1pt Which part of the scientific method helps you figure out what you've learned?
O A. Predict
OB. Observe
O c. Design
OD. Analyze

Answer:

the amount of Ba(OH)2 compared to H2SO4?

The Ba(OH)2 dissociates as Ba+2 + 2 OH-. H2SO4 dissociates as 2 H+ + SO4-2.

Why does it not conduct at this low point?

Why does it conduct more before and after this minimum point

Can someone please help with this I am not that great at chemistry. Thankyou fo any help that I ge

Answer:

How Long Is The Lunar Cycle: Each lunar cycle lasts 27 days, 7 hours and 43 minutes. This means that the moon takes almost 28 days to complete a full orbit around the earth. Over this course, the moon goes through several phases, which alters its appearance and even the pattern of movement in the sky.

Explanation:

hope this helps plz mark brainliest

Answer:

27 days and 7 hours

Explanation:

im guessing on this one but im pretty sure its correct it also says that our moon completes the cycle in 29.5 days.

Answer:

Antarctica is a desert. It does not rain or snow a lot there. When it snows, the snow does not melt and builds up over many years to make large, thick sheets of ice, called ice sheets.

Explanation:

Answer:

C₂H6 + O2 → 2CO2 + 3H2O

A chemist determines that a substance is composed of 30.4% nitrogen by mass and 69.6% oxygen by mass. The molar mass of the compound is 230.5 g/mol, the molecular formula is NO₂.

We must compute the empirical formula in order to ascertain the compound's chemical composition.

If we have 100 grams of the compound.

This suggests we have:

30.4 g of nitrogen

69.6 g of oxygen

Now, we have to convert the mass of each element to moles.

The molar mass of nitrogen (N) = 14.01 g/mol

the molar mass of oxygen (O)  =  16.00 g/mol.

Number of moles of nitrogen (N):

2.17 mol

Number of moles of oxygen (O):

4.35 mol

The simplest whole-number ratio between the moles of nitrogen and oxygen must now be determined. To calculate the ratio, we divide both numbers by the smaller value.

Moles N / moles O = 2.17 mol / 2.17 mol = 1.00

Moles O / moles O = 4.35 mol / 2.17 mol = 2.00

The ratio is approximately N₁O₂.

We divide the subscripts by their greatest common divisor to obtain the simplest ratio, since we are looking for the empirical formula. The empirical formula is NO₂ since the greatest common divisor in this situation is 1.

The molecular formula of the compound is NO₂.

Learn more about molecular formula, here:

https://brainly.com/question/11203434

#SPJ1

Cu + O2 --->  CuO2 -The first reaction is a combustion reaction

2 HCl + Mg → H2 + MgCl2- The second reaction is a Single replacement reaction

A combustion reaction is a type of chemical reaction that occurs between a fuel and an oxidizer in the presence of heat or light, resulting in the release of energy in the form of heat and light.

In other words, it is a reaction in which a substance reacts with oxygen to produce heat and light.

Combustion reactions are important in many aspects of daily life, including the burning of fossil fuels for energy production, the combustion of wood or other materials for heating or cooking, and the combustion of fuels in internal combustion engines.

Learn more about combustion reaction:https://brainly.com/question/30562669

#SPJ1

The structure of Arg-Ile-Tyr is given below:

Peptides make up short chains of amino acids, which act as the fundamental units for building proteins. Within these chains, peptides usually consist of no more than 50 amino acids in contrast to proteins that are made up of significantly longer structures.

Found throughout various sources such as plants, animals, and bacteria, peptides play crucial roles in multiple biological processes including signaling, enzyme activity, and immune response.

Additionally, artificially synthesized peptides serve several purposes within the medicine, cosmetics, and food industries. Scientists are also exploring certain peptide's potential therapeutic advantages mainly pertaining to anti-inflammatory, antimicrobial, and anticancer activities.

Read more about peptides here:

https://brainly.com/question/21884818

#SPJ1

The amount of acetylsalicylic acid in the tablet is 0.001389 moles and the number of hydrogen atoms in the amount of acetylsalicylic acid in the tablet is 6.69 × 10²¹.

(a)

The formula of acetylsalicylic acid is C₉H₈O₄.

Molar mass of C₉H₈O₄ = 9 × atomic mass of C + 8 × atomic mass of H + 4 × atomic mass of O

                                      = 9 × 12 + 8 × 1 + 4 × 16

                                      = 108 + 8 + 64

                                      = 180

No of moles of acetylsalicylic acid = Given mass / molar mass

                                                         = 0.25 / 180

                                                         = 0.001389

Hence, the number of moles of acetylsalicylic acid is 0.001389 moles.

(b)

Number of hydrogen atoms present in 1 mole of acetylsalicylic acid = 6.023 × 10²³ atoms

Number of hydrogen atom present in 0.001389 moles of acetylsalicylic acid = 0.001389 × 6.023 × 10²³ = 0.008365 = 8.36 × 10²⁰ atoms.

Now there are 8 hydrogen atoms in acetylsalicylic acid so,

Number of atoms of hydrogen in acetylsalicylic acid = 8 × 8.36 × 10²⁰ atoms = 6.69 × 10²¹ atoms.

Hence, the number of atoms of hydrogen in 0.001389 moles of acetylsalicylic acid is 6.69 × 10²¹ atoms.

Learn more about number of atoms from the link given below.

https://brainly.com/question/496549

#SPJ1

Organic transformation sequential equation using catalysts will be as follows:

2CH3-CH2-O => (alc. KOH) => CH2=CH2 + KCl + H2O => (Br2/CCl4) => CH2Br-CH2Br + Zn

CH2Br-CH2Br + Zn => (HBr /Pd) => CH2=CH2+ZnBr2

As can be visualized from above organic transformation equation, conversion of dry ether in presence of alkaline potassium hydroxide results in formation of unstable ethene. This dry unsaturated compound of ethene is stabilized by reaction that happens in presence of bromine or calcium tetrachloride as the catalyst which results in formation of ethylene bromide which in presence of highly efficient palladium as catalyst results in formation of stable ethene as byproduct. Thereby with formation of stable compound of ethylene, it releases zinc bromide as byproduct resulting completion of reaction equation. This stable product ethene is a double bonded carbon structure that is chemically extremely flammable and has planar structure.

To know more about organic transformation:

brainly.com/question/14413579

#SPJ1

The energy in joules of a photon that has a frequency of 7.49 × 10¹⁴ s⁻¹ is 4.963 × 10-²¹ J.

The energy of a photon or light wave can be calculated using the following formula:

E = hf

Where;

According to this question, the frequency a photon is given as 7.49 × 10¹⁴ s⁻¹ where the Planck's constant (h) is 6.626 × 10⁻³⁴ J • s. The energy can be calculated as follows:

E = 7.49 × 10¹⁴ × 6.626 × 10⁻³⁴

E = 4.963 × 10-²¹ J

Therefore, the energy in joules of a photon that has a frequency of 7.49 × 10¹⁴ s⁻¹ is 4.963 × 10-²¹ J.

Learn more about energy of a photon at: https://brainly.com/question/2393994

#SPJ1

Answer:

Q = 3937.56  J

Explanation:

Heat transferred due to change in temperature is given by :

\(Q=mc\Delta T\)

c is the specific heat of water, c=4.18 J/g-°C

We have, m = 15 g, \(T_i=100^{\circ} C\ \text{and}\ T_f=37.2^{\circ} C\)

So,

\(Q=15\times 4.18\times (37.2-100)\\Q=-3937.56\ J\)

Hence, 3937.56  J of heat is transferred.

Answer:

Energy retained at consumer level 1 -  units

Energy retained at consumer level 2 -  units

Energy retained at consumer level 3 -  units

Explanation:

The chemical formulas for the ions and compounds you listed:

Copper (II) ion: Cu²⁺

Bromide ion: Br⁻

Magnesium ion: Mg²⁺

Phosphide ion: P³⁻

Copper (I) Bromide: CuBr

Sulfur Dichloride: SCl₂

Barium Fluoride: BaF₂

Magnesium Phosphate: Mg₃(PO₄)₂

Lithium Permanganate: LiMnO₄

Strontium Sulfite: SrSO₃

Nitrogen Monoxide: NO

Diselenium Tetraoxide: Se₂O₄

Aluminum Sulfide: Al₂S₃

Tin (IV) Iodide: SnI₄

Beryllium Oxide: BeO

Potassium Hydroxide: KOH

Copper (II) ion: Cu²⁺

Copper (II) ion has a charge of 2+ and is represented by Cu²⁺. This means that copper has lost two electrons, resulting in a 2+ charge.

Bromide ion: Br⁻

The bromide ion has a charge of 1- and is represented by Br⁻. This means that bromine has gained one electron, resulting in a 1- charge.

Magnesium ion: Mg²⁺

The magnesium ion has a charge of 2+ and is represented by Mg²⁺. This means that magnesium has lost two electrons, resulting in a 2+ charge.

Phosphide ion: P³⁻

The phosphide ion has a charge of 3- and is represented by P³⁻. This means that phosphorus has gained three electrons, resulting in a 3- charge.

Copper (I) Bromide: CuBr

Copper (I) bromide is a compound formed by combining copper (I) ion (Cu⁺) and bromide ion (Br⁻). The charges of the ions balance each other, resulting in a neutral compound.

Sulfur Dichloride: SCl₂

Sulfur dichloride is a compound consisting of one sulfur atom (S) and two chlorine atoms (Cl). The subscript "2" indicates the presence of two chlorine atoms.

Barium Fluoride: BaF₂

Barium fluoride is a compound composed of one barium ion (Ba²⁺) and two fluoride ions (F⁻). The charges of the ions balance each other, resulting in a neutral compound.

Magnesium Phosphate: Mg₃(PO₄)₂

Magnesium phosphate is a compound consisting of one magnesium ion (Mg²⁺) and two phosphate ions (PO₄³⁻). The charges of the ions balance each other, resulting in a neutral compound. The subscript "3" indicates the presence of three magnesium ions, and the subscript "2" indicates the presence of two phosphate ions.

Lithium Permanganate: LiMnO₄

Lithium permanganate is a compound composed of one lithium ion (Li⁺) and one permanganate ion (MnO₄⁻). The charges of the ions balance each other, resulting in a neutral compound.

Strontium Sulfite: SrSO₃

Strontium sulfite is a compound consisting of one strontium ion (Sr²⁺) and one sulfite ion (SO₃²⁻). The charges of the ions balance each other, resulting in a neutral compound.

Nitrogen Monoxide: NO

Nitrogen monoxide is a compound composed of one nitrogen atom (N) and one oxygen atom (O). Since the compound does not contain ions, it is represented by its elemental symbols.

Diselenium Tetraoxide: Se₂O₄

Diselenium tetraoxide is a compound consisting of two selenium atoms (Se) and four oxygen atoms (O). The prefix "di-" indicates the presence of two selenium atoms.

Aluminum Sulfide: Al₂S₃

Aluminum sulfide is a compound composed of two aluminum ions (Al³⁺) and three sulfide ions (S²⁻). The charges of the ions balance each other, resulting in a neutral compound. The subscript "

2" indicates the presence of two aluminum ions, and the subscript "3" indicates the presence of three sulfide ions.

Tin (IV) Iodide: SnI₄

Tin (IV) iodide is a compound formed by combining tin (IV) ion (Sn⁴⁺) and iodide ion (I⁻). The charges of the ions balance each other, resulting in a neutral compound.

Beryllium Oxide: BeO

Beryllium oxide is a compound composed of one beryllium ion (Be²⁺) and one oxygen ion (O²⁻). The charges of the ions balance each other, resulting in a neutral compound.

Potassium Hydroxide: KOH

Potassium hydroxide is a compound consisting of one potassium ion (K⁺) and one hydroxide ion (OH⁻). The charges of the ions balance each other, resulting in a neutral compound.

For more question on ions click on

https://brainly.com/question/1310794

#SPJ11

The valency of magnesium is 2 because it has two valence electrons in its outermost shell. Magnesium belongs to the second group of the periodic table, which means it has two electrons in its outermost shell or valence shell. In order to achieve a stable configuration, magnesium tends to lose these two valence electrons to form a positively charged ion with a charge of 2+. This makes magnesium a bivalent or divalent element with a valency of 2.

Answer:

Because the outer shell of magnesium contains 2 atoms

Answer:

0.68g/ml

Explanation:

The density of an object is its mass per unit volume. It is calculated using the formula

Density = mass / volume

Mass of stopper weighed = 4.8g

The volume of stopper can be got by subtracting the (volume of water) from the (volume of water+stopper) i.e.

= 39.2ml - 32.1ml

= 7.1ml

Volume of stopper = 7.1ml

Density of stopper= 4.8/7.1

Density= 0.676056

Therefore, the density of the stopper is 0.68g/ml

Answer: The particles are spread apart and can move freely.

The rate of disappearance of Br- is 5 times  of the rate of disappearance of BrO₃⁻. Hence, the disappearance rate of Br- in the reaction is 0.201 M/s .

The rate of a reaction is the rate of disappearance of the reactants or the rate of appearance of the products. The rate of a reaction is directly proportional to the molar concentration of the reactants.

For the given reaction, the rate of reaction can be written in the following terms.

-d/dt [BrO₃⁻] = -1/5 d/dt [Br-] =  -1/6d/dt [H+ ] = +1/3d/dt  [Br²] = + 1/3 d/dt[H₂O]

The minus sign indicates the disappearance and + indicates the formation.

Given, the rate of disappearance of BrO₃⁻ = -d/dt [BrO₃⁻]  = 0.041 M/s.

-d/dt [BrO₃⁻]  = 1/5 d/dt [Br-]

then  d/dt [Br-] = 5 -d/dt [BrO₃⁻]  = 5 × 0.041 M/s = 0.201 M/s.

Therefore, the rate of disappearance of Br- in this reaction is 0.201 M/s.

Find more on reaction rate :

https://brainly.com/question/29261432

#SPJ9

We can see here that the best fuel is the one that produces the most heat per unit mass. In this case, the fuel that produces the most heat per unit mass is methanol.

Fuel is a substance that is used to produce energy through combustion or other chemical reactions. It is commonly utilized to power various forms of transportation, generate heat or electricity, and operate machinery and appliances.

The results of the experiment are shown below:

Fuel            Mass (g)      Heat produced (J)       Heat per gram (J/g)

Methanol 1.0                          350                   350

Ethanol         1.0                          250                   250

Propane         1.0                          200                   200

Butane         1.0                          150                            150

Pentane         1.0                          100                            100

It is important to note that the results of this experiment are only a measure of the heat produced by the fuels.

Learn more about fuel on https://brainly.com/question/10172005

#SPJ1

Answer:

The moon is closer to Earth than the sun! (Last one)

Explanation:

Answer:

molecule. The smallest part of a compound is the molecule. A molecule retains all the properties of that compound.

Explanation:

thanks me later

The combustion of methane can be represented by the equation CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)We are to find the standard enthalpy of combustion of methane.

We are also to create a Hess enthalpy diagram for the reaction. Standard enthalpy of combustion is the amount of energy released when one mole of a substance is completely burned in excess oxygen at standard temperature and pressure. We can use the data in the table to calculate the standard enthalpy of combustion of methane.The table gives us the standard enthalpies of formation of the reactants and products. The standard enthalpy of formation is the amount of energy change that occurs when one mole of a compound is formed from its constituent elements in their standard states (usually at 25°C and 1 atm).We can use the standard enthalpies of formation to calculate the standard enthalpy of combustion of methane. The standard enthalpy of combustion is given by the following equation:ΔH°c = ΣΔH°f(products) – ΣΔH°f(reactants)We can calculate the standard enthalpy of combustion of methane using the standard enthalpies of formation from the table as follows:ΔH°c = [ΔH°f(CO2(g)) + 2ΔH°f(H2O(g))] – [ΔH°f(CH4(g)) + 2ΔH°f(O2(g))]Substituting the values from the table:ΔH°c = [(–393.5 kJ/mol) + 2(–241.8 kJ/mol)] – [(–74.8 kJ/mol) + 2(0 kJ/mol)]ΔH°c = (–890.2 kJ/mol) – (–74.8 kJ/mol)ΔH°c = –815.4 kJ/mol. Therefore, the standard enthalpy of combustion of methane is –815.4 kJ/mol.We can create a Hess enthalpy diagram for the reaction as shown below: The Hess enthalpy diagram is used to show how the standard enthalpy of the reaction can be calculated using the standard enthalpies of formation of the reactants and products. The diagram shows the two steps involved in the reaction. The first step involves the breaking of the bonds in methane and oxygen to form the reactants. The second step involves the formation of the products from the reactants. The standard enthalpy of combustion is the difference between the standard enthalpies of formation of the products and reactants. The Hess enthalpy diagram shows that the same standard enthalpy of combustion can be obtained regardless of the pathway taken to get from reactants to products.

for such more questions on equation

https://brainly.com/question/26694427

#SPJ8

Starting with solid 3-sulfolene and then breaking it down was simpler than doing it with gaseous 1,3-butadiene. Maleic anhydride, a dienophile, reacts with the diene to produce 4-cyclohexene-cis-dicarboxylic anhydride.

A cyclic organic compound with a sulfone functional group is known as sulfolene or butadiene sulfone. It is a crystalline, odorless, white solid that can be stored forever and dissolves in various organic solvents as well as water. The substance is utilized as a butadiene source.

Sulfolane is a common industrial solvent that is used for cleaning natural gas and extracting aromatic hydrocarbons from hydrocarbon mixtures.

Sulfolane, a dipolar aprotic sulfone solvent, is comparable in physicochemical qualities to other dipolar aprotic solvents as DMSO, NMP, DMF, and DMAC. Sulfolane (anhydrous) has the highest freezing point and highest boiling point among the solvents in Table 1 at 28.4 °C.

Thus, solid 3-sulfolene and then breaking it down was simpler than doing it with gaseous 1,3-butadiene.

To learn more about sulfolene, follow the link;

https://brainly.com/question/29854277

#SPJ1

Answer:

Explanation:

Answer:

Yes

Explanation:

I doesn't change the substance or the chemical properties of the substance.

Answer:The reactions are as follows: a carbon-12 (12C) nucleus captures a hydrogen nucleus (1H, a proton) to form a nucleus of nitrogen-13 (13N); a gamma ray (γ) is emitted in the process. The nitrogen-13 nucleus emits a positive electron (positron, e+) and becomes carbon-13 (13C).

Answer:

1.1

0.050*0.005

0.00025

Explanation: