18. which factor does not significantly affect the amount of solar energy reaching the surface of earth?

Answer:

atom

Explanation:

the first guy who gave link this is for you:

we cannot use links in brainly

Thankyou.

Answer: The law of conservation of linear momentum helps to understand the behavior of a Newton's cradle In a closed system. This law is nothing more than action and reaction.it can be used to predict the resulting direction and speed of motion of objects after they collide.

Explanation: Just as an example, when you play pool/8ball, the white play exerts force on the other balls causing them to break away.

hope this helps.

The dot product of velocity vector and acceleration vector at maximum height is equal to zero.

\($\overrightarrow{v}.\overrightarrow{a}= 0\)

We have a football player who kicked a football in order to do a goal.

We have to determine the relationship between the direction of the velocity and acceleration vectors when the football reaches its maximum height.

Projectile motion is the two - dimensional motion of an object thrown or projected into the air such that it moves under the influence of acceleration of gravity.

According to the question -

Assume that the velocity with which the projectile was fired is u m/s.

Therefore, it can be resolved into two components as -

\(\overrightarrow{u} =\) u(x) + u(y) = u cosθ \(a_{x}\) + u sinθ \(a_{y}\).

Now, when the projectile reaches the maximum height, it will no longer cover any vertical height but it will keep moving in the horizontal direction. Therefore - the vertical component of the velocity will become zero. Therefore -

\(\overrightarrow{u} =\) u(x) + u(y) = u cosθ \(a_{x}\) + 0 = u cosθ \(a_{x}\)

Now, refer to the figure attached for reference -

At the maximum height, the velocity vector is in the horizontal direction and the vector for the acceleration due to gravity is vertically downwards.

Therefore - the acceleration vector and velocity vector will have an angle of 90° between them. Assume -

Velocity at maximum height = v = u cosθ \(a_{x}\)

and acceleration = a = g = 9.8 m/\(s^{2}\)

Therefore -

The dot product of velocity vector and acceleration vector is equal to zero.

\(\overrightarrow{v}.\overrightarrow{a}= 0\)

To solve more questions on Projectile motion, visit the link below-

https://brainly.com/question/547813

#SPJ4

The correct option B. opposite the direction of the displacement from equilibrium, is the direction of the restoring force.

Mechanical waves that move through a solid, liquid, or gas with a wave speed that is influenced by the elastic and inertial characteristics of that medium.

Thus, the force that returns an object to its equilibrium position is known as the restoring force; it is denoted by a negative sign since its direction of action is the opposite of that of the displacement.

To know more about the mechanical wave, here

https://brainly.com/question/26116832

#SPJ4

The electric field is equal to zero at a point on the line through the ends of the meter stick located between the two charges, specifically between 0 cm and 50 cm.

To determine the point on the line where the electric field is zero, we can use the principle of superposition. The electric field produced by a point charge is given by Coulomb's law:

\(\[ E = \frac{{k \cdot |q|}}{{r^2}} \]\)

where E is the electric field, k is Coulomb's constant \((\(8.99 \times 10^9 \, \text{N}\cdot\text{m}^2/\text{C}^2\)), \(q\)\) is the charge, and r is the distance from the charge.

Considering the positive charge at the 0.0 cm mark, the electric field it produces points away from it. Similarly, the negative charge at the 50.0 cm mark produces an electric field that points towards it.

Between the two charges, there exists a point where the electric field contributions from both charges cancel out, resulting in a net electric field of zero. This point can be determined by setting the electric field equations for the two charges equal to each other and solving for the position:

\(\[ \frac{{k \cdot |q_1|}}{{r_1^2}} = \frac{{k \cdot |q_2|}}{{r_2^2}} \]\)

Substituting the values \(\(q_1 = 5.00 \, \mu\text{C}\), \(r_1 = 0.00 \, \text{cm}\), \(q_2 = -4.00 \, \mu\text{C}\), and \(r_2 = 50.00 \, \text{cm}\)\), we can solve for the position r of the point where the electric field is zero. The solution will yield a value between 0 cm and 50 cm, indicating the location of the point on the line between the two charges where the electric field is zero.

To learn more about electric field refer:

https://brainly.com/question/28027633

#SPJ11

The Na'vi can communicate over great distances or between many by means of messages that they emit through the earth, the goddess Eywa. Additionally, if F spends days in the dark because she rotates around the earth so in some phases of her rotation the earth covers the sunlight during the day.

To know how the Na'vi communicate, we must watch the Avatar movie to find out the answer. In this case, the indigenous people of Avatar use different forms of communication such as oral or intercom radios that are on their necks. However, the most conventional way is to use Eywa to send messages over long distances.

The dark days on Pandora are due to the fact that this planet rotates around the earth, so on some days, the earth covers the sunlight during the day.

Learn more about Avatar in: https://brainly.com/question/8278536

#SPJ1

It can hear the two speakers' beats because of the frequency of 30 Hz. Consider driving one speaker at 590 Hz and another at 560 Hz.

The quantity of observations that take place during a specific predetermined timeframe is the frequency of the a class interval. Therefore, if 20 individuals between the ages of 5 and 9 are found in the data from our study, the frequency again for 5–9 age range is 20.

The temporal rate of evolution seen in oscillatory & periodic events, such as vibrations, speech recordings (sound), radio frequencies, and light, is specified by the frequency, an essential parameter in science and engineering.

Beat frequency f = f₂ - f₁

F₂ = 590 Hz

F₁ = 560 Hz

f = 590 - 560

f = 30 Hz

To know more about frequency visit:

https://brainly.com/question/17196899

#SPJ4

The potential energy of the book-Earth system relative to the desk when the book is on the shelf is 42.84 Joules. This is calculated by multiplying the mass of the book (2.2 kg).

The acceleration due to gravity (9.8 m/s²), and then multiplying that by the vertical distance the book is lifted (1.3 m).

Potential energy is the energy possessed by an object due to its position or height. It is calculated using the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the vertical distance or height.

In this case, the mass of the book is 2.2 kg, the acceleration due to gravity is 9.8 m/s², and the vertical distance the book is lifted is 1.3 m (the difference between the height of the bookshelf and the desk). Plugging these values into the formula, we get:

\(PE = (2.2 kg) * (9.8 m/s²) * (1.3 m)\)

\(= 42.84 Joules\)

Therefore, the potential energy of the book-Earth system relative to the desk when the book is on the shelf is 42.84 Joules.

learn more about energy here:

https://brainly.com/question/1932868

#SPJ11

The distance between the object and the mirror is 13.96 cm, given to 3 significant figures.

The given data are as follows:Object height, h1= 4.50 cmFocal length of the convex mirror, f = −(5.25a) Magnification, m = 1/(2b)We are supposed to find the distance between the object and the mirror, u using the mirror formula. We can use the formula,1/f = 1/u + 1/vSince the mirror is convex, the focal length f is negative.

Therefore, substituting the values in the formula, we get,1/(-5.25a) = 1/u + 1/v⇒ −0.1905 = 1/u + 1/v…… (1)The magnification of an object is given by,m = −v/u where, m is the magnification, u is the distance of the object from the mirror and v is the distance of the image from the mirror. Substituting the values of m and solving for v, we get,v = m×u= (1/(2b))×u…… (2)

We are now supposed to solve the above equations to find the value of u. To do that, we have to substitute equation (2) into (1). On substituting, we get,−0.1905 = 1/u + 1/[(1/(2b))×u]Simplifying the above equation and cross multiplying, we get,(1/(2b))u − 0.1905u = −1On further simplification and solving for u, we get,u = 13.96 cm…… (3).

Learn more about convex mirror here:

https://brainly.com/question/3627454

#SPJ11

The specific heat of aluminum is approximately 0.093 J/g°C.

To find the specific heat of aluminum, we can use the principle of heat transfer. The heat gained by the water is equal to the heat lost by the aluminum.

First, we calculate the heat lost by the aluminum using the equation:

Qaluminum = m × c × ΔT

Where:

Qaluminum is the heat lost by aluminum

m is the mass of aluminum (100 grams)

c is the specific heat of aluminum (unknown)

ΔT is the change in temperature of aluminum (100°C - 25°C = 75°C)

Qaluminum = 100 g × c × 75°C

Next, we calculate the heat gained by the water using the equation:

Qwater = m × c × ΔT

Where:

Qwater is the heat gained by water

m is the mass of water (109 grams)

c is the specific heat of water (4.18 J/g°C)

ΔT is the change in temperature of water (25°C - 10°C = 15°C)

Qwater = 109 g × 4.18 J/g°C × 15°C

Since the heat gained by water is equal to the heat lost by aluminum, we can set up the equation:

Qaluminum = Qwater

100 g × c × 75°C = 109 g × 4.18 J/g°C × 15°C

Simplifying the equation, we can solve for c:

c = (109 g × 4.18 J/g°C × 15°C) / (100 g × 75°C)

Calculating the value, we find:

c ≈ 0.093 J/g°C

Therefore, the specific heat of aluminum is approximately 0.093 J/g°C.

For more such questions on specific heat

https://brainly.com/question/21406849

#SPJ11

The investigation presented did offer proof in favor of the existence of imperceptible electric force fields.

The force between two charged objects is the electric force, sometimes referred to as the Coulomb force. The interaction of charged particles produces this fundamental force of nature. The magnitudes of the charges on the two objects and the separation between them define the strength of the electric force.

The tape was observed to interact without touching when it was charged by rubbing the tape against one another. The formation of an electric field surrounding the charged tape, which pulls on other nearby charged items, can be used to explain this interaction.

Even though the electric field surrounding the charged tape was not explicitly measured or quantified, the observed interaction between the tape offers a weak indirection for its presence. Hence, the investigation did offer sufficient proof to back up the existence of undetectable electric force fields.

To know more about electric force, visit:

https://brainly.com/question/20935307

#SPJ1

a) To balance the gravitational attraction between Earth and the Moon, the electrostatic force between their net negative charges (-Q) needs to be equal to the gravitational force between them. Mathematically, we can equate these two forces:

k(Q^2/r^2) = G(Mm/r^2),

where k is the electrostatic constant, G is the gravitational constant, M is the mass of Earth, m is the mass of the Moon, and r is the distance between their centers.

Canceling out the common terms and solving for Q, we get:

Q = sqrt(GMm/k).

b) The distance between the Earth and the Moon does not affect the value of Q. The gravitational force and electrostatic force both depend on the distance squared (1/r^2), so as long as the distance remains the same, the value of Q required to balance the forces remains constant.

c) To find the number of electrons needed to produce a net charge of -Q, we need to know the charge of a single electron. The elementary charge, e, is approximately -1.602 x 10^-19 Coulombs. Therefore, the number of electrons required can be calculated as:

Number of electrons = Q/e.

In summary, the value of Q required to balance the gravitational attraction between Earth and the Moon can be calculated using the equation Q = sqrt(GMm/k). The distance between the Earth and the Moon does not affect this value. To determine the number of electrons needed to produce this charge, we divide Q by the charge of a single electron, e.

Learn more about "gravitational attraction " here:

brainly.com/question/29326667

#SPJ11

Answer:

Explanat      Enthalpy of Vaporizationion:

Using the tabulated data and forward difference numerical differentiation, the shear stress distribution in the fluid can be determined.

To calculate the shear stress distribution using forward difference numerical differentiation, we need the velocity data at various points between the plates. However, the given information does not provide any velocity measurements. Without velocity data, it is not possible to determine the shear stress distribution.

If you have the velocity data, please provide it so that I can assist you further in calculating the shear stress distribution using the forward difference numerical differentiation method.

To know more about shear stress distribution click here,

https://brainly.com/question/13034525

#SPJ11

Assuming that the electron-pair geometry of the two ball-and-stick representations is identical, the hybridizаtion of the centrаl аtom is sp².

The hybridization on the central atom would be governed by the type аnd number of electrons involved in the formаtion of the bonds between the centrаl аtoms аnd the outer аtoms.

Electron-pаir geometry determines the spаtiаl аrrаngement of а molecule's bonds аnd lone pаirs. If someone asked what the hybridization on the atom was, we would first draw the Lewis structure. We could then apply VSEPR to the Lewis structure to deduce that the molecular shape was linear and from this, we conclude that the hybridization of the atom is sp.

For more information about the hybridization of the central atom refer to the link:

https://brainly.com/question/28168894

#SPJ4

Capacitance is the ability of an electrical conductor and insulator system to store electric charge when there is a potential difference between the conductors.

Capacitance is 3.54×\(10^{-9}\) F,  energy stored is \(2*10^5NC^{-1}\).charge on each plate is 3.54×\(10^{-6\) C.

a parallel - plate capacitor are 5mm apart and 2m² in area.

potential difference = 1k

d=5×\(10 ^ {-3}\)m,

A=2\(m^2\),

V=1000 volt,

Capacitance,  C=∈\(_0\frac{A}{d}\)

=(8.85×\(10^{-12}\)×2)/5×\(10^{-3}\)

=3.54×\(10^{-9}\) F

charge on each plate , q=CV=3.54×\(10^{-9}\)×1000

=3.54×\(10^{-6\) C

energy stored ,E=σ/∈0

=Q/(A∈0)

=(CV)/(A∈0)

=\(\frac{3.54*10^{-9}*1000}{2*8.85*10^{-12}}\)

=\(2*10^5NC^{-1}\).

Capacitance is 3.54×\(10^{-9}\) F,  energy stored is \(2*10^5NC^{-1}\).charge on each plate is 3.54×\(10^{-6\) C.

To learn more about Capacitance refer,

https://brainly.com/question/27393410

#SPJ1

Answer:

156.28m

Explanation:

Given;

His displacement is 900 m 80° North of west

Let North and South represent y axis and west east represent axis.

the x component of his displacement vector can be written as;

dx = dcosθ

Where d is the resultant displacement = 900m

θ is the angle with the x axis = 80°

Substituting the values;

dx = 900cos80°

dx = 156.2833599002 m

dx = 156.28 m

the x component of his displacement vector is 156.28m

(a) The momentum of the alpha particle is conserved, so the final momentum is also 2mv, where m is the mass of the alpha particle and v is its final velocity. Therefore, we need to find the final velocity. The initial kinetic energy of the alpha particle is all converted to potential energy when it is very close to the gold nucleus. Using conservation of energy, we have:

Initial KE = Final PE + Final KE

(1/2)mv2 = kq1q2/r + (1/2)mv2f

where k is Coulomb's constant, q1 and q2 are the charges on the alpha particle and gold nucleus (2e and 79e, respectively), r is the distance of closest approach, and v2f is the final velocity of the alpha particle after the collision. We can rearrange this equation to solve for v2f:

v2f = sqrt[(mv2)2 + 2kq1q2/mr - (2kq1q2/r)]

Plugging in the values given, we get:

v2f = 2.37 x 106 m/s

So the final momentum is:

p = 2mv2f = 9.48 x 10-22 kg m/s

(b) Since the gold nucleus is initially at rest, the final momentum of the gold nucleus is also equal to the momentum of the alpha particle. Therefore:

p = mv

where m is the mass of the gold nucleus and v is its final velocity. Solving for v, we get:

v = p/m = (2mv2f)/m = 3.39 x 104 m/s

(c) The final kinetic energy of the alpha particle is:

KE = (1/2)mv2f = 5.60 x 10-14 J = 350 keV

(d) The final kinetic energy of the gold nucleus is:

KE = (1/2)mv2 = 1.45 x 10-19 J = 9.03 keV

(e) At the point of closest approach, the potential energy between the alpha particle and gold nucleus is converted entirely into kinetic energy. Therefore, we can equate the potential energy to the initial kinetic energy of the alpha particle:

kq1q2/r = (1/2)mv2i

Plugging in the values given, we get:

r = kq1q2/(mv2i) = 7.09 x 10-15 m

Therefore, the alpha particle will get as close as 7.09 x 10-15 m to the gold nucleus in this head-on collision.

TO KNOW MORE ABOUT The momentum of the alpha particle CLICK THIS LINK -

brainly.com/question/31486301

#SPJ11

A brighter light source will result in a larger voltage drop across the resistor in a circuit with a phototransistor because the increased current flowing through the circuit causes a larger voltage drop according to Ohm's law.

If there is a single resistor in series with a phototransistor, a brighter light source would result in a larger voltage drop across the resistor.

The reason for this is that when the phototransistor is exposed to a brighter light source, more current will flow through the circuit because the phototransistor allows more current to pass through in the presence of a brighter light.

This increased current will cause a larger voltage drop across the resistor because the voltage drop across a resistor is directly proportional to the current flowing through it according to Ohm's law.

Ohm's law states that the voltage drop (V) across a resistor is equal to the current (I) flowing through it multiplied by the resistance (R) of the resistor:

V = IR.

Therefore, if the current through the circuit increases due to the brighter light source, the voltage drop across the resistor will also increase because the resistance of the resistor remains constant.

to know more about phototransistors refer here:

https://brainly.com/question/30322239#

#SPJ11

To find the speed at which the bicycle is traveling, we can use the formula that relates the circumference of the wheel to the distance covered in one revolution. By multiplying the circumference by the number of revolutions per minute, we can determine the speed of the bicycle.

The circumference of a circle can be calculated using the formula C = 2πr, where r is the radius of the circle. In this case, the bicycle wheels have a diameter of 26 inches, so the radius is half of that, which is 13 inches. Converting the diameter to inches, the circumference of each wheel is 2π(13) = 26π inches.

Given that the wheels are rotating at 160 RPM, we can multiply the circumference by the number of revolutions per minute to find the distance covered in one minute. This can be converted to the speed in inches per minute.

To obtain the speed in a more common unit, we can convert inches per minute to miles per hour by using appropriate conversion factors. Finally, rounding the answer to three decimal places provides the speed at which the bicycle is traveling down the road.

Learn more about speed here:

https://brainly.com/question/28224010

#SPJ11

A toy car that is 0.12 m long is used to model the actions of an actual car that is 6 m long. So, The acceleration of the actual car is 1515.15 m/s².

The solution to this question can be achieved through the use of the equation: F = ma Where F is force, m is mass, and a is acceleration.

Step 1: Calculating the mass of the toy car using the ratio of lengths m1/m2 = l1/l2, where m1 and m2 are the masses of the toy car and actual car, and l1 and l2 are their respective lengths.

Rearranging, we have:m1 = (l1/l2)m2 = (0.12 m)/(6 m) m2 = 0.02 m2

Step 2: Using the equation, F = ma, we can determine the mass of the toy car: F = ma2 N = (0.02 m2) a a = 2 N / 0.02 m2 = 100 m/s²

Step 3: Using the same force of 5 N, the acceleration of the actual car can be calculated:F = ma5 N = ma m = m2/l2 m = 0.02 m2 / 6 m = 0.0033 kg a = F/m a = 5 N / 0.0033 kg = 1515.15 m/s²

Therefore, the acceleration of the actual car is 1515.15 m/s².

For more questions on acceleration

https://brainly.com/question/460763

#SPJ8

The probable question may be:

A toy car that is 0.12 m long is used to model the actions of an actual car that is 6 m long. The toy car is pushed with a force of 5 N, causing it to accelerate at a rate of 2 m/s². Assuming the same force is applied to the actual car, calculate the acceleration of the actual car.

Explanation:

DIFFRACTION

Answer:

k = 2

L = 8

M = 18

N = 32

plz mark me as a brainelist

The final image of the coin is located 5.54 cm to the right of the diverging lens and has a magnification of -0.86.

To find the location and magnification of the final image, we need to use the thin lens equation and the magnification equation.

First, we can find the location of the image formed by the converging lens. Using the thin lens equation 1/f = 1/do + 1/di, where f is the focal length, do is the object distance, and di is the image distance, we have:

1/7.50 = 1/12.0 + 1/di

di = 30.0 cm

The image formed by the converging lens is located 30.0 cm to the right of the lens.

Now, we can use the image formed by the converging lens as the object for the diverging lens. The distance between the two lenses is 16.0 cm, so the object distance for the diverging lens is:

do = 16.0 cm - 30.0 cm = -14.0 cm (negative sign indicates that the object is to the left of the lens)

Using the thin lens equation again, this time with f = -5.50 cm, we can find the image distance for the diverging lens:

1/-5.50 = 1/-14.0 + 1/di

di = 5.54 cm

The final image of the coin is formed 5.54 cm to the right of the diverging lens.

To find the magnification of the final image, we can use the magnification equation m = -di/do, where m is the magnification:

m = -5.54 cm / (-14.0 cm) = -0.86

The negative sign of the magnification indicates that the final image is inverted.

To know more about magnification, refer here:

https://brainly.com/question/27872394#

#SPJ11

Answer:

Explanation:

Gain  of kinetic energy + work done by friction = loss of potential energy

= 1 / 2 m ( 25² - 8² ) + work done by friction = m x 9.8 x ( 12 + 12 )

= .5 x 100 x ( 625 - 64 ) + work done by friction = 100 x 9.8 x 24

28050 + work done by friction = 23520

work done by friction = -4530 J

Answer:

2cm/year

Explanation:

20000/10000=2cm/year

During the first 1000 seconds, the heat caused an increase in the temperature of the water sample. This is because the water was being heated and as a result, the energy of the water molecules increased, leading to an increase in temperature.

The heating graph would show a steep increase in temperature during the first 1000 seconds, indicating that the water was rapidly warming up. The exact amount of temperature change would depend on the specifics of the experiment and the heating rate, but it is clear that the heat caused a change in the water sample by increasing its temperature.

Learn more about water molecules

https://brainly.com/question/26529979

#SPJ4

Translated Question;

In Acapulco, a water sample was heated and the temperature of the sample was recorded at different times. A heating graph was constructed where the sample temperature is related to the elapsed time, which is divided into two stages: the first from 0 s to 1000 s, and the second from 1000 s to 2000 s. What change did the heat cause in the water sample during the first 1000 s?