14) Which is true about the polarity of the substances in the graph?a. All are polar b. All are nonpolar c. Some are polar, some are nonpolar d. Unable to answer with info provided

Answer:

This movement releases energy and generates seismic waves that can be recorded by specialized instruments used by scientists. The point on a fault at which the first movement or break occurs during an earthquake is called the earthquake's hypocenter

Explanation:

The percent of water in the unknown sample is calculated as 57.3%.

Process of providing energy that is required to initiate a combustion process is called ignition.

mass of crucible + cover + unknown sample = 36.65 g

mass of crucible + cover = 34.12 g

mass of unknown sample = (36.65 g - 34.12 g) = 2.53 g

mass of water lost during ignition:

mass of unknown sample (before ignition) = 2.53 g

mass of unknown sample (after 1st weighing) = 35.67 g - 34.12 g = 1.55 g

mass of unknown sample (after 2nd weighing) = 35.23 g - 34.12 g = 1.11 g

mass of unknown sample (after 3rd weighing) = 35.20 g - 34.12 g = 1.08 g

total mass of water lost during ignition = (2.53 g - 1.08 g) = 1.45 g

As % water in unknown sample = (mass of water lost / mass of unknown sample) x 100%

= (1.45 g / 2.53 g) x 100%

% water in unknown sample = 57.3%

Therefore,  percent of water in the unknown sample is 57.3%.

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A brewed black tea generally has 81.30 milligrams of TA per 100 mL of water (which is to say it is at equilibrium). If a tea bag is steeped in 150. mL of water, 54.2 is the concentration of TA at equilibrium.

A substance's concentration is the amount of solute present in a given amount of solution. Molarity is the number of moles of solute in one liter of solution and is used to express concentrations.

Given:

M₁ = 81.30 milligrams

M₂ = ?

V₁ = 100ml

V₂ = 150ml

M₁V₁ = M₂V₂

By substituting given values in this equation and we get,

81.30 × 100 = M₂ × 150

M₂ = 81.30 × 100 / 150

= 54.2

Thus,  54.2 is the concentration of TA at equilibrium.

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Answer:

C = 67%

O = 22%

H = 11%

Explanation:

Given C = 12, O = 16, H = 1

C8 = 8(12) = 96

O2 = 2(16) = 32

H16 = 16(1) = 16

Total molar mass = 96 + 32 + 16 = 144

% of C = 96/144 = 0.67 = 67%

% of O = 32/144 = 0.22 = 22%

% of H = 16/144 = 0.11 = 11%

When a 200°C iron bar is placed in thermal contact with a 30°C block of wood, energy leaves the iron bar and enters the wood until the temperatures are equal.

Law of conservation of energy states that the energy cannot be lost or formed but it can only be transformed from one form to another.

According to the given question, the block of wood is at a lower temperature than an iron bar. Hence, heat will flow from the iron bar to the block of wood until the temperatures of both are equal.

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The first step we have to follow to answer this question is to convert the mass of Fe2O3 to moles using its molecular mass:

According to its formula, each kmol of Fe2O3 contains 2 kmol of Fe. Use this information to find the amount of moles of iron:

Use the molecular mass of iron to find the mass of iron that can be recovered from the Fe2O3:

It means that 446.76kg of iron can be recovered.

Answer:

2 is correct

Explanation:

My friend for you this answer

Answer:

18 L

Explanation:

boyles law

P1V1 = P2V2

V2 = P1V1/P2

V2 = (.9 * 4)/.2

V2 = 18

This question is based on Boyle's law as temperature is constant. Boyle's law is derived from ideal gas equation only at constant temperature. Therefore, the new pressure is  18L.

Boyle's law is a law which states that at constant temperature, the pressure that is exerted by an ideal gas on the walls of the container is inversely proportional to the volume occupied that gas.

Ideal gas is a gas where there is no forces of attraction or forces of repulsion between the particles . The volume of container is equal to the volume occupied by the gas.

Mathematically, Boyle's law can be written as

P₁V₁ = P₂V₂

P₁=initial pressure

P₂=final pressure

V₁ = initial volume

V₂=final pressure

V₂ = P₁V₁/P₂

V₂ = (0.9 × 4)/0.2

V₂  = 18L

Therefore, the new volume is  18L.

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First, we need to write out the balanced chemical equation for the reaction: 4 KO2 + 2 CO2 → 2 K2CO3 + 3 O2

From the equation, we can see that 4 moles of KO2 react with 2 moles of CO2 to produce 3 moles of O2. Therefore, we need to convert the given masses of KO2 and CO2 into moles:

moles of KO2 = 2.61 g / molar mass of KO2 = 2.61 g / 71.10 g/mol = 0.0367 mol
moles of CO2 = 4.46 g / molar mass of CO2 = 4.46 g / 44.01 g/mol = 0.1013 mol

Next, we need to determine the limiting reagent (the reactant that will be completely consumed in the reaction) by comparing the mole ratios of KO2 and CO2 in the balanced equation. The ratio of moles of KO2 to moles of CO2 is:
0.0367 mol KO2 / 4 mol KO2 per 2 mol CO2 = 0.0184 mol CO2

Since this ratio is less than the actual number of moles of CO2 we have (0.1013 mol), CO2 is in excess and KO2 is the limiting reagent.

Using the mole ratio from the balanced equation, we can calculate the number of moles of O2 produced:

moles of O2 = 3 mol O2 per 4 mol KO2 × 0.0367 mol KO2 = 0.0275 mol O2

Finally, we can convert the moles of O2 to grams:

mass of O2 = moles of O2 × molar mass of O2 = 0.0275 mol × 32.00 g/mol = 0.88 g
Therefore, 2.61 g of KO2 and 4.46 g of CO2 would produce 0.88 g of O2.

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The pH would decrease very little if a small amount of acid is added.

The pH scale determines how acidic or basic water is. The range is 0 to 14, with 7 representing neutrality. Acidity is indicated by pH values below 7, whereas baseness is shown by pH values above 7. In reality, pH is a measurement of the proportion of free hydrogen and hydroxyl ions in water.

You need to know the hydronium ion concentration in moles per litre to determine the pH of an aqueous solution (molarity). The equation pH = - log [H3O+] is then used to determine the pH. Example: In a 0.0025 M HCl solution, determine the pH. Strong and entirely ionised in water, HCl is an acid.

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Answer:

Correct option is

D

1 g of B(s)

Larger is the number of moles, larger is the number of molecules.

As molar mass of B is lowest (=11 g), it will have larger number of moles. Hence, its 1 g will have highest number of molecules and moles.

Answer:d

Explanation:

The change in the boiling point of a solution always depends on the solute.

The boiling point is the temperature at which the vapor pressure of a liquid is equal to the external pressure experienced by the liquid. A liquid in a vacuum will have a lower boiling point than if it were under atmospheric pressure.

A solution has a higher boiling point than the pure solvent. This is because the solution must reach a temperature where the boiling pure solvent (eg water 100°C) must also exceed the boiling point of thore solute. So the boiling point of a solution depends on the solute.

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Answer: 2.34

Explanation:

pH= -log (H+)

H+ is the acid's M

pH= -log (0.0046) =2.34

The boiling point of water generally increases as the amount of impurities (which a solute like KCl technically can be thought of) dissolved increases. This relation can be quantified using the equation,

\(\Delta T_b = i \times K_b \times m\)

where \(\Delta{T}_{b}\) is the change in the water's boiling point (normally taken to be 100 °C), \(i\) is the Van 't Hoff factor (the number of particles a single formula unit of the solute dissociates into in water), \(K_b\) is the boiling point elevation constant, and \(m\) is the molality (moles of solute/kilogram(s) of solvent) of the solution.

We are forming a solution by dissolving KCl in water. KCl is an electrolyte that, in water, will dissociate into K⁺ and Cl⁻ ions. So, for every formula unit, KCl, we obtain two particles. Thus, the Van 't Hoff factor, or \(i\), will be 2.

The molality of the solution can be calculated by dividing the number of moles of KCl by the mass of water in kilograms. Since we have 1.00 kg of water, we would be dividing 0.75 mol KCl by 1, giving us a molality (m) of 0.75 m.

We aren't provided the boiling point elevation constant for water. Several authoritative sources give the value 0.512 °C/m, so we will adopt that as our \(K_b\).

Note: m = mol/kg as used in this problem.

Plugging everything in,

\(\Delta T_b = i \times K_b \times m \\\Delta T_b = 2 \times 0.512 \text{ } \frac{^oC}{mol/kg} \times 0.75 \text{ } \frac{mol}{kg} \\\Delta T_b = 0.768 \text{ } \mathrm{ ^oC}\)

As you can see, our change in boiling point is positive (the boiling point is elevated), and it is also quite modest. Taking 100 °C to be the boiling point of pure water, the boiling point of our solution would be 100 ⁰C + 0.768 ⁰C, or 100.768 ⁰C.

If we are considering significant figures, then we must give our answer to two significant figures (since 0.75 has two sig figs). We can regard the boiling point of water (100 ⁰C) as a defined value. Since our final answer is a sum, the boiling point of our solution to two significant figures would be 100.77 ⁰C.

Given:

We know,

The molality of the solution will be:

= \(\frac{Mole}{Mass}\)

= \(\frac{0.75}{1}\)

= \(0.75 \ m\)

Now,

→ \(T_{solution}-T_{water} = Kb\times m\times i\)

By putting the values, we get

                              \(= 0.51\times 0.75\times 2\)

                              \(= 0.765\)

hence,

Solution's boiling point will be:

→ \(T_{solution} = 100+0.765\)

                \(= 100.765^{\circ} C\)

Thus the above approach is right.

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The amount of volume of KOH solution that should be added to make 500mL of a 0.300M solution is 200mL.

The volume of a solution given the concentration can be calculated using the following expression;

CaVa = CbVb

Where;

According to this question, we are to calculate how many mL of a 0.75 M OH solution that should be added to a 500 mL flask to make 500 mL of a 0.300 M KOH solution.

0.75 × Va = 500 × 0.3

0.75Va = 150

Va = 150/0.75

Va = 200mL

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Answer:

1.44 × 10⁻⁶

Explanation:

Step 1: Given data

Step 2: Calculate the concentration of H⁺ ions

We will use the definition of pH.

pH = -log [H⁺]

[H⁺] = antilog -pH = antilog -2.88 = 1.32 × 10⁻³ M

Step 3: Calculate the acid dissociation constant of the acid (Ka)

For a weak monoprotic acid, we will use the following expression.

Ka = [H⁺]²/Ca

Ka = (1.32 × 10⁻³)²/1.21 = 1.44 × 10⁻⁶

To find moles when given the molar mass, you can use the concept of molar mass as a conversion factor.Molar mass represents the mass of one mole of a substance, expressed in grams per mole (g/mol).

To calculate moles, divide the given mass of the substance by its molar mass. The equation is:

moles = mass / molar mass

For example, if you have 56 grams of carbon dioxide (CO2) and want to find the number of moles, you need to know the molar mass of CO2, which is approximately 44 g/mol. Using the equation above:

moles = 56 g / 44 g/mol

moles ≈ 1.27 mol

Therefore, there are approximately 1.27 moles of carbon dioxide in 56 grams.

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The mass of the solid aluminum that forms are 192.73 grams

To determine the mass of solid aluminum that forms, we need to use stoichiometry and the balanced chemical equation for the reaction between magnesium and aluminum nitrate.

The balanced chemical equation is:

3 Mg + 2 Al(\(NO_{3}\))3 → 3 Mg(\(NO_{3}\))2 + 2 Al

The equation shows that 3 moles of magnesium react with 2 moles of aluminum to produce 2 moles of aluminum nitrate.

To calculate the mass of solid aluminum, we need to know the amount of magnesium used. Given that the volume of the magnesium is 150.0 mL and its density is 1.738 g/cm³, we can calculate the mass of magnesium using the formula:

Mass = Volume × Density

Mass of magnesium = 150.0 mL × 1.738 g/cm³ = 260.7 g

Now, using the molar mass of magnesium (24.31 g/mol) and the molar ratio from the balanced equation, we can determine the moles of magnesium used:

Moles of magnesium = Mass of magnesium / Molar mass of magnesium

= 260.7 g / 24.31 g/mol

= 10.72 mol

According to the stoichiometry of the balanced equation, the ratio of moles of magnesium to moles of aluminum is 3:2. Therefore, the moles of aluminum formed will be:

Moles of aluminum = (2/3) × Moles of magnesium

= (2/3) × 10.72 mol

= 7.15 mol

Finally, we can calculate the mass of solid aluminum using its molar mass (26.98 g/mol):

Mass of aluminum = Moles of aluminum × Molar mass of aluminum

= 7.15 mol × 26.98 g/mol

= 192.73 g

Therefore, the mass of the solid aluminum that forms is approximately 192.73 grams.

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Answer:

Molarity =  2.02 M

Explanation:

Given data:

Molarity of solution = ?

Mass of sodium chloride = 38.5 g

Volume of solution = 325 mL (0.325 L)

Solution:

Number of moles = mass/molar mass

Number of moles = 38.5 g/ 58.44 g/mol

Number of moles = 0.658 mol

Molarity:

Molarity = number of moles / volume of solution in L

Molarity = 0.658 mol /0.325 L

Molarity =  2.02 M

Answer:ch4

Explanation:

Answer:

Its H2

Explanation:

Helium has the lowest effusion rate. So its H2

Answer:

\(\boxed {\boxed {\sf -2}}\)

Explanation:

We are asked to find the net charge of an ion.

The ion has 14 protons, 16 electrons, and 12 neutrons. Recall the charges of each subatomic particle.

Neutrons are neutral and have no charge, so we can ignore them while finding the net charge. There are 14 protons and 16 electrons.

14 protons and 14 electrons have a net charge of 0 because the charges balance each other out. However, we have 16 electrons, which is 2 more than 14. Each electron has a charge of -1, so the 2 electrons add a charge of -2.

The net charge of the ion is -2.

A combustion reaction is a type of chemical reaction that involves the rapid combination of fuel (typically a hydrocarbon) with oxygen, resulting in the release of energy in the form of heat and light.

Combustion reactions are often characterized by the presence of a flame and the production of carbon dioxide (CO₂) and water (H₂O) as products.

In the given balanced combustion reaction:

C₂H₂ + 5O₂ → 4H₂O + 2CO₂

The stoichiometric ratio indicates that 1 mole of C₂H₂ reacts with 2 moles of CO₂ produced. Therefore, if 4.44 moles of C₂H₂ react, we can calculate the moles of CO₂ produced using the ratio:

Moles of CO₂ = (4.44 mol C₂H₂) × (2 mol CO₂ / 1 mol C₂H₂)

Moles of CO₂ = 8.88 mol

Therefore, 8.88 moles of CO₂ will be produced in the combustion reaction.

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Answer:

3.85E-12

Explanation:

from

KW=[H3O+]×[OH]

BUT KW=1E-14

Answer:

The answer is

Plant also use cellular respiration

Answer:

B - Plants also use cellular respiration.

Explanation:

Did the test.

Quantifying chemical reactions is essential in understanding the stoichiometry of a reaction, predicting product formation, and optimizing product yield in industrial applications. Stoichiometric coefficients and limiting reactants are two important tools used in this process.

Quantifying chemical reactions involves measuring the amount of reactants and products involved in a chemical reaction. This is important in determining the stoichiometry of the reaction, which refers to the relative amounts of reactants and products involved. Stoichiometry is a crucial concept in chemistry because it allows scientists to predict the amount of product that will be formed from a given amount of reactant, or vice versa.
One way to quantify chemical reactions is through the use of stoichiometric coefficients. These coefficients represent the number of moles of each reactant and product involved in the reaction. For example, the balanced chemical equation for the reaction between hydrogen gas and oxygen gas to form water is:
\(2H2 + O2 → 2H2O\)
This equation tells us that two moles of hydrogen gas react with one mole of oxygen gas to form two moles of water. The stoichiometric coefficients can be used to determine the mass of each reactant and product involved in the reaction, using the molar masses of each substance.
Another way to quantify chemical reactions is through the use of limiting reactants. A limiting reactant is the reactant that is completely consumed in a reaction, limiting the amount of product that can be formed. The amount of product formed will be determined by the amount of limiting reactant present. This concept is important in industrial chemistry, where maximizing product yield is often the goal.

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Answer:

B. pOH = 14 - pH and D. pH = 14 - pOH.

Explanation:

Hello,

In this case, we must remember that pH and pOH are referred to a measure of acidity and basicity  respectively, since pH accounts for the concentration of H⁺ and pOH for the concentration of OH⁻ in a solution. In such a way, since the maximum scale is 14, we say that the addition between the pH and pOH must be 14:

\(pH+pOH=14\)

Therefore, the correct answers are B. pOH = 14 - pH and D. pH = 14 - pOH since the both of them are derived from the previous definition.

Best regards.

Answer:

D: by subtracting the pOH from 14.

Explanation:

we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.

To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.

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Answer:

the answer to the answer above is motion

Given the balanced chemical reaction expressed as:

A Redox reaction is a reaction that involves the transfer of electrons and changes in the oxidation state between the elements.

The given chemical equation is therefore an oxidation-reduction reaction since it involves a change in the oxidation state of the elements.

Determine the moles of Au₂O₃

According to stochiometry, you can see that 2 moles of Gold(III)oxide produce 4 moles of Gold. Hence the moles of Gold produced will be:

Determine the mass of Gold.

Next is determining the mole of Oxygen

According to stochiometry, you can see that 2 moles of Gold(III)oxide produce 3 moles of Oxygen. Hence the moles of Oxygen produced will be:

Determine the mass of oxygen produced

Hence the mass of oxygen produced is 0.543 grams

Answer:

Vaccines. Vaccines are chemicals that stimulate the body's immune system to better fight pathogens when they attack the body. ...

Antibiotics. ...

Pest Resistant Crops. ...

Plant and Animal Breeding. ...

Biocatalysts. ...

Fermentation. ...

Microorganisms. ...

Bioremediation.

Explanation: