15. When objects are moved further apart from each other, the force of
gravity between them

The density of the oil when the water and oil are mixed is 661kg/m³.

From the information illustrated, water and then oil are poured into a U-shaped tube, open at both ends and they then come to equilibrium.

It was stated that suppose that H = 25.7 cm and h = 8.72 cm. It should be noted that the pressure ends at the one of the opening is the atmospheric pressure, therefore the gauge pressure will be:

∆P = pgh

This will be illustrated as:

(0.257)P = (1000) × (0.257 - 0.0872)

0.257P = 169.8

Divide

P = 169.8 / 0.257

P = 661kg/m³

The density is 661kg/m³.

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a. the speed of the ultrasound in water is 1480 m/s

b. the wavelength of the ultrasound in water is 37 m

c. the depth of the fish below the boat is 89.76 m

a.

v = fλ

v = fλ = (4.0 x 10^2 Hz)(λ)

the speed of the ultrasound in water is given as :

v = v_water = 1480 m/s

substitute v_water into the equation above and solve for λ:

λ = v_water / f = (1480 m/s) / (4.0 x 10^2 Hz) = 37 m

Therefore,  the speed of the ultrasound in water is 1480 m/s and the wavelength is 37 m.

c. The depth of the fish below the boat ia found using,

d = v_water * t / 2

The first echo came back after 0.09 s:

d = (1480 m/s) * (0.09 s) / 2 = 64.32 m

This is the depth of the sea bed, which is already known to be 64 m. So the fish must be deeper than the sea bed, and the second echo must have come from the fish. The second echo came back after 0.12 s:

d = (1480 m/s) * (0.12 s) / 2 = 89.76 m

So the depth of the fish below the boat is 89.76 m

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At the apex of the trajectory, the ball's velocity and acceleration are u (10i+15j) m/s and zero

The initial velocity of the ball is u (10i+15j) m/s.

Velocity at the top of the trajectory: Since the ball is thrown with an initial velocity, it will reach the top of its trajectory with the same velocity, since there is no air resistance. Therefore, the velocity of the ball at the top of the trajectory is u (10i+15j) m/s.

Acceleration: The acceleration of the ball at the top of the trajectory is zero, since the ball is not accelerating (there is no acceleration due to air resistance).

Therefore, the velocity and acceleration of the ball at the top of the trajectory are u (10i+15j) m/s and zero, respectively.

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A series circuit's characteristics are The voltage is divided among all devices in the circuit, The same amount of current flows through all devices in the circuit, There is only one path for current to follow through the circuit, and If one device in the circuit stops allowing current to flow, all other devices in the circuit will also stop functioning.

Single Wire moves down, loop rotates left.

A single-wire system is a method of transmitting power or signals using only a single conductor. This is in contrast to the usual use of a pair of wires to provide a complete circuit, or an electrical cable containing (at least) two conductors for this purpose.

A single-wire transmission line is not the same as a single-wire earth return system. This is beyond the scope of this article. The latter system relies on reverse current flow through earth, using earth as a second conductor between earth terminal electrodes. A single-wire transmission line does not have a second conductor of any kind. 

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A heat engine is in violation of the second rule of thermodynamics if it claims to have a thermal efficiency higher than the Carnot efficiency.

Energy is characterized as having the "ability to accomplish work, which is the capacity to apply a force sufficient to move an object." Despite this unclear definition, the concept is essentially quite straightforward: electricity merely refers to the force that drives objects. Potential and kinetic energy are the two different categories.

The ability to perform work is the most basic definition of energy. Things alter and move because of energy. It comes in many different shapes and is all around us. Cooking food requires energy.

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Answer:

The car C has KE = 100, PE = 0

Explanation:

The principle of conservation of energy states that although energy can be transformed from one form to another, the total energy of the given system remains unchanged.

The energy that a body possesses due to its motion or position is known as mechanical energy. There are two kinds of mechanical energy: kinetic energy, KE and potential energy, PE.

Kinetic energy is the energy that a body possesses due to its motion.

Potential energy is the energy a body possesses due to its position.

From the principle of conservation of energy, kinetic energy can be transformed into potential energy and vice versa, but in all cases the energy is conserved or constant.

In the diagram above, the cars at various positions of rest or motion are transforming the various forms of mechanical energy, but the total energy is conserved at every point. At the point A, energy is all potential, at B, it is partly potential partly kinetic energy, However, at the point C, all the potential energy has been converted to kinetic energy. At D, some of the kinetic energy has been converted to potential energy as the car climbs up the hill.

Therefore, the car C has KE = 100, PE = 0

Answer:

T=F/A

Explanation:

T= shear stress

F=applied force

A=cross sectional area

shear stress, force tending to cause deformation of material by slippage along a plane or planes parallel to the imposed stress, the resultant shear is of a great importance in nature, being intimately related to the downslope movement of earth materials and earthquakes.

Answer:

A: 0.83 Hz

Explanation:

Frequency can be calculated in a multitude of ways. The one way that is going to help you solve this problem is (# of times/seconds)

so you would divide 85 swings/102 seconds

= 5/6 or 0.8333 Hz

so your answer is A

The magnetic force per unit length of the wire is (C) (0.49i - 0.51j - 1.37k) N/m.

To calculate the magnetic force per unit length of the wire, we can use the formula:

F = I * (L x B),

where F is the force, I is the current, L is the length vector of the wire, and B is the magnetic field.

Given:

Current, I = 3A

Length vector, L = √√3 * (i + j + k)

Magnetic field, B = 0.75i + 0.4k

Let's calculate the cross product of L and B:

L x B = | i j k |

|√√3 √√3 √√3|

|0.75 0 0.4|

To evaluate this cross product, we calculate the determinants:

(i) component: (√√3 * 0 - √√3 * 0.4) = -0.4√√3

(j) component: (-√√3 * 0.75 - √√3 * 0) = -0.75√√3

(k) component: (√√3 * 0.75 - √√3 * 0) = 0.75√√3

Now, multiply the cross product by the current:

F = 3A * (-0.4√√3i - 0.75√√3j + 0.75√√3k)

Simplifying this expression gives:

F = (-1.2√√3i - 2.25√√3j + 2.25√√3k) N

Therefore, the magnetic force per unit length of the wire is approximately (-1.2√√3i - 2.25√√3j + 2.25√√3k) N/m.

Comparing the given answer options, the closest match is C. (0.49i - 0.51j - 1.37k) N/m.

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Answer:

A stunt person jumps from the roof of a tall building, but no injury occurs because the person lands on a large, air-filled bag. Which one of the following best describes why no injury occurs?

The bag increases the amount of time during which the momentum is changing and reduces the average force on the person.

ANSWER: A

Answer:

A. The bag increases the amount of time during which the momentum is changing and reduces the average force on the person.

During stunts, people usually put an-air filled bag on the ground for safe landing and to prevent injuries.

Momentum is calculated by m* v where m is for mass and v is for velocity.

Force is directly proportional to momentum

F∝M

The bag in this scenario helps to increases the amount of time the force acts on the person. This implication means that there is a reduction in the change of momentum. Since Force and momentum have a directly proportional relationship then the Force taken to hit the floor is greatly reduced.

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a class b network needs to be subnetted such that it supports 100 subnets and 100 hosts/subnet. which of the following answers list a workable combination for the number of network, subnet, and host bits

A Class B network has a default subnet mask of 255.255.0.0 and provides 16 bits for the network portion and 16 bits for the host portion. To support 100 subnets and 100 hosts/subnet, we need to borrow some of the host bits for subnetting.

To determine the number of bits needed for the subnet portion, we can use the formula:

\(2^{n}\)> = number of subnets

where n is the number of subnet bits. Solving for n, we get:

n = ceil(log2(number of subnets))

For 100 subnets, we need at least 7 subnet bits:

n = ceil(log2(100)) = ceil(6.643) = 7

To determine the number of bits needed for the host portion, we can use the formula:

\(2^{n}\) >= number of hosts per subnet - 2

where n is the number of host bits. We subtract 2 from the number of hosts per subnet because the first and last IP addresses in each subnet are reserved (network address and broadcast address).

For 100 hosts per subnet, we need at least 7 host bits:

n = ceil(log2(100 - 2)) = ceil(log2(98)) = ceil(6.624) = 7

So, the minimum number of bits we need for subnetting and host addressing is 7 bits each.

We can use the remaining 2 bits for the network portion, giving us a total of 9 network bits (16 - 7).

Therefore, a workable combination would be:

9 network bits

7 subnet bits

7 host bits

This would give us a total of 512 (\(2^{9}\)) network addresses, 128 (\(2^{7}\)) subnets per network, and 126 (2^7A Class B network has a default subnet mask of 255.255.0.0 and provides 16 bits for the network portion and 16 bits for the host portion. To support 100 subnets and 100 hosts/subnet, we need to borrow some of the host bits for subnetting.

To determine the number of bits needed for the subnet portion, we can use the formula:

\(2^{n}\) >= number of subnets

where n is the number of subnet bits. Solving for n, we get:

n = ceil(log2(number of subnets))

For 100 subnets, we need at least 7 subnet bits:

n = ceil(log2(100)) = ceil(6.643) = 7

To determine the number of bits needed for the host portion, we can use the formula:

\(2^{n}\) >= number of hosts per subnet - 2

where n is the number of host bits. We subtract 2 from the number of hosts per subnet because the first and last IP addresses in each subnet are reserved (network address and broadcast address).

For 100 hosts per subnet, we need at least 7 host bits:

n = ceil(log2(100 - 2)) = ceil(log2(98)) = ceil(6.624) = 7

So, the minimum number of bits we need for subnetting and host addressing is 7 bits each.

We can use the remaining 2 bits for the network portion, giving us a total of 9 network bits (16 - 7).

Therefore, a workable combination would be:

9 network bits

7 subnet bits

7 host bits

This would give us a total of 512 (\(2^{9}\)) network addresses, 128 (\(2^{7}\)) subnets per network, and 126 (\(2^{7}\)- 2) host addresses per subnet.

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A.  The motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.

B. The speed of this motor as a function of the field resistance RF is approximately 1086 r/min

A. According to the magnetization curve shown in Figure 8-9, the motor's speed can be calculated by using the following equation:

EA = kϕN, where EA is the back EMF, k is a constant, ϕ is the magnetic flux, and N is the motor speed.

Since the amount of armature current remains constant, the back EMF is also constant.

Therefore, the magnetic flux must also be constant. The magnetic flux is proportional to the field current IF, which can be calculated using Ohm's law:

IF = (250 V - EA)/(RF + R₁)

At the initial field resistance of 41.67 Ω, the field current is IF = (250 V - EA)/(41.67 Ω + 0.03 Ω) = (250 V - EA)/41.70 Ω.

If the field resistance is raised to 50 Ω, then the new field current is IF = (250 V - EA)/(50 Ω + 0.03 Ω) = (250 V - EA)/50.03 Ω.

Since the magnetic flux is constant, we can set the two expressions for IF equal to each other and solve for N:

kϕN/IF1 = kϕN/IF2

N = (IF2/IF1)N1 = (250 V - EA)/(50.03 Ω + 0.03 Ω) * 1103 r/min ≈ 1086 r/min

Therefore, the motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.

B. The speed of the motor as a function of the field resistance RF can be plotted using the same equation used in part A:

N = (250 V - EA)/(RF + R₁ + Radj) * 1103 r/min

where Radj is the resistance of any additional resistance in the circuit. Since the load current is constant, the current through the motor is also constant, so EA is also constant.

Therefore, the speed is inversely proportional to the total resistance in the circuit, which includes the field resistance RF, armature resistance R₁, and any additional resistance Radj.

A plot of the speed as a function of the field resistance is shown in Figure 8-10. As the field resistance increases, the speed of the motor decreases due to the increased total resistance in the circuit. This relationship is linear for this type of constant-current load.

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Answer:

24>0y

Explanation:

Answer:

The ratio of the new potential energy to the potential energy before the insertion of the dielectric is 0.58

Explanation:

Given that,

Length of plates = 8 cm

Width = 5.52 cm

Distance = 1.99 cm

Dielectric constant = 2.6

Length = 4.4 cm

Potential = 0.8 V

We need to calculate the initial capacitance

Using formula of capacitance

\(C=\dfrac{\epsilon_{0}A}{d}\)

Put the value into the formula

\(C=\dfrac{8.85\times10^{-12}\times8\times5.52\times10^{-4}}{1.99\times10^{-2}}\)

\(C=1.96\times10^{-12}\)

We need to calculate the final capacitance

Using formula of capacitance

\(C'=\dfrac{\epsilon_{0}A_{1}}{d}+\dfrac{k\epsilon_{0}A_{2}}{d}\)

Put the value into the formula

\(C'=(\dfrac{8.85\times10^{-12}}{1.99\times10^{-2}})((4.4\times5.52)+(3.6\times5.52)2.6)\times10^{-4}\)

\(C'=3.37\times10^{-12}\)

We need to calculate the  ratio of the new potential energy to the potential energy before the insertion of the dielectric

Using formula of energy

\(\dfrac{E}{E'}=\dfrac{\dfrac{1}{2}CV^2}{\dfrac{1}{2}C'V^2}\)

Put the value into the formula

\(\dfrac{E}{E'}=\dfrac{1.96\times10^{-12}}{3.37\times10^{-12}}\)

\(\dfrac{E}{E'}=0.58\)

Hence, The ratio of the new potential energy to the potential energy before the insertion of the dielectric is 0.58

The atom that has been shown is an atom of carbon(C).

We know that in an atom is the smallest particle of a substance that can be able to take part in a chemical reaction. In this case, we have a an atom that have been shown. As expected, the protons that are in the atom have been shown as the circle that is in the innermost part of the image.

The electrons are found around the shells of the atom. The electrons that are in the shells of the atom must be equal to the number of protons that are in the atom of the element.

Given that the number of electrons must be equal to the number of protons and the number of protons gives us the identity of the element that have been shown in the image, we can conclude that this is an atom of carbon.

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Answer:Magnetic fields from two sources add up as vectors at each point, so the strength of the field is not necessarily the sum of the strengths1. Magnetic fields are vectors, which means they have direction as well as size. Therefore, the sum of two magnetic fields is not simply the sum of their magnitudes2.

Explanation:

Answer:

3 seconds

Explanation:

  initial velocity = 0ms

  final velocity = 24ms

  time(1) = 3s

  acceleration = ?

  time (2) =?

 solution:-

                          to find acceleration,

                 a =( vf - vi ) / t

                    = 24-0 /3

                    = 24/ 3

                 a= 8ms^-2

                          To find time(2)

                 t= (vf - vi )/ a

                   = 24- 0 / 8

                   = 24/ 8

                   = 3seconds

Answer:

B: Energy that is transformed is neither created or destroyed

Explanation:

Answer:

R (total) = 14 Ω

V1 = 68,58 V

V2 = 68,58 V

V3 = 51,42 V

I (total) ≈ 8,57 A

I1 ≈ 4,29 A

I2 = 4,28 A

I3 ≈ 8,57 A

Explanation:

Given:

R1 and R2 are connected in parallel

R3 with (R1 and R2) are connected in series

V (total) = 120,0 V

R1 = 16,0 Ω

R2 = 16,0 Ω

R3 = 6,0 Ω

R (total) = R1 + R2 + R3

First, let's find the resistance in (R1 and R2) part

Since R1 = R2, we can use this formula:

R = R1/n (n is the number of resistors, in this case it's 2)

R = 16/2 = 8 Ω

Now, we add this number to R3 and we'll get the total resistance in this circuit:

R (total) = 8 + 6 = 14 Ω

I (total) = V (total) / R (total)

I (total) = 120/14 ≈ 8,57 A

I3 = I ≈ 8,57 A, since it's connected in series with the current source

V3 = I3 × R3

V3 = 8,57 × 6 = 51,42 V

V1 = V2 = V (total) - V3, since it's a parallel connection

V1 = V2 = 120 - 51,42 = 68,58 V

I1 = V1/R1

I1 = 68,58/16 ≈ 4,29 A

I2 = I (total) - I1

I2 = 8,57 - 4,29 = 4,28 A

I hope I did everything correct

The weight of the human body is distributed across a wider region due to an opposing force acting in opposition to it.

In science, the word "force" has a precise definition. At this level, the phrases "push" and "pull" are entirely suitable to describe forces. A force is not something that exists inside or within an object. A force acts on the first thing from another. A force can be thought of as consisting of both living and non-living things.

The term "force" refers to the tendency of a body to modify to change its state as a result of an outside factor. Additionally, a force applied to the body might cause it to alter in size, shape, and direction. Like kicking a ball, opening and closing doors, or kneading dough, for instance.

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According to Chargaff's rule, the amounts of adenine (A), thymine (T), and guanine (G) in the DNA molecule are equal to each other. The amounts of cytosine (C) and guanine (G) are also equal.

Erwin Chargaff was a biochemist, author, Bucovinian Jew who immigrated to America during the Nazi era, and professor of biochemistry at Columbia University's medical school.

Chargaff found patterns among the four bases, or chemical building blocks, of DNA, which are directly related to DNA's function as the genetic material of living things.

He was born in Austria-Hungary. Heraclitean Fire: Sketches from a Life Before Nature, an autobiography he penned, received positive reviews.

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The radius of the Sun is approximately 654497.9 kilometers.

A subtended angle in geometry is an angle created by a common point (in this case, the Earth) that crosses two points of a nearby circular arc (the Sun in this case). Below is a visual illustration of the subtended angle.

The law of cosine can be used to calculate the sun's radius, which is 654497.950 kilometers in kilometers.

The Sun's radius is nearly 109 times bigger than the Earth's. The Earth's radius is 6378 kilometers. Or to put it another way, both dimensions are 1: 109 ratios.

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Newton's Second Law.

We have the following data, provided in the exercise:

Mass (m) = ?

Force (F) = 13607 N

Acceleration (a) = 2.9 m/s²

To calculate the mass, we solve the following formula:

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{F=m*a \ \ < ====Formula \ clear==== > \ \frac{F}{a}=\frac{m*\not{a}}{\not{a}} } \end{gathered}$}}\)\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{\frac{F}{a}=m \ \iff \ Address \ is \ changed \Rightarrow \ m=\frac{F}{a} } \end{gathered}$}}\)

We substitute the data in the clear formula.

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{m=\frac{13607 \ N}{2.9 \ \frac{m}{s^{2} } } } \end{gathered}$} }\)

We break down the units of Newton = Kg * m/s².

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{m=\frac{13607 \ Kg*\not{\frac{m}{s^{2}} } }{2.9 \not{\frac{m}{s^{2}} } } } \end{gathered}$} }\)

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{m=4692.07 \ Kg } \end{gathered}$} }\)

(a) The magnitude of the car's normal force is 7,792.2 N.

(b) The mass of the car is 795.1 kg.

The weight of the car is calculated by applying Newton's second law of motion as shown below.

Mathematically, the formula for Newton's second law of motion is given as;

Ff = μW

where;

The weight of the car is calculated as follows;

W = Ff / μ

W = ( 6,000 N ) / ( 0.77 )

W = 7,792.2 N

Based on Newton's third law of motion, the weight of the car acting downwards is equal to normal force on the car, acting upward.

The mass of the car is calculated as follows;

W = mg

where;

m = W / g

m = ( 7792.2 ) / (9.8)

m = 795.1 kg

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Explanation

A longitudinalwave is in which the particles of the medium vibrate in the direction of the line of advance of the wave.Longitudinal waves cause the medium to move parallel to the direction of the wave.

A longitudinal wave can be set up for example in a streched spring by compressing the coils in a small region, and releasing the compressed region,

the back and forth motions of the coils of the spring is in the same direction that the wave travels

so, in a longitudinal wave there is not Vertical movement, so the answer is

C. Vertical

Answer:

This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.

The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.

The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).

The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:

R(n) = √(X² + Y²)

Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.

However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:

<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2

<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2

Because <X²> = <Y²>, we can write:

<R²> = <X²> + <Y²> = n A²

So, the root mean square distance (the square root of the mean square displacement) after n steps is:

R(n) = √(<R²>) = √(n) * A

Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.