14) Calculate the magnitude and direction of the magnetic force on a particle of charge q= 13C that
is moving with a velocity of v= -20m/s x (to the left) in a magnetic field of B= 0.5 T 2

Answers

Answer 1

The magnitude and direction of the magnetic force on a particle of charge is - 2.21 in the opposite direction.

What is magnetic force?

Magnetic force is defined as the electrically charged particles that are in motion and exhibit either attraction or repulsion. The interaction between moving and stationary charged particles is explained by the electromagnetic force, commonly known as the Lorentz force.

The magnitude and direction of the magnetic force can be calculated as

F = q v B sinθ

Given q = 13 C

v = - 20 m/s

B =  0.5 T²

F = 13 C x - 20 m/s x 0.5 T² sinθ

F = - 130 sinθ

Let θ is equal to 1

Then, F = 130 sin1

F = - 130 x 0.017

F = - 2.21

Thus, the magnitude and direction of the magnetic force on a particle of charge is - 2.21 in the opposite direction.

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Related Questions

Based on observations by the Dawn spacecraft, scientists have concluded that Vesta might be:

A. the only remaining protoplanet in our solar system.
B. a planetesimal leftover from the solar system's formation.
C. a fragment of Mars.
D. one of the remnants of the planet that broke up to form the asteroid belt.
E. one of the dwarf planets in our solar system.

Answers

Based on observations by the Dawn spacecraft, scientists have concluded that Vesta might be: D. one of the remnants of the planet that broke up to form the asteroid belt.

Based on observations by the Dawn spacecraft, scientists have concluded that Vesta might be a planetesimal leftover from the solar system's formation. Vesta is one of the largest asteroids in the asteroid belt between Mars and Jupiter. Its unique characteristics and composition provide insights into the early stages of our solar system.

Dawn's data reveals that Vesta is differentiated, meaning it has distinct layers and a core, which is consistent with its formation as a planetesimal. The spacecraft detected evidence of volcanic activity, impact craters, and the presence of basaltic lava flows on Vesta's surface. These features suggest that Vesta experienced a significant amount of geologic activity in the past.

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The paving stone has the weight of 600N side A has the area of 300cm 2 Calculate the pressure under the paving stone if Mr smith puts the stone on Side A

Answers

Answer:

20N

Explanation:

w over h is 600 divided by 300

Answer:

20 000 pascals

Explanation:

PRESSURE in the metric system is measured in Pascals

   the units are   N / m^2

300 cm^2 = .03 m^2

600N / .03 m^2 =20 000 pascals

The mass of a newborn baby's brain has been found to increase by about 1.6 mg perminute. (a) How much does the brain's mass increase in one day?

Answers

ANSWER

2304 mg

EXPLANATION

The rate is given in mg per minute. To find how much the brain's mass increases in one day we have to find how many minutes are in a day.

Assuming that a day has 24 hours and 1 hour has 60 minutes:

\(24h\cdot\frac{60\min}{1h}=1440\min \)

One day has 1440 minutes. Then, in one day the brain's mass increases:

\(1.6mg/\min \cdot1440\min =2304mg\)

The newborn baby's brain's mass increases 2304 mg in one day.

are u god tell me u have to tell me are u a god

Answers

They tell me I'm a god, I'm lost in the facade

Six-feet off the ground at all times, I think I'm feelin' odd

No matter what I make, they never see mistakes

Makin' so much bread, I don't care that they're just being fake

They tell me they're below me, I act like I'm above

The people blend together but I would be lost without their love

Can you heal me? Have I gained too much?

When you become untouchable, you're unable to touch

Is there a real me? Pop the champagne

It hurts me just to think and I don't do pain

Stayin' still, eyes closed

Let the world just pass me by

Pain pills, nice clothes

If I fall, I think I'll fly

Touch me, Midas

Make me part of your design

None to guide us

I feel fear for the very last time.

What magnitude force is required to give a helicopter of mass m an acceleration of 0. 10g upward?.

Answers

The helicopter of mass `m` requires a force to move in an upward direction with an acceleration of `a = 0.10g`, where `g` is the acceleration due to gravity.

The force required can be calculated as follows:

\(`F = m x 0.10g`\)

For an upward direction, the force required is greater than the weight of the helicopter, which acts downwards. The weight of the helicopter is given by `W = mg`, where `g = 9.81 m/s²` (acceleration due to gravity).

Substituting the value of `g` into the equation, we have:

\(`W = mg = m × 9.81 m/s²`\)

Therefore, the magnitude of the force required to give the helicopter of mass `m` an acceleration of `0.10g` upward is:

\(`F = m x 0.10g = m x 0.10 × 9.81 m/s² = 0.981m N`\)

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Find the maximum energy stored in the spring bumpers

Answers

The maximum energy stored in the spring bumpers is given as ¹/₂kx².

Maximum energy stored in a spring

The maximum energy stored in a spring is given by the following equations;

E = ¹/₂kx²

where;

E is the energy stored in the springk is spring constantx is extension of the spring

Thus, the maximum energy stored in the spring bumpers is given as ¹/₂kx².

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The Escape speed at the surface of a certain planet is twice that of the earth. what is its mass in unit of earth's mass?
Plzz help

Answers

Answer:

22Km/sec

Explanation:

The Round Up carnival ride below has a radius of 3.62 meters and rotates 0.537 times per second. As shown, riders can be held up by only friction. What coefficient of friction is needed to keep the riders from sliding down? Include units in your answer. Answer must be in 3 significant digits.

The Round Up carnival ride below has a radius of 3.62 meters and rotates 0.537 times per second. As shown,

Answers

The free body diagram for the problem is shown below:

If the people don't slide down this means that the friction has to be equal to the Weight, then we have:

\(\begin{gathered} F_f-W=0 \\ F_f=W \\ \mu F_n=W \\ \mu=\frac{W}{F_n} \end{gathered}\)

Now, from newton's second law we have that:

\(F_n=ma_c\)

but

\(a_c=\frac{4\pi^2r}{T^2}\)

then:

\(F_n=\frac{4\pi^2mr}{T^2}\)

And then we have:

\(\begin{gathered} \mu=\frac{mg}{\frac{4\pi^2mr}{T^2}} \\ \mu=\frac{gT^2}{4\pi^2r} \end{gathered}\)

Plugging the values given we have:

\(\begin{gathered} \mu=\frac{(9.8)(\frac{1}{0.537})^2}{4\pi^2(3.62)} \\ \mu=0.238 \end{gathered}\)

Therefore the coefficient of friction is 0.238

The Round Up carnival ride below has a radius of 3.62 meters and rotates 0.537 times per second. As shown,

A student is trying to demonstrate static electricity, so they rub two identical balloons with a neutral rabbit fur to give them a charge. How
do these three objects now behave when brought near to each other?
o A. They all attract each other.
OB. The balloons repel each other but attract the rabbit fur.
C. They all repel each other.
D. The balloons attract each other but repel the rabbit fur.

Answers

Answer: The balloons repel each other but attract the rabbit fur.

Brainliest pwease if I could do you any help!

˙ᵕ˙

Here, both the balloons gains a negative charge through rubbing and they attracts to the neutral rabbit fur. But the balloons themselves repel each other. Hence, option B is correct.

What is static electricity ?

When a  material rub on a surface its electrons gets aligned and acquire a negative charge. This negative charge when comes in contact with a neutral material, the second one get partially polarized and gets attracted to the negative charge.

This flow of electrons through induced polarization is called static electricity. When the balloon are rubbed with the neutral rabbit fur and gets negatively charged by friction.

This negatively charged balloons repel each other but they induce a polarity to the neutral rabbit fur and its positive charges gets aligned with the negative charges results in electrostatic attraction.

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A transverse wave on a rope is given by y(x,t)= (0.750cm)cos(π[(0.400cm−1)x+(250s−1)t]).Find- A) Amplitude- B) Period- C) Frequency- D) Wavelength- E) Speed of propagation- F) Is the wave traveling in the +x- or − x-direction?- G) The mass per unit length of the rope is 0.0500 kg/m. Find the tension?- H) Find the average power of the wave (Watts)?

Answers

A transverse wave n a rope is given by y(x,t)=(0.750cm)cos(π[(0.400cm−1)x+(250s−1)t]), the amplitude is  0.750cm, the time period of wave is 8m/s, Frequency is 0.125 Hz, average power of the wave is  Watts.

The amplitude of a wave corresponds to its maximum oscillation of the wave itself.

In our problem, the equation of the wave is

y(x,t)=(0.750cm)cos(π[(0.400cm−1)x+(250s−1)t])

We can see that the maximum value of y(x,t) is reached when the cosine is equal to 1. When this condition occurs,

y(x,t)=(0.750cm) which is the amplitude of the wave.

A transverse wave is a wave in which the disturbance in the medium is perpendicular to the propagation of the wave. The time period of the wave is the time taken in completing one oscillation about the mean position.

The standard wave is given as,

y(x,t) = Acos(kx+t)

Comparing the standard wave to the wave given in question.

We find out the time period is 0.025 s.

Frequency = 1/T= 40

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Mountains can ONLY be formed by continental crust colliding?
True
False

Answers

Answer

:Fold mountains are often associated with continental crust. They are created at convergent plate boundaries, sometimes called continental collision zones or compression zones. Convergent plate boundaries are sites of collisions, where tectonic plates crash into each other.

if an object starts from rest and accelerates at the rate of 0.5 m/s^2 for 30 seconds, what is its final velocity?

Answers

The final velocity of the object is 15 m/s. It means that after accelerating at a rate of 0.5 m/s² for 30 seconds, the object reaches a velocity of 15 m/s.

To determine the final velocity of an object, we can use the formula:

v = u + at

Where:

v is the final velocity,

u is the initial velocity (which is 0 m/s since the object starts from rest),

a is the acceleration, and

t is the time taken.

In this case, the initial velocity (u) is 0 m/s, the acceleration (a) is 0.5 m/s², and the time (t) is 30 seconds. Plugging these values into the formula, we get:

v = 0 + (0.5 m/s²)(30 s)

v = 0 + 15 m/s

v = 15 m/s

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Here we will look at the difference between average and instantaneous velocities via a specific example of a cheetah chasing its prey. The cheetah is crouched in ambush 20.0 m to the east of an observer’s vehicle, as shown in (Figure 1). At time t=0, the cheetah charges an antelope in a clearing 50.0 m east of the observer. The cheetah runs along a straight line; the observer estimates that, during the first 2.00 s of the attack, the cheetah’s coordinate x varies with time t according to the equation x=20.0m+(3.00m/s2)t2. (a) Find the displacement of the cheetah during the interval between t1=1.00s and t2=2.00s. (b) Find the average velocity during this time interval. (c) Estimate the instantaneous velocity at time t1=1.00s by taking Δt=0.10s.What is the cheetah’s average speed over the first second of the attack?

Answers

The cheetah’s average speed over the first second of the attack is 12.0m/s.

The displacement of the cheetah during the time interval between t1=1.00s and t2=2.00s can be found by calculating the difference between the positions of the cheetah at these two times. Using the equation x=20.0m+(3.00m/s2)t2, we can find the positions of the cheetah at t1 and t2:

x1=20.0m+(3.00m/s2)(1.00s)2=23.0m
x2=20.0m+(3.00m/s2)(2.00s)2=32.0m

The displacement of the cheetah during this time interval is:

Δx=x2-x1=32.0m-23.0m=9.0m

The average velocity of the cheetah during this time interval is:

vavg=Δx/Δt=(9.0m)/(2.00s-1.00s)=9.0m/s

To estimate the instantaneous velocity of the cheetah at time t1=1.00s, we can take a small time interval around t1 and calculate the average velocity during this time interval. For example, we can take Δt=0.10s and calculate the average velocity between t1-Δt/2=0.95s and t1+Δt/2=1.05s:

x1=20.0m+(3.00m/s2)(0.95s)2=22.7m
x2=20.0m+(3.00m/s2)(1.05s)2=23.3m
vavg=Δx/Δt=(23.3m-22.7m)/(1.05s-0.95s)=6.0m/s

This is an estimate of the instantaneous velocity of the cheetah at time t1=1.00s.

The average speed of the cheetah over the first second of the attack is the total distance traveled by the cheetah during this time divided by the time interval:

vavg=Δx/Δt=(32.0m-20.0m)/(2.00s-0s)=12.0m/s

Therefore, the cheetah’s average speed over the first second of the attack is 12.0m/s.

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How do you calculate the average power, current, potential difference of an AC generator

Answers

The average ac power is found by multiplying the rms values of current and voltage

A single 1-M star will eventually eject significant amounts of which of the following chemical elements into the interstellar medium?
hydrogen
iron
nickel
all of the above

Answers

The nuclear fusion reaction, which occurs in the star's core, is responsible for this. In stars that are more massive than the Sun, heavier elements such as iron and nickel are formed and ejected into the interstellar medium through supernova explosions. However, in the case of a 1-M star, the fusion process only produces helium, carbon, and nitrogen.

The answer is Hydrogen. Explanation: In terms of chemical elements, a single 1-M star will eventually eject significant amounts of hydrogen into the interstellar medium. Once the helium in the core has been exhausted, the outer layers of the star begin to expand and cool. It becomes a red giant as a result of this process. The star's outer layers eventually expand so far that they are lost, forming a planetary nebula. The core of the star, which is now exposed, emits ultraviolet radiation that ionizes the planetary nebula's gases, causing it to glow brightly. The core is now known as a white dwarf, which gradually cools and dims over time.

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A single 1-M star will eventually eject significant amounts of hydrogen, iron, nickel, and other chemical elements into the interstellar medium.

A 1-M star, also known as a solar-mass star, goes through several stages of stellar evolution. Initially, it burns hydrogen in its core, producing helium through nuclear fusion. As the star evolves, it undergoes a series of nuclear reactions, leading to the synthesis of heavier elements. During the red giant phase, the star expands and loses its outer layers, which results in the ejection of significant amounts of hydrogen and other light elements into the interstellar medium.

Additionally, during the late stages of a 1-M star's life, it undergoes a supernova explosion, which releases enormous amounts of energy and leads to the synthesis of even heavier elements like iron and nickel. These elements are synthesized through nuclear reactions occurring during the explosive event. The explosion disperses these newly formed elements into space, enriching the interstellar medium with iron, nickel, and other elements.

Therefore, a single 1-M star will indeed eject significant amounts of hydrogen, iron, nickel, and various other chemical elements into the interstellar medium throughout its evolution and, particularly, during the supernova explosion at the end of it.

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determine the degeneracy (number of orbitals characterized with the same energy) for the a. π2p mos 2 b. π∗2p mos

Answers

For part a, the π2p MOs have a degeneracy of 3, meaning there are 3 orbitals with the same energy level. This is because there are 3 p orbitals (px, py, and pz) that can combine to form the π2p MO.

For part b, the π∗2p MOs have a degeneracy of also 3. This is because the π∗2p MOs are formed by anti-bonding combinations of the same 3 p orbitals used in part a. So, there are also 3 orbitals with the same energy level for the π∗2p MOs.
Hi! I'd be happy to help you determine the degeneracy for the given molecular orbitals.

a. For the π2p molecular orbitals:
The degeneracy of π2p molecular orbitals is 2. This is because there are two π2p orbitals with the same energy level, one in the x-axis (π2px) and the other in the y-axis (π2py).

b. For the π∗2p molecular orbitals:
The degeneracy of π∗2p molecular orbitals is also 2. Similar to the π2p orbitals, there are two π∗2p orbitals with the same energy level, one in the x-axis (π∗2px) and the other in the y-axis (π∗2py).

In both cases, the degeneracy is 2, as there are two orbitals with the same energy level.

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A cart of mass m is moving with negligible friction along a track with known speed y, to the right. It


collides with and sticks to a cart of mass 4m moving with known speed y, to the right. Which of the two


principles, conservation of momentum and conservation of mechanical energy, must be applied to determine


the final speed of the carts, and why?

Answers

The principle of conservation of momentum must be applied to determine the final speed of the carts. Conservation of momentum states that the total momentum of a system remains constant if no external forces act on it.

In this scenario, the collision between the two carts is an isolated system, meaning no external forces are involved. Therefore, the initial momentum of the system before the collision should be equal to the final momentum after the collision. Since the carts stick together after the collision, they move as a single combined mass. The initial momentum of the system is given by the sum of the individual momenta of the two carts. After the collision, the combined mass moves with a final velocity, which is the same for both carts since they are now connected.

On the other hand, the principle of conservation of mechanical energy cannot be directly applied in this scenario. Conservation of mechanical energy states that the total mechanical energy of a system remains constant if no external non-conservative forces (such as friction or air resistance) act on it. However, in this case, the collision is not perfectly elastic, and there is a change in the mechanical energy due to the deformation of the carts and the conversion of kinetic energy into other forms of energy, such as heat or sound. Therefore, conservation of mechanical energy cannot be used to determine the final speed of the carts.

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For a certain transverse wave, the distance between two successive maxima is 1.9 m and eight maxima pass a given point along the direction of travel every 8.76 s.
calculate the wave speed. answer in units of m/s.

Answers

To find the velocity of the wave, we can use the formula:

velocity (v) = wavelength (λ) * frequency (f)

Given:

Distance between two successive maxima (wavelength, λ) = 1.9 m

Number of maxima passing a point (frequency, f) = 8 maxima / 8.76 s

First, we need to calculate the frequency:

frequency (f) = Number of maxima passing a point / Time taken

f = 8 maxima / 8.76 s

Next, we can calculate the wavelength:

wavelength (λ) = Distance between two successive maxima

λ = 1.9 m

Finally, we can calculate the velocity using the formula:

velocity (v) = wavelength (λ) × frequency (f)

v = λ × f

Substituting the values:

v = 1.9 m × (8 maxima / 8.76 s)

Calculating the result:

v ≈ 1.9 m × 0.913 s⁻¹

v ≈ 1.7377 m/s

Therefore, the velocity of the transverse wave is approximately 1.7377 m/s.

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Place the molecules in the list in order with the smallest molecules at the top and largest molecules at the bottom: starch molecule, water molecule, glucose molecule, carbon dioxide molecule, protein molecule, amino acid molecule, oxygen molecule

Answers

Explanation:

list in order with the smallest molecules at the top and largest molecules at the bottom:

1.Oxygen

2.Water

3.Carbon dioxide

4.amino acid

5.Glucose

6. Starch

7. Protein

The molecules can be arranged as follows with the smallest at the top is oxygen, water, carbon dioxide, amino acid, glucose, starch, protein.

The given molecules;

starch, water, glucose, carbon dioxide, protein, amino acid, oxygen

The molecular weight of the given compounds is listed as follows;

water -------- 18 g/mol

glucose -------  180.2 g/mol

starch (2 or more glucose) ------ 360 g/mol

carbon dioxide ------ 44 g/mol

protein -------- 20,000 g/mol

amino acid (glycine) ----- 75 g/mol

oxygen -------- 16 g/mol

Thus, the molecules can be arranged as follows with the smallest at the top;

oxygenwatercarbon dioxideamino acidglucosestarchprotein

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A cup of coffee with cooling constant k = -0.09 is placed in a room temperature of 18°C. If the coffee is served at 93 °C, how long will it take to reach a drinking temperature of 73 °C?

Answers

The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

The cooling law is given by:

$$\frac{dQ}{dt}=-k(T-T_0)$$

where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.

We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.

Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.

Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:

dQ = - dQ where dQ is the heat energy gained by the environment.

We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.

We can rearrange the equation as follows:

$$-\frac{dQ}{dt}=k(T-T_0)$$

$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$

$$\frac{d}{dt}T=-k(T-T_0)$$

The differential equation above can be solved using separation of variables as follows:

$$\frac{d}{dt}\ln(T-T_0)=-k$$

$$\ln(T-T_0)=-kt+c_1$$

$$T-T_0=e^{-kt+c_1}$$

$$T=T_0+Ce^{-kt}$$

where C = e^(c1).

We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.

$$T=T_0+Ce^{-kt}$$

$$73=18+C\cdot e^{-0.09t}$$

$$55=C\cdot e^{-0.09t}$$

$$C=55e^{0.09t}$$

$$T=18+55e^{0.09t}$$

We can now solve for the value of t when T=93 as follows:

$$93=18+55e^{0.09t}$$

$$e^{0.09t}=\frac{93-18}{55}$$

$$e^{0.09t}=1.3636$$

$$t=\frac{\ln(1.3636)}{0.09}$$

Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

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PLEASE HELP ASAP!! DUE IN AN HOUR :’))!!

PLEASE HELP ASAP!! DUE IN AN HOUR :))!!

Answers

Answer: The object moves with constant velocity

Explanation:

In this velocity vs time graph we're dealing with Ap physics or regents physics. If we look at the slope we can see it is constant or not changing. Even so lets check the other answers and prove them wrong

The objects speed increases: This is wrong because the line shows a steady 5m/s with no change

The object is in free fall: If the object was in freefall the speed would be increasing as a result of acceleration due to gravity

The object moves with a constant speed: This seems to be the case since the slope or line doesn't change at all

The object stays at rest: Can't be right because the object is at a speed of 5m/s so we know its moving at least

The objects speed decreases: Again the line isn't going up or down so we can't say speed increases or decreases

Shelley's cup of tea cooled down
1
2
of a degree in 10 minutes. At what rate is her tea cooling down

Answers

If Shelley's cup of tea cools 1/2 of a degree in 10 minutes, the rate of her tea cooling down is 0.05 degrees per minute.

10 minutes = 1 / 2 degrees

1 minute = 1 / 2 / 10 degrees

1 minute = 1 / 20 degrees

1 minute = 0.05 degrees

If a value is given for x amount of a factor, to calculate for unit amount of the factor, divide the value by the value of x. Similarly, if a value is given for unit amount of a factor, to calculate for x amount of factor, multiply the value by x.

Therefore, the rate of her tea cooling down is 0.05 degrees / minute.

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Please help with physics homework.
Show work for question c)

Please help with physics homework.Show work for question c)

Answers

a) The force diagram of the block and all the forces are in the image attached.

(b) The weight of the block and its parallel component is  98.1 N and 33.55 N respectively.

(c) The applied force on the block is 52.75 N

What are the component of the forces?

(a) The force diagram of the block include, the parallel and pedicular component, as well as friction force.

(b) The weight of the block and its parallel component is calculated as;

Fg = mg

where;

m is the mass of the blockg is acceleration due to gravity

Fg = 10 kg x 9.81 m/s²

Fg = 98.1 N

Fgₓ = mgsinθ

Fgₓ = 98.1 N x sin(20)

Fgₓ = 33.55 N

(c) The applied force on the block is calculated as follows;

F - Fgₓ - μFgcosθ = ma

where;

m is the mass of the blocka is the acceleration of the blockμ is the coefficient of frictionF is the applied force

μ = a/g

μ = 1 / 9.81 = 0.1

F - 33.55 - 0.1(98.1 x cos20) = 10 x 1

F - 33.55 - 9.2 = 10

F = 10 + 33.55 + 9.2

F = 52.75 N

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Please help with physics homework.Show work for question c)

Which two parts do the capillaries surround?

A. small intestines and heart

B. heart and lungs

C. alveoli and small intestines​

Answers

Answer:

do we have to choose 2 answers here?

Answer:

most probably it's C

Explanation:

alveoli is surrounded by capillaries and whit that option small intestines is also there

While driving on Fairway Drive, you see a pedestrian in the crosswalk, so you step on the brakes. If you decelerate at a rate of -2.4m/s2 and you were originally driving at a rate of 24 miles per hour (*hint convert to m/s), how long would it take you to come to a full stop. Please give your answer in seconds.

While driving on Fairway Drive, you see a pedestrian in the crosswalk, so you step on the brakes. If

Answers

24 mph is 10.729 m/s

Below is the velocity function, in feet per second, for a particle moving along a straight line. Find (a) the displacement and (b) the total distance that the particle travels over the given interval.
v(t) = t³ 13t2 + 47t-35 1≤t≤7
(a) Displacement: 36
(b) Total distance:

Answers

Given function isv(t) = t³ +13t²+47t-35and time interval is 1≤t≤7. We have to calculate:

(a) Displacement

(b) Total Distance

(a) Displacement:

Displacement is defined as the shortest distance between initial and final points. We can find the displacement of a particle with the help of following formula:

Displacement = Final Position - Initial PositionHere, the particle moves along a straight line, and we don't know the initial and final position.  Thus, the displacement of the particle is 219 ft.(b) Total Distance:Total distance traveled by the particle is the sum of all the distances covered by it in different intervals.

Thus, we have two real roots of the given equation:t₁

≈ - 6.548t₂

≈ 0.215

Therefore, ∫|v(t)|dt = 309

As we have to find the total distance, we have to add both the cases. Therefore,

Total Distance =∫|v(t)|dt  [from 1 to 7]

=∫|v(t)|dt [from 1 to 7]

=∫|v(t)|dt (from 1 to 1.215) +|v(t)|dt (from 1.215 to 7) = 252 + 309= 561 ft Thus, the total distance traveled by the particle is 561 feet.

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an electron travels with velocity < 4e5, 0, 0 > m/s. it enters a region in which there is a uniform magnetic field of < 0, 0.7, 0 > t. what is the magnetic force on the electron? b

Answers

The magnetic force on the electron 4.48×10⁻¹⁴ N

we are provided with the velocity which is (4e5, 0, 0) and  the magnetic field which  is  (0, 0.7, 0) .the Lorentz equation a charged molecule of charge q moving with a speed v will encounter a force ,

F = q × ( E + v × B ) where E is the electric field and  B is the magnetic field and q is the charge of the particle. The electron is moving in the positive x direction. The magnetic field is coordinated within the positive y direction from the right-hand palm rule we see that the magnetic force acting on an electron in the + z direction.

so the magnetic forc will be :

F=qvB

 = 1.6×10⁻¹⁹*4×10⁵*0.7

 =  4.48×10⁻¹⁴ N

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A sailboat started its journey at 6:30am and reached the destination at 6:30pm. If the distance of the journey was 144 miles, what was the sailboats average speed?___mph

Answers

Answer:

The sailboats average speed was 13 mph.

Explanation:

To calculate the speed of the boat first calculate the total ammountof hours it took the boat to get to its destination. Then divide 144 by that number which comes out to 13.

The average speed of the sailboat is determined as 12 miles per hours.

What is average speed?

The average speed of an object in motion is obtained by dividing the total distance traveled by the object with the time spent in the entire journey.

v = total distance/total time

where;

total distance = 144 milestotal time = from 6:30am to 6:30pm = 12 hours

v = 144/12

v = 12 mph

Thus, the average speed of the sailboat is determined as 12 miles per hours.

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3. Determine the units of the quantity described by the following com-
binations of units:
a. kg (m/s) (1/s)
b. (kg/s) (m/s2)
c. (kg/s) (m/s)
d. (kg/s) (m/s)

Answers

B is the answer!! Hope this helps

Based on what you learned about light, select all of the correct statements from the following list. -High frequency photons carry more energy than long wavelength photons.
-All electromagnetic waves travel at the speed of light.
-Light can act both as a wave and a particle.
-A photon is a particle of light. X-rays and gamma rays are long wavelength photons.
-Different types of electromagnetic radiation are fundamentally different types of waves.
-The only type of electromagnetic radiation that is actually considered light is visible light.

Answers

The correct statements include:

High frequency photons carry more energy than long wavelength photons.All electromagnetic waves travel at the speed of light.Light can act both as a wave and a particle.A photon is a particle of light.

option A, B, C, D

What are the incorrect statements about electromagnetic waves?

The Incorrect statements include:

Different types of electromagnetic radiation are fundamentally different types of waves. (All types of electromagnetic radiation are fundamentally the same type of wave but have different frequencies and wavelengths.)

The only type of electromagnetic radiation that is actually considered light is visible light. (All types of electromagnetic radiation are considered light, including radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays.)

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Answer: A B C D

Explanation: k12 I had this quiz

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