by the sample(s) would increase.ii) If more hexanes were added to the eluent, the distance traveled by the sample(s) would decrease.

a) The eluent used in the TLC experiment is a 2:1 mixture of hexanes/ethyl acetate. According to Table 8.3 in the TLC chapter, this eluent is made up of mostly nonpolar solvent.

b) In order to move spots from the spotting line, the eluent must have a requirement other than the proper polarity. Specifically, it must have the ability to dissolve the compounds present in the sample.

c) In addition to having a proper balance of polarity, the pair of solvents used in the TLC experiment must also have different rates of migration. This allows for the separation of the components in the sample mixture.

d) The distances traveled by the sample(s) on the TLC plate would be impacted if more ethyl acetate or hexanes were added to the eluent. Specifically:

i) If more ethyl acetate was added to the eluent, the distance traveled by the sample(s) would increase. This is because ethyl acetate is a more polar solvent than hexanes, which means that it would cause the sample(s) to travel further up the TLC plate.

ii) If more hexanes were added to the eluent, the distance traveled by the sample(s) would decrease. This is because hexanes is a less polar solvent than ethyl acetate, which means that it would cause the sample(s) to travel a shorter distance up the TLC plate.

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AgNO₃ means silver nitrate reagent could be used to separate Br- from SO₄²⁻ when added to an aqueous solution containing both

Reagents may be used in a chemical reaction to detect, measure, or make other substances and silver nitrate is the reagent could be used to separate bromine from SO₄²⁻ when added to an aqueous solution and in this reaction bromine is separate out from thiosulphate in the presence of silver nitrate give silver thiosulphate and silver thiosulphate is a white precipitate

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To answer this question, we have to use the partial pressures gas law, that states that:

Where Pi is the partial pressure of the gas, Xi is the mole fraction of the gas and PT is the total pressure, replace for the given values:

It means that the partial pressure of Ne is 0.51atm.

Here, we are required to explain why solids are less affected by pressure than liquid and gases are.

Solids are a state of matter characterized by a fixed volume.

Although, liquids are relatively incompressible compared to gases.

The order of organization in states of matter is;

Solids > liquids > gases

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The mass of hydrogen is 5.5g.

1st) We are going to assume that the density of water is 1g/ml, so using the density formula and replacing the volume on it, we can calculate the mass of water:

Now we know that the mass of water is 50g.

2nd) The mass of water calculated (50g) represents the 100% of the mass.

With the percent of hydrogen, we can calculate the mass of hydrogen:

If 100% represents 50g of water, then the 11% of hydrogen in the water represents 5.5g.

So, the mass of hydrogen in 50ml of water is 5.5g.

Answer:

Calcium (Ca) is in group 2 and period 4 on the periodic table be because Calcium has 2 valence electrons and 4 electron shell. Thus, calcium is a metal like all other group 2 element.

Explanation:

The average atomic mass of magnesium is 24.305 amu.

The mass of a single atom is too small to be measured directly, but chemists and physicists use the atomic mass unit (amu) to describe the mass of an atom.

The atomic mass unit is defined as 1/12th of the mass of a carbon-12 atom. Magnesium (Mg) has three isotopes: Mg-24, Mg-25, and Mg-26, with masses of 23.985 amu, 24.986 amu, and 25.983 amu, respectively.

These isotopes make up 78.99%, 10.00%, and 11.01%, respectively, of all naturally occurring Mg atoms.

The atomic mass of Mg can be calculated using the weighted average of the three isotopes as follows:Average atomic mass = (78.99/100 x 23.985 amu) + (10.00/100 x 24.986 amu) + (11.01/100 x 25.983 amu)Average atomic mass = 23.940 amu + 2.499 amu + 2.864 amuAverage atomic mass = 29.303 amu.

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The oxidation state of nitrogen (N) in NaNO3 is +5. option B

To determine the oxidation state of nitrogen (N) in sodium nitrate (NaNO3), we need to assign oxidation numbers to each element in the compound.

In NaNO3, we know that the sodium ion (Na+) has a +1 oxidation state because it is an alkali metal. Oxygen (O) typically has an oxidation state of -2 in compounds, and there are three oxygen atoms in NaNO3. Since the compound is neutral, the sum of the oxidation states must be zero.

Let's assume that the oxidation state of nitrogen is x. Therefore, we can set up the equation:

(+1) + x + (-2) * 3 = 0

Simplifying the equation:

+1 + x - 6 = 0

x - 5 = 0

x = +5

Therefore, the oxidation state of nitrogen (N) in NaNO3 is +5.

The oxidation state of an element indicates the number of electrons it has gained or lost in a compound. In this case, the nitrogen atom in NaNO3 has gained five electrons to achieve a stable oxidation state of +5.

It is important to note that oxidation states are formal charges and do not necessarily represent the actual distribution of electrons in a compound. They are assigned based on a set of rules and can be useful in understanding the reactivity and behavior of elements in chemical reactions.

Option B

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Answer:

Protons

Explanation:

Metals, Nonmetals, and Metalloids group the elements on the periodic table. Protons is not one of these but rather a subatomic particle that all the elements have.

Answer:

protons

Explanation:

Explanation:

I have a dog in my dog is a girl

Answer:

me

Explanation:

I'm a girl and I have a RIDE skele-rex and a ride cerberus and a n f r GRIFFIN and a f r gold rat and a normal unicorn a RIDE kitsune

Answer:

The coloring and possibly testing it

Potassium chloride is a medication that is used to treat or prevent low potassium levels in the body.Potassium can be removed from the body by certain diseases, illnesses, and drugs.

The addition of NaCl to a KCl mixture reduces the unpleasant side tastes associated with KCl, such as bitter, chemical, and metallic.

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Answer:

The pH at the midpoint in the titration of an acid with a base is

A) equal to the pK of the corresponding base.

B) equal to the pK of the corresponding acid.

C) equal to 14 minus the pK of the corresponding acid.

D) equal to 14 plus the pK of the corresponding base.

E) none of the above

Explanation:

When a weak acid is titrated with a strong base, then a buffer solution is formed.

pH of a buffer solution can be calculated by using the formula:

\(pH=pKa+log\frac{[salt]}{[acid]}\)

Exactly at the mid point,

[conjugate base of the salt]=[acid]

So, log [salt]/[acid] =0

Hence, pH of the solution will be equal to pKa of the weak acid.

Answer is option B.

Answer:

\(t=90.0s\)

Explanation:

Hello,

In this case, for first-order kinetics we have an integrated rate law of this reaction as:

\(ln(\frac{[N_2O_5]}{[N_2O_5]_0} )=-kt\)

Thus, we compute the time for an initial concentration of 0.280 M which ends up in 0.0476 M as shown below:

\(t=\frac{ln(\frac{[N_2O_5]}{[N_2O_5]_0} )}{-k}=\frac{ln(\frac{0.0476M}{0.280M})}{-0.0197s}\\ \\t=90.0s\)

Best regards.

A type of fossil fuel,known as Tar stands.

A fossil fuel is a hydrocarbon-containing material formed naturally in to  the Earth's crust from to the  remains of dead plants and animals and birds that is the  extracted and burned as thr  a fuel. The main fossil  fuels are mainly coal, oil, and natural gas.

Tar sands are a combination of clay, sand, water and bitumen, which is a heavy hydrocarbon. Like the  kerogen in oil shale, tar sands' bitumen can be upgraded to synthetic crude oil.

So answer is tar sands.

These include tar sands – deposits of moist sand and it is  clay with 1-2 percent  bitumen (thick and heavy are  petroleum rich in the  carbon and poor in the  hydrogen). These are the  removed by strip mining in the  (see section below on coal)

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We must melt about 3.8 kg of brass A, 4.1 kg of brass B, and 6.5 kg of brass C to obtain about 14.5 kg of the desired alloy

we can set up a system of equations based on the conservation of mass and the desired composition:

0.533x + 0.247y + 0.220z = 14.5 (desired composition of copper, zinc, and nickel)

The given information includes:

Brass A: 41% copper, 23% zinc, 36% nickel

Brass B: 54% copper, 23% zinc, 23% nickel

Brass C: 56% copper, 26% zinc, 18% nickel

Using this information, we can write the following equations:

0.41x + 0.54y + 0.56z = 0.533(x + y + z) (copper)

0.23x + 0.23y + 0.26z = 0.247(x + y + z) (zinc)

0.36x + 0.23y + 0.18z = 0.220(x + y + z) (nickel)

Simplifying each equation, we get:

0.067x - 0.027y - 0.023z = 0 (copper)

-0.017x + 0.017y + 0.003z = 0 (zinc)

-0.020x - 0.027y + 0.038z = 0 (nickel)

We can solve the equations using substitution method or elimination method and our values will be:

x = 3.8462

y = 4.1077

z = 6.5461

In conclusion, we need to melt about 3.8 kg of brass A, 4.1 kg of brass B, and 6.5 kg of brass C to obtain about 14.5 kg of the desired alloy.

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Types of luminous flames:

1. Yellow Luminous Flame

2. Smoky Luminous Flame

3. Orange Luminous Flame

4. Blue Luminous Flame

Luminous flames are characterized by their visible glow, which is caused by the incomplete combustion of fuel. The presence of soot particles in the flame causes the emission of light. There are different types of luminous flames, which can be classified based on their fuel composition and burning conditions. Here are some common types of luminous flames:

1. Yellow Luminous Flame: This is the most common type of luminous flame, often seen in open fires, candles, and gas stoves. It appears yellow due to the presence of soot particles in the flame. Yellow flames indicate incomplete combustion of hydrocarbon fuels, such as methane, propane, or natural gas. The high carbon content in these fuels leads to the formation of soot, which emits visible light.

2. Smoky Luminous Flame: This type of flame is characterized by a significant amount of black smoke and soot production. It is commonly observed in poorly adjusted or malfunctioning burners or engines. The excessive presence of unburned fuel in the flame results in incomplete combustion and the emission of dark smoke particles.

3. Orange Luminous Flame: An orange flame indicates a higher combustion temperature compared to a yellow flame. It is often seen in more efficient burners or when burning fuels with a higher carbon content, such as oil or diesel. The higher temperature helps in burning more of the carbon particles, reducing the amount of soot and making the flame appear less yellow.

4. Blue Luminous Flame: A blue flame is typically associated with complete combustion. It indicates efficient burning of fuel, resulting in minimal soot formation. Blue flames are commonly observed in gas burners or Bunsen burners. The blue color is a result of the combustion of gases, such as methane, in the presence of sufficient oxygen.

It's important to note that the luminosity of a flame can vary depending on factors such as fuel-air mixture, combustion temperature, and the presence of impurities. Achieving complete combustion and minimizing the production of soot is desirable for efficient and cleaner burning processes.

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i think it's a simple covalent structure

Determining the exact time of death based solely on the condition of a body can be challenging and imprecise. However, several factors can provide some insight into the estimated time since death.

In the given scenario, the body has lost its nails and its tissues have died, indicating some level of decomposition.During mild temperatures in the spring, the rate of decomposition is typically faster compared to colder or hotter conditions. Under such circumstances, and assuming no significant external factors affecting decomposition (e.g., burial or covering), a rough estimate suggests that the person may have been deceased for several weeks to a few months.The loss of nails and tissue death suggest the progression of decomposition beyond the early stages. In the initial days following death, the body undergoes autolysis, where enzymes within the body's cells begin breaking them down.

This is followed by putrefaction, the breakdown of tissues by bacteria and other microorganisms. During putrefaction, nails and other keratinous structures can detach.However, it's important to note that various factors such as body size, health conditions, humidity, and exposure to insects and scavengers can influence the rate of decomposition. Therefore, the estimated time since death should be considered approximate, and a forensic examination conducted by professionals would provide a more accurate determination.

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Answer:

pretty sure its B

Explanation:

Answer:

b :)

Explanation:

right on edge 2020

This problem is asking for the mass of anthracene one should use to decrease the melting point of a solution with 100.0 g of cyclohexane, and its freezing point depression constant, by 5.50 °C. At the end, the result turns out to be 4.81 g.

In chemistry, colligative properties are the result from mixing a solute and a solvent in order to modify the properties of the latter due to the addition of the former. Thus, freezing point depression, boiling point elevation, osmotic pressure and vapor pressure lowering are colligative properties one can go over.

In this case, we talk about freezing point depression, or even melting, because anthracene is added to cyclohexane to decrease its freezing, or melting, point by 5.50 °C. In such a way, we can calculate the mass of anthracene by firstly calculating the molality of the solution with:

\(\Delta T_f=-m*Kf\\\\m=\frac{-\Delta T_f}{Kf} \\\\m=\frac{-(-5.50\°C)}{20.4\°C/m}\\\\m=0.270mol/kg\)

Then, as 100.0 g of cyclohexane are equivalent to 0.1000 kg and, given the molar mass of anthracene, we can calculate the mass with the previous molality:

\(m_{anthracene}=0.270\frac{mol}{kg}*0.1000kg*\frac{178.23g}{1mol} \\\\m_{anthracene}=4.81g\)

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Explanation:

colligative properties are properties that depend on the concentration of molecules or ions of the solute, but not on the identity of the solute. Colligative properties include lowering of vapour pressure, boiling point elevation, depression of the freezing point, and osmotic pressure

Answer:

1. Vapor pressure

2. Boiling point

3. freezing point

4. Osmic pressure

Explanation:

1. Vapor pressure: the pressure by the gas in equilibrium with a solid or a liquid at a given temperature is called the Vapor pressure.

2. Boiling point: the temperature at which a liquid boils and turns into Vapor.

3. Freezing point: the temperature at which a liquid turns into a solid when cooled.

4. Osmic pressure: Osmotic pressure is the minimum pressure which needs to be applied to a solution to prevent the inward flow of its pure solvent across a semipermeable membrane. It is also defined as the measure of the tendency of a solution to take in a pure solvent by osmosis.