160 mm Determine the magnitude and direction of the anchoring force needed to hold the horizontal elbow and nozzle combination in place. assume the mass of the water and the pipe is 20 kg P1 is gage pressure. Section (2 300 mm ction(1 =100kPa =2m/s

Answers

Answer 1

The anchoring force needed to hold the horizontal elbow and nozzle combination in place is approximately 20,256,133.89 N, directed upward.

How to calculate

We can find the magnitude and direction of the anchoring force needed to hold the horizontal elbow and nozzle combination in place by using the following formula:

F = ma + mg + Fp

where F is the anchoring force needed, m is the mass of the water and the pipe, a is the acceleration, g is the gravitational acceleration, and Fp is the pressure force.Let's plug in the given values:

P1 = 100 kPa = 100,000 Pa

Section(1) = 2 m/s

Section(2) = 300 mm = 0.3 m

First, we need to calculate the pressure force:

Fp = P1A

where A is the area of the nozzle.

Fp = 100,000 * (π/4 * (160 mm)^2)Fp = 1,020,655.89 Pa

Next, we need to calculate the acceleration:

a = (v2 - v1) / t

where t = 1 seconda = (0 - 2) / 1a = -2 m/s^2

Now, we can calculate the anchoring force:

F = ma + mg + Fp

F = 20 * (-2) + 20 * 9.8 + 1,020,655.89

F = 20,256,133.89 N

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Related Questions

Your friend has a rubber band stretched between two fingers. When you pluck the rubber band, it vibrates and makes sound. What would you have to do to make the sound a higher pitch?

To make a higher pitch, stretch the rubber band more.


To make a higher pitch, pluck the rubber band less hard.


To make a higher pitch, stretch the rubber band less.


To make a higher pitch, pluck the rubber band harder.

Answers

Answer:

I think it is   To make a higher pitch, stretch the rubber band more

Explanation:

I'm not too sure. Sry if u got it wrong

Answer:

To make a higher pitch ,pluck the rubber band more

A galaxy has a recession velocity of 12,000 km/s and follows
Hubble’s Law. How far away is the galaxy from Earth?

Answers

The distance of a galaxy from Earth with a recession velocity of 12,000 km/s and follows Hubble's Law is 167.94 Mpc.

What is recession velocity?The recession velocity is the velocity at which objects move away from Earth due to the expansion of the universe. The recession velocity of a galaxy can be calculated using Hubble's Law. In 1929, astronomer Edwin Hubble discovered that galaxies are moving away from us, and that the farther away a galaxy is, the faster it is moving. He formulated this discovery into Hubble's Law.

Hubble's law states that the recession velocity of a galaxy is directly proportional to its distance from Earth.

Recession velocity = Hubble's constant × distance from Earth.

Therefore, the distance from Earth can be calculated using the formula;

Distance from Earth = Recession velocity/Hubble's constant= 12000 km/s/71.9 km/s/Mpc= 166.94 Mpc.

Thus, the galaxy is about 167 Mpc away from Earth.

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What must occur for neutral chargers to occur

Answers

The speed of sound is determined by the temperature and density of the medium through which it travels. Based on the speed data above, which choice below lists the media in order from most to least dense?


A. Wood, water, air

B. Air, water, wood

C. Air, wood, water

D. Wood, air, water

The speed of sound is determined by the temperature and density of the medium through which it travels.

Answers

Answer:

A?

Explanation: put them in order

Sorry if its wrong...

Answer:

It's A

Explanation:

It wants it in order from most dense to least. Wood is most dense so it's first, then water, and then air is last.

The Empire State Building is 1472 ft high. How long would it take an object dropped from the top to reach the ground

Answers

Answer:

Explanation:

Givens

a = 32 feet / second

vi = 0

d = 1472 feet

t = ?

Formula

d = vi*t + 1/2 a t^2

Solution

1472 = 0*t + 1/2 * a * t^2               Multiply both sides by 2

2944 = 32 * t^2                             Divide by 32

2944/32 = t^2                

92 = t^2                                    Take the square root of both sides

sqrt(t^2) = sqrt(92)

t = 9.59 seconds

a circuit is connected to 8 volt battery and it has 2 amperes of current flowing through the wires.What is the resistance of the circuit

Answers

Answer:

4 ohms

Explanation:

Current = Voltage/resistance

2 = 8/R

2R = 8

R = 4

Consider a double Atwood machine constructed as follows: A mass 4m is suspended from a string that passes over a massless pulley on frictionless bearings. The other end of this string supports a second similar pulley, over which passes a second string supporting a mass of 3m at one end and m at the other. Using two suitable generalized coordinates, set up the Lagrangian and use the Lagrange equations to find the acceleration of the mass 4m when the system is released. Explain why the top pulley rotates even though it carries equal weights on each side.​

Answers

Can you apply the picture to the problem for us

would this be Newtons 1st, 2nd, or 3rd law​

would this be Newtons 1st, 2nd, or 3rd law

Answers

Answer:

Newton's First Law of Motion.

Explanation:

Newton's First Law of Motion states that a body continues its state of motion untill and unless an external force acts on it. Here, the truck moves forward even after the breaks are applied in order to maintain its State of motion.

______is when different species live in close association.

Answers

Answer:

Symbiosis

Explanation:

When you have a symbiotic relationship,  it is between two or more organisms of different species.

during which of piaget's stages of sensorimotor development does adaptation first occur?

Answers

According to Piaget's theory of cognitive development, adaptation first occurs during the sensorimotor stage, specifically in the substage called the "circular reactions" stage.

This stage occurs between the ages of 8 to 12 months. During this period, infants engage in repetitive actions to explore and interact with their environment.

They begin to adapt their behaviors based on the responses they receive from their actions. The circular reactions involve repetitive behaviors that serve a purpose, such as shaking a rattle to hear the sound.

Through these actions, infants start to develop a basic understanding of cause and effect relationships and adapt their behaviors to achieve desired outcomes.

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Bijan wanted to find the density of a piece of metal. He weighed it. Them he measured its volume by placing it in measuring cylinder which was half-full of water. Here are his measurements: Mass of metal - 196.0 g, reading on measuring cylinder (water only) = 45 cm3 and reading on measuring cylinder (water + metal) = 68 cm3. What is the density of the piece of metal?

Answers

density equals mass over volume. density= 196/(68-45)
density=4.4 g/cm3

If Argon's melting point is -309 degrees then what is its freezing point?

Answers

The melting point of a substance is the temperature at which the substance changes its phase from solid to liquid.

The freezing point is the temperature at which the substance changes its phase from liquid to solid.

The melting point of a substance is the same as the freezing point. That is when the temperature of the substance in the liquid form is increased continuously, the temperature at which the substance turns into a solid is equal to the temperature at which the substance will turn into liquid from solid if the temperature is decreased continuously, from a higher temperature.

What is the potential difference between two points when a 65 C charge requires 250 J to move between the points?

Answers

Answer:

3.85 V

Explanation:

The potential difference between two points can be calculated using the following equation

\(V=\frac{E}{Q}\)

Where E is the energy and Q is the charge. So, replacing E = 250 J and Q = 65 C, we get:

\(V=\frac{250J}{65C}=3.85\text{ V}\)

Therefore, the potential difference is 3.85 V

How is Newton’s Third Law important for snowboarding?

Answers

The starting of a snowboarder's motion is explained by Newton's third law of motion.

According to this law, every action has an equal and opposite reaction. Thus, forces always operate in pairs.

The first object exerts force, which is the person's foot pushing against the ground. The snowboarder then experiences a pushback from the ground as a result of the equal and opposite reaction force on the foot. The ground's reaction propels the person forward. Always of equal magnitude to the action force, the response force acts in the opposite direction.

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1. A uniform magnetic field is directed vertically upwards. In which direction in this field should an alpha particle be projected so that it is deflected south ward? Name and state the rule you have used to find the direction in this case.

Answers

Answer:

1. Fleming's left hand rule

2. It must be projected towards the east

Explanation:

Fleming's left-hand rule states that; When a current-carrying conductor is placed in an external magnetic field, the conductor experiences a force perpendicular to both the field and to the direction of the current flow. This rule was first put forward by John Ambrose Fleming in the later part of the nineteenth century.

Hence if the thumb, fore finger and middle finger of the lefthand are held mutually at right angles to each other; the thumb shows the direction of motion, the fore finger shows the direction of the field while the middle finger shows the direction of the current.

Hence, if the alpha particle is projected eastwards(at right angles) to the uniform magnetic field, it will be deflected southwards in the magnetic field.

A physics student stands on a cliff overlooking a lake and decides to throw a softball to her friends in the water below. She throws the softball with a velocity of 23.5 m/s at an angle of 39.5∘ above the horizontal. When the softball leaves her hand, it is 11.5 m above the water. How far does the softball travel horizontally before it hits the water? Neglect any effects of air resistance when calculating the answer.

Answers

Answer:

66.86m

Explanation:

Velocity of ball thrown, u = 23.5 m/s

Initial height of the ball above the water, H = 11.5 m

Angle of projection, θ = 39.5°

Vertical components of veloclty = usinθ

Horizontal components of veloclty = ucosθ

The soft ball hits the water after time 't'

Considering the second equation of motion

S = ut + 1/2at^2........ 1

But since the ball went through motion under gravity ( free fall ) rather than linear motion, then equation 1 can be rewritten as:

H = ut +/- 1/2gt^2

H = - 11.5m

U = usinθ

θ = 39.5°

a = -g = -9.8m/s^2

- 11.5m = 23.5(sin39.5°)t + 1/2(-9.8)t^2

-11.5m = 23.5(0.6360)t - 4.9t^2

-11.5m = 14.946t - 4.9t^2

4.9t^2 -14.946t-11.5m = 0

Since the ball drifted horizontally

D = (Ucosθ)t

Where θ = 39.5°

U = 23.5m/s t=

Alternatively,

horizontal component of the velocity is 23.5 cos 39.5º = 18.1331 m/s

now how long does it take the ball to raise to a peak and fall to the water.

vertical component of velocity = 23.5 sin 39.5º = 14.947m/s

time to reach peak t = v/g = 11.947/9.8 = 1.5252 sec

peak reached above cliff top is

h = ½gt² = ½(9.8)(1.5252)²

= ½×22.797

= 11.3985m

now the ball has to fall 11.3985+ 11.5 = 22.8985m

time to fall from that height is

t = √(2h/g) = √(2• 22.8986/9.8) = 2.1617 sec

add up the two times to get time it is in the air, 2.1617 + 1.5252 = 3.6869

now haw far does the ball travel horizontally in that time

d = vt = 18.1331 ×3.6869= 66.856m

= 66.86m

Which quantity is measured in newton seconds

Answers

The newton-second (also newton second; symbol: N⋅s or N s) is the derived SI unit of impulse. It is dimensionally equivalent to the momentum unit kilogram-metre per second (kg⋅m/s). One newton-second corresponds to a one-newton force applied for one second.

which four items were invented for moving and working in space This is astrology but it didn't give me an option to put that as the subject.

Answers

Answer: Innovations originally designed for space vehicles, including artificial muscle systems, robotic sensors, diamond-joint coatings, and temper foam,

Explanation: make artificial human limbs more functional, durable, comfortable, and life-like.

(a) What is the energy in joules of an x-ray photon with wavelength 3.30 ✕ 10−10 m?
J

(b) Convert the energy to electron volts.
keV

(c) If more penetrating x-rays are desired, should the wavelength be increased or decreased?

increaseddecreased



(d) Should the frequency be increased or decreased?

increaseddecreased

Answers

(a) the energy in joules of an x-ray photon with wavelength 3.30 ✕ 10−10 m is 6.03 x 10^-16 J.

(b) Convert the energy to electron volts = 3.75 keV

(c) If more penetrating x-rays are desired, should the wavelength be increased or decreased?  decreased

(d) Should the frequency be increased or decreased?   increased

(a) The energy in joules of an x-ray photon with wavelength of 3.30 x 10^-10 m can be calculated using the Planck's equation:

Planck's equation is given by:

E = hf

Where, E = Energy of a photon in Joules h = Planck's constant f = Frequency of the electromagnetic radiation λ = Wavelength of the electromagnetic radiation

Since the question provides the wavelength, we need to calculate the frequency of the electromagnetic radiation.

h = 6.626 x 10^-34 Js, and λ = 3.30 x 10^-10 m

Thus, f = c/λ, where c is the speed of light and is given by c = 3.0 x 10^8 m/s.

Therefore, f = 3 x 10^8/3.30 x 10^-10 = 9.09 x 10^17 Hz

Now, we can calculate the energy of the x-ray photon using Planck's equation.

E = hf = 6.626 x 10^-34 J s × 9.09 × 10^17 Hz= 6.03 x 10^-16 J

Therefore, the energy of the x-ray photon is 6.03 x 10^-16 J.

(b) The energy can be converted to electron volts using the equation:

1 eV = 1.602 x 10^-19 J

Thus, 6.03 x 10^-16 J = 6.03 x 10^-16 / (1.602 x 10^-19) eV = 3753 eV ≈ 3.75 keV

Therefore, the energy of the x-ray photon is approximately 3.75 keV.

(c) If more penetrating x-rays are desired, the wavelength should be decreased. This is because the energy of the x-ray photon is inversely proportional to the wavelength. As the wavelength decreases, the energy of the x-ray photon increases. This means that shorter wavelength x-rays are more energetic and can penetrate more deeply into materials.

(d) The frequency should be increased. This is because the energy of the x-ray photon is directly proportional to the frequency. As the frequency increases, the energy of the x-ray photon increases. Therefore, x-rays with higher frequencies are more energetic and can penetrate more deeply into materials.

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what is the half-life of lithium-8 if the decay constant is 0.825/s? what is the half-life of lithium-8 if the decay constant is 0.825/s? A. 0.572s B. 2.42s
C. 1.19s
D. 0.840s

Answers

0.840s is the half-life of lithium-8 if the decay constant is 0.825/s. The decay constant is unique to each radioactive substance and measures the speed of radioactive decay. Therefore, the correct answer is option D.

The half-life of lithium-8 can be calculated using the formula:

\(t1/2 = ln(2) / \lambda\)

Where t1/2 is the half-life, ln is the natural logarithm, and λ is the decay constant. Substituting the given decay constant of 0.825/s into the formula:

t1/2 = ln(2) / 0.825/s

t1/2 ≈ 0.840s

Therefore, the half-life of lithium-8 is approximately 0.840s. The formula for half-life is a fundamental concept in nuclear physics, which determines the time required for a radioactive substance to decay by half of its original quantity. The decay constant, which is specific to each radioactive substance, measures the rate at which radioactive decay occurs.

The higher the decay constant, the shorter the half-life, indicating that the substance is more unstable and decays faster. In this case, the decay constant of lithium-8 is 0.825/s, indicating that it is relatively unstable and has a short half-life of approximately 0.840s.

In summary, the half-life of lithium-8 is approximately 0.840s with a decay constant of 0.825/s. Therefore, the correct answer is option D.

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El Sol radia energía electromagnética a un tasa de P = 3. 85×1026 W. A) ¿A qué distancia del Sol la intensidad disminuye hasta 1000 W/m2

Answers

Sabiendo la tasa de energía electromagnética que el sol radi, la distancia a la cual la intensidad disminuye a 1000 W/m² es de 6.96×10¹⁰ m metros o 69.6 millones de kilómetros.

La intensidad de la energía electromagnética emitida por el Sol disminuye a medida que se aleja del Sol. Esta disminución está dada por la ley del cuadrado inverso, que establece que la intensidad es inversamente proporcional al cuadrado de la distancia desde la fuente.

La intensidad de la energía electromagnética se puede calcular mediante la siguiente fórmula:
I = P / 4πr²

Donde I es la intensidad, P es la potencia del Sol, y r es la distancia desde el Sol.

Si queremos encontrar la distancia a la cual la intensidad disminuye a 1000 W/m², podemos despejar r de la fórmula y sustituir los valores conocidos:
1000 = 3.85×10²⁶ / 4πr²
r² = 3.85×10²⁶ / (1000 × 4π)
r = √(3.85×10²⁶ / (1000 × 4π))
r = 6.96×10¹⁰ m

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a resistance r and a 3.2 h inductance are in series across a 60-hz ac voltage. the voltage across the resistor is 29 v and the voltage across the inductor is 33 v. assume that all voltages in this problem are rms voltages. (a) what is the resistance r?

Answers

The Resistance r is 56.97 ohms

To solve this problem, we can use Ohm's Law and the equation for the voltage across an inductor in an AC circuit.

First, let's find the current in the circuit. We know that the voltage across the series combination of the resistor and inductor is the sum of the voltage across the resistor (29 V) and the voltage across the inductor (33 V):

V_total = V_R + V_L
V_total = IR + IXL
where I is the current in the circuit, X_L is the inductive reactance (which depends on the frequency and inductance of the inductor), and R is the resistance.

Since the circuit is operating at a frequency of 60 Hz and the inductance is 3.2 H, we can find the inductive reactance using the formula:

X_L = 2πfL
X_L = 2π(60)(3.2)
X_L ≈ 120.96 Ω

Now we can solve the current:

V_total = IR + IXL
62 = I(R + 120.96)
I ≈ 0.509 A

Next, we can use Ohm's Law to solve for the resistance:

V_R = IR
29 = (0.509)R
R ≈ 56.97 Ω

Therefore, the resistance in the circuit is approximately 56.97 ohms.

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A crowbar having the length of 1.75 m is used to balance a load of 500 N If the distance between the fulcrum and the load is 0.5 calculate MA and VR and efficiency

Answers

load distance*l=effort distance*e

o.5*500=x*1.25

250/1.25=x

200=x

ma=load/effort

500/200

2.5

vr=ed/ld

1.25/0.5

2.5

effciency=ma/vr*100

100%

At what altitude does 1% of the mass of the atmosphere lies above and 99% of the mass lies below? Assume that the global mean surface pressure is about 1000hPa, and the scale height H is 8km. State your assumptions.

Answers

At 0.0804 km altitude the 1% of the mass of the atmosphere lies above and 99% of the mass lies below. Assumptions made are the global mean surface pressure of 1000 hPa is a representative value and the scale height is assumed to be constant throughout the entire atmosphere.

First, we need to calculate the pressure at the desired percentiles (1% and 99%) relative to the surface pressure.

For 1% of the mass lying above, we consider the pressure to be 1% of the surface pressure:

1% of 1000 hPa = 0.01 × 1000 hPa

= 10 hPa.

For 99% of the mass lying below, we consider the pressure to be 99% of the surface pressure:

99% of 1000 hPa = 0.99 × 1000 hPa

= 990 hPa.

Next, we use the exponential relationship between pressure and altitude:

P = P0 × exp(-z/H),

where P is the pressure at a given altitude, P0 is the surface pressure, z is the altitude, and H is the scale height.

To find the altitude z at which the pressure is equal to 10 hPa (1% of the surface pressure), we rearrange the equation:

10 hPa = 1000 hPa × exp(-z/H).

Taking the natural logarithm (ln) of both sides, we have:

ln(10 hPa / 1000 hPa) = -z / H.

ln(0.01) = -z / 8 km.

z = -8 km × ln(0.01).

Evaluating the expression:

z = -8 km × (-4.605)

= 36.84 km.

Therefore, 1% of the mass of the atmosphere lies above an altitude of approximately 36.84 km.

Similarly, to find the altitude z at which the pressure is equal to 990 hPa (99% of the surface pressure), we follow the same procedure:

990 hPa = 1000 hPa × exp(-z/H).

ln(990 hPa / 1000 hPa) = -z / H.

ln(0.99) = -z / 8 km.

z = -8 km × ln(0.99).

Evaluating the expression:

z = -8 km × (-0.01005)

= 0.0804 km.

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A 100 N force causes an object to accelerate at 2 m/s2. What is the mass of the
object?

Answers

Answer:

50 kg

Explanation:

Given,

Force ( F ) = 100 N

Acceleration ( a ) = 2 m/s^2

To find : Mass ( m ) = ?

Formula : -

F = ma

m = F / a

= 100 / 2

m = 50 kg

Therefore, the mass of the object is 50 kg.

What is the formula for velocity???

Answers

Explanation:

divide the distance by the time it takes to travel that same distance, then add your direction to it.

Or change in displacement divided by change in time.

the sun tends to bloat outward by nuclear fusion, and contract due to

Answers

The Sun's outward bloating is driven by nuclear fusion, while its contraction is due to the force of gravity. The balance between these forces maintains the Sun's size and shape, ensuring its stability over billions of years.

The sun is a dynamic and complex celestial body that undergoes constant change and evolution. One of the main processes that affects the sun's size and shape is nuclear fusion. This process involves the merging of atomic nuclei to form heavier elements, releasing a tremendous amount of energy in the process. As the sun undergoes fusion, it tends to bloat outward, expanding in size and becoming less dense. However, this expansion is not infinite, as the gravitational force of the sun's mass ultimately pulls it back together. In fact, the sun also undergoes a process of contraction, as gravity causes it to compress and become more dense. This cycle of expansion and contraction is essential for the sun's stability, as it helps maintain a delicate balance between the forces of nuclear fusion and gravity.

The sun's size and shape are influenced by the opposing forces of nuclear fusion and gravity. While fusion causes the sun to bloat outward, gravity pulls it back together and causes it to contract. This cycle of expansion and contraction is a crucial factor in the sun's overall stability and longevity. The Sun tends to bloat outward due to nuclear fusion and contract due to gravity. In the core of the Sun, nuclear fusion occurs, converting hydrogen into helium. This process releases a tremendous amount of energy in the form of light and heat, which creates an outward pressure that counteracts the force of gravity.

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A 5 kg object oscillates with simple harmonic motion. Its position as a function of time varies according to the following equation x(t) = 2 sin(( π/2)t + ( π/6))
At what time (in seconds) after t = 0 seconds is the kinetic energy first at a maximum?

Answers

The kinetic energy is first at a maximum after approximately 3.67 seconds after t=0.

To determine the time when the kinetic energy is first at a maximum, we need to find the time at which the velocity of the object is at a maximum. The kinetic energy of an object undergoing simple harmonic motion is maximum when the velocity is maximum.

The equation for velocity as a function of time in simple harmonic motion is given by:

v(t) = Aω cos(ωt + φ)

where A is the amplitude, ω is the angular frequency, t is time, and φ is the phase constant.

In this case, the equation for position is x(t) = 2 sin((π/2)t + (π/6)), which is in the form x(t) = A sin(ωt + φ).

Comparing the two equations, we can see that ω = π/2.

The velocity equation becomes:

v(t) = (π/2)A cos((π/2)t + φ)

To find the time at which the velocity is maximum, we need to find when the cosine term is at its maximum value of 1. This occurs when (π/2)t + φ = 0 or (π/2)t + φ = 2π.

Solving for t, we get:

(π/2)t = -φ or (π/2)t = 2π - φ

t = (-2φ/π) or t = (4π - 2φ)/π

Since the phase constant φ in the given equation is π/6, we substitute this value into the equations:

t = (-2(π/6)/π) or t = (4π - 2(π/6))/π

t = -1/3 or t = 11/3

Therefore, the kinetic energy is first at a maximum at t = 11/3 seconds.

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Help thank you...............

Help thank you...............

Answers

Answer:

do explain what u need help with?

A boulder with a mass of 2,500 kg resting on a ledge 200 m above the ground falls. If the boulder’s ME is conserved, what is the speed of the boulder just before it hits the ground?

Answers

Answer:

nitial GPE = final KE 2500*10*200 = ½ 2500*v^2 v^2 = 2*10*200 v= 63.24 m/sec

Explanation:

Other Questions
Write these phrases in pass compos. Then, translate them into English (make sure its in past tense.) 1. Est-ce quil meurt? A. Au pass compos: B. En anglais: 2. Quand nais-tu? A. Au pass compos: B. En anglais: Select the word in the sentence that is not used correctly:The nurse's notes in the medical record indicate the patients pain was severe.A. PatientsB. Nurse'sC. NotesD. Was QUESTION 5 Which is not the characteristic of a succesful entrepreneur ? O Self-confident Risk averse O Visionary Creative 1) in what ways russia's invasion of ukraine has affected global business and multinational enterprises so far? 6.2 Simplify the following: -x(2x+5) 2 #p ? 1 Vx 24 V 4KQ2 VX 3 a) Find the thevenin equivalent circuit between the terminals a,b of the above circuit. b) If a load resistance is connected between the terminals a,b what should be its value, in order to transfer maximum amount of power to the load? c) How much is the maximum power that can be transferred from the circuit to the load? +1 0.2 Determine parameters for the Taylor Tool Life model (C, n) that fit the two data points below for a given tool material cutting mild steel. (hint: you are determining the unique set of parameters (C, n) that fit a the log-log straight line between the following 2 points). life of 3.4 minutes at a speed of 250 ft/min life of 53 minutes at speed of 100 ft/min What were Sons of Liberty?a) A secret group who traveled to England to talk with the King.b) A secret group that found interesting ways to oppose the British.c) A secret group who fought battles against the British without the support of the colonist.d) A secret group who drafted the Declaration of Independence. Determine whether the relation (1,2), (2,1), (3,6), (4,13), (5,22) is a function. Explain. yo querra ms.correct or incorrect Help me please i need the lenght of yz . . . . . . . . . .. . . . . . . which category of preoperative medication has an effect on the vagus nerve? Development of Version 2.0 of a particular accounting softwareproduct is being considered by Jose Noguera's technology firm inBaton Rouge. The activities necessary for the completion of thisproject Please answer this :):(:) George and Peter.........been playing soccer is it have or has Draw an arrow diagram and give the range of function:b) f: {0, 1}2 {0, 1}3. For each x {0, 1}2, f(x) = x0.c) f: {0, 1}2 {0, 1}2. For each x {0, 1}2, f(x) is obtained by swapping the two bits in x. For example, f(01)=10 consider the sequence whose terms are this sequence can be described by the following formulas. which of these formulas are its recursive form and which is it's closed form? a) , for which one of these is correct? and how do I find out? The price of a television is $245. The sales tax rate is 8%. What is the amount of sales tax? 6.22(b). Consider the cell; Pt / H (g, P) / HCl (aq) / AgCl(s)/ Ag(s) for which the cell reaction is: 2 AgCl (s) +H (g) 2 Ag(s) + HCl (aq) At 25C and a molarity of HCl of 0.010 -