KCl > NaF > MgO. NaCl has the highest percentage of ionic character because it has the greatest difference in electronegativity between the two elements.
Lattice energy is the energy required to completely separate one mole of an ionic compound into its gaseous ions. Generally, the more electronegative element (the one with the higher electronegativity) has a higher lattice energy. In this case, KCl has the highest lattice energy because Cl is more electronegative than Na or Mg. NaF has the second highest lattice energy due to the relatively high electronegativity of F. MgO has the lowest lattice energy because O is less electronegative than both K and F. Therefore, the order of increasing lattice energy is KCl > NaF > MgO. The electronegativity difference between Na and Cl is 2.1, which is the highest of the five compounds given. This large difference in electronegativity between the two elements leads to a much stronger attraction between the positive and negative charges, which makes the bonding more ionic in nature.
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Lesson outline: magnets and magnetic fields if the magnetic fields of atoms point in different directions, the magnetic fields ________________ each other and the object is not a(n) _____________.
If the magnetic fields of atoms point in different directions, the magnetic fields cancel out each other, and the object is not a magnet.
When the magnetic fields of atoms within an object point in different directions, they can interact and cancel each other out. The magnetic fields can either align in opposite directions or have random orientations, resulting in a net magnetic field of zero. This cancellation of magnetic fields leads to a scenario where the object does not exhibit a significant or detectable magnetic field. As a result, the object is not considered a magnet. This cancellation phenomenon can occur in materials that do not possess strong magnetic properties or have a disordered arrangement of magnetic domains.
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The half-life of 3H (H-3) is 12 years. About how long does it take for 127/128 of a sample of that radionuclide to decay? (Hint: this means only 1/128 are left)
A: 7 years
B:11.9 years
C:84 years
D:12.1 years
Answer:
i do believe its 7
Explanation:
Answer:84
Explanation:
formation of water: 2H2 + 1 O2 --> 2H20
How many moles of O2 will I need to produce 15 moles of H2O?
Answer don’t delete comment or I’ll report
Answer:
n=15 moles H2O
1:2
x:15
x=7.5 moles of O2
Scientist use alternative ways to seek out if a fault is active which one isn't include
Answer:
Geologists commonly consider faults to be active if there has been movement observed or evidence of seismic activity during the last 10,000 years. Active faulting is considered to be a geologic hazard - one related to earthquakes as a cause.
Explanation:
Plz mark brainliest thanks
Which compound contains ionic bonds?
Answer:
Sodium chloride, on the other hand, contains ions; it is an ionic compound. CaO is correct.
Explanation:
3. (7 pts) Identify the functional or alkyl group present in the R groups of each of the following amino acids (see p. 75): a. aspartic acid b. threonine c. glutamine
d. cysteine e. arginine f.
a. Aspartic acid contains a carboxylic acid functional group (-COOH) in its R group.
b. Threonine contains a hydroxyl (-OH) functional group in its R group. c. Glutamine contains an amide (-CONH2) functional group in its R group.d. Cysteine contains a thiol (-SH) functional group in its R group. e. Arginine contains a guanidine (-C(NH2)(NH)NH2) functional group in its R group.f. Please provide the missing amino acid in the question to answer it correctly.
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Which set of elements have the most similar chemical properties?
1. Potassium, Calcium, Scandium
2. Chromium, Cobalt, Copper
3. Nitrogen, Oxygen, Fluorine
4. Oxygen, Sulfur, Selenium
Answer:
4
Explanation:
Oxygen, Sulfur, Selenium
Transformation of Energy Lab Report Instructions: In Part One of the Transformation of Energy lab, you will research and experiment with a Rube Goldberg Machine simulation to show the transformation of energy from one object to another to complete a simple task. In Part Two, you will design your own Rube Goldberg device. Record your observations and work in the lab report below. You will submit your completed lab report for both Part One and Part Two of the lab. Name and Title: Title of Lab: Student Name: Instructor: Date: Part One: Rube Goldberg Simulation Research Instructions: First, complete the Rube Goldberg Machine simulation located in the lesson by selecting the shelves, levers, five-pound weight, slingshot, and/or pail to activate or deactivate each item. Once you feel the design is complete, select "Go" to test the design. After you make the necessary adjustments in the simulation so that the Rube Goldberg device will function properly, you will answer the following question. Please write in complete sentences. List three examples of where potential energy is transformed to kinetic energy in the Rube Goldberg Machine simulation. Fully explain the energy transformations using complete sentences. (Example: The ball has potential energy when it sits on the shelf that transforms to kinetic energy when it falls to the ground.) Example 1: Example 2: Example 3: Part Two: Your Rube Goldberg Device Design Instructions: Choose one option (either Build It or Draw it) to design your own Rube Goldberg device. Then, complete each of the sections of the lab report below. Your Rube Goldberg device design must include at least three energy transformations to perform a simple task. Option One: Build it If you build your device, you will need to turn in a video clip or photograph of your device along with a written description on how each step works. Option Two: Draw It If you draw your device, you will need to turn in your device design along with a written description of how each step works. You may choose to draw it freehand and scan or photograph the drawing, or you may use a computer program to digitally create your device. Objective(s): The purpose of this lab is to use models to explore how energy transforms from one form to another to support the law of conservation of energy. Hypothesis: In this section, include the if/then statement for your lab. This statement reflects your predicted outcome for the experiment. If I transfer potential and kinetic energy using a Rube Goldberg device, then I will be able to ________________. (Fill in the blank with the simple task your device will be able to do.) Materials: In this section, list the items and/or materials that are part of your Rube Goldberg device design. Procedure: In this section, include a summary of how your Rube Goldberg device design works from start to finish to complete a task. Your Rube Goldberg device design must include at least three energy transformations. Be sure to include the image, drawing, or video of the Rube Goldberg device that you created. You can include that here or submit a separate file. Data: Record your data in the chart below to include three examples of energy transformations in your Rube Goldberg device design. Example Item Types of energy that were transformed How the energy was transformed? Example Ball Potential energy transformed to sound energy. The ball fell off the shelf and hit the floor causing sound. 1 2 3 Conclusion: Complete the conclusion questions below. Please write in complete sentences. Describe how the Rube Goldberg device design that you created follows the law of conservation of energy. Be sure to include both parts of the law of conservation of energy in your description. Give a real-world example of an energy transformation that uses two of the following forms of energy: chemical, mechanical, nuclear, gravitational, radiant, electrical, thermal (heat), and/or sound.
Answer:
1. Click here to access an interactive simulation where you will explore the transfer and transformations of different types of energy that you have learned about in this lesson.
2. Click the systems box, and then select the energy symbols box. This will allow you to see the movement of energy and its type in the system.
3. Under the bike the person is riding, drag the blue rectangle to the right to start the system.
4. The chemical energy in the person's body is transformed into
✔ mechanical energy
when they peddle the bike, causing the generator to rotate. Some energy in the bike wheel is lost to
✔ thermal energy
. The generator produces electricity, which heats the water, causing it to produce thermal energy in the form of steam. When the person's chemical energy runs out, how do you replenish it?
✔ by feeding them food
5. Change the initial energy source to sun, the intermediate energy source to the solar panel, and the final energy source to the windmill. In this system,
✔ light energy
is produced from the sun and transformed into electricity in the solar panel. Both of these types of energy are considered forms of
✔ electromagnetic energy
. The result of this system is that the windmill produces mechanical energy.
6. Try a few more scenarios, choosing different initial, intermediate, and final energy sources. Observe places where energy is transformed and lost. Creating systems with the least amount of energy is important in engineering design.
Explanation:
✔ mechanical energy
✔ thermal energy
✔ by feeding them food
✔ light energy
✔ electromagnetic energy
A solution of iodine, which is dark brown, added to a solution of sodium bromide. What will be the color of the resulting solution
\(\huge\bold{ANSWER:}\)
brown-purple color── ── ── ── ── ── ── ── ── ── ──The oxidation potential of the halogens increases in the order I<Br<Cl<F, which means that if you have a solution of iodide ions and add bromine, the iodide will be oxidized to iodine, and the bromines reduced to bromides:
2 I(-) + Br2 → 2 Br(-) + I2
In the same way, two Br(-) will lose their electronsto a chlorine molecule, and the chlorides formed are going to lose their electrons if confronted with a fluorine molecule. This means that the opposite to the above reaction, i. e.
I2 + 2 Br(-) → no reaction
the brown-purple color of the iodine solution, when mixed with a colorless solution of bromide ions (from sodium bromide) will remain purple-brown, perhaps paler because of the dilution (a physical effect) which comes from mixing of two solutions but not because of any chemical reaction.
── ── ── ── ── ── ── ── ── ── ──I Hope you like my answer
Thank you:)
An unknown compound has an empirical formula of C2H3O and a molecular mass of 86 amu. -Draw a plausible structure for this compound that contains alcohol, ether, and alkyne functional groups.-Draw a plausible structure for this compound that contains aldehyde and ketone functional groups.
Based on the empirical formula of C2H3O, the molecular formula of the compound can be calculated using its molecular mass:
Molecular formula mass = (empirical formula mass) x n
where n is a positive integer that represents the number of empirical formula units in the molecule.
For this compound, the molecular formula mass is 86 amu, which is the same as the molecular mass given in the problem. Therefore, n = 1, and the molecular formula is also C2H3O.
Plausible structure with alcohol, ether, and alkyne functional groups:
One possible structure for this compound that contains an alcohol, ether, and alkyne functional groups is propargyl alcohol.
H C≡C─CH2─OH
│
O
This compound has the empirical formula C2H3O and a molecular mass of 56 amu. To get the molecular mass of 86 amu, we can add a methyl group (CH3) to the propargyl alcohol molecule:
H C≡C─CH2─O─CH3
│
O
Plausible structure with aldehyde and ketone functional groups:
Another possible structure for this compound that contains an aldehyde and ketone functional groups is propanal acetone.
H
│
O═C─CH2─CH3
│
O
│
CH3
This compound has the empirical formula C2H3O and a molecular mass of 86 amu.
What is an empirical formula?
The empirical formula of a chemical compound is the simplest ratio of whole number atoms of each element present in the compound. It gives the relative number of atoms of each element in a compound, but it does not indicate the actual number of atoms in the molecule. The empirical formula is determined from the mass percent composition of the compound.To know more about empirical formula, click the link given below:
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The difference between sunspots solar flares and prominence
Answer:
Sunspots are cooler and darker than the rest of the Sun's surface. They are marked by intense magnetic activity. Solar prominences are the plasma loops that connect two sunspots. Solar flares and coronal mass ejections are eruptions of highly energetic particles from the Sun's surface.
Explanation:
Answer:
Sunspots are dark areas on the surface of the Sun that are cooler than surrounding areas. They appear in groups, vary in size, and cycle in number over an 11-year period. Solar flares are sudden eruptions of energy from a small area of the Sun's surface. They are extremely hot (10 to 20 million degrees Celsius) and extend into the corona. Solar flares occur near sunspots and can disturb radio communications on Earth.
Explanation:
Express the dosage using the ratio format you prefer. (Use mg for milligrams and mL for an injectable solution that contains 250mg in each 0.6 mL 3. [-/3 Points] CURRENMEDMATH11 12.3.002. EP. Consider the following. A 40mg in 2.5 mL solution will be used to prepare a 26mg dosage. Calculate the dosage using ratio and proportion. Express your final answer in mL to the
40mg
mL
=
X mL
26mg
40x
X
=
=
mL
[-/1 Points] CURRENMEDMATH11 12.3.004. Calculate the dosage (in milliliters). Express your answer to the nearest tenth. Assess y A 36mg per 2 mL strength solution is used to prepare 22mg. mL
The dosage of 26mg can be prepared using approximately 1.625 mL of the 40mg in 2.5 mL solution.
The dosage of 22mg can be prepared using approximately 1.222 mL of the 36mg per 2 mL strength solution.
To calculate the dosage using ratio and proportion, we can set up a proportion based on the strength of the solution.
40mg in 2.5 mL solution will be used to prepare a 26mg dosage.
Let X represent the mL of the solution needed to prepare the 26mg dosage.
We can set up the proportion as follows:
40mg/2.5mL = 26mg/X mL
Cross-multiplying and solving for X, we have:
40mg * X mL = 2.5mL * 26mg
40X = 65
X = 65/40
X ≈ 1.625 mL
For the second question:
36mg per 2 mL strength solution is used to prepare 22mg.
Let Y represent the mL of the solution needed to prepare the 22mg dosage.
We can set up the proportion as follows:
36mg/2mL = 22mg/Y mL
Cross-multiplying and solving for Y, we have:
36mg * Y mL = 2mL * 22mg
36Y = 44
Y = 44/36
Y ≈ 1.222 mL
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PPPPPPPPLLLLLLLLLSSSSSS HHHHHHEEEEEELLLLPPPPP!!!!!!!!!!!!!!
Answer:
B
Explanation:
The student is not able to move the box in D --> 55N, 0N. Since the net force is 0, it means that no force is being applied. So you will choose answer B from your options.
Hope this helps, thank you !!
If a beach ball has a volume of 261 L at a temperature of 502 K, what will be the new
temperature of the balloon if the volume decreases to 176 L? Formula: V/T, -V2/T2
The new temperature of the balloon if the volume is decreased to the given amount is 338.5K.
Charles's law
Charles's law states that the volume occupied by a definite quantity of gas is directly proportional to its absolute temperature.
It is expressed as;
\(\frac{V_1}{T_1} = \frac{V_2}{T_2}\)
Given the data in the question;
Initial volume; \(V_1 = 261L\)Initial temperature; \(T_1 = 502K\)Final volume; \(V_2 = 176L\)Final Temperature; \(T_2 = \ ?\)
To determine the new temperature as the volume is decrease, we substitute our given values into the expression above.
\(\frac{V_1}{T_1} = \frac{V_2}{T_2}\\\\V_1T_2 = V_2T_1\\\\261L * T_2 = 176L * 502K\\\\261L * T_2 = 88352L.K\\\\T_2 = \frac{88352L.K}{261L}\\ \\T_2 = 338.5K\)
Therefore, the new temperature of the balloon if the volume is decreased to the given amount is 338.5K.
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draw the structure of the product of the enamine formed between acetophenone and dimethylamine.
Enamines are a class of nitrogen-containing compounds that include both nitrogen and carbon. A primary amine and a carbonyl compound are used to form enamines. The enamine structure of the product formed between acetophenone and dimethylamine is shown below:
H H
| |
H3C-C C-N(CH3)2
| + H2O -> |
C=O C
| |
Ph H
The product is N,N-dimethylcinnamamide.
In this process, an imine intermediate is produced first, which is then converted into an enamine. In this reaction, dimethylamine is used as a primary amine and acetophenone is used as a carbonyl compound. The nitrogen atom of dimethylamine is nucleophilic, and it can donate electrons to the carbonyl carbon of acetophenone.
This causes a pi bond to form between the carbon and the nitrogen atoms. The nitrogen atom also has a lone pair of electrons that can bond to a hydrogen atom. The enamine formed as a result of this reaction is shown above. The enamine has a double bond between the nitrogen and carbon atoms and a hydrogen atom bonded to the nitrogen atom.
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Due to periodicity, which of the following elements has chemical behavior similar to that of fluorine? Potassium Chlorine Magnesium Iron
Fluorine and chlorine, the following element, have comparable chemical properties.
How do we define "chemical"?Chemicals are thought to include any substance whose composition is known. A chemical, to put it another way, always contains the same "stuff." Some chemicals can be found in natural things like water. Numerous chemicals, including chlorine, are created (used for bleaching fabrics or in swimming pools).
An illustration of a chemical would be.A chemical is composed of one element or any combination of these components. As an illustration, the molecule of oxygen in the air is always composed of two distinct oxygen molecules. A chemical can exist in many different forms, but an element is the most basic since it is used to create additional compounds.
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Why is Gold non-reactive?
Metals such as copper, silver, and gold are the least reactive and are at the bottom of the reactivity scale, this is the reason tha gold is non-reacive.
Why is Gold non-reactive?The one electron in the 6s orbital is more closely bonded to the nucleus and has less space to form bonds with other atoms as a result of the contraction of the 6s orbital. The 4f and 5d orbitals expand but cannot participate in bond formation since they are totally filled. This explains why gold is largely inert.
Due to its low reactivity in the reactivity series and its propensity to resist reactions with moisture or air, gold does not corrode. Most acids and oxygen have little effect on gold. Compared to other substances like sulphides or oxides, gold is the most stable.
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what is a coulomnbic interaction? is the coulombic contribution to bonding stronger in lif or in mgo?
The coulombic contribution to bonding stronger is in mgo
Coulomb interaction is the electrostatic interactions between electric charges, and follows the Coulomb's law.
It is a basis of classical electrodynamics. In general, Coulomb interaction can manifest itself on various scales from microscopic particles to macroscopic bodies.
When unlike charges (one negative and the other positive) attract each other, or like charges (both positive or both negative) repel each other, Coulomb's law governs the force between them. According to this law the force of attraction or repulsion varies inversely with the square of the distance between the charges.
Higher the magnitude of the charges we have higher coulombs force of attraction. Thus, we can say that the molecule MgO has a higher attraction force between them and has a stronger ionic bond than LiF.
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Describe the four states of matter.
Part 1: Predict which compound in each pair is more acidic. Explain your answers
. a) cyclopentanol or 3-clorophenol
b) cyclohexanol or cyclohexantiol
c) cyclohexanol or cyclohexanecarboxylic acid
d) 2,2-dichlorobutan-1-ol or butan-1-ol
Part 2: Predict which compound in each group is more soluble in water. Explain your answers.
a) butan-1-ol, pentan-1-ol or propan-2-ol
b) chlorocyclohexane, cyclohexanol or cyclohexane-1,2-diol
c) phenol, cyclohexanol or 4-methylcyclohexanol
(1a) 3-Chlorophenol is more acidic than cyclopentanol (chlorine atom electron-withdrawal). (1b) Cyclohexanecarboxylic acid is more acidic than cyclohexanol (stronger carboxylic acid group).
(2a) Propan-2-ol is more soluble in water than butan-1-ol and pentan-1-ol (hydrogen bonding ability). (2b) Cyclohexanol is more soluble in water than chlorocyclohexane (hydroxyl group enables hydrogen bonding).
Part 1: Comparing Acidic Strength
a) 3-chlorophenol is more acidic than cyclopentanol. This is because the presence of a chlorine atom in 3-chlorophenol can stabilize the negative charge on the phenoxide ion through inductive and resonance effects, making it more stable and easier to form.
b) Cyclohexanecarboxylic acid is more acidic than cyclohexanol. The carboxylic acid group (-COOH) is a stronger acid functional group compared to the hydroxyl group (-OH) present in cyclohexanol.
c) 2,2-dichlorobutan-1-ol is more acidic than butan-1-ol. The presence of the electron-withdrawing chlorine atoms in 2,2-dichlorobutan-1-ol enhances the acidity by stabilizing the negative charge on the alkoxide ion formed upon deprotonation.
d) Cyclohexanecarboxylic acid is more acidic than cyclohexanol. The carboxylic acid group (-COOH) is a stronger acid functional group compared to the hydroxyl group (-OH) present in cyclohexanol.
Part 2: Comparing Solubility in Water
a) Propan-2-ol is more soluble in water than butan-1-ol and pentan-1-ol. Propan-2-ol has a hydroxyl group (-OH) that can form hydrogen bonds with water molecules, increasing its solubility.
b) Cyclohexanol is more soluble in water than chlorocyclohexane. The presence of the hydroxyl group in cyclohexanol allows for hydrogen bonding with water molecules, enhancing its solubility. Chlorocyclohexane, on the other hand, is nonpolar and lacks the ability to form significant hydrogen bonds with water.
c) Cyclohexanol is more soluble in water than phenol and 4-methylcyclohexanol. Both cyclohexanol and phenol can form hydrogen bonds with water, but phenol's aromatic ring reduces its solubility. 4-methylcyclohexanol is also less soluble than cyclohexanol due to the steric hindrance from the methyl group, which disrupts hydrogen bonding.
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Which of the following explains how inlets are impacted by high tides?
A. High tides fill inlets with water so they become larger.
B. High tides cause the land to be more exposed.
C. High tides remove sand and seashells on the beach.
D. High tides erode the sediments from an inlet.
(pls help)
Answer:It's D
Explanation:
Under what conditions would pressure affect the reaction rate?
A. If the reaction requires the use of a catalyst
B. If the reaction takes place between a solid and a liquid
O c. If the reaction is between two liquids
D. If the reaction occurs in the gas phase
Answer: D. If the reaction occurs in the gas phase
Explanation:
Answer:
D is correct via A P e x
Explanation:
which of the compounds ofh2c2o4,ca(oh)2,koh, and hi, behave as acids when they aredissolved in water?
Answer: The compound H2C2O4 behaves as an acid when dissolved in water.
What are acids?
Acids are chemical compounds that donate protons, hydrogen ions, or accept electrons or lone pairs in chemical reactions. Acids increase the concentration of hydrogen ions (H+) in a solution.
Arrhenius acid: Arrhenius acid is any substance that provides an excess of H+ (hydronium ions) when dissolved in water, increasing the concentration of H+ ions in the solution.
What are bases?
Bases, like acids, are substances that contain elements or molecules that can interact with ions or protons in water. In water, bases, in general, decrease the concentration of hydrogen ions and increase the concentration of hydroxide ions. Base solutions may be defined as those with a pH greater than 7.
What is a solution?
A solution is a homogeneous mixture of two or more substances that is uniform throughout.
What is dissolution?
Dissolution is the process of dissolving a solute in a solvent to form a solution. Solutes: Solutes are the substances that are dissolved in a solvent to create a solution. Solvents: Solvents are the substances in which solutes dissolve to create a solution.
Which of the given compounds behave as acids when they are dissolved in water?
The following are the given compounds: Ca(OH)2KOHHIH2C2O4 Of all the given compounds, the compound H2C2O4 behaves as an acid when it is dissolved in water.
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what mass of al is required to completely react with 30.0 g mno2 ?what mass of is required to completely react with 30.0 ?12.4 g al 7.76 g al 5.82 g al 10.3 g al
10.3 g of Al is required to completely react with 30.0 g of MnO₂. The correct answer is option D.
Manganese dioxide reacts with aluminum to produce manganese and aluminum oxide. Here's the balanced chemical equation: 3MnO₂ + 4Al → 3Mn + 2Al₂O₃. Now, let's calculate the mass of Al required to react completely with 30.0 g of MnO₂: From the balanced equation, we can see that 3 moles of MnO₂ react with 4 moles of Al.
The molar mass of MnO₂ is 86.94 g/mol. 30.0 g of MnO₂ is equal to:30.0 g / 86.94 g/mol = 0.3444 mol MnO₂. According to the balanced equation, 0.3444 mol of MnO₂ requires: 4/3 × 0.3444 mol = 0.4592 mol of Al. The molar mass of Al is 26.98 g/mol. 0.4592 mol of Al is equal to: 0.4592 mol × 26.98 g/mol = 12.4 g of Al. Therefore, 12.4 g of Al is required to completely react with 30.0 g of MnO₂. Hence, option D is the correct answer.
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An object that has 0 acceleration will NEVER be in motio
TRUE
FALSE
Check it
Answer:
true
Explanation:
Just think if a car was going 0 mph, would it move?
6. What is the mass of the object if the net force acting on it was 356 N and the acceleration rate
was 4 m/s/s2
The mass of an object with a net force of 356N and an acceleration rate of 4m/s² is 89kg.
How to calculate mass?The mass of an object can be calculated using the following formula:
F = ma
Where;
F = force (N)m = mass (kg)a = acceleration (m/s²)m = F/a
m = 356/4
m = 89kg
Therefore, the mass of an object with a net force of 356N and an acceleration rate of 4m/s² is 89kg.
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Name the element with an atomic mass of 267
If potassium is a soft reactive metal at room temperature, name one other element you would expect to also be a soft reactive metal at room temperature? How do you know?
Explanation:
Lithium
Sodium
group one elements are highly reactive
if a reaction is first order with a rate constant of 0.0450 s⁻¹, how much time is required for 65% of the initial quantity of reactant to be consumed?
It will take approximately 26.5 seconds for 65% of the initial quantity of reactant to be consumed in this first-order reaction.
The integrated rate law for a first-order reaction is:
ln([A]t/[A]0) = -kt
where [A]t is the concentration of a reactant at time t, [A]0 is the initial concentration, k is the rate constant, and ln is the natural logarithm.
To solve for t when 65% of the initial quantity of reactant is consumed, we can use the following steps:
Determine the concentration of reactant remaining after 65% is consumed:
[A]t = (1 - 0.65) [A]0 = 0.35 [A]0
Rearrange the integrated rate law to solve for time t:
t = -ln([A]t/[A]0) / k
Substitute the given values and solve for t:
t = -ln(0.35) / 0.0450 s⁻¹
t ≈ 26.5 seconds
Therefore, it will take approximately 26.5 seconds for 65% of the initial quantity of reactant to be consumed in this first-order reaction.
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Balanced chemical reactions obey the law of
conservation of mass
a. True
b. False
Answer:
True
Explanation:
A balanced chemical equation always obeys the law of conservation of mass. According to this law, the mass of products must be equal to the mass of reactants. A reaction is said to be balanced when the total mass of atoms on both sides of the chemical reaction is equal.