1/5 of 45 is what number?

The true statement is that (b) The limit \(\lim_{x \to 0} f(x)\) does not exist because there is an open circle at (0, 4).

From the graph of the function (see attachment), we have the following highlight:

There is an open circle at point (0,4), the maximum point of the function f(x) and when x = 0

When there is an open circle in the graph at x = 0, then the function has no limit at this point

This is so because the value is exclusive of the function values

Hence, the limit \(\lim_{x \to 0} f(x)\) does not exist because there is an open circle at (0, 4).

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Answer:

C - The limit Limit of f (x) as x approaches 0 = 4 because both the left-hand and right-hand limits equal 4.

Step-by-step explanation:

Precalc Edge 2023

Answer:

y = 5x - 3, so M = 5 and C = -3.

Answer: X is equal to either 0 or -42

Step-by-step explanation:

The correct answer is C. $11,250.

To calculate the interest on a 90-day, 9% note for $50,000, we can use the simple interest formula:

Interest = Principal × Rate × Time

Given:

Principal (P) = $50,000

Rate (R) = 9% = 0.09 (decimal)

Time (T) = 90 days

Since the interest is calculated based on a 360-day year, we need to convert the time in days to a fraction of a year:

Time (T) = 90 days / 360 days = 0.25 (fraction of a year)

Now we can calculate the interest:

Interest = $50,000 × 0.09 × 0.25

Interest = $11,250

Rounded to the nearest dollar, the interest on the 90-day, 9% note for $50,000 is $11,250.

Therefore, the correct answer is C. $11,250.

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Answer:

-3

Step-by-step explanation:

Slope = Rise/Run

We can find the amount between 7 and -5 as 12, and -2 and 2 as 4.

Then we can do rise/run and 12/4

Which would divide into 3.

ANd because we can see the x increases as the y decreases, we can find that it's a negative slope.

-3

Answer:

C) 352 cm^2

Step-by-step explanation:

\(We\ are\ given\ that\ ,\\Volume\ of\ the\ cylindrical\ vessel = 448\pi\ cm^3\\Height\ of\ the\ cylindrical\ vessel =7 cm\\\\We\ know\ that,\\Volume\ of\ a\ cylinder=\pi r^2h\\Hence,\\\pi r^2h=448\pi \\Substituting\ 7\ instead\ of\ h,\ we\ get,\\\pi r^2*7=448\pi \\Canceling\ \pi \ on\ both\ the\ sides\ we\ have,\\r^2*7=448\\r^2=448/7\\r^2=64\\r=8\)

\(We\ now\ know\ that\ ,\\Radius\ of\ cylindrical\ vessel\ = 8\\Height\ of\ the\ cylindrical\ vessel\ =7\\\\Hence,\\CSA\ of\ a\ cylinder\ = 2\pi rh\\CSA\ of\ the\ cylindrical\ vessel = 2*\pi *7*8\\Approxiamating\ the\ value\ of\ \pi\ as\ \frac{22}{7} ,\\CSA\ of\ the\ cylindrical\ vessel = 2*\ \frac{22}{7} *7*8\\=2*22*8\\=352\ cm^2\)

The vertical stress increment at your location, 13 feet below grade and 9 feet off center of the concentrated load, due to the structural load is approximately 3,282 lb/ft². This information helps in understanding the stress distribution and its impact on the soil and nearby structures.

To calculate the vertical stress increment at your location due to the structural load, we need to consider the weight of the soil, the weight of the water table, and the weight of the concentrated load.

The total vertical stress at your location can be calculated as follows:

p_total = p_soil + p_water + p_load

1. Vertical Stress from Soil:

The vertical stress from the soil is given by the equation:

p_soil = γ_soil * z

Where:

- γ_soil is the unit weight of the soil (128 lb/ft³)

- z is the depth below grade (13 ft)

Substituting the given values:

p_soil = 128 lb/ft³ * 13 ft = 1,664 lb/ft²

2. Vertical Stress from Water:

The vertical stress from the water table can be calculated as follows:

p_water = γ_water * z_water

Where:

- γ_water is the unit weight of water (62.4 lb/ft³)

- z_water is the depth to the water table (6 ft)

Substituting the given values:

p_water = 62.4 lb/ft³ * 6 ft = 374.4 lb/ft²

3. Vertical Stress from Concentrated Load:

The vertical stress from the concentrated load can be calculated as follows:

p_load = P / A

Where:

- P is the concentrated load (460 tons)

- A is the area over which the load is distributed (considering a circular area with a radius of 9 ft)

Converting the concentrated load to pounds:

P = 460 tons * 2,000 lb/ton = 920,000 lb

Calculating the area of the circular load:

A = π * r²

A = 3.14 * (9 ft)² = 254.34 ft²

Substituting the values:

p_load = 920,000 lb / 254.34 ft² ≈ 3,618.39 lb/ft²

Therefore, the vertical stress increment at your location due to the structural load is approximately:

p = p_total - p_soil - p_water

p = 3,618.39 lb/ft² - 1,664 lb/ft² - 374.4 lb/ft²

p ≈ 3,282 lb/ft²

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When a scientific team uses special equipment to measures the pressure under water and finds it to be 159 pounds per square foot, the depth is around 70 feet.

It's important to note that pressure increases as depth increases under water. The pressure in pounds per square foot, P, at a depth of d feet is given by the equation:

P = 0.433d + 14.7 where 0.433 is a constant for water, and 14.7 is the pressure at the surface.

In order to find the depth at which the pressure is 159 pounds per square foot, we need to solve the equation for

d.P = 0.433d + 14.7

Substitute P = 159 and solve for

d.159 = 0.433d + 14.7

Subtract 14.7 from both sides.

144.3 = 0.433d

Divide both sides by 0.433 to isolate d.

d ≈ 333.06

Hence, when a scientific team uses special equipment to measures the pressure under water and finds it to be 159 pounds per square foot, the depth is around 70 feet.

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Answer:

x = 4

Step-by-step explanation:

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS. PEMDAS is the order of operation, and stands for:

Parenthesis

Exponents (& Roots)

Multiplication

Division

Addition

Subtraction

First, subtract 4 from both sides of the equation:

-6x + 4 (-4) = -20 (-4)

-6x = -20 - 4

-6x = -24

Next, divide -6 from both sides of the equation:

(-6x)/-6 = (-24)/-6

x = (-24)/(-6)

x = 4

x = 4 is your answer.

~

Answer:

-4

Step-by-step explanation:

-6x+4=-20

-6x+24 (add like variables)

-4 (divide by -6)

Answer:

49x

Step-by-step explanation:

Answer:

-49x

Step-by-step explanation:

-11 2/3x (-4 1/5)

= -49x

Answer:

860.3

Step-by-step explanation:

43·π·5.93≈860.28954in³

860.28954 = 860.3

The volume of the sphere is V = 859.9 inches³

A sphere is symmetrical, round in shape. It is a three dimensional solid, that has all its surface points at equal distances from the center. It has surface area and volume based on its radius. It does not have any faces, corners or edges.

The Surface Area of a Sphere = 4πr²

The Volume of a Sphere = ( 4/3 ) πr³

where r is the radius of the sphere

Given data ,

Let the radius of the sphere be r = 5.9 inches

Now , Volume of a Sphere = ( 4/3 ) πr³

On simplifying , we get

V = ( 4/3 ) ( 3.14 ) ( 5.9 )³

V = 859.853 inches³

Hence , the sphere has volume of 859.9 inches³

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Answer:

actually its c

Step-by-step explanation:

looked it up

my bad :(

Answer:

-1.177 x 10^27

Step-by-step explanation:

Hence, the solution of the system of linear equations is;(x, y, z) = (1/3, -1, -8/3)

To convert the system to an augmented matrix and reduce it to echelon form, we will be following the steps below;Consider the given system of linear equations;

x + 3y − 2z = −4,

2x + y + z = 3,3x − y + z = 2T

he augmented matrix for the given system is; \[\left[\begin{matrix}1&3&-2&-4\\2&1&1&3\\3&-1&1&2\end{matrix}\right]\]

To reduce the augmented matrix to echelon form, we will be using the Gaussian elimination method;Performing row operations: -2R1+R2=> R2,-3R1+R3=> R3.

\[\left[\begin{matrix}1&3&-2&-4\\0&-5&5&11\\0&-10&7&14\end{matrix}\right]\]Now, performing row operation, -2R2+R3=> R3. \[\left[\begin{matrix}1&3&-2&-4\\0&-5&5&11\\0&0&-3&8\end{matrix}\right]\]

We now have the matrix in echelon form.The matrix is consistent since there is no row where we have all zeroes except the last column.

The last equation of the augmented matrix is -3z = 8.The solution of z = -8/3 is substituted into the second equation;

-5y + 5 (-8/3) = 11 => y = -1.

The solution of y = -1 and z = -8/3 is substituted into the first equation to obtain the value of x;

x + 3(-1) - 2(-8/3) = -4 => x = 1/3.

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The three roots of 125i are:

To find these roots, we can use de Moivre's identity. The de Moivre's identity states that for any complex number z and any integer n, we have:

\(z^n\) = (r * e^{iθ})^n = r^n * e^{inθ}

where r is the absolute value of z and θ is the angle of z.

In our case, we have z = 125i and n = 3. So, we have:

\(z^3\) = \((125i)^3 = (5 * i)^3 = 125i^3\)

Using de Moivre's identity, we can write this as:

\(125i^3\) = 5^3 * e^{3iθ} = 125 * e^{i(3π/2)} = -125i

Therefore, the three roots of 125i are the three cube roots of -125i. We can find these roots using the following formula:

z = r * e^{iθ/3}

where r is the cube root of 125 and θ is the angle of -125i.

The cube root of 125 is 5.

The angle of -125i is π/2.

So, the three roots of 125i are:

\(z_1\) = 5 * e^{iπ/6} = 5(12+i√32)

\(z_2\) = 5 * e^{i5π/6} = -5

\(z_3\) = 5 * e^{i9π/6} = 5(12-i√32)

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Answer:

Option B.

Step-by-step explanation:

The given table is

                          Meat              Not meat         Total

Seafood               16                      31                  47

Not seafood        20                      5                  25

Total                     36                    36                  72

From the given table it is clear that:

Seafood-Meat = 16

Not seafood-Meat = 20

Seafood-not meat = 31

Not seafood- not meat = 5

Total = 72

We need to find the joint relative frequency for mall visitors who like seafood and meat.

Joint relative frequency \(=\dfrac{\text{who like seafood and meat}}{\text{Total}}\)

Joint relative frequency \(=\dfrac{16}{72}\)

Therefore, the correct option is B.

Answer:

The Answer On Edge Is B.), Have Fun Dreamers!

Step-by-step explanation:

Answer:

16 ft

Step-by-step explanation:

Because h = √20² - (24/2)² = √400-144 = √256 = 16

hope this is helpful!

Answer:

B) -34

Step-by-step explanation:

6x - 4

x = -5

6(-5) -4 = -30 - 4 = -34

The probability that the concentration of the insecticide dieldrin is greater than 356 ng/g is 0.3745 (approx).

Given that the concentration of the insecticide dieldrin in all male minke whales is N(340 ng/g, 50 ng/g).

Here, μ = 340 and σ = 50. The concentration is measured in nanograms per gram of blubber.

Now, we have to find the probability that the concentration of the insecticide dieldrin is greater than 356 ng/g.

To calculate the probability of P(X > 356), standardize the random variable X using the formula z = (X - μ) / σ.

Here, X = 356.

So, z = (X - μ) / σ= (356 - 340) / 50= 0.32

Now, the probability P(X > 356) is equivalent to P(Z > 0.32) using the standard normal distribution table.

To find this probability, we need to subtract the standard normal table value of 0.6255 from 1.

Note: N(μ, σ) represents a normal distribution with mean μ and standard deviation σ.

Therefore,

P(X > 356) = P(Z > 0.32) = 1 - 0.6255= 0.3745 (approx)

Hence, the probability that the concentration of the insecticide dieldrin is greater than 356 ng/g is 0.3745 (approx).

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Answer:

red

Step-by-step explanation:

big red

Answer:

ijrrrrrrrrrrrrg to 19399

Step-by-step explanation:

Answer:

Its a because volume is equal to length times width time height and that answ choice is the only one that provides this correct statement

$0.54 x 2.6 =$1.404  

$1.28 x 3.1=$3.968  

$1.404 rounds to $1.40

$3.968 rounds to $4

$4 = $ 1.40 = $5.40  

:)

Answer:

$12.84

Step-by-step explanation:

to solve this you will just have to multiply the given prices by the three pounds and then add up all the fruits:

0.54 x 3 = 1.62

2.19 x 3= 6.57

1.55 x 3= 4.65

1.62 + 6.57 + 4.65 = 12.84

Given the initial expression sin(θ) + cos(θ) * cos(θ) * (1 - cos(θ)), we simplified it to sin(θ) + cos²(θ) - cos³(θ).

Given the expression:
sin(θ) + cos(θ) * cos(θ) * (1 - cos(θ))
Let's simplify this expression step by step:
1. First, recognize that cos(θ) * cos(θ) can be written as cos²(θ). So, the expression becomes:
sin(θ) + cos²(θ) * (1 - cos(θ))
2. Next, we'll distribute cos²(θ) to both terms inside the parentheses:
sin(θ) + cos²(θ) - cos³(θ)
At this point, we have simplified the expression as much as possible. The final expression is:
sin(θ) + cos²(θ) - cos³(θ)
In summary, given the initial expression sin(θ) + cos(θ) * cos(θ) * (1 - cos(θ)), we simplified it to sin(θ) + cos²(θ) - cos³(θ). Remember that this is a general expression and its specific value depends on the angle θ.

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Answer:

Angle 1 = 115 degrees

Angle 2 = 65 degrees

Step-by-step explanation:

Angle 1: Same-side interior angle of Line 1

Angle 2: Same-side interior angle of Line 2

We know that the difference between the angles is 50 degrees. Since the angles are supplementary, we can write the equation:

Angle 1 + Angle 2 = 180

Now, we need to express the difference between the angles in terms of Angle 1 or Angle 2. We can choose either angle, so let's express it in terms of Angle 1:

Angle 1 - Angle 2 = 50

We can rewrite this equation as:

Angle 1 = 50 + Angle 2

Now substitute this expression for Angle 1 into the first equation:

(50 + Angle 2) + Angle 2 = 180

Combine like terms:

2Angle 2 + 50 = 180

Subtract 50 from both sides:

2Angle 2 = 130

Divide by 2:

Angle 2 = 65

Now substitute this value back into the equation for Angle 1:

Angle 1 = 50 + Angle 2

Angle 1 = 50 + 65

Angle 1 = 115

Therefore, the angles are as follows:

Angle 1 = 115 degrees

Angle 2 = 65 degrees

Answer: 267.947 (or 267.95) inches^3

Step-by-step explanation:

The formula for the volume of a sphere is \(\frac{4}{3}\pi r^{3}\).

To find your radius (r), divide the diameter of 8 inches by 2. The radius is 4 inches.

Plug in your numbers to the volume equation to get \(\frac{4}{3} (3.14)(4^3)\). The first step is to cube 4 (4*4*4) to get 64. Now your equation is \(\frac{4}{3}(3.14)(64)\).

Multiply 3.14 and 64 to get 200.96. The equation is now \(\frac{4}{3}(200.96)\) or \(\frac{4}{3} * \frac{200.96}{1}\).

Multiply the numerators (4 * 200.96) and denominators (1 * 3) to get a final equation of \(\frac{803.84}{3}\).

Finally, divide 803.84 by 3 to get the final answer of 267.947 in^3.

Answer:

\(4 \sqrt{5} \)

☽------------❀-------------☾

Hi there!

~

\(4\sqrt{5}\)

⇒Using the law of radicals

\(\sqrt{a}\) × \(\sqrt{b}\) ⇔ \(\sqrt{ab}\)

⇒ \(\sqrt{80}\)

⇒ \(\sqrt{16} \times 5\)   \(= \sqrt{16}\) × \(\sqrt{5}\) \(= 4\sqrt{5}\)

❀Hope this helped you!❀

☽------------❀-------------☾

The equipment acquired at the beginning of the year had a value of $7,620.

⇒ Debit: Cash/Bank Account = $59,200

   Debit: Accumulated Depreciation = $26,140

   Debit/Credit: (Gain) or Loss on Sale of Equipment = $6,920 (if gain) or        ($6,920) (if loss)

   Credit: Equipment = $78,420

At the beginning of the year, equipment with a value of $7,620 was acquired. The equipment's cost was $78,420, and it was depreciated using the straight-line method over an estimated useful life of 6 years with an estimated residual value.

a. To calculate the depreciation expense for the first year, we need to determine the annual depreciation amount. The formula for straight-line depreciation is:

Annual Depreciation Expense = (Cost - Residual Value) / Useful Life

Given that the cost is $78,420, the estimated residual value is not provided in the question, so we assume it to be $0, and the useful life is 6 years, we can calculate the annual depreciation expense as follows:

Annual Depreciation Expense = ($78,420 - $0) / 6 = $13,070

Therefore, the depreciation expense for the first year is $13,070.

b. To determine the gain or loss on the sale of the equipment at the end of the second year, we need to compare the selling price with the equipment's book value. The book value can be calculated as follows:

Book Value = Cost - Accumulated Depreciation

Given that the cost is $78,420 and the depreciation expense for the first year is $13,070, we can calculate the accumulated depreciation for the first year:

Accumulated Depreciation (Year 1) = Depreciation Expense (Year 1) = $13,070

The accumulated depreciation for the second year would be twice the first-year depreciation expense:

Accumulated Depreciation (Year 2) = 2 * Depreciation Expense (Year 1) = 2 * $13,070 = $26,140

Now we can calculate the book value at the end of the second year:

Book Value (Year 2) = Cost - Accumulated Depreciation (Year 2) = $78,420 - $26,140 = $52,280

Given that the equipment was sold for $59,200, we can determine the gain or loss on the sale:

Gain or Loss = Selling Price - Book Value = $59,200 - $52,280 = $6,920

Therefore, there is a gain of $6,920 on the sale of the equipment.

c. Journal entry to record the sale:

Debit: Cash/Bank Account = $59,200

Debit: Accumulated Depreciation = $26,140

Debit/Credit: (Gain) or Loss on Sale of Equipment = $6,920 (if gain) or ($6,920) (if loss)

Credit: Equipment = $78,420

The journal entry debits the cash/bank account for the selling price, debits the accumulated depreciation to remove the accumulated depreciation up to the sale date, credits the gain or loss on the sale of equipment, and credits the equipment account to remove the equipment from the books.

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